At 40.°C, the concentration of hydronium (H3O+) ions in an aqueous solution is 2.9 ✕ 10−5 M. (Note: At 40.°C, the ion-product constant for water is 2.87 ✕ 10−14.) (a) What is the concentration of hydroxide (OH −) ions in this solution?

Answer:

118750 ml

Explanation:

The chemical equation for complete combustion of hexane is given as;

2C6H14 + 19O2 → 12CO2 + 14H2O  

From the equation of the reaction;

2 mol of C6H14 reacts with 19 mol of O2

2 ml of C6H14 reacts with 19 ml of O2

2500 mL of C6H14 would react with x ml of O2

2 = 19

2500 = x

x = 2500 * 19 / 2 = 23750 ml

Since oxygen is 20% of air;

23750 = 20 / 100 * (Volume of air)

Volume of air = 23750 * 100 / 20 = 118750 ml

Therefore, Student C had the purest crystals and the correct product

Melting point determination is a useful technique for checking the purity and identity of the crystalline solid. The melting point of a compound is the temperature range where the solid changes to a liquid. The literature value for the melting point of a product is an important property to know, and it can be compared to the values obtained experimentally.

The melting point of the compound is an important factor in determining its purity. A pure compound has a sharp melting point, whereas an impure compound has a broad melting range that is lower than the pure melting point.

The student with the purest crystals and the correct product was Student C.

Student A's melting point range is too low, which indicates that the compound is impure.

The melting point range of Student B is too high, which indicates that the compound is impure.

The melting point range of Student D is close to the literature value, but it is still too broad, which indicates that the compound is impure.

Student C's melting point range is close to the literature value, and it is relatively sharp, which indicates that the compound is pure.

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Answer:

C) creating a relationship between mass and volume

g/L

g or gram is mass

L or Litres is for volume

3C⁻⁻ on reaction with HI gives I⁻⁻⁻ as the main products and not H⁻ and C₂H₅I.

When 3C⁻⁻ is reacted with HI, the reaction product obtained is I⁻⁻⁻ as the main product. The C₂H₅I and H⁻ are not produced in significant quantities and cannot be considered the main product.The 3C⁻⁻ compound reacts with HI in the presence of a solvent to produce hydrogen gas, H⁻, C₂H₅I, and I⁻⁻⁻. The primary product obtained is I⁻⁻⁻ because it is stable and has a higher energy than C₂H₅I and H⁻.However, the reaction can be controlled to obtain C₂H₅I and H⁻ as the primary products by changing the reaction conditions. The reaction must be carried out in anhydrous conditions and at a low temperature so that the reaction proceeds in the desired direction.

3C⁻⁻ on reaction with HI gives I⁻⁻⁻ as the main products and not H⁻ and C₂H₅I. However, the reaction can be controlled to obtain C₂H₅I and H⁻ as the primary products by changing the reaction conditions.

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The pressure that is develops in the container when the water is reaches this higher temperature is 2.03 × 10³ psi.

According to the law of mass of conservation , wet :

Density (40 °C) × V = Density ( 100 °C ) × (V + ΔV)

ΔV/ V = ( Density (40 °C) / Density ( 100 °C ) ) - 1

ΔV/ V  = 1.940 / 1.927

ΔV/ V = 0.00675

The change in volume and bulk modulus relation given as :

K = - ΔP / ( ΔV/ V)

ΔP = - 300000 × - 0.00675

ΔP =  2.03 × 10³ psi

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Answer:

a proton turns into an atom that goes kabloey into fission products and other neutrons.

Explanation:

Hello.

Magnesium nitrate is a chemical compound with the formula Mg (NO₃) ₂. Magnesium nitrate is an inorganic salt very soluble in water and alcohol and has the appearance of fine white crystals.

Magnesium Nitrate is commonly used as a fertilizer due to its high nutritional value, since it provides Magnesium and Nitrogen, these are important nutrients in the growth of crops. It is a water soluble fertilizer. Contains 10.5% N - 15.6% MgO. Provides nitrogen in the form of nitrate.

The only reagent that could potentially oxidize Zn to Zn²⁺ without oxidizing Sn to Sn²⁺ is Br₂ (bromine).

To determine which reagent would oxidize Zn to Zn²⁺ but not Sn to Sn²⁺, we need to compare the reduction potentials (E°) of the elements involved. The reagent with a higher reduction potential will have a greater tendency to accept electrons and oxidize the other element.

The reduction potential for Zn²⁺/Zn (Zn²⁺ + 2e⁻ ⇌ Zn) is approximately -0.76 V, while the reduction potential for Sn²⁺/Sn (Sn²⁺ + 2e⁻ ⇌ Sn) is approximately -0.14 V. Since the reduction potential for Zn²⁺/Zn is lower than that of Sn²⁺/Sn, Zn is less easily oxidized compared to Sn.

Now, let's examine the given reagents:

Br₂: Bromine (Br₂) has a higher reduction potential than Zn²⁺/Zn. It could potentially oxidize Zn to Zn²⁺. However, it can also oxidize Sn to Sn²⁺ because its reduction potential is higher than both Zn²⁺/Zn and Sn²⁺/Sn.

Br-: Bromide ion (Br-) has a lower reduction potential than both Zn²⁺/Zn and Sn²⁺/Sn. It would not oxidize either Zn or Sn.

Ca²⁺+: Calcium ion (Ca²⁺) has a lower reduction potential than both Zn²⁺/Zn and Sn2+/Sn. It would not oxidize either Zn or Sn.

Co²⁺: Cobalt(II) ion (Co²⁺) has a lower reduction potential than both Zn²⁺/Zn and Sn²⁺/Sn. It would not oxidize either Zn or Sn.

CaCo: This combination does not represent a known reagent or species and cannot be evaluated in terms of its oxidation potential.

Based on the given options, the only reagent that could potentially oxidize Zn to Zn²⁺ without oxidizing Sn to Sn²⁺ is Br₂ (bromine). However, it's important to note that in practical scenarios, multiple factors can influence redox reactions, so careful experimental considerations may be required to determine the actual outcome.

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Answer:

Liquid water  

Explanation:

Jesus Christ had dreads so shake em', I ain't got none but I'm planning on growing some

Answer:

ooo_SoSpooky add me :>

Answer:oxygen Explanation:The medical condition described here is anaemia. It is a blood cell disorder whereby the red blood cell doesn't function properly and hence doesn't carry enough oxygen to the tissues. This is usually caused when ones body is deficient of iron.The symptoms that may occur to such patients are weakness, fatigue, headache and pale skin.Based on the explanation, the answer is oxygen

Explanation:

The mass of the hexane sample is 0.580 g. The mass of the bomb calorimeter is 1.900 kg, and its specific heat is 3.21 J/g·K. The change in temperature is 4.542 K. So, heat produced during the combustion of hexane is 11195.1576 J.


To calculate the amount of heat produced during the combustion of hexane, we can use the formula q = m × C × ΔT.

First, we need to determine the mass of the hexane sample, which is given as 0.580 g.

Next, we need to find the mass of the bomb calorimeter, which is given as 1.900 kg.

Note that we need to convert the mass to grams by multiplying it by 1000, so the mass is 1900 g.

The specific heat of the bomb calorimeter is given as 3.21 J/g·K.

Finally, we have the change in temperature, which is given as 4.542 K.

Now, we can substitute these values into the formula: q = (0.580 g + 1900 g) × 3.21 J/g·K × 4.542 K.

Simplifying the equation, we get:
q = 2467.8 J/g·K × 4.542 K

Calculating the product:
q = 11195.1576 J

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Due to Incomplete combustion, a candle produces a yellow flame and due to complete combustion, an LPG burner produces a blue flame.

A candle is made of wax, which does not burn completely. As a result, candles have partial combustion, which gives them their yellow color. On the other hand, LPG (Liquified Petroleum Gas), burns at approx. around 1,960°C temperature. Hence, LPG burners have complete combustion, giving them their blue color.

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Answer: womans  chest area

Explanation:

Approximately 18.4832 mL of 0.250 M NaOH is required to neutralize 30.4 mL of 0.152 M HCl.

To determine the volume of 0.250 M NaOH required to neutralize 30.4 mL of 0.152 M HCl, we can use the concept of stoichiometry and the balanced chemical equation for the neutralization reaction between NaOH and HCl:

NaOH + HCl -> NaCl + H2O

From the balanced equation, we can see that the stoichiometric ratio between NaOH and HCl is 1:1. This means that for every mole of NaOH, we require an equal number of moles of HCl to neutralize.

First, let's calculate the number of moles of HCl present in the given volume:

Moles of HCl = concentration of HCl * volume of HCl

= 0.152 M * 30.4 mL

= 4.6208 mmol (millimoles)

Since the stoichiometric ratio is 1:1, the number of moles of NaOH required to neutralize the HCl is also 4.6208 mmol.

Now, let's calculate the volume of 0.250 M NaOH needed to contain 4.6208 mmol:

Volume of NaOH = (moles of NaOH) / (concentration of NaOH)

= 4.6208 mmol / 0.250 M

= 18.4832 mL

Therefore, approximately 18.4832 mL of 0.250 M NaOH is required to neutralize 30.4 mL of 0.152 M HCl.

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The pH of a 0.25 M solution of NaNO2= 6.65.

Given the concentration of NaNO2, we can find the concentration of NaOH and HNO2 as follows:

NaNO2 = 0.25 MNaOH = HNO2 = x

(since they have equal concentrations due to the stoichiometry of the reaction)

Thus, we can write the equilibrium constant expression as:

Ka = x^2/0.25

Now, let's solve for x:

x^2 = 0.25 x 4.5 x 10^-4x = √(0.25 x 4.5 x 10^-4) = 0.015

This value represents the concentration of both HNO2 and NaOH. Since we are interested in pH, we need to find the concentration of H+ ions using the following equation:

Kw = [H+][OH-]

Since we have found the concentration of OH- (which is the same as the concentration of NaOH),

we can solve for H+:

Kw = 1.0 x 10^-14[H+][0.015] = 1.0 x 10^-14[H+] = 6.7 x 10^-13

Finally, we can find pH:

pH = -log[H+]pH = -log(6.7 x 10^-13)pH = 6.65

Therefore, the correct option is d) pH = 6.65.

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Answer:

cutting, bending, dissolving, freezing, and boiling

Explanation:

A physical change is a change in one or more physical properties of matter without any change in chemical properties. In other words, matter doesn't change into a different substance in a physical change. Examples of physical change include but are not limited to, from solid to liquid or from liquid to gas are also physical changes.

Answer:

because it was in the mixture

Explanation:

Answer:

Good environmental and weather conditions.

Explanation:

The main influence for a horse that will become a racehorse or farm horse are  good environmental and weather conditions. It also needs good food and proper training to made a racehorse. High quality race of a horse always prefer for making a racehorse because it has higher agility, speed, and spirit as compared to horse belongs to ordinary race.

Answer:

organ cloning for use in transplants.

Explanation:

Metallic bonding is different than ionic or covalent bond as that Metallic bond form when atoms share number of electrons in a metal lattice. The properties of metals that result from this type of bonding are: Malleability, Ductility, High melting point and boiling point. The nature of the bonding leads to the properties of metallic substances is that metallic bonds involves electrostatic forces of attraction.

Ionic bonds is a chemical bond formed when one atom transfer its valence electron to another atom. Ionic bond is also called electrovalent bond. These bonds are stronger.

A chemical bond in which pairs of electrons are shared between the two atoms is known as Covalent Bond. Covalent bond is also called molecular bond.

Metallic bonding is different than ionic or covalent bond as that Metallic bond form when atoms share number of electrons in a metal lattice while Covalent bond form when pairs of electrons are shared between the two atoms and Ionic bond form when one atom transfer its valence electron to another atom.

The properties of metals that result from this type of bonding are:

The nature of the bonding leads to the properties of metallic substances is that metallic bonds involves electrostatic forces of attraction. The delocalized electrons are highly mobile due to the metallic bonds.

Thus from the above conclusion we can say that Metallic bonding is different than ionic or covalent bond as that Metallic bond form when atoms share number of electrons in a metal lattice. The properties of metals that result from this type of bonding are: Malleability, Ductility, High melting point and boiling point. The nature of the bonding leads to the properties of metallic substances is that metallic bonds involves electrostatic forces of attraction.

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Answer:

1.Phenolphthalein

2.Method

a.Use the pipette and pipette filler to add 25 cm 3 of alkali to a clean conical flask.

b.Add a few drops of indicator and put the conical flask on a white tile.

c.Fill the burette with acid and note the starting volume.

d.Slowly add the acid from the burette to the alkali in the conical flask, swirling to mix.

Explanation:

The missing products of the neutralization reactions are;

1) KBr

2) NH3

3) HNO3

A neutralization reaction is a reaction that occurs between an acid and a base to yield salt and water only.

The missing products of the neutralization reactions are;

1) KBr

2) NH3

3) HNO3

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Answer:

KBr

2 NH4OH

2 HNO3

Explanation:

Answer:

Liquid

Explanation:

Because water becomes a solid (freezes) at 0°C and becomes a gas (evaporates) at 100°C, it is liquid at any temperature in between.

O2 is the correct answer.

Explanation:

On a magnetic susceptibility balance, the O2 species will have the strongest mass shift since stronger paramagnetic species will have a larger mass shift.

The oxygen atoms in the O2 species are paramagnetic because unpaired electrons rotate in the same direction, increasing the magnetic field force. As a result, the oxygen atoms with two unpaired electrons will exhibit the largest mass shift on a magnetic susceptibility balance.

The magnitude of the mass shift is -O2, which increases with species paramagneticity. The mass shift increases with species paramagneticity. Therefore, on a magnetic susceptibility balance, oxygen will have the highest mass shift since it has two unpaired electrons in the molecular orbital diagram.

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Answer:

1280J are required.

Explanation:

Heat of fusion is defined as the amount of heat required to change its state from liquid to solid at its melting point at constant pressure.

As heat of fusion of gold is 64J/g, there are required 64J to melt 1g of gold at its melting point. The energy required to melt 20g is:

20g * (64J/g) =

1280J are required

The percentage of yield is 2.2%. and the weight of Br2 is 228 grams if 203 grams of CL2 react with excess KBr to actually produce 415 grams of Br2.

Weight of CL2 =  203 grams

Weight of  Br2 =  415 grams

To calculate the yield percentage, we need to compare the actual yield to the theoretical yield.

We need to balance the chemical equation for the reaction between chlorine gas and potassium bromide.

Cl2 + 2 KBr = 2 KCl + Br2

We can notice that 1 mole of Cl2 reacts with 2 moles of KBr to produce 1 mole of Br2.

moles of Cl2 = 203 g / 70.90 g/mol

moles of Cl2 = 2.863 mol

moles of Br2 = (1 mol Br2 / 2 mol Cl2) × 2.863 mol Cl2

moles of Br2 = 1.432 mol

mass of Br2 = 1.432 mol × 159.81 g/mol

mass of Br2  = 228.9 g

Percentage of yield  = 2.2%

Therefore, we can conclude that the weight of Br2 is 228 grams and the percentage of yield is 2.2%.

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Answer:

I didn't get you

Explanation:

Please explain