At a particular point near a second charge, a 50-µC charge experiences an attractive force of 2.0 N. What is the electric field strength at that point? Use \(10^{-6}\) coulumb for 1µC.

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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The luminosity of this star in units of the solar luminosity would be: 483.7L.

To calculate the luminosity, we would use the different values given and the formula for luminosity.

Temperature = 9305K

Star's radius = \(5.90 * 10^{9} m\\\)

Luminoisty of the star

Luminosity of the sun

= \(\frac{4π * (5.90 * 10^9)^2 * 5.67 * 10^-8 * 9305^4 W}{3.846 * 10^26 W}\)

= 483.7L

This is the unit for luminosity.

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The third law is also known as the law of action and reaction

FA = −FB.

Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction (FA = −FB).

Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object (FA = −FB).

For every action there is a reaction equal in magnitude and opposite in direction.

Examples of Newton's Third Law of Motion are:

Rowing a boat

Attraction of paper clip to a magnet

Recoil of a gun

Therefore, The third law is also known as the law of action and reaction (FA = −FB).

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Answer:

false because this is not possible that children behaviour is marked over by egocentrism children are also the tender creation of God

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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The equation  for a machine’s efficiency is = (output energy ÷ input energy) × 100%

Efficiency is the ability to achieve something or get a desired outcome without wasting resources, time, money, energy, or effort. In a broader sense, it is the capacity to carry out tasks effectively and efficiently.

It denotes the degree of performance that requires the fewest inputs to provide the greatest amount of output in more mathematical or scientific words.

Hence, mathematically, machine’s efficiency can be expressed as:

machine’s efficiency =  (output energy ÷ input energy) × 100%

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Answer:

Newton's first law of motion concerns any object that has no force applied to it.

Explanation:

three laws of motion and the law of universal gravitation.

Complete Question

Two parallel-plate capacitors C1 and C2 are connected in parallel to a 12.0 V battery. Both capacitors have the same plate area of 5.30 cm2 and plate separation of 2.65 mm. However, the first capacitor C1 is filled with air, while the second capacitor C2 is filled with a dielectric that has a dielectric constant of 2.10.

(a) What is the charge stored on each capacitor

 (b)  What is the total charge stored in the parallel combination?

Answer:

a

   i    \(Q_1 = 2.124 *10^{-11} \ C\)

   ii    \(Q_2 = 4.4604 *10^{-11} \ C\)

b

  \(Q_{eq} = 6.5844 *10^{-11} \ C\)

Explanation:

From the question we are told that

   The  voltage of the battery is  \(V = 12.0 \ V\)

    The  plate area of each capacitor is  \(A = 5.30 \ cm^2 = 5.30 *10^{-4} \ m^2\)

    The  separation between the plates is  \(d = 2.65 \ mm = 2.65 *10^{-3} \ m\)

     The permittivity of free space  has a value  \(\epsilon_o = 8.85 *10^{-12} \ F/m\)

     The  dielectric constant of the other material is  \(z = 2.10\)

The  capacitance of the  first capacitor is mathematically represented as

       \(C_1 = \frac{\epsilon * A }{d }\)

substituting values

        \(C_1 = \frac{8.85 *10^{-12 } * 5.30 *10^{-4} }{2.65 *10^{-3} }\)

       \(C_1 = 1.77 *10^{-12} \ F\)

The  charge stored in the first capacitor is  

       \(Q_1 = C_1 * V\)

substituting values

        \(Q_1 = 1.77 *10^{-12} * 12\)

       \(Q_1 = 2.124 *10^{-11} \ C\)

The capacitance of the second  capacitor is mathematically represented as

       \(C_2 = \frac{ z * \epsilon * A }{d }\)

substituting values

       \(C_1 = \frac{ 2.10 *8.85 *10^{-12 } * 5.30 *10^{-4} }{2.65 *10^{-3} }\)

       \(C_1 = 3.717 *10^{-12} \ F\)

The  charge stored in the second capacitor is  

      \(Q_2 = C_2 * V\)

substituting values

     \(Q_2 = 3.717*10^{-12} * 12\)

     \(Q_2 = 4.4604 *10^{-11} \ C\)

Now  the total charge stored in the parallel combination is mathematically represented as

     \(Q_{eq} = Q_1 + Q_2\)

substituting values

    \(Q_{eq} = 4.4604 *10^{-11} + 2.124*10^{-11}\)

     \(Q_{eq} = 6.5844 *10^{-11} \ C\)

On Mars, with an acceleration due to gravity of 3.71 m/s^2, the same falling mass of 15.0 kg would impart 55.6 J of kinetic energy to the rotating drum if it falls through the same height of 3.00 m, assuming all other factors remain the same.

The kinetic energy (K) imparted to the drum by the falling mass can be calculated using the formula:

where m is the mass of the falling object, and v is its velocity.

Since the object starts from rest, its initial velocity is zero, and we can simplify the formula to:

where u is the initial velocity of the falling object.

The potential energy (U) of the falling object is given by:

where g is the acceleration due to gravity and h is the height through which the object falls.

Since the potential energy is converted to kinetic energy, we can set U equal to K:

Simplifying the formula, we get:

Substituting the values given in the problem, we get:

Taking the square root of both sides, we get:

Using this velocity, we can calculate the kinetic energy imparted to the drum on earth:

To calculate the kinetic energy imparted to the drum on Mars, we can use the same formula, but with the acceleration due to gravity on Mars (3.71 m/s²):

Taking the square root of both sides, we get:

Using this velocity, we can calculate the kinetic energy imparted to the drum on Mars:

Therefore, the same falling mass of 15.0 kg would impart 55.6 J of kinetic energy to the rotating drum on Mars, which is less than the 350.0 J on earth due to the lower acceleration due to gravity.

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The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

From the data:

We substitute our values into the expression above and solve for final pressure.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

P₂ = P₁T₂  / T₁

P₂ = ( 3 atm × 900 K ) / 300 K

P₂ = 9.0 atm

Therefore, the final pressure is 9.0 atm.

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Newton's second law tells us that force is directly proportional to mass and acceleration, such that:

Where force is measured in newtons (N).

The three fundamental laws of Newton are:

Newton's laws are fundamental to understanding the interaction between bodies. Today they are still valid, although at the atomic level it has some exceptions that quantum mechanics studies.

Data:

m = 7.5 kg

F = ?

a = 3.2 m/s²

The formula to calculate the force is: F = m * a

We clear, but in this case it is not necessary, since we only want to calculate the force.

The force you need to accelerate down the alley is 24 Newtons.

Answer:

I believe it is C, Potential

Explanation:

Google, since all types are either kinetic or potential, so it wouldn't make sense if kinetic was itself. I also know for a fact it isn't Chemical

Answer:

Explanation:

Moment of inertial of a UNIFORM cylinder is ½mR²

Moment of inertial of a spherical shell is ⅔mR²

Total kinetic energy is

KE = ½mv² + ½Iω²

KE = ½m(Rω)² + ½Iω²

KE = ½mR²ω² + ½Iω²

for the cylinder

KE = ½mR²ω₁² + ½(½mR²)ω₁²

KE = ¾m0.0134²ω₁²

for the sphere

KE = ½mR²ω₂² + ½(⅔mR²)ω₂²

KE = ⅚m0.0697²ω₂²

as the KE and mass are the same

¾m0.0134²ω₁² = ⅚m0.0697²ω₂²

¾0.0134²ω₁² = ⅚0.0697²ω₂²

ω₁²/ω₂² = ⅚0.0697²/¾0.0134²

ω₁/ω₂ = 0.0697√⅚ / 0.0134√¾

ω₁/ω₂ = 5.48285455...

Answer:

=24.25 ^−1

Explanation:

Let   and   be initial and final velocity of the body respectively,  

be acceleration due to gravity ( 9.8^−2 ),  ℎ be the height of the body.

=0 ^ −1

ℎ=30

we know that, ^2−^ 2=2ℎ

^2=2∗9.8∗30

^2=588

=24.25 ^−1

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Answer:

(c) electron - they are found in the outer "shells" of atoms

Answer:

am pretty sure the answer is d

The required, it experiences a downward force due to gravity and a force due to air resistance.

Projectile motion is the movement of an entity projected into space. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.

Here,

When throwing a ball vertically upward, there is a displacement of about 1.0 m from the initial position of the hand to the position where the ball leaves the hand. The mass of the ball is 0.80 kg and it reaches a maximum height of about 20 m above the initial position of the hand. While the ball is in the hand after it leaves, it experiences a downward force due to gravity and a force due to air resistance.

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Answer:

E = K Q / R^2     by Gauss' Law where Q is the  charge enclosed by the surface of revolution and R is the distance from the enclosed charge

Since Q = d 4 pi r^2   where d is the charge density and r the radius of the inner sphere

E = K / R^2 * (4 d pi r^2) = 4 K pi d (r / R)^2 = 4 K pi d * 1/4

E =  9 * 10E9 * 3.14 * 40 * 10E-12 = 1.13 N / C

Answer: The answer would be option B waxing phase as per the phases of the moon.

Explanation: The moon has a cycle of 30 days in the first fifteen days it starts from a new moon and travels the path upto it reaches a full moon this phase of the moon is called Waxing Phase and in the next phase it travels from a full moon to the new moon again and this phase of the moon is said to be the Waning Phase.

These two phases of the moon are also divided into two subphases where they have Crescent and Gibbous.

As per these explanations, the conclusion could be driven that the moon from a full moon to a new moon is called as Waning phase.

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Answer:

The external forces such as wind, water and the vibration of the earth when an earthquake happens create internal forces within a structure. Internal forces such as shear, tension and compression can destroy the inner framework of a building or a bridge even though it is made of super strong steel and concrete.

I Hope This Will Help You ...

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\(\longrightarrow\) The rate of change of velocity per unit time is called acceleration.

\(\longrightarrow\) Its SI unit is m/s².

\(\longrightarrow\) Formula of acceleration is v-u/t

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Yes, if a body is floating in a liquid, the rise in the liquid level is equal to the body height. This phenomenon is known as Archimedes' principle.

Archimedes' principle says when a body is immersed in a fluid (liquid or gas), it experiences an upward buoyant force equal to the weight of the fluid displaced by the body. Buoyant forces act in the opposite direction to gravity.

When a body floats in a liquid, it displaces a volume of liquid equal to its volume. As a result, the liquid level rises by an amount equal to the height of the submerged part of the body.

This principle holds for objects that float or are partially immersed in a liquid, such as a buoyant boat or a floating object. However, if the body sinks completely into the liquid, the liquid level rise will no longer be equal to its height. Instead, it depends on the density and volume of the submerged object.

Answer:

q=9.43×10^-5C

Explanation:

F=kq^2/r^2

500= 9×10^9 × q^2/ (0.4)^2

500N×0.16m=9×10^9Nm^2C^2 × q^2

80/(9×10^9)= q^2

√(8.8889×10^9) = q

q= 9.43×10^-5C

since they are identical both charges, q=9.43×10^-5C

The magnitude of the two charges is ​9.43×10^-5 C.

To calculate the magnitude of an electric force, it is necessary to use the following expression:

                                          \(F = k \frac{q_{1} \times q_{2} }{d^{2}}\)

Assuming that the constant is:

                                          \(k = 9\times 10^{9}\)

We can apply the values ​​in the formula above, obtaining:

                                     \(500 = 9 \times 10^{9} \times \frac{q^{2}}{0.4^{2}}\)

                                         \(q = \sqrt{0.88\times10^{-8}}\)

                                          \(q = 9.43 \times 10^{-5} C\)

So, the magnitude of the two charges is   ​9.43×10^-5 C.

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Answer:

211.2 kg:m/s

Explanation:

Mark brainily

Answer:

The distance is \(d = 193.6 \ m\)

Explanation:

From the question we are told that

   The time interval between the sounds is  k\(t_1 = k + t_2\) =  0.50 s

    The  speed of sound in air is  \(v_s = 343 \ m/s\)

    The  speed of sound in the concrete is \(v_c = 3000 \ m/s\)

Generally the distance where the collision occurred is  mathematically represented as

          \(d = v * t\)

Now from the question we see that d is the same for both sound waves

 So

        \(v_c t = v_s * t_1\)

Now  

So \(t_1 = k + t\)

      \(v_c t = v_s * (t+ k)\)

=>     \(3000 t = 343* (t+ 0.50)\)

=>    \(3000 t = 343* (t+ 0.50)\)

=>    \(t = 0.0645 \ s\)

So

     \(d = 3000 * 0.0645\)

     \(d = 193.6 \ m\)

Given:

The time period of the wave is T = 10 s

Required: The frequency of the wave

Explanation:

The frequency can be calculated by the formula

On substituting the values, the frequency of the wave will be

Final Answer: The frequency of the wave is 0.1 Hz

Answer:

Approaches mathematical learning through inquiry

-Explore real contexts, problems, situations, and models

-Learning through doing shifts the focus on the students

-Problems have multiple entry and exit points

-Links to other disciplines

Explanation:

quizlet

The current required by the 60W bulb is three-fifths that required by the 110W bulb

The formula for calculating power is as follows:

Assuming the voltage across the light bulbs is the same

From the formula, P = IV;

I = P/V

For the 60 W bulb

I₁ = 60/V

For the 100W bulb

I₂ = 100/V

Taking ratios of the currents:

I₁/I₂ = {60/V}/{`100/V}

I₁/I₂ = 3/5

Therefore, the current required by the 60W bulb is three-fifths that required by the 110W bulb

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