Answer:
: An app thr features menu planning with healthy recipes and pairs with a calorie tracking tool
which quanities are scalars
Answer:
they are quantities with magnitude without direction e.g weight,
A string of length 75.0cm has fixed ends. Two consecutive harmonics are 420 Hz and 315 Hz. Find the wave speed and the fundamental frequency.
please use equations: f=vλ and λ=\(\frac{2L}{n}\)
The wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.
Frequency is the number of cycles of a periodic waveform that occur per unit of time. It is measured in Hertz (Hz).
We can use the equation λ=2L/n, where λ is the wavelength, L is the length of the string, and n is the harmonic number. Since the string has fixed ends, the harmonics must be odd-numbered, so we have n=1 for the fundamental frequency, n=3 for the second harmonic (315 Hz), and n=5 for the third harmonic (420 Hz).
Using n=1 and λ=2L/n, we get:
λ = 2L/1
λ = 2L
Using n=3 and λ=2L/n, we get:
λ = 2L/3
Using n=5 and λ=2L/n, we get:
λ = 2L/5
We can use the formula f=v/λ to relate the wave speed v, wavelength λ, and frequency f. For the two consecutive harmonics, we can write:
v/λ1 = f1
v/λ2 = f2
Since the two harmonics are consecutive, we can assume that they correspond to adjacent values of n, so we have:
λ1 = 2L/1 = 2L
λ2 = 2L/3
Substituting these values into the above equations and solving for v, we get:
v = f1λ1 = f2λ2 = (420 Hz)(2L) / (2L) = (315 Hz)(2L)/(2L/3) = 840 cm/s
To find the fundamental frequency, we use the formula f=v/λ1:
f = v/λ1 = 840 cm/s / 2L = (840 cm/s) / (0.75 m) = 1120 Hz
Therefore, the wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.
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1.How are elements arranged on the periodic table in terms of valence electrons?
2. Show some evidence using data tables
3. Explain how the evidence supports your claim. Explain how the evidence from your data table shows the trends for valence electrons for both groups and periods on the periodic table.
Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.
1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.
2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:
Element | Electron Configuration | Group | Period |
--------------------------------------------
Hydrogen | 1s^1 | 1 | 1 |
Lithium | [He] 2s^1 | 1 | 2 |
Carbon | [He] 2s^2 2p^2 | 14 | 2 |
Oxygen | [He] 2s^2 2p^4 | 16 | 2 |
Neon | [He] 2s^2 2p^6 | 18 | 2 |
--------------------------------------------
3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.
- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.
- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.
By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.
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A wave travels through a rope at a speed of 2.1 m/s and has a wavelength of 0.15 m. The wave then passes into a spring where it
travels at a speed of 5.0 m/s. The wave's wavelength in the spring is
m.
The wavelength of the wave in the spring is 0.357 m.
What is wavelenth?Wavelength is the length of a complete revolution of a wave.
To calculate the wavelength of the wave in the spring, we use the formula below
Formula:
v'/λ' = v/λ........................ Equation 1Where:
v' = Speed of the wave in the ropeλ' = Wavelength of the wave in the ropev = Speed of the wave in the springλ = Wavelength of the wave in the springFrom the question,
Given:
v' = 2.1 m/sλ' = 0.15 mv = 5.0 m/sSubstitute these values into equation 1 and solve for λ
2.1/0.15 = 5.0/λλ = (5×0.15)/2.1λ = 0.357 mHence, the wavelength is 0.357 m.
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a proton travelling along is x-axis is lowed by a niform electric field E. at x = 20.0 cm, the proton has a speed of 3.5x10^6 m/s and at 80.0 cm the speed is zero. Determine the magnitude and direction of e,
Answer:
Magnitude of electric field is 1.06 x \(10^5\) V/m along negative X-direction
Explanation:
Given: initial velocity of proton = u = 3.5 x \(10^6\) m/s
final velocity of proton = v = 0 m/s
initial point \(l_i\) = 0.2 m and final point is \(l_f\) = 0.8 m
According to conservation of energy:
change in in kinetic energy = change in potential energy of proton
⇒\(\frac{m}{2}(v^2-u^2 ) = qE(l_i - l_f)\)
where q and m is the charge and mass of proton E is the electric field , \(l_i\) and \(l_f\) is the initial and final position of proton
on substituting the respected values we get,
1.023 x \(10^-^1^4\) = 9.6 x \(10^-^2^0\) x E
⇒ E = 1.06 x \(10^5\) V/m
external force is opposite to the motion as velocity of proton decreases with distance.
Therefore, magnitude of electric field is 1.06 x \(10^5\) V/m along negative X-direction
What is the magnetic force on a 2.0-m length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic field has a magnitude of 55 mT and is directed at an angle of 20° away from the wire?
To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:
F = I * L * B * sin(θ)
where:
F is the magnetic force,
I is the current in the wire,
L is the length of the wire,
B is the magnitude of the magnetic field, and
θ is the angle between the wire and the magnetic field.
In this case, the values are:
I = 30 A (current in the wire)
L = 2.0 m (length of the wire)
B = 55 mT = 0.055 T (magnitude of the magnetic field)
θ = 20° (angle between the wire and the magnetic field)
Substituting the values into the formula:
F = 30 A * 2.0 m * 0.055 T * sin(20°)
Calculating sin(20°):
F = 30 A * 2.0 m * 0.055 T * 0.3420
F ≈ 1.5714 N
Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.
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HELP PLS ASAP. ??????
Answer:
I believe it would be 132
Explanation: when you take a your pulse times 6 because it breaks down to 6 per second and if in 10 seconds you have 22 beats 22x6 is 132.
Through what angle in degrees does a 33 rpm record turn in 0.32 s?
63°
35°
46°
74°
Answer:
1 rev = 2(pi) rad pi(rad) = 180 degrees
so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees
Explanation:
63.36 estimated to 63 so 63
The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.
Calculation of the angle:Since we know that1 rev = 2(pi) rad
So here pi(rad) = 180 degrees
Now for 33 rpm it should be like
= 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s
= 63.36 degrees
= 63 degrees
hence, The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.
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A skier uses a pair of poles to push himself down a ski slope. Which of the following correctly states when the skier has the most potential energy? ( HELP WILL MARK YOU AS BRAINLIEST!!)
a
when the skier is at the top of the ski slope
b
when the skier starts to travel down the slope
c
when the skier reaches the bottom of the slope
d
when the skier comes to a complete stop at the bottom of the slop
The correct statement for the skier has the most potential energy is when the skier is at the top of the ski slope. Hence, option (a) is correct.
What is Potential Energy?Potential energy is a form of energy that is stored but is dependent on the size positions of different system components. Extending or contracting a spring increases its potential energy.
A specimen has much more potential energy when it is raised above the surface of the earth than when it is brought to Earth. It can conduct more work in the raised position. Potential energy is a system property, not a feature of a single entity or particle. For example, the system made up of Earth and the raised ball has greater potential energy as they are far apart.
The potential energy at the top of the ski slope will be maximum, while the kinetic energy at the top of the ski slope will be equal to zero.
Therefore, when he was at the top of the ski slope, the potential energy will be maximum.
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Urgent, need answering!:
A light hangs on a chain in the kitchen. What types of forces are acting on the light?
A) gravity and tension
B) gravity and normal
C) normal and tension
D) just gravity
A 100 kg mass, initially at rest, is blown apart into two 50.0 kg pieces.
After the blast, the two masses are moving apart with a relative velocity
of 100 m/s. The total kinetic energy after the explosion is
Answer:
Since the center of mass is zero prior to the explosion, it must also be zero after the explosion because no external forces are present,
KE1 = 1/2 (M/2) * 50^2 m2/s^2= 25 * 2500 J = 62,500 J
The total KE will be 2 * 62,500 J = 125,000 J
The displacement of a car is a function of time as follows: x(t)=25+3.0t², with x is in meters. Find the average velocity between t1 = 1.0s and t2 = 4.0s.
Answer: 15m/s
Explanation: Average Velocity is vector describing the total displacement of an object and the time taken to change its position. It is represented as:
\(v=\frac{\Delta x}{\Delta t}\)
At t₁ = 1.0s, displacement x₁ is:
\(x(1)=25+3(1)^{2}\)
x(1) = 28
At t₂ = 4.0s:
\(x(4)=25+3(4)^{2}\)
x(4) = 73
Then, average speed is
\(v=\frac{73-28}{4-1}\)
v = 15
The average velocity of a car between t₁ = 1s and t₂ = 4s is 15m/s
How many times does the light beam shown in FIGURE 26-59 reflect from (a) the top and (b) the bottom mirror?
Answer:
5
Explanation:
To accelerate, an object must
Answer:
be acted upon an object or person
Explanation:
What occurs when energy is added or removed from an object or a system by an outside agent? PLEASE HELP ME!!
A Potential Energy
B Kinetic Energy
C Elastic Potential Energy
D Thermal Energy
E Work
Astronomers observe the motion of four planets that orbit a star similar to the Sun. Each planet follows an elliptical orbit around its star. The astronomers measure each planet's orbital period, as shown in the table.
Planet; Orbital Period (Earth days)
Planet W; 10
Planet X; 640
Planet Y; 80
Planet Z; 270
To determine the distance each planet is from the star, astronomers applied one of Kepler's three laws.
Kepler's first law: The path of each planet around a star is an ellipse, with the star at one focus. Kepler's second law: A planet sweeps out equal areas in equal amounts of time as it revolves around the star.
Kepler's third law: The square of the time for one revolution of a planet is proportional to the cube of the radius of its orbit.
Based on the table, identify the planet that is the farthest distance from the star, and indicate which of Kepler's three laws can be used to justify your answer. Enter your answer in the box provided.
Answer:
planet that is farthest away is planet X
kepler's third law
Explanation:
For this exercise we can use Kepler's third law which is an application of Newton's second law to the case of the orbits of the planets
T² = (\(\frac{4\pi ^2}{ G M_s}\) a³ = K_s a³
Let's apply this equation to our case
a = \(\sqrt[3]{ \frac{T^2}{K_s} }\)
for this particular exercise it is not necessary to reduce the period to seconds
Plant W
10² = K_s \(a_{w}^3\)
a_w = \(\sqrt[3]{ \frac{100}{ K_s} }\)
a_w = \(\frac{1}{ \sqrt[3]{K_s} }\) 4.64
Planet X
a_x = \(\sqrt[3]{ \frac{640^3}{K_s} }\)
a_x = \frac{1}{ \sqrt[3]{K_s} } 74.3
Planet Y
a_y = \(\sqrt[3]{ \frac{80^2}{K_s} }\)
a_y = \frac{1}{ \sqrt[3]{K_s} } 18.6
Planet z
a_z = \(\sqrt[3]{ \frac{270^2}{K_s} }\)
a_z = \frac{1}{ \sqrt[3]{K_s} } 41.8
From the previous results we see that planet that is farthest away is planet X
where we have used kepler's third law
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Suppose 3 mol of neon (an ideal monatomic gas) at STP are compressed slowly and isothermally to 0.19 the original volume. The gas is then allowed to expand quickly and adiabatically back to its original volume.
Required:
a. Find the highest temperature attained by the gas.
b. Find the lowest temperature attained by the gas.
c. Find the highest pressure attained by the gas.
d. Find the lowest pressure attained by the gas.
Answer:
a. 273 K b. 90.1 K c. 5.26 atm d. 0.33 atm
Explanation:
For isothermal expansion PV = constant
So, P₁V₁ = P₂V₂ where P₁ = initial pressure of gas = 1 atm (standard pressure), V₁ = initial volume of gas, P₂ = final pressure of gas and V₂ = final volume of gas,
So, P₁V₁ = P₂V₂
P₂ = P₁V₁/V₂
Since V₂/V₁ = 0.19,
P₂ = P₁V₁/V₂
P₂ = 1 atm (1/0.19)
P₂ = 5.26 atm
For an adiabatic expansion, PVⁿ = constant where n = ratio of molar heat capacities = 5/3 for monoatomic gas
So, P₂V₂ⁿ = P₃V₃ⁿ where P₂ = initial pressure of gas = 5.26 atm, V₂ = initial volume of gas, P₃ = final pressure of gas and V₃ = final volume of gas,
So, P₂V₂ⁿ = P₃V₃ⁿ
P₃ = P₂V₂ⁿ/V₃ⁿ
P₃ = P₂(V₂/V₃)ⁿ
Since V₃ = V₁ ,V₂/V₃ = V₂/V₁ = 0.19
1/0.19,
P₃ = P₂(V₂/V₃)ⁿ
P₃ = 5.26 atm (0.19)⁽⁵/³⁾
P₃ = 5.26 atm × 0.0628
P₃ = 0.33 atm
Using the ideal gas equation
P₃V₃/T₃ = P₄V₄/T₄ where P₃ = pressure after adiabatic expansion = 0.33 atm , V₃ = volume after adiabatic expansion, T₃ = temperature after adiabatic expansion P₄ = initial pressure of gas = P₁ = 1 atm , V₄ = initial volume of gas = V₁ and T₄ = initial temperature of gas = T₁ = 273 K (standard temperature)
P₃V₃/T₃ = P₄V₄/T₄
T₃ = P₃V₃T₄/P₄V₄
T₃ = (P₃/P₄)(V₃/V₄)T₂
Since V₃ = V₄ = V₁ and P₄ = P₁
V₃/V₄ = 1 and P₃/P₄ = P₃/P₁
T₃ = (P₃/P₁)(V₃/V₄)T₂
T₃ = (0.33 atm/1 atm)(1)273 K
T₃ = 90.1 K
So,
a. The highest temperature attained by the gas is T₁ = 273 K
b. The lowest temperature attained by the gas = T₃ = 90.1 K
c. The highest pressure attained by the gas is P₂ = 5.26 atm
d. The lowest pressure attained by the gas is P₃ = 0.33 atm
Assume you are a trainer at a local gym. There is evidence that intense or exhaustive physical exercise can increase the production of free radicals. Antioxidants can be used to combat the damage caused by free radicals. One of your competitive athletes has heard bits and pieces of this information and asks you more about it. How would you counsel him?
Use language that the average person will understand, respond to this athlete and be sure to include the following information as a part of your response:
What is meant by oxidation and why can it be damaging to cells?What are free radicals?Why do we produce free radicals if they can damage my body?What are antioxidants? How do antioxidants combat free radicals?What foods are high in antioxidants?Should your friend buy an antioxidant supplement?
Why is the mass of an atom's electrons not included in the atom's mass number?
A. The electrons move so fast that their mass cannot be measured.
B. The electrons' negative charge cancels out their masses.
C. The electrons' mass is represented in the atomic number.
D. The electrons are much less massive than the rest of the atom.
Answer: A: the electrons move so fast that their mass cannot be measured
Explanation: because they are so fast scientist and other people cannot measure them
Answer:
A
Explanation:
Question 8 (5 points)
What is indicated by the slope of an acceleration vs. time graph?
The maximum speed of the object
The total displacement of the object
The change in position of the object
The velocity of an object
The velocity of an object is indicated by the slope of an acceleration vs. time graph
What is velocity of an object?Acceleration is how much velocity changes,from the definition here, the slope of the graph tells us how quickly the object's velocity is changing over time.
To dtermine object's velocity from an acceleration vs. time graph, you would have to carry out the integration of the acceleration to get the object's velocity as a function of time.
Hence the last option is the corrcet answer here
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Answer:The velocity of an object
Give two examples of situations or application where electronic circuits are used
Q5. Which of the following is NOT true about gravity?
A). The more massive two objects are, the greater the
gravitational force between them.
.B). Gravitational force between two objects depends
only on the mass of the larger object.
.C). Gravitational force between two objects depends on
the distance between them.
.D). People can jump higher on the moon than on Earth
because the gravitational force between a person and
the moon is lower than the gravitational force between
a person and the Earth.
.E). A gravitational force exists between the moon and
the sun.
C. Gravitational force between two objects depends
only on the mass of the larger object is NOT true about gravity
What is Gravitational force?Gravity is a fundamental interaction that causes all entities with mass or energy to attract one other.
In nature, there are no other sorts of gravity. This indicates that based on their masses and the distance between their centers, there is only one form of gravitational force pulling the two bodies together.
Gravity is the weakest force known in nature and is a form of central force.
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Looking at the position of the house and the tree, if the man ran starting from the house going
to
the tree in 8 seconds, the average velocity would be?
Average velocity of man is 2 m/s
Given that;
Distance between tree and house = 16 m
Time taken = 8 seconds
Find:
Average velocity
Computation:
Average velocity = Total distance cover / Time taken
Average velocity = Distance between tree and house / Time taken
Average velocity = 16 / 8
Average velocity = 2 m/s
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What is evidence used by Galileo to disprove Aristotle and Ptolemy?
Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
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A car with a mass of 1800 kg is traveling at a speed of 50.0 km/h on an icy road when it collides with a stationary truck. The two vehicles stick together after the collision, and their speed after the collision is 10 km/h. What is the mass of the truck?
The two vehicles stick together after the collision, and their speed/velocity after the collision is 10 km/h. The mass of the truck is 7200 kg.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Given in the question a car with a mass of 1800 kg is traveling at a speed of 50.0 km/h on an icy road when it collides with a stationary truck. The two vehicles stick together after the collision, and their speed after the collision is 10 km/h. mass of truck is
Using conservation of momentum equation,
\(m_{1}v_{i} + M_{2} V_{i} = (m_{1} + M_{2}) V_{f}\)
here,
\(m_{1}\) = 1800 kg mass of car
\(v_{1}\) = 50 km/h velocity of car
\(V_{i}\) = 0 as the truck is stationary.
\(V_{f}\) = 10 km/h is the velocity when two vehicles stick together after the collision
1800.50 + 0 = (1800 + \(M_{2}\)).10
\(M_{2}\) = 7200 kg.
The mass of the truck 7200 kg.
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Particle A has less mass than particle B. Both are pushed forward across a frictionless surface by equals forces for 1 s. Both start from rest.
a. Compare the amount of work done on each particle. That is, is the work done on A greater thane, less than, or equal to the work done on B? Explain.
b. Compare the impulses delivered to particles A and B. Explain.
c. Compare the final speeds of particles A and B. Explain.
An Particle a has Weston practical.
What is Friction?
The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab).
According to the book Soil Mechanics(opens in new tab), scientists started putting together the laws governing friction in the 1400s.
However, because the interactions are so complex, characterizing the force of friction in various circumstances typically requires experiments and can't be derived from equations or laws alone. There are numerous exceptions to every frictional general rule.
Therefore, An Particle a has Weston practical.
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A current of 17.o mA is maintained in a single circular loop with a circumference of 2.0 m .A magnetic field of 0.80 T is directed parallel to the plane of the loop. What is the magnitude of the torque exerted by the magnetic field on the loop?
The magnitude of the magnetic field's torque on the loop is 0.034 Nm.
When a current-carrying conductor is put in a magnetic field, it experiences a force known as the Lorentz force, which is proportional to the magnetic field's strength and the current running through the conductor. As a result of this force, a torque is imparted to the conductor, which tends to turn it around an axis perpendicular to the conductor's plane.
The following formula can be used to calculate the torque operating on the conductor:
= NIABsin
where is the torque, N is the number of turns, I is the current, A is the area of the loop, B is the strength of the magnetic field, and is the angle between the magnetic field and the plane of the loop.
If the magnetic field is parallel to the plane of the loop, then θ is equal to 0°, and sinθ is equal to 0.
As a result, the torque formula can be shortened to: = NIAB.
When the numbers for N, I, A, and B are entered into this formula, the magnetic field's torque on the loop is found to be:
= (1)(0.017 A)(π(1 m)²)(0.80 T)τ = 0.034 Nm.
As a result, the magnitude of the magnetic field's torque on the loop is 0.034 Nm.
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A 30.0 kg box hangs from a rope. What is the tension (in N) in the rope if the box has an initial velocity of 2.0 m/s and is slowing down at 2.0 m/s2?
Answer:
360 N
Explanation:
m = 30kg u = 2 m/s a = -2m/s/s
Since the object has an initial velocity of 2 m/s and acceleration of -2 m/s/s
the object will come to rest in 1 second but the force applied in that one second can be calculated by:
F = ma
F = 30 * -2
F = -60 N (the negative sign tells us that the force is acting downwards)
Now, calculating the force applied on the box due to gravity
letting g = -10m/s/s
F = ma
F = 30 * -10
F = -300 N (the negative sign tells us that the force is acting downwards)
Now, calculating the total downward force:
-300 + (-60) = -360 N
Hence, a downward force of 360 N is being applied on the box and since the box did not disconnect from the rope, the rope applied the same amount of force in the opposite direction
Therefore tension on the force = 360 N
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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