Answers
Answer:
No, superconductors cannot conduct at 0 Kelvin's.
Related Questions
As water has a higher ___________________, we can assume that land will heat and cool faster than water.
Answers
Water enhance living activity, as water has a higher specific heat capacity,
we can assume that land will heat and cool faster than water.
What is water?Water is a liquid with no color, taste and odour. The sea, rivers, streams are made of water.
Water has more heat capacity, it has the tendency to absorb heat to itself and it takes a longer time to cool off, while land or soil takes a shorter time to cool.
Therefore ,As water has a higher specific heat capacity we can assume that land will heat and cool faster than water
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You threw a ball straight up into the air at 7.34m/s. How high does the ball go?
Answers
Answer:
7.34x
Explanation:
Depends on how long it was in the air. 7.34x, x is how many seconds.
If a car has a suspension system with a force constant of 5.00x104 N/m, how much energy must the car's shocks remove to dampen an oscillation starting with a maximum displacement of 0.0750 m
Answers
Answer: 140.625
Explanation: Because energy gained due to damped motion and needs to be absorbed
An object is thrown down from a tall building with an initial velocity of 2 m/s. How fast is it going after 5 seconds of free fall?
Answers
Answer: Vf = Vi + A(t)
Vf= -2+ (-9.8)(5)
Vf = -51 m/s
Explanation:
The final velocity is equal to the initial velocity plus the acceleration multiplied by the time
(-9.8) is used for the acceleration for this question because that is the speed at which things in free fall accelerate when they are on earth
-2 is used as the initial velocity because the ball was thrown in the negative direction which is down.
The time of 5 was given in the question so you can plug it in for time
Answer:
Explanation:
Given:
V₀ = 2 m/s
g = 9.8 m/s²
t = 5 s
____________
V - ?
Axis OX direct vertically down. Then:
V = Vₓ = V₀ₓ + g·t
V = 2 + 9.8*5 = 51 m
What is evidence used by Galileo to disprove Aristotle and Ptolemy?
Answers
Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
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If the marshmallows represent the atoms in the substance, which change of state is Freida modeling Freida wants to model the way atoms move when a substance changes its state. To do this, Freida makes a pyramid of marshmallows. Then, she knocked down the pyramid causing the marshmallows to fall. O melting O freezing O condensation O deposition
Answers
Answer: Melting
Explanation:
When Frieda made a pyramid of marshmallows, she was representing the atoms in a solid substance as the atoms are clumped together and unable to move.
When she then knocks it down, she is showing the movement of atoms in a liquid substance as they are now freer than they were before. The process by which substances go from solid to liquid is melting.
Answer: Melting
Explanation: When Frieda made a pyramid of marshmallows, she was representing the atoms in a solid substance as the atoms are clumped together and unable to move.
When she then knocks it down, she is showing the movement of atoms in a liquid substance as they are now freer than they were before. The process by which substances go from solid to liquid is melting.
The reason uranium mining is dangerous is that chain reactions occur naturally in uranium ore deposits
O True
O False
Answers
Answer:
False po cguro yung sagot d ko po kac Alam e Kaya I Wil study hard to get the correct answer and I will share to you pero I try to be a good friend of mine and I will be a great help to you and your family and your family and friends with you and your family and friends and family and friends with you and your family and friends and family and friends with you and your family and friends and family and friends with you and your family and friends and family and friends with you and your family and friends and family and friends with you and your family and friends and family and friends with you and your family and friends and family and friends with you and your family and and I hope I hope you you will be will be able to come to the next event in the future and hope to see you see you soon and hope you have a great day and I will see you see you soon and and will see you soon and hope you have a great day and I will see you soon and hope you have a great day and I will see you soon and hope you have a great day and I will see you soon and hope you have a great day and I will see you soon and hope you have a great day and I will see you soon and hope you have a great day and I will see you soon soon and and thank you for your thank you
A lump of clay with a mass of .50.0 g is moving south at a speed of 20.0 cm/s. It collides head on with a second lump of clay with a mass of 70.0 g that is moving north at a speed of 40.0 cm/s. The two lumps stick together, and no external horizontal forces act on the system. What is the velocity of the combined lump after the collision?
Answers
The velocity of the combined lump after the collision is 39.5 cm/s, which is the average velocity of the two lumps before the collision.
To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision, provided there are no external horizontal forces acting on the system.
The momentum of an object is equal to its mass multiplied by its velocity. Therefore, we can calculate the total momentum of the system before the collision as:
Total momentum before collision = (0.50 g) × (-20.0 cm/s) + (70.0 g) × 40.0 cm/s
= -10.0 g·cm/s + 2800.0 g·cm/s
= 2790.0 g·cm/s
Since the two lumps stick together after the collision, their masses combine to form a single lump. Let's call the velocity of the combined lump after the collision "v". We can then calculate the total momentum of the system after the collision as:
Total momentum after collision = (0.50 g + 70.0 g) × v
= 70.50 g × v
According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, we can equate these two expressions and solve for "v":
Total momentum before collision = Total momentum after collision
2790.0 g·cm/s = 70.50 g × v
v = 2790.0 g·cm/s ÷ 70.50 g
v = 39.5 cm/s
This result can be explained by the fact that, in the absence of external horizontal forces, the momentum of the system is conserved, and the total mass of the system remains constant.
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When the sun provides energy for photosynthesis, an interaction with the __________ takes place.
Answers
Explanation:
The chloroplast are organelles that conduct photosynthesis, where the photosynthetic pigment chlorophyll captures the energy from sunlight
A thin, non-conducting spherical shell of radius r carries a uniform charge density and a total charge Q. A small, circular disc is removed from the shell, leaving a hole of radius b of radius b (b < < < r). a) What is the magnitude and direction of the electric field at the center of the hole? Hint - how is a hole like on object of negative mass? The plug Is replaced. Use the result of a) to calculate the force acting on the plug. c) From this, calculate the electrostatic pressure that tends to expand the sphere.
Answers
A thin, non-conducting spherical shell of radius r carries a uniform charge density and a total charge is \(\Rightarrow P=\frac{a^2 b^2}{32 \pi 6 r^3\left(4 \pi r^2-\pi b^2\right)}\)
What is density?
The mass of a substance per unit of volume is its density. Density is most frequently represented by the symbol, however Latin letter D may also be used. Mass divided by volume is the formula for density in mathematics: displaystyle rho = frac mV. where m is the mass, V is the volume, and is the density.
Elewk fiud 4 the center of \($x$\) din of
\($$E^{\prime}=\frac{\sigma}{2 \epsilon_0}=\frac{Q^{\prime}}{\left(\pi b^2\right) 2 \epsilon_0}$$\)
where 9 is the total every in the disk.
rose before the dusk tory reigned, the
evener held at the point was
\(F_0=\frac{Q}{4 \pi t r^2} \cdot \text { But } \varepsilon_0=\text { elecke held by the }\)
\(reat of the sphere + deurc freld by the disk of radiun ' $b$ '$\Rightarrow$ Eleunc field alter rennoual $=E_0-E^{\prime}$\)
\(\Rightarrow E=\frac{a}{4 \pi 6 r^2}-\frac{a^{\prime}}{2 \pi \epsilon b^2} \cdot d=a\left(\frac{\pi b^2}{4 \pi r^2}\right)\)
\(\Rightarrow a^{\prime}=\frac{9 b^2}{4 r^2} \Rightarrow E=\frac{3}{4 \pi z r^2}-\frac{9 b^2}{8 \pi 6 b^2 r^2}\)
\(\Rightarrow E=\frac{Q}{4 \pi 6 r^2}-\frac{Q}{8 \pi \sigma_0 r^2}=\frac{Q}{P \pi 60 r^2}\)
\(\text { (b) } F=Q^{\prime} E=\frac{Q b^2}{4 r^2} \frac{d}{8 \pi 6 r^2}=\frac{Q^2 b^2}{32 \pi \epsilon r^3}\)
\(\text { (c) } P=\frac{F}{A} \cdot a r e a=4 \pi r^2-\pi b^2\)
\(\Rightarrow P=\frac{a^2 b^2}{32 \pi 6 r^3\left(4 \pi r^2-\pi b^2\right)}\)
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Quastion and answer about Accrate and precise
Answers
Accuracy refers to how close a measurement is to the true or accepted value. Precision refers to how close measurements of the same item are to each other.
Precision and accuracy are two indices of observational error. Precision is how near a collection of measurements is to its true value, whereas accuracy is how close the measurements are to one other. Precision, in other terms, is a description of random errors and a measure of statistical variability.
If you weigh a body weighing 20 kg and obtain 17.4,17,17.3, and 17.1, your weighing scale is exact but not particularly accurate. If your scale returns values of 19.8, 20.5, 21.0, and 19.6, it is more accurate but not particularly precise.
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Assume the three blocks (m. = 1.0 kg, m = 20 kg and m = 40 ko) portrayed in the figure below move on a frictionless surface and a force F: 36w acts as shown on the 4.0 kg block.
a) Determine the acceleration given this system (in m/s2 to the right). m/s2 (to the right)
b) Determine the tension in the cord connecting the 4.0 kg and the 1.0 kg blocks in N). Determine the force exerted by the 1.0 kg block on the 2.0 kg block (in N). N (a) What If How would your answers to parts (a) and (b) of this problem change if the 2.0 kg block was now stacked on top of the 1.0 kg block? Assume that the 2.0 kg block sticks to and does not slide on the 1.0 kg block when the system is accelerated.
(Enter the acceleration in m/s2 to the right and the tension in N.) acceleration m/s (to the right) tension
Answers
Answer:
a) 5.143 m/s^2
b) T = 15.43 N
c) Fr = 10.29 N
d) 5.143 m/s^2 , T = 15.43 N
Explanation:
Given:-
- The mass of left most block, m1 = 1.0 kg
- The mass of center block, m2 = 2.0 kg
- The mass of right most block, m3 = 4.0 kg
- A force that acts on the right most block, F = 36 N
Solution:-
a)
- For the first part we will consider the three blocks with masses ( m1 , m2 , and m3 ) as one system on which a force of F = 36 N is acted upon. The masses m1 and m3 are connected with a string with tension ( T ) and the m1 and m2 are in contact.
- We apply the Newton's second law of motion to the system with acceleration ( a ) and the combined mass ( M ) of the three blocks as follows:
\(F = M*a\\\\36 = ( 1 + 2 + 4 )*a\\\\a = \frac{36}{7}\\\\a = 5.143 \frac{m}{s^2}\)
Answer: The system moves in the direction of external force ( F ) i.e to the right with an acceleration of 5.143 m/s^2
b)
- The blocks with mass ( m1 and m3 ) are connected with a string with tension ( T ) with a combined acceleration of ( a ).
- We will isolate the massive block ( m3 ) and notice that two opposing forces ( F and T ) act on the block.
- We will again apply the Newton's 2nd law of motion for the block m3 as follows:
\(F_n_e_t = m_3 * a\\\\F - T = m_3 * a\\\\36 - T = 4*5.143\\\\T = 36 - 20.5714\\\\T = 15.43 N\)
Answer:- A tension of T = 15.43 Newtons acts on both blocks ( m1 and m3 )
c)
- We will now isolate the left most block ( m1 ) and draw a free body diagram. This block experiences two forces that is due to tension ( T ) and a reaction force ( Fr ) exerted by block ( m2 ) onto ( m3 ).
- Again we will apply the the Newton's 2nd law of motion for the block m3 as follows:
\(F_n_e_t = m_1*a\\\\T - F_r = m_1*a\\\\15.43 - F_r = 1*5.143\\\\F_r = 15.43 - 5.143\\\\F_r = 10.29 N\)
- The reaction force ( Fr ) is contact between masses ( m1 and m2 ) exists as a pair of equal magnitude and opposite direction acting on both the masses. ( Newton's Third Law of motion )
Answer: The block m2 experiences a contact force of ( Fr = 10.29 N ) to the right.
d)
- If we were to stack the block ( m2 ) on-top of block ( m1 ) such that block ( m2 ) does not slip we the initial system would remain the same and move with the same acceleration calculated in part a) i.e 5.143 m/s^2
- We will check to see if the tension ( T ) differs or not as the two block ( m1 and m2 ) both experience the same Tension force ( T ) as a sub-system. with a combined mass of ( m1 + m2 ).
- We apply the Newton's 2nd law of motion for the block m3 as follows:
\(T = ( m_1 + m_2 ) *a\\\\T = ( 1 + 2 ) * 5.143\\\\T = 15.43 N\)
Answer: The acceleration of the whole system remains the same at a = 5.143 m/s^2 and the tension T = 15.43 N also remains the same.
In blacksmithing, quenching is when you heat steel to 600°C, then dipping it into a pool of oil to quickly lower its temperature. Steel has a specific heat capacity of 470 J/kgK, and quenching oil has a specific heat capacity of 510 J/kgK. A 7kg sword was quenched in 20°C oil, reaching a final temperature of 75°C. What was the total mass of oil in that quenching pool?
Answers
Q = mcΔT
where Q is the heat transferred, m is the mass of the object, c is the specific heat capacity, and ΔT is the change in temperature.
The heat lost by the sword is:
Q_sword = mcΔT = (7 kg)(470 J/kgK)(600°C - 75°C) = 2,835,000 J
The heat gained by the oil is:
Q_oil = mcΔT = (m_oil)(510 J/kgK)(75°C - 20°C)
We can solve for m_oil:
Q_oil = Q_sword
(m_oil)(510 J/kgK)(55°C) = 2,835,000 J
m_oil = 104,706 kg
Therefore, the total mass of oil in the quenching pool was 104,706 kg.
basics of gravitation:
Planet a exerts a force on planet b. What can be said about the magnitude and direction of the gravitational force planet b exerts on planet a?
Answers
Answer:
Explanation:
According to Newton's Law of Gravitation, the gravitational force between two objects is always mutual, meaning that the force that one object exerts on the other is equal in magnitude but opposite in direction.
This means that if planet A exerts a gravitational force on planet B, then planet B will also exert a gravitational force on planet A. The magnitude of this force will be equal to the magnitude of the force that planet A exerts on planet B, but the direction will be opposite.
For example, if planet A exerts a gravitational force on planet B that is pulling planet B towards planet A, then planet B will also exert a gravitational force on planet A that is pulling planet A towards planet B. The magnitude of these two forces will be equal, but the directions will be opposite.
hat he sais
Answer:w
Explanation:
Particles q₁ = -66.3 μC, q2 = +108 μC, and
q3 = -43.2 μC are in a line. Particles q₁ and q2 are
separated by 0.550 m and particles q2 and q3 are
separated by 0.550 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
Answers
F = (k * |q₁ * q₂|) / r²
Where:
F is the force between the particles,
k is the electrostatic constant (approximately 9 × 10^9 N m²/C²),
q₁ and q₂ are the magnitudes of the charges on the two particles, and
r is the separation between the particles.
Let's calculate the forces between q₁ and q₂ as well as q₂ and q₃ using the given values:
For q₁ and q₂:
F₁₂ = (9 × 10^9 N m²/C² * |-66.3 μC * 108 μC|) / (0.550 m)²
For q₂ and q₃:
F₂₃ = (9 × 10^9 N m²/C² * |108 μC * -43.2 μC|) / (0.550 m)²
To find the net force on q₂, we need to consider the direction of each force and add them up. Since q₁ and q₂ have opposite charges, the force F₁₂ will be negative (pointing left), and the force F₂₃ will be positive (pointing right).
Net force on q₂ = F₁₂ + F₂₃
Let's calculate the values:
What is indicated by the amplitude of a wave?; Which part of the wave represents the wavelength?; Is amplitude the height of a wave?; What part of the wave determines how much energy it has amplitude period velocity wavelength?
Answers
The amplitude of a wave represents the power of the wave. The greater the amplitude i.e. the greater its height the higher is the power possessed by the wave. The loudness of the wave is dependent on the amplitude.
Wavelength is the distance covered by one wave. It can be calculated by measuring the distance between two consecutive crests or troughs or one crest and one trough. The inverse of wavelength is known as wave number. It represents the total number of singular waves present in the total distance covered by the wave.
The amount of energy possessed by the wave is showcased by the amplitude.
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Carol Gillian theorized that when it comes to a perspective of Justice,males per socialized for a blank environment while females are socialized for a blank environment
Answers
Answer: men = work environment , women = home environment
Explanation: Gillian proposed that women come to prioritize as “ethics of care” and men as “ethics of justice”.
A 5,257 kg rocket blasts off to the moon with an acceleration of 76 m/s ^2 what is the net force on the rocket
Answers
Newton's subsequent law expresses that power is corresponding to what exactly is needed for an object of consistent mass to change its speed. This is equivalent to that item's mass increased by its speed increase.
We use Newtons, kilograms, and meters each second squared as our default units, albeit any proper units for mass (grams, ounces, and so forth) or speed (miles each hour out of every second, millimeters per second², and so on) could unquestionably be utilized also - the estimation is the equivalent notwithstanding.
Hence, the appropriate answer will be 399,532.
Net Force = 399532
pls help! George pushes a wheelbarrow for a distance of 12 meters at a constant speed for 35 seconds by applying a force of 20 newtons. What is the
power applied to push this wheelbarrow?
A. 1.2 watts
B. 3.4 watts
C. 6.9 watts
D. 13 watts
Answers
Answer:
C. 6.9 watts
Explanation:
Power = work/time
if work = force×distance...
Then... power= (force×distance)/time
Power = (20×12)/35
= 6.9 watts
What constant acceleration, in SI units, must a car have to go from zero to 30 m/s in 14 s ?
Express your answer with the appropriate units.
Answers
Answer:
Acceleration = 2.143m/s²
Explanation:
Vf=Vi+at
(30)=(0)+a(14)
a=2.143m/s²
A certain sea cow can paddle 2.0 m/s in still water. If she attempts to cross a river, from the south bank to the north with a current of 3.0 m/s flowing toward the east by paddling entirely perpendicularly to the flow of the river, in what direction will she be traveling relative to an observer on shore
Answers
Answer:
v = 3.6m / s , θ = 56º
Explanation:
This is a relative speed exercise, let's use the Pythagorean theorem
v = √ (v₁² + v₂²)
where v₁ is the speed of the sea still water and v₂ the speed of the current
let's calculate
v = √ (2² + 3²)
v = 3.6m / s
to find the direction we use trigonometry
tan θ = v₂ / v₁
θ = tan⁻¹ (v₂ / v₁)
let's calculate
θ = tan⁻¹ (3/2)
θ = 56º
what is the equivalent resistance of the circuit shown below?
Answers
The equivalent resistance of the circuit shown is 23 ohms.
Option A is correct.
What is resistance?Resistance is described as the opposition that a substance offers to the flow of electric current.
In a series circuit, all components are connected end-to-end to form a single path for current flow.
In a parallel circuit, all components are connected across each other with exactly two electrically common nodes with the same volt.
We then 1/R = 1/100 + 1/100 + 1 /(50+ 50) + 1 /(50+ 50)
I/R = 0.04
R = 25 ohms.
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A 2.00 x10³ kg crate is pushed to the top of an incline as shown. If the force applied along the incline is 12000 N, what is the potential energy of the object
when it is at the top of the incline with respect to the bottom?
Answers
As demonstrated, a 2.00 x 103 kg container is pushed to the summit of an incline. The height of the inclination in relation to the bottom is 118000 J if a force of 12000 N is applied along it..
What do you meant by kinetic energy ?As seen, an inclination is topped off with a 2.00 x 103 kg container. When the force acting along the incline is 12000 N, Ep = mgh = (2.0010345) (19.84/16) (6.0m) = 117600 J = 118000 J. The relationship between kinetic energy and an object's mass and squared velocity is given by K.E. = 1/2 m v2. If the mass is measured in kilograms and the speed is measured in meters per second, the kinetic energy is measured in kilogram-meters squared per second squared.The amount of force needed will depend on how steep the incline is; the least steep incline (30 degrees) will require the least force, and the steepest incline (100 degrees) will require the most. Less gravitational potential energy is present the lower the cart is.To learn more about kinetic energy refer to :
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The density of lead is 30.2g/cm^3.what is the value in kilograms per meter cube?
Answers
11300 kgm3
Hope this helps
. If two vectors are equal, what can you say about their components?
Answers
Answer:
If two vectors are equal, their components are also equal. For example, vector A and B both share the same x, y, and z components. By having the same components, the magnitude and direction does not change, which attest to how the vectors are identical.
So, if two vectors are equal, their components are also equal.
In vector mathematics, when two vectors are equal, it means their corresponding components are also equal. Thus, the magnitude and direction of the two vectors must be identical.
Explanation:In the world of mathematics, specifically vector mathematics, if two vectors are equal, that means their corresponding components are also equal. A vector is typically described by its individual components which are its magnitude (size) and direction.
For example, if vector A and vector B are equal, and vector A = \((x_1, y_1)\) and vector B = \((x_2, y_2)\), then\(x_1 = x_2\) and \(y_1 = y_2\). This applies to vectors in two-dimensional and three-dimensional spaces as well. Therefore, equality in vectors involves the same direction and magnitude causing the corresponding components to be equal.
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in lecture module 4, there is considerable coverage of the law of conservation of angular momentum. discuss why you think angular momentum is particularly relevant in astronomy. give an example of how the conservation of angular momentum is part of our understanding of astronomical phenomena.
Answers
The law of conservation of angular momentum is particularly relevant in astronomy because it helps us understand how celestial objects move and interact in the universe.
Angular momentum is the product of an object's rotational inertia and its rotational velocity. According to the law of conservation of angular momentum, the total angular momentum of a system remains constant unless acted upon by an external force.
One example of how the conservation of angular momentum is part of our understanding of astronomical phenomena is in the formation of planetary systems. As a cloud of gas and dust collapses under its own gravity to form a star, the conservation of angular momentum causes the cloud to spin faster and flatten into a disk. This disk of material eventually forms into planets orbiting the central star. Without the conservation of angular momentum, the planets would not be able to maintain their stable orbits and the formation of planetary systems would be drastically different.
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what is indoor noise pollution
Answers
Answer:
Domestic gadgets like the mixer-grinders, pressure cookers, desert coolers, air- conditioners, exhaust fans, vacuum cleaners, sewing and washing machines are all indoor sources of noise pollution.
Explanation:
To take off from the ground, an airplane must reach a sufficiently high speed. The velocity required for the takeoff, the takeoff velocity, depends on several factors, including the weight of the aircraft and the wind velocity. Part A A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches the required takeoff velocity at the end of the runway. What is the time tTO needed to take off
Answers
Answer:
t = 26.8 s
Explanation:
Here, we can use the second equation of motion to calculate the required time:
\(s = v_it + \frac{1}{2}at^2\)
where,
s = distance = 1800 m
vi = initial speed = 0 m/s
t = time needed = ?
a = acceleration = 5 m/s²
Therefore,
\(1800\ m = (0\ m/s)t+\frac{1}{2}(5\ m/s^2)t^2\\\\t^2 = \frac{(1800\ m)(2)}{5\ m/s^2}\\\\t = \sqrt{720\ s^2}\)
t = 26.8 s
According to Newton's 3rd Law of Motion, Doug, a baseball
player hits a ball with his bat with a force of 1,000N. The ball
exerts a reaction force equally against the bat of
A.less than 1,000N
B.more than 1,00N
C.1,000N
D.double 1,000N
Answers
the reaction according to Newton’s third law must be an equal and opposite reaction. The force will be greater in order to bounce off of Doug’s bat
Give two examples of situations or application where electronic circuits are used