6. How can an answer from an experiment be verified?

Answer:

376.56 g/mol.

Explanation:

The molar mass of bromine is approx. 79.904 g/mol. 79.904 x 4 = 319.616 g/mol. The molar mass of Fluorine is approx. 18.998 g/mol. 18.998 x 3 =  56.994 g/mol. 56.994 amu + 319.616 amu = 376.56 g/mol.

Answer:

\(\boxed {\boxed {\sf 376.594 \ g/mol}}\)

Explanation:

We are asked to find the molar mass of tetrabromine trifluoride. This compound has the formula Br₄F₃.

The molar mass is the mass of 1 mole of a substance. The values are found on the Periodic Table because they are equal to the atomic masses, but the units are grams per mole instead of atomic mass units.

Look up the molar masses of the individual elements in the compound: bromine and fluorine.

Look at the subscripts in the formula. There is a subscript of 4 after Br and one of 3 after F. This means one mole of the compound contains 4 moles of bromine and 3 moles of fluorine.

Multiply the molar masses by their respective subscript, then add the results.

The molar mass of Br₄F₃ is 376.594 grams per mole.

Answer:

342.29648 g/mol

Explanation:

Mass of sugar C₁₂H₂₂O₁₁ is required to provide 2.50 x 10²³ molecules of O₂ is 11.84.

Avogadro's number is the number of units in one mole of any substance and equals to 6.02214076 × 10²³. The units can be electrons, atoms, ions, or molecules.

No. of moles is defined as a particular no. of particles that we can calculate with the help of Avogadro’s number.

Mass of a particular product is also find out by stoichiometry of a reaction as per the no. of mole given in the reaction.

Reaction is-

C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O

1 mole of C₁₂H₂₂O₁₁ forms 12 moles of O₂.

12 × 6.02214076 × 10²³ molecules of O₂ formed by 342.3 g of C₁₂H₂₂O₁₁.

1 molecule of O₂ formed by 4.73 × 10⁻²³  g of C₁₂H₂₂O₁₁.

2.50 × 10²³ molecules of O₂ formed by 11.84 g of C₁₂H₂₂O₁₁.

Therefore, Mass of sugar C₁₂H₂₂O₁₁ is required to provide 2.50 x 10²³ molecules of O₂ is 11.84.

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1. The mass of sodium sulfate, Na₂SO₄ formed from the reaction is 131.13 g

2. The percentage yield obtained from the reaction is 93.3%

We shall begin by obtaining the limiting reactant. This obtained as follow

2NaOH + H₂SO₄ —> Na₂SO₄ + 2H₂O

From the balanced equation above,

80 g of NaOH reacted with 98 g of H₂SO₄

Therefore,

98.6 g of NaOH will react with = (98.6 × 98) / 80 = 120.785 g of H₂SO₄

Since a higher amount (i.e 120.785 g) of H₂SO₄ than what was given (i.e 80.5 g) is needed to react with 98.6 g of NaOH, thus, the limiting reactant is H₂SO₄

Finally, we shall determine mass of sodium sulfate, Na₂SO₄ formed. Details below:

2NaOH + H₂SO₄ —> Na₂SO₄ + 2H₂O

From the balanced equation above,

98 g of H₂SO₄ reacted to produce 142 g of Na₂SO₄

Therefore,

90.5 g of H₂SO₄ will react to produce = (90.5 × 142) / 98 = 131.13 g of Na₂SO₄

Thus, the mass of mass of sodium sulfate, Na₂SO₄ formed is 131.13 g

The percentage yield obtained can be obtained as follow:

Percentage yield = (Actual /Theoretical) × 100

Percentage yield = (122.4 / 131.13) × 100

Percentage yield = 93.3%

Thus, the percentage yield is 93.3%

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Answer:

A test variable is a user-defined, name-value pair that stores and refers to information throughout a test and between tests. For example, in a study looking at how tutoring impacts test scores, the dependent variable would be the participants' test scores, since that is what is being measured...

The control group is defined as the group in an experiment or study that does not receive treatment by the researchers and is then used as a benchmark to measure how the other tested subjects do. For example, The control group is used in an experiment as a way to ensure that your experiment actually works. Your experimental group would be given the Gatorade and your control group would be given regular water. The conditions must be exactly the same for all members of the experiment.

A limiting factor is anything that constrains a population's size and slows or stops it from growing. Some examples of limiting factors are biotic, like food, mates, and competition with other organisms for resources. Limiting factors are usually expressed as a lack of a particular resource.

Infectious agents commonly spread through the direct transfer of bacteria, viruses, or other germs from one person to another. This can happen when an individual with the bacterium or virus touches, kisses, or coughs or sneezes on someone who isn't infected.

Explanation:

Considering the phase diagram, the state of matter that exists in area B is gas.

The correct option is A.

A phase diagram is a graphical representation that shows the conditions of temperature and pressure at which different phases or states of a substance exist.

The axes of a phase diagram typically represent temperature (usually on the horizontal axis) and pressure (usually on the vertical axis). The diagram is divided into regions that correspond to different phases, and the lines separating these regions represent phase boundaries.

The point where three phase boundaries meet is known as the triple point, which represents the temperature and pressure at which all three phases can coexist in equilibrium.

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The strand 1 of hydrocarbons is used to produce plastic, hence option D is correct.

Raw resources like natural gas, oil, or plants that have been processed into ethane and propane are used to make plastics. The subsequent "cracking" procedure uses heat to transform ethane and propane into ethylene and propylene. To produce various polymers, these components are mixed.

Propylene is a substance found in large quantities in petroleum. In order to speed up chemical processes, refiners combine heated propylene with a catalyst to create plastic. Propylene molecules start to cluster together like beads on a thread as a result.

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Answer: 2

Explanation: Calcium has a +2 charge and PO4 has a -1 charge. When writing this expression, the charges are flipped; instead of Ca2(PO4), it's Ca(PO4)2.

Answer:

\(x_{A.A}=0.668\)

Explanation:

Hello!

In this case, since the mole fraction involves the moles of each substance, we first compute them considering the molar masses of acetic acid and acetone to be 60.052 and 58.08 g/mol respectively:

\(n_{A.A}=\frac{100gA.A}{60.052g/mol}=1.67molA.A\\n_{acetone}=\frac{48gAcetone}{58.08g/mol} =0.824molAcetone\)

Thus, the mole fraction of acetic acid is computed below:

\(x_{A.A}=\frac{n_{A.A}}{n_{A.A}+n_{Acetone}} =\frac{1.67mol}{1.67mol+0.826mol}\\\\ x_{A.A}=0.668\)

Regards!

The process of gas effusion involves a hole, where the gas escapes. Lower molecular mass gases emit more quickly than greater molecular mass gases is( n2 and co )

The rate law demonstrates how the rate of a chemical reaction is influenced by the reactant concentration. The mathematical explanation provided by the Rate laws demonstrates how variations in a substance's amount can alter the rate of a chemical reaction.

The molecular mass is connected to the relative rates of effusion.

a) M(N₂)/M(O₂) = 28/32 = 0,875

b) M(N₂O)/M(NO₂) = 44/46 = 0,956

c) M(CO)/M(CO₂) = 28/44 = 0,636

d) M(NO₂)/M(N₂O₂) = 44/58= 0,758

e) M(CO)/M(N₂) = 28/28 = 1, CO and N₂ The equation for the elementary step is if the reaction takes place in the single elementary step, which is the three-body molecular collision. have inexact molecular masses and will effuse at nearly identical rates.

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Answer:

I guess this answer is c

yh

Answer:

b. (Actual yield ÷ theoretical yield) x 100

Explanation:

The percent yield will be a ratio of collected or actual yield to the theoretical yield. Like any percentage, you are determining a part of a whole. You multiply by 100 to convert your decimal answer from the division into a percentage.

For an electron as a particle, E = \(1/2mv^2\)

For an electron as a particle, the energy E can be described using the equation:

E =  \(1/2mv^2\)

where

This equation represents the kinetic energy of the electron, which is the E is the energy

energy associated with its motion.

This equation assumes classical mechanics and does not take into account relativistic effects that become significant at high speeds close to the speed of light.

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Answer:

Explanation:

To calculate the concentration of the resulting solution, we can use the dilution equation:

C1V1 = C2V2

where C1 and V1 are the initial concentration and volume of the stock solution, and C2 and V2 are the final concentration and volume of the resulting solution.

Plugging in the given values, we get:

C1 = 0.021 M

V1 = 8.19 mL = 0.00819 L

V2 = 25 mL = 0.025 L

Solving for C2:

C2 = (C1 x V1) / V2

= (0.021 M x 0.00819 L) / 0.025 L

= 0.00687 M

Therefore, the concentration of the resulting solution is 0.00687 M.

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If it took 412.5 J of heat to raise the temperature of 24.6 g of a substance from 14.5°C to 52.6°C, the specific heat of the substance is 0.44 J/g°C.

The specific heat of a substance can be calculated by using the following formula:

Q = m × c × ∆T

Where;

412.5 = 24.6 × c × (52.6 - 14.5)

412.5 = 937.26c

c = 412.5/937.26

c = 0.44 J/g°C

Therefore, If it took 412.5 J of heat to raise the temperature of 24.6 g of a substance from 14.5°C to 52.6°C, the specific heat of the substance is 0.44 J/g°C.

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Answer:

D The number of protons

Answer:

8.90

Explanation:

because I calculated it

The mass of Fluorine in grams in the second sample is 2066 g. The concept law of definite proportions is used here to obtain the mass of Fluorine in the second sample.

This law was stated by a French chemist, Louis Proust. It states that 'a chemical compound always contains the same elements combined together in the same proportion by mass'.

The mass of Mg in sample 1 is 1.66 kg and that of F is 2.56 kg. The mass of Mg in sample 2 is 1.34 kg and we have to find out the mass of F in second sample.

The mass of Fluorine in sample 2 can be obtained by using the mass ratio of the elements in sample 1.

In sample 1:

Mass of magnesium ÷ Mass of Fluorine = 1.66 kg ÷ 2.56 kg

In sample 2:

By using dimensional analysis,

Mass of Fluorine = 2.56 kg Fluorine ÷ 1.66 kg Magnesium × 1.34 kg Magnesium

Therefore the mass of Fluorine = 2.066 kg

The mass in kilogram can be converted into grams as:

Mass of Fluorine = 2.066 kg × 1000 g ÷ 1 kg = 2066 g

Thus the mass of Fluorine in the second sample is 2066 g.

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Answer:

solusoin ( 0.0130 )²

Explanation:

Answer:

different from ionic or covalent bonding

Explanation:

The equilibrium constant at this temperature is Kc= 4.17 x 10⁻⁶.

Since the equilibrium constant depends on the equilibrium concentration of both the reactants and the products of the chemical reaction.

Balanced reaction equation

2CH₄(g)⇌C₂H₂(g)+3H₂(g)

The initial concentration of the CH₄ = 0.093 M

The equilibrium concentration of the H = 0.017 M

Equilibrium constant = ?

Let's make the ice table

2CH₄(g) ⇌ C₂H₂(g) + 3H₂(g)

0.093 M 0 0

-2x +x +3x

0.093-2x x 0.017 M

3x = 0.017 M

Therefore, x =0.017 M /3 = 0.00567 M

Therefore, the equilibrium concentration of CH₄ =

0.093 M – 2x = 0.093 M – (2 x 0.00567 M) = 0.0817 M

Equilibrium concentration of the C₂H₄ = x = 0.00567 M

Let's write the equilibrium constant expression

Kc= [C₂H₄[H2]³/[CH₄]²

Let's put the values in the formula

Kc= [0.00567][0.017]³/[0.0817]²

Kc= 4.17 x 10⁻⁶

Therefore, the equilibrium constant is 4.17 x 10⁻⁶.

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When the equilibrium constant is higher than one, it indicates that the reaction prefers to produce products, whereas if the equilibrium constant is less than one, it indicates that the reaction prefers to produce reactants. If the equilibrium constant is equal to one, the reaction proceeds in both directions equally.

In a chemical reaction, exothermic reactions are defined as reactions that release heat into their environment. It implies that heat is given off when reactants are converted to products. At equilibrium, an exothermic reaction continues to be exothermic, meaning that heat is given off even after the reaction reaches a state of equilibrium.There are two types of reactions: exothermic and endothermic.

A reaction is classified as exothermic if it releases heat, and endothermic if it absorbs heat. The direction of the reaction is determined by whether it is exothermic or endothermic. At equilibrium, the reaction is no longer moving forwards or backwards. It's also worth noting that reactions can be exothermic in one direction and endothermic in the other.

The equilibrium constant (K) is defined as the ratio of the concentration of products to the concentration of reactants in the chemical reaction equation. It is used to express how much of the products is generated by the reaction in comparison to the reactants.  the equilibrium constant aids in the identification of the direction in which the reaction will proceed at equilibrium.

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Answer:

NADH is formed

Explanation:

If oxygen exists in the system, pyruvate goes into mitochondrial matrix in order to perform kreb's cycle and forms NADH

Otherwise, pyruvate forms into lactate acid.

Good luck on your final exam

Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).

The Nernst equation is given as follows:

E = E° - (RT/nF) * ln(Q)

Given information:

Ksp = 1 × 10^(-12)

E = +0.799 V (standard reduction potential of Ag+ to Ag)

Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].

Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.

Therefore, Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.

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Answer:

the genes and traits of the offspring is a 50/50 chance.

Explanation:

The type of reproduction has 2 parents involved

There are approximately 6.022 × 10^23 atoms in 12 grams of Carbon-12 (12C).

The number of atoms in a given amount of a substance can be calculated using Avogadro's number, which represents the number of atoms or molecules in one mole of a substance. Avogadro's number is approximately 6.022 × 10^23.

Carbon-12 is a specific isotope of carbon, with an atomic mass of 12 atomic mass units (amu). One mole of Carbon-12 has a mass of 12 grams. Since one mole of any substance contains Avogadro's number of particles, in the case of Carbon-12, it contains 6.022 × 10^23 atoms.

Therefore, if we have 12 grams of Carbon-12, which is equal to one mole, we can conclude that there are approximately 6.022 × 10^23 atoms in this amount of Carbon-12.

In summary, 12 grams of Carbon-12 contains approximately 6.022 × 10^23 atoms. Avogadro's number allows us to relate the mass of a substance to the number of atoms or molecules it contains, providing a fundamental concept in chemistry and enabling us to quantify and understand the microscopic world of atoms and molecules.

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The gas that has a volume of 752 mL at 1.98 atm and 62°C is most likely NO₂ (option D).

The volume of a sample of gas can be calculated using the following formula:

PV = nRT

Where;

According to this question, the volume of a sample of gas (2.49 g) was 752 mL at 1.98 atm and 62°C. The number of moles is as follows:

1.98 × 0.752 = n × 0.0821 × 335

1.489 = 27.5n

n = 0.054mol

molar mass of the gas = 2.49g ÷ 0.054mol = 45.99g/mol

The gaseous substance with the molar mass of 45.99g/mol is NO₂.

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Answer: city w

Explanation:

cities w,y,z all use renewable energy (sun, water, wind) which offput any greenhouse emmissions,

city w uses coal which produces greenhouse gases when used (burnt).

hope this helped! ♡