Answer:
70
Step-by-step explanation:
The vertices of a rectangle are located at the coordinates (1, 4), (1, 5), (6, 5), and (6, 4).
Find the length of the sides of the rectangle and its perimeter.
Check the picture below.
What i the meaure in radian for the central angle of a circle whoe radiu i 9 cm and intercepted arc length i 7. 2 cm?
Enter your anwer a a decimal in the box. Radian
The central angle (in radians ) is 0.8 radians.
What is a cricle ?
A circle is a basic 2D shape measured by its radius. A circle divides the plane into two areas: interior and exterior. Similar to line type. Imagine a line segment bending until the ends connect. Arrange the loops so that they form a perfect circle.
we know that,
arc length = radius * central angle (in radians)
and central angle (in radians) = arc length / radius
by substituting the given values
arc length = 7.2
radius=9
we get,
central angle (in radians) = 7.2 / 9
=0.8 radians
Hence , the central angle = 0.8 radians
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solve by factorising
2x^2+3x-20=0
Answer:
Step-by-step explanation:
2x^2+8x+5x-20=0
2x(x+4) - 5(x+4)=0
(2x-5)(x+4)=0
x=-4 or x=5/2
Divide.
(2x² - 2x-7) divided by (x+2)
Your answer should give the quotient and the remainder.
Answer:
2x³-2x²-3x-14
Hope it helps you
Find the exact length of the curve. y = In(sec(x)), 0≤x≤ Need Help? Read It π 4 Watch It
The curve is y = In(sec(x)) and we have to find its length. We are given the range as 0 ≤ x ≤ π/4. So, the formula for the length of the curve is given as:
To solve for the length of the curve of y = In(sec(x)), we use the formula,
`L = ∫[a,b] √[1+(f′(x))^2] dx`.Where, `a = 0` and `b = π/4`. And `f′(x)` is the derivative of `In(sec(x))`.
We know that:`f′(x) = d/dx[In(sec(x))]`
Using the formula of logarithm differentiation, we can write the above equation as:
`f′(x) = d/dx[In(1/cos(x))]`
So,`f′(x) = -d/dx[In(cos(x))]`
Therefore,`f′(x) = -sin(x)/cos(x)`
Substituting the values, we get:
`L = ∫[a,b] √[1+(f′(x))^2] dx`
`L = ∫[0,π/4] √[1+(-sin(x)/cos(x))^2] dx`
`L = ∫[0,π/4] √[(cos^2(x)+sin^2(x))/(cos^2(x))] dx`
`L = ∫[0,π/4] sec(x) dx`
Now, `L = ln(sec(x) + tan(x)) + C` where `C` is a constant.
We calculate the constant by substituting the values of `a = 0` and `b = π/4`:
`L = ln(sec(π/4) + tan(π/4)) - ln(sec(0) + tan(0))`
`L = ln(√2 + 1) - ln(1 + 0)`
`L = ln(√2 + 1)`
Thus, the exact length of the curve is `ln(√2 + 1)` units.
Thus, the exact length of the curve of y = In(sec(x)), 0≤x≤π/4 is `ln(√2 + 1)` units.
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Other things being equal, an alpha level of .01 should lead to a rejection of the null hypothesis:_________
An alpha level of 0.01 indicates a stringent criterion for statistical significance. In most cases, it would lead to the rejection of the null hypothesis.
In statistical hypothesis testing, the null hypothesis represents the absence of a relationship or effect. The alpha level, also known as the significance level, determines the threshold for rejecting the null hypothesis. An alpha level of 0.01 implies that the researcher is willing to accept a 1% chance of making a Type I error, which is the rejection of a true null hypothesis.
When conducting hypothesis testing, if the calculated p-value (the probability of observing the data or more extreme results given that the null hypothesis is true) is less than the alpha level, it is considered statistically significant. In the case of an alpha level of 0.01, if the p-value falls below this threshold, the null hypothesis is rejected. This means that the observed results are unlikely to occur by chance alone and provide sufficient evidence to support the alternative hypothesis, which suggests the presence of a relationship or effect.
However, it's important to note that the appropriateness of an alpha level depends on various factors, such as the field of study, sample size, and the potential consequences of Type I and Type II errors. Researchers need to carefully consider the context and interpret the results accordingly.
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Robert has a steel barrel with a diameter of 6 feet that can be filled to a depth of 4.9 feet with oil. What is the volume of the barrel?
Use pi = 3.14
A.
102.174 cubic feet
B.
162.594 cubic feet
C.
138.474 cubic feet
D.
132.3 cubic feet
The volume of the steel barrel with the given diameter and depth is 138.474ft³.
Hence, option C) 138.474 cubic feet is the correct answer.
What is a cylinder?A cylinder is simply a 3-dimensional shape having two parallel circular bases joined by a curved surface.
The volume of a cylinder is expressed as;
V = π × r² × h
Where r is radius of the circular base, h is height and π is constant pi ( π = 3.14 )
Given the data in the question;
Diameter of the steel barrel d = 6ftRadius r = d/2 = 6ft/2 = 3ftDepth or height h = 4.9ftConstant pi π = 3.14Volume of the steel barrel V = ?
We substitute our values into the expression above.
V = π × r² × h
V = 3.14 × (3ft)² × 4.9ft
V = 3.14 × 9ft² × 4.9ft
V = 138.474ft³
The volume of the steel barrel with the given diameter and depth is 138.474ft³.
Hence, option C) 138.474 cubic feet is the correct answer.
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X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y) (2 points) v(3x 2y) (4 points) find p(3x 2y>20) (4 points)
The result for the given normal random variables are as follows;
a. E(3X + 2Y) = 18
b. V(3X + 2Y) = 77
c. P(3X + 2Y < 18) = 0.5
d. P(3X + 2Y < 28) = 0.8729
What is normal random variables?Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.
Now, according to the question;
The given normal random variables are;
E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.
Part a.
Consider E(3X + 2Y)
\(\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}\)
Part b.
Consider V(3X + 2Y)
\(\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}\)
Part c.
Consider P(3X + 2Y < 18)
A normal random variable is also linear combination of two independent normal random variables.
\(3 X+2 Y \sim N(18,77)\)
Thus,
\(P(3 X+2 Y < 18)=0.5\)
Part d.
Consider P(3X + 2Y < 28)
\(Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}\)
\(\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}\)
Therefore, the values for the given normal random variables are found.
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The correct question is-
X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:
a. E(3X + 2Y)
b. V(3X + 2Y)
c. P(3X + 2Y < 18)
d. P(3X + 2Y < 28)
DUE IN 2 HOURS.Need help on circled one.GIVING BRAINLIEST.
Answer:
C is the hypothenuse of the Triangle,
Ten is the hypothenuse
Seven is the leg
So do it like this:
\(7^2+b^2=10^2\\\\49 + b^2 = 100\\b^2 = 100-49\\b^2 = 51\\\\b = \sqrt{51}\)
Find a polynomial f(x) of degree 4 with real coefficients and the following zeros:
2 (multiplicity 2), i
The polynomial from the given problem is; f(x) = (x - 2)(x - 2)(x + i)(x - i)
How to find the polynomial?First of all, we will use the factored form of a polynomial. Since we are told that the degree of the polynomial is 4, then, there will be four factors written as:
f(x) = a(x - p)(x - q)(x - r)(x - s)
where;
a is a constant
p, q, r, s are the zeros of the polynomial.
We are given three of the four roots. Now, a multiplicity of 2 means that the root appears twice, and as such the three roots are 2, 2, and -i.
Now with real coefficients, we can employ the conjugate root theorem which states that if -i is a root or zero of a polynomial, then +I is also a zero of the polynomial.
Thus, all 4 roots will be: 2, 2, -i, and i.
The polynomial will then be expressed as;
f(x) = a·(x - 2)(x - 2)(x + i)(x - i)
Since we are asked to find any polynomial, then we can choose an value of a except zero. If we select a = 1, then the polynomial will be;
f(x) = (x - 2)(x - 2)(x + i)(x - i)
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i need the first and second one, please anyone
Answer:
f(-1) = 0
f(2) = 16
Step-by-step explanation:
f(-1) = 4(-1) + 4 = 0
f(2) = 4(2) + 8 = 16
. suppose that the solutions to the characteristic equation are m1 and m2. list all the cases in which the general solution y(x) has the property that y(x) → 0 as x → [infinity]
If the solutions to the characteristic equation are m1 and m2, the general solution y(x) will have the property that,
y(x) → 0 as x → ∞ in the following cases:
CASE-1:
Both m1 and m2 are negative real numbers. In this case, the general solution will be:
y(x) = C1 * e^(m1 * x) + C2 * e^(m2 * x), and as x → ∞, y(x) → 0 due to the exponential decay of the negative exponents.
CASE-2:
m1 and m2 are complex conjugates with negative real parts. This occurs when the characteristic equation has complex roots with negative real components.
In this case, the general solution will be y(x) = e^(α * x) * (C1 * cos(β * x) + C2 * sin(β * x)),
where α is the negative real part, and β is the imaginary part of the complex conjugates.
As x → ∞, y(x) → 0 because the exponential term (e^(α * x)) decays to zero.
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Which of the following is the domain of the graph below?
Answer:
That answer is correct
Step-by-step explanation:
all of the other ones have errors in them, the domain is every dot above below or on the x-axis.
Determine the value of x in the triangle below:
x = 65
x = 45
x = 20
x = 50
Answer: 45
Because 8*2.25=18 it has to be the same way to calculate below on the same triangle
20*2.25=45
hamid has three boxes of different fruits. Box A weighs 5/4 kg more than Box B and Box C weighs 41/4 kg more than Box B. The total weight of the three boxes is 195/4 kg. What is weight of box a
Answer:
The answer is 39 kg
Step-by-step explanation:
We are looking for the weight of box A so we will use the number given to use for Box A.
We also have the total which is 194/4 kg
If we divide 195 by 5 we will get 39 kg
But to check if your answer is correct also divide 195 by 41 and that will give us 4.75 kg
And if you add the two answers up your will get 43.75 kg
Now we need to find the weight of Box B to see if our answer is correct
When you subtract 43.75 from 195 you will get 151.25
When we will add 43.75 to 151.25 you will get 195
So the answer is correct, the answer is 39 Kg
Two trains leave towns 1160 kilometers apart at the same time and travel toward each other. One train travels 22 faster than the other. If they meet in 4 hours, what is the rate of each train? h
Distance = rate x time
x= rate of slower train
x+22 = rate of faster train
Both trains meet when the sum of the distances is 1160 km.
4x+ 4 (x+22) = 1160
Solve for x:
4x+4x+88 = 1160
8x = 1160-88
8x = 1072
x= 1072/8
x= 134
rate of slower train = 134 km /h
Rate of faster train= x+22 = 134+22 = 156 km/h
The measures of the angles of a triangle are shown in the figure below. Solve for x.
54°
(7x+1)°
The value of x according to the complete task content as given is; 5.
Sum of interior angles in a triangle.It follows from the complete task content that a right angled triangle is given(in which case one of the angles is a right angle = 90°).
Hence, the required value of x can be determined from the; sum of interior angles of a triangle as follows;
90° + 54° + 7x + 1° = 180°
7x = 180° - 90° - 54° - 1°
Evaluate the right side of the equation;
7x = 35°
Divide both sides by; 7;
x = 35°/7
x = 5.
Ultimately, the value of x according to the task content is; 5.
Remark:
The completed task content is; The measures of the angles of a triangle are shown in the figure below. Solve for x. The figure is a right triangle with the other two interior angles 54° and (7x + 1)°.
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The following algebraic expression is given: 1 xy + 5y + 2x + 10 2.1 What do you notice about all 4 terms?
Answer: linear combo of terms involving x & y, with respective numbers determining their contribution to the expression
In a sample of 16 employees randomly selected at a company, the average age is 25 years and the standard deviation is 2 years. We want to test if the average age of all employees is greater than 24. If ages are normally distributed in the population, using a significance level of 0.05, we can claim that the population mean is: Group of answer choices
If ages are normally distributed then using a significance level of 0.05 , we can claim that the population mean is greater than 24.
Given sample mean of 25 years , sample size of 16 ,standard deviation of 2 years.
We have to find whether the population average is greater than 24.
We have to use t test because n is less than 30. It is right tailed.
We have to first form Hypothesis.
\(H_{0}\):μ>24,
\(H_{1}\):μ<24.
t=X-μ/S/\(\sqrt{n}\)
t critical at 5% significance level and degree of freedom=15 (16-1)=1.7531
t=24-25/2/\(\sqrt{16}\)
=-1/0.5
=-2
Because 1.7531 is greater than -2 so we will accept the null hypothesis.
Hence we can say that the average of population is greater than 24.
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Jayden’s family is going to Magic Mountain Amusement Park. It is 320 miles. They drive at an average speed of 64 miles per hour on highway. How long will it take Jayden’s family to get to the park?
The unknown quantity, equation, and the answer in a complete sentence.
Answer:
5 hours
Step-by-step explanation:
You can use a simple equation for this problem, speed times time is distance. s * t = x. In this case, the distance, x, is 320 and the speed, s, is 64. We can move the s from the equation around and get t = x/s. So time = 320/64 which is 5 hours.
What is the area of section A? OA. 49 square inches OB. 28.5 square inches OC. 14 square inches OD. 24.5 square inches Section A 7 inches 7 inches *Picture not drawn to scale
the area of section A, which has side lengths of 7 inches each.
To determine the area, we will use the following terms:
area, square inches, and side lengths.Area = Side length × Side length
Area = 7 inches × 7 inches
7 inches × 7 inches = 49 square inches
So, the area of section A is 49 square inches (OA).
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The height of a triangle is 5 more than double the base length. If the height of the triangle is 74 mm, what is the base length of the triangle? If b represents the length of the base in mm, the equation that represents this problem is
Answer:
The base length of the triangle is 34.5 mm.
34.5×2+5=74.
Step-by-step explanation:
Subtract 5 from 74 then divide 2 from 69 and you will get 34.5.
Answer:
The first answer is 74=2b+5
And the second answer is 34.5
Step-by-step explanation:
please help it’s for tomorrow..
one segment measures 161 cm. Calculate its multiple according to the number 3 and its submultiple according to the number 7
Answer:
78
Step-by-step explanation:
The answer is 78 or 87 dear friend its a mystery
Simplify
1) 9/7+1/6
2) 1 1/6- 2 1/5
3) 4/7x8/4
4) 4/7* 8/4
you answer fast and correct I will mark you as a brainliest
Answer:
1 19/42
- 1 1/30
3&4 are both 1 1/7
Step-by-step explanation:
b.) Shipping is free for all online orders over $70. Write an inequality to describe the amount of money you will need to spend to get free shipping.
Inequality:
help? i cant understand
Can some also help me with these problems please.
Answer:
5. ∠1.
6. ∠3.
7. ∠1.
8. 180°.
note: wherever there is a ∠ symbol, it means "angle".
Step-by-step explanation:
5. An exterior angle of the triangle is ∠1.
6. The remote interior angles of the triangle to the exterior angle 1 are ∠2 and ∠3.
7. The sum of the measure of angles 2 and 3 is equal to the measure of ∠1.
8. The sum of the measure of angles 1 and 4 is 180°.
note: wherever there is a ∠ symbol, it means "angle".
Find the volume given cylinder. 8in,8in. Use 3.14 for pi and round to the nearest tenth.
A.1607.7in*3
B.2845.7in*3
C.6430.7in*3
D.401.9in*3
2.Find the volume of a rectangular prism with the following dimensions: L=5mm B=7mm H=3mm
142mm*3
105mm*3
126mm*3
130mm*3
3.Find the volume of the given pyramid. 7yd,7yd,9yd
147yd*3
175yd
Answer:
1. \(V =1607.7\ in^3\)
2. \(V = 105mm^3\)
3. \(V = 147yd^3\)
Step-by-step explanation:
Solving (1):
Given
\(Radius, r =8\ in\)
\(Height, h =8\ in\)
Required
Determine the volume
Volume (V) of a cylinder is calculated as thus:
\(V =\pi r^2h\)
\(V =3.14 * 8^2 * 8\)
\(V =1607.7\ in^3\)
Hence, the volume of the cylinder is \(1607.7\ in^3\)
Solving (2):
Given
\(Length, l = 5mm\)
\(Width, B = 7mm\)
\(Height, H = 3mm\)
Required
Determine the volume (V) of the rectangular prism
Volume (V) of a rectangular prism is calculated as thus:
\(V = LBH\)
\(V = 5mm * 7mm * 3mm\)
\(V = 105mm^3\)
Hence, the volume of the prism is \(105mm^3\)
Solving (3):
Given
\(Length, l = 7yd\)
\(Width, B = 7yd\)
\(Height, H = 9yd\)
Required
Determine the volume (V) of the pyramid
Volume (V) of a pyramid is calculated as thus:
\(V = \frac{1}{3} *LBH\)
\(V = \frac{1}{3} * 7yd * 7yd * 9yd\)
\(V = \frac{1}{3} * 441yd^3\)
\(V = 147yd^3\)
Hence, the volume of the pyramid is \(147yd^3\)
significent figures 56.27- 35.6
Answer:
20.67
Step-by-step explanation:
In the similaritytransformation of AABCto ADFE, AABC was dilated bya scale factor of [?], reflected5 across the [ ], and movedthrough the translation [ ].
Solution: B. 1/2
Analysis
We are transforming triangle ABC to DFE. If we see the graph, we can see the measures of each side of the triangle, decrease by half. According to that, it would be 1/2 of the original measure.