The best explanation for why a carbonyl group is a m-director in electrophilic aromatic substitution reactions is C) The carbonyl group destabilizes the m-substituted arenium cation intermediate LESS than the o, p-substituted intermediate. This means that the meta position is relatively more stable in the intermediate, directing the electrophilic attack to that position.
The carbonyl group destabilises the intermediate arenium cation with m-substitution LESS than the intermediate with o, p-substitution, which is the best explanation for why a carbonyl group is an m-director in electrophilic aromatic substitution processes.
As a result, the electrophilic assault is focused on the meta location, which is comparatively more stable in the intermediate.
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A set of solubility data is given below.
What is the mass of the dry solute
recovered?
Sample
2
Temperature
(°C)
30.1
Boat Mass
(8)
0.730
Boat +
Solution (g)
0.929
Boat + Dry
(g)
0.816
Answer:
0.086
Explanation:
got it on acellus
The mass of the dry solute recovered from the given data is 0.086 g. Option C
To determine the mass of the dry solute recovered, we need to subtract the mass of the boat from the mass of the boat with the dry solute.
Given the data provided:
Boat Mass: 0.730 g
Boat + Solution: 0.929 g
Boat + Dry: 0.816 g
To find the mass of the dry solute, we subtract the boat mass from the boat + dry mass:
Mass of Dry Solute = (Boat + Dry) - (Boat Mass)
Mass of Dry Solute = 0.816 g - 0.730 g
Mass of Dry Solute = 0.086 g
Therefore, the correct answer is c) 0.086 g.
The mass of the dry solute recovered from the given data is 0.086 g. It is important to note that the mass of the dry solute is obtained by subtracting the mass of the boat from the mass of the boat with the dry solute, as the boat mass represents the weight of the empty boat or container used in the experiment.
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Which is a process that involves collecting information and ideas that are supported by belief or opinion?
science
systematics
pseudoscience
hypothesis
Answer:
The answer is C
Explanation:
I did it on edge
Why is methane, CHA, a nonpolar compound?
It can be inferred that due to the relatively slight difference in electronegativity between carbon and hydrogen, and because of its symmetrical tetrahedral shape, methane CH4 is a nonpolar molecule.
What is Methane?Methane is a colorless, odorless gas that occurs naturally in large quantities and is also a byproduct of some human activities. Methane is the most basic hydrocarbon in the paraffin family and one of the most potent greenhouse gases. It has the molecular formula CH4.
Methane is the second most prevalent anthropogenic GHG after CO2, accounting for approximately 20% of world emissions. Compared to carbon dioxide, methane traps heat in the atmosphere 25 times more effectively.
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True or false? The ground state electron configuration for calcium is 1s22s22p63s23p64s2.
The given statement "The ground state electron configuration for calcium is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² " is true as the atomic number of the calcium is 20.
The atomic number of the calcium is 20. The ground state electron configuration is as follows :
The ground state electron configuration = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
The calcium is an alkaline earth metal, the calcium is the reactive metal that forms the dark oxide nitride layer when it exposed to the air. In the modern periodic table the calcium belongs to the group 2 and it belongs to the period 4.
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PLEASE HELP me create a fictional video game using at least 2 of the ecological roles. (roles to choose from: decomposer, detritivore, pollinator, and seed disperser) (PLS TYPE IT OUT, PLS PLS)
what to include:
-Your characters (include creative names)
-An explanation of how the game is played
-The story of the game
-How the game is won/lost
-Connect the definition of of the two roles with the game and/or how the game is won.
Write a paragraph with at least 7-10 sentences.
BTW ILL GIVE BRAINLIEST OR WHATEVER ITS CALLED!! PLEASE HELP MEE! DESPERATE! IVE BEEN STARING AT THE SCREEN AND CRYING LOLZ <3
Answer:
GOT YOU
Explanation:
Jotun (pollinator)
Norse(decomposer)
Its a point and click adventure game. Where you only have specific actions you can do with your mouse. The basic options are Inspect for notes or Pollinate pollinate the right plants to escape. Your goal and how to win is go through each level picking up the plants to pollinate leave the level. The only way to lose is if you are unable to find the right plants by a set amount of time. The story is your wife has been taken prisoner by Norse and you are alerted by this from a note. You go to a location and find a tower once you walk in the doors shut behind you and a screen appears saying "Get out of the room and to the top of the tower in an hour or she dies. Jotun escapes and gets to the top of the tower to find out his wife died long ago and Norse has been using her for food.
Question:
In a laboratory demonstration, a balloon filled with methane and oxygen was exposed to a
flame. The result was a brief, large flame. The students were asked to formulate an equation for
the reaction. One answer is below.
CH, + 0 = CO,
This equation is incorrect.
A. Explain how and why it is incorrect
B. What would the correct equation be, and how do you know that?
Answer:
The laboratory demonstration consists of the following;
The compounds present in the combustion reaction = Methane, CH₄ and Oxygen, O₂
The chemical equation for the combustion reaction is given as follows;
CH₄ + 2O₂ → CO₂ + 2H₂O
Therefore;
A. The equation given as CH₄ + O → CO₂ is not correct because;
1) Oxygen gas exist as diatomic molecules, O₂, and given that the experiment involves the mixture of gases, the oxygen gas present which can exist as a separate compound, should be represented as O₂
2) The number of oxygen molecules in the reaction is two rather than one
3) The product also includes two molecules of water (vapor) H₂O
B. The correct equation for the reaction should be given as follows;
CH₄ + 2O₂ → CO₂ + 2H₂O
B i) The constituents of the equation is obtained by the knowledge of the fact that the combustion reaction of an organic substance such as methane in the presence of oxygen yields, carbon dioxide and water (vapor)
The equation showing the relative amounts the reacting compounds is by balancing the basic equation of the combustion of methane in the presence of oxygen
Explanation:
Why can't sound waves travel through space?
A certain first-order reaction a → b is 25% complete in 42 min at 25°c. What is the half-life of the reaction?.
Half life of the reaction is :-101.9 min
a→b
25% reacted means 75% remains
t=42 min
Rate constant
k=(2.303/t)(log a/a-x)
k=(2.303/42)(log 100/100-25 )
k=(0.054) (log 100/75)
k=(0.054)(0.1249)
k=0.0068per min
half life
t1/2=(0.693/k)
=(0.693/0.0068)
=101.9 min
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Imagine you have a radioactive sample containing both virtualium and decayed atoms of virtualium. After analysis you find it contains 10 atoms of virtualium and 40 decayed atoms . How old is your sample? Hint you must use the half life of virtualium determined earlier. BTW the half life of virtualium is 12
Answer:
COULD WE PLEASE GET THIS ANSWER?????
Explanation:
Please answer Q1, Q2, Q3 and Q4 in great detail. Thank you so much
Q1. State the formula for the energy levels of Hydrogen
Q2. What is the wavelength (in nm) for a transition between:
a) n=1⇒n=6?
b) n=25⇒n=26?
Q3. For a gas temperature of 300K, what is the relative density (between the two states) for each of the transitions in Q2? To two decimal points is sufficient.
Q4. The Lambert-Beers law is:
I(x) = I◦ exp(−nσx)
where n is the density of the absorber, σ(λ) is the wavelength-dependent cross section for absorption, x is the position, I◦ is the initial photon flux, I(x) is the photon flux versus position through the absorber.
Derive the Lambert-Beers law. (State and justify any assumptions.)
Q1. The formula for the energy levels of hydrogen is E = -13.6 eV/n².
Q2. a) The wavelength for the transition between n=1 and n=6 is approximately 93.5 nm. b) The wavelength for the transition between n=25 and n=26 is approximately 29.46 nm.
Q3. For the transitions in Q2, the relative densities are approximately 0.73 and 0.995, respectively.
Q4. The Lambert-Beers law relates the intensity of light transmitted through an absorber to the absorber's density, cross section for absorption, and position within the medium. It is expressed as I(x) = I₀ * exp(-n * σ(λ) * x).
Q1. The formula for the energy levels of hydrogen is given by the Rydberg formula, which is used to calculate the energy of an electron in the hydrogen atom:
E = -13.6 eV/n²
Where:
- E is the energy of the electron in electron volts (eV).
- n is the principal quantum number, which represents the energy level or shell of the electron.
Q2. a) To find the wavelength (in nm) for a transition between n=1 and n=6 in hydrogen, we can use the Balmer series formula:
1/λ = R_H * (1/n₁² - 1/n₂²)
Where:
- λ is the wavelength of the photon emitted or absorbed in meters (m).
- R_H is the Rydberg constant for hydrogen, approximately 1.097 x 10⁷ m⁻¹.
- n₁ and n₂ are the initial and final energy levels, respectively.
Plugging in the values, we have:
1/λ = (1.097 x 10⁷ m⁻¹) * (1/1² - 1/6²)
1/λ = (1.097 x 10⁷ m⁻¹) * (1 - 1/36)
1/λ = (1.097 x 10⁷ m⁻¹) * (35/36)
1/λ = 1.069 x 10⁷ m⁻¹
λ = 9.35 x 10⁻⁸ m = 93.5 nm
Therefore, the wavelength for the transition between n=1 and n=6 in hydrogen is approximately 93.5 nm.
b) Similarly, to find the wavelength (in nm) for a transition between n=25 and n=26 in hydrogen, we can use the same formula:
1/λ = R_H * (1/n₁² - 1/n₂²)
Plugging in the values:
1/λ = (1.097 x 10⁷ m⁻¹) * (1/25² - 1/26²)
1/λ = (1.097 x 10⁷ m⁻¹) * (1/625 - 1/676)
1/λ = (1.097 x 10⁷ m⁻¹) * (51/164000)
1/λ = 3.396 x 10⁴ m⁻¹
λ = 2.946 x 10⁻⁵ m = 29.46 nm
Therefore, the wavelength for the transition between n=25 and n=26 in hydrogen is approximately 29.46 nm.
Q3. To determine the relative density for each of the transitions in Q2, we need to calculate the ratio of the photon flux between the two states. The relative density is given by the equation:
Relative Density = (I(x2) / I(x1))
Where I(x2) and I(x1) are the photon fluxes at positions x2 and x1, respectively.
For a gas temperature of 300K, the relative density is proportional to the Boltzmann distribution of states, which is given by:
Relative Density = exp(-ΔE/kT)
Where ΔE is the energy difference between the two states, k is the Boltzmann constant (approximately 1.38 x 10⁻²³ J/K), and T is the temperature in Kelvin.
a) For the transition between n=1 and n=6, the energy difference is:
ΔE = E₁ - E₂ = (-13.6 eV / 1²) - (-13.6 eV / 6²)
ΔE = -13.6 eV + 0.6 eV = -13.0 eV
Converting the energy difference to joules:
ΔE = -13.0 eV * 1.6 x 10⁻¹⁹ J/eV = -2.08 x 10⁻¹⁸ J
Substituting the values into the relative density equation:
Relative Density = exp(-(-2.08 x 10⁻¹⁸ J) / (1.38 x 10⁻²³ J/K * 300 K))
Relative Density ≈ 0.73
Therefore, for the transition between n=1 and n=6, the relative density is approximately 0.73.
b) For the transition between n=25 and n=26, the energy difference is:
ΔE = E₁ - E₂ = (-13.6 eV / 25²) - (-13.6 eV / 26²)
ΔE ≈ -13.6 eV + 0.0585 eV ≈ -13.5415 eV
Converting the energy difference to joules:
ΔE ≈ -13.5415 eV * 1.6 x 10⁻¹⁹ J/eV ≈ -2.1664 x 10⁻¹⁸ J
Substituting the values into the relative density equation:
Relative Density = exp(-(-2.1664 x 10⁻¹⁸ J) / (1.38 x 10⁻²³ J/K * 300 K))
Relative Density ≈ 0.995
Therefore, for the transition between n=25 and n=26, the relative density is approximately 0.995.
Q4. Derivation of the Lambert-Beers law:
To derive the Lambert-Beers law, we consider a thin slice of the absorber with thickness dx. The intensity of light passing through this slice decreases due to absorption.
The change in intensity, dI, within the slice can be expressed as the product of the intensity at that position, I(x), and the fraction of light absorbed within the slice, nσ(λ)dx:
dI = -I(x) * nσ(λ)dx
The negative sign indicates the decrease in intensity due to absorption.
Integrating this equation from x = 0 to x = x (the total thickness of the absorber), we have:
∫[0,x] dI = -∫[0,x] I(x) * nσ(λ)dx
The left-hand side represents the total change in intensity, which is equal to I₀ - I(x) since the initial intensity is I₀.
∫[0,x] dI = I₀ - I(x)
Substituting this into the equation:
I₀ - I(x) = -∫[0,x] I(x) * nσ(λ)dx
Rearranging the equation:
I(x) = I₀ * exp(-nσ(λ)x)
This is the Lambert-Beers law, which shows the exponential decrease in intensity (photon flux) as light passes through an absorber. The law quantifies the dependence of intensity on the density of the absorber, the absorption cross section, and the position within the absorber.
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In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quantum mechanics works just as it does in our universe, except that there are three d orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the second and third elements in the first transition series in Universe L. Note: you may use X to stand for the electron configuration of the noble gas at the end of the row before the first transition series. second transition metal: third transition metal:
Answer:
Follows are the solution to this question:
Explanation:
The law of dogs:
Under such a law, although electrons were filled in the
electron, a computer terminal is loaded into it's orbital or paired.
All particles should have the same spinning as one another.
Principle of building construction:
By this principle, atoms are filled with both the energy equation in the angular first. Three d-orbitals exist in cosmos L.
The very first series of transition metals show divergence from the dog law and the principle of Aufbau.
Besides that, half - or full-filled orbital angular momentum is much more stable than orbitally filled up. Components thus strive to achieve equilibrium through transferring electrons, as was shown below partially filled:
please find the attaced file.
Its second transition element (such that, titanium) is thus the electrical structure in the universe L. \([X]4s^23d^3\) besides half-filled stable setup since only 3 d, orbital angular is filled present.
Its third transition factor (Vanadium) electronically does have a configuration of \([X]4s^23d^3\), It's half-full already. where X sits only at end of the row for noble gas Before the first sequence for transformations.
Isabella tiene una pileta que tiene una superficie de 678,32 dam2 mientras que Tadeo tiene una de 865,42 dm2. ¿Cuál pileta tiene mayor superficie?
Isabella has a pool that has an area of 678.32 dam² while Taddeo has one of 865.42 m². Which pool has the largest surface area?
Solution :
We know, 1 dam² = 100 m².
So, area of Isabella pool in m² is :
A = 678.32 × 100 m² = 67832 m² .
Therefore, area of Isabella is greater that volume of Taddeo .
a protein contains four disulfide bonds. in order to break these bonds nad vs nadhresearchers added a minimum of:
A protein contains four disulfide bonds. In order to break these bonds researchers added a minimum of 4 moles of NADH for each mole of protein.
Proteins mature in the cell, forming protein disulfide bonds between the sulfur atoms of two cysteine amino acids (the cystine residue). These connections have grown over time as eukaryotic proteins have evolved, and once obtained, they have nearly always been kept.
The oxidized form of NAD+ is one in which it has lost an electron. As the molecule's reduced form, NADH receives the electron that was lost by NAD+. Disulfide bond is reduced by NADH.
NAD, also known as nicotinamide adenine dinucleotide, is essential for a variety of cellular processes. The process by which NAD is changed from its oxidized form (NAD+) to its reduced form (NADH) and back again gives the cell a way to absorb and give electrons.
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the method of mass production that developed during the nineteenth century was a process that
Answer:
Relied on the use of power driven machinery
Explanation:
Its because the machines would increase the mass productivity of goods
For the following reaction, 14.1 grams of nitrogen monoxide are allowed to react with 4.85 grams of oxygen gas. nitrogen monoxide(g) + oxygen(g) nitrogen dioxide(g) What is the maximum mass of nitrogen dioxide that can be formed? grams What is the FORMULA for the limiting reagent? What mass of the excess reagent remains after the reaction is complete? grams
2NO(g) plus O2(g) equals 2NO2(g). equilibrium equation:
20.7 g NO2 is produced when 13.5 g NO x 1 mol NO / 30 g x 2 mol NO2 / 2 mol NO x 46 g NO2/mol NO is combined.
The amount of NO2 generated is 5.17 g O2 x 1 mol O2/32 g x 2 mol NO2/1 mol O2 x 46 g NO2/mol.
NO2 formation's maximum mass is 149 g.
Limiting reagent's formula is O2.
The leftover mass of excess reagent (NO) is...
Initial moles: 0.45 moles at 13.5 g NO x 1 mol NO/30 g
The formula is: 5.17 g O2 x 1 mol/32 g x 2 mole NO utilized/mol O2 = 0.323 moles NO used up.
0.45 mol - 0.323 mol = 0.127 mol x 30 g/mol = 3.81 g NO remaining is the mass of NO that is still present.
What is a monoxide's purpose?In addition to producing hydrogen, pure metals, heterogeneous catalysts, formic acid, methyl formate, N,N-dimethylformamide, and propanoic acid, carbon monoxide is also utilized as a reducing agent in blast furnaces.
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Answer the following questions with specific reference to relevant Articles of the Commercial Companies Law: 1. What is the liability of Nasser and Buti for the debts and other financial obligations o
Nasser and Buti are liable for the debts and other financial obligations of their company under the Commercial Companies Law of UAE.
Article 73 states that a partner in a partnership company is jointly liable with the company for the company's obligations. Hence, both the partners are responsible for the debts and obligations of the company.
2. No, the appointment of Ahmad, a non-partner, as a manager of the company was not in accordance with the law. Article 154(1) states that a manager must be a partner in the limited liability company or a shareholder in a public joint-stock company. As Ahmad is not a partner, his appointment as a manager is not valid.
3. Victor's liability for debts and other financial obligations of the company is limited as he is a shareholder of the company and not a partner. Article 72 states that the liability of a shareholder is limited to the value of the shares that he holds. Therefore, Victor's liability is limited to the value of his shares.
4. Yes, Viktor has acted in contravention of the law by performing managerial duties and entering deals on behalf of the company. Article 154(2) states that a manager must not perform any activities that are not related to the company's business or have the potential to cause harm to the company. By performing managerial duties and entering deals on behalf of the company, Viktor has violated this provision.
5. Yes, Ahmad violated the law by withdrawing the 50,000 AED from the company's account. Article 172(1) states that a manager must not withdraw any amount from the company's account without the approval of the general assembly. As Ahmad withdrew the amount without the approval of the general assembly, he violated the law.
6. Yes, Ahmad's dismissal was lawful and in accordance with the law. Article 159 states that a manager can be dismissed by a resolution of the general assembly. As Ahmad was dismissed by a resolution of the general assembly, his dismissal was lawful.
7. Global Domination LLC has joined the company as a shareholder. The transfer of shares is considered effective as per Article 83, which states that the transfer of shares is effective from the date of registration in the commercial register.
Incomplete question :
Answer the following questions with specific reference to relevant Articles of the Commercial Companies Law: 1. What is the liability of Nasser and Buti for the debts and other financial obligations of their company? (2 points)
2. Was the appointment of Ahmad, a non-partner, as a manager of the company in accordance with the law? (1 point)
3. What is Victor's liability for debts and other financial obligations of the company? ( 2 points)
4. Has Viktor acted in contravention of the law by performing managerial duties and entering deals on behalf of the company? (1 point)
5. Did Ahmad violate any rules by withdrawing the 50,000 AED from the company's account? (1 point)
6. Was Ahmad's dismissal lawful and in accordance with the law? (1 point)
7. In what capacity has Global Domination LLC joined the company? Is the transfer of shares considered effective? (2 points)
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a 0.250 m solution of a weak acid has a ph of 2.67. what is the value of ka for the acid?
To solve this problem, we need to use the formula for calculating the Ka of a weak acid: Ka = [H+][A-]/[HA].
where [H+] is the concentration of hydrogen ions (protons), [A-] is the concentration of the conjugate base of the acid, and [HA] is the concentration of the acid. We are given the pH of the solution, which is 2.67. We know that pH = -log[H+], so we can find the concentration of hydrogen ions: [H+] = 10^(-pH) = 10^(-2.67) = 0.00200 M.
Since this is a weak acid, we can assume that most of the acid is in the form of HA, and only a small fraction has dissociated into H+ and A-. Therefore, we can assume that the concentration of HA is approximately equal to the initial concentration of the acid, which is 0.250 M.
Now we need to find the concentration of A-. To do this, we use the fact that the acid is weak, which means that its dissociation is described by the equilibrium: HA ⇌ H+ + A-, The equilibrium constant for this reaction is Ka. At equilibrium, the concentrations of the reactants and products are related by the expression: Ka = [H+][A-]/[HA].
We know the values of Ka and [H+] (from the pH), and we have already estimated the value of [HA]. Therefore, we can solve for [A-]: Ka = [H+][A-]/[HA], Ka = (0.00200)(x)/(0.250 - x), where x is the concentration of A- at equilibrium (which we don't know yet). Solving for x, we get: x = 0.0087 M, Now we can calculate the value of Ka: Ka = [H+][A-]/[HA]
Ka = (0.00200)(0.0087)/(0.250 - 0.0087), Ka = 7.2 x 10^-5, Therefore, the value of Ka for the weak acid is 7.2 x 10^-5.
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find the value of Ka for the weak acid. To calculate the Ka value of a weak acid with a 0.250 M concentration and a pH of 2.67:
Step 1: Calculate the hydrogen ion concentration [H+] using the pH value.
pH = -log[H+]
2.67 = -log[H+]
[H+] = 10^(-2.67)
Step 2: Determine the concentration of the weak acid and its conjugate base.
Initial concentration of the weak acid (HA) = 0.250 M
Initial concentration of its conjugate base (A-) = 0
Since the weak acid partially dissociates, let x be the change in concentration:
HA ⇌ H+ + A-
0.250 - x x x
Step 3: Write the expression for Ka.
Ka = ([H+][A-]) / [HA]
Step 4: Use the equilibrium concentrations in the Ka expression.
Ka = (x)(x) / (0.250 - x)
Step 5: Since x is very small compared to 0.250, you can simplify the expression.
Ka ≈ (x^2) / 0.250
Step 6: Substitute the [H+] value obtained in Step 1 for x.
Ka ≈ (10^(-2.67))^2 / 0.250
Step 7: Calculate the Ka value.
Ka ≈ 2.189 × 10^(-5)
The value of Ka for the weak acid is approximately 2.189 × 10^(-5).
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What type of chemical bonds share electrons between atoms?
Answer:
electrons
Explanation:
Polarities of analyte functional group increase in the order of hydrocarbon ethers < esters
The correct order of the increasing polarity of the analyte functional group isEthers < Esters.
The given statement is "Polarities of analyte functional group increase in the order of hydrocarbon ethers < esters." The order of polarities of functional groups is the order of their increasing polarity (i.e., less polar to more polar) based on their electron-donating or withdrawing ability from the rest of the molecule.Polarity of analyte: The analyte's polarity is directly proportional to the dipole moment of the functional group, which is associated with a difference in electronegativity between the atoms that make up the functional group.The electronegativity of an element is its ability to attract electrons towards itself. The greater the difference in electronegativity between two atoms, the more polar their bond, and hence the greater the polarity of the molecule.
To find the correct order of the increasing polarity of the analyte functional group, let's first compare the two groups: hydrocarbon ethers and esters. Here, esters have a carbonyl group while ethers have an oxygen atom with two alkyl or aryl groups. The carbonyl group has more electronegative oxygen, which pulls electrons away from the carbon atom, resulting in a polar molecule. On the other hand, ethers have a less polar oxygen atom with two alkyl or aryl groups, making them less polar than esters. Therefore, the correct order of the increasing polarity of the analyte functional group isEthers < Esters.
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Question 8
What is the effective nuclear charge for a 2nd row electron in sulfur
Answer:
The effective nuclear charge for a 2nd row electron in Sulfur is +8
Explanation:
Zeff = Z (# of protons) - S (# of shielded electrons)
Since there are 8 electrons in the first and second rows combined, there are 8 shielding electrons.
The number of protons in Sulfur is 16.
Therefore,
Zeff = 16 - 8
Zeff = 8
(It's been awhile, so I am not 100% sure)
The effective nuclear charge for a 2nd row electron in sulfur is 14.
Sulfur has 16 atomic number means 16 number of protons and we know that in the first shell or orbit 2 electrons are present which produces a shielding effect due to its fast motion.
Its 2s electrons are shielded only by the two 1s electrons, therefore the second row electron experience an effective nuclear charge i.e. Z effective = 16 − 2 = 14 so we can conclude that the effective nuclear charge for a 2nd row electron in sulfur is 14.
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Consider 5 sequential reactions where the product of each reaction is the reactant of the next and the 5 percent yields are 80%, 90%, 65%, 76% and 30%. If you begin with 100 molecules of the first limiting reagent, what is the maximum number of product molecules you can form at the end of the final reaction
The maximum number of product molecules we can form at the end of the final reaction is 19.5% of the starting number of reactant molecules, or 19.5 molecules.
To solve this problem, we need to find the maximum number of product molecules that can be formed at the end of the final reaction. We can do this by multiplying the number of reactant molecules at each stage by the yield percentage for that stage, and then multiplying all of the results together.
Starting with 100 molecules of the first limiting reagent, we can calculate the number of reactant molecules at each stage as follows:
- Stage 1: 100 molecules
- Stage 2: 80% yield, so 80 molecules
- Stage 3: 90% yield, so 72 molecules
- Stage 4: 65% yield, so 47 molecules
- Stage 5: 76% yield, so 36 molecules
Multiplying these results together, we get:
100 x 80% x 90% x 65% x 76% = 19.5%
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Ok take two tell me if u can see it or not it's #9
ANSWER DISCLAIMER; IF DISSATISFIED, REPORT THIS ANSWER AS SOON AS POSSIBLE:
*This may not be an option but this is most definently another way of saying the answer, through this, learning can be improved instead of giving the answer right off the bat.*Answer:
The motion of the gas particles is random and in a straight-line.
Explanation:
According to the kinetic hypothesis, a gas is made up of a huge number of submicroscopic particles (atoms or molecules) that are all in continual, random motion. The swiftly moving particles clash with one another and with the container's walls on a regular basis. The phrase ideal gas refers to a hypothetical gas made up of molecules that adhere to a few rules: The molecules of an ideal gas do neither attract or repel one another. The sole interaction between perfect gas molecules would be an elastic collision when they collided or an elastic collision with the container's walls.
how many hydrogen bonds connect adenine and thymine
Answer:
Hydrogen can make two bonds with Adenine and Thymine.
Explanation:
Adenine and thymine similarly pair via hydrogen bond donors and acceptors; however an AT base pair has only two hydrogen bonds between the bases.
Answer:
2 hydrogen bonds.
Explanation:
There are two hydrogen bonds between adenine and thymine.
help me with my bell work
Answer:
1) It gets slower the farther out they are.
2) The farther out you are from the sun the less gravitational pull you have, which makes it go slower as it orbits.
3) Gravity ;) :)
Explanation:
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1.) The four inner planets have slower orbits and the four outer planets have faster orbits.
2.) The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves.
3.) Gravity
How many rings/energy levels would the Bohe model for an element
have if it had 12 electrons?
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Miss Kitty's Chocolate Corral is located in an out-of-the-way small shopping center. However, the company enjoys outstanding business because satisfied customers share their delightful experiences at Miss Kitty's with their friends and relatives. Miss Kitty's apparently benefits from positive:
Miss Kitty's Chocolate Corral is a testament to the power of positive word-of-mouth marketing. Even though the small shop is located in an out-of-the-way shopping center, its outstanding business speaks volumes about the effectiveness of customer satisfaction in driving growth and success.
Positive word-of-mouth marketing is a powerful tool that can help businesses thrive. When customers have a delightful experience with a company, they are likely to share their experiences with their friends and family. This can lead to new customers and increased business. Miss Kitty's success can be attributed to the fact that the company provides high-quality chocolate and exceptional customer service. Customers leave feeling satisfied and happy, and they are eager to share their positive experiences with others. This generates a sense of loyalty and trust among customers, which in turn drives repeat business.
In summary, Miss Kitty's Chocolate Corral is an excellent example of how positive word-of-mouth marketing can drive business growth and success. By prioritizing customer satisfaction and delivering high-quality products and services, businesses can build a loyal customer base that will help them thrive in the long term.
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How is chemical weathering different from physical weathering?(1 point)
Chemical weathering involves plants and animals, while physical weathering does not.
Chemical weathering requires a reaction with water, while physical weathering does not.
Chemical weathering forms new substances, while physical weathering does not.
Chemical weathering results in the breakdown of rock, while physical weathering does not.
Chemical weathering different from physical weathering because chemical weathering results in the breakdown of rock, while physical weathering does not
Chemical weathering involve the interaction of rock with minerals solution to change the composition of rock in this process water interact with minerals to create various chemical reaction and transform the rock and physical weathering is the process that cause disintegration of rock, minerals soil without chemical change that's why chemical weathering different from physical weathering because chemical weathering results in the breakdown of rock, while physical weathering does not
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1) Determine a fórmula da base hidróxido de bário: * 1 ponto a) b) c) d) 2) As bases são substâncias iônicas, ou seja, quando são solubilizadas em água liberam íons, qual das características abaixo pode ser atribuída as soluções iônicas? * 1 ponto a) Conduzem corrente elétrica. B) Isolantes elétricos. C) Radioatividade. D) Emissão de raio UVA.
Answer:
1) Ba(OH)₂
2) The correct option is a) they conduct electricity.
Explanation:
To deduce the formula of Barium hydroxide, we have to go to the periodic table and look for the Barium (Ba), which is in group 2 and has an ionic charge of 2+. Hydroxides are not an element that is present in the periodic table is the combination of Oxygen and Hydrogen (OH), and its ionic charge is 1-.
To name this substance, we write the elements that form it, which are Ba OH, then we see the ionic charges that they have, Ba2+ OH 1- and we change these charges giving the 2+ to the OH and the 1- to the Ba. It would look Ba OH₂; we do not write the 1, and as there is a 2, the OH, has to be between brackets so that the final formula is Ba(OH)₂. What we did is balancing the charges of the elements. In other words, we need 2 OH for every Ba. Hydroxides give an electron to balance the Ba ionic charge.
Barium Hydroxide is an ionic compound because ionic compounds are formed by a metal (Ba) and a nonmetal element (OH), ionic compounds are charged, so when they are in an aqueous solution they conduct electricity because their ions move freely in the solution.
Different kinds of atoms chemically combined to form a substance are.
Answer:
A chemical compound.
For example...
\(C + H2 + O1 = Cx(H2O)y(carbohydrate)\)
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1. You are given the number of moles of carbon and must convert it to an equivalent mass using the molar mass from the periodic table. The carbon sample is 0.045 moles.
2. How many moles of potassium are in 525.0 g of pure potassium? Explain
0.54g is the mass of carbon in 0.045 moles of carbon. Elementary particles shared the same quantity of matter.
What is mass?A body's mass is an inherent attribute. Until the discoveries of the atom as well as particle physics, it was thought to be tied to the amount of matter inside a physical body. It was discovered that various atoms and elementary particles shared the same quantity of matter.
mole = given mass/ molar mass
substituting all the given values in the above equation, we get
0.045 moles = mass/ 12
mass =0.045×12= 0.54g
Therefore, 0.54g is the mass of carbon in 0.045 moles of carbon.
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