Answer your answer and show all the steps that you used to solve this problem in the space provided use the 30° - 60° - 90° triangle theorem to find the answer

Answer:

992

Step-by-step explanation:

You must convert the meter the kilometer by miltiplying by 1000

and when you do it you must multiply 0.992 by 1000 since it is a fraction .

or you can work it this way :

Answer:

Hello!

In 1990 the price of a gallon of unleaded gasoline was 1.37. In 1998 it was 1.02 per gallon what is the decrease expressed. The decrease is 35 cents. This decrease as a percentage is 25%.

Step-by-step explanation:

\(Q= x/100\) of \($1.37 = 0.35\)

\(1.37x/100 = 0.35\)

\(1.37x = 35\)

divide each side by 1.37

answer is 25.5474453... rounded to the nearest 10th is 25%

Hope this helps!!

The simplified form of the expression 4(4y-\(7y^{2}\))-9(5y+2) is -28\(y^{2}\)-29y-18

The given the expression is 4(4y-\(7y^{2}\))-9(5y+2)

To solve this problem first we have to use the distributive property

The distributive property states that multiplying the sum of two or more variables by a number gives the same result as when each variable is multiplied individually by the number and the products are added together

The distributive property of addition

A(B+C) = AB + AC

The distributive property of subtraction

A(B-C) = AB - AC

The given equation is 4(4y-\(7y^{2}\))-9(5y+2)

Apply distributive property

4(4y-\(7y^{2}\))-9(5y+2) = 16y -28\(y^{2}\)-45y-18

Rearrange the terms

-28\(y^{2}\)-45y+16y-18 = -28\(y^{2}\)-29y-18

Hence, the simplified form of the expression 4(4y-\(7y^{2}\))-9(5y+2) is -28\(y^{2}\)-29y-18

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Answer:

P = $140 (the principal amount)

r = 6% per year (the annual interest rate)

n = 12 (the number of times the interest is compounded per year, since it is compounded monthly)

t = 15 years (the time period)

A(15) = $140(1 + 0.06/12)^(12*15)

A(15) = $140(1 + 0.005)^180

A(15) = $281.49

The difference between finite sample and large sample properties of estimators lies in how they perform when applied to a finite sample size or in the limit as the sample size approaches infinity, respectively.

Finite Sample Properties:

Finite sample properties refer to the behavior and characteristics of estimators when applied to a specific, finite sample size. These properties are concerned with the accuracy, precision, bias, efficiency, and consistency of estimators based on the specific sample.

In a finite sample, the properties of estimators can vary. The estimator may be unbiased, meaning that its expected value is equal to the true value of the parameter being estimated. However, it can also be biased, meaning that its expected value deviates from the true value. Additionally, the estimator's precision, or variability, can be high or low. In some cases, estimators with lower bias may have higher variability, and vice versa.

Large Sample Properties:

Large sample properties, on the other hand, focus on the behavior of estimators when the sample size becomes very large, approaching infinity. Large sample properties are based on statistical theories and asymptotic results.

In the large sample limit, certain desirable properties tend to emerge consistently. These properties include consistency, efficiency, and asymptotic normality.

Consistency refers to the property that as the sample size increases, the estimator converges to the true value of the parameter being estimated. In other words, the estimator becomes more accurate as the sample size increases.

Efficiency refers to the property that the estimator has the smallest variance among all unbiased estimators. In other words, it achieves the best precision for a given sample size.

Asymptotic normality refers to the property that the sampling distribution of the estimator approaches a normal distribution as the sample size increases. This property allows for the application of various statistical inference techniques, such as hypothesis testing and confidence interval estimation.

In summary, finite sample properties describe the behavior of estimators in a specific sample size, while large sample properties focus on the behavior of estimators as the sample size becomes large. Large sample properties provide valuable insights into the long-term behavior of estimators, allowing for more robust statistical inference.

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Answer:  A) The volume of the pyramid is 1/3 the volume of the rectangular prism.

Explanation:

Let's say we had a rectangular block that has a volume of 90 cubic meters. If we wanted a pyramid that had the same base as the block, then the pyramid would have 1/3 of that 90 m^3 volume. The pyramidal volume would be (1/3)*90 = 30 m^3.

Put another way: we can fit 3 pyramids into one rectangular block.

Alex will pay 13.8 for her lunch after adding a 15% tip.

We will calculate the amount she paid for her lunch by calculating the tip she paid and adding it to the original price of the lunch(i.e. 12).

\(\implies{\sf{15 \% \ of \ 12 \ = \ 12 \times \dfrac{\cancel{15}}{\cancel{100}} }}\)

\(\implies{\sf{Tip = \cancel{12} \times \dfrac{3}{\cancel{20}}}}\)

\(\implies{\sf{Tip = 3 \times \dfrac{3}{5}}}\)

\(\implies{\sf{Tip = \dfrac{9}{5}}}\)

\(\implies{\sf{ Tip = 1.8}}\)

Now, add the amount of lunch and tip

\(\implies{\bf{ Total \ amount = 12 + 1.8}} \\ \implies{\bf{Total \ amount = 13.8}\)

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Answer:

A: y=3x-1

Step-by-step explanation:

we can use slope formula to get the rate of change

y2-y1/x2-1

3-1/1-0

2/1

2 is the rate of change

so A has the rate of change of 3 so it’s the only one with the greater one

Hopes this helps please mark brainliest

Answer:

it should be 40º but it doesn't look like that's an option...

Step-by-step explanation:

so we know that the inside of a triangle is equal to 180º and for the triangle on the right we already have two angles. so we can add the angles (41 + 72 = 113) and then subtract that from 180 to find the missing angle.

180 - 113 = 67º

now we also know that vertical angles are congruent/the same. so the vertice that is connecting the two triangles is also 67º. we can do the same thing we did with the other triangle, add the angles up and subtract from 180.

67 + 73 = 140

180 - 140 = 40º

we know this is true because when you add all the angles up it equals 180.

67 + 73 = 140 + 40 = 180

44 would put it at 184º which is not correct, and 150 would put it at 290ª which is also not correct...

Answer:

its should be b

Step-by-step explanation

mark brainlist

The types of concurrent constructions that are needed to find the centroid of a triangle include the following: B. intersection of the lines drawn to the midpoint of each side of the triangle to its opposite vertex.

In Mathematics and Geometry, the centroid theorem states that the centroid of a triangle is located at two-third (2/3) of the distance from the vertex to the midpoint of the (opposite) sides.

Generally speaking, the centroid of a triangle simply refers to the point where the three (3) medians of the triangle meet or intersect. This ultimately implies that, a centroid is a point of intersection of the lines from each vertex of a triangle to the midpoint of the opposite sides.

In this context, the types of concurrent constructions would be modeled by answer option B.

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Complete Question:

What types of concurrent constructions are needed to find the centroid of a triangle.

A. intersection of the lines drawn from each vertex of a triangle and perpendicular to its opposite side.

B. intersection of the lines drawn to the midpoint of each side of the triangle to its opposite vertex.

C. intersection of the lines drawn to bisect each vertex of the triangle.

D. intersection of the lines drawn perpendicular to each side of the triangle through its midpoint

there are 120 permutations of 6 letters taken 3 at a time without repetition.
To find the number of permutations of 6 letters taken 3 at a time without repetition, we can use the formula for permutations:

P(n, r) = n! / (n - r)!

where n is the total number of objects and r is the number of objects taken at a time.

In this case, we have 6 letters and we are taking them 3 at a time, so n = 6 and r = 3.

P(6, 3) = 6! / (6 - 3)!
        = 6! / 3!

Now, let's calculate the factorial values:

6! = 6 × 5 × 4 × 3 × 2 × 1
3! = 3 × 2 × 1

Substituting the values into the formula:

P(6, 3) = (6 × 5 × 4 × 3 × 2 × 1) / (3 × 2 × 1)
       = 6 × 5 × 4
       = 120

Therefore, there are 120 permutations of 6 letters taken 3 at a time without repetition.

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The solution of the differential equation y′′(t) y(t) = g(t),

y(0) = 1, y′(0) = 1, for t ≥ 0 with

g(t) = (et sin(t), 0 ≤ t < π 0, t ≥ π] is:

y(t) = - t + \(c_4\) for 0 ≤ t < πy(t) = \(c_5\) for t ≥ π.

where \(c_4\) and \(c_5\) are constants of integration.

The solution of the differential equation

y′′(t) y(t) = g(t),

y(0) = 1,

y′(0) = 1, for t ≥ 0 with

g(t) = (et sin(t), 0 ≤ t < π 0, t ≥ π] is as follows:

The given differential equation is:

y′′(t) y(t) = g(t)

We can write this in the form of a second-order linear differential equation as,

y′′(t) = g(t)/y(t)

This is a separable differential equation, so we can write it as

y′dy/dt = g(t)/y(t)

Now, integrating both sides with respect to t, we get

ln|y| = ∫g(t)/y(t) dt + \(c_1\)

Where \(c_1\) is the constant of integration.

Integrating the right-hand side by parts,

let u = 1/y and dv = g(t) dt, then we get

ln|y| = - ∫(du/dt) ∫g(t)dt dt + \(c_1\)

= - ln|y| + ∫g(t)dt + \(c_1\)

⇒ 2 ln|y| = ∫g(t)dt + \(c_2\)

Where \(c_2\) is the constant of integration.

Taking exponentials on both sides,

we get |y|² = \(e^{\int g(t)}dt\ e^{c_2\)

So we can write the solution of the differential equation as

y(t) = ±\(e^{(\int g(t)dt)/ \sqrt(e^{c_2})\)

= ±\(e^{(\int g(t)}dt\)

where the constant of integration has been absorbed into the positive/negative sign depending on the boundary condition.

Using the initial conditions, we get

y(0) = 1

⇒ ±\(e^{\int g(t)}dt\) = 1y′(0) = 1

⇒ ±\(e^{\int g(t)}dt\) dy/dt + 1 = 0

The above two equations can be used to solve for the constant of integration \(c_2\).

Using the first equation, we get

±\(e^{\intg(t)\)dt = 1

⇒ ∫g(t)dt = 0,

since g(t) = 0 for t ≥ π.

So, the first equation gives us no information.

Using the second equation, we get

±\(e^{\intg(t)}dt\) dy/dt + 1 = 0

⇒ dy/dt = - 1/\(e^{\intg(t)dt\)

Now, integrating both sides with respect to t, we get

y = \(- \int1/e^{\intg(t)\)dt dt + c₃

Where c₃ is the constant of integration.

Using the second initial condition y′(0) = 1,

we get

1 = dy/dt = - 1/\(e^{\int g(t)}\)dt

⇒ \(e^{\int g(t)}\)dt = - 1

Now, substituting this value in the above equation, we get

y = - ∫1/(-1) dt + c₃

= t + c₃

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Answer:

basically its D as the answer

Answer:

Step-by-step explanation:

Answer:

1. x = -4, y = -5

Chosen strategy was to substitute for y in the second equation since the first equation gives y in terms of x. This gives an equation in x which can be solved for x, then y can be found by substituting for x in the first equation

2.  x = -2, y = -3
Strategy used is to eliminate the x terms by simply adding the equations since the coefficients of x are the same but of opposite signs. Solve for y and use this value to solve for x by substituting in any one equation

3. x = -5, y = 6

Strategy used was to set the RHS of the equations equal to each other since both equations are  equations with y on the LHS. Solve for x then use this value to find y value

4. x = 0, y = 1

Strategy used was to get the y coefficients same but of opposite signs, add the two equations to eliminate the y term, solve for x and then solve for y by substituting x in one of the equations - in this case, the second equation

Step-by-step explanation:

Here is how I would answer this question. Remember there are multiple ways of solving a linear equation of two variables but looking at the equations and from experience, I have chosen the most efficient way (my opinion)

Q1.

y = x - 1     [1]
3x - 4y = 8  [2]

Since we are given y = x - 1 in Eq [1], an obvious strategy is to substitute for y in eqn [2]

=>  3x - 4y

=>  3x - 4(x-1)
=>  3x - 4x - 4(-1) =
=> 3x -4x + 4

=> -1x + 4

=> -x + 4

And we know that eqn [2] has 8 on the RHS

∴   -x + 4 = 8

Subtract 4 from both sides

-x + 4 - 4= 8 -4
-x = 4

Multiply by -1 both sides

x = -4

Substitute for x in equation [1] y = x - 1 to get
y = -4 - 1 = -5

Solution: x = -4, y = -5

Q2
3x + 2y = -12    [1}

-3x + 2y = 0     [2]

Here we can see the coefficients of x are the same but with opposite signs

Adding the two equations will eliminate the x terms and  allow us to solve for y which can be used then to solve for x

Adding [1] and [2] gives

3x + 2y + (-3x + 2y) = -12 + 0

4y = -12

y = -3

Substitute for y in equation [1]

=> 3x + 2(-3) = -12

=> 3x - 6 = -12

=> 3x = -12 + 6  (adding 6 on both sides

=> 3x = -6

x = -2

Solution x = -2, y = -3

Strategy used: Adding both equations to eliminate x terms since x coefficients are same but of different signs

Q3

y = 3x + 21  [1]

y = 2x + 16  ][2]

Since we have two expressions for y in terms of x, set the RHS of equations [1] and [2] to be equal and solve for x

=>  3x + 21 = 2x + 16

Subtract 2x from both sides

=> 3x - 2x  + 21 = 16

=> x + 21 = 16

Subtract 21 from both sides

x = 16 - 21  = -5

Substitute for x in equation [2]
y = 2x + 16

=> y =  2(-5) + 16

y = -10 + 16

y = 6

Solution: x = -5, y = 6

Q4

2x - 7y = -7   [1]

x + y = 1        [2]

We can make the coefficients of one of the variable in both equations the same and either add/subtract as necessary to eliminate one of the variable terms and solve for the other

Multiply [2] by 7 to get
7x + 7 y = 7   [3]

[1] and [3] have y coefficients same but of opposite signs so add [1] and [3] together

2x - 7y + (7x + 7y ) = - 7 + 7

2x + 7x - 7y + 7y = 0

9x = 0

x = 0

Sub for x in [2] x + y = 0 to get

0 + y = 1

or y = 1

Solution: x = 0, y = 1

Strategy used was to get the y coefficients same but of opposite signs, add the two equations to eliminate the y term, solve for x and then solve for y by substituting x in one of the equations - in this case, the second equation

If four fudge machines complete a big order in 32 hours. then it takes 128 hours  to complete the order with 4 times the number of machines.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

The number of machines in a factory are four

4 machines complete a big order in 32 hours.

If all the machines at the fudge factory work at the same pace, we need to find How many hours would it take to complete the order with 4 times the number of machines.

4 times the number of machines.

=4×4=16 machine.

How long it will take for 16 machines to complete the same order.

4/32=16/x

Apply cross multiplication

4x=512

x=128

Hence 128 hours would it take to complete the order with 4 times the number of machines.

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To rotate parallelogram WXYZ clockwise 270 degrees around point W, Dylan should draw a circle with W as the center, intersecting sides WX and WZ. Connecting X to the intersection with WX and Y to the intersection with WZ will determine the new position of point Z. This procedure ensures a proper 270-degree rotation.

To rotate the parallelogram WXYZ clockwise 270 degrees around point W, Dylan can use the following steps. First, he needs to draw a circle with W as the center and any radius, intersecting the sides WX and WZ. Let the points of intersection be A and B, respectively.

Then, he should draw lines connecting points X and A, as well as Y and B. The intersecting point of these lines will be the new position of point Z after the rotation.

By following this procedure, Dylan ensures that the parallelogram is rotated 270 degrees clockwise around point W. The circle with W as the center guarantees the preservation of the distance between point W and the other vertices, while the lines connecting X to A and Y to B ensure that the angles between the sides of the parallelogram are maintained. This rotation transforms the initial parallelogram WXYZ into a new configuration with the vertices arranged in their new positions, reflecting the desired 270-degree clockwise rotation around point W.

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To rotate a parallelogram clockwise around a point involves moving each point to the position of the next point in the clockwise direction. In this case, point w remains stationary, while points x, y, and z move in a 270-degree clockwise rotation.

Rotating a shape in geometry is shifting it in a specific direction without alteration of its shape or dimension. When we want to rotate the parallelogram wxyz clockwise 270 around point w, it means that we keep point w fixed and move the remaining points (x, y, z) in a 270-degree clockwise direction.

Let's imagine point w on a 2D plane. Without loss of generality, let us place point w at the origin (0,0). Visualize the rest of the points x, y, z, forming a parallelogram around point w. Upon rotation by 270 degrees clockwise, each point will rotate into the position of the next point in the clockwise direction.

So the point x will replace point w, point y will replace point x, point z will replace point y, and point w, where the rotation begins, will be replaced by point z. Therefore, the new locations of the point after rotation will be: w remains at its position, x comes to the position of w, y comes to the position of x, and z comes to the position of y.

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Answer: 44%

Step-by-step explanation:

125 km are traveled when traveling at a pace of 75 km/h.

The entire travel time to complete 300 km is 1.14 hours, with an average travel speed of 263.15 km/hr.

Given that,

The first 85 kilometers are traveled at a 51 km/hr pace.

A pace of 135 km/hr is used to cover the second 90 km stretch.

75 km/hr is used to cover the remaining distance.

Journey distance is 300 kilometers.

Distance traveled at 75 km/hr is equal to 300 - (85 + 90) = 125 kilometers.

The total time required was 300/261 miles per hour, or 1.14 hours.

The distance traveled divided by the time required equals 300/1.14, or 263.15 kilometers per hour, as the average speed for the whole trip.

Thus, 125 km are traveled when traveling at a pace of 75 km/h.

The entire travel time to complete 300 km is 1.14 hours, with an average travel speed of 263.15 km/hr.

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Answer:

The missing lenght is 12 kilometers.

Step-by-step explanation:

The correct answer is B) the graph of g is a 1/3 horizontal shrink of the graph of f.

A mathematical transformation is the movement of a geometric object or function from one space to another. This new space may be a new quadrant in a Cartesian coordinate system, or it could be a whole new plane or number set. When we translate, we move a figure in any direction. When we flip a figure over a line, we call this reflection. When we rotate a figure a given amount around a point, we call this rotation. Transformations are classified into four types: translation, rotation, reflection, and dilation. Rotation, translation, and reflection are examples of stiff transformations.

Here,

The function g(x) = f(3x) is defined as the transformation of f(x) by replacing x with 3x in the argument of f. This means that each x-value of f(x) is replaced with 3 times its original value in g(x). As a result, the graph of g(x) will be a horizontal shrink of the graph of f(x) by a factor of 1/3. The horizontal axis will be compressed, making the graph appear narrower than the graph of f(x).

The correct answer is B) the graph of g is a horizontal shrink of the graph of f by a factor of 1/3.

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Answer:

B. <

absolute bars make the negative positive

Answer:B

Step-by-step explanation:

There are three commonly used congruency proofs.

Side-angle-side (SAS) congruence.

Side-side-side (SSS) congruence:

Angle-side-angle (ASA) congruence:

To prove that two figures are congruent which means they have the same size and shape in geometry we use the congruency proofs.

We have,

There are commonly used methods to prove congruency.

a) Side-angle-side (SAS) congruence.

Two pairs of congruent sides and the included angle between them is congruent.

b) Side-side-side (SSS) congruence:
Two triangles have three pairs of congruent sides.

c) Angle-side-angle (ASA) congruence:

The two triangles have two pairs of congruent angles and the included side between them is congruent.

Thus,

Side-angle-side (SAS) congruence.

Side-side-side (SSS) congruence:

Angle-side-angle (ASA) congruence:

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Jade give away 3/4 fraction of the cake.

Answer:

x = 4

Step-by-step explanation:

Since M is the midpoint of segment KL, then segments KM and LM are congruent. They have the same length.

4x + 1 = 8x - 15

4x = -16

x = 4

the answer to the inequality is..

Inequality Form: x < 6

Interval Notation: (-∞,6)

Answer:

A 0.4kg object rolling at 2 m/s that's d right answer

Answer:

A 0.4 kg object moving at 4 m.

Step-by-step explanation:

The heavier the object is, the faster it goes. Also the faster is goes and the heavier it is, the more momentum it has.