Blood is an example of a basic buffer system. Which of the following could be used to mimic the buffering abilities of blood?
Select the correct answer below:
HF and NaF
CH3NH2 and CH3NH3Cl
KOH and H2O
none of the above

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer:

heat, electrical, mechanical, nuclear,sound

Explanation:

The power plant is mechanicalised so it produce heat which is in form of electrical and then we start hearing sound

Answer:

TRUE

Explanation:

plz brian list

Answer:

True

Explanation:

Answer:

Refer to the picture. I managed to solve a few.

The most reactants in the system are the oxygen molecules while the least reactants in the system is carbon sulfide. As such carbon sulfide is the limiting reactant.

We know that when we talk about a chemical reaction, what we are referring to is the interaction that is able to occur between the reactants and the products that are found in the system. We know that when we write down a chemical reaction, the species that are combined are the species that we can find on the left hand side and they are called the reactants. The species that we obtain in the reaction are the species that we can find on the right hand side and they are called the products of the reactions.

If we look at the reaction as it has been shown, we can see that there are ten oxygen molecules and three carbon sulfide molecules that were initially present in the system as we can see here. The entire reaction equation is given as; CS₂(g)+30₂(g) → CO₂(g) +2 SO₂(g).

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Answer:

Fe + CuCl2 = FeCl2 + Cu

Explanation:

This is already balanced.

Answer:

3.13M

Explanation:

Using the Molaitry equation ( M = n/v ) just plug numbers in and solve.

Moles of potassium nitrate are produced at the same time 4.4 moles of aluminum phosphate are produced is 28.63 mole

Potassium nitrate is an inorganic salt with a chemical formula of KNO₃ it is a natural source of nitrate and has been used as a constituent for several different purposes including food preservatives, fertilizers, tree stump removal, rocket propellants, and fireworks

Here given data is

4.4 moles of aluminum phosphate

We have to find  moles of potassium nitrate =?

Number of mole = mass of substances/mass of one mole

Number of mole = 126/ 4.4 moles

Number of mole = 28.63mole

So, 28.63 mole potassium nitrate are produced at the same time 4.4 moles of aluminum phosphate are produced

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Covalent and ionic bonds refer to atoms joined by their electrons. In covalent bonds, electrons are shared by the involved non-metal atoms. Option 2 is correct. Occurs due to the sharing of electrons between two non-metal atoms.

Both of them, covalent and ionic bonds, are chemical bonds that can form between atoms.

Ionic bonds occur between atoms with different electronegativity. When they bind, they transfer electrons from one atom to the other creating ions with opposite charges that attract each other.

Ionic compounds are formed by anions and cations.

• Cations are positive ions derivated from metals.

• Anions are negative ions derivated from non-metals.

The metal atoms share its electrons with the non-metal ones, creating stable configurations. Ionic bonds do not create molecules.

Covalent bonds are formed between atoms share electrons to be more stable. Atoms involved share electrons equally, creating a strong bond between them.

Covalent bonds are usually formed between non-metal atoms.

Option 2 is correct. Occurs due to the sharing of electrons between two non-metal atoms

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Complete question

A template of a Venn diagram representing common and differentiating characteristics of covalent and ionic bonds is shown.

Which of the following characteristics can be written only in space C?

On the diagram,

Options,

There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. Therefore, Strontium belongs to group 2, alkaline earth metal family of the periodic table.

Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.

Periodic table help a scientist to know what are the different types of elements are present in periodic table so that they can discover the new elements that are not being discovered yet.

Strontium is the element having 38 protons and 50 neutrons.

mass number= proton number + neutron number

                      =38+ 50

                     =88

Group number of this element is group 2. Strontium belongs to akaline earth metal family.

Therefore, Strontium belongs to group 2, alkaline earth metal family of the periodic table.

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Tyndall effect is the scattering of light by colloidal particles. Colloids are mixtures in which one substance is dispersed evenly throughout another substance.

Solutions are a type of mixture that appear homogeneous and do not exhibit the Tyndall effect. On the other hand, suspensions and colloids do not appear homogeneous and do exhibit the Tyndall effect.

Based on the information given, Sample 1 shows yes for both filtering and settling, which means it is a heterogeneous mixture, and therefore not a solution.

Sample 2 does not show the Tyndall effect and does not settle, which means it is a homogeneous mixture, and therefore a solution. Sample 3 shows the Tyndall effect but does not settle, which means it is a heterogeneous mixture, and therefore not a solution.

Therefore, the sample that represents a solution and does not exhibit the Tyndall effect is Sample 2, and the answer is A. Sample 2.

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Answer:

LI

Explanation:

The vapor-pressure lowering, AP, of an aqueous solution is 2.44Torr.

Mole = \(\frac{weight}{molecular weight}\)

In a 1.80m (molal) solution, 1 kilogram of the solvent contains 1.80 moles of the solute (which is water in this case).

Water's molar mass is equal to 2(atomic mass of H) + [2(1)+16] (atomic mass of O).

=18g/mol

The mole of water in 1 kilogram (equivalent to 1000 grams)::

\(n_{H_{2} O}\)= \(\frac{1000}{18g/mol}\) = 55.56mol

The solute's mole fraction in the 1.80 m solution is as follows::

\(x_{solute}\) = \(\frac{n_{solute} }{n_{H_{2}O }}\)

   ⇒\(x_{solute} =\) \(\frac{1.80}{55.56}\) = 0.032

a. Sucrose is a non-electrolyte, i.e., it does not undergo dissociation in the aqueous solution.

As a result, the Van't Hoff factor for sucrose is = i = 1

The lowering in vapor pressure of the solution, which is 1.80m in sucrose:

=\(ix_{solute}p^{0}\)

=(1)(0.032)(17.54)Torr

=(0.56)Torr

b. Aluminum chloride dissociate in water as follows:

\(AlCl_{3}\) →\(Al^{3+}+ 3Cl^{-}\)

As a result, an aqueous solution containing one aluminum chloride particle yields four more particles.

Thus, i=4

The lowering in vapor pressure is thus:

=\(ix_{solute}p^{0}\)

=(4)(0.032)(17.54)Torr

=(2.24)Torr

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One molecule of propanol contains only one -OH group and not three -OH groups or three -CH3 groups.

The -OH group is attached to the central carbon atom and makes propanol a useful solvent and intermediate in organic chemistry.Propanol is a colorless liquid that belongs to the family of alcohols. It has the formula C3H8O, and it contains three carbon atoms, eight hydrogen atoms, and one hydroxyl group (-OH) attached to one of the carbons. One molecule of propanol contains only one -OH group, which is attached to the central carbon atom.

Thus, option (2) is the correct answer, and the other options are incorrect.The -OH group in propanol is responsible for its unique chemical and physical properties. It makes propanol soluble in water and other polar solvents and gives it a high boiling point of around 97°C. The hydroxyl group can also participate in chemical reactions, such as esterification, dehydration, oxidation, and reduction. For example, propanol can be oxidized to form propanal and then propanoic acid, which is a useful synthetic intermediate for many organic compounds.Apart from the -OH group, propanol also contains two other functional groups called methyl groups (-CH3). These are attached to the two carbon atoms adjacent to the central carbon. However, the question only asks about the number of -OH groups in propanol, so the methyl groups are irrelevant.
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The density of the iron pyrite cube is 1.343 g/cm³.

Given,

Side of iron pyrite cube = 0.31 cm

Mass of iron pyrite = 0.040 g

The volume of iron pyrite cube = s³ cm³

Or, volume = 0.029791 cm³

We have to find the density of the sample.

Density is defined as the mass per unit volume. Or, it is the ratio of mass to the volume of the substance.

Using the formula for density, we get,

Density = mass/volume

Or, density = 0.40/0.029791

Or, density = 1.343 g/cm³

Hence, the density of the iron pyrite cube is 1.343 g/cm³.

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There are approximately 0.16 moles of gas present in the lungs.

To solve this problem, we can use the ideal gas law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas:

PV = nRT

where R is the gas constant.

First, we need to convert the temperature to Kelvin:

T = 37°C + 273.15 = 310.15 K

Next, we can plug in the given values:

P = 1.0 atm

V = 4.0 L

T = 310.15 K

We also need to find the value of R, which depends on the units we are using for pressure, volume, and temperature. In this case, we are using atmospheres, liters, and Kelvin, so we can use the value:

R = 0.08206 L·atm/K·mol

Now we can rearrange the ideal gas law to solve for the number of moles:

n = PV/RT

n = (1.0 atm)(4.0 L)/(0.08206 L·atm/K·mol)(310.15 K)

n = 0.1638 mol

Therefore, there are approximately 0.16 moles of gas present in the lungs.

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Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Answer:

a. The Zn and HCl both retained their identity.

344.0 / 68.8 = 5 (no.of half life that have elapsed)

Mass remains = (1/2)^n × (original mass)

= (1/2)^5 × 200

= (0.5) ^5 × 200

= 0.03125 × 200

= 6.25 grams

Answer:

Option 4: ¹⁴₆C —> ⁰₋₁e + ¹⁴₇N

Explanation:

To know which option is correct, do the following:

Option 1:

²²¹₈₇Fr —> ⁴₂He + ²²⁵₈₅At

87 = 2 + 85

87 = 87

221 = 4 + 225

221 ≠ 229

Thus the equation is not balanced.

Option 2:

²³⁷₉₃Np —> ⁴₂He + ²³³₉₅Am

93 = 2 + 95

93 ≠ 97

237 = 4 + 233

237 = 237

Thus, the equation is not balanced.

Option 3:

²¹⁴₈₂Pb —> ⁰₋₁e + ²¹⁴₈₁Tl

82 = –1 + 81

82 ≠ 80

214 = 0 + 214

214 = 214

Thus, the equation is not balanced.

Option 4:

¹⁴₆C —> ⁰₋₁e + ¹⁴₇N

6 = –1 + 7

6 = 6

14 = 0 + 14

14 = 14

Thus, the equation is balanced.

From the illustrations above, only option 4 is correct.

Answer:

1. Some combination of ions form a solid precipitate because it is not favorable for the ions to become solvated (dissolved). Large and lowly charged ions tend to form precipitates, especially metals such as lead, barium, and silver.

2.
a. Pb(NO3)2 + 2KI -> 2KNO3 + PbI2

b. PbI2 is a precipitate because no other combinations of cations and anions will make an insoluble compound. KI, KNO3, and Pb(NO3)2 are all soluble.

c.

\(Pb^{2+}(aq) + 2NO_3^{-}(aq) + 2K^+(aq) + 2I^-{aq} = > PbI_2(s) + 2NO_3^{-}(aq) + 2K^+{(aq)}\\\\\)

is the ionic equation. Spectator ions are NO3- and K+

d.

\(Pb^{2+}(aq)+ 2I^-{aq} = > PbI_2(s) \\\)  is the net ionic equation

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Decreasing vapour pressure for the following compounds is as follow:

CH4

CH3CH-CH3CH2CH3

CH3CH2CH2CH2CH3

CH3CH2CH2OH

Vapour Pressure of the compound:

The pressure characteristic of a pure compound's vapour at any given temperature when it is in equilibrium with its liquid or solid state is known as the vapour pressure. Compound molecules that bond well with one another will have a low vapor pressure (less inclination to escape to the vapor phase), whereas compounds that connect poorly with one another would have a high vapor pressure. Vapor pressure is a measure of a compound's capacity to bond with itself.

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Explanation:

First, we need to know that chemical bonds such as covalent and ionic bonds will always have greater strengths in relation to intermolecular interactions.

Hydrogen bond will be the intermolecular interaction with the greates streght. Then dipole force and then dipole.

Answer: B. Dispersion force < dipole force < hydrogen bonding < covalent bonding

Explanation:

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eight

The sodium chloride solution would melt at a high temperature and conduct electricity but the sucrose would not do any of these.

The conductivity test is the test that can be use to determine which of the substances can be able to conduct electricity. The substance that can be able to conduct electricity must be ionic in nature and would also have a high melting point.

a) If we dissolve the two substances in water and then connect an external cell to it, we would notice that the sodium chloride solution would conduct electricity but the sucrose solution would not.

b) On the other hand, the sodium chloride solution would be found to melt at a much higher temperature than the sucrose.

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Esterification is the process that turned salicylic acid and acetic acid into acetylsalicylic acid.

Thus,  The process of creating esters from carboxylic acids is known as esterification. When a carbon is linked to two oxygen atoms, an ester results from one of the oxygens being double-bonded to the carbon while the other oxygen is linked to another carbon.

The letter "R" stands for a carbon chain in the following generic formula for an ester.

Esterification occurs when a carboxylic acid reacts with an alcohol. This reaction can only occur in the presence of an acid catalyst and heat. It takes a lot of energy to remove the -OH from the carboxylic acid, so a catalyst and heat are needed to produce the necessary energy.

Thus, Esterification is the process that turned salicylic acid and acetic acid into acetylsalicylic acid.

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Explanation:

To calculate the heat gained by nickel, we can use the formula:

q = m * c * ΔT

where q is the heat gained, m is the mass of the nickel, c is the specific heat of nickel, and ΔT is the change in temperature.

Given:

- Mass of nickel, m = 31.4 g

- Specific heat of nickel, c = 0.443 J/g · °C

- Change in temperature, ΔT = 64.2 °C - 27.2 °C = 37.0 °C

Substituting the values into the formula, we get:

q = (31.4 g) * (0.443 J/g · °C) * (37.0 °C)

Simplifying the calculation, we get:

q = 584 J

Therefore, the heat gained by nickel when 31.4 g of nickel is warmed from 27.2 °C to 64.2 °C is 584 J.

The IUPAC name for 2,3,7,9-tetramethyl-5-(1-methylbutyl)decanoic acid is 2,3,7,9-tetramethyl-5-(1-methylbutyl)decanoic acid. It is a carboxylic acid with a molecular formula of C20H40O2 and a molecular mass of 312.54 g/mol. The compound has a melting point range of 70-75°C.

2,3,7,9-tetramethyl-5-(1-methylbutyl)decanoic acid contains a carboxyl group (-COOH), which is the functional group responsible for its acidic properties and solubility in water. The presence of the carboxyl group makes the compound more polar than similar molecules, enhancing its water solubility. Carboxylic acids are also known for their reactivity with bases and ability to undergo esterification reactions.

In summary, 2,3,7,9-tetramethyl-5-(1-methylbutyl)decanoic acid is a carboxylic acid with a unique molecular structure. Its IUPAC name describes the positions and nature of the substituent groups. The presence of the carboxyl group contributes to its polarity, water solubility, acidity, and reactivity with bases and esterification reactions. The compound's characteristics are significant in understanding its properties and potential applications in various chemical reactions and processes.

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