An object has a volume of 5 cm3 and a mass of 20 g. What is the density of the object?.

Answer:

1.2m/s

Explanation:

Using the law of conservation of energy

m1u1+m2u2 = (m1+m2)v

v is the common velocity after collision

Substitute the given values

3(2) + 2(0) = (3+2)v

6 + 0 = 5v

v = 6/5

v = 1.2m/s

Hence the velocity of the white ball after the collision is 1.2m/s

Answer:

1) True

2) None of the above

Explanation:

Q # 1:

Weight is actually the gravitational force or force of gravity. So, it's true.

Q # 2:

None of above because force of gravity can not be negative. In order to have a negative weight, the body has to be "repelled" by gravity.

\(\rule[225]{225}{2}\)

Hope this helped!

The angular velocity of the moon is approximately \(2.7 \times 10^{-6\) rad/s, which is the answer (d).

To calculate the angular velocity of the moon, we first need to understand what angular velocity is. Angular velocity is defined as the rate of change of angular displacement with respect to time. In simpler terms, it is the speed at which an object is rotating or moving in a circular path.

In this case, the moon is moving in a circular path around the Earth, so we can use the formula for angular velocity:

ω = θ / t

where ω is the angular velocity, θ is the angular displacement, and t is the time taken for one complete revolution.

We know that the time taken for one complete revolution of the moon around the Earth is 27.3 days. To convert this into seconds, we multiply by 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute:

t = 27.3 x 24 x 60 x 60 = 2,360,320 seconds

Now we need to find the angular displacement of the moon in one complete revolution. Since the moon moves in a circular path, its angular displacement is equal to the angle subtended by its path at the center of the earth. This angle is equal to 2π radians since the circumference of a circle is 2π times its radius (in this case, the distance from the moon to the center of the earth).

θ = 2π radians

Now we can substitute these values into the formula for angular velocity:

\(\omega = \frac{\theta}{t} = \frac{2\pi}{2{,}360{,}320} \approx 2.7\times 10^{-6}\ \mathrm{rad/s}\)

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The correct answer for how the albedo of polar regions affect insolation is: Low temperatures are maintained because of the high amount of reflection.

The albedo of a surface refers to its ability to reflect sunlight. Higher albedo means more sunlight is reflected, while lower albedo means more sunlight is absorbed. Polar regions, such as the Arctic and Antarctic, have high albedo due to the presence of ice and snow, which reflect a significant portion of incoming sunlight.

When sunlight hits the polar regions with high albedo, a large portion of it is reflected back into space rather than being absorbed by the surface. As a result, less solar energy is available to heat the surface, leading to lower temperatures in these regions.

Therefore, low temperatures are maintained in polar regions because of the high amount of reflection caused by their high albedo.

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There are several countries that have a coastline on the Pacific Ocean, including the United States, Canada, Mexico, Peru, Chile, Japan, and Australia.

However, if we had to pick just one country, the answer would be Chile. Chile is a narrow country located in South America that stretches over 4,000 km (2,485 miles) along the western coast of the continent. Its coastline borders the Pacific Ocean, making it the country with the longest coastline on the Pacific Ocean.

Thus, Chile is the country that has a coastline on the Pacific Ocean. It is important to note that there are other countries with a coastline on the Pacific Ocean as well.

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A. The peak current through the capacitor is 20.0 mA if the frequency of emf is doubled = 40 mA

B. If the emf peak voltage is doubled (at the original frequency) = 40 mA

C. The current if the frequency is halved and, at the same time, the emf is doubled = 20.0 mA

The peak current = 20.0 mA

{v / \(\frac{1}{wc}\) ) = wvc = 2πfvc = 20.0 mA = I₁

A. If the emf frequency is doubled

I₂ = 2f

= 2π (2fvc)

= 2 (2πfvc)

= 2 (20.0)

= 40 mA

B. If the emf peak voltage is doubled (at the original frequency):

v₂ = 2v₁

= 2πf (v₁) c

= 2π (2v) c

= 2 (2πfvc)

= 2 (20.0)

= 40 mA

C. The current if the frequency is halved and, at the same time, the emf is doubled:

f₂ = \(\frac{1}{2}\) f₁ and v₂ = 2v₁

= 2πf₁v₁c

= 2π ( \(\frac{1}{2}\) f₁) (2v) C

= 2πfvc

= 20.0 mA

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Answer:

A wave with a frequency of 10 Hz and a wavelength of  10 m should have a velocity of 100 meters per second (m/s)

Explanation:

The kinetic energy of another body having three times the mass of the given object will be 108 J

Kinetic energy-In physics, the kinetic energy of an object is the energy  it has due to  motion. It is defined as the work required to accelerate a body from a given mass from rest to a specified speed.

The kinetic energy of a body is given by \(K.E= \frac{1}{2}Mv^{2}\) (first equation)

Given K.E= 36J

Now the mass of second body is m=3M

also the second body is moving with the same speed v

So kinetic energy of second body K.E₂= \(\frac{1}{2}mv^{2} =\frac{1}{2}(3M)v^{2}\)=36×3

=108J (from first equation)

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According to the text, jupiter has a central pressure of 100 million bars, while earth has a central pressure of 4 million bars. Therefore, the pressure at the center of Jupiter is 25 times greater than that of the Earth.

Below are detailed explanations on Jupiter's pressure, Earth's pressure and how many times more pressure exists in the center of Jupiter compared to that of Earth.

Pressure of Jupiter: Jupiter is known for having the largest and strongest magnetic field among all the planets in the solar system. According to research, Jupiter’s central pressure can go up to 100 million bars. The pressure at Jupiter's core is around 4,000,000 atmospheres. This central pressure is what sustains the fusion process.

Pressure of Earth: Earth is composed of several layers, with the innermost layer being the core. The pressure at the center of the Earth is around 4 million bars. This is because the Earth is much smaller than Jupiter and has much less mass. This pressure is still much greater than the pressure that we experience at the surface.

How many times more pressure exists in the center of Jupiter compared to that of Earth?The pressure at the center of Jupiter is 25 times greater than that of the Earth.

We can calculate this as follows: Pressure in Jupiter's center = 100 million bars

Pressure in Earth's center = 4 million bars

Therefore, Pressure in Jupiter's center ÷ Pressure in Earth's center = 100 million bars ÷ 4 million bars = 25 times greater pressure exists in the center of Jupiter compared to that of Earth.

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Trigonometry allows to find the result for the question about the height of the mountain is:

Trigonometry allows finding relationships between the angles of a right triangle.

         \(tan \theta = \frac{y}{x}\)  

Where θ is the angle, y the opposite leg (height) and x the adjacent leg (horizontal distance).

In the attachment we can see a diagram of the system. They indicate that for x  distance the angle is 14.67º  

         tan 14.67 = \(\frac{y}{x}\)  

At the other point the angle is 10.38º.

        tan 10.38 = \(\frac{y}{x+15860}\)

We look for the horizontal distance (x) with these equations.

        x tan 14.67 = (x + 15860) tan 10.38

        x tan 14.67 / tan 10.38 = x + 15860

        x 1,429 = x + 15860

        x 0.429 = 15860

        x = \(\frac{15680}{0.429}\)

        x = 36955.3 ft

We calculate for the height.

        y = x tan 14.67

        y = 36955.3 tan 14.67

        y = 9674.4 ft

In conclusion using trigonometry we can find the result for the height of the mountain is:

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If you were on the Moon, observing the Earth over the course of a month, you would observe different phases of the Earth similar to the lunar phases we observe from Earth. However, the specific phases would be reversed compared to what we see on our planet. Let's explore the phases of the Earth as seen from the Moon:

1. New Earth: At the beginning of the lunar month, you would observe the New Earth phase. During this phase, the side of the Earth facing the Moon would be in complete darkness, as the sunlight is illuminating the opposite side of the Earth.

2. Waxing Crescent Earth: As the days progress, you would start to see a small crescent of illuminated Earth. This phase is known as the Waxing Crescent Earth. The illuminated portion would be gradually increasing, but still a small fraction of the whole Earth.

3. First Quarter Earth: As the Moon continues its orbit around the Earth, you would observe the First Quarter Earth phase. At this point, half of the Earth would be illuminated, similar to the First Quarter Moon we observe from Earth.

4. Waxing Gibbous Earth: Following the First Quarter Earth phase, you would see an increasingly larger portion of the Earth illuminated. This phase is called the Waxing Gibbous Earth. The illuminated part would be more than half but not yet fully illuminated.

5. Full Earth: Approximately halfway through the lunar month, you would witness the Full Earth phase. During this phase, the entire side of the Earth facing the Moon would be fully illuminated, similar to the Full Moon as seen from Earth.

6. Waning Gibbous Earth: After the Full Earth phase, you would observe a gradual decrease in the illuminated portion. This phase is known as the Waning Gibbous Earth.

7. Third Quarter Earth: Following the Waning Gibbous Earth phase, you would observe the Third Quarter Earth phase. At this point, again, half of the Earth would be illuminated, resembling the Third Quarter Moon observed from Earth.

8. Waning Crescent Earth: As the lunar month nears its end, you would witness a shrinking crescent of illuminated Earth, similar to the Waning Crescent Moon phase.

9. New Earth: Finally, the lunar month would conclude with another New Earth phase, where the side of the Earth facing the Moon would be in darkness, as the sunlight is primarily illuminating the opposite side.

These phases of the Earth as observed from the Moon would occur due to the relative positions and interactions between the Sun, Earth, and Moon during their respective orbits.

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Answer:

Media literacy creates a conscious awareness, the ability to understand, analyze, the messages various media like the newspapers, the radio, that is for the consumer, and it also promotes how best media create information for production.

While information literacy and technology literacy differs from other literacy asked in the question above, as information literacy and technology could be used when describing getting information through adequate research and further dishing out this available information so as to effectively use the information with the aim to solve problems, create awareness, or educate, through technologies such as for example, email.

Lastly, media and information literacy differ in terms of use from the other two explained above, as media and information literacy describes discerning information credibility, accuracy, and objectivity of sources they come from, and it shows people how important it is to have credible information to make informed judgments and the ethical use of the information they consume.

Answer:

Q = 2.95*10^5 kJ

Explanation:

In order to calculate the energy required to melt the cooper, you first calculate the energy required to reach the boiling temperature. You use the following formula:

\(Q_1=mc(T_b-T_1)\)     (1)

m: mass of cooper = 540 kg

c: specific heat of cooper = 390 J/kg°C

Tb: boiling temperature of cooper = 1080°C

T1: initial temperature of cooper = 20°C

You replace the values of the parameters in the equation (1):

\(Q_1=(540kg)(390\frac{J}{kg.\°C})(1080\°C-20\°C)=2.23*10^8J\)

Next, you calculate the energy required to melt the cooper by using the following formula:

\(Q_2=mL_f\)         (2)

Lf: melting constant of cooper = 134000J/kg

\(Q_2=(540kg)(134000\frac{J}{kg})=7.24*10^7J\)

Finally, the total amount of energy required to melt the cooper from a temperature of 20°C is the sum of Q1 and Q2:

\(Q=Q_1+Q_2=2.23*10^8J+7.24*10^7J=2.95*10^8J=2.95*10^5kJ\)

The total energy required is 2.95*10^5 kJ

The total energy required to melt the copper is equal to \(2.95 \times 10^5\) Kilojoules.

Given the following data:

Scientifically, we know that:

To calculate the total energy required to melt the copper:

First of all, we would determine the quantity of heat energy required to reach the boiling temperature of copper.

Mathematically, quantity of heat is given by the formula;

\(Q_b = mc\theta\\\\Q_b = 540 \times 390 \times (1080-20)\\\\Q_b = 210600 \times 1060\\\\Q_b = 2.23 \times 10^8 \;Joules\)

Next, we would determine the quantity of heat energy required to melt copper.

\(Q_b = 540 \times 134000\\\\Q_b = 7.2 \times 10^6 \; Joules\)

For total energy:

\(Q_T = Q_b + Q_m\\\\Q_T = 2.23 \times 10^8 + 7.24 \times 10^7\\\\Q_T = 2.95\times 10^8\\\\Q_T = 2.95\times 10^5\; Kilojoules\)

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Answer:

A proton has a positive charge :)

A neutron has no charge because it is neutral :)

Have a great day!!

Please rate and mark brainliest!!

A proton is positively charged while a neutron has no charge at all.

Answer:

Does more sunlight make rose bushes grow taller?

Explanation:

When conducting a research, the researcher usually poses research questions in order to confirm or disprove the research hypothesis. A research question addresses the key issues and questions that the research project is intended to answer. Good research questions always aim at improving the body of knowledge on the selected topic of the research. Research questions must be narrowed down to specific details of the topic. They must also be testable, they must not be vague.

If I am studying the effect of sunlight on rose bushes, then the question, 'does more sunlight make rose bushes grow taller?' Is apt to the research because it can be tested by exposing various thorn bush plants to varying degrees of sunlight and recording my observation.

Answer:

If rose bushes receive more hours of sunlight each day, they will grow taller.

Explanation:

I just answered it on Apex, and they like to switch up how they word things sometimes.

Object at rest :

*An object is said to be at rest if it does not change its position with respect to its surroundings with time.

Object at motion:

*An object is said to be in motion if the position changes with respect to it surrounding and time.

Answer:

Objects at rest: Objects at rest are ones that have no motion in them and will be stable in the same position. They have potential energy.

Objects at motion: Objects at motion are ones that are constantly in motion and a consistent velocity until they are acted upon by an unbalanced force. They have kinetic energy.  

Explanation:

Answer:

It is most likely option A B and C

Answer:

I think option A ,B,D are correct

Answer:

4km/m

Explanation:

She was going at 2km/m, so 2 kilometers per minute. She has 2 minutes therefore she needs to double her rate to 4 kilometers per minute.

The car covers a distance d after time t of

d = (2.8 m/s²) t²

Solve for t when d = 69 m:

69 m = (2.8 m/s²) t²

t² = (69 m) / (2.8 m/s²)

t ≈ 4.96 s

Answer:from 0.75 to 1.25 hours

Explanation:

If the line goes straight, it means that time is going by but they're not moving.

Excitability or responsiveness can be referred to as Sensitivity to the environment

Excitability or responsiveness can be defined as an ability possessed by living things that helps them react to the environment according to the vibe or energy they sense.

In conclusion, Excitability or responsiveness can be referred to as Sensitivity to the environment

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Answer:

Vectors have both magnitude and direction

Explanation:

Vectors show how strong the force in because the bigger the arrow, the stronger the force.  Also, it obviously shows direction because its an arrow.

Vectors have magnitude and direction while scalars have only magnitude. Vectors are shown using an arrow above the symbol of the quantity and are often printed in bold face.

In Physics, we generally recognize two categories of quantities; vector quantities and scalar quantities.

Vector quantities have both magnitude and direction. It is normal to print vectors in bold face, with an arrow written above the symbol of the quantity. The arrow points in the direction of the vector.

The following are true regarding vectors;

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Answer:it fires its engine for 1 minute. If the forward thrust provided by the rocket engines is 10000 N, what is the increase in ... From this, work out the increase in velocity of the rocket and its new velocity ... You can put this solution on YOUR website! . From Physics (Mechanics), there is this impulse-momentum change equation: ...

Explanation:

Jupiter exhibit differential rotation by C) The equator rotates in one direction; the higher latitudes rotate in the opposite direction.

Jupiter exhibits differential rotation, meaning that different parts of the planet rotate at different speeds. This is due to the fact that Jupiter is a gaseous planet composed mainly of hydrogen and helium, without a solid surface.

Jupiter's equator rotates faster than its higher latitudes. The rotation period at the equator is about 9 hours and 50 minutes, while at higher latitudes, the rotation period increases. This differential rotation creates distinct bands and zones on Jupiter's surface, with alternating eastward and westward jet streams.

The bands and zones of Jupiter's atmosphere are visible as colorful cloud features. The equatorial region shows faster-moving clouds and storms, while the higher latitudes exhibit slower-moving cloud systems. These different cloud patterns are a result of the varying rotation speeds at different latitudes.

Additionally, it's worth noting that the Great Red Spot, a giant storm on Jupiter, exhibits counterclockwise rotation. This iconic feature has been observed for centuries and is a prominent example of the atmospheric dynamics on the planet.

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Answer: the answers would be both of the ones in the middle

Explanation:

the one where it says plant more trees

and the other one that says paint ore cover black asphalt streets

The bucket is 0.8 meters away from the older child.

In this scenario, we have two children carrying a 2.4-meter long horizontal pole with a water bucket hanging from it. The older child supports twice the weight of the younger child. Let's denote the distance of the bucket from the older child as 'x' and the distance from the younger child as '2.4 - x'.

Since the older child is supporting twice the weight of the younger child, we can relate the forces using a balance of torques. Torque is the force applied at a distance from the pivot point. In this case, the pivot point is where the younger child is holding the pole.

The torque applied by the older child is equal to the weight supported by the older child multiplied by the distance 'x'. Similarly, the torque applied by the younger child is equal to half the weight supported by the older child multiplied by the distance '2.4 - x'. For the pole to be in equilibrium, these two torques must be equal. Therefore:

Older child's torque = Younger child's torque
(weight supported by older child) * x = (1/2 * weight supported by older child) * (2.4 - x)

Since we only need to find 'x', we can cancel out the weight supported by the older child from both sides of the equation:

x = (1/2) * (2.4 - x)

Solving for 'x', we get:

x = 0.8 meters

So, the bucket is 0.8 meters away from the older child.

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Answer:

\(100\; {\rm N}\).

Explanation:

The block is in a translational equilibrium since the velocity of the block is constant.

Because velocity of the block is not changing, acceleration of the block would be \(0\). By Newton's Laws of Motion, the net force on this block would also be \(0\!\), meaning that forces on the block would be balanced.

Specifically, forces on this block need to be balanced in the horizontal direction. There are two forces on this block in that direction:

For these two forces to balance each other, their magnitudes need to be the same. Hence, the force pointing to the left should also have a magnitude of \(100\; {\rm N}\).

The motor could  lift 15 g in a time of 8 seconds 10884 meter.

The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.

Given that motor operates at 200 W.

At time interval of 8 second, it do a work = 200×8 joule = 1600 joule.

Hence,  it lift 15 g in a time of 8 seconds = 1600/(0.015×9.8) meter

= 10884 meter.

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