Classify the scenarios described according to the force that would be exerted on the center charge 2. Assume in each case that q is a positive charge. Force is zero Force is to the left Force is to the right Force is undetermined Answer Bank qa = 4c = negative and q = qd = negative qa = qd = negative and qc = qb = negative qa = qd = positive and qc = 96 = positive qa = qe = positive and q. = qa = positive qa = qd = negative and qe = qb= positive 4a = qe = negative and q = qd = positive 9a = 4c = positive and q. = qd = negative 9a = qd = positive and qc = qb= negative Question Credit: OpenStax College Physics
Answers
Given the problem, the electrostatic force exerted on the center charge 2 is to be classified into the following scenarios.
The force may be zero, to the left, to the right, or undetermined.Scenarios:qa = 4c = negative and q = qd = negativeqa = qd = negative and qc = qb = negativeqa = qd = positive and qc = 96 = positiveqa = qe = positive and q. = qa = positiveqa = qd = negative and qe = qb = positive4a = qe = negative and q = qd = positive9a = 4c = positive and q. = qd = negative9a = qd = positive and qc = qb = negative
Classification of the scenarios:If the center charge 2 is negative, it will be pushed to the left by any charge that is negatively charged.If the center charge 2 is negative, it will be pulled to the right by any charge that is positively charged.
If the center charge 2 is positive, it will be pushed to the right by any charge that is positively charged.If the center charge 2 is positive, it will be pulled to the left by any charge that is negatively charged. In case all charges are of the same charge, it can't be determined if there is a net force or not
.Explanation of the given scenarios:qa = 4c = negative and q = qd = negative:The force on charge 2 cannot be determined by this scenario.qa = qd = negative and qc = qb = negative:The force on charge 2 cannot be determined by this scenario.qa = qd = positive and qc = 96 = positive:The force on charge 2 cannot be determined by this scenario.qa = qe = positive and q. = qa = positive:
The force on charge 2 cannot be determined by this scenario.qa = qd = negative and qe = qb = positive:Charge 2 will be pushed to the left.4a = qe = negative and q = qd = positive:Charge 2 will be pushed to the right.9a = 4c = positive and q. = qd = negative:Charge 2 will be pushed to the left.9a = qd = positive and qc = qb = negative:Charge 2 will be pushed to the right.
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Related Questions
Find the sum. Express the answer in scientific notation. (1.54 x 10^6)+(6.15 x 10^6)
Answers
Answer:
\( { \tt{(1.54 \times {10}^{6}) + (6.15 \times {10}^{6}) }} \\ = { \tt{(1.54 + 6.15) \times {10}^{6} }} \\ = { \tt{7.69 \times {10}^{6} }}\)
A metal sphere has a charge of 6.0 µC. What is the net charge after 7.0 x1013 electrons have been placed on it?
Answers
When electrons are added to a sphere, they will cause it to become negatively charged. As a result, the net charge will increase. A negative charge would be the charge on the sphere.
Coulomb's law states that the charge Q is equal to the product of the charge Q_0 on the metal sphere plus the product of the charge\(n_e\)on the electrons multiplied by the elementary charge, which is e.
Symbolically:\(Q=Q_0+ne*e\)
where e is the elementary charge.
It's equal to\(1.602×10^−19 C.µC\) (microcoulombs) must be converted to coulombs in the question.
Because one microcoulomb is one millionth of a coulomb,\(6.0 µC = 6.0 x 10^-6 C (coulombs).\)
Substitute the given values in the above Coulomb's law equation:
\(Q = (6.0 x 10^-6) + (7.0 x 10^13) x (1.602 x 10^-19)Q = 1.122 C\)
The net charge on the sphere is 1.122 C.
Therefore, the net charge of the sphere after \(7.0 x 10^13\)
electrons have been placed on it is 1.122 C.
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There are three main types of rocks identified by how they are formed.Which of the following is true concerning the formation of rocks on Earth
Answers
Answer:
Igneous Rock
Sedimentary Rock
Metamorphic Rock
Explanation:
Igneous Formed by lava
Sedimentary Form By other fragmented pieces of rock
Metamorphic rocks that have undergone physical changes exposed to extreme presure.
You drive a car at a speed of 40 mph for 600 miles. How long did it take you to travel that distance?
A. 18 hours
B. 12 hours
C. 24 hours
D. 15 hours
Answers
Answer:
B
Explanation:
The path of a projectile is called a ???
Answers
Answer:
Projectile motion is a form of motion where an object moves in parabolic path; the path that the object follows is called its trajectory.
Explanation:
when a conductor cuts magnetic lines of force a voltage is induced into the conductor this principle is called
Answers
when a conductor cuts magnetic lines of force a voltage is induced into the conductor this principle is called Faraday's law of electromagnetic induction.
Faraday's law, named after the British physicist Michael Faraday, describes the relationship between a changing magnetic field and an induced electromotive force (EMF) in a conductor. According to the law, when a conductor is placed in a varying magnetic field, a voltage is induced across the ends of the conductor, creating an electric current.
Faraday's law is a fundamental principle of electromagnetism and is used to explain a wide range of phenomena, including the operation of electric generators, transformers, and motors. It also plays a crucial role in the understanding of electromagnetic induction, which is the process by which a changing magnetic field can create an electric field, and vice versa.
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One end of a uniform 4.00-m-long rod of weight Fg is supported by a cable at an angle of theta=37 degrees with the rod. The other end tests against the wall, where it is held by friction as shown in Figure P12.23. The coefficient of static friction between the wall and the rod is 0.500. Determine the minimum distance x from point A at which an additional object, also with the same weight Fg, can be hung without causing the rod to slip at point A.
Answers
Therefore, the minimum distance x from point A at which an additional object, also with the same weight Fg, can be hung without causing the rod to slip at point A is 1.65 m.
The given diagram for the problem is as follows. The length of the rod is 4 m, and it weighs Fg, and it is hanging from a cable at an angle θ = 37° with the rod. The other end of the rod is held against the wall by friction. The coefficient of static friction between the wall and the rod is 0.5. An additional object with the same weight Fg is hung from point A at a minimum distance x so that the rod does not slip at point A.
To solve this problem, we need to use the concept of torque. We need to balance the torque about point A. The torque acting on the rod is due to its weight, which acts through the center of mass, and the tension in the cable, which acts at a distance of 2 m from point A.
The tension in the cable can be resolved into two components, one horizontal and one vertical. The horizontal component of tension balances the frictional force acting on the rod.
We have,
2 T sin θ = Ff
where Ff is the frictional force acting on the rod.
The vertical component of tension balances the weight of the rod.
We have,
2 T cos θ = Fg
where Fg is the weight of the rod.
The minimum distance x can be calculated by balancing the torque about point A. The torque due to the weight of the rod is,
Fg (4 - x)sin 37°
and the torque due to the additional weight Fg is, Fg x
The torque due to the tension in the cable is zero since it acts through point A.
Therefore, we have,
Fg (4 - x)sin 37° = Fg x
Solving for x, we get, x = 1.65 m
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What is the active volcanoes
Answers
The price of a television was reduced from
$250 to $200. By what percent was the price
of the television reduced?
Answers
Answer:
20%
Explanation:
List 1 advantage and 1 disadvantage of a series circuit.
Answers
Explanation:
advantage: Easy to design and build the circuit
disadvantage: if one component in a series circuit fails, then all the components in the circuit fail because the circuit has been broken.
hope it helps!
When you are approached by an emergency vehicle sounding a siren, having at least one lighted lamp exhibiting a red or blue light you do not need to do anything, keep driving as before
Answers
When an emergency vehicle sounding a siren approaches you, having at least one lighted red/white or blue/white lamp that is visible; a driver must yield the right of way.
When an emergency vehicle is approaching:
Pull over to the edge of the roadway, clear of intersections, and stop.Remain there until the emergency vehicle has passed. ...Keep a foot on the brake so the brake lights let emergency vehicle drivers know you have stopped.What is the first thing you should do when you hear sirens while driving?
As soon as you hear sirens coming your way, calmly pull over to the right and stop. “Slow down, check to the right, and pull over as soon as it is safe to do so to allow the emergency vehicle to pass you,”
When you hear a siren bell or see red flashing lights?
Yield the right-of-way to any approaching emergency vehicle that is using its flashing lights or siren, regardless of its direction of travel. You must immediately drive to the right side of the road and stop until the emergency vehicle has passed.
Can you go through a red light if an ambulance is behind you?
The ambulance crew are trained to negotiate traffic and may look to use the bus lane to pass, and you could get in their way or even get a ticket. Do not go through a red light to try to get out of the way as you may commit an offence.
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What separates musical theater from other dance styles?
Answers
Answer: Musical theater is like acting in a musical.
Explanation: Other dance styles don't involve singing.
If a person rides a bike 80 miles in 4 hours, what speed was the person traveling?
Answers
Answer:
i think its 20 miles per hour
Explanation:
If a ball is thrown straight up into the air with an initial velocity of $60{ft} /{s}$, its height in feet after $t$ second is given by $y=60 t-16 t^2$. Find the average velocity (include units, help (units)) for the time period begining when $t=2$ seconds and lasting
(i) 0.5 seconds
Avenge velocity:
(ii) 0.1 seconds
Average velocity:
(iii) 0.01 seconds
Average velocity:
Finally based on the above results, guess what the instantaneous velocity of the ball is when $t=2$. Average velociry:
Answers
The instantaneous velocity of the ball is when $t=2$ is 32 ft/s so the average velocity: 32 ft/s.
The given function is $y=60t-16t^2$. We need to find the average velocity of the ball for the time period beginning when $t=2$ seconds and lasting. The average velocity is calculated by dividing the distance travelled by the time taken. The average velocity for the time period beginning when $t=2$ seconds and lasting 0.5 seconds is calculated as follows:
Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Here, $y_2$ is the value of the function when $t=2.5$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.5)-16(2.5)^2=45$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.5$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{45-32}{0.5}]$Average velocity = $[\frac{13}{0.5}]$Average velocity = $26$ ft/sNow, for the time period beginning when $t=2$ seconds and lasting(ii) 0.1 seconds. Here, $y_2$ is the value of the function when $t=2.1$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.1)-16(2.1)^2=31.84$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.1$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{31.84-32}{0.1}]$Average velocity = $[-1.6]$ ft/s(iii) 0.01 seconds. Here, $y_2$ is the value of the function when $t=2.01$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.01)-16(2.01)^2=31.9364$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.01$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{31.9364-32}{0.01}]$Average velocity = $[-6.36]$ ft/s
Finally based on the above results, we can guess that the instantaneous velocity of the ball is when $t=2$ is 32 ft/s. hence, Average velocity: 32 ft/s.
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Location A on the surface of Earth bas a much higher temperature than Location Which statement is most likely true A.Both locations are at the poles B.Both are at the equator C.Location A is at the equator and Location B is the poles D.Location at the poles and location B is the equator
Answers
Answer:
The anwser is b
Explanation:
Answer:
the answer is B
I know because i just did it
a. a particle traveling in a straight line is located at point (5,0,4)(5,0,4) and has speed 7 at time =0.t=0. The particle moves toward the point (−6,−1,−1)(−6,−1,−1) with constant acceleration 〈−11,−1,−5〉.〈−11,−1,−5〉. Find position vector ⃗ ()r→(t) at time .
b. A baseball is thrown from the stands 40 ft above the field at an angle of 20∘20∘ up from the horizontal. When and how far away will the ball strike the ground if its initial speed is 26 ft/sec? (Assume ideal projectile motion, that is, that the baseball undergoes constant downward acceleration due to gravity but no other acceleration; assume also that acceleration due to gravity is -32 feet per second-squared.)
The ball will hit the ground after ? sec.
The ball will hit the ground a horizontal distance of ? ft away
Answers
The ball will hit the ground after approximately 1.88 seconds and at a horizontal distance of approximately 34.15 ft away.
a. To find the position vector of the particle at time t, we can use the kinematic equation for motion with constant acceleration. The position vector ⃗r(t) is given by ⃗r(t) = ⃗r₀ + ⃗v₀t + 0.5⃗at², where ⃗r₀ is the initial position vector, ⃗v₀ is the initial velocity vector, ⃗a is the acceleration vector, and t is the time.
Plugging in the values, we have ⃗r(t) = (5, 0, 4) + (0, 0, 7)t + 0.5(-11, -1, -5)t², which simplifies to ⃗r(t) = (5 - 11t^2, -t, 4 - 5t^2). This gives the position vector of the particle at any given time t.
b. For the baseball, we can analyze its motion using projectile motion equations. The vertical and horizontal motions are independent of each other, except for the initial velocity. The vertical motion is affected by gravity, with an acceleration of -32 ft/s².
Using the given initial speed of 26 ft/s and the launch angle of 20 degrees, we can decompose the initial velocity into its vertical and horizontal components. The vertical component is 26 * sin(20°) ft/s, and the horizontal component is 26 * cos(20°) ft/s.
To find the time of flight, we can use the equation for vertical motion: y = y₀ + v₀yt + 0.5at². The initial vertical position is 40 ft, the initial vertical velocity is 26 * sin(20°) ft/s, and the vertical acceleration is -32 ft/s². Solving for t, we get t ≈ 1.88 seconds.
To find the horizontal distance, we use the equation x = x₀ + v₀xt, where the initial horizontal position x₀ is 0 ft (assuming the ball is thrown from the stands), the initial horizontal velocity v₀x is 26 * cos(20°) ft/s, and the time of flight t is approximately 1.88 seconds. Solving for x, we find x ≈ 34.15 ft.
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Mass and weight are different.mass depends on………., And weight depends on…………
Answers
Answer:
Matter, Force
Explanation:
In scientific contexts, mass is the amount of "matter" in an object (though "matter" may be difficult to define) whereas weight is the force exerted on an object by gravity. Objects on the surface of the Earth have weight, although sometimes the weight is difficult to measure.
a balloon is rising at the constant rate of 5 meters per second a passes beneath it taveling in a straigthh line at the constant speed o10 meteres per second at the moment that the bicyclist is directly beneath the height of the balloon is 95 meters how fast is the distance between the and the balloon incrasing 5 seconds after the bicyclist was directly
Answers
Saying that someone or something is beneath you expresses your opinion that they are either unworthy of you or not appropriate for you.
What do you mean by beneath?They concluded that she should not marry. Alternatives: inappropriate, unworthy of, unsuited for, unsuitable for Additional Synonyms for below.
It is the passed beneath by which a velociraptor riding a bicycle while maintaining a steady speed of 6 meters per second. How quickly do the velociraptor's distances grow Under his T-shirt, she could make out the shoulders' muscles. Sitting beneath the trees gave her pleasure. The theatre's four levels of parking were insufficient.
He noticed that a known photo book on a shelf below. adverb further down than the; underneath; lower in the location than. close to the ground; short. below. underneath. bottom. bottommost the first drawer down from the top.
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How many ounces in a cup?
Answers
Answer:
8 oz
Explanation:
Hope this helps have a blessed day!
________ galaxies may bridge the gap between spiral galaxies and quasars.
Answers
According to recent research, galaxies may play a crucial role in connecting spiral galaxies to quasars.
These mysterious galaxies are thought to be the missing link between the two extreme phenomena, as they are believed to have the right conditions to fuel both types of objects. The discovery of these galaxies could help astronomers better understand the formation and evolution of galaxies and their relationship to quasars, which are some of the most luminous objects in the universe.
Quasars are extremely bright, distant objects that are thought to be powered by supermassive black holes at the centers of galaxies. They emit intense radiation across the entire electromagnetic spectrum and are often used as cosmic mile markers, as their light can travel billions of light-years before reaching us. Spiral galaxies, on the other hand, are galaxies with a flat, rotating disk of stars, gas, and dust, surrounded by a halo of dark matter.
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A scientist performs tests on a sample of an element. The element is a shiny solid that conducts electricity and heat. The scientist is able to bend and flatten the sample when pressure is applied to it.
Based on this information, the element could NOT be a member of which group on the periodic table?
Answers
Answer:
Group 18
Explanation:
Answer:
gold
Explanation:
gold is shinny and solid can conduct ele tricity ,maleabl
Hii I need help asap with these 3 questions, thanks if you're able to find a solution or at least see this
Answers
Explanation:
sorry I don't know this because this question is Garbo. question this answer by ur self
The acceleration due to gravity on Mars is about 3. 7 m/s2. A pendulum on that planet has an object at the end with a mass of 1. 5 kg and a period of 4. 6 seconds. What is the length of the pendulum’s string?
1. ) 1. 0m
2. ) 2. 0m
3. ) 5. 3m
4. ) 6. 3m
Answers
To find the length of the pendulum's string, we can use the formula for the period of a simple pendulum: T = 2π√(L/g), where T is the period, L is the length of the string, and g is the acceleration due to gravity.
We are given the period (T) as 4.6 seconds and the acceleration due to gravity on Mars (g) as 3.7 m/s². We can rearrange the formula to solve for the length (L):
L = (T² * g) / (4π²)
Now, substitute the given values:
L = (4.6² * 3.7) / (4π²)
L ≈ 2.0 m
Therefore, the length of the pendulum's string is approximately 2.0 meters. Your answer is 2.) 2.0m.
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What can be used to plot the magnetic field around a bar magnet?
Answers
Answer:
A bar magnet creates a magnetic field around it. The field cannot be seen, but its effects can be observed. This is how the magnetic field around a magnet is detected. Iron fillings can be used to study the presence of magnetic field and a compass can be used to plot the field lines.
Explanation:
heat = 80J light = 119J sound = 1J electricity = 200J what form of energy is transferred as waste energy by the television set?
Answers
The form of energy that is transferred as waste energy by the television set is heat energy (80 J).
Waste energy by the television setBased on the law of conservation of energy, energy can neither be created nor destroyed but can be converted from one form to another.
Useful energy supplied to television setThe useful energy supplied to television set is calculated as follows;
= 119 J + 1 J = 120 J
Waste energyThe wasteful energy of the television set is calculated as follows;
= 200 J - 120 J = 80 J
Thus, the form of energy that is transferred as waste energy by the television set is heat energy (80 J).
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Q|C Two capacitors, C₁ = 18.0σF and C₂ = 36.0σF , are connected in series, and a 12.0-V battery is connected across the two capacitors. Find (d) Show that the sum of these two energies is the same as the energy found in part (b).
Answers
The sum of the energies of the two capacitors is 3888σJ, which is the same as the energy found in part (b). To find the sum of the energies of the two capacitors connected in series, we need to calculate the energy stored in each capacitor separately and then add them together.
First, let's find the energy stored in capacitor C₁. The formula for the energy stored in a capacitor is given by:
E = 1/2 * C * V²
Where E is the energy, C is the capacitance, and V is the voltage.
Plugging in the values, we have:
E₁ = 1/2 * 18.0σF * (12.0V)²
E₁ = 1/2 * 18.0 * (12.0)²
E₁ = 1/2 * 18.0 * 144
E₁ = 1296σJ
Next, let's find the energy stored in capacitor C₂. Using the same formula:
E₂ = 1/2 * 36.0σF * (12.0V)²
E₂ = 1/2 * 36.0 * (12.0)²
E₂ = 1/2 * 36.0 * 144
E₂ = 2592σJ
Now, let's find the sum of these two energies:
E_total = E₁ + E₂
E_total = 1296σJ + 2592σJ
E_total = 3888σJ
So, the sum of the energies of the two capacitors is 3888σJ, which is the same as the energy found in part (b).
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A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 34.5 m/s. With what maximum speed can it go around a curve having a radius of 60.0 m
Answers
With 20.23 ms⁻¹, maximum speed can it go around a curve having a radius of 60.0 m
What's the maximum speed?The highest rate of speed a person can reach is called maximum speed. When athletes alter the magnitude (how quickly they are moving) or direction (or both) of their motion, or both, their acceleration changes as well since acceleration is related to velocity, which has both a magnitude and a direction connected with it.
ac max = V² max / R ....(1)
Inserting given values we get
ac, max = (34.5)² / 150 = 7.935 ms⁻²
For a changed radius of the curve of 60.0 m, the maximum safe speed from (1) becomes
Unew, max= √ac, max R new
Unew, max = √6.826 x 60
Unew, max 1 = 20.23 ms⁻¹, rounded to one decimal place.
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An accelerometer is a device that uses the extension
a spring to measure acceleration in terms of Earth's gravitational acceleration (g). What is
the approximate acceleration if this accelerometer spring is extended just 0.43 centimeters?
Answers
Answer:
your question explains that an accelerometer is a device that uses the extension spring to measure acceleration in terms of Earth's Gravitational accelerations. So if this device is extended just 0.43 centimeters the possible accelerations is letter B. 0.80 g
A block with mass = 12 kg rests on a frictionless table and is accelerated by a spring with spring constant k = 4,539 N/m after being compressed a distance x1=0.443m from the spring's unstretched length. The floor is frictionless except for a rough patch a distance d = 2.7 m long. For this rough path, the coefficient of friction is μk=0.4
How much work is done by friction as the block crosses the rough spot?
Answers
The work done by friction as the block crosses the rough spot is approximately 19.6 J.
How did we get the value?To solve this problem, we need to find the speed of the block when it reaches the end of the rough patch, and then use the work-energy principle to calculate the work done by friction.
First, let's find the maximum compression of the spring using Hooke's Law:
F = -kx
where F is the force exerted by the spring, k is the spring constant, and x is the compression distance.
At maximum compression, the force exerted by the spring is equal and opposite to the weight of the block:
F = mg
where m is the mass of the block and g is the acceleration due to gravity.
Thus, we have:
-kx1 = mg
Solving for x1, we get:
x1 = -mg/k = - (12 kg)(9.81 m/s^2) / (4539 N/m) ≈ -0.246 m
Note that x1 is negative because the spring is compressed.
Now, let's find the speed of the block when it reaches the end of the rough patch. We can use conservation of energy to relate the potential energy stored in the spring to the kinetic energy of the block:
(1/2)kx1^2 = (1/2)mv^2
where v is the speed of the block.
Solving for v, we get:
v = sqrt[(k/m)x1^2] = sqrt[(4539 N/m) / (12 kg)] x 0.246 m ≈ 1.61 m/s
Now we can calculate the work done by friction using the work-energy principle:
W_friction = ΔK = (1/2)mv^2 - 0
where ΔK is the change in kinetic energy of the block.
Since the block starts from rest and ends with speed v, we have:
ΔK = (1/2)mv^2 - 0 = (1/2)(12 kg)(1.61 m/s)^2 ≈ 19.6 J
Therefore, the work done by friction as the block crosses the rough spot is approximately 19.6 J.
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from 0 seconds to 4 seconds is the acceleration positive or negative?
from 6 seconds to 10 seconds is the acceleration positive or negative?
BEST ANSWER GETS 5 STAR AND POINTS. (MUST BE CORRECT)
Answers
Answer:
From 0 -4 seconds the acceleration is positive. (The graph is going upwards.)
From 6-10 seconds the acceleration is negative. (The graph is going downwards.)