:answer question number 5

Answer:

1.39 x 10^25 atoms

Explanation:

12 amu of C has 6.02 x 10^23 atoms

so 276.23 amu has

(276.23)(6.02 x 10^23)/(12) = 1.39 x 10^25 atoms

Answer:

The atom economy is defined as the percentage of total mass of reactants that ends up as the desired product.

For the reaction of carbon with steam to produce hydrogen:

C + 2H2O → CO2 + 2H2

The total molar mass of the reactants is:

Mtotal = Mc + 2Mh2o = 12 + 2(18) = 48 g/mol

The molar mass of the desired product (H2) is:

Mh2 = 2(1) = 2 g/mol

The atom economy can be calculated as:

Atom economy = (2Mh2 / Mtotal) x 100% = (2/48) x 100% ≈ 4.17%

Therefore, the atom economy of making hydrogen via this process is approximately 4.17%.

For the reaction of iron (III) oxide with carbon monoxide to produce iron:

Fe2O3 + 3CO → 2Fe + 3CO2

The total molar mass of the reactants is:

Mtotal = 2Mfe2o3 + 3Mco = 2(160) + 3(28) = 404 g/mol

The molar mass of the desired product (Fe) is:

Mfe = 2(56) = 112 g/mol

The atom economy can be calculated as:

Atom economy = (2Mfe / Mtotal) x 100% = (2(56) / 404) x 100% ≈ 46.53%

Therefore, the atom economy of making iron via this process is approximately 46.53%.

Answer:

Mass is .5kg

Explanation:

F=ma, plug in your numbers:

F=4N

A=8m/s^2

4=m8

m=4/8

Mass of tin = moles of tin x molar mass of tin

Mass of tin = 0.020 mol x 118.7 g/mol

Mass of tin = 2.37 g

Therefore, the mass of tin in the chemical reaction is 2.37 g.

If tin is heated, it cracks. This is caused by crystals rubbing against each other. This characteristic crackle is heard if a piece of tin is simply bent. Tin is very malleable and ductile.

Some properties of tin is that it amphoteric. On reacting with both strong bases and strong acids with the evolution of hydrogen occurs. With sodium hydroxide solution, tin forms Na2[Sn(OH)6]. The reaction with acids is slow in the absence of oxygen.

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Answer:

The base dissociation constant for the equation is Kb= [BH][OH-]
                                                                                           -------------------
                                                                                                  [B]

Explanation:

Base dissociation constant,  exists when a weak base is dissolved in water. It is expressed as the ratio of molar concentration of the products and the molar concentration of the reactants raised to power their respective stoichiometric coefficients.

Answer:

Winds are a result of the tendency of warm air to rise and, conversely, cool air to sink. ... Because the atmosphere constantly flows, like a fluid in a container, air rushes into such low pressure areas from cooler, high-pressure ones, and the movement of the air creates wind.

Answer:

The answer is D.

Explanation:

Malleable is the property of metal not non-metal.

Answer:

malleable

Explanation:

6.86 x 10⁻¹¹ mol/L [OH-] is the pH of the resulting solution if 45 ml of 0.432ml methylamine, CH₃NH₂ is added to 15 ml of 0.234 m Hcl.

We must ascertain the amount of H+ ions present in the resultant solution in order to calculate its pH.

For the reaction between HCl and CH₃NH₂, the balanced equation is:

CH₃NH₂ + HCl + CH₃NH₃ + Cl-

We can deduce from the equation that when 1 mole of HCl is combined with 1 mole of CH₃NH₂, 1 mole of CH₃NH₃+ and 1 mole of Cl- are produced.

0.015 L x 0.234 mol/L = 0.00351 mol = moles of HCl

0.045 L x 0.432 mol/L = 0.01944 mol for moles of CH3NH2

All of the HCl will react with the CH₃NH₂ to produce CH₃NH₃+ and Cl- because it is anticipated that the reaction will proceed to completion.

The moles of CH₃NH₃+ in solution are as a result:

CH₃NH₃+ moles equal 0.01944 mol

Kw / Ka for CH₃NH₃+ = Kb for CH₃NH₂.

we obtain: The formula for 2.28 x 10-11 is (0.324 mol/L)([OH-]) / 0.108 mol/L = 6.86 x 10-11 mol/L [OH-]

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Answer:B

Explanation:

Total, 28.6 mL of the 17.5 M stock solution of acetic acid is required to prepare a 500 mL solution of 1.00 M acetic acid.

To determine the volume of the 17.5 M stock solution of acetic acid required to prepare a 500 mL solution of 1.00 M acetic acid, we can use the following formula:

V₁ × C₁ = V₂ × C₂

Where; V₁ = Volume of the stock solution (in liters)

C₁ = Concentration of the stock solution (in moles per liter)

V₂ = Volume of the final solution (in liters)

C₂ = Concentration of the final solution (in moles per liter)

Converting given values to required units;

V₁ = ?

C₁ = 17.5 M

V₂ = 500 mL = 0.5 L

C₂ = 1.00 M

Now, we can plug in the values into the formula and solve for V₁

V₁ × (17.5 M) = (0.5 L) × (1.00 M)

V₁ = (0.5 L × 1.00 M) / 17.5 M

= 0.0286 L

≈ 28.6 mL

Now, we can plug in the values into the formula and solve for V₁

V₁ × (17.5 M) = (0.5 L) × (1.00 M)

V₁ = (0.5 L × 1.00 M) / 17.5 M

= 0.0286 L

≈ 28.6 mL

Therefore, approximately 28.6 mL of the 17.5 M stock solution of acetic acid is required.

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The correct answer is B, 3 mitochondria the student sees in the real cell.

The scale of the model is 1 um: 0.5 cm, which means that for every 1 um in the model, there is 0.5 cm in the real cell. The model includes 6 mitochondria, which means that in the real cell, there are 6 × 0.5 cm = 3 um.

Since the scale is 1 um: 0.5 cm, this means that in the real cell, there are 3 / 1 = 3 mitochondria. Therefore, the student sees 3 mitochondria in the real cell.

When a student makes a model of a cell using a microscope, they typically use a scale to represent the size of the cell and its components in the model. The scale is usually expressed as a ratio, such as 1 um: 0.5 cm, which means that for every 1 unit of measurement in the model (in this case, 1 um), there are 0.5 units of measurement in the real cell (in this case, 0.5 cm).

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Taking into account the definition of dilution, the concentration of the diluted solution is 0.063 M.

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

0.197 M× 2.42 mL= Cf× 7.55 mL

Solving:

(0.197 M× 2.42 mL)÷ 7.55 mL= Cf

0.063 M= Cf

In summary, the concentration of the diluted solution is 0.063 M.

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Answer:

A and D

Explanation:

it might seem like B and D but I took the test and it's A and D.

Answer:

A And D

Yw C: for help

Answer:

353 ppm

Explanation:

PPM also refers to parts per million, it represents a low concentration of a solution. It represents 0.001 gram or a milligram in 1000 mL, equivalent to 1 mg per liter

Given that;

276 mg of Ca in 780.0 g of water

1 ppm = 1 mg/L

780 g = 780 mL = 0.78 L

Therefore;

= 276 mg/ 0.78 L  

=  353.84mg/L

= 353 ppm

The equilibrium constant (K) for the reaction HCN(aq) + NH3(aq) ⇌ CN(aq) + NH4(aq) can be calculated using the given concentrations. The value of K is determined to be 0.036.

To calculate the equilibrium constant (K), we need to use the concentrations of the species at equilibrium. In this case, the given concentrations are:

[HCN] = 0.100 M

[NH3] = 0.140 M

[CN] = 0.055 M

Using the balanced chemical equation, we can write the expression for K as:

K = ([CN][NH4]) / ([HCN][NH3])

Substituting the given concentrations:

K = (0.055)([NH4]) / (0.100)(0.140)

We need to determine the concentration of NH4 at equilibrium. Since HCN and NH3 react to form CN and NH4, we can assume that the change in concentration of NH3 is equal to the change in concentration of NH4.

Change in [NH3] = Change in [NH4]

Let's assume x is the change in concentration of NH3 and NH4 at equilibrium. Therefore:

[HCN] = 0.100 - x

[NH3] = 0.140 - x

[CN] = 0.055 + x

[NH4] = x

Now we can substitute these values into the equilibrium constant expression:

K = (0.055 + x)(x) / ((0.100 - x)(0.140 - x))

Simplifying the expression and neglecting the x term in comparison to the initial concentrations:

K = (0.055)(x) / (0.100)(0.140)

Solving for x:

K = 0.036

Therefore, the equilibrium constant (K) for the given reaction is 0.036.

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Answer: Significant figures in a measurement are all measured digits, and one estimated digit

Significant figures communicate the level of precision in measurements Significant figures are an indicator of the certainty in measurements.

Explanation:

Significant figures : The figures in a number which express the value or the magnitude of a quantity to a specific degree of accuracy or precision is known as significant digits.

The significant figures of a measured quantity are defined as all the digits known with certainty and the first uncertain or estimated digit.

Rules for significant figures:

1. Digits from 1 to 9 are always significant and have infinite number of significant figures.

2. All non-zero numbers are always significant.

3. All zero’s between integers are always significant.

4. All zero’s preceding the first integers are never significant.

5. All zero’s after the decimal point are always significant.

The true statements are

Significant figures in measurement are all measured digits, and one estimated digit

Significant figures communicate the level of precision in measurements Significant figures are an indicator of the certainty in measurements.

The following information should be considered:

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Answer:

Ver explicacion

Explanation:

La gravedad es una fuerza que actúa a distancia. La fuerza que actúa entre la tierra y los cuerpos en ella es la fuerza gravitacional.

Es un ejemplo típico de una fuerza de acción a distancia.

Por lo tanto, la fuerza tat que existe entre la tierra y los cuerpos que se encuentran en ella es una fuerza de distancia.

To calculate the work that an object does when it moves covering a distance of 3000 meters when it is propelled by a force of 65 Newton, one of the principles of mechanics must be considered.

A force does work when there is a displacement of the center of mass of the body on which the force is applied, in the direction of said force.

The work of the force on that body will be equivalent to the energy necessary to displace it, so that:

W = F.d

Substituting the corresponding values in said formula:

F = 65N

d = 3000m

W = 65 N. 3000 m

W = 195000 W

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Answer:

the answer is D I would say thats the answer

Answer:

I really don't know how I got to switching to a new job because I was in a hurry

Answer:Acceleration has to do with changing how fast an object is moving If an object is not changing its velocity, then the object is not accelerating.  Anytime an object's velocity is changing, the object is said to be accelerating it has an acceleration.

Explanation:

Answer: hewo, there! your answer is Below

CH4(g) + 2O2(g) CO2(g) + 2H2O(g) + 802 kJ/mol

Explanation:

Hope this helps!!!

Have a great day!!!

The reaction \(CH_{4} (g)+2O_{2}\) → \(CO_{2}(g) +2H2_{O} (g)+802kJ/mol\)

shows combustion reaction of methane in which energy 802 KJ/mol energy produces.

A combustion reaction occurs when a substance combines with oxygen gas and produces energy in the form of light and heat. One of the reactants in combustion reactions must be oxygen. Water vapor is produced when hydrogen gas is burned.

It can be seen that this reaction give carbon di-oxide and water hence, combustion reaction will show this reaction.

\(CH_{4} (g)+2O_{2}\) → \(CO_{2}(g) +2H2_{O} (g)+802kJ/mol\)

the correct answer will be option (c).

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The value of x in ZnSO4⋅xH2O is 5.87.

The value of x in ZnSO4⋅xH2O can be determined by a simple calculation. First, we need to determine the mass of anhydrous ZnSO4, which can be done by subtracting the mass of the precipitate (0.8223 g) from the mass of the sample (1.013 g).

This yields 0.1907 g of anhydrous ZnSO4. Since ZnSO4⋅xH2O is composed of ZnSO4 and x moles of H2O, we can divide the mass of anhydrous ZnSO4 (0.1907 g) by the molar mass of ZnSO4 (179.45 g/mol) to determine the moles of ZnSO4 present.

Then, we can subtract this from the moles of ZnSO4⋅xH2O present in the original sample (1.013 g) to obtain the moles of H2O. Dividing this by the molar mass of H2O (18.02 g/mol) gives us the value of x, which is 5.87.

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Endothermic and exothermic reactions are two types of chemical reactions. In an endothermic reaction, the energy is absorbed from the surroundings, resulting in a decrease in temperature. On the other hand, in an exothermic reaction, energy is released into the surroundings, resulting in an increase in temperature. In other words, endothermic reactions require energy to be put in, while exothermic reactions release energy. An example of an endothermic reaction is photosynthesis, while combustion is an example of an exothermic reaction.

Answer:

A pure substance has a sharp melting point (melts at one temperature) and a sharp boiling point (boils at one temperature). A mixture melts over a range of temperatures and boils over a range of temperatures. Homogeneous mixtures are called solutions.

Answer:

What is it has fixed boiling point substance or mixture? A pure substance has a sharp melting point (melts at one temperature) and a sharp boiling point (boils at one temperature). A mixture melts over a range of temperatures and boils over a range of temperatures. Homogeneous mixtures are called solutions.

Explanation:

lol they got it from go ogle

The rate of formation of ammonia is 0.0327 mol/L/s, as molecular hydrogen is reacting at the rate of 0.049 M/s.

Given that a mixture of nitrogen and hydrogen gas in the ratio 1:3 by volume is heated at a temperature of 450-5000C and 200-900 atmospheric pressure in the presence of iron as a catalyst and molybdenum as a promoter, ammonia gas is produced. The reaction involved in this process is: N2(g) + 3H2(g) → 2NH3(g)Suppose that at a particular moment during the reaction, molecular hydrogen is reacting at the rate of 0.049 M/s.

To find the rate of formation of ammonia, we need to relate the rate of consumption of hydrogen to the rate of formation of ammonia. The molar ratio of hydrogen to ammonia is 3:2.If 3 mol of H2 reacts, 2 mol of NH3 will be produced. Hence,1 mol of H2 reacts to form 2/3 mol of NH3.So, the rate of formation of ammonia will be (0.049 mol/L/s of H2) × (2/3 mol NH3/1 mol H2) = 0.0327 mol/L/s of NH3. Thus, the rate of formation of ammonia is 0.0327 mol/L/s.

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When a seismic wave passes from the ground into a body of water the waves energy would be absorbed. The correct answer is Option A. Seismic waves move more slowly through a liquid than a solid.

Seismic waves are waves that travel below or over Earth. Explosions, volcanoes and landslides are the reason for the movements of the earth tectonic plates. Seismic waves can be identified by a number of characteristics including the speed the waves travel, the direction that the waves move particles as they pass by, where and where they don't propagate

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Answer:

Krypton

Explanation:

They're both inert gases

Answer:

3.40% corrected to 1dp

Explanation:

78.4-75.7=2.7

percentage error = error/original value× 100

= 2.7/78.40×100

= 3.44387755102040

= 3.40% corrected to 1dp

The equilibrium vapor pressure with respect to water (eow) is 259.9 Pa. assume that saturation vapor pressure is same as equilibrium vapor pressure.

Therefore, the RH at the frost point is  

RH = (eow / saturation vapor pressure) × 100

= (259.9 Pa / 259.9 Pa) × 100

= 100%

b) At T = -11 °C, we need to compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi) to determine if ice particles will form. From the given table, at T = -11 °C, the equilibrium vapor pressure with respect to water (eow) is 237.7 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 165.3 Pa.

The air is supersaturated with respect to ice, and the presence of Kaolinite particles can provide surfaces for water droplets to condense onto, leading to the formation of ice particles.

c) At T = -12 °C, we compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi). From the given table, at T = -12 °C, the equilibrium vapor pressure with respect to water (eow) is 217.3 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 181.2 Pa.

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Potatoes were originally cultivated in South America and were introduced to Europe during the Columbian Exchange, which was a period of cultural and biological exchange between the New World and the Old World. The correct option is D.

While grapes, wheat, barley, and horses were also part of the Columbian Exchange, potatoes were one of the most significant and widely adopted crops that came from the New World.

The Columbian Exchange was a widespread transfer of plants, animals, culture, human populations, technology, and ideas between the Americas and the Old World in the 15th and 16th centuries. Among the various products that were exchanged, potatoes made their way to Europe from the Americas, becoming a significant crop and staple food in European cuisine.

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