Can anyone help me with this portfolio?


6. 9. 4 - Portfolio Item: Linear Functions Unit Portfolio

Course: Algebra 1 A (CL), 5. 18, D 20/21 (3)

49 tiles will be needed to cover the floor.

A square is a shape having equal sides. The area of a square is expressed as:

A = L²

Where L is the side length of a square.

If a square tile has a side length of x²y units, the area of the square tile will be:

A = (x²y)²

A square = x⁴y² units²

Similarly, if a quart floor has a side length of 7x⁵y⁶ units. The area of the quart floor will be expressed as:

A quart = (7x⁵y⁶)²

A quart = 49x¹⁰y¹²

Divide both areas to get the number of tiles that will cover the floor

Number of tiles = 49x¹⁰y¹²/x⁴y²

Number of tiles = 49x⁶y¹⁰

Thus, this shows that about 49 tiles will be needed to cover the floor.

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a. The probability that two or fewer will withdraw is 0.2614.

b. The probability that exactly four will withdraw is 0.1342.

a. To compute the probability that two or fewer will withdraw, we can use a binomial probability distribution. The probability of success is 0.2 since 20% of the students are expected to withdraw.

Since two or fewer successes is the same as two successes, we can calculate the probability of two successes as: P(X = 2) = 20C2 * 0.2^2 * 0.8^18, which comes out to 0.2614.

b. To compute the probability that exactly four will withdraw, we can use the same binomial probability distribution. We can calculate the probability of four successes as P(X = 4) = 20C4 * 0.2^4 * 0.8^16, which comes out to 0.1342.

c. To compute the probability that more than three will withdraw, we can use the same binomial probability distribution. We can calculate the probability of four or more successes as 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3). This comes out to 0.8994.

d. To compute the expected number of withdrawals, we can use the same binomial probability distribution. The expected number of successes (withdrawals) is the probability of success multiplied by the number of trials, which is 20 in this case. Therefore, the expected number of withdrawals is 20 * 0.2 = 4.

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The complete question is attached below.

Answer:

Step-by-step explanation:

so we know 3w = L + 5

and then we know that 2w + 2L = 194

so those are our two equations

since we have L by itself in the first equation, we are going to move the 5

L = 3w - 5

so now we can plug that in as L in the second equation

2w + 2(3w - 5) = 194

so now we distribute that 2

2w + 6w - 10 = 194

then simplify

8w - 10 = 194

then add the 10 to the other side

8w = 204

then we divide the 8

we get w = 25.5

so now we take that and go all the way back and plug that into the othr equation (ik this is a lot)

L = 3w - 5

so we plug in what we got for w

L = 3(25.5) -5

then multiply

L = 76.5 - 5

L = 71.5

so we end up with

w = 25.5 and L = 71.5

have a great day!! <3

Answer:

we know that

area of the circle is equal to

A=pi* r^{2}A=pi∗r

2

solve for r

r= \sqrt{ \frac{A}{pi}}r=

pi

A

for A=60 cm^{2}60cm

2

r= \sqrt{ \frac{60}{pi}} cmr=

pi

60

cm

we know that

\begin{gathered} \sqrt{60} = \sqrt{ 2^{4}*3*5} \\ =2 \sqrt{15} \end{gathered}

60

=

2

4

∗3∗5

=2

15

so

\sqrt{ \frac{60}{pi}}=2 \sqrt{ \frac{15}{pi}}

pi

60

=2

pi

15

2 \sqrt{ \frac{15}{pi}}=2 \frac{ \sqrt{15}}{ \sqrt{pi}} * \frac{ \sqrt{pi}}{ \sqrt{pi}}2

pi

15

=2

pi

15

∗

pi

pi

=2 \frac{ \sqrt{15pi}}{pi} cm=2

pi

15pi

cm

the answer is

2 \frac{ \sqrt{15pi}}{pi} cm2

pi

15pi

cm

True. Parametric tests are a category of statistical tests that can only be applied to data that meets certain criteria.

They make use of normal distribution assumptions when analyzing data, which means that a significant proportion of the data must follow a normal distribution for the test to produce valid outcomes

.A sample is a subset of the population that is being examined. The size of the sample has an impact on the accuracy of the study. If the sample size is insufficient, it may not be representative of the entire population. In small sample sizes, the main assumptions of parametric tests may be violated, and the results of the test may be skewed.

A sample is a group of individuals or objects from a population that are chosen for a study. The size of the sample is critical since it has a direct impact on the statistical accuracy of the data. A small sample size can cause the primary assumptions of parametric tests to be broken.

Parametric tests are a type of statistical test that can only be used with specific kinds of data. When parametric tests are used to evaluate data, it is assumed that the data follows a normal distribution. In general, this means that the data should be symmetric around the mean, with the majority of the data values being near the mean and fewer outliers. However, when the sample size is small, the accuracy of these assumptions may be in doubt.

As a result, it's crucial to ensure that you choose the proper statistical test based on the size of your sample and the distribution of your data.

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Step-by-step explanation:

3/8 = 15/40= 75/200

2/5 = 16/40 = 80/200

-> 4 rational numbers between 75/200 and 80/200 are 76/200, 77/200, 78/200, 79/200

Answer:

6,000 or 6 hundredths

Step-by-step explanation:

The calculated value of n in the cube with the given properties is 5

If we cut the original cube into smaller cubes of side length 1 unit, then the total number of smaller cubes is given by the formula:

Total number of smaller cubes = (number of cubes along each edge of the original cube)^3 = n^3

So, we have

n^3 = 125

Take the cube root of both sides

n = 5

Hence, the value of n is 5

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1. a function that could be used to model the data in the table. Make sure to use h for height and d for distance is d = -0.425h + 39.25

2. If the balloon is 800 meters high,  the farthest distance that you would be able to see is  48 km

3. at the  height  of  67 does the balloon have to rise for the building to be visible.

The table in the question shows a relationship between the height of a balloon and the distance away from the balloon that can be seen. Using this data, a linear function can be determined that models this relationship. The function is d = -0.425h + 39.25, where h is the height of the balloon in meters and d is the distance in kilometers. Using this function, if the balloon is 800 meters high, the farthest distance that can be seen is 48 km, which is the y-intercept of the equation.

Inversely, if a building is 16 km away from the balloon, the height the balloon must rise for the building to be visible is 67 m. This can be determined by substituting 16 for d in the equation and solving for h.   Overall, the linear function d = -0.425h + 39.25 models the relationship between the height of the balloon and the distance away from the balloon that can be seen. The equation can be used to determine the height of the balloon needed to see a certain distance or the distance away from the balloon that can be seen when the balloon is at a certain height.

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Height in meters 15 30 45 60 75 90 105 , Distance in kilometers 13.833 19.562 23.959 27.665 30.931 33.833 36.598

1. Determine a function that could be used to model the data in the table. Make sure to use h for height and d for distance.

2. If the balloon is 800 meters high, what is the farthest distance that you would be able to see? Round the answer to the nearest whole number

3. Round answer to the nearest whole number A building is 16 km away. What height does the balloon have to rise for the building to be visible?

The charge contained in a section of the line of length 2.80 depends on the charge density of the line. The charge density is the amount of charge per unit length. To find the charge contained in a section of the line of length 2.80, you need to multiply the charge density by the length of the section.

For example, if the charge density of the line is 3 coulombs per meter, then the charge contained in a section of the line of length 2.80 meters is:

Charge = Charge density × Length
Charge = 3 coulombs/meter × 2.80 meters
Charge = 8.4 coulombs

Therefore, the charge contained in a section of the line of length 2.80 is 8.4 coulombs.

I hope this helps! Let me know if you have any further questions.

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Answer:

THE THE YON 21 70 10 12030

a) H1 student hasn't cheated on an test, H2 Student has cheated on an test

b) the student hasn't cheated, but got indicted of cheating

c) the student cheated, but got down with it, and

d) Type 1 error as it indicted of cheating and thus failed the class, fully innocent.

Since we want to examine whether the pupil has cheated on an test, we will test

H1 student hasn’t cheated on an test

H2 Student has cheated on an test

Flash back that the Type 1 error occurs when the null thesis is true, but we conclude that we can reject it.

In this environment, a Type 1 error would be made when the pupil hasn't cheated on an test, but we reject that statement and conclude that he has cheated on the test.

This is actually the case of" chastising the innocent", and the consequence is that the pupil will fail the course, indeed though he did nothing wrong.

Flash back that the Type 2 error occurs when the indispensable thesis is true, but we can not reject the null thesis in favor of the indispensable thesis.

In this environment, a Type 2 error would be made when the pupil actually cheated on an test, but the data that we gathered still show that it's inconclusive whether or not he cheated, i.e. we conclude that we can not reject the possibility that he hasn't cheated on the test.

This is the case of" releasing the shamefaced", and the consequence is that the pupil" got down" with cheating with no discipline.

A Type 1 error is clearly much more serious, because it would mean that the pupil did nothing wrong, but was indicted of cheating and thus failed the class, fully innocent.

thus, a) H1 Pupil hasn't cheated on an test, H2 Student has cheated on an test

b) the student hasn't cheated, but got indicted of cheating

c) the student cheated, but got down with it, and

d) Type 1 error

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The speed of the moving body that is being referred to here is 80 kilometer per hour.

The given problem is a straightforward one based on the idea of the universal law of motion. According to the universal law of motion, any uniformly traveling body's distance traveled is determined by the product of its speed and the time elapsed. Distance is calculated as speed * time. Therefore the body is going at a speed of 80 kilometers per hour, according to the same relation as above, assuming that it is moving at a constant speed.

                                \(Distance = speed * time\)

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Answer:

66 x+6

Step-by-step explanation:

Because you add from the x's then you go on from the hope this helped :) .

\(1.04 \times {10}^{10} = \)

\(104 \times {10}^{ - 2} \times {10}^{10} = \)

\(104 \times {10}^{8} = \)

\(10400000000\)

_________________________________

And we're done.

Thanks for watching buddy good luck.

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The ladder touches the wall at a height of approximately 9.2 feet above the ground.

We can use the Pythagorean theorem to solve this problem. The theorem states that in a right triangle, the square of the length of the hypotenuse (the longest side, which is the ladder in this case) is equal to the sum of the squares of the lengths of the other two sides (the distance from the wall and the height of the ladder on the wall).

Let's call the distance from the wall "x" and the height of the ladder on the wall "h". Then we have:

\(x^2 + h^2 = 14^2\)

We also know that the bottom of the ladder is placed 3 feet from the wall, so we have:

x + 3 = 14

Solving for x, we get:

x = 11

Substituting this value into the first equation, we get:

\(11^2 + h^2 = 14^2\)

Simplifying and solving for h, we get:

\(h = \sqrt{(14^2 - 11^2)}\)

h ≈ 9.2

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Answer: Let us call the centers of the four circles C1, C3, C5, and C7, respectively, where the subscript refers to the radius of the circle. Without loss of generality, we can assume that the tangent point A lies to the right of all the centers, as shown in the diagram below:

                 C7

          o-----------o

       C5 /             \ C3

         /               \

        o-----------------o

                C1

                |

                |

                | l

                |

                A

Let us first find the coordinates of the centers C1, C3, C5, and C7. Since all the circles are tangent to line l at point A, the centers must lie on the perpendicular bisector of the line segment joining A to the centers. Let us denote the distance from A to the center Cn by dn. Then, the coordinates of Cn are given by (an, dn), where an is the x-coordinate of point A.

Using the Pythagorean theorem, we can write the following equations relating the distances dn:

d1 = sqrt((d3 - 2)^2 - 1)

d3 = sqrt((d5 - 4)^2 - 9)

d5 = sqrt((d7 - 6)^2 - 25)

We can solve these equations to obtain:

d1 = sqrt(16 - (d7 - 6)^2)

d3 = sqrt(4 - (d7 - 6)^2)

d5 = sqrt(1 - (d7 - 6)^2)

Now, let us consider the region S that lies inside exactly one of the four circles. This region is bounded by the circle of radius 1 centered at C1, the circle of radius 3 centered at C3, the circle of radius 5 centered at C5, and the circle of radius 7 centered at C7. Since the circles are all tangent to line l at point A, the boundary of region S must pass through point A.

The maximum possible area of region S occurs when the boundary passes through the centers of the two largest circles, C5 and C7. To see why, imagine sliding the circle of radius 1 along line l until it is tangent to the circle of radius 3 at point B. This increases the area of region S, since it adds more points to the interior of the circle of radius 1 without removing any points from the interior of the other circles. Similarly, sliding the circle of radius 5 along line l until it is tangent to the circle of radius 7 at point C also increases the area of region S. Therefore, the boundary of region S must pass through points B and C.

Using the coordinates we obtained earlier, we can find the x-coordinates of points B and C as follows:

x_B = a - 2 - sqrt(9 - (d7 - 6)^2)

x_C = a + 6 + sqrt(9 - (d7 - 6)^2)

To maximize the area of region S, we want to maximize the distance BC. Using the distance formula, we have:

BC^2 = (x_C - x_B)^2 + (d5 - d3)^2

Substituting the expressions we derived earlier for d3 and d5, we get:

BC^2 = 32 - 2(d7 - 6)sqrt(9 - (d7 - 6)^2)

To maximize BC^2, we need to maximize the expression inside the square root. Let y = d7 - 6. Then, we want to maximize:

f(y) = 9y^2 - y^4

Taking the derivative of f(y) with respect to y and setting it equal to zero, we get:

f'(y) = 18y - 4y^3 = 0

This equation has three solutions: y = 0, y = sqrt(6)/2, and y = -sqrt(6)/2. The only solution that gives a maximum value of BC^2 is y = sqrt(6)/2, which corresponds to d7 = 6 + sqrt(6)/2.

Substituting this value of d7 into our expressions for d1, d3, and d5, we obtain:

d1 = sqrt(16 - (sqrt(6)/2)^2) = sqrt(55/2)

d3 = sqrt(4 - (sqrt(6)/2)^2) = sqrt(19/2)

d5 = sqrt(1 - (sqrt(6)/2)^2) = sqrt(5/2)

Using these values, we can compute the coordinates of points B and C as follows:

x_B = a - 2 - sqrt(9 - (sqrt(6)/2)^2) = a - 2 - sqrt(55)/2

x_C = a + 6 + sqrt(9 - (sqrt(6)/2)^2) = a + 6 + sqrt(55)/2

The distance between points B and C is then:

BC = |x_C - x_B| = 8 + sqrt(55)

Finally, the area of region S is given by:

Area(S) = Area(circle of radius 5 centered at C5) - Area(circle of radius 7 centered at C7)

= pi(5^2) - pi(7^2)

= 25pi - 49pi

= -24pi

Since the area of region S cannot be negative, the maximum possible area is zero. This means that there is no point that lies inside exactly one of the four circles. In other words, any point that lies inside one of the circles must also lie inside at least one of the other circles.

Step-by-step explanation:

Answer:

77

Step-by-step explanation:

11•7=77

you multiply it because Scott read 11 pages each day for 1 week. And since it is 7 days not 2, it is faster to just multiply. And since 1•7=7 then you just multiply 7 by 11 and it is shown to be 77.

In a multiple regression model, the variance of the error term e is assumed to be the same for all values of the independent variable. Therefore, the correct option is C) the same for all values of the independent variable.

In multiple regression, we use several independent variables to predict the values of the dependent variable. The model estimates the relationship between the independent variables and the dependent variable by calculating the coefficients of the independent variables.

The error term e represents the difference between the predicted value of the dependent variable and the actual value of the dependent variable.

The assumption of constant variance of the error term e is known as homoscedasticity. It means that the variance of the errors is the same for all levels of the independent variables.

This assumption is important because, if the errors have different variances across the levels of the independent variable, the model may not accurately capture the relationship between the independent variables and the dependent variable, leading to biased and unreliable results. so, the correct answer is C).

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Solution

Step 1

A)The domain refers to all values of x for which the function remains defined. Any value of x that makes the function undefined is out of the domain. This can be achieved by factorizing the denominator of the known function to get the values of x that make the function undefined. All other values of x that make the function defined are part of the domain.

Step 2

B)Factorize the denominator

Hence factorizing further we will have

Hence, the domain of the function given is all real values of x except -3 and 5/6

The translation 1 unit left of f ( x ) =–7x+10  then g(x) is -7x + 3.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in its range(involving values of y) or in its domain(involving values of x).

The up and down movements are in the vertical direction by the y coordinate.

The left and right movements are in the horizontal direction by the x coordinate.

When translating a graph, adding units moves the graph to the left, and eliminating units moves the graph to the right.

hence we say that;

f(x) = –7x+10

g(x) = f(x + 1)

= –7(x + 1)+10

= -7x - 7 + 10

= -7x + 3

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With regard to the similar triangles,

In ΔACD

BE ∥ CD

In ΔACD and ΔABE

BE ∥ CD

∠ACD =∠ABE           (corresponding angles)

∠ADC = ∠AEB          (corresponding angles)

∠A = ∠A                    (common angle)

ACD ∼ ΔABE

So,  The corresponding sides are in proportion.

Now, find ED

AB/BC = AE/ED
ED = AE (BC/AB)
ED = 26(5/20)
ED = 6.5cm


For BE

AB/AC = BE/CD
BE = CD (AB/AC)
BE = 18 (20/25)
BE  = 14.4cm

Now, find BE

Therefore, the length of ED is 6.5cm and the length of BE is 14.4 cm.

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Answer:

y=2/3x-7

Step-by-step explanation:

For lines to be parallel, they must have the same slope which is 2/3. However, they can't have the same y-intercept.

A "required parameter" requires an assigned value for the argument used to call the method, while "optional parameters" do not need to be included in the method call and have a default value assigned to them.

The type of parameter that requires that the argument used to call the method must have an assigned value is a "required parameter".

Required parameters are parameters that must be included in the method call, and the argument passed for the required parameter must have a value assigned to it. If a required parameter is not included in the method call, or if the argument passed for the required parameter does not have a value assigned to it, an error will be thrown.

In contrast, there are also optional parameters, which are parameters that do not need to be included in the method call. If an optional parameter is not included in the method call, the method will use a default value assigned to the parameter.

In many programming languages, the syntax for specifying required and optional parameters in a method or function call is specified using different symbols, such as parentheses or square brackets.

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Answer:

8n-10=30 n=5

8n-10=30 n=5

Answer:

8n-10=30

n=5

8(5)-10

40-10=30

n=5

Answer:

\(Cost \ total= \$ 1755\)

Step-by-step explanation:

Find the total cost of a rectangular shaped carpet, given the carpets length,  width, and the cost of carpet per square foot. Using the formula for the area of a rectangle.

\(\boxed{\left\begin{array}{ccc}\text{\underline{Area of a Rectangle:}}\\\\A=l \times w\end{array}\right}\)

Where...

Given:

\(l=15 \ ft\\w=9 \ ft\\ 1 \ ft^2= \$ 13\)

Find:

\(Cost \ total = \ ?? \\)

(1) - Calculating the total area of the carpet, which is a rectangle

\(A=l \times w\\\\\Longrightarrow A=15 \ ft \times 9 \ ft\\\\\therefore \boxed{A=135 \ ft^2}\)

(2) Calculate the total cost of the carpet by multiplying the total area of the carpet by the cost of one square foot of carpet

\(Cost \ total=135 \ ft^2 \times \$ 13\\\\\therefore \boxed{\boxed{Cost \ total= \$ 1755}}\)

Thus, the total cost of the carpet is found.

The required perimeter of the door on the scale drawing is 4 cm, which is option A.

Perimeter is the measure of the figure on its circumference.

Here,
To find the perimeter of the door on the scale drawing, we need to first find the dimensions of the door on the scale drawing. We can use the scale 2:8 to convert the actual dimensions of the door to the corresponding dimensions on the scale drawing:

Height on scale drawing = (2/8) x 5 cm = 1.25 cm

Width on scale drawing = (2/8) x 3 cm = 0.75 cm

The perimeter on the scale drawing = 2 x (height on scale drawing + width on scale drawing)

Perimeter on scale drawing = 2 x (1.25 cm + 0.75 cm)

Perimeter on scale drawing = 2 x 2 cm

The perimeter on the scale drawing = 4 cm

Therefore, the perimeter of the door on the scale drawing is 4 cm, which is option A.

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The required final answer is option a) Incentre

The point of concurrency of the angle bisectors of a triangle is known as the "Incentre".

It is the center of the circle inscribed within the triangle, which is equidistant from all three sides of the triangle.

The incentre is the point where the angle bisectors of a triangle intersect, forming the incircle, which is the largest circle that can be inscribed inside the triangle.

The incentre is always within the triangle and is equidistant from all three sides of the triangle, making

it a useful tool in construction and design applications. In summary, the incentre is the center of the incircle of a triangle, and it is the point where the angle bisectors of the triangle intersect.

Thus, required answer is "Incentre".

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Answer: Refer to Below

Step-by-step explanation:

Given information

Php 2,000 activation fee

Php 1,500 monthly fee

Analysis of given information

Activation fee: the amount of money to start a charge (i.e. Let's say if there is a membership, then this fee would be the same as having a card of membership)

Monthly fee: the amount of money that would be charged monthly (i.e. Let's say if there is a membership, then this fee would be the amount of money that you would need to pay for maintenance every month)

Set variable according to the given information

Let x be the number of months for the membership

Write expression with the given information and the variable

Cost = Monthly fee × Number of months + Activation fee

\(\boxed{C = 1500x + 2000}\)

**Information** Since we have already written the expression in [PART 1] and defined the number of months as [x], we are going to substitute the given number of months into the expression.

Given information

Number of months = 1, 2, 3, 4, 5, 6

Written expression from [PART 1]

C = 1500x + 2000

Substitute values into the expression

1 month = 1500 (1) + 2000 = \(\boxed{Php 3500}\)

2 months = 1500 (2) + 2000 = \(\boxed{Php 5000}\)

3 months = 1500 (3) + 2000 = \(\boxed{Php 6500}\)

4 months = 1500 (4) + 2000 = \(\boxed{Php 8000}\)

5 months = 1500 (5) + 2000 = \(\boxed{Php 9500}\)

6 months = 1500 (6) + 2000 = \(\boxed{Php 11000}\)

Hope this helps!! :)

Please let me know if you have any questions