An oil tank will hold 250 gallons . The tank is 80% full how many gallons of oil are in the tank

The mystery number, represented by the expression 1.5 < c < 2 is 1.6

1.6 = 16/10 = 8/5

1.7 = 17/10

1.8 = 18/10 = 9/5

1.9 = 19/10

1÷8/5

= 1 × 5/8

= 5/8

= 0.625

1 ÷ 17/10

= 10/17

= 0.58823529411764

1 ÷ 9/5

= 5/9

= 0.55555555555555

1÷19/10

= 10/19

= 0.52631578947368

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Answer:

$100

Step-by-step explanation:

she earned $60 last week, to get how much she earned you'll take 60 and multiply it by .25(1/4 in decimal form) which would mean she saved $15 last week, so she needs to save $25 this week and I tested until I got to $25. equation is .25x$100=$25

So we need to build a confidence interval for the percentage of cell phone users who develop cancer of the brain or nervous system. Using P for this value we have that the confidence interval is given by:

Where P is the percentage we want to estimate, p is the rate of cancer found in previous studies (0.0438%/100 in this case) and n is study sample size (here is 420079). The parameter alpha is given by the following equation:

Then we have to find the Z value that is giving in tables. Since we have:

we must look for the value 0.95 in the table:

Which basically means that Z=1.65. Now let's substitute all of the values we get in the equation:

This interval written with percentages is:

Answer:

t= b/2 - 3d/2

Step-by-step explanation:

The logical expression that is equivalent to ¬∀x∃y(P(x)∧Q(x,y)) is ∀x∃y(¬P(x)∨¬Q(x,y)) i.e., the correct option is option D.

To determine the equivalent logical expression, we need to apply De Morgan's laws and quantifier negation rules.

Starting with the given expression ¬∀x∃y(P(x)∧Q(x,y)), let's break it down step by step:

Apply the negation of the universal quantifier (∀x) to get ∃x¬∃y(P(x)∧Q(x,y)).

This step changes the universal quantifier (∀x) to an existential quantifier (∃x) and negates the following expression.

Apply the negation of the existential quantifier (∃y) to get ∃x∀y¬(P(x)∧Q(x,y)).

This step changes the existential quantifier (∃y) to a universal quantifier (∀y) and negates the following expression.

Apply De Morgan's law to the negation of the conjunction (P(x)∧Q(x,y)) to get ∃x∀y(¬P(x)∨¬Q(x,y)).

This step distributes the negation inside the parentheses and changes the conjunction (∧) to a disjunction (∨).

Therefore, the equivalent logical expression is option D. ∀x∃y(¬P(x)∨¬Q(x,y)).

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the probability that he drove the small car is 0.890 (option A).

Using Bayes' theorem to solve the problem given, let us represent the following events:

A: Friend drives the small carB: Friend drives the large carC: Friend is on timeGiven that three-quarters of the time he drives the small car and one-quarter of the time he drives the large car, we can calculate the prior probabilities:

P(A) = 3/4 and P(B) = 1/4.

Also, given that he usually has little trouble parking with probability 0.9 when driving the small car and is on time with probability 0.6 when driving the large car, we can calculate the likelihoods:

P(C|A) = 0.9 and P(C|B) = 0.6

Using Bayes' theorem, we can calculate the posterior probability of driving the small car given that he was on time on a particular morning:

P(A|C) = P(C|A) * P(A) / (P(C|A) * P(A) + P(C|B) * P(B))= 0.9 * 3/4 / (0.9 * 3/4 + 0.6 * 1/4) = 0.890

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The solution to the initial value problem is given by:

ln|u| = -t + ln(2)

|u| = e^(-t + ln(2))

|u| = e^(ln(2)/e^t)

u = ± e^(ln(2)/e^t)

To determine the solution to the given initial value problem using the previous exercise, we need to find the characteristics of the equation and solve them.

The characteristic equations corresponding to the given partial differential equation are:

dx/dt = 1, dt/dt = u^2, du/dt = -u

From the second equation, we have dt/u^2 = dx. Integrating both sides gives us t = -1/(3u) + C1, where C1 is a constant of integration.

From the first equation, dx/dt = 1, we have dx = dt. Integrating both sides gives us x = t + C2, where C2 is another constant of integration.

From the third equation, du/dt = -u, we have du/u = -dt. Integrating both sides gives us ln|u| = -t + C3, where C3 is another constant of integration.

Now let's use the initial condition u(x,0) = 2 to find the values of the constants C1, C2, and C3.

When t = 0, x = 0 (since x > 0 for all x in R), and u = 2. Substituting these values into the characteristic equations, we get:

C1 = -1/6

C2 = 0

ln|2| = C3

C3 = ln(2)

Therefore, the solution to the initial value problem is given by:

ln|u| = -t + ln(2)

|u| = e^(-t + ln(2))

|u| = e^(ln(2)/e^t)

u = ± e^(ln(2)/e^t)

Since we know that u(0) = 2, we can take the positive sign to obtain:

u = e^(ln(2)/e^t)

So the solution to the initial value problem is u(x, t) = e^(ln(2)/e^t).

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The ratio of the number of unshaded to shaded squares is 7 : 3.

Ratio is defined as the relationship between two quantities where it tells how much one quantity is contained in the other.

It is also defined as the fraction of one quantity with respect to other.

The ratio of a and b is denoted as a : b.

Given is a grid of squares which is given below.

Total number of squares = 10

Of that,

Number of shaded squares = 3

Number of unshaded squares = 7

We have to find the ratio of unshaded to shaded squares in the grid which is 7 / 3 or 7 : 3.

Ratio of unshaded squares to shaded squares = 7 : 3

Hence 7 : 3 is the ratio of unshaded to shaded.

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a) The probability that the third card will be the two of clubs is 1/50 since there are 50 cards left in the deck after the first two cards have been drawn, and only one of them is the two of clubs.
b) Your odds are the same for choosing the two of clubs on each draw since the probability of drawing the two of clubs does not change with each draw.
c) This example illustrates the difference between independent and dependent events. In the case of drawing cards without replacement, the events are dependent since the outcome of one draw affects the probability of the next draw.
d) If we drew the cards with replacement, the marginal probabilities would not change since the probability of drawing any particular card is always 1/52. However, the joint probabilities would change since each draw is now independent.

a) To find the probability that the third card will be the two of clubs, we need to calculate the joint probability of not drawing the two of clubs in the first two draws and drawing it in the third. The probability of not drawing the two of clubs in the first draw is 51/52, and in the second draw, it is 50/51. The probability of drawing the two of clubs in the third draw is 1/50. So, the joint probability is (51/52) * (50/51) * (1/50) = 1/52.

b) The odds of choosing the two of clubs are the same for each draw: 1/52 for the first, second, or third draw. This is because the probability is based on the number of favorable outcomes (one card) over the total possible outcomes (52 cards) in a standard deck.

c) This example illustrates the difference between independent and dependent events. In this scenario, the events are dependent because each card drawn affects the remaining cards in the deck. If the events were independent, the probability of drawing the two of clubs would not change after drawing the first or second card.

d) If we draw cards with replacement, the marginal, joint, and conditional probabilities change because the events become independent. With replacement, the probability of drawing the two of clubs remains constant at 1/52 for each draw. The joint probability of not drawing the two of clubs in the first two draws and drawing it in the third becomes (51/52) * (51/52) * (1/52), and conditional probabilities will not be affected by the previous draws.

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If we have a large enough number of samples, the sample mean can provide a reliable estimate of the population mean.

As the number of samples increases, the sample mean can be used to approximate a population mean.

The sample mean is the average value calculated from a subset of the population, which represents the overall population mean when the sample is random and representative.

By taking multiple samples and calculating their means, we can estimate the population mean more accurately.

This is because as the number of samples increases, the sample mean values tend to converge towards the population mean.

This concept is known as the Central Limit Theorem.

Therefore, if we have a large enough number of samples, the sample mean can provide a reliable estimate of the population mean.

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When we do a confidence interval for the mean, we use T-distribution to determine the number of standard deviations needed for our confidence

The T-distribution is a way to describe a collection of observations in which the majority of the observations are close to the mean and the remaining observations are the tails on either side. It is a type of normal distribution that is utilized for data with unknown variance and smaller sample sizes.

We use the T-distribution to obtain the required critical value, which is nothing more than the number of standard deviations from the center taken to obtain the confidence interval, despite the fact that there is no population standard deviation and only sample metrics—the sample mean and standard deviation—are used. As a result, the solution to this problem is T-distribution.

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First, we need to determine the time it takes for each girl to mow one lawn.

For Betty:
4 lawns in 4.4 hours, so 4.4 hours ÷ 4 lawns = 1.1 hours per lawn.

For Jemma:
6 lawns in 5.4 hours, so 5.4 hours ÷ 6 lawns = 0.9 hours per lawn.

Now, we need to find the time it takes for each girl to mow 7 lawns.

For Betty:
7 lawns × 1.1 hours per lawn = 7.7 hours.

For Jemma:
7 lawns × 0.9 hours per lawn = 6.3 hours.

Finally, we need to find the difference in time between Betty and Jemma:

7.7 hours (Betty) - 6.3 hours (Jemma) = 1.4 hours.

So, the correct answer is B. Jemma will take 1.40 hours less than Betty to mow 7 lawns.

Answer:

No one can answer this

Step-by-step explanation:

You need to add a picture or something because we need more information. This could be a graph, a number line, etc.

Answer:

(Image 1)

d(A,C)=10d(C,B)=8

d(A,B)=d(A,C)+d(C,B)=10+8=18

(Image 2)

AB=AC−BC

=10−8=2

Step-by-step explanation:

I'm sorry, but your question does not make complete sense. It seems like you have provided a list of expressions with x as a variable, but there is no context or specific question being asked. Can you please provide more information or clarify what you are asking?

The name of the rhythm with an atrial rate greater than 250 beats per minute, a non-measurable pr interval, and a ventricular rate of 120 is

The atria, or top chambers of the heart, beat too fast in atrial flutter. As a result, the heart beats quickly yet typically in a regular rhythm.

An example of a heart rhythm disturbance (arrhythmia) brought on by issues with the heart's electrical circuitry is atrial flutter.

Atrial fibrillation, a frequent disease that causes the heart to pulse irregularly, is comparable to atrial flutter.

Atrial flutter patients have a cardiac rhythm that is less erratic and more controlled than atrial fibrillation patients. A person may occasionally have both atrial flutter and atrial fibrillation in the same episode.

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To find the basis of W^1, the orthogonal complement of the subspace W spanned by ū and v, we first need to find a basis for W. Using Gaussian elimination, we can reduce the matrix [u v] to row echelon form and get two pivot variables corresponding to the first and second columns. Therefore, a basis for W is {ū, v}. To find the basis for W^1, we need to find all vectors in R^4 that are orthogonal to W. This can be done by solving the system of equations obtained by equating the dot product of a vector in W^1 with each vector in W to zero. The resulting basis for W^1 is {(2, 1, 0, 0), (4, 0, 1, 0)}.

Let's start by finding a basis for the subspace W spanned by ū and v. To do this, we put the matrix [u v] in row echelon form:
[ 0 -1 ]
[ 1  4 ]
[-3 -4 ]
[ 4  4 ]
We can see that the first and second columns are pivot columns, so the corresponding variables are pivot variables. Therefore, a basis for W is {ū, v}.
Now, we need to find the basis for W^1, the orthogonal complement of W. We know that any vector in W^1 is orthogonal to every vector in W, so it must satisfy the following system of equations:
(2, 1, 0, 0)·ū + (4, 0, 1, 0)·v = 0
(2, 1, 0, 0)·v + (4, 0, 1, 0)·v = 0
We can solve this system of equations to get:
(2, 1, 0, 0) = 1/9*(-4, 3, 0, 0) + 1/3*(1, 0, 0, 0)
(4, 0, 1, 0) = 1/3*(0, 1, 0, 0) - 2/3*(1, 4, 0, 0)
Therefore, the basis for W^1 is {(2, 1, 0, 0), (4, 0, 1, 0)}.

The basis for W, the subspace spanned by ū and v, is {ū, v}. The basis for W^1, the orthogonal complement of W, is {(2, 1, 0, 0), (4, 0, 1, 0)}. These vectors are orthogonal to every vector in W, and together with the basis for W, they form a basis for the entire space R^4.

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The two statements  a iff b and (not a) iff (not b) has been explained

The two statements are known as biconditionals, which state that two statements are true if and only if each other.

"a iff b" means that "a" is true if "b" is true, and "a" is false if "b" is false. In other words, "a" and "b" have the same truth value.

"(not a) iff (not b)" means that "not a" is true if and only if "not b" is true, and "not a" is false if and only if "not b" is false.

Therefore, these two statements are equivalent because they express the same idea: "a" and "b" have the same truth value. If "a" is true, then "b" is true, and if "a" is false, then "b" is false. Similarly, if "b" is true, then "a" is true, and if "b" is false, then "a" is false.

These statements are true in cases where both "a" and "b" have the same truth value. If both are true or both are false, then the statements are true. If "a" is true and "b" is false, or vice versa, then the statements are false.

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In a two-factor experiment, the expected value of the mean square for the major factor

(a) can differ depending on whether the minor factor

(b) is fixed or random.

Both parts are briefly discussed belwo.

If the minor factor (b) is fixed, it means that the levels of the minor factor are chosen by the experimenter, and they are held constant throughout the experiment.

In this case, the expected value of the mean square for the major factor (a) is calculated by dividing the sum of squares for the major factor by the degrees of freedom for the major factor.

The degrees of freedom for the major factor are equal to the number of levels of the major factor minus one.

On the other hand, if the minor factor (b) is random, it means that the levels of the minor factor are chosen randomly from a population of possible levels, and they are not held constant throughout the experiment.

In this case, the expected value of the mean square for the major factor (a) is calculated by dividing the sum of squares for the major factor by the degrees of freedom for the major factor and the degrees of freedom for the interaction between the major and minor factors.

The degrees of freedom for the interaction are equal to the product of the degrees of freedom for the major and minor factors.

The reason why the expected value of the mean square for the major factor (a) differs depending on whether the minor factor (b) is fixed or random is that in the fixed case.

The variability due to the minor factor is accounted for in the error term, while in the random case, the variability due to the minor factor is accounted for in the interaction term.

Therefore, the degrees of freedom for the major factor are different in the two cases, and this affects the expected value of the mean square for the major factor.

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Answer:

This line is exponential and has no slope

Answer:

10

y=mx+b

m=slope

In your equation, m would be 10

The similarity between the volume of a cone and the volume of a pyramid is that:

In contrast, the differences between the volume of a cone and the volume of a pyramid include:

Mathematically, the volume of a cone can be calculated by using this formula:

V = 1/3 × πr²h

Where:

Mathematically, the volume of a pyramid can be calculated by using this formula:

Volume = 1/3 × b × h

Where:

In this context, we can infer and logically deduce that the similarity between the volume of a cone and the volume of a pyramid is that:

On the other hand (conversely), the differences between the volume of a cone and the volume of a pyramid include:

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Answer. 655.4

Step-by-step explanation:

what did u get?

Let's rewrite every line in the slope-intercept form:

Since their slopes are equal, we can conclude that those lines are parallel.

From the problem, we have :

The common factor will be 6x, this will be :

The answer is :

Answer:

200 times and 2x10^2

Step-by-step explanation:

I hope this helps ( ps love the Killua Profile pic !)

The length of side b is 56m, angle A is 45°, and angle C is 67°.

In the given triangle with side lengths a = 74m, b ≈ 56m, and c = 36m, the length of side b is approximately 56m.

To solve the triangle, we can use the Law of Cosines and the fact that the sum of angles in a triangle is 180 degrees. Given angle B = 67°51', we have:

Using the Law of Cosines, we have:

b² = a² + c² - 2ac * cos(B)

Substituting the known values:

b² = 74² + 36² - 2 * 74 * 36 * cos(67°51')

Calculating the value of b:

b ≈ √(74² + 36² - 2 * 74 * 36 * cos(67°51'))

b ≈ 55.92m (rounded to the nearest whole number, b ≈ 56m)

Using the Law of Cosines again, we have:

cos(A) = (b² + c² - a²) / (2 * b * c)

Substituting the known values:

cos(A) = (56² + 36² - 74²) / (2 * 56 * 36)

Calculating the value of A:

A = cos⁻¹((56² + 36² - 74²) / (2 * 56 * 36))

A ≈ 45° (rounded to the nearest whole number)

Using the fact that the sum of angles in a triangle is 180 degrees:

C = 180° - A - B

Substituting the known values:

C ≈ 180° - 45° - 67°51'

Calculating the value of C:

C ≈ 67°9' (rounded to the nearest whole number, C ≈ 67°)

Therefore, in the given triangle, the length of side b is approximately 56m, angle A is approximately 45°, and angle C is approximately 67°.

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In the given algebraic equation of y=-4x+1 when x=-1, y=5; x=0, y=1; x=1, y=-3; x=2, 7=-7.

Algebraic equations are defined as mathematical statements in which two algebraic expressions are set equal to each other. An algebraic expression usually consists of  variables,  coefficients and  constants.

Given algebraic equation is y=-4x+1

For x=-1,

y=-4(-1)+1

=5

For x=0

y=-4(0)+1

=1

For x=1

y=-4(1)+1

=-3

For x=2

y=-4(2)+1

=-7

Therefore in the given algebraic equation of y=-4x+1 when the value of x is -1, the value of y becomes 5; when the value of x is 0, the value of y becomes 1; when the value of x is 1, the value of becomes -3 and when the value of x is 2, the value of y becomes -7.

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The equation of the line that passes through the points (-8, 9) and (2, -6) is y = (-3 / 2)x - 3.Given two points (-8, 9) and (2, -6). We are supposed to find the equation of the line that passes through these two points.

We can find the equation of a line that passes through two given points, using the slope-intercept form of the equation of a line. The slope-intercept form of the equation of a line is given by, y = mx + b,Where m is the slope of the line and b is the y-intercept.To find the slope of the line passing through the given points, we can use the slope formula: m = (y2 - y1) / (x2 - x1).Here, x1 = -8, y1 = 9, x2 = 2 and y2 = -6.

Hence, we can substitute these values to find the slope.m = (-6 - 9) / (2 - (-8))m = (-6 - 9) / (2 + 8)m = -15 / 10m = -3 / 2Hence, the slope of the line passing through the points (-8, 9) and (2, -6) is -3 / 2.

Now, using the point-slope form of the equation of a line, we can find the equation of the line that passes through the point (-8, 9) and has a slope of -3 / 2.

The point-slope form of the equation of a line is given by,y - y1 = m(x - x1)Here, x1 = -8, y1 = 9 and m = -3 / 2.

Hence, we can substitute these values to find the equation of the line.y - 9 = (-3 / 2)(x - (-8))y - 9 = (-3 / 2)(x + 8)y - 9 = (-3 / 2)x - 12y = (-3 / 2)x - 12 + 9y = (-3 / 2)x - 3.

Therefore, the equation of the line that passes through the points (-8, 9) and (2, -6) is y = (-3 / 2)x - 3. Thus, the answer is (-3/2)x - 3.

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Answer:

Step-by-step explanation:

The two smaller triangles are similar.

The ratio of corresponding sides of similar triangles is equal:

\(\\ \sf\longmapsto x^2=12(8)\)

\(\\ \sf\longmapsto x^2=96\)

\(\\ \sf\longmapsto x=\sqrt{96}\)

\(\\ \sf\longmapsto x=9.7\)