At a football game, 6 adult pay AED 20 each and 4 children pay AED 10 each. What i the
total cot of the ticket?

To find the probability that the mean weight of 19 fish is between 16.1 and 20.6 lb, you would need to know the distribution of the weights of the individual fish. If the weights of the fish are normally distributed with a mean of 18.4 lb and a standard deviation of 2.5 lb, then you can use a normal distribution to find the probability that the mean weight of the 19 fish falls in the specified range.

How does probability work exactly?

Probability is calculated by dividing the total possible outcomes by the number of outcomes that are theoretically possible. Probability differs from odds in this regard. Calculating odds involves dividing the likelihood of a particular event by the likelihood that it won't occur.

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The solution of the given initial value problem, x'' + 33.64x = 4cos(6t), with x(0) = x'(0) = 0, can be expressed as a sum of the homogeneous solution and the particular solution.

To find the solution, we start by solving the homogeneous equation, x'' + 33.64x = 0. The characteristic equation associated with this homogeneous equation is \(r^2 + 33.64 = 0\), which yields the roots

r = ±i√33.64. Thus, the homogeneous solution can be expressed as

x_h(t) = A*cos(√33.64*t) + B*sin(√33.64*t),

where A and B are constants determined by the initial conditions.

Next, we need to find the particular solution for the forced oscillation. Since the right-hand side of the equation is of the form Acos(ωt), where ω = 6, we assume a particular solution of the form x_p(t) = C*cos(ω*t + φ), where C and φ are constants to be determined. Taking the derivatives, we have x_p''(t) = -ω^2*C*cos(ω*t + φ) and x_p'(t) = -ω*C*sin(ω*t + φ). Substituting these into the original equation, we obtain -ω^2*C*cos(ω*t + φ) + 33.64*C*cos(ω*t + φ) = 4*cos(ω*t).

To satisfy this equation, the coefficient of the cosine term must be 4, while the coefficient of the sine term must be zero. This gives us two equations: -ω^2*C + 33.64*C = 4 and -ω*C = 0. Solving these equations, we find C = 4/(33.64 - ω^2) and φ = 0. Therefore, the particular solution is x_p(t) = (4/(33.64 - ω^2))*cos(ω*t).

Finally, we combine the homogeneous solution and the particular solution to obtain the complete solution:

x(t) = x_h(t) + x_p(t) = A*cos(√33.64*t) + B*sin(√33.64*t) + (4/(33.64 - ω^2))*cos(ω*t).

By substituting the initial conditions x(0) = x'(0) = 0 into this equation, we can determine the values of A and B. With the obtained values, the final solution for the initial value problem can be expressed in terms of the given constants and the trigonometric functions involved.

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The probability that a sampled woman has two children is 0.2436, rounded to four decimal places.

This can be calculated using the following formula:

P(2 children) = (number of women with 2 children) / (total number of women)

The number of women with 2 children is 11,274. The total number of women is 46,239.

Substituting these values into the formula:

P(2 children) = (11,274) / (46,239) = 0.2436

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Answer:

129.9

Step-by-step explanation:

Deltamath

Answer:

y=-5

Step-by-step explanation:

line equation is y=mx+b

y is the y value

m is the slope

x is the x value

b is the y intercept (when x is 0)

find slope rise over run (y increase divided by x increase)

-5-(-5)/-6-3

=0/-9

=0

y=(0)x+b

y=b

find y intercept (b)

you can see in the previous equation x already became 0 not on purpose

this means that that is the y intercept

y intercept is -5

y=0(x)-5

y=-5

Answer: 6.24

Step-by-step explanation:

To round 6.235 to the nearest hundredth means to round the numbers so you only have two digits in the fractional part (numbers after the decimal)

The last digit in the fractional part of 6.235 is 5 or more and less than 9, so add 1 to the second digit of the fractional part and remove the third digit.

Therefore, the answer is 6.24

58

a right triangle is 90 degrees so you subtract 32 from 90 to find the remainder

Answer:

The third angle is 58 degrees

Step-by-step explanation:

In a triangle all three angles add up to 180 degrees. If you know two sides, add them up then subtract the sum from 180. This will leave you with the last angle measurement.

In a right triangle we always know there is one angle that has a measure of 90 degrees. So now we know two angles 90 and 32.

90 + 32 = 122

180 - 122 = 58

The value of f[g(x)] is - 64x³ - 336x² - 588x - 340 and the value of g[f(x)] is -4x³ + 19

The functions are as follows; f(x) = -x³ +3 and g(x) = 4x+7

The value of f[g(x)] is obtained by replacing every x in f(x) with the value of g(x) as given below

f[g(x)] = f(4x + 7) = - (4x + 7)³ + 3

When we expand (4x + 7)³, it gives us 64x³ + 336x² + 588x + 343

Then

f[g(x)] = - 64x³ - 336x² - 588x - 340

Similarly, g[f(x)] is obtained by replacing every x in g(x) with the value of f(x) as shown below;

g[f(x)] = g(-x³ + 3) = 4(-x³ + 3) + 7g

[f(x)] = -4x³ + 19

Therefore,

f[g(x)] = - 64x³ - 336x² - 588x - 340

g[f(x)] = -4x³ + 19

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The dimensions that will result in a solid with maximum volume are approximately x = 12.02 centimeters and h = 5.01 centimeters.

Let the side of the square base be x, and let the height of the rectangular solid be h. Then, the surface area of the solid is given by:

Surface area = area of base + area of front + area of back + area of left + area of right

Surface area = x² + 2xh + 2xh + 2xh + 2xh = x² + 8xh

We are given that the surface area is 433.5 square centimeters, so we can write: x² + 8xh = 433.5

We want to find the dimensions that will result in a solid with maximum volume. The volume of the solid is given by:

Volume = area of base × height = x² × h

We can use the surface area equation to solve for h in terms of x:

x² + 8xh = 433.5

h = (433.5 - x²)/(8x)

Substituting this expression for h into the volume equation, we get:

Volume = x² × (433.5 - x²)/(8x) = (433.5x - x³)/8

To find the maximum volume, we need to find the value of x that maximizes this expression. To do this, we can take the derivative of the expression with respect to x, set it equal to zero, and solve for x:

d(Volume)/dx = (433.5 - 3x²)/8 = 0

433.5 - 3x² = 0

x² = 144.5

x = sqrt(144.5) ≈ 12.02

We can check that this is a maximum by computing the second derivative of the volume expression with respect to x:

d²(Volume)/dx² = -3x/4

At x = sqrt(144.5), this is negative, which means that the volume is maximized at x = sqrt(144.5).

Substituting x = sqrt(144.5) into the expression for h, we get:

h = (433.5 - (sqrt(144.5))²)/(8×sqrt(144.5))

h = 433.5/(8×sqrt(144.5)) - sqrt(144.5)/8

h = 5.01

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The dimensions of the rectangular solid that will result in a maximum volume are approximately.\(6.34 cm \times 9.03 cm \times 9.03 cm.\)

Let's assume that the length, width, and height of the rectangular solid are all equal to x, so the base of the solid is a square.

The surface area of the rectangular solid can be expressed as:

\(SA = 2xy + 2xz + 2yz\)

Substituting x for y and z, we get:

\(SA = 2x^2 + 4xy\)

We are given that the surface area is 433.5 square centimeters, so:

\(2x^2 + 4xy = 433.5\)

Simplifying, we get:

\(x^2 + 2xy - 216.75 = 0\)

Using the quadratic formula to solve for y, we get:

\(y = (-2x\± \sqrt (4x^2 + 4(216.75)))/2\)

\(y = -x \± \sqrt (x^2 + 216.75)\)

Since the base of the rectangular solid is a square, we know that y = z. So:

\(z = -x \± \sqrt(x^2 + 216.75)\)

The volume of the rectangular solid is given by:

\(V = x^2y\)

Substituting y for\(-x + \sqrt (x^2 + 216.75),\) we get:

\(V = x^2(-x + \sqrt(x^2 + 216.75))\)

Expanding and simplifying, we get:

\(V = -x^3 + x^2\sqrt(x^2 + 216.75)\)

The dimensions that will result in a solid with maximum volume, we need to find the value of x that maximizes the volume V.

We can do this by taking the derivative of V with respect to x, setting it equal to zero, and solving for x:

\(dV/dx = -3x^2 + 2x\sqrt(x^2 + 216.75) + x^2/(2\sqrt (x^2 + 216.75)) = 0\)

Multiplying both sides by \(2\sqrt (x^2 + 216.75)\) to eliminate the denominator, we get:

\(-6x^2\sqrt (x^2 + 216.75) + 4x(x^2 + 216.75) + x^3 = 0\)

Simplifying, we get:

\(x^3 - 6x^2\sqrt (x^2 + 216.75) + 4x(x^2 + 216.75) = 0\)

We can solve this equation numerically using a graphing calculator or computer software.

\(The solution is approximately x = 6.34 centimeters.\)

Substituting x = 6.34 into the expression for y and z, we get:

\(y = z \approx 9.03 centimeters\)

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The coefficient of \((x - 1)^k\) in the Taylor series for f(x) centered at 1 is (-1/2) for k > 1 and \(f^{(k)}(1) = -k!/(2^k)\) for k > 1

What is coefficient?

In mathematics, a coefficient is a numerical or constant factor that is applied to a variable or term. Coefficients are used in various mathematical contexts, including algebra, calculus, and statistics.

Since the first derivative of f(x) is \(f'(x) = -1/(x^2 * \sqrt{(x^2 - 1)})\), we have f'(1) = -1/0, which is undefined. Hence, we cannot use the Taylor series formula for f(x) centered at 1 directly.

However, we are given that \(f^{(k)}(1) = -k!/(2^k)\) for k > 1. Using this information, we can write the Taylor series formula for f(x) centered at 1 as:

\(f(x) = f(1) + f'(1)(x - 1) + (1/2!)f''(1)(x - 1)^2\)\(+$\sum_{k=2}^{\infty} \frac{1}{k!}f^{(k)}(1)(x-1)^k$\)

Substituting f(1) = 1/2 and f'(1) = -1/2, we get:

\($f(x) = \frac{1}{2} - \frac{1}{2}(x-1) + \frac{1}{2!} \left(-\frac{2}{2^2}\right) (x-1)^2 + \sum_{k=2}^{\infty} \frac{1}{k!} \left(-\frac{k!}{2^k}\right) (x-1)^k$\)

Simplifying the expression, we get:

\($f(x) = \frac{1}{2} - \frac{1}{2}(x-1) - \frac{1}{4}(x-1)^2 + \sum_{k=2}^{\infty} \left(-\frac{1}{2}\right)(x-1)^k$\)

Hence, the coefficient of \((x - 1)^k\) in the Taylor series for f(x) centered at 1 is (-1/2) for k > 1.

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The total number of students who did not have a dog or a cat was 5

Jennifer conducted a survey about the pets of students in her class. In total, 27 students participated in the survey. Among these, 14 students had cats, 12 students had dogs, and 4 students had both cats and dogs.

Jennifer took a survey among the students in her class to know about their pets. The total number of students who took part in the survey was 27. She found that 14 students had cats, 12 students had dogs, and 4 students had both cats and dogs.

Now, we need to calculate the number of students who don't have a dog or a cat. Let's start by calculating the total number of students who had either a dog or a cat.There were 14 students with cats and 12 students with dogs, which means that 26 students had either a cat or a dog.

However, since 4 students had both a cat and a dog, we must subtract this from our total. Therefore, there were 22 students with either a cat or a dog.Now, we need to subtract this from the total number of students who took the survey. That is,27 - 22 = 5 students Therefore, there were 5 students who did not have a dog or a cat.

The total number of students who did not have a dog or a cat was 5.

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When frequency distributions are constructed from the same data set, the distribution with the widest class will have the smallest classes.

This refers to a mathematical or statistical set of numbers or data which have been arranged to show the frequency of occurrence of each number that can be repeatedly observed.

The different types of Frequency Distribution are:

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To determine the percent of incorrect answers:

Out of 120 trigonometry test question, 54 was answered correctly:

Let the number of question with incorrect answer be 120 - 54 = 66

Hence she answered 55 % incorrectly

Answer: It is obtuse

Step-by-step explanation: the angle looks greater than 90 degrees :)

Answer:

cant see picture its blocked off

Step-by-step explanation:

Answer:

i think 4/3 is the answer

The total cost of producing the first 81 units, we need to integrate the marginal cost function over the range of 0 to 81:

Total cost = ∫(0 to 81) 9√x dx

We can integrate this using the power rule of integration:

Total cost = [ 6/5 * 9x^(3/2) ] from x=0 to x=81

Evaluating this expression with the upper and lower limits, we get:

Total cost = 6/5 * 9 * (81)^(3/2) - 6/5 * 9 * (0)^(3/2)

Total cost = 6/5 * 9 * 81^(3/2)

Total cost ≈ $3,442.27

The total cost of producing the first 81 units is approximately $3,442.27.

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The total cost of the first 81 units is 486. This can be answered by the concept of integration.

To find the total cost of the first 81 units, we need to integrate the marginal cost function from x=0 to x=81:

∫(0 to 81) 9√x dx

Using the power rule of integration, we can simplify this as:

= 9 × [2/3 × x^(3/2)] from 0 to 81

= 9 × [2/3 × 81^(3/2) - 2/3 × 0^(3/2)]

= 9 × [2/3 × 81^(3/2)]

= 9 × [2/3 × 81 × √81]

= 9 × [2/3 × 81 × 9]

= 9 × 54

= 486

Therefore, the total cost of the first 81 units is 486.

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Since the rectangle's shorter side is half as long as its longer side, its top left vertex is (0,a).

A pair of numbers that use the horizontal and vertical separations from the two reference axes to define a point's location on a coordinate plane. typically expressed by the x-value and y-value pair (x,y). You do the reverse to determine a point's coordinates in a coordinate system. Start at the point, then move up or down a vertical line until you reach the x-axis. Your x-coordinate is shown there. To find the y-coordinate, repeat the previous step while adhering to a horizontal line.

Here,

Let x be the length and y be the width,

y=x/2

x=2a

y=a

The top left vertex=(0,a)

The top left vertex is (0,a) as shorter side of the rectangle is half the length of the longer side.

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The answer to the following algebra is;

b² at b = 4 is 16

y /5 at y = 15 is 3

27/s at s = 9 is 3

q/3 + 4 at q = 3 is 5

Algebra is the system for computation using letters or other symbols to represent numbers, with rules for manipulating these symbols.

Given the following:

b² at b = 4

substitute b = 4

= 4²

= 4 × 4

= 16

y /5 at y = 15

substitute y = 15

= 15/5

= 3

27/s at s = 9

substitute s = 9

= 27/9

= 3

q/3 + 4 at q = 3

substitute q = 3

= 3/3 + 4

= 1 + 4

= 5

In conclusion, the algebraic expression is solved by substituting the value of the variables.

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Answer:

Estimation: 93

Step-by-step explanation:

Actual answer: 93.0416666667

Answer:

A. 25°

- 15°

B. 5.3

-8. 2

Answer:

where's the picture?

Step-by-step explanation:

For sector 1, the bid-rent curve is defined by the equation LC(x1) + L(x1) + F(x1) = P(x1), where LC(x1) represents the land cost, L(x1) represents the labor cost, and F(x1) represents the freight cost for sector 1. Similarly, for sector 2, the bid-rent curve is given by LC(x2) + L(x2) + F(x2) = P(x2).

To derive the bid-rent curve for sector 1, we substitute the given labor cost equation L(x1) = 20 - A1*x1 and freight cost equation F(x1) = (B1 + 3)x1 into the bid-rent curve equation LC(x1) + L(x1) + F(x1) = P(x1). Since LC(x1) is assumed to be equal to P(x1) (as stated in the problem), the equation becomes P(x1) + 20 - A1x1 + (B1 + 3)x1 = P(x1). Simplifying this equation, we have 20 - A1x1 + (B1 + 3)x1 = 0. Rearranging terms, we get x1(B1 + 3 - A1) = -20. Dividing both sides by (B1 + 3 - A1), we obtain x1 = -20 / (B1 + 3 - A1). This is the bid-rent curve equation for sector 1.

Similarly, for sector 2, we substitute the given labor cost equation L(x2) = 30 - A2*x2 and freight cost equation F(x2) = (B2 + 3)x2 into the bid-rent curve equation LC(x2) + L(x2) + F(x2) = P(x2). Since LC(x2) is assumed to be equal to P(x2), the equation becomes P(x2) + 30 - A2x2 + (B2 + 3)x2 = P(x2). Simplifying this equation, we have 30 - A2x2 + (B2 + 3)x2 = 0. Rearranging terms, we get x2(B2 + 3 - A2) = -30. Dividing both sides by (B2 + 3 - A2), we obtain x2 = -30 / (B2 + 3 - A2). This is the bid-rent curve equation for sector 2.

Therefore, the bid-rent curves for manufacturing firms in each sector are x1 = -20 / (B1 + 3 - A1) for sector 1 and x2 = -30 / (B2 + 3 - A2) for sector 2.

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Answer:

t= 20+40c

Step-by-step explanation:

Given that Ray's total cost is always $30 less than Earl's and they charge the same amount per carpet cleaned, the difference is in the amount charged for a house call and to find that amount you have to subtract 30 from the amount Earl's charges:

50-30=20

This means that Ray charges $20 for a house call and $40 per carpet cleaned. According to this, the equation would indicate that the total cost for Ray is equal to the amount he charges for a house call plus the price per carpet cleaned for the number of carpets cleaned, which would be:

t= 20+40c, where:

t is the total cost

c is the number of carpets cleaned

Answer:

£21

Step-by-step explanation:

We know

Three women earned a total of £36. They shared the £36 in a ratio of 7:3:2. Meaning for every £12, one receives £7, one receives £3, and one receives £2.

Donna receives the largest amount working out the amount Donna receives.​ Meaning Donna receives £7.

To get from 12 to 36, we time 3.

We take

7 x 3 =  £21

So, Donna receives £21

To solve the equation \(6sin^2(x)\) + 6sin(x) + 1 = 0, we can use algebraic methods and the unit circle to determine the values of x that satisfy the equation.

1. Start by rearranging the equation to a quadratic form: \(6sin^2(x)\) + 6sin(x) + 1 = 0.

2. Notice that the equation resembles a quadratic equation in terms of sin(x). Let's substitute sin(x) with a variable, such as u: \(6u^2\) + 6u + 1 = 0.

3. Solve this quadratic equation for u. You can use the quadratic formula or factorization methods to find the values of u. The solutions are u = (-3 ± √3) / 6.

4. Since sin(x) = u, substitute back the values of u into sin(x) to obtain the values for sin(x): sin(x) = (-3 ± √3) / 6.

5. To find the values of x, we can use the inverse sine function. Take the inverse sine of both sides: x = arcsin[(-3 ± √3) / 6].

6. The arcsin function has a range of [-π/2, π/2], so the values of x lie within that range. Use a calculator to find the approximate values of x based on the values obtained in step 5.

7. Plot the obtained x-values on the graph to show the solutions of the equation \(6sin^2(x)\) + 6sin(x) + 1 = 0. The graph will illustrate the points where the curve intersects the x-axis.

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Answer:

B. 24:48

Step-by-step explanation:

3:6 is equivalent to 1:2 which is also equivalent to 24:48.

The circle and the lines AC & AB are illustrations of congruent angles

See below for the proof that the angles ∠ACB and ∠MAB are equal

To prove that ∠MAB=∠ACB, we make use of the attached diagram

From the attached diagram, we have:

∠MAB = x°

The angle at between a tangent and a radius or a diameter is a right angle.

This means that:

∠MAB + ∠BAC = 90°

Substitute ∠MAB = x°

x° + ∠BAC = 90°

Subtract x from both sides

∠BAC = 90° - x°

The angle at in a semicircle is a right angle.

This means that:

∠CBA = 90°

The angles in a triangle add up to 180°.

So, we have:

∠BAC + ∠CBA + ∠ACB = 180°

Substitute ∠CBA = 90° and ∠BAC = 90° - x°

90° - x° + 90° + ∠ACB = 180°

Evaluate the like terms

180° - x° + ∠ACB = 180°

Subtract 180° from both sides

- x° + ∠ACB = 0

Add x° to both sides

∠ACB = x°

Recall that:

∠MAB = x°

So, we have:

∠ACB = ∠MAB = x°

Hence, the angles ∠ACB and ∠MAB are equal

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