assume that a 1-l solution of silver chromate solid (ag2cro4(s)) is in equilibrium with its ions (i.e., the solution is saturated). calculate the solubility (or, the equilibrium concentration) of the chromate ion. the ksp of silver chromate is 2.76 x 10-12 .

There are only two stereoisomers of 3-chloro-2-methylbutane: (R)-3-chloro-2-methylbutane and (S)-3-chloro-2-methylbutane.

The given compound, (CH3)2CHCHClCH3, is a chiral molecule because it has a stereogenic center (the carbon atom bonded to four different groups). Therefore, it can exist in two stereoisomeric forms: the enantiomer that is the mirror image of the molecule and the original molecule itself.

To determine if there are any additional stereoisomers, we can examine whether there are any other stereogenic centers in the molecule.

However, we can see that there are no other carbon atoms with four different groups bonded to them. Therefore, there are only two stereoisomers of 3-chloro-2-methylbutane: (R)-3-chloro-2-methylbutane and (S)-3-chloro-2-methylbutane.

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a.It requires 1066 mL of 0.20 M KOH  to reach the equivalence point.

b.The equivalence point, the concentration of [Cl-], [K+], and [\(NH_{3}\)] in the solution, is 0.175 M.

What is the Equivalence point?

The chemical equivalent between the added titrant and the sample analyte is called the equivalence point in a titration.

a. We need to know how many moles of \(NH_{4}Cl\) are in the solution to calculate the volume of 0.20 M KOH needed to achieve the equivalence point.

First, we can determine how many moles  \(NH_{4}Cl\) are present in the solution:

moles \(NH_{4}Cl\) = mass / molar mass

moles \(NH_{4}Cl\) = 11.4 g / 53.49 g/mol (molar mass of \(NH_{4}Cl\))

moles \(NH_{4}Cl\) = 0.2132 mol

At the equivalence point, all the \(NH_{4}Cl\) has interacted with the KOH, resulting in an equal amount of moles of \(NH_{3}\) and \(H_{2} O\). This suggests that 0.2132 moles of KOH are also needed to react with \(NH_{4}Cl\) The volume of 0.20 M KOH required to react with 0.2132 mol can be determined using the equation for the reaction between \(NH_{4}Cl\) and KOH:

\(NH_{4}Cl\) + KOH → \(NH_{3}\) + \(H_{2}O\) + KCl

moles KOH = moles \(NH_{4}Cl\)

                   = 0.2132 mol

volume of KOH = moles KOH / concentration of KOH

                          = 0.2132 mol / 0.20 mol/L

                           = 1.066 L or 1066 mL

Therefore, 1066 mL of 0.20 M KOH is required to reach the equivalence point.

b. At the equivalence point, an equal amount of moles of KOH and \(NH_{4}Cl\) interacted to create \(NH_{3}\), \(H_{2}O\), and KCl.

We may determine the concentration of [Cl-] and [K+] in the solution following the reaction at the equivalence point by assuming volumes are additive:

moles KCl = moles \(NH_{4}Cl\)

                 = 0.2132 mol

volume of solution = 150 mL + volume of KOH added

                                = 150 mL + 1066 mL

                                = 1216 mL

                                 = 1.216 L

[Cl-] = moles KCl / volume of solution

[Cl-] = 0.2132 mol / 1.216 L

[Cl-] = 0.175 M

[K+] = moles KCl / volume of solution

[K+] = 0.2132 mol / 1.216 L

[K+] = 0.175 M

The fact that the reaction between \(NH_{4}Cl\)and KOH is a one-to-one reaction can be used to compute the concentration of [\(NH_{3}\)]. As a result, 0.2132 mol of NH3 is likewise created at the equivalence point. Using the overall volume of the solution, we can get the [\(NH_{3}\)] concentration:

[\(NH_{3}\)] = moles \(NH_{3}\)/ total volume of solution

[\(NH_{3}\)] = 0.2132 mol / 1.216 L

[\(NH_{3}\)] = 0.175 M

Therefore, at the equivalence point, the concentration of [Cl-], [K+], and [\(NH_3}\)] in the solution is 0.175 M.

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When we bring a magnet near the doorbell when it is not connected to the battery, we feel a pull, or an attractive force.

For this the hypothesis can be:

Hypothesis: If there is no permanent magnet in the doorbell, just metal like iron, then when we bring a paper clip to the doorbell, we will observe an attractive force between the paper clip and the doorbell due to the interaction between the magnet and the iron in the doorbell.

Hypothesis: If there is a permanent magnet in the doorbell, then when we bring a paper clip to the doorbell, we will observe a stronger attractive force between the paper clip and the doorbell due to the interaction between the magnet and the metal components (such as iron) in the doorbell.

Thus, these can be the Hypothesis for the given scenario.

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Answer:

5SiO2 + 2CaC2 = 5Si + 2CaO + 4CO2

Explanation:

balancing equations is a lot of trial and error. My strategy to approaching this equation was to get the O's balanced. After trying several combonations I found that I needed 10 O's on each side of the equation for the other elements to match up. After I balanced the O's, I balanced my C's to 4 on each side. Then I balanced my Ca's to have 2 on each side. And last but not least I balanced my Si to have 5 on each side.

Answer:

The correct answer is - Pine tree.

Explanation:

Coniferous trees or cone-bearing trees normally called conifers adapted their leaves and have needles like leaves that retain more water. Needles do not appear to be leaves but are modified leaves.

Conifer trees adapt this leaf modification to prevent water loss due to transpiration in the case of dry air or atmosphere. Important members of the conifer trees are pine trees, cedars, spruces, and Pines.

Answer:

2.61

Explanation:

pH+pOH=14, so sub in 11.39 for pOH, then subtract it over to get pH=2.61

if you have any questions, leave them in the comments and i will try to answer them, if this helped, pls give brainliest.

According to the forces of attraction the tungsten metal alloy that is W₂C( tungsten carbide) is most difficult to damage or change shape through force.

Forces of attraction  is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion and an atom as well.It varies for different  states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases  as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

The physical properties such as melting point, boiling point, density  are all dependent on forces of attraction which exists in the substances.

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Answer:

C: remaining at rest

Explanation:

Acceleration (a) is the change in velocity (Δv), remaining at rest is not changing the velocity.

In a hydrogen atom, the transition that will release a photon with greater energy is c) n = 5 to n = 1. This is because the energy difference between these two energy levels is larger compared to the other transitions provided. The greater the energy difference, the higher the energy of the released photon.

The energy of a photon is directly proportional to the difference in energy between the initial and final energy levels of the electron. Therefore, the transition with the greatest energy release would be the one with the greatest difference in energy levels.

a) n=1 to n=2: The energy of the photon released is (E2 - E1).
b) n=3 to n=2: The energy of the photon released is (E2 - E3).
c) n=5 to n=1: The energy of the photon released is (E1 - E5).
d) n=2 to n=8: This transition is not possible in the hydrogen atom as the maximum energy level for an electron in a hydrogen atom is n=6.
e) n=6 to n=5: The energy of the photon released is (E5 - E6).

Therefore, the transition with the greatest energy release would be option c) n=5 to n=1.

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The chemical symbols for three different atoms or atomic cations with 26 electrons are Fe, \(Co^+\), \(Ni^{2+}\)

Explanation:

So, from this, we can write chemical symbols for three different atoms or atomic cations with 26 electrons are Fe, \(Co^+\), \(Ni^{2+}\).

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Answer:

Carboxylic acid group

Explanation:

Carboxylic acid and amine groups form the basis of an amino acid.  One group reacts with the other group on a neighboring amino acid to form the peptide bond, with the release of a water molecule.

Answer:

Explanation:

Speed and velocity I think

In each pair, the solution that contains the weaker conjugate acid is more basic. Without any calculations, we can determine which solution is more basic by identifying the stronger conjugate acid in each pair.

In Part A, KClO is a stronger acid than NaF, so the solution in (b) is more basic in Part B, NaBrO is a stronger acid than NaBr, so the solution in (b) is more basic in Part C, HNO2 is a weaker acid than KOH, so the solution in (b) is more basic in Part D, NH4Cl is a weaker acid than HCN, so the solution in (a) is more basic.

It is important to note that while we did not perform any calculations, this method only works for comparing solutions with the same concentration. If the concentrations were different, we would need to perform calculations to determine which solution is more basic. A

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Answer:

Part A

pH ≈ 2.273

Part B

ΔpH ≈ -4.726

Part C

pH ≈ 1.973

Part D

ΔpH ≈ -0.301

Explanation:

Part A

The pH of a solution is given by the negative concentration of hydrogen ions in the solution

2.0 mL = 0.002 L

The number of moles of HCl in 2.0 mL of 4.0 M HCl is given as follows;

1 Liter of 4.0 M HCl contains 4.0 moles of HCl

2.0 mL = 0.002 L 4.0 M HCl contains 0.002 L/(1 L) × 4.0 M = 0.008 moles of HCl

The concentration of 0.008 moles in 1.50 L is given as follows;

Concentration = The number of moles/(The volume in liters)

∴ The concentration of 0.008 moles in 1.50 L, C = 0.008 moles/(1.5 L + 0.002 L)

∴ The concentration of 0.008 moles in 1.50 L, C ≈ 0.00533 moles/liter = 0.00533 M HCl

Given that HCl is a strong acid, we have that HCl dissociates completely to give equal number of H⁺ and Cl⁻ ions;

The number of moles of [H⁺] in the solution = 0.00533 moles

The pH of the solution = -log[H⁺]

∴ pH = -log[5.33 × 10⁻³] ≈ 2.273

The pH of the 1.5 L of pure water will be approximately 2.273

Part B

The pH of the pure water has changed from neutral (pH = 7) tp pH = 2.273

The change in pH is ΔpH = 2.274 - 7 = -4.726

ΔpH ≈ -4.726

Part C

When 2.0 mL of the 4.0 M HCl is added, the solution above, we have;

C = (0.008 + 0.008)/(1.5 + 0.002 + 0.002) ≈ 1.06383 × 10⁻²

The concentration of the solution becomes, C ≈ 1.06383 × 10⁻² mole/liter

The pH becomes, pH = -log(1.06383 × 10⁻²) ≈ 1.973

Part D

The amount by which the pH has changed, ΔpH ≈ 1.973 - 2.274 = -0.301.

Answer:

λ  = 3.0 × 10⁻¹² m

Explanation:

Speed of Light = Wavelength × frequency

c = λν

Step 1: Define

c = 3.0 × 10⁸ m/s

λ = unknown

ν = 1 × 10²⁰ Hz

Step 2: Substitute and Evaluate for λ

3.0 × 10⁸ m/s = λ · 1 × 10²⁰ Hz

λ = 3.0 × 10⁸ m/s ÷ 1 × 10²⁰ Hz

λ  = 3.0 × 10⁻¹² m

Explanation:

Answer is (3) Group 17.

The pH of the solution at equivalence is equal to 10.

A chemist titrates 25 mL of a 0.10 M hydrocyanic acid solution with 0.10 M NaOH solution at 25°C. The pKa of hydrocyanic acid is 9.2. Round your answer to two decimal places.

Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.

The pH of the hydrocyanic acid solution can be calculated using the Henderson-Hasselbalch Equation, which states that pH = pKa + log ([salt]/[acid]).

First, we need to calculate the amount of NaOH (salt) added to the solution. This can be done by multiplying the molarity (0.10 M) by the volume (25 mL) of hydrocyanic acid.

This yields 0.25 moles of NaOH. We can then plug this into the Henderson-Hasselbalch Equation, along with the pKa of hydrocyanic acid (9.2). Solving for pH yields 10.2. Since the volume of the solution increases when NaOH is added, but the molarity remains constant, the pH of the solution at equivalence is equal to 10.

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Mass is not conserved when the chemical reaction occurs inside the body.

Mass is converted into energy when reactions within the mass occur. Nuclear reactions violate the law of conservation of mass. No new atoms are created during the reaction and no existing atoms disappear or are destroyed showing that mass is conserved. Mass can not be conserved because a little amount of mass turns into energy in every chemical reaction. But mass + energy is always conserved. Energy can only be created by destroying the specific amount of mass according to the equation of energy i.e. E = mc².

So we can conclude that nuclear reactions are the cause due to which mass is not conserved.

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Answer:

B. move from the negatively charged body to the positively charged body.

Explanation:

Because they only partially ionize in solution, carboxylic acids are weak acids. When compared to a solution of a strong acid at the same concentration, their solutions contain fewer hydrogen ions. At the same concentration, the pH of a weak acid will be higher than that of a strong acid. This statement is true.

A carboxylic acid is an organic acid with a carboxyl group attached to an R-group in organic chemistry. A carboxylic acid has the general formula RCOOH or RCO2H, where R refers to the alkyl, alkenyl, aryl, or other group. Carboxylic acids are found in abundance.

Carboxylic acids do this much more readily than most other classes of organic compounds, so they are referred to as stronger acids, despite being far weaker than the most important mineral acids—sulfuric (H2SO4), nitric (HNO3), and hydrochloric (HCL) (HCl).

Because of the following factors, carboxylic acid is weaker than HCl: Carboxylic acid ions do not completely dissociate in water. Carboxylic acid, as an organic acid, does not behave like other acids because it is not ionic.

Thus, carboxylic acids are weak acids.

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The replacement of a hydrogen atom in CH\(_{4}\) by a chlorine atom causes an increase in boiling point because chlorine is more electronegative than hydrogen, resulting in a stronger dipole-dipole attraction between molecules.

When a hydrogen atom in CH\(_{4}\) is replaced by a chlorine atom, the resulting molecule becomes CH\(_{3}\)Cl. Chlorine is more electronegative than hydrogen, meaning it has a higher affinity for electrons. This causes the chlorine atom to pull the shared electrons closer to itself, creating a partial negative charge. The hydrogen atom in CH\(_{4}\), on the other hand, is less electronegative, resulting in a partial positive charge.

The difference in electronegativity between chlorine and hydrogen leads to a stronger dipole-dipole attraction between CH\(_{3}\)Cl molecules compared to CH\(_{4}\) molecules. This increased intermolecular force requires more energy to break the attractive forces and convert the substance from a liquid to a gas, resulting in a higher boiling point.

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The ionic substance strontium oxide, SrO, forms from the reaction of strontium metal with molecular oxygen.

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Alkynes can undergo oxidative cleavage with ozone followed by hydrolysis to form carboxylic acids. To determine which alkyne will give only one carboxylic acid with the molecular formula C4H8O2, we need to consider the possibilities.

The molecular formula C4H8O2 suggests the presence of four carbon atoms, eight hydrogen atoms, and two oxygen atoms. Let's consider the possible alkyne options and check if they meet this requirement:

1. Ethyne (acetylene): C2H2

  When acetylene reacts with ozone and water, it forms two molecules of carbon dioxide (CO2) and two molecules of water (H2O). Therefore, it does not yield a carboxylic acid with the given molecular formula.

2. Propyne: C3H4

  Propyne, when reacted with ozone and water, gives two molecules of acetic acid (CH3COOH) and one molecule of formaldehyde (CH2O). Thus, it does not yield a carboxylic acid with the given molecular formula.

3. 1-Butyne: C4H6

  1-Butyne, upon reaction with ozone and water, can yield one molecule of butanoic acid (C3H7COOH) and one molecule of formaldehyde (CH2O). This corresponds to the molecular formula C4H8O2 and satisfies the given criteria.

Based on the options provided, the alkyne that will react with ozone, followed by water, to give only one carboxylic acid with the molecular formula C4H8O2 is 1-Butyne.

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Answer:

top one is anaphase and the middle one is cytokinesis can't see enough of the bottom one to tell

Explanation:

Answer:

Explanation:

Zn+H

2

​

SO

4

​

→ZnSO

4

​

+H

2

​

Answer:

The correct option is;

b. The particles are positively and negatively charged, have high compressibility, and spread out to fill a container

Explanation:

Plasma are gases that contain positively and negatively charged particles. Therefore, plasma flow drift in space such that plasma. like gases has no characteristic shape or volume but takes the shape and fills the entire volume of a container in which it is placed

Other characteristics of plasma are that plasma is a conductor of electricity and magnetic fields can therefore exist in plasma due to the fact that plasma are made of atoms in which part or all of the electrons have been removed leaving the ions to roam freely in a container.

The standard Gibbs free energy of the reaction is -88kJ/mol.

The relation between ∆G° and the equilibrium constant (K) is given by the equation:

∆G° = -RT ln(K)

where R is the gas constant, T is the temperature in Kelvin, ln is the natural logarithm, and K is the equilibrium constant.

The given values are as follows:

K=8.2×10¹⁰

T=150°C

T=273+150 = 423K

R = 8.314J/K.mol

Using the equation above and substituting the given values, we get:

∆G° = - (8.314 J/K.mol) x 423 K x ln(8.2×10¹⁰) = -88377.68 J/mol

Converting this to kilojoules per mole, we get:

∆G° = 88377.68 J/mol×0.001

= -88.32 kJ/mol

Rounding to two significant digits, the value of ∆G° is approximately -88kJ/mol.

Therefore, the value of ∆G° for the given reaction is approximately -88kJ/mol.

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Answer: The volume of 9.7 tons of given ethylene glycol is 0.0079 \(m^{3}\).

Explanation:

Given: Density = 1.11 \(g/cm^{3}\)

Mass = 9.7 tons

Convert tons into lb as follows.

\(1 ton = 2 \times 10^{3} lb\\9.7 ton = 9.7 ton \times 2 \times 10^{3} \frac{lb}{1 ton}\\= 19.4 \times 10^{3} lb\)

Now, lb is converted into kg as follows.

\(1 kg = 2.2046 lb\\1 lb = 0.453592 kg\\19.4 \times 10^{3} lb = 19.4 \times 10^{3} lb \times 0.453592 \frac{kg}{1 lb}\\= 8.79 kg\)

1 kg = 1000 g

So, 8.79 kg = 8790 g

Density is the mass of a substance divided by its volume. Hence, volume of ethylene glycol is calculated as follows.

\(Density = \frac{mass}{volume}\\1.11 g/cm^{3} = \frac{8790 g}{volume}\\volume = 7918.92 cm^{3} (1 cm^{3} = 10^{-6} m^{3})\\= 0.0079 m^{3}\)

Thus, we can conclude that the volume of 9.7 tons of given ethylene glycol is 0.0079 \(m^{3}\).