Write the number 86,360,000 using the number word "million" and then round to one decimal place.

million
M

Answer:

This is gebber gabber but yes

Step-by-step explanation:

The people of Northern Africa used camel caravans, boats, and later on, the introduction of railways and modern road systems to travel from place to place for communication and trade.

In ancient times, camel caravans played a crucial role in facilitating trade and communication across the vast desert regions of Northern Africa. Camels were well-suited for traversing long distances in arid and challenging terrains, carrying goods and enabling merchants to travel between different trading centers.

These caravans played a vital role in connecting cities and facilitating the exchange of goods, ideas, and cultural influences.In coastal regions, maritime trade was prevalent, with boats and ships used for transportation. Coastal cities and ports served as important hubs for trade, linking Northern Africa with other regions through sea routes.

This maritime trade allowed for the movement of goods, including valuable commodities such as spices, textiles, and precious metals. With advancements in technology and infrastructure, modern transportation systems were introduced. Railways and road networks were established, enabling faster and more efficient travel across Northern Africa.

These developments further facilitated communication, trade, and economic integration within the region and beyond. Overall, the people of Northern Africa utilized camel caravans, maritime trade, and later modern transportation systems to travel from place to place, fostering communication and facilitating trade throughout the region.

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Answer:

One solution at (-4, -22)

Step-by-step explanation:

5x - y = 2

y = 5x - 2 --(1)

2x - 0.5y = 3 --(2)

sub (1) into (2):

2x - 0.5(5x - 2) = 3

2x - 2.5x + 1 = 3

-0.5x = 2

x = -4

when x = -4, y = 5(-4) - 2 = -22

The nature of the solution set to the system of equations are,

⇒ One solution at (-4,-22).

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The system of equations are,

5x - y = 2   .. (i)

2x - 0.5y = 3  .. (ii)

Now, We can simplify as;

From (i);

5x - y = 2

y = 5x - 2

Put above value in (ii);

2x - 0.5 (5x -2) = 3

2x - 2.5x + 1 = 3

- 0.5x = 2

x = - 4

From (i);

y = 5 × - 4 - 2

y = - 20 - 2

y = - 22

Thus, The nature of the solution set to the system of equations are,

⇒ One solution at (-4,-22).

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the final simplified expression is (36/37) + (23/37)j.To simplify the expression 39 - 37, we simply subtract the two numbers:

39 - 37 = 2

So, the simplified expression is 2.

To divide (5 + 6j) by (6 + j), we can use the complex division formula. Multiply the numerator and denominator by the conjugate of the denominator to rationalize the denominator:

(5 + 6j)(6 - j) / (6 + j)(6 - j)

Expanding and simplifying, we have:

(30 + 29j - 6j - 6j²) / (36 - j²)

Since j² is equal to -1, we can substitute -1:

(30 + 29j - 6j + 6) / (36 + 1)

Simplifying further, we get:

(36 + 23j) / 37

So, the final simplified expression is (36/37) + (23/37)j.

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If Station 1 (at 74, 41) is 44 km away and Station 2( at 0,43 ) is 38 km away. The required approximate location of the GPS receiver is (42, 10).

The location of the GPS receiver can be determined with the help of trilateration. Trilateration is a process of determining absolute or relative locations of points by measurement of distances, using the geometry of circles, spheres, or triangles. If three stations (or more) are in known locations, with a known distance from the point of interest, we can determine the position of the GPS receiver with the help of trilateration.

It can be determined by the following method:

1: Plot the given stations on a coordinate plane. Stations are:

Station 1: (74, 41)

Station 2: (0, 43)

2: Calculate the distance of the GPS receiver from each station using the distance formula.

Distance Formula: The distance formula is used to find the distance between two points in the coordinate plane. The distance between points (x1,y1) and (x2,y2) is given by

d = √[(x2 - x1)² + (y2 - y1)²]

Station 1: Distance from station 1 = 44 kmSo, d1 = 44 km

Station 2: Distance from station 2 = 38 kmSo, d2 = 38 km

3: Plot the given distances as the circle on the coordinate plane.

Circle 1: Centred at (74, 41) with a radius of 44 km.

Circle 2: Centred at (0, 43) with a radius of 38 km.

4: The intersection of two circles. Circle 1 and Circle 2 intersect at point P (approx) (42, 10). So, the approximate location of the GPS receiver is (42, 10).

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The width of the chest shaped like a rectangular prism, to the nearest tenth of an inch is 32.1.

Kenji has made a treasure chest, shaped like a rectangular prism that must hold around 10,368 cubic inches of sand. In the second act of the school play, an actor will stand on the chest.

Therefore, the chest must be 24 inches tall. The length of the chest is twice its width.

To determine the width of the chest, you should first determine the length of the chest.

Then, using the formula for the volume of a rectangular prism, you can solve for the width of the chest.

Length of the chest

The formula for the volume of a rectangular prism is V = lwh

Given that the chest needs to hold around 10,368 cubic inches of sand, we can write 10,368 = lwh

Since the chest is twice as long as it is wide, the length (l) of the chest is equal to 2w.

Substituting 2w for l, we have:

10,368 = (2w)w

hence 5,184 = wh²(5,184/h)

= w*h(5,184/h²) = w

Since the chest must also be 24 inches tall, we can write:

h = 24 feet

Substituting this value into the equation, we have:

(5,184/24²) = w

hence w = 32.1 inches

Therefore, the width of the chest to the nearest tenth of an inch is 32.1 inches.

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Answer:

2:40

Step-by-step explanation:

Short hand (hours): a little past 2

Long hand (minutes): 40 -- 8*5=40

Answer:

824/360 or 824:360

Step-by-step explanation:

quick mafs

Answer:824/360,p or 824:360 or 824 to 360

Answer:

Step-by-step explanation:

We can use trigonometry to solve this problem. Let's draw a right triangle to represent the situation:

        |\

        | \

   h    |  \   9 ft

        |   \

        |    \

        |     \

        -------

        6 ft

Here, h represents the height on the wall where the ladder touches. We want to find the angle of elevation θ.

Using the right triangle, we can write:

sin(θ) = h / 9

cos(θ) = 6 / 9 = 2 / 3

We can solve for h using the Pythagorean theorem:

h^2 + 6^2 = 9^2

h^2 = 9^2 - 6^2

h = √(9^2 - 6^2)

h = √45

h = 3√5

So, sin(θ) = 3√5 / 9 = √5 / 3. We can solve for θ by taking the inverse sine:

θ = sin^-1(√5 / 3)

θ ≈ 37.5 degrees

Therefore, to the nearest tenth of a degree, the angle of elevation the ladder makes with the ground is 37.5 degrees.

The mean of this probability distribution is 1.55.

To find the mean of a probability distribution, we need to multiply each possible value by its corresponding probability, and then add up these products. So, the mean is:

mean = (0)(0.19) + (1)(0.37) + (2)(0.16) + (3)(0.26) + (4)(0.02)
    = 0 + 0.37 + 0.32 + 0.78 + 0.08
    = 1.55

Therefore, the mean of this probability distribution is 1.55.

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Answer:

15 miles

Step-by-step explanation:

1 hour would be 7.5 miles an hour. So if you just add another one on then it'll be 15.

For an investment with completely certain returns, the return distribution would be a very tight, vertical line at the predetermined return. This is because the risk associated with the investment is zero, meaning the return will not vary regardless of market conditions.

For an investment with completely uncertain returns, the return distribution would be a flat line with no particular shape. This is because the risk associated with the investment is very high, meaning the return could be anything, as it is impossible to predict the returns with any degree of accuracy.

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Answer:

yea

Step-by-step explanation:

The statement is true. Multiplication is commutative, which means that the order of multiplication does not affect the result.

The statement "0 x 5 = 5 x 0" is true because of the commutative property of multiplication. In multiplication, the order of factors does not change the result.

When we multiply 0 by 5, it equals 0 since anything multiplied by 0 is 0. Similarly, when we multiply 5 by 0, the result is still 0. Both expressions are equal to 0, confirming the commutative property.

In summary, 0 x 5 and 5 x 0 are interchangeable and yield the same result, proving the truth of the statement based on the fundamental property of multiplication.

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Answer:

Step-by-step explanation:

You want three additional equivalent expressions to 6(3x +8) +32 +12x, one of which is the expression in simplest form.

Any expression you write along the path to simplifying the given expression will be an equivalent. Here's one way to get three different expressions:

  6(3x +8) +32 +12x . . . . . . given

  18x +48 +32 +12x . . . . . . eliminate parentheses

  30x +48 +32 . . . . . . . . . . combine x terms

  30x +80 . . . . . . . . . . . . . . combine constants (2 terms)

We can write another equivalent by factoring out a common factor:

  10(3x +8)

Farmer Ed has 3,000 meters of fencing and wants to enclose a rectangular plot that borders on a river.The largest area that can be enclosed is 750,000 square meters.

To get the largest area that can be enclosed, we have to find the dimensions of the rectangular plot. Let's assume that the width of the rectangle is x meters.The length of the rectangle can be found by subtracting the width from the total length of fencing available:L = 3000 - x. The area of the rectangle can be found by multiplying the length and width:Area = L × W = (3000 - x) × x = 3000x - x²To find the maximum value of the area, we can differentiate the area equation with respect to x and set it equal to zero.

Then we can solve for x: dA/dx = 3000 - 2x = 0x = 1500. This means that the width of the rectangle is 1500 meters and the length is 3000 - 1500 = 1500 meters.The area of the rectangle is therefore: Area = L × W = (3000 - 1500) × 1500 = 750,000 square meters. So the largest area that can be enclosed is 750,000 square meters.

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Answer:

x=(1)/(3),-(3)/(2)

Step-by-step explanation:

Answer:

(- 3/2, 1/3)

Step-by-step explanation:

7x^2+10x-3=x^2+3x

7x^2+10x-3-x^2-3x=0

6x^2+7x-3=0

6x^2+9x-2x-3=0

3x x (2x+3)-(2x+3)=0

(2x+3)x(3x-1)=0

2x+3=0

3x-1=0

x1=- 3/2

x2= 1/3

Answer:

See explanation

Step-by-step explanation:

The question is incomplete, as the diagram of coordinates of the three triangles are not given.

A general explanation is as follows:

First, record the coordinates of the corresponding points of the three triangles.

For instance; In triangles ABC, DEF and GHI; A, D and G are corresponding points.

Now, assume the coordinates are:

\(A = (1,1)\)

\(D = (1,5)\)

\(G= (-2,1)\)

Point D is 4 points to the right of A;

i.e.

\(D =(1,1+4) = (1,5)\)

Hence, ABC will be moved 4 units right to lie on DEF

Similarly, point G is 3 units down of A

i.e.

\(G =(1-3,1) = (-2,1)\)

Hence, ABC will be moved 3 units down to lie on GHI.

Answer:

67

Step-by-step explanation:

Answer:

\(x=\frac{y-3}{4}\)

Step-by-step explanation:

\(y=4x+3\)

\(y-3=4x\)

\(\frac{y-3}{4}=x\)

\(x=\frac{y-3}{4}\)

Answer:

\(\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}\)

\(y = 4x + 3 \\ y - 3 = 4x \\ \frac {y - 3}{4} = x \)

⎆ The formula will be \(\hookrightarrow\boxed{\underline\frac {y - 3}{4}=x}\)

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ RainbowSalt2²2² ࿐

The volume of the solid generated by revolving the region in the first quadrant bounded by the coordinate axes, the curve y = e^-x and the line x = 8 about the line x = 8 is approximately 1483.6 cubic units.

To find the volume of the solid generated by revolving the region in the first quadrant bounded by the coordinate axes, the curve y = e^-x and the line x = 8 about the line x = 8, we can use the method of cylindrical shells.

To find the volume of the solid, we need to integrate the area of each cylindrical shell over the height of the solid. Let r be the radius of a cylindrical shell at height y, and let h be the thickness of the shell. Then the volume of the shell is given by:

dV = 2πrh × h

where the factor of 2 comes from the fact that there are two cylindrical shells (one on either side of the line x = 8).

We can express r and h in terms of y:

r = 8 - y

h = e^8 - e^-x

Substituting these expressions into the formula for dV and integrating from y = 0 to y = 1, we get,

V = ∫(0 to 1) 2π(8 - y)(e^8 - e^-x) dy

= 2π ∫(0 to 1) (8e^8 - 8e^-x - ye^8 + ye^-x) dy

= 2π [8e^8 - 8e^-1 - (1/2)e^8 + (1/2)e^-1]

= 2π [15e^8 - 4e^-1]

≈ 1483.6 cubic units

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The given question is incomplete, the complete question is:

Find the volume of the solid generated by revolving the region in the first quadrant bounded by the coordinate axes, the curve y = e^-x and the line x = 8 about the line x = 8.

Explanation: Since the y moves to the right 2, then it changes from 0 to 2.

Answer:

c

Step-by-step explanation:

edge 2020

Answer:

Let "b" be the total bill before the tip.

The tip was 18% of the bill, or 0.18 * b.

The tip was also $4.50, so we can set up the equation 0.18b = $4.50.

Solving for b, we get:

0.18b = $4.50

b = $4.50 / 0.18

b = $25

Therefore, Sierra's total bill before the tip was $25.

The probability that all seven selected eggs are cracked can be calculated as follows:

The total number of ways to select 7 eggs from a carton of 19 is given by the binomial coefficient, which is denoted as C(19, 7). This can be calculated as:

C(19, 7) = 19! / (7! * (19 - 7)!)

where "!" represents the factorial of a number.

Next, we need to consider the number of ways to select 7 cracked eggs from the 5 available. This can be represented as C(5, 7) = 5! / (7! * (5 - 7)!), which simplifies to 0 since there are only 5 cracked eggs available.

Therefore, the probability of selecting all seven cracked eggs is 0, as there are not enough cracked eggs to fulfill the selection requirement.

The probability that all seven selected eggs are cracked is 0, as there are only 5 cracked eggs available in the carton.

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The solution to the variables using equations 1, 2 and 3 is x = 2, y = -1 and z = 3 and the solutions in part b hold for equation 4

There are three variables in the system

To solve the three variables, there must be at least three equations in the system of equations

Hence, the variables cannot be solved because the number of equations is not enough

We have:

3x + z + y = 8

5y - x = -7

3z + 2x - 2y = 15

Make x the subject in (2)

x = 5y + 7

Substitute x = 5y + 7 in (1) and (3)

3(5y + 7) + z + y = 8

15y + 21 + z + y = 8

16y + z = -13

3z + 2(5y + 7) - 2y = 15

3z + 10y + 14 - 2y = 15

3z + 8y = 1

Multiply 16y + z = -13 by 3

48y + 3z = -39

Subtract 3z + 8y = 1 from 48y + 3z = -39

48y - 8y + 3z - 3z = -39 - 1

40y = -40

Divide by 40

y = -1

Substitute y = -1 in x = 5y + 7

x = 5(-1) + 7

x = 2

Make z the subject in 16y + z = -13

z = -13 - 16y

Substitute y = -1

z = -13 - 16(-1)

z = 3

Hence, the solution to the variables using equations 1, 2 and 3 is x = 2, y = -1 and z = 3

We have:

4x + 5y - 2z = -3

Substitute x = 2, y = -1 and z = 3

4(2) + 5(-1) - 2(3) = -3

Evaluate

-3 = -3 --- this is true

Hence, the solutions in part b hold for equation 4

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Missing part of the question

The following equations are given:

Equation #1: 3x + z + y = 8

Equation #2: 5y - x = -7

Equation #3: 3z + 2x - 2y = 15

Equation #4: 4x + 5y - 2z = -3

The simplified form of the expression 3(w +1) + 4(2w0 + 3) is 3w + 8w0 + 15.

Simplification is the process of reducing or expressing a complex expression or equation in a simpler form. In mathematics, simplification is often used to make calculations easier, to find solutions to problems, or to gain a better understanding of a mathematical concept. Simplification involves the use of various algebraic properties and techniques to transform an expression into an equivalent, but simpler, form. These techniques include combining like terms, factoring, expanding, using the distributive property, and simplifying fractions, among others. The goal of simplification is to make a mathematical expression or equation more manageable and easier to work with.

To simplify the expression 3(w +1) + 4(2w0 + 3), we need to use the distributive property and simplify the terms as follows:

3(w +1) + 4(2w0 + 3) = 3w + 3 + 8w0 + 12 (distributing 3 and 4)

= 3w + 8w0 + 15 (combining like terms)

Therefore, the simplified form of the expression 3(w +1) + 4(2w0 + 3) is 3w + 8w0 + 15.

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Answer:

D) 900 in.3

Step-by-step explanation:

Volume = (base area)^2 times (height divided by 3)

300^2 * 3/3

Answer:

its b

Step-by-step explanation:

It seems like you have a question related to logistic population growth. I'll address each part of your question using the terms you provided.

(a) In the logistic equation, the carrying capacity is the maximum population that the environment can sustain indefinitely. It is represented by the variable K in the equation. To determine the value of K, we would need the specific equation you are working with. The same goes for the value of any other variable.

(b) In a direction field for the logistic equation, slopes close to 0 typically occur when the population is close to either 0 or the carrying capacity (K). Slopes are largest when the population is at half of the carrying capacity (K/2). Solutions with increasing population are represented by positive slopes, while solutions with decreasing population are represented by negative slopes.

Please provide the specific equation you are working with if you need more detailed information.

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As p-value is less than the typical significance level of 0.05 so there is evidence that after training, players can throw strikes more than 60% of the time. There is no evidence that the training is effective in improving a player's ability to throw strikes because  p-value is greater than the typical significance level of 0.05.

To test whether there is evidence that after training, players can throw strikes more than 60% of the time, we will use a one-sample proportion test. First, we need to calculate the proportion of strikes thrown after training

Number of strikes after training = 35+36+32+28+30+31+32+34+35+36+33+35+32+33+33+34+37+33+35+32 = 656

Total number of pitches after training = 20*50 = 1000

Proportion of strikes after training = 656/1000 = 0.656

Next, we need to calculate the standard error of the proportion

Standard error = sqrt((proportion * (1 - proportion)) / sample size) = sqrt((0.656 * (1 - 0.656)) / 1000) = 0.024

Finally, we can calculate the test statistic using the following formula

Test statistic = (proportion - hypothesized proportion) / standard error = (0.656 - 0.60) / 0.024 = 2.5

Using a standard normal distribution table, we can find the p-value associated with a test statistic of 2.5 to be approximately 0.0062. Since this p-value is less than the typical significance level of 0.05, we can conclude that there is evidence that after training, players can throw strikes more than 60% of the time.

To test whether there is evidence that the training is effective in improving a player's ability to throw strikes, we will use a paired sample t-test.

We will calculate the difference in the number of strikes thrown before and after training for each player, and then calculate the mean and standard deviation of these differences.

The differences in the number of strikes are

7, 7, 2, -4, -2, -1, 0, 2, 3, 3, 0, 2, -2, -1, -1, -1, 1, -3, -2, -5

The mean of the differences is

mean = sum of differences / number of differences = 20 / 20 = 0

The standard deviation of the differences is

standard deviation = sqrt(sum of (difference - mean)^2 / (number of differences - 1)) = sqrt(91 / 19) = 2.30

The t-statistic is calculated as

t = mean / (standard deviation / sqrt(number of differences)) = 0 / (2.30 / sqrt(20)) = 0

Using a t-distribution table with 19 degrees of freedom (since there are 20 pairs of differences), we find the p-value associated with a t-statistic of 0 to be approximately 1.0.

Since this p-value is greater than the typical significance level of 0.05, we cannot reject the null hypothesis that there is no difference in the mean number of strikes thrown before and after training. Therefore, we do not have evidence that the training is effective in improving a player's ability to throw strikes.

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The value of y in \(-3 = 7\left(y-\dfrac97\right)\) is 6/7

The equation is given as:

\(-3 = 7\left(y-\dfrac97\right)\)

Open the bracket

-3 = 7y - 9

Add 9 to both sides of the equation

7y = 6

Divide both sides by 7

y= 6/7

Hence, the value of y in \(-3 = 7\left(y-\dfrac97\right)\) is 6/7

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Complete question

Solve for y

\(-3 = 7\left(y-\dfrac97\right)\)