An element with the electron configuration [noble gas]ns2(n - 1)d10np3 has ____________ valence electrons.

34.5 grams of C can be produced during this reaction  if the molar mass

of compound C is 46 g/mol.

The balanced chemical equation for the given reaction is:

2A + 2B - 3C

From the equation, we can see that 2 moles of A react with 2 moles of B of to produce 3 moles of C. Therefore, 0.5 moles of A will react with (0.5/2) * 2 = 0.5 moles of B to produce of (0.5/2) * 3 = 0.75 moles of C.

To calculate the mass of C produced, we can use the formula:

mass = moles * molar mass

Substituting the values, we get:

mass of C = 0.75 moles * 46 g/mol

= 34.5 g

Therefore, 34.5 grams of C can be produced during this reaction.

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Maddy made the error of multiplying by 10 rather than 100, which produced an answer that was 10 times off in the conversion of units.

The work of Maddy is flawed. We must multiply the value in grammes by 100 to convert it to centigrammes. Maddy gave the wrong answer of 7.5 cg by multiplying the weight in grammes by 10 rather than 100.

In order to convert 0.75 grammes to centigrammes, use the following formula:

100 cg/g x 0.75 g equals 75 cg

Consequently, 0.75 grammes is 75 centigrammes. Maddy made the error of multiplying by 10 rather than 100, which produced an answer that was 10 times off.

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The VSEPR (Valence Shell Electron Pair Repulsion) theory describes the arrangement of electron pairs around a central atom in a molecule, and the VSEPR number represents the total number of electron pairs around the central atom, including both bonding pairs and lone pairs.The VSEPR number can be determined from the Lewis structure of the molecule, which shows the arrangement of atoms and lone pairs around the central atom. The first two digits of the VSEPR number correspond to the number of bonding pairs and lone pairs, respectively, around the central atom.To determine the third digit of the VSEPR number, you need to consider the shape of the molecule. The shape is determined by the repulsion between electron pairs, which is strongest between lone pairs and decreases in the order lone pair-lone pair > lone pair-bonding pair > bonding pair-bonding pair.The third digit of the VSEPR number indicates the shape of the molecule according to the following scheme:1: linear shape2: trigonal planar shape3: tetrahedral shape4: trigonal bipyramidal shape5: octahedral shapeThus, to determine the third digit of the VSEPR number, you need to determine the shape of the molecule based on the number of electron pairs and their relative positions. This can be done by applying the VSEPR theory and considering the repulsion between electron pairs. Alternatively, you can consult a table or chart that lists the shapes associated with different VSEPR numbers.

Answer:

Exercises Example 6. How Many Moles Of Carbon Atoms And How Many Carbon Atoms Are Contained In 1.0 G Of C,H,OH

Explanation:

The mass of the propane that would have the same number of carbon atoms is  0.63 g.

We know that we can be able to obtain the number of the carbon atoms by the use of the simple stoichiometry of the reaction as we have it in the question that we have been asked here.

We can see that we have the molar mass of the ethanol as we can see as 46 g/mol. We have to obtain the number of moles of the ethanol that we have in the compound as follows;

Number of moles = 1 g/ 46 g/mol = 0.022 moles

Number of the carbon atoms that we have is; 0.022 moles * 2 * 6.02 * 10^23 = 2.6 * 10^22 atoms

Now the number of the grams of the propane that we have is;

2.6 * 10^22  = x * 3 * 6.02 * 10^23

Where x is the number of moles present

x =  2.6 * 10^22 / 1.806 * 10^24

x = 1.44 * 10^-2 moles

x = 0.0144 moles

Given that the molar mass of the propane is 44 g/mol

mass  =  0.0144 moles * 44 g/mol

Mass = 0.63 g

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Answer:

antimony

Explanation:

The representation of the electrons in the shell is called electronic configuration.

The correct answer is antimony

The shell is as follows:-

These are the shells in which electrons are filled.

The total number of electrons is 2+2+6+2+6+2+10+6+2+7= 45

After calculating the electrons, the total number of electrons is 45 which is the atomic number of antimony.

Hence, antimony is the correct option.

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Considering the ideal gas law, the volume occupied by 3.25 moles of an ideal gas at a temperature of 18.00°C is 686.71 L.

An ideal gas is the behavior of those gases whose molecules do not interact with each other and move randomly. Under normal conditions and under standard conditions, most gases exhibit ideal gas behavior.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T), related by a simple formula called the ideal gas law:

P×V = n×R×T

Where:

In this case, you know:

Replacing in the ideal gas law:

1.13 atm×V = 3.25 mol× 0.8205 L.atm/K.mol× 291 K

Solving:

V = (3.25 mol× 0.8205 L.atm/K.mol× 291 K)÷ 1.13 atm

V= 686.71 L

Finally, the volume is 686.71 L.

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Answer:

Ni(NO3)2 is the limiting reactant.

Explanation:

- First, we balance the equation...

Ni(NO3)2 + 2 KOH --->  2 KNO3 + Ni(OH)2

- Second, we find the moles of each substance...

65g Ni(NO3)2 / 182.703g Ni(NO3)2 = 0.356 mol Ni(NO3)2

58g KOH / 56.1056g KOH = 1.034 mol KOH

- Third, to make the molar ratio equal to each other for comparison, we either multiply KOH by 1/2 or multiply Ni(NO3)2 by 2 to compare the number of moles; because the Ni(NO3)2 to KOH molar ratio is 1 to 2. Note that the multiplication of moles is only for comparison. We do not use these multiplied values. We use the values from step 2...

0.356 mol Ni(NO3)2 * 2 = 0.712 mol Ni(NO3)2

0.712 mol Ni(NO3)2 < 1.034 mol KOH ... Ni(NO3)2 is the limiting reactant.

Answer:

kais#+2==€=

so?×¢ ×€✓($8;™+38$-?

The molar mass of the sugar is obtained as  1.43 g/mol.

We know that the boiling point of a substance is one of the properties of the substances that could be called the colligative properties since they can be affected by the number of particles present.

We are told that the mass concentration of the substances w/w of the solution is 17% thus we have 17 g of the compound and 83 g of water. We can now get the number of moles of the substance as;

Number of moles = ?

Mass of the solution = 1000 mL * 1.015 g/mL = 1015 g or 1.015 Kg

Given that;

ΔT = K m i

ΔT = Boiling point elevation

K = Boing constant of water

m = molality of the solution

i = Van't Hoff factor

ΔT = 106 °C - 100°C

= 6 °C

Then;

6 = 0.515 *  17/MM * 1/1.015 * 1

Where MM = molar mass of the sugar

6 = 0.515 * 17/1.015 MM * 1

6 = 0.515 * 17/1.015 MM

6 = 8.755/1.015 MM

6 * 1.015 MM =  8.755

MM =  8.755/6 * 1.015

MM = 1.43 g/mol

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The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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Answer:

I don't know

Explanation:

that how old I am

Answer:

C

Explanation:

NP

Answer:

Answer:

Argon Ar is the element that satisfies the following condition

Answer:

Explanation:

Baking soda decomposes to produce sodium carbonate .

2NaHCO₃  = Na₂CO₃ + CO₂ + H₂O.

2 x 84 g          106 + 10 x 18  g

Molecular mass of Na₂CO₃ .10H₂O = 286

168 g baking soda  produces 286  g sodium carbonate

1.555g baking soda will produce 286 x 1.555 / 168

= 2.647 g

Percentage yield = actual yield / theoretical yield x 100

= ( .991 /2.647 ) x 100

= 37.43 %.

Answer:

The answer is C

3+

Explanation:

electron configuration =2,3

oxidation state of boron=3+

Answer:

c

Explanation:

The compound which increase the solubility of AgCl in water is determined on the basis of the process called common ion effect. The solubility of AgCl will be maximum in NH₃. The correct option is C.

The process common ion effect can be defined as the suppression of the dissociation of a weak electrolyte (weak acid or weak base) by the addition of some strong electrolyte containing common ion.

The solubility is defined as the maximum amount of solute that can be dissolved in a given solvent. Here AgCl dissociates into Ag⁺ and Cl⁻ ions. Both KClO₄ and NaCl contain Cl⁻ ions and thus common ion effect takes place. So the solubility decreases.

When AgCl is dissolved in NH₃ it forms a complex [ Ag (NH₃)₂]⁺. So it is highly soluble in NH₃. It is also soluble in water but not more than NH₃.

Thus the correct option C.

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Answer:

\(r_{Br_2}=2.1x10^{-4}M/s\)

Explanation:

Hello,

In this case, for the reaction:

\(5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)\)

Thus, via the rate proportions between Br⁻ and Br₂ for which the stoichiometric coefficients are 5 and 3 respectively, we can write:

\(\frac{r_{Br^-}}{-5} =\frac{r_{Br_2}}{3}\)

Hence, the rate of appearance of Br₂ turns out:

\(r_{Br_2}=\frac{3r_{Br^-}}{-5}=\frac{3*-3.5x10^{-4}M/s}{-5}\\ \\r_{Br_2}=2.1x10^{-4}M/s\)

Take into account that the rate of disappearance is negative for reactants.

Best regards.

As per the balanced reaction of Al and oxygen gas, 4 moles of Al needs 3 moles of oxygen gas. Hence, 7 moles of Al needs 5.2 moles of O₂.

Aluminum metal is more reactive towards oxygen and it forms oxides on its surface. The balanced chemical equation of the reaction between Al and oxygen is written as follows:

\(\rm 4 Al + 3O_{2}\rightarrow2 Al_{2}O_{3}\)

As per this reaction, 4 moles of aluminum needs 3 moles of oxygen molecule. Then, the number of moles oxygen molecule required to react with  7 moles of Al is :

no.of moles of O₂  = (7×3)/4 = 5.2

Therefore, 5.2 moles of oxygen gas is required to completely react with 7 moles of aluminum metal.

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Answer:

\(\Delta H_{f,C_3H_4}=276.8kJ/mol\)

Explanation:

Hello!

In this case, since the equation we use to model the heat exchange into the calorimeter and compute the heat of reaction is:

\(\Delta H_{rxn} =- m_wC_w\Delta T\)

We plug in the mass of water, temperature change and specific heat to obtain:

\(\Delta H_{rxn} =- (35000g)(4.184\frac{J}{g\°C} )(2.316\°C)\\\\\Delta H_{rxn}=-339.16kJ\)

Now, this enthalpy of reaction corresponds to the combustion of propyne:

\(C_3H_4+4O_2\rightarrow 3CO_2+2H_2O\)

Whose enthalpy change involves the enthalpies of formation of propyne, carbon dioxide and water, considering that of propyne is the target:

\(\Delta H_{rxn}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{f,C_3H_4}\)

However, the enthalpy of reaction should be expressed in kJ per moles of C3H4, so we divide by the appropriate moles in 7.00 g of this compound:

\(\Delta H_{rxn} =-339.16kJ*\frac{1}{7.00g}*\frac{40.06g}{1mol}=-1940.9kJ/mol\)

Now, we solve for the enthalpy of formation of C3H4 as shown below:

\(\Delta H_{f,C_3H_4}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{rxn}\)

So we plug in to obtain (enthalpies of formation of CO2 and H2O are found on NIST data base):

\(\Delta H_{f,C_3H_4}=3(-393.5kJ/mol)+2(-241.8kJ/mol)-(-1940.9kJ/mol)\\\\\Delta H_{f,C_3H_4}=276.8kJ/mol\)

Best regards!

Explanation:

We have to travel 2000 km at a speed of 73 miles per hour. We have to find how long will it take us to go to Key West.

speed = 73 mi/hr

distance = 2000 km

Before we solve the problem we have to convert the km to mi.

1 mi = 1.61 km

distance = 2000 km * 1 mi/(1.61 km)

distance = 1242 mi

Finally we can find the time.

Time = 1242 mi * 1 hr/(73 mi)

Time = 17.0 hr

Answer: The trip will take 17.0 hours.

Jonathon's experiment produced 24.5 grams of Al(OH), which is less than the predicted amount of 26.0 grams of AKOH. The discrepancy could be due to measurement errors, incomplete reaction.

What is discrepancy?

To determine the cause of the discrepancy, Jonathon should first review his experimental procedure and make sure that all measurements and calculations were performed accurately. He should also check that the reactants were mixed thoroughly and that the reaction was allowed to proceed to completion. If any errors or inconsistencies are identified, Jonathon should correct them and repeat the experiment to obtain more accurate results.

If the experimental procedure was carried out correctly and the discrepancy cannot be attributed to measurement errors, Jonathon should consider the possibility of impurities in the reactants. Even small amounts of impurities can affect the outcome of a chemical reaction, so it is important to use high-quality, pure chemicals in experiments whenever possible.

Overall, the most important thing for Jonathon to do in this situation is to carefully review his experimental data and methodology, and to identify any potential sources of error or uncertainty. By doing so, he can improve the accuracy and reliability of his results and draw more meaningful conclusions from his experiment.

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Answer: An electron con only exist in a limited number of quantized energy levels.

Explanation:

Sample A increased its average kinetic energy more than sample B when they were melted.

Kinetic energy is the type of energy which an item or particle has as a result of its motion. When work, which transfers the heat, is performed on an item by exerting a net force, that object accelerates and obtains kinetic energy.

Kinetic energy is indeed a characteristic of an object moving and particle that is affected by both its speed and its mass. Translation, rotation forward along axis, vibration, or indeed any combination of movements are all possible. Sample A increased its average kinetic energy more than sample B when they were melted.

Therefore,  sample A increased its average kinetic energy more than sample B when they were melted.

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The optimal pH for any buffer is when its pKa value coincides with the pH of the solution. A buffer typically functions well throughout a pH range that is 1 unit on either side of the pKa value.

The buffer in the pH range of 6.6 to 8.6 is made up of lactic acid, whose pKa value is 3.86, a PIPES buffer at pH 2.9 to 4.9, an acetic acid buffer at pH 5.8 to 7.8, and a HEPES buffer at pH 3.8 to 5.8. An amalgam of a weak acid and its conjugate base is known as a buffer solution. When basic or acidic components are added, it resists any pH shift. We can divide buffer solutions into two categories. Acidic and basic buffer solutions are the two categories into which we can divide buffer solutions. Because they produce unionised acid or base when they react with acid or base, a buffer solution resists any pH shift.

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To get the number of moles of Cu, look up its molar mass. The mole ratio of Cu to Ag is 1:1 if the reaction is Cu(s) + AgNO3(aq) CuNO3(aq) + Ag(s).

Copper has a molar mass of 63.5 g/mol. Page 15 Molar Mass: An Overview The atomic mass of a copper atom is 63.5 amu. Copper has a molar mass of 63.5 g/mol.

You need to know the product's mass and its molar mass (g/mol), which is the mass of one mole of the product, in order to calculate the moles of a substance. The product's molar mass is then divided by the product's mass.

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For a weak intermolecular bond, both the melting point and boiling point are lower.

A lesser energy is required to break bond of weak intermolecular forces while a greater energy is required to break bond of strong intermolecular forces.

E ∝ T

where;

A lesser energy means a lower temperature and a lower temperature will result in lower boiling point and melting point.

Thus, we can conclude that for a weak intermolecular bond, both the melting point and boiling point are lower.

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Answer:

0.877 mL

Explanation:

The box's density would be the ratio of the mass of the box and its volume
which is, (23.23/26.5) mL
or, 0.8766 mL
We must round this down to 3 significant figures,
which will be 0.877 mL