Aquafers are bodies of water found above ground with thriving ecosystems.
O True
O False

Answer:

202

Explanation:

5 moles of Oxygen gas must totally react with 224 litres of Hydrogen gas at STP.

There is nothing in front of this, thus we may place a one. I get three moles of Carbon dioxide and four moles of Water from one mole of this and five moles of Oxygen. According to Avogadro's law, a mole of any gas has a 22.4 L volume at STP.

2Hydrogen(g) + Oxygen (g) → 2Water (g)

From the equation, we can see that 2 moles of Hydrogen are required to react with 1 mole of Oxygen.

Therefore, to react completely with 5 moles of Oxygen, we need:

5 moles Oxygen × 2 moles Hydrogen / 1 mole Oxygen = 10 moles Hydrogen

At STP (standard temperature and pressure), 1 mole of any ideal gas occupies 22.4 L. Therefore, 10 moles of Hydrogen would occupy:

10 moles H2 × 22.4 L/mole = 224 L

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Answer:

Explanation:

Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.

Metal X can form 2 oxides (A and B).

A + B = 3g

The mass of oxygen in A is 0.72g and the mass of oxygen in B is 1.16g.

The mass of metal X in the two oxides will be the same because it's the same metal.

Thus, we represent the mass of the metal in the two oxides as 2X.

2X + 0.72 + 1.16 = 3

2X + 1.88 = 3

2X = 3 - 1.88

2X = 1.12

X = 0.56

Thus, 0.56 g of the metal combines with 0.72g of oxygen in A and 1.16 g of oxygen in B.

Thus, mass of metal (X) in 1g of oxygen in A is

0.56g ⇒ 0.72g

X ⇒ 1

X = 1 × 0.56/0.72

X = 0.78 g

Hence, 0.78g of the metal will combine with 1g of oxygen for A

Also, mass of metal (X) in 1g of oxygen in B is

0.56g ⇒ 1.16g

X ⇒ 1g

X = 1×0.56/1.16

X = 0.48 g

Thus, 0.48g of the metal will combine with 1g of oxygen for B

This is a perfect answer

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The volume of the solids are found in the attached table.

Volume of a substance refers to the amount of space a given mass of the substance occupies.

Since liquids have no definite volume, the volume of liquids are measured using containers.

Also, the volume of solids can be determined by displacing liquids.

The unit for measuring  the volume of a liquid substance is liters.

Other multiples of the base unit are, mL, cL, dL, daL, hL, kL.

Considering the given volume of substances, the table can be filled as seen in the attachment.

In conclusion, the volume of solids was determined by displacing liquids water.

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Answer:

c. 2s2 2p5

Explanation:

2s2 2p5 has 7 valence electrons and only needs one electron to complete the octet.  This element will be the most electronegative.

Answer:

15.32 days

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 3.83 days

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Time (t) =.?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Number of half-lives (n) =?

N = N₀ / 2ⁿ

14.06 = 225 / 2ⁿ

Cross multiply

14.06 × 2ⁿ = 225

Divide both side by 14.06

2ⁿ = 225 / 14.06

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Half-life (t½) = 3.83 days

Number of half-lives (n) = 4

Time (t) =.?

n = t / t½

4 = t / 3.83

Cross multiply

t = 4 × 3.83

t = 15.32 days

Therefore the time for 225 g sample of Radon to decay to 14.06 g is 15.32 days

A flare would be seen in visible light even though they are much brighter in x-ray and ultraviolet light because (D) The telescopes need to be in space in order to observe x-ray and ultraviolet light.

When the Sun's powerful magnetic fields get too twisted, flares happen. The tangled magnetic fields snap when they are overtwisted, much like a rubber band that snaps when overtwisted.

A quick explosion of energy known as a solar flare is brought on by the tangling, crossing, or reorganisation of magnetic field lines close to sunspots. It contains electrically charged gases that produce strong magnetic fields in some regions.

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In the formation of 1.0 mole of the following crystalline solids from the gaseous ions, the most energy is released by AlF₃. Hence , Option (D) is correct

For an ionic compound, there are two main terms that this magnitude depends upon: ion size and ion charge.

Ion size: the smaller the ionic radii, the shorter the internuclear distance and, therefore, the closer the ions. This factor makes lattice enthalpy increase

Ion charge: the greater the charge on ions, the greater the attractive forces between them and, therefore, the larger the lattice enthalpy.

The lattice enthalpy of AlF₃ (5215 kJ/mol) is indeed greater than that of other given solids

Therefore , In the formation of 1.0 mole of the following crystalline solids from the gaseous ions, the most energy is released by AlF₃. Hence , Option (D) is correct

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Answer:

among these which is not a base is CaSO4

Answer:

\(M=1.62M\)

Explanation:

Hello.

In this case, since the molarity is computed by the division of the moles of the solute by the volume of the solution in liters:

\(M=\frac{n_{solute}}{V_{solution}}\)

We first compute the moles of glucose (molar mass 180 g/mol) as shown below:

\(n_{solute}=582.0g*\frac{1mol}{180g} =3.233mol\)

Therefore, the molarity turns out:

\(M=\frac{3.233mol}{2.00L}\\ \\M=1.62M\)

Best regards.

The freezing point of the silver nitrate solution is - 12.6 degrees Celsius.

We know that freezing point is a colligative property. This implies that it depends on the amount of the substance that is present . We should also know that when we dissolve the  silver nitrate in water, the particles of the substance would decrease the freezing point of the water.

Freezing point of water = 0 degrees Celsius

Molality of the solution = 3.40 m

Freezing constant of water =  1.86∘C/m

We now have;

ΔT = K m i

ΔT =  1.86∘C/m *  3.40 m * 2

ΔT = 12.6 degrees

Temperature of the solution = 0 - 12.6 = - 12.6 degrees Celsius

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Answer: D- ecotourism helps pay for conservation efforts

Explanation:

says help and the others exploit and harm

A polymer is a molecule that has a very long chain of monomers, which can be defined as a single part of the molecule that repeats itself throughout a polymer. So the union of many monomers results in a polymer. For example, the PVC (polyvinyl chloride) has the following monomer:

When this monomer repeats itself, the resulting chain has the following denotation:

Where n = the number of times vinyl chloride repeats in the polymer structure

For this reason of being a very long-chain molecule, polymers have specific properties such as high resistance to heat, they can be flexible or tough, and they can conduct electricity or not; every property depends on the polymer and its structure. So plastics, besides other commonly used materials, are an example of a polymeric material and are usually referred to as a polymer.

Hard water contains higher levels of minerals such as calcium and magnesium, while soft water has low levels of these minerals. While both hard and soft water can be safe for drinking, hard water is generally considered safer due to the minerals it contains.

The minerals in hard water can actually be beneficial to human health, as they are important for strong bones and teeth. In addition, the minerals in hard water can help to balance the body's electrolytes and may have other health benefits.

Soft water, on the other hand, may contain higher levels of sodium or other chemicals used in the softening process. While these levels are generally considered safe, some people with certain health conditions may need to avoid drinking water with higher sodium levels.

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It can take hundreds of billions of years for a red dwarf to convert all of its hydrogen completely to helium is false it takes less than 14 billion years to completely burn through its fuel.

A red dwarf is one of the smallest and coldest stars on the main sequence. As red people are the most common type of star in the Milky Way, at least in the vicinity of the Sun, but because of their low luminosity, people cannot be easily observed.

In the solar core, the temperature and density are gigantic and cause nuclear fusion of hydrogen into helium. Four hydrogen atoms fuse to form a helium atom. And this fusion is an incredible way to produce energy.

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Answer:

The heat absorbed in Trial 2 is about 1,240 J greater than the heat absorbed in Trial 1.

The heat absorbed in Trial 2 is about 1,674 J greater than the heat absorbed in Trial 1.

The amount of heat absorbed or released by a substance can be calculated using the formula Q = mcΔT, where Q represents heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

In this case, the mass (m) is the same in both trials, but the initial and final temperatures (ΔT) differ. By comparing the values of ΔT in both trials, we can determine the difference in the amount of heat absorbed.

In Trial 1, the initial temperature is 15.0 °C and the final temperature is 65.0 °C, resulting in a ΔT of 65.0 - 15.0 = 50.0 °C.

In Trial 2, the initial temperature is 10.0 °C and the final temperature is 65.0 °C, resulting in a ΔT of 65.0 - 10.0 = 55.0 °C.

Since the specific heat capacity of water is approximately 4.18 J/g°C, we can calculate the difference in heat absorbed:

ΔQ = mcΔT = (80.0 g)(4.18 J/g°C)(55.0 °C - 50.0 °C) = 1,674 J

Therefore, the heat absorbed in Trial 2 is approximately 1,674 J greater than the heat absorbed in Trial 1.

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The limiting and excess reactant can be obtained as follow:

2Mg + O₂ -> 2MgO

From the balanced equation above,

48 g of Mg reacted with 32 g of O₂

Therefore,

62.1 g of Mg will react with = (62.1 × 32) / 48 = 41.4 g of O₂

We can see from the above that only 41.4 g of O₂ is required to react completely with 62.1 g of Mg.

Thus, the limiting reactant is magnesium, Mg and the excess reactant is oxygen, O₂

The mass of the excess reactant remaining can be obtained as shown below:

Mass of excess reactant remaining = Mass given - mass reacted

Mass of excess reactant remaining = 100 - 41.4

Mass of excess reactant remaining = 58.6 g

The mass of H₂SO₄ produced can be obtained as illustrated below:

Mg + O₂ -> 2MgO

From the balanced equation above,

48 g of Mg reacted to produce 80 g of MgO

Therefore,

62.1 g of Mg will react to produce = (62.1 × 80) / 48 = 103.5 g of MgO

Thus, the mass of product, MgO produced is 103.5 g

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Complete question:

If 62.1 grams of magnesium react with 100.0 grams of oxygen, how many grams of product are produced?

Which is the Limiting reactant?

Which is the Excess reactant?

How many grams of excess reactant remain?

Answer:

The common system of naming alcohol in its series is alcohol

In comparison to modern, highly accurate density meters or pycnometers, hydrometers are far less accurate and temperature.

Thus,  Although they require very large sample sizes, hydrometers are rather simple to operate. Usually, 300 to 500 ml per measurement are required. Hydrometers frequently require calibration off-site as well.

With measurements taken by eye, user error is a major issue, and temperature management is especially challenging. Inaccurately bringing and maintaining samples at temperature might take a long time, and once more, user perception of temperature levels is used to determine temperature levels.

Pycnometers and hydrometers have a further problem in that the findings of alcohol measurement are challenging to evaluate and record.

Thus, In comparison to modern, highly accurate density meters or pycnometers, hydrometers are far less accurate and temperature.

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Answer:

2.5 moles of aluminum oxide will form when all 5.0 moles of aluminum are used up.

Explanation:

The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O2) to form aluminum oxide (Al2O3) is:

4 Al + 3 O2 → 2 Al2O3

This equation shows that 4 moles of aluminum react with 3 moles of oxygen to form 2 moles of aluminum oxide.

According to the problem, we have 5.0 mol of aluminum, which is more than enough to react with the oxygen available, and the limiting reagent in this reaction will be aluminum. Therefore, we need to use the mole ratio from the balanced equation to find out how many moles of aluminum oxide will form when all 5.0 moles of aluminum are used up.

From the equation, we can see that for every 4 moles of aluminum, 2 moles of aluminum oxide will form. Therefore, the mole ratio of aluminum to aluminum oxide is 4:2, or simplified, 2:1.

Using this mole ratio, we can calculate the number of moles of aluminum oxide that will form when all 5.0 moles of aluminum react:

5.0 mol Al × (2 mol Al2O3/4 mol Al) = 2.5 mol Al2O3

Therefore, 2.5 moles of aluminum oxide will form when all 5.0 moles of aluminum are used up.

The number of mole of the gas that were lost is 0.021 mole

We'll begin by obtaining the initial mole of the gas. This is obatined as follow:

PV = nRT

Divide both sides by RT

n = PV / RT

n = (225 × 1.75) / (8.314 × 298)

n = 0.159 mole

Next, we shall determine the new mole of the gas. This is illustrated below:

PV = nRT

Divide both sides by RT

n = PV / RT

n = (185 × 1.75) / (8.314 × 283)

n = 0.138 mole

Finally, we sall determine the mole of the gas that were lost. This can be obtained as follow:

Mole lost = 0.159 - 0.138

Mole lost = 0.021 mole

Thus, the mole lost is 0.021 mole

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The answers include the following below:

This is referred to as the science of cultivating the soil, growing crops and raising livestock for different purposes.

In determining a good location for a farm, the area has to be one which has a good infrastructure, fertile soil, and various forms of labor needed for its operations and activities. This is because there is easy access to many resource required for an agricultural business.

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The full question is:

Julian wants to grow carrots and corn. He purchases a farm in a town called Daisyville. Daisyville is well connected to the nearest market by road and railways. Its good 1. _____is one of the major reasons Julian chose Daisyville to start his business. Additionally, Daisyville has a favorable climate, fertile soil, and a good supply of skilled, unskilled, and experienced farm 2. _______ This meant Daisyville would give Julian easy access to many 3._____ required for an agricultural business.

The options are:

1.

A. Income

B. infrastructure

C. Production

D. stock

2,

A.Labor

B.Pests

C.Produce

D. Soil

3.

A. Ambience

B. Demand

C. Finance

D. Resource

Answer:

61.6 g

Explanation:

Step 1: Write the balanced equation

C + O₂ → CO₂

Since there are 14.6 g of oxygen that remain unreacted by the end of the reaction, oxygen is the reactant in excess and carbon is the limiting reactant, thus the one used to calculate the mass of carbon dioxide produced.

Step 2: Calculate the moles corresponding to 16.8 g of C

The molar mass of C is 12.01 g/mol

16.8 g × 1 mol/12.01 g = 1.40 mol

Step 3: Calculate the number of moles of CO₂ produced from 1.40 moles of C

The molar ratio of C to CO₂ is 1:1. The moles of CO₂ produced are 1/1 × 1.40 mol = 1.40 mol.

Step 4: Calculate the mass corresponding to 1.40 moles of CO₂

The molar mass of CO₂ is 44.01 g/mol.

1.40 mol × 44.01 g/mol = 61.6 g

Answer:

Explanation:

From the information given:

a)

The function of a buffer is effective between the region of  about one pH unit below and one unit above its pKa value.

For glycine; The pH range that is best effective for glycine to be used as a buffer is: (9.6 - 1.0) to (9.6 + 1.0)

= 8.6 to 10.6 pH region

b)  In a 0.1 M solution of glycine at pH 9.0, what fraction of glycine has its amino group in the -NH3+ form?

According to Henderson hasselbalch equation:

pH = pKa + log [A⁻]/[HA]

9.0 = 9.6 + log [A⁻]/[HA]

[A⁻]/[HA] = \(10 ^{9.6-9.0}\)

[A⁻]/[HA] = \(10^{0.6}\)

[A⁻]/[HA] = 0.25 = 1/4

C) How much 5 M KOH must be added to 1.0 L of 0.1 M glycine at pH 9.0 to bring its pH to exactly 10.0?

Using Henderson Hasselbalch equation

pH = pKa + log[A-]/[HA]

1 mole of KOH would result in 1 mole of [A-] salt formation

The number of moles of glycine = Molarity  x Litre = 0.1 x 1 = 0.1 moles

From (B) :

[A⁻]/[HA] = 0.25

[A⁻] = 0.25 [HA]

we know that, equal volume of [base]+[acid] = 0.1

For [A-] from above:

0.25[acid] + [acid] = 0.1

1.25[acid] = 0.1

[acid] = 0.1/1.25

=  0.08 mol,

NOW; [base] = 1 - 0.08 mol

= 0.02 mol

For pH at  10.0

pH = pKa + log [A⁻]/[HA]

10.0 = 9.6 + log[A-]/[HA]

10.0 -9.6 =  log[A-]/[HA]

0.4 = log[A-]/[HA]

[A-]/[HA]  = \(10^{0.4}\)

[A-] = 2.511[HA]

Now;

2.5[acid] + [acid] = 0.1

[acid] = 0.03 mol,

[base] = 1-  0.03 mol  = 0.07 mol

Thus,  the difference between the two moles of [base] is  (0.07 - 0.02) = 0.05 mol will be the amount of base required to be added

Finally, the volume of KOH = number of moles/Molarity of KOH

= 0.05/5

= 0.010 L

= 10 mL

Therefore; the volume of KOH needed to add would be 10 mL in order to bring the pH  from 9.0 to exactly pH 10.0

D) When 99% of the glycine is in its -NH3+ form, what is the numerical relation between the pH of the solution and the pKa of the amino group?

Using Henderson Hasselbalch equation again:

\(pH = pKa + log [\dfrac{NH_2}{NH_3^+}]\)

\(pH = pKa + log [\dfrac{0.01}{0.99}]\)

pH = pKa + (-1.99)

pH = pKa - 1.99

Therefore ,  the numerical relation between the pH of the solution and the pKa of the amino group is approximately 2.00 pH units

A balloon filled with 2.00L of helium initially at 1.15 atm of pressure rises into the atmosphere. When the surrounding pressure reaches 370.mmHg, the balloon will burst. What volume will the ballon occupy in the instant before it bursts?

From the problem we can identify that:

Vi = 2.00 L Pi = 1.15 atm

Vf = ? Pf = 370 mmHg

Before we calculate the final volume we have to take the pressures to the same unit. We can convert the final pressure from mmHg to atm. We know that 760 mmHg is equal to 1 atm, so:

760 mmHg = 1 atm

Pf = 370 mmHg * 1 atm/(760 mmHg) = 0.487 atm

Pf = 0.487 atm

Since the process is at constant temperature, we can apply this formula to calculate the final volume:

Pi * Vi = Pf * Vf

Vf = Pi * Vi / Pf

Vf = 1.15 atm * 2.00 L / 0.487 atm

Vf = 4.72 L

Answer: the volume that the balloon will occupy is 4.72 L.

The statement that is true of a Lewis base is that a Lewis base donates electron pairs (option A).

A Lewis base is any nucleophylic compound that can donate a pair of electrons and form a coordinate covalent bond.

On the other hand, a Lewis acid is any electrophylic compound that can accept a pair of electrons and form a coordinate covalent bond.

This means that a Lewis base can donate a pair of electrons to a Lewis acid to form a product containing a coordinate covalent bond. This product is also referred to as a Lewis adduct.

Therefore, option A is correct about Lewis base

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