When limestone (which is principally CaCO3)


is heated, carbon dioxide and quicklime


(Cao) are produced by the reaction


CaCO3(s) 4CaO(s) + CO2(g).


If 12. 5 g of CO2 was produced from the ther-


mal decomposition of 40. 79 g of CaCO3, what


is the percentage yield of the reaction?


Answer in units of %.

Answer:

angle

Explanation:

let us see the sun moves an a angle

The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.

Given:

Power rating of the refrigerator = 500 W

Running time per day = 12 hours

Number of days = 30

First, we need to convert the power rating from watts to kilowatts:

Power rating = 500 W / 1000 = 0.5 kW

Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:

Energy used = Power rating × Running time × Number of days

Energy used = 0.5 kW × 12 hours/day × 30 days

Energy used = 180 kWh

Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

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The balanced molecular equation for the neutralization reaction between nitric acid (HNO₃) and potassium hydroxide (KOH) is HNO₃ + KOH → KNO₃ + H₂O.

In a neutralization reaction between a strong acid and a strong base, the hydrogen ion (H+) from the acid combines with the hydroxide ion (OH-) from the base to form water (H₂O). The remaining ions from the acid and the base combine to form a salt. In this case, nitric acid (HNO₃) is a strong acid and potassium hydroxide (KOH) is a strong base.

The balanced molecular equation for the reaction is as follows:

HNO₃ + KOH → KNO₃ + H₂O

In this equation, one molecule of nitric acid reacts with one molecule of potassium hydroxide, resulting in the formation of one molecule of potassium nitrate (KNO₃) and one molecule of water (H₂O). This equation represents the overall reaction that occurs during the neutralization process.

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Answer: d. boiling point of ethyl alcohol is 75.

Explanation:

When a metal is subjected to pressure, such as a blow from a hammer, the metal cations easily slide past one another. This is due to the unique properties of metallic bonding and the arrangement of atoms in a metal lattice.

In a metal, the atoms are held together by metallic bonds, which are formed by the sharing of valence electrons among all the atoms in the lattice. These delocalized valence electrons move freely throughout the metal, creating a sea of electrons that surround and hold the metal cations together. The metal cations, which are positively charged ions, are arranged in a regular and repeating pattern within the lattice.

When pressure is applied to a metal, the metal cations are pushed closer together. However, due to the presence of the delocalized electrons, the metal cations can easily slide past one another without the crystal structure shattering. This ability of metal cations to slide past each other is known as plastic deformation, and it is a characteristic feature of metals.

The delocalized electrons act as a lubricant, reducing the resistance between the metal cations as they slide. This phenomenon allows metals to be malleable and ductile, meaning they can be bent, shaped, and drawn into wires without breaking.

It is important to note that during this process, there is no transfer of valence electrons from one metal atom to another. The delocalized electrons remain within the metal lattice, maintaining the metallic bonding. The movement of the valence electrons facilitates the flow of electrical current in metals, contributing to their high electrical conductivity.

In summary, when a metal is subjected to pressure, the metal cations easily slide past one another due to the presence of delocalized electrons. This property allows metals to be malleable and ductile, distinguishing them from other types of materials.

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momentum = mass x velocity

When know that:

momentum is 12 km m/s

Mass is 6 kg

Hence, velocity = 12/ 6 = 2m/s

The required mass of water vaporized is 15.5 grams, from a 250 gram sample of water at the boiling point had 35.0 kj

Given: Mass of water (m) = 250 gHeat added (q) = 35.0 kJHeat of vaporization (ΔHvap) = 40.6 kJ/mole

To find:Mass of water vaporized (x) Formula:q = ΔHvap × nx = (q / ΔHvap) × nMass = moles × molar mass

We know that molar mass of water (H2O) = 18 g/molMoles of water vaporized (n) = (35.0 kJ / 40.6 kJ/mol) = 0.861 mol

Therefore,Mass of water vaporized (x) = 0.861 mol × 18 g/mol= 15.5  

Detailed Solution: According to the given statement,250g of water was taken at its boiling point and 35.0 kJ of heat was added to it, we need to find how many grams of water were vaporized. To solve this question, first, we need to know the heat of vaporization for water, which is 40.6 kJ/mole. It means to vaporize 1 mole of water, 40.6 kJ of heat is required.

Mass of water (m) = 250 g Heat added (q) = 35.0 kJHeat of vaporization (ΔHvap) = 40.6 kJ/molen = q / ΔHvapn = (35.0 kJ / 40.6 kJ/mol) = 0.861 molMoles of water vaporized (n) = 0.861 mol

Therefore, Mass of water vaporized (x) = 0.861 mol × 18 g/mol= 15.5 g Hence, the required mass of water vaporized is 15.5 grams.

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Answer:

D.

Explanation:

In a shallow cylindrical lake with a radius of 4 km and an average water height of 5 m, a type A exhaust basin recorded a total water loss of 4.5 cm during a summer month.

The task is to calculate the evaporation of the lake and the volume of lake water in cubic meters for that specific time period, assuming an evaporation coefficient of 0.7. To calculate the evaporation of the lake, we first convert the recorded water loss from centimeters to meters. The total water loss is 4.5 cm, which is equal to 0.045 meters.

The evaporation from the lake can be determined by multiplying the water loss by the evaporation coefficient. In this case, the evaporation coefficient is given as 0.7. So, the evaporation from the lake is calculated as:

Evaporation = Water loss * Evaporation coefficient

Evaporation = 0.045 m * 0.7 = 0.0315 m

Therefore, the evaporation of the lake during the specified time period is 0.0315 cubic meters.To calculate the volume of lake water, we need to consider the shape of the lake, which is a shallow cylinder. The formula for the volume of a cylinder is:

Volume = π * radius^2 * height

Given that the radius of the lake is 4 km (4000 m) and the average water height is 5 m, we can calculate the volume of the lake as:

Volume = π * (4000 m)^2 * 5 m = 251,327,412 m^3

Therefore, the volume of lake water for the specific time period is approximately 251,327,412 cubic meters.

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Answer:

The actual sequence of steps which describe the life cycle of a lake is given below:

C. Runoff fills a depression - sediments build up

- water rises continuously

Explanation:

This is because, the water which builds up as a result of the runoff water accumulating on the depression helps towards building up. When it must have accumulated greatly, it ends up forming a lake.

The concentration of [Hg2+] is 2.02 x\(10^-11 M\) and the concentration of [I-] is 4.04 x\(10^{11}\). The concentration of [K+] in the solution is equal to its initial concentration, which is 0.05 M.

The solubility product constant expression for K2[HgI4] can be written as follows:

Ksp =\([Hg2+][I-]^2\)

We can use stoichiometry to determine the initial concentration of [Hg2+] and [I-] in the solution:

0.05 M K2[HgI4] = 0.05 M K+ = 0.025 M  \(HgI4^2-\)

From the formula of K2[HgI4], we can see that each mole of K2[HgI4] contains 2 moles of K+ and one mole of  \(HgI4^2-\)          . Therefore, the initial concentration of \(HgI4^2-\)is 0.025 M.

We can assume that x is the concentration of [Hg2+] and 2x is the concentration of [I-] that dissociates from  \(HgI4^2-\). Therefore, the equilibrium concentrations are:

[Hg2+] = x

[I-] = 2x

Using the solubility product constant expression and substituting the concentrations:

Ksp =\([Hg2+][I-]^2\)

1.48 x\(10^-30 = x(2x)^2\)

x = 2.02 x\(10^-11 M\)

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The citrate synthase-catalyzed phase must have significant favorable free power change so that it can contribute to the production of  high energy molecule, ATP, in order for citric acid cycle to function effectively.

A molecule is an object comprised of at least two atoms that are linked together chemically; the precise number of atomic nuclei that make up a molecule is known. One hydrogen atom gets joined to one halogen atom to form the molecule HCl(g), for instance. It is referred to as a diatomic molecule and has only two atoms.

This term was meant to cover its original definition, which was "the smallest quantity of a component that nevertheless keeps the properties of that substance." "An atom is a body that can't cut in two; a dime is the smallest conceivable component of a specific substance," wrote James Maxwell in 1873 when defining atom and molecule.

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Answer:

Find the chemical formulas of oxides that contain the following composition:

S:50%; C:42,8%; Mn:49,6%; Pb:86,6%

Explanation:

In the given oxide of sulphur,

50%S is present that means remaining 50% is O.

Divide the % with atomic mass:

S                                     O

50/32= 1.5625            50/16=3.125

divide with smallest ratio:

1.5625/1.5625=1              3.125/1.5625=2

Hence, the formula of oxide is \(SO_2\).

Similarly:

Carbon is 42.8% means the reamining % will be O that is 57.2%.

C                                                    O

42.8/12=3.575                         57.2/16=3.575

Divide with smallest ratio:

3.575/3.575=1                            3.575/3.575=1

Hence, the formula of oxide is CO.

Mn is 49.6% means the remining is % is O that is 50.4%.

First divide with atmic mass of respective element, then get the smallest ratio.

That gives the mole ratio of each constituent atom.

Mn                                 O

49.6/55.0=0.90            50.4/16=3.15

0.90/0.90=1                   3.15/0.90=3.5

Multiply with two

2                                        7

Hence, the formula becomes:

\(Mn_2O_7\)

Pb is 86.6% means ---remaining 13.4% is O.

Pb                                               O

86.6/207 = 0.418 mol                13.4/16=0.85

0.418/0.418=1                               0.85/0.418=2.0

Hence, the formula is:\(PbO_2\)  

The identity of the gas, given that 3.33 g occupies a volume of 1.365 L at 95 °C and 790 torr is chlorine gas (Cl₂)

First, we shall determine the number of mole of the gas. This is obtained as follow:

PV = nRT

1.039 × 1.365 = n × 0.0821 × 368

Divide both sides by (0.0821 × 368)

n = (1.039 × 1.365) / (0.0821 × 368)

n = 0.0469 mole

Finally, we shall determine the identity of the gas as follow:

Molar mass = mass / mole

Molar mass = 3.33 / 0.0469

Molar mass of gas = 71 g/mol

From the above calculation, we can see that the molar mass of the gas is 71 g/mol.

Thus, we can conclude that the identity of gas is chlorine gas (Cl₂) since:

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Answer:

New volume of gas = 95.93 ml (Approx)

Explanation:

Given:

Old volume of gas = 86 ml

Old temperature = 30°C = 30 + 273 = 303 K

New temperature = 65°C = 65 + 273 = 338 K

Find:

New volume of gas

Computation:

V1T2 = V2T1

(86)(338) = (V2)(303)

New volume of gas = 95.93 ml (Approx)

Answer:

Although the daytime length at the Equator remains 12 hours in all seasons, the duration at all other latitudes varies with the seasons. During the winter, daytime lasts shorter than 12 hours; during the summer, it lasts longer than 12 hours.

Explanation:

Maybe this answer is hopeful in your homework.

Answer:

i'm assuming you meant to say nonmetal atoms... in an ionic bond, electrons from the metal are transferred to the nonmetal. The reason why different numbers of metal and nonmetal atoms can combine is so their charges cancel out. take CaCl2 for example. There are two chlorine atoms for every calcium atom. If it was just CaCl, the charges wouldn't cancel out since calcium has a charge of 2+ and chlorine has a charge of 1-. Therefore to balance the compound, you need two chlorines.

Considering the solvents is NaOH that we used, the ether byproduct that we also produced in the kinetics experiment

Solvents is the liquid in which other material dissolve to form a solution and   it is possible to extract from organic layer using sodium hydroxide and it can react with NaOH and other are the functional group that cannot react so NaOH that we used, the ether byproduct that we also produced in the kinetics experiment and pure sodium hydroxide is a colorless crystalline solid that melt at 318°C without decomposition and with boiling point 1,388°C and it is highly soluble in water and in the kinetic experiment one determine the rate constant for the forward and reserve reaction

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When sulfuric acid is combined with sugar, gas is released and a tall black column forms. This is an example of a Dehydration Reaction.

A Dehydration reaction is defined as a chemical reaction that involves the loss of water from the reacting molecule or ion. Dehydration reactions is the reverse of a hydration reaction. Concentrated sulfuric acid can perform a dehydration reaction with table sugar. After mixing, the color changes from white to brownish and eventually to black. The expansion of the mixture is the result of vaporization of water and CO2 inside the container. The gases inflate the mixture to form a snake-like shape and give off a burned sugar smell. The granularity of the sugar can greatly affect the reaction. powdered sugar reacts very quickly but sugar cubes take longer to react.

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Answer:

satellite

Explanation:

found it on the internet

The correct answer is Radar

Answer:

3 moles H₂

Explanation:

The reaction equation Zn + 2HCl => ZnCl₂ + H₂ shows a 1:1 mole ratio between Zn and molecular hydrogen (H₁). Therefore, the moles of Zn consumed in the reaction is then equal to the moles of H₂ produced. In this case using 3 moles Zn => 3 moles H₂ will be produced.

Answer:

3 moles

Explanation:

Use the ratio

Yeah, I agree with the other person

Answer:

. 44.0 g/mol.

Explanation:

The phase diagram of water depicts the behavior of water with respect to temperature and pressure, showing the physical states of water: solid, liquid, and gas, at different points on the diagram. It is also known as the pressure-temperature phase diagram

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The p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.

Firstly, let us conduct a Chi-square test of independence of categorical variables based on the information given above. We have three different cases of hypothesis testing that we have to solve one by one.

Case 1: HD​:pSun ​=rhoMan ​=pTue ​=pWed ​=pThu ​=pFri ​=pSat ​=71​
Ha​ : Not all proportions are equal.

Test Statistic
For this hypothesis, we need to compute the test statistic that is given as:
\($$\chi^2=\sum_{i=1}^{k}\frac{(O_i-E_i)^2}{E_i}$$\)  where k is the number of groups/categories. Since we have 7 days of the week, \(k = 7. $O_i$ and $E_i$\) are the observed and expected frequencies respectively.  
Here, we have equal proportions of 71 for each day of the week.
Therefore, the expected frequencies are also equal to 71.
\($$E_i = 71, i=1,2,3,4,5,6,7.$$\)

We also have to use the given information to compute the observed frequencies,
\($O_i$.$$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126$$\)

Therefore, the test statistic can be computed as \($$\chi^2=\frac{(90-71)^2}{71} + \frac{(99-71)^2}{71} + \frac{(122-71)^2}{71} + \frac{(123-71)^2}{71} + \frac{(130-71)^2}{71} + \frac{(160-71)^2}{71} + \frac{(126-71)^2}{71}$$$$\chi^2=180.14\)

Now we have to find the p-value of this test. Since the number of degrees of freedom is k - 1 = 7 - 1 = 6, the p-value can be found using the chi-square distribution table with 6 degrees of freedom at the 0.05 significance level. The p-value is 0.000014. ConclusionSince the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.

The total number of accidents is \($$90+99+122+123+130+160+126=850$$\)

The percentage of accidents occurring on each day of the week can be found as follows:
\($$Sunday: $$\frac{90}{850}\times 100 = 10.59\%$$Monday: $$\frac{99}{850}\times 100 = 11.65\%$$Tuesday: $$\frac{122}{850}\times 100 = 14.35\%$$Wednesday: $$\frac{123}{850}\times 100 = 14.47\%$$Thursday: $$\frac{130}{850}\times 100 = 15.29\%$$Friday: $$\frac{160}{850}\times 100 = 18.82\%$$Saturday: $$\frac{126}{850}\times 100 = 14.82\%$$\)

From the above percentages, we can see that Friday has the highest percentage of traffic accidents.

Case 2:
HD​: Not all proportions are equal.

Ha​:pSun ​=pMon ​=pTue ​=rhoWed ​=pThu ​=rhoFri ​=rhoSat ​=71

Test Statistic

\($$E_1 = 78.57, E_2 = 86.57, E_3 = 106.86, E_4 = 107.43, E_5 = 113.57, E_6 = 139.43, E_7 = 109.14$$\)

We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)

The test statistic can be computed as:

\($$\chi^2=\frac{(90-78.57)^2}{78.57} + \frac{(99-86.57)^2}{86.57} + \frac{(122-106.86)^2}{106.86}+ \frac{(123-107.43)^2}{107.43} + \frac{(130-113.57)^2}{113.57} + \frac{(160-139.43)^2}{139.43} + \frac{(126-109.14)^2}{109.14} $$$$ \implies \chi^2=34.98$$\)
The p-value is 0.000001.
Conclusion- Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.

Case 3:

All proportions are equal.
Test Statistic
The expected frequency for each group is
\(E = \frac{850}{7} = 121.43\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)

The test statistic is,

\($$\chi^2=\frac{(90-121.43)^2}{121.43} + \frac{(99-121.43)^2}{121.43} + \frac{(122-121.43)^2}{121.43} + \frac{(123-121.43)^2}{121.43} + \frac{(130-121.43)^2}{121.43} + \frac{(160-121.43)^2}{121.43} + \frac{(126-121.43)^2}{121.43}} \\\implies \chi^2=9.17$$\)

The p-value is 0.1664.

Since the p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.

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The validity of the statements are as follows:
1. True

2. True

3. False

4. True

5. False

6. False

7. True

8. True

9. False

10. True

11. False

12. False

13. True

14. True

15. False

Food scientists are using techniques such as irradiation and pulsed electric field technology to extend the shelf-life of food, while artificial flavors can be created to mimic the taste of natural foods, as done by Givaudan, the world's largest flavorings manufacturer.

Here are the correct responses to the statements:

1. True: Bursts of high-voltage electricity can kill bacteria such as E. coli and salmonella.

2. True: Food scientists can copy the flavor of natural foods using artificial alternatives.

3. False: The shelf-life of food refers to how long the product can be stored before it becomes unfit for consumption, not the price.

4. True: Scientists refer to artificial flavor components as "nature identical chemicals."

5. False: The statement mentions that Givaudan has produced 200 synthetic flavors for strawberry, not 300 flavors for a real banana.

6. False: Bacteria like salmonella and E. coli are harmful and can cause food spoilage, so they do not extend the shelf-life of food.

7. True: Food manufacturers aim to extend food freshness to serve consumers and increase profits.

8. True: Pulsed electric field technology can give food a fresher appearance even for an extended period.

9. False: Synthetic flavors are not inherently natural; they are artificial.

10. True: Irradiation involves exposing a product to an acceptable level of gamma ray radiation.

11. False: A real banana has 225 natural flavor components, not 200.

12. False: The Swiss firm Givaudan is the world's biggest flavorings manufacturer but does not exclusively supply irradiated food.

13. True: Fresh foods exposed to bursts of high-voltage electricity can stay fresh longer.

14. True: Food companies invest significant funds in research to find ways to prolong the shelf-life of food.

15. False: The name of the vice president mentioned is Dr. Heini Menzi, not Dr. Heinz Menzi. The location mentioned is outside Zurich, not specifically in Zurich.

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Answer:

Carbon and phosphorus

Explanation:

The atoms of carbon and phosphorus are most likely to gain electrons from the given choices .

The reason for this is because, both carbon and phosphorus are non-metals. Most non-metals usually accept electrons.

Metals are usually electron donors .

Answer:

o cany give because of i am in 9th

Answer:

\(V_{2} = 29.28\,L\)

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

\(\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\)

\(V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)\)

\(V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)\)

\(V_{2} = 29.28\,L\)

1. I noticed that the soil particles settled out of the water with the larger, heavier particles settling out first and on the bottom, and each layer has smaller and lighter particles in it.

2. Sand settled on the bottom because they are heavier and have more mass than the smaller particles such as silt and clay.

3. Yes, this is a good way to determine particle size distribution. The method used in the experiment allows for the separation of soil particles based on their size and weight, which is a good indicator of their distribution in the soil sample.

4. The results in this experiment may look different when done in different locations because the particle size distribution of soil can vary depending on the location, climate, and geology of the area. Soils in different locations may have different compositions, including different amounts of sand, silt, and clay, which can affect the results of the experiment. Additionally, the sedimentation rate of the particles can also be influenced by factors such as the temperature, the presence of organic matter, and the presence of clay minerals, which can further affect the results.