The velocity of the airplane will be 301.85 meters per second.
What is the velocity?The velocity of the airplane is given as,
v = m√(γRT)
Where γ is the polytropic index (1.14), R gas constant, and T is the temperature.
An airplane is flying at a standard altitude of 5 km. A pitot tube mounted at the nose measures pressure of 0.957 bar.
From the table, the static pressure (p) and static temperature (T) will be 54019.91 Pa and 255.5 K.
Then the static density is given as,
P = p / RT
P = 54019.91 / (287 x 255.5)
P = 0.737 kg / m³
We know that the formula
\(\begin{aligned} \left ( \dfrac{P_o}{P} \right )^{\frac{\gamma -1}{\gamma }} &= 1 + \dfrac{\gamma - 1}{2}m^2\\\\\left ( \dfrac{0.957 \times 10^5}{54019.91} \right )^{\frac{1.4 -1}{1.4}} &= 1 + \dfrac{1.4- 1}{2}m^2\\ \end{aligned}\)
On simplifying, we have
m = 0.9421 kg
Then the velocity of the airplane is given as
v = 0.9421 × √(1.4 × 287 × 255.5)
v = 301.85 m/s
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Give reason: 1. Copper wires are used in domestic circuits. 2. Tungsten is used as filament in bulb. 3. Filament bulbs are replaced by CFL and LEDs
Answer:
your mom
Explanation:
Answer:
1.Copper electrical wires are safer to use than wires made of most other conductive metals because they are resistant to heat. As you can see, copper is the preferred metal for electrical wires for several reasons. It has high electrical conductive; it's inexpensive; it's ductile; and it's thermal resistant.
2.Tungsten is used for making filament of an electric bulb due to the following reasons: Being an alloy it has a very high melting point. It has very high resistivity so it does not burn easily at room temperature. The lamp glows at high temperatures.
3.Confused about choosing between CFL bulbs vs. LED bulbs? Since 2014, government regulations have been pushing consumers to replace familiar incandescent light bulbs with more energy-efficient compact fluorescent lamp (CFL) and light-emitting diode (LED) bulbs.Advances in both CFL and LED technologies have expanded consumer choice — yet make evaluating your options a little more complex. Knowing how different kinds of light bulbs stack up against each other will help you not only get the right lighting for any given space but also save energy in the process.
a ______ energy transition state of hydrogen abstraction by chlorine leads to a ______ reaction compared to bromine.
A high-energy transition state of hydrogen abstraction by chlorine leads to a more exothermic reaction compared to bromine.
An exothermic reaction is a reaction in which energy is released in the form of light or heat. Thus in an exothermic reaction, energy is transferred into the surroundings rather than taking energy from the surroundings as in an endothermic reaction.
A higher energy transition state of hydrogen abstraction by chlorine leads to a faster reaction compared to bromine.
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A higher energy transition state of hydrogen abstraction by chlorine leads to a slower reaction compared to bromine.
Explanation:
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If we aim a radio telescope at a distant spiral arm of the Milky Way Galaxy, we will probably observe a 21-cm line. If we point a large optical telescope at this same region, we will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal. Why not
Answer:
Because of the interstellar dust and interior location of the solar system.
Explanation:
We will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal if we point a large optical telescope to the region because, the interstellar dust obscures the location of the spiral arm of the Milky way galaxy and this makes neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.
Also, the interior location of the solar system also makes the neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.
So, the interstellar dust and the interior location of the solar system makes it difficult to detect the neutral hydrogen that gives rise to the 21-cm radio signal with a large optical telescope.
a lapidary cuts a diamond so that the light will refract at an angle of 17.0° to the normal. what is the index of refraction of the diamond when the angle of incidence is 45.0°?
The index of refraction of air, which is approximately 1.000: n_(2) = (1.000 × sin(45.0°)) / sin(17.0°). This expression will give us the index of refraction of the diamond.
To calculate the index of refraction of the diamond, we can use Snell's law, which relates the angles of incidence and refraction to the indices of refraction of the two media involved. Snell's law can be expressed as follows:
n1 × sin(θ_(1)) = n2 × sin(θ_(2))
where:
n_(1) is the index of refraction of the initial medium (in this case, air),
θ_(1) is the angle of incidence,
n_(2) is the index of refraction of the second medium (in this case, diamond),
θ_(2) is the angle of refraction.
We can rearrange the equation to solve for the index of refraction of the diamond, n_(2):
n_(2) = (n_(1) × sin(θ_(1))) / sin(θ_(2))
Given that the angle of incidence θ_(1) is 45.0° and the angle of refraction θ_(2) is 17.0°, we can substitute these values into the equation along with the index of refraction of air, which is approximately 1.000:
n_(2) = (1.000 × sin(45.0°)) / sin(17.0°)
This expression will give us the index of refraction of the diamond.
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Which best contrasts Newton's and Einstein's ideas?
Newton believed that mass tells objects how to move. Einstein believed that the curvature of space-time tells force how to
move objects.
Newton believed that force tells mass how to move. Einstein believed that the curvature of space-time tells velocity how to
change.
Newton believed that distance tells gravity how much force to exert. Einstein believed that distance tells space-time how to
curve.
Newton believed that mass tells gravity how much force to exert. Einstein believed that mass tells space-time how to curve.
Answer:
Newton believed that mass tells gravity how much force to exert. Einstein believed that mass tells space-time how to curve.
Explanation:
Isaac Newton believed that bodies on earth had a force of gravity pulling them down as a result of their masses.
Albert Einstein believed that the bodies were not pulled down but were moving around in a circular sphere/manner.
This confirms Newton believing that mass tells gravity how much force to exert and Einstein believing that mass tells space-time how to curve.
Answer:
first one is for the assignment second is for the quiz
Explanation:
Assignment - C.
Quiz - D.
What is the net force acting on a 52 kg object that has a velocity of 8.0 m/s and is moving in a circle of radius 1.6 m? a. 4000N b. 20880N c. 2500N d. 3500N
Given values are:
Mass, m = 52 kgVelocity, v = 8.0 m/sRadius, r = 1.6 mAs we know the formula,
→ \(\Sigma f = ma\)
or,
→ \(\Sigma f = \frac{mv^2}{r}\)
By putting the values, we get
\(= \frac{52\times 8^2}{1.6}\)
\(= \frac{52\times 64}{1.6}\)
\(= 2080 \ N\)
Thus the response above is appropriate.
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I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!
This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.
When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.
In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.
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find the resistance of a multiplier connected with milliammeter of resistance 10 ohms with a deflection of 10 milliamperes and the voltage of the circuit is 15 volts
A volleyball accelerates due to a constant force acting on it for 5 seconds, and it reaches a speed of 60 m/s. If the mass of the volleyball is 0.25 kg, what is the constant force?
The constant force acting on a volleyball to accelerate it to a speed of 60 m/s for 5 seconds is 75 N. The acceleration of an object is given by the following formula: a = F/m Where, a is acceleration, F is force, and m is mass.
The force required to accelerate an object is given by: F = ma
We can use the above two formulas to find the constant force acting on a volleyball with a mass of 0.25 kg, which is accelerated to a speed of 60 m/s for 5 seconds.
F = maF
= (0.25 kg) x (60 m/s ÷ 5 s)F
= (0.25 kg) x (12 m/s²)F
= 3 N x 25F
= 75 N
Therefore, the constant force acting on the volleyball is 75 N.
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S A helium-neon laser emits a beam of circular cross section with a radius r and a power P. (c) Find the momentum carried by a length l of the beam.
The momentum carried by a length l of the beam can be calculated using the formula momentum = P × (l / c).
To find the momentum carried by a length l of the beam, we need to consider the properties of the laser beam. The beam has a circular cross section with a radius r and a power P.
The momentum of the beam can be calculated using the formula: momentum = power × time. In this case, we need to find the momentum carried by a length l of the beam.
Assuming that the beam is uniform along its length, we can calculate the momentum by multiplying the power P by the time it takes for the beam to traverse the length l.
Since the speed of light in a vacuum is constant, the time it takes for the beam to traverse the length l is equal to l divided by the speed of light.
Therefore, the momentum carried by a length l of the beam is given by the formula: momentum = P × (l / c), where c is the speed of light.
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when a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied: group of answer choices (b) there is a large increase in the magnetic induction (b) (a) the magnetic induction (b) is decreased both a
When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, the magnetic induction (B) is increased.
Ferromagnetic materials, such as iron, nickel, and cobalt, have unique properties that make them highly responsive to magnetic fields. When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, several factors contribute to the increase in magnetic induction (B):Alignment of Magnetic Domains: In the absence of an external magnetic field, the magnetic domains within a ferromagnetic material are randomly oriented, resulting in a net magnetic moment of zero. However, when a magnetic field is applied, the domains align themselves in the direction of the field, leading to an increase in the overall magnetic induction.Magnetic Saturation: Ferromagnetic materials have a saturation point, beyond which further increase in the magnetic field does not significantly increase the magnetic induction. This saturation point is typically higher than that of other magnetic materials, allowing ferromagnetic materials to exhibit a larger increase in magnetic induction.Amplification of Magnetic Field: The presence of a ferromagnetic material within an electromagnetic coil enhances the magnetic field generated by the coil. This phenomenon is known as magnetic amplification or magnetic flux concentration. The ferromagnetic material acts as a magnetic conductor, guiding and intensifying the magnetic field lines, resulting in a larger magnetic induction.In contrast, option (a) stating that the magnetic induction (B) is decreased is incorrect. When a ferromagnetic material is subjected to an external magnetic field, the magnetic induction increases due to the alignment of magnetic domains and the amplification of the magnetic field.Therefore, the correct answer is:
(a) There is a large increase in the magnetic induction (B)
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Atom A has an atomic number of 19 and a mass number of 40. Atom B has an atomic number of 20 and a mass number of 40. Which of these is an accurate statement?
A) Atom A has more protons than Atom B.
B) Atom A has one less proton and one more neutron than Atom B.
C) Atom A has an extra nucleon compared to Atom B.
D) Atom A has one more proton and one more electron than Atom B
Answer:
B
Explanation:
how fast is the cheetah running in m/s
With 4.3 m/s velocity, is the cheetah running.
velocity= distance/time
distance=27.6 m
time=6.3 s
velocity=27.6 m/6.3 s
velocity=4.3 m/s
A vector number known as velocity describes "the pace at which an item changes its location." Imagine a person moving quickly, taking one stride ahead, one step back, and then beginning from the same place each time. A vector quantity is velocity. As a result, velocity is aware of direction. One must consider direction while calculating an object's velocity. Saying that an item has a velocity of 55 miles per hour is insufficient. The direction must be included in order to adequately characterize the object's velocity. Simply said, the velocity vector's direction corresponds to the motion of an item.
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a spring of spring constant k is attached to a block of mass m. the spring moves the block through a displacement x. how can you calculate how much work the spring does on the block?
An endless spring A block with mass m is connected to a constant k. The block undergoes a displacement x as a result of the spring. then, by using\((K+U)_{i} =(K+U) _{f}\), we can determine how much effort the spring performs on the block
It is used to determine a spring's stability or instability and, as a result, what system it should be used in. It reworks Hooke's Law and is mathematically expressed as k = - F/x.
where k is the spring constant, F is the force applied over x, and x is the displacement generated by the spring in N/m. Fs = -kx, where F is the spring's restoring force, k is the spring constant, and x is the displacement, is the formula utilized by the Hooke's Law Calculator.
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Problem
Position The figure shows a motorcyclist traveling east along a straight
road. After passing point B, the cyclist continues to travel at an average
velocity of 18 m/s east and arrives at point C2.8 s later. What is the
position of point ?
Answer:
s = 50.4 m
Hence, the point C is 50.4 m towards east from point B
Explanation:
Since, the motorcyclist travels at a constant speed in straight line towards east after point B. Therefore, we can use the following equation in this case:
s = vt
where,
s = distance covered = position of point C = ?
v = uniform speed of motorcyclist = 18 m/s
t = time interval = 2.8 s
Therefore,
s = (18 m/s)(2.8 s)
s = 50.4 m
Hence, the point C is 50.4 m towards east from point B
25 n object requires a 5. 0 n to start moving over a horizontal surface. What is the coefficient of static friction?.
Answer:
μ=1/5=0.2
Explanation:
using the formula
Fs=Fn*μ
Where
Fs is the static force
Fn = Normal force
μ= coefficient
so if Fn=25n
and it requires 5 n to start moving, means the max Fs is 5n
5=25μ
μ=5/25
μ=1/5=0.2
. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.
Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :
Step 1: Calculate the velocity using the equation:
\(v = u + at\)
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity (0 m/s, as the car starts from rest)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)
Step 2: Calculate the distance traveled using the equation:
\(s = ut + \frac{1}{2}at^2\)
where:
- \(s\) is the distance traveled
- \(u\) is the initial velocity (0 m/s)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)
Now, let's simplify these equations:
\(v = 3 \times 50\)
\(s = \frac{1}{2} \times 3 \times 50^2\)
Calculating the results:
\(v = 150\) m/s
\(s = 3750\) meters
Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.
A dog running with an initial speed of 7.5 m/s comes to a stop in 5 seconds. What is the
dog's displacement?
Answer:
4.6
Explanation:
If a dog running with an initial speed of 7.5 m/s comes to a stop in 5 seconds, then the displacement of the dog would be 37.5 m / s .
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.
As given in the problem If a dog running with an initial speed of 7.5 m/s comes to a stop in 5 seconds, then we have to find the displacement of the dog.
The displacement of the dog = 7.5 × 5
= 37.5 m /s
Thus , If a dog running with an initial speed of 7.5 m/s comes to a stop in 5 seconds, then the displacement of the dog would be 37.5 m / s .
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A hollow metal sphere has 6 cm and 10 cm inner and outer radii, respectively. The surface charge density on the inside surface is -100 nC/m2. The surface charge density on the exterior surface is 100 nC/m2.
What are the strength and direction of the electric field at points 4, 8, and 12 cm from the center?
By applying Gauss's Law and using the appropriate Gaussian surface for each point, you can find the strength and direction of the electric field at points 4 cm, 8 cm, and 12 cm from the center of the hollow metal sphere.
Gauss's Law states that the electric field through a closed surface is proportional to the total charge enclosed by the surface.
In this case, we have a hollow metal sphere with different surface charge densities on the inside and outside surfaces. To find the electric field at the specified points, we need to consider the contributions from both the inner and outer surface charges.
To calculate the electric field at a point outside the sphere, such as 4 cm, 8 cm, or 12 cm from the center, we can consider a Gaussian surface in the form of a sphere centered at the center of the hollow metal sphere. The radius of this Gaussian surface should be larger than the outer radius of the metal sphere.
Since the charge on the inner surface of the hollow sphere is negative (-100 nC/m^2), it will create an electric field directed towards the inside of the sphere. On the other hand, the charge on the outer surface of the sphere is positive (100 nC/m^2), creating an electric field directed away from the sphere.
To determine the electric field at a point outside the sphere, we only need to consider the contribution from the outer surface charge, as the inner surface charge is shielded by the metal.
Let's calculate the electric field at the specified points using Gauss's Law:
1. At 4 cm from the center:
The electric field due to the outer surface charge will be radially outward.
To calculate the electric field at this point, we can consider a Gaussian surface of radius 4 cm centered at the center of the hollow sphere.
The electric field at this point can be calculated using the formula:
Electric field = (Surface charge density * Gaussian surface area) / (ε0),
where ε0 is the vacuum permittivity.
2. At 8 cm from the center:
The electric field due to the outer surface charge will also be radially outward.
To calculate the electric field at this point, we can consider a Gaussian surface of radius 8 cm centered at the center of the hollow sphere.
The electric field at this point can be calculated using the same formula mentioned above.
3. At 12 cm from the center:
The electric field due to the outer surface charge will still be radially outward.
To calculate the electric field at this point, we can consider a Gaussian surface of radius 12 cm centered at the center of the hollow sphere.
Again, we can use the same formula to calculate the electric field.
By applying Gauss's Law and using the appropriate Gaussian surface for each point, you can find the strength and direction of the electric field at points 4 cm, 8 cm, and 12 cm from the center of the hollow metal sphere.
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What is a gravity anomaly?
What causes gravity anomalies to occur?
How would you expect the gravity anomaly of a buried dense
sphere to change if the sphere is buried at different depths?
A gravity anomaly refers to a variation in the strength of gravitational acceleration at a specific location on Earth's surface. These anomalies can be caused by differences in the density distribution of subsurface materials. When a dense sphere is buried at different depths, the gravity anomaly it produces changes in magnitude and spatial extent.
A gravity anomaly occurs when there are variations in the gravitational field strength at different points on Earth's surface. The standard value for gravitational acceleration is approximately 9.8 meters per second squared (m/s²). However, due to variations in the distribution of subsurface materials, the actual gravitational acceleration can deviate from this standard value, resulting in gravity anomalies.
Gravity anomalies are caused by differences in the density of subsurface materials. The gravitational force experienced by an object is directly proportional to the mass of the object. Therefore, regions with higher densities have a greater gravitational attraction, leading to a positive gravity anomaly. Conversely, regions with lower densities exhibit a weaker gravitational pull, resulting in a negative gravity anomaly.
When a dense sphere is buried at different depths, the gravity anomaly it produces changes in several ways. Firstly, as the sphere is buried deeper, the gravitational effect of its mass is distributed over a larger area, leading to a decrease in the magnitude of the gravity anomaly. Secondly, the spatial extent of the anomaly decreases as the sphere moves deeper underground since its influence is more localized. Therefore, the gravity anomaly of a buried dense sphere diminishes in magnitude and becomes more confined as the depth of burial increases.
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Question:
Which of the following has the most kinetic energy?
Answer Choices:
A. a 25-kg fish tank sitting on a table
B. a 50-g fish swimming in a fish tank
C. a 7,500-kg car parked on a steep hill
D. a 50-kg boulder suspended from a cliff
Answer:
B: a 50-g fish swimming in a fish tank.
Explanation:
I chooses B because kinetic energy is energy present in moving bodies or objects. And the fish swimming has kinetic energy because it is moving
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Which of the following theories argues that our life-friendly universe is best explained by an intelligent Designer?
A.) Intelligent design
B.) Progressive creationism
C.) Scientific naturalism
D.) Theistic evolution
Answer:
I think it's c but don't quote me on it
What will be the acceleration of the 12-kg object if it is acted upon by a force of 60n?.
The acceleration of the object is 5 m/s². The result is obtained by using the Newton's second law.
What is Newton's second law?The Newton's second law states that "The acceleration is directly proportional to the net force acting on an object and inversely proportional to the object's mass." It can be expressed as
a = ∑F/m
Where
∑F = net forcea = accelerationm = object's massAn object with a mass of 12 kg is acted upon by a force of 60 N.
Find the acceleration of the object!
Using the Newton's second law formula, we get acceleration.
a = ∑F/m
a = 60/12
a = 5 m/s²
Hence, the acceleration of the object is 5 m/s².
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Pls help me I need help thanks.
Answer: The Answer Is A
Explanation:
Calculate the wavelength of the sound wave that are produced by tuning fork marked C - 264 Hz. Take the speed of sound in air as 343 metres per second
Can someone help me with this question
formula
v = fλ
v = velocity
f=frequency
λ = wavelength
Speed (meters/second) = Wavelength (meters) x Wave Frequency (hertz) (1/seconds)
343 meters/second = x meters times 264 hertz (1 /second)
x (wavelength) = 343/264 = 343 ÷ 264 =
1.29924242 meters
1.3 meters = wavelength = answer
https://www.scienceworld.ca/resource/sound-vibration-vibration-vibration
Hertz (1 Hz = 1 vibration per second)
The number of vibrations per second is known as the frequency, measured in Hertz (1 Hz = 1 vibration per second).
These vibrations enter the outer ear and cause the eardrum to vibrate too
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How much work is done when mass of 3kg(weighing 30N)is lifted vertically through 6m?
Answer:
180 [J].
Explanation:
1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;
2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;
3) then the required work [W]:
W=mg*(h₂-h₁)=30*6=180 [J].
Which changes in surface water movement are likely
to occur when vegetation is removed from the side of
a hill?
A) infiltration decreases and runoff decreases
B) infiltration decreases and runoff increases
C) infiltration increases and runoff decreases
D) infiltration increases and runoff increases
Answer:
infiltration decreases and runoff increase
Explanation:
The changes in surface water movement which is likely to occur when vegetation is removed from the side of a hill is infiltration decreases and runoff increases.
What is surface overflow?Surface overflow is the flow of water which take place on the surface of the ground. The extra water due to rain or flood arises on the ground or at the surface, flows in the nearby lacks or ponds.
Now if the vegetation is removed, great amount of water started to come from the hills. The result of it, more water started to overflow on the land of the surface. This way the runoff increases.
Infiltration is the way by which the ground level water enters into the soil of the earth.
Now, if the vegetation is removed, a lot of amounts of water started to come from the hills. This excess amount of water does not enter in to the soil of the earth.
The changes in surface water movement which is likely to occur when vegetation is removed from the side of a hill is infiltration decreases and runoff increases.
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the three charges hang from strings of the length and angle as shown. the charges are all at the same height. what is the magnitude of the electric force on the right charge?
The product of the magnitudes of the charges and the square of the distance between them determines the magnitude of the electrostatic force F between two point charges, q1 and q2, and vice versa.
The magnetic field B and the charge q's velocity v are both perpendicular to the force. F = qvB sin, where is the angle of 180 degrees between the velocity and magnetic field, gives the force's magnitude.
The product of the magnitudes of the charges and the square of the distance between them determines the magnitude of the electrostatic force F between two point charges, q1 and q2, and vice versa.
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What could damage the eardrum and bones of the middle ear?
a) earwax
b) harmful noise
c) hammer
d) anvil
Answer:
B or D
Explanation:
I wanna say B but I don't really know if it's a trick question
my explanation for D is that anvils are usually 110 decibles and ear drums usually are damaged when exposed to 82dbs or higher at a consistant rate so I'd imagine that'd be the answer I hoped this helped
Answer:
the answer is B
Explanation:
Any harmful noises can be bad. yes, an Anvil and Hammer can be bad but so can explosions and gun fire and having music to loud
What is a source of a Sound wave???
Answer:
A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium such as air, water, or any other liquid or solid matter, as it propagates away from the source of the sound. The source is some object that causes a vibration, such as a ringing telephone, or a person's vocal chords.
Explanation: