An unopened bag of chips expanding as one drives up a mountain is a good example of how volume _________. Question 11 options: decreases when pressure decreases increases when pressure increases decreases when pressure increases increases when pressure decreases.

Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

One piece of evidence that suggests Triton is a captured moon is its retrograde orbit around Neptune, which means it orbits in the opposite direction of Neptune's rotation, a characteristic commonly observed in captured objects.

Multiple lines of evidence support the hypothesis that Triton, the largest moon of Neptune, is a captured moon. One significant piece of evidence is Triton's retrograde orbit, which means it orbits in the opposite direction of Neptune's rotation.

Retrograde orbits are uncommon for moons formed in the same protoplanetary disk as their host planet. This suggests that Triton may have originated elsewhere and been captured by Neptune's gravitational pull. Additionally, Triton's highly inclined and eccentric orbit further supports the capture theory.

Its orbit is tilted relative to Neptune's equator and is more elongated than typical moons formed in situ.

These characteristics align with expectations for a captured object, as gravitational interactions during capture can alter the moon's orbit and result in these unique orbital properties observed in Triton.

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Changes in gas pressure have a significant impact on breathing. Gas pressure in the lungs must be maintained at a stable level for proper breathing to occur. The muscles in the diaphragm and ribcage work together to change the volume of the chest cavity. When the chest cavity expands, it causes a decrease in pressure that allows air to be drawn into the lungs.

When the chest cavity shrinks, it causes an increase in pressure that forces air out of the lungs. The gas pressure of oxygen and carbon dioxide in the lungs is directly related to the gas pressure in the environment. When the atmospheric pressure is decreased, as occurs at higher altitudes, the pressure of oxygen in the lungs also decreases, making it more difficult to extract oxygen from the air. This makes breathing more difficult. Conversely, when the atmospheric pressure is increased, as occurs in deep sea diving, the pressure of nitrogen in the body increases. This can cause a condition known as decompression sickness or the bends. Nitrogen bubbles can form in the bloodstream, leading to severe pain, organ damage, and even death.

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Answer:

(C) 700 N

Explanation:

The given parameters are;

The mass of the mountain climber, m = 100 kg

The angle formed by the rope with the horizontal, θ = 45°

The gravitational field strength, g = 10 N/kg

The weight of the man, W = m × g

∴ W = 100 kg × 10 N/kg = 1,000 N

At equilibrium, we have;

The downward force, the weight of the man, W = The upward force, the vertical component of the tension on the two halves of the rope

We have;

W = T × sin(θ) + T × sin(θ)

∴ 1,000 N = 2 × T × sin(45°)

Therefore, we have;

T = 1,000 N/(2 × sin(45°)) = 707.106781 Newtons

Therefore, the tension in the rope is closest to (approximately) 700 N.

Answer:

0.10 m/s

Explanation:

The graph appears to be linear, so the velocity is constant and is represented by the slope of the graph. The slope can be calculating by taking any two points and inputting them into the equation: \(\frac{y_2-y_1}{x_2-x_1}\) which is essentially rise/run. In this case the slope is really easy to calculate taking the two points of (0, 0) and (10, 1). In this case you can easily see the rise is 1 and the run is 10. So the slope is 1/10. So the average velocity of the object was 0.10 m/s or 1/10 m/s

Answer:

2 N

Explanation:

From the question, it's given that

Mass m = 0.2 kg

Acceleration a = 10 m/s^2

The force a soccer goalie experience when stopping a ball will be equal to the force at which the ball is being kicked. This is

F = ma

Substitute all the parameters into the formula

F = 0.2 × 10

F = 2 Newton.

a. The amount of thermal energy 'wasted' by the turbine per second = 500,000 J

b. Efficiency of the turbine = 66.7%

Energy is the ability to do work.

Energy is essential to sustain the material universe. Energy constantly flows in the universe and is transformed into various forms.

Th various forms of energy are:

When energy is lost in a system, it is usually converted to heat.

a. The amount of thermal energy 'wasted' by the turbine per second = 1,500,000 J - 1,000,000 = 500,000 J

b. Efficiency = (1,000,000/1,500,000) * 100%

Efficiency of the turbine = 66.7%

In conclusion, energy is usually lost in the form of heat or thermal energy during energy transformations.

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Answer:

weight.................

A star is 230 light years away. the light we see tonight from that star left it

Instead of time, a light-year counts distance (as the name might imply). One light-year, or roughly 6 trillion miles, is the distance a light beam travels in one year on Earth (9.7 trillion kilometers).

Since light takes around 230 years to travel the distance from the star to us, the light we see tonight departed that star 230 years ago.

Because of this, astronomers frequently discuss the "lookback time" when seeing far-off celestial objects. The older the light we witness from an object, the further away it is, and the further back in time we can see.

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Answer:

\(R=mg \\ R=100 \times 9.8 = 980 \: N \\ \mu = \frac{F}{R} = \frac{500}{980} \\ \mu = 0.51 \approx \: 0.5\)

From the question, the compression that is able to produce the maximum speed is 1.73 m.

We can see that there is potential energy stored in the spring. This energy can be converted into kinetic energy when a spring is released. In this case, the spring can now be able to do a meaningful work as we can see.

The image that shows the set up of the question can be seen clearly in the image that is attached to this answer as we can see. We can now write the following;

W = dmgsin∅

Where W is the work done by the spring, we have;

1/2 kx² = dmgsin∅

k = force constant

x = compression

d = distance covered

∅ = angle covered

Thus we can substitute the values as;

(0.5 * 170 * x²) = 4 * 13 * 9.8 * sin 30

x² = 4 * 13 * 9.8 * sin 30/0.5 * 170

x² = 254.8/85

x = 1.73 m

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The mass of the mouse, m₁=0.042 kg

The mass of the 1st cart, m₂=0.35 kg

The mass of the second cart, m₃=0.25 kg

The speed of the 1st car after the jump, u₁=0.88 m/s

From the law of conservation of momentum, the momentum of a system should always remain the same.

Before the mouse jumps from one cart to another, all the objects were at rest. Therefore the total momentum of the system was zero.

Thus after the mouse jumps, the total momentum of the system should be equal to zero.

Thus the momentum of the second cart and the mouse will be equal in magnitude to the momentum of the first cart but it will be in the opposite direction.

Thus,

On substituting the known values,

Thus the speed of the mouse and the second cart after the mouse jumps is 1.05 m/s

Answer:

Eelas = 5 [J]

Explanation:

Elastic energy is associated with the ability that has a spring or any other material with elastic properties.

We can calculate the elastic energy by means of the following equation:

\(E_{elas}=\frac{1}{2} *k*x^{2}\)

where:

k = constant spring = 2.5 [N/m]

x = distance stretched = 2 [m]

\(E_{elas}=\frac{1}{2} *2.5*(2)^{2}\\E_{elas}=5[J]\)

Answer:

a) In order for the riders to stay pinned against the inside of the drum when the floor drops away, the force of friction between the drum and the riders must be greater than or equal to the force of gravity pulling them down.The maximum force of friction that can be exerted on a rider is given by:f_max = μNwhere μ is the coefficient of static friction and N is the normal force acting on the rider.At the minimum speed required for the riders to stay pinned against the inside of the drum, the normal force acting on each rider is equal to their weight, so:N = mgwhere m is the mass of the rider and g is the acceleration due to gravity.The force of gravity pulling the rider down is:F = mgTherefore, the minimum speed required for the riders to stay pinned against the inside of the drum is given by:f_max = FμN = mgv_min = sqrt(rgμ)where r is the radius of the drum, which is half of the diameter, so r = 5m.Plugging in the values, we get:v_min = sqrt(59.80.15) = 2.16 m/sb) The angular velocity of the drum at this speed can be found using the formula:v = ωrwhere v is the linear velocity of the riders at the minimum speed required to stay pinned against the inside of the drum, r is the radius of the drum, and ω is the angular velocity of the drum.Rearranging this equation to solve for ω, we get:ω = v/rPlugging in the values, we get:ω = 2.16/5 = 0.432 rad/sSo the angular velocity of the drum at the minimum speed required for the riders to stay pinned against the inside of the drum is 0.432 rad/s.

Answer:

2.54 m/s

Explanation:

By conservation of energy,

work done by force due to hand = mechanical energy gained by yo-yo

So Fd = mgh + 1/2m(v₂² - v₁²)

where F = force on string = 0.19 N, d = distance moved by hand = 0.12 m, m = mass of yo-yo = 0.058 kg, g = acceleration due to gravity = 9.8 m/s², h = distance moved by yo-yo = 0.30 m, v₁ = initial speed of yo-yo = 3.4 m/s and v₂ = final speed of yo-yo = unknown

So,  Fd = mgh + 1/2m(v₂² - v₁²)

Fd/m = gh + 1/2(v₂² - v₁²)

Fd/m - gh = 1/2(v₂² - v₁²)

2(Fd/m - gh) = (v₂² - v₁²)

(v₂² - v₁²) = 2(Fd/m - gh)

v₂²  = v₁² + 2(Fd/m - gh)

taking square-root of both sides, we have

v₂  = √[v₁² + 2(Fd/m - gh)]

Substituting the values of the variables into the equation, we have

v₂  = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.0228 Nm/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.393 Nm/kg - 2.94 m²/s²)]

v₂  = √[(3.4 m/s)² + 2(-2.547 m²/s²)]

v₂  = √[11.56 m²/s² - 5.094 m²/s²)]

v₂  = √[6.466 m²/s²]

v₂ = 2.54 m/s

According to   equations of motion, we get after 8.70 seconds  she running directly east.

These are the three equations:

Given :

v₀ = 2.38 m/s

v = 0 m/s

a = 0.310 sin (-62.0°) m/s²

to find time t :

v = at + v₀

0 m/s = (0.310 sin (-62.0°) m/s²) t + (2.38 m/s)

t = 8.70 s

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Answer: at the same time

Explanation: in a vacuum, there isnt air, right? so there isnt gravity pushing down on the heavier object, so they will both land at the same time.

good? :)

The positive velocity at 0.0 s on the graph is equal to the mass moving upward and at the origin in 0.0 s.

Velocity is a vector quantity that has both magnitude and direction. Velocity ​​can be positive and negative. Velocity is positive if the direction of motion is up and negative if the direction of motion is down.

On a speed-time graph, a horizontal (flat) line indicates that the object is moving at a constant speed. The diagonal straight line shows the speed of the object changes.

This question is an of choice

The mass moves down and at the origin at 0.0 s.

The mass moves up and at the origin at 0.0 s.

The mass moves upward but not at the origin in 0.0 s.

The mass moves down but not at the origin in 0.0 s.

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Answer:

NaHCO3 + CaCl2 = CaCO3 + 2NaCl + H2O

Explanation:

It is physically impossible to balance this equation you may be missing another compound

Answer:

Initial velocity of an object

The acceleration of an object

The change in position of an object

Explanation:

In that equation, you are solving for the final velocity of an object.

Answer:

6

Explanation:

120/30=6

Work required to stretch the rubber band by 0.10 meters will be negative, indicating that work needs to be done against the force applied to stretch the rubber band.

To determine how much the rubber band will stretch under a 20 N force and the work required to stretch it, we need to apply Hooke's Law. Hooke's Law states that the force applied to a spring or elastic material is directly proportional to the displacement it undergoes.

We can set up a proportion to find the stretch under Force 2:

(F1 / S1) = (F2 / S2)

Substituting the given values:

(24 N / 0.12 m) = (20 N / S2)

To find S2, we can rearrange the equation:

S2 = (20 N * 0.12 m) / 24 N

Simplifying:

S2 = 0.10 m

Therefore, a 20 N force will stretch the rubber band by 0.10 meters.

Now, let's calculate the work required to stretch the rubber band this far. The work (W) can be calculated using the formula:

W = (1/2) * k * (S2^2 - S1^2)

Where k is the spring constant.

However, we don't have the spring constant (k) given in the problem. So, we cannot determine the exact work without that information.

But, if we assume that the rubber band behaves as a linear spring and Hooke's Law applies, we can simplify the equation. Hooke's Law states that the force applied to a spring is equal to the spring constant (k) multiplied by the displacement (S).

F = k * S

Rearranging the equation:

S = F / k

Since the stretch (S) is directly proportional to the force (F), we can approximate the work required by assuming a constant k value:

W ≈ (1/2) * k * (S2^2 - S1^2)

W ≈ (1/2) * k * [(0.10 m)^2 - (0.12 m)^2]

Simplifying:

W ≈ (1/2) * k * (0.01 m^2 - 0.0144 m^2)

W ≈ (1/2) * k * (-0.0044 m^2)

Without the exact value of the spring constant, we cannot calculate the work precisely. However, we can still conclude that the work required to stretch the rubber band by 0.10 meters will be negative, indicating that work needs to be done against the force applied to stretch the rubber band.

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The focal length of the mirror is 13.3 cm.

Focal length is the gap (measured in millimeters) between the point of convergence of your lens and the sensor or movie recording the picture. The focal period of your film or virtual digicam lens dictates how tons of the scene your digicam could be able to capture.

For a converging lens (for instance a convex lens), the focal duration is wonderful and is the distance at which a beam of collimated mild could be centered to a single spot.

SOLUTION:

M = S'/S = 5

S' = 5S = 2*20 = 40cm

1/F = 1/S + 1/S'

1/F = (1/20)+(1/40)

F = 13.3 cm

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The force is different because of the amount of weight applied so the answer is A

The force that makes a difference in the weight of each person is Gravitational. Correct option is B.

Gravitational force is a fundamental force of nature that exists between any two objects with mass. It's the force that keeps us and everything else on Earth anchored to its surface. This force is proportional to the mass of the objects involved and inversely proportional to the square of the distance between them.

For example, if you were standing on a bathroom scale, the reading on the scale represents the force of the Earth's gravity acting on your body, which is why it's often referred to as your "weight." The actual mass of an object remains constant regardless of its location, but its weight can vary depending on the strength of the gravitational field at different locations (e.g., the weight on the Moon would be less than on Earth due to the Moon's weaker gravitational pull).

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The order of magnitude of the force of air drag on your hand in this scenario is approximately 100 N.

To estimate the order of magnitude of the force of air drag on your hand when you stretch it out of the open window of a speeding car, we can make some reasonable assumptions and approximations.

Let's consider the following quantities and their values:

Speed of the car (v): Assume the car is traveling at a typical highway speed of 100 km/h, which is equivalent to approximately 28 m/s.

Surface area of your hand (A): Assume the effective surface area of your hand facing the oncoming air is approximately 0.1 square meters.

Air density (ρ): Take the air density at sea level to be approximately 1.2 kg/m³.

Now, we can estimate the force of air drag (F) using the equation:

F = 0.5 * ρ * v² * A * Cd

where Cd is the drag coefficient, a dimensionless quantity that depends on the shape and orientation of your hand.

Since it's difficult to accurately determine the drag coefficient for a hand in this specific situation, we can make a rough estimate by assuming a drag coefficient of 1.0, which is typical for a flat plate perpendicular to the flow.

Substituting the values into the equation, we have:

F = 0.5 * (1.2 kg/m³) * (28 m/s)² * (0.1 m²) * 1.0

Simplifying the equation, we get:

F ≈ 94.08 N

Therefore, the order of magnitude of the force of air drag on your hand in this scenario is approximately 100 N.

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Magnitude and direction of a vector that is equal to a+b is 19m and 0.0° resp. Hence the correct option is C. magnitude 19 m direction 0.0°

Vector is a mathematical quantity which has both magnitude and direction.

Vectors are denoted with usual notation with an arrow upon it. for example, Force, Displacement, Velocity and Acceleration etc. are the vectors which has both magnitude as well as direction.

When two same vectors are acting at a point in two dimension. The magnitude of  resultant of this two vectors are given by,

R² = R₁² + R₁² +2R₁R₂cosθ......1

Where θ is the angle between them.

The direction of the resultant vector of two same vectors is given by the equation,

tanθ = (R₁ sinθ) ÷ (R₁ + R₂cosθ)......2.

In this picture, we have to find magnitude and direction of vector A+B, we have nothing to do with vector C.

vector A is at 37° from vertical, means 90-37 = 53° from positive x direction.

A = 12 m and 53°

B = 15m and 40°

angle between these two vectors are θ= 53+40 = 93°

magnitude of resultant of this two vectors are A+B which is given by the equation.

putting these values in equ. 1 we get,

R² = 12² + 15² +2(12×15)cos93°

R² = 350.15

R = 18.71 ≅ 19m ( magnitude)

From equation 2

tanα = (12 sin93°) ÷ (12+ 15cos93°)

tanα  = 0.8337

α  = 39.82° this angle is from vector B

so the angle of resultant from positive x axis is 40-39.82 = 0.17 ≅ 0.0°

Hence C is correct option is c: magnitude 19 m direction 0.0°

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Answer:

A: Excess H+ is absorbed by bicarbonate ions.

Explanation:

The statement that describes an energy measurement is one gram of wood stores 16,000 J, therefore the correct answer is option D

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

Thermal energy can be produced with help of various means such as by burning fossil fuels, with the help of solar energy.

The Joule is the recognized unit of measurement for energy (J). Kilowatt/hour (kWh), which is used specifically for electric energy, should be listed among the most used units for measuring energy (in fact it is used to calculate electricity bills). The Terawatt/hour (TWh), or one billion kW/h, is used to calculate the output of big power facilities or the country's consumption.

Thus, The statement that describes an energy measurement is one gram of wood stores 16,000 J, therefore the correct answer is option D

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V1f= -6.75 m/s (left),original elastic potential energy = 12.7575 J,The original energy is in the Spring,In bursting-apart process, The conservation of momentum is Holds.

(a) Mass of the first block, M

Mass of the second block, 3M

final speed of the second block, V2f =2.25 m/s

Before the cord burns, both masses are in rest oposition,

Hence, initial speed of then m is 0,

They are V1i, V2i  = 0 m/s

Hence, by conservation of momentum,

   MV1i + 3MV2i = MV1f + MV2f

    M(0) + 3M (0) = MV1f + 3M (2.25 m/s)

                       V1f= -6.75 m/s    (left)

(b) Kinetic energy of the system,

  K.E = 1/2 MV1f2 + 1/2 3M V2f2

        =1/2 (0.420 kg)(6.75 m/s)2+1/2(1.26)(2.25 m/s)2    (given, M = 0.420 kg)

        =9.568125  J + 3.189375 j

         =12.7575 j

According to conservation of energy,

The loos of kinetic energy is used to gain in original elastic potential energy

Hence, original elastic potential energy = 12.7575 J

(c) Since the spring stores the potential energy,

The original energy is in the Spring

(d) In bursting-apart process, The conservation of momentum is Holds.

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Answer:

i'm not quite sure

Explanation:

just grive me a sec

Answer:

29.4 m/s

Explanation:

f = ma

a = \(\frac{f}{m}\)

a = \(\frac{50000}{850}\)

a = 58.8 \(m/s^{2}\)

a = \(\frac{change in velocity}{t}\)

change in velocity= at

change in velocity = 58.8 × 0.5

change in velocity = 29.4 m/s