ANSWER ASAP!!
What is the measure of RSL?

A. 142°
B. 144°
C. 146°
D. 140°

ANSWER ASAP!!What Is The Measure Of RSL?A. 142B. 144C. 146D. 140

Answers

Answer 1

Answer:

144

Step-by-step explanation:


Related Questions

the question is: water pours into a conical tank that is 10 meters in height and has a radius of 4 meters at a rate of 6m^3/min. find the rate the water level is rising when the level is 5 meters high.

Answers

The rate at which the water level is rising when it is 5 meters high is approximately 0.477 m/min

The volume of a conical tank:
V = (1/3)πr^2h
where V is the volume of the tank, r is the radius, and h is the height.
Differentiating both sides with respect to time, we get:
dV/dt = (1/3)π(2rh dr/dt + r^2 dh/dt)
Where dV/dt is the rate at which the volume is changing (in m^3/min), and dr/dt and dh/dt are the rates at which the radius and height are changing, respectively.
We know that water is pouring into the tank at a rate of 6m^3/min, so we can substitute this value for dV/dt. We also know that the height of the water level is rising, so dh/dt is what we need to find. Finally, we know that when the water level is 5 meters high, the radius of the water surface can be found using similar triangles:
r/h = 4/10
r = (4/10)h = 0.4h
Now we can substitute all of these values into the formula and solve for dh/dt:
6 = (1/3)π(2(0.4h)(dh/dt) + (0.4h)^2 dh/dt)
6 = (1/3)π(0.8h + 0.16h^2) dh/dt
dh/dt = 6 / [(1/3)π(0.8h + 0.16h^2)]
When the water level is 5 meters high, h = 5, so:

dh/dt = 6 / [(1/3)π(0.8(5) + 0.16(5)^2)]

dh/dt = 0.477m/min

Therefore, the rate at which the water level rises when it is 5 meters high is approximately 0.477 m/min.

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Pauline orders wristbands from two different companies. • Company 1 sells each wristband for $2 and has free shipping. Company 2 sells each wristband for $1.25 and charges $6 for shipping per order. Write an equation to model the number of wristbands, w, for which the two companies charge the same amount.

Answers

Answer:

8 wristbands

Step-by-step explanation:

Let us assume that both of the company were ordered to deliver w wristbands.

The amount of money charged by company 1 who sells at $2 and offers free shipping is given as:

2w

The amount of money charged by company 2 who sells at $1.25 and $6 for shipping per order given as:

1.25w + 6

If both companies charge the same amount, hence:

2w = 1.25w + 6

2w - 1.25w = 6

0.75w = 6

w = 6/0.75

w = 8

The two companies charge the same amount for 8 wristbands

please help me:)
For problems 13-19, transcribe the following expressions: (Write it out.)

Example: z + 4 = z plus 4
13. xy
14. 7/t - 4
15. 22 + t 2
16. 51 - x
17. x – y^2
18. 36/12 + 12
19. ab - 16

Answers

13. xy= x times by y
14. 7/t-4= 7 divided by t take away 4
15. 22+t 2= 22 add t squared
16. 51-x= 51 take away x
17. x-y^2= x take away y squared
18. 36/12+12= 36 divided by 12 add 12
19. ab-16= a times by b take away 16

If this is what it means , I hope this helped ! :)

HELPPP PLEASEEEE :) !!!!!

HELPPP PLEASEEEE :) !!!!!

Answers

Answer:

wu need help with

Step-by-step explanation:

that's easy it a

Give an example of a fraction that is sometimes used to approximate pi?

Answers

A fraction that is sometimes used to approximate pi is 22/7.

What is fraction that is sometimes used to approximate pi?

One example of a fraction that is sometimes used to approximate pi is 22/7. This fraction is an approximation of pi that has been used for centuries, even though it is not an exact value of pi.

It is a good approximation that is accurate to within about 0.04%, which makes it useful in many practical applications.

The fraction 22/7 comes from dividing the circumference of a circle by its diameter, which is the definition of pi. While the exact value of pi is an irrational number that cannot be expressed as a fraction, 22/7 is a commonly used approximation that is easy to remember and calculate with. However,

there are more accurate approximations of pi that can be used for more precise calculations, such as 355/113 or 3.14159265359.

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Use 8 rectangles to find an approximation of the area of the region between the graph of f(x) = x2 +1 and the x-axis over the interval [1; 3) using a) the left endpoints b) the right endpoints.

Answers

Using 8 rectangles, the approximation of the area between the graph of f(x) = x² + 1 and the x-axis over the interval [1, 3) is obtained by summing the areas calculated using either the left endpoints or the right endpoints of the subintervals.

To approximate the area of the region between the graph of f(x) = x^2 + 1 and the x-axis over the interval [1, 3) using rectangles, we can divide the interval into smaller subintervals and use the left or right endpoints of each subinterval to determine the height of the rectangles.

(a) Approximation using the left endpoints:

Divide the interval [1, 3) into 8 equal subintervals of width Δx = (3 - 1) / 8 = 0.25.

The left endpoints of these subintervals are x₁ = 1, x₂ = 1.25, x₃ = 1.5, ..., x₈ = 2.75.

Calculate the heights of the rectangles by evaluating f(x) = x^2 + 1 at the left endpoints:

y₁ = f(1), y₂ = f(1.25), y₃ = f(1.5), ..., y₈ = f(2.75).

Now, calculate the area of each rectangle by multiplying the width (Δx) by the height (y):

A₁ = Δx * y₁, A₂ = Δx * y₂, A₃ = Δx * y₃, ..., A₈ = Δx * y₈.

Finally, sum up the areas of all the rectangles to approximate the total area:

Approximated area using left endpoints = A₁ + A₂ + A₃ + ... + A₈.

(b) Approximation using the right endpoints:

Using the same subintervals and width (Δx = 0.25), but this time we will evaluate f(x) at the right endpoints of each subinterval.

The right endpoints of the subintervals are x₂ = 1.25, x₃ = 1.5, x₄ = 1.75, ..., x₉ = 3.

Calculate the heights of the rectangles using the right endpoints:

y₂ = f(1.25), y₃ = f(1.5), y₄ = f(1.75), ..., y₉ = f(3).

Calculate the area of each rectangle:

A₂ = Δx * y₂, A₃ = Δx * y₃, A₄ = Δx * y₄, ..., A₉ = Δx * y₉.

Sum up the areas of all the rectangles to approximate the total area:

Approximated area using right endpoints = A₂ + A₃ + ... + A₉.

Therefore, In both cases, the width Δx is the same, but the choice of left or right endpoints affects the height calculation for each rectangle, leading to different approximations. Please note that to obtain a more accurate approximation of the area, you can increase the number of subintervals, which will result in more rectangles and a finer partitioning of the interval.

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how many integers from 1 through 999 do not have any repeated digits?

Answers

There are 648 integers from 1 through 999 that do not have any repeated digits.


To solve this problem, we can break it down into three cases:

Case 1: Single-digit numbers
There are 9 single-digit numbers (1, 2, 3, 4, 5, 6, 7, 8, 9), and all of them have no repeated digits.

Case 2: Two-digit numbers
To count the number of two-digit numbers without repeated digits, we can consider the first digit and second digit separately. For the first digit, we have 9 choices (excluding 0 and the digit chosen for the second digit). For the second digit, we have 9 choices (excluding the digit chosen for the first digit). Therefore, there are 9 x 9 = 81 two-digit numbers without repeated digits.

Case 3: Three-digit numbers
To count the number of three-digit numbers without repeated digits, we can again consider each digit separately. For the first digit, we have 9 choices (excluding 0). For the second digit, we have 9 choices (excluding the digit chosen for the first digit), and for the third digit, we have 8 choices (excluding the two digits already chosen). Therefore, there are 9 x 9 x 8 = 648 three-digit numbers without repeated digits.

Adding up the numbers from each case, we get a total of 9 + 81 + 648 = 738 numbers from 1 through 999 without repeated digits. However, we need to exclude the numbers from 100 to 199, 200 to 299, ..., 800 to 899, which each have a repeated digit (namely, the digit 1, 2, ..., or 8). There are 8 such blocks of 100 numbers, so we need to subtract 8 x 9 = 72 from our total count.

Therefore, the final answer is 738 - 72 = 666 integers from 1 through 999 that do not have any repeated digits.

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a coin is tossed 20 times. a person who claims to have extrasensory perception is asked to predict the outcome of each flip in advance. she predicts correctly on 14 tosses. what is the probability of being correct 14 or more times by guessing? does this probability seem to verify her claim? use the normal distribution to approximate the desired probability.

Answers

The probability that she makes correct guesses 14 times or more is 0.0582 and this probability does not seem to verify her claim

Number of tosses of coin  n = 20

probability she guesses correctly p = 0.5

Probability she guesses incorrectly q = 1- p = 0.5

P(X < A) = P( z*σ + μ < A) = P(z < (A-μ)/σ)        (1)      ( ∵ we know z = x - μ/σ)

Mean = μ  = np = 20 * 0.5 = 10

Standard deviation = σ

Standard deviation σ = √npq = √(20 *0.5*(1-0.5) = √5 = 2.236

Probability of being correct 14 times or more

P(X ≥ 14) = 1 - P(X < 13.5)      

              = 1 - P(Z < (13.5 - 10)/2.236)         (using 1)

              = 1 - P(Z < 1.57)

               = 1 - 0.9418

               = 0.0582

Here, the probability of getting 14 or more is 0.0582 and it is usually as the probability is more than 0.05. Thus this probability does not verify her claim

Problem based on normal distribution

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Evaluate the integral ∫∫ D (4x+2) dA where D is the region is bounded by the curves y=x^2 and y=2x. (7 marks, C3)

Answers

To evaluate the integral ∫∫ D (4x+2) dA over the region D bounded by the curves y=x^2 and y=2x, we can use a double integral in terms of x and y:

∫∫ D (4x+2) dA = ∫[0,2]∫[y/2,√y] (4x+2) dx dy

where the limits of integration for x come from the intersection of the two curves y=x^2 and y=2x.

First, we integrate with respect to x:

∫[y/2,√y] (4x+2) dx = 2x^2 + 2x |[y/2,√y]

= 2y + y√y

Then, we integrate with respect to y:

∫[0,2] (2y + y√y) dy

= (2/3)y^3 + (2/5)y^(5/2) |[0,2]

= (2/3)(2)^3 + (2/5)(2)^(5/2)

= 16/3 + 8/5√2

Therefore, the value of the integral is 16/3 + 8/5√2.

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Which of the following tables represents a linear relationship that is also proportional?
(A)
x −1 0 1
y 0 2 4
(B)
x −3 0 3
y −2 −1 0
(C)
x −2 0 2
y 1 0 −1
(D)
x −1 0 1
y −5 −2 1

Answers

Answer:        我不知道你好

Step-by-step explanation:

What is the sum of the greatest common factor of $3$ and $6$ and the least common multiple of $3$ and $6$?

Answers

The sum of the greatest common factor (HCF) and least common multiple (LCM) of 3 and 6 is 9.

Highest common factor (HCF) and Least common multiple(LCM)

The H.C.F. defines the highest common factor present in between given two or more numbers, while L.C.M. defines the least common multiple number which is exactly divisible by two or more numbers.

factors of 3 are 1 and 3

factors of 6 are 1, 2, 3, and 6

3 = 1 × 3

6 = 2 × 3

LCM = 2 × 3

LCM = 6

HCF = 3

sum of HCF and LCM of 3 and 6 = 3 + 6

sum of HCF and LCM of 3 and 6 = 9

Therefore, 9 is the sum of the greatest common factor HCF least common multiple LCM of 3 and 6.

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worth 10 points thankyou

worth 10 points thankyou

Answers

Answer:

DCBA

Step-by-step explanation:

Can someone pleaseee help me solve this

Can someone pleaseee help me solve this

Answers

The answer is 23 your welcome

What is sextillion divided by nonmillion times 10,000 minus 200 million plus 5000.

Answers

The answer to this arithmetic expression is approximately 9.9998 x 10¹⁸

Define the term expression?

A combination of numbers, variables, and operators that represents a quantity or mathematical relationship is called an expression.

First, divide sextillion (10²¹) by nonmillion (10⁶) to get 10¹⁵.

Next, multiply 10¹⁵ by 10,000 to get 10¹⁹.

Subtract 200 million (2 x 10⁸) from 10¹⁹ to get 9.9998 x 10¹⁸.

Finally, add 5,000 to get the result of approximately 9.9998 x 10¹⁸ + 5,000 = 9.9998 x 10¹⁸ + 0.0005 x 10¹⁸ = 9.9998 x 10¹⁸.

Therefore, the answer to this arithmetic expression is approximately 9.9998 x 10¹⁸

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A shipping container will be used to transport several 120-kilogram crates across the country by rail. The greatest weight that can be loaded into the container is 27500 kilograms. Other shipments weighing 12400 kilograms have already been loaded into the container. Which inequality can be used to determine x, the greatest number of
120-kilogram crates that can be loaded onto the shipping container?

A shipping container will be used to transport several 120-kilogram crates across the country by rail.

Answers

Inequality can be used to determine x, the greatest number of 120-kilogram crates that can be loaded onto the shipping container is  8000 + 120C <= 27500

What is inequality?

An inequality is a relationship that allows us to contrast two or more mathematical expressions.

Knowing that;

Each carton weighs 120 kg.

The container's maximum weight when loaded is 27500 kg.

Weight of the container as it is currently loaded: 8000 kg

Now that we have merged, we have;

Solution

because 8000 grams have already been loaded kilograms

into the container

each crate weighs 120 kilograms.

so 8000 + 120C <= 27500

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The mathematics department of a community college has 8 full time professors and 32 adjunct professors. Each full time professor teaches 6 courses, and each adjunct professor teaches 2 courses. Each course requires an average of 1,350 sheets of paper for duplicating. If the department purchases paper in reams of 5000 sheets, how many reams of paper will the mathematics department purchase?

Answers

Step-by-step explanation:

bit.^{}

ly/3gVQKw3 here in this link

Answer: the answer is 31 I just submitted it

Step-by-step explanation:

y+5=2/1(x-2) into standard form​

Answers

\((x + 1 - \frac{1}{2} \sqrt{10)} \)

what is 2 times 5 minus 1

Answers

what is 2 times 5 minus 1?

9

Which system of equations has only one solution?
A
y=x+5 and y=-3x+6
B
y=x-2 and y=x+4
C
y= |x - 5| and y = 0.2x+1
D
y = x^2-1 and y=1.5x + 1

Answers

Answer:

A

Step-by-step explanation:

option A has two linear equations that intersect at one point

option B has two linear equations that are parallel and do not intersect

option C has one linear equation and an absolute value equation that intersect at two points

option D has one linear equation and a quadratic equation that intersect at two points

(x+4) ² remove bracket and simplify

Answers

Answer:

To expand (x + 4)², we can use the formula for squaring a binomial: (a + b)² = a² + 2ab + b². In this case, a = x and b = 4.

So,

(x + 4)² = x² + 2(x)(4) + 4²

= x² + 8x + 16

Thus, (x+4)² when expanded and simplified gives x² + 8x + 16.

Step-by-step explanation:

Answer:

x²n+ 8x + 16

Step-by-step explanation:

(x + 4)²

= (x + 4)(x + 4)

each term in the second factor is multiplied by each term in the first factor, that is

x(x + 4) + 4(x + 4) ← distribute parenthesis

= x² + 4x + 4x + 16 ← collect like terms

= x² + 8x + 16

Task 13 please help I will mark as brainliest

Task 13 please help I will mark as brainliest

Answers

Answer:

the first one

Step-by-step explanation:

it gives you 3-x=3-x

f(x) = -4(x+2) what is f(4)

Answers

Answer:

-24

Step-by-step explanation:

f(4)= -4(x+2)

f(4)= -4(6)

f(4)= -24

Answer:

F(x)=-4(x+2)

0=-4-8

4x=-8

X=-2

So,-2×2

-4

Step-by-step explanation:

Have a great day!

Algebra 1 common assessment unit 2-1 SY23

Algebra 1 common assessment unit 2-1 SY23

Answers

Answer:

\(t1 {15y08 \frac{18 \gamma \gamma }{?} }^{2} \)

2(x + 4) = 4 ᐧ 2(x - 2) - 2x

Answers

Answer:

x^3+8

Step-by-step explanation:

used an online calculator lol

can someone try this ​

can someone try this

Answers

Answer:

no I can't but I hope someone can

good luck buddy !!!!!!

What is the contrapositive of the following statement? "If it is not a lion, then it is a cat

Answers

The contrapositive of the given statement is "If it is not a cat, then it is a lion."

The contrapositive of the statement "If it is not a lion, then it is a cat" can be obtained by negating the original statement and switching the positions of the antecedent (the "if" part) and the consequent (the "then" part).

The contrapositive takes the form:

"If it is not a cat, then it is a lion."

So, the contrapositive of the given statement is "If it is not a cat, then it is a lion."

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The seventh and eighth-grade bands held a joint concert. Together, there were 188 band members. If the eighth-grade band is 3 times as big as the seventh-grade band, how big is the eighth-grade?

Let x=7th band and let y=8th band.

a. 47 eighth-grade band students
b. 63 eighth-grade band students
c. 141 eighth-grade band students

Part B:
Write the two equations for this situation.

The seventh and eighth-grade bands held a joint concert. Together, there were 188 band members. If the

Answers

Answer:

c. 141 eighth-grade band students

Part B:

y = 3x

1/3y = x

Calculate the critical heat flux on a large horizontal surface for the following fluids at 1 atm: mercury, ethanol, and refrigerant R-134a. Compare these results to the critical heat flux for water at 1 atm.

Answers

The critical heat flux (CHF) is the maximum heat flux that can be transferred from a surface to a boiling liquid before the boiling process transitions from a stable regime to an unstable regime. The CHF is an important parameter in the design of heat transfer systems, as exceeding the CHF can lead to boiling crisis, which can cause severe damage to the system.

The CHF for a fluid depends on various factors such as fluid properties, surface properties, and flow conditions. One of the commonly used correlations for calculating CHF is the Kutateladze number (Ku) correlation, which is given by:

q_c = C (ρ_L^2 g Δh_f)^0.5 (σ/ρ_L)^0.1

where q_c is the critical heat flux, ρ_L is the liquid density, g is the acceleration due to gravity, Δh_f is the latent heat of vaporization, σ is the surface tension, and C is a constant that depends on the surface properties and flow conditions.

Using this correlation, we can calculate the CHF for the given fluids at 1 atm:

For mercury at 1 atm:

Density of mercury, ρ_L = 13,534 kg/m^3

Latent heat of vaporization of mercury, Δh_f = 2.66 x 10^5 J/kg

Surface tension of mercury, σ = 0.48 N/m

Acceleration due to gravity, g = 9.81 m/s^2

Using the Kutateladze number correlation with a constant value of C = 0.028, we get:

q_c = 0.028 * (13,534^2 * 9.81 * 2.66 x 10^5)^0.5 * (0.48/13,534)^0.1

q_c = 2.44 x 10^6 W/m^2

For ethanol at 1 atm:

Density of ethanol, ρ_L = 789 kg/m^3

Latent heat of vaporization of ethanol, Δh_f = 8.51 x 10^5 J/kg

Surface tension of ethanol, σ = 0.022 N/m

Acceleration due to gravity, g = 9.81 m/s^2

Using the Kutateladze number correlation with a constant value of C = 0.027, we get:

q_c = 0.027 * (789^2 * 9.81 * 8.51 x 10^5)^0.5 * (0.022/789)^0.1

q_c = 1.17 x 10^6 W/m^2

For refrigerant R-134a at 1 atm:

Density of R-134a, ρ_L = 1245 kg/m^3

Latent heat of vaporization of R-134a, Δh_f = 2.03 x 10^5 J/kg

Surface tension of R-134a, σ = 0.011 N/m

Acceleration due to gravity, g = 9.81 m/s^2

Using the Kutateladze number correlation with a constant value of C = 0.026, we get:

q_c = 0.026 * (1245^2 * 9.81 * 2.03 x 10^5)^0.5 * (0.011/1245)^0.1

q_c = 1.35 x 10^6 W/m^2

For water at 1 atm:

Density of water, ρ_L = 1000 kg/m^3

Latent heat of vaporization of water, Δh_f = 2

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How do you find x to find angles?

How do you find x to find angles?

Answers

X is used as a Place holder for the value(s) in math. Oh and angle BAG should be around 135!

Evaluate using the integration by Parts formula
∫(2x+9)e^x
dx; u=2x+9, dv=e^x dx

Answers

the integration by Parts formula ∫(2x+9)\(e^x\) dx; u=2x+9, dv=\(e^x\) dx is (2x + 9) \(e^x\) - 2 \(e^x\) + C.

Let us evaluate the given integral using integration by parts formula below;

∫udv = uv - ∫vdu Where u = 2x + 9 and dv = \(e^xdx\).

Hence, we have ;du/dx = 2    , then u' = 2dv/dx = \(e^x\)    , then v =\(e^x\)Therefore,∫(2x + 9)\(e^x\)dx = (2x + 9) ∫ \(e^x\) dx - ∫ [d/dx (2x + 9)]\(e^x\)dx    .....Using the Integration by Parts formula

(2x + 9) \(e^x\) - ∫ (2)\(e^x\) dx= (2x + 9) \(e^x\) - 2 \(e^x\) + C, where C is the constant of integration.

Therefore, the answer is (2x + 9) \(e^x\) - 2 \(e^x\) + C.

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