college students and stds: a recent report estimated that 25% of all college students in the united states have a sexually transmitted disease (std). due to the demographics of the community, the director of the campus health center believes that the proportion of students who have a std is lower at his college. he tests h0: p

The sampling plan's reliability or validity. Before using a sampling plan, it is crucial to examine its reliability or validity. This assessment helps determine how well the sampling plan can discriminate between good and bad quality.

Reliability refers to the consistency and stability of the sampling plan's results. A reliable sampling plan consistently produces similar outcomes when applied to the same population under similar conditions. If a sampling plan is unreliable, its results may vary widely, leading to inconsistent judgments about quality.

Validity, on the other hand, refers to the extent to which the sampling plan accurately measures or identifies the desired characteristics or qualities. A valid sampling plan provides a true representation of the quality being assessed and ensures that good quality is distinguished from bad quality effectively.

By examining the reliability and validity of a sampling plan, we can gain confidence in its ability to accurately discriminate between good and bad quality. This examination may involve conducting pilot tests, analyzing historical data, or seeking expert opinions to assess the plan's effectiveness and suitability for the specific context.

Without considering the reliability and validity of a sampling plan, there is a risk of making incorrect judgments or decisions based on flawed or biased sampling outcomes. Therefore, it is essential to evaluate these aspects before using a sampling plan to ensure the reliability and accuracy of the results obtained.

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\(\\ \rm\Rrightarrow \dfrac{7513/100\times 5x^3}{3x^2}\)

\(\\ \rm\Rrightarrow \dfrac{75.13(5)x^3}{3x^2}\)

\(\\ \rm\Rrightarrow {125.22x}\)

The gradient of f is nabla f(x, y, z) = (1/sqrt(x+yz), z/sqrt(x+yz), y/sqrt(x+yz)).

At point P, the gradient is nabla f(1, 3, 1) = (1/2, 1/sqrt(2), sqrt(2)/2).

The rate of change of f at P in the direction of the vector u is D_u f(1, 3, 1) = 9/7sqrt(2).

The gradient of f is defined as the vector of partial derivatives of f with respect to its variables. Hence, we have nabla f(x, y, z) = (∂f/∂x, ∂f/∂y, ∂f/∂z) = (1/sqrt(x+yz), z/sqrt(x+yz), y/sqrt(x+yz)).

Substituting the values of P into this expression, we get nabla f(1, 3, 1) = (1/2, 1/sqrt(2), sqrt(2)/2).

The directional derivative of f at P in the direction of the unit vector u is given by the dot product of the gradient of f at P and the unit vector u, i.e., D_u f(1, 3, 1) = nabla f(1, 3, 1) · u.

Substituting the values of P and u into this expression, we get D_u f(1, 3, 1) = (1/2) * (3/7) + (1/sqrt(2)) * (6/7) + (sqrt(2)/2) * (2/7) = 9/7sqrt(2). Therefore, the rate of change of f at P in the direction of the vector u is 9/7sqrt(2).

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Answer:

81

Step-by-step explanation:

a+4

Let a = 87

87+4

81

Answer:

Y =  12 x + 75

Step-by-step explanation:

y = total cost of the tour

x = how many bikes rented

75 = tour cost for a group

Answer:

D

Step-by-step explanation:

3x and 30 are vertically opposite angles and congruent, then

3x = 30 ( divide both sides by 3 )

x = 10 , thus

3x = 3 × 10 = 30°

x = 10 ; angle measure is 30° → D

Answer:

the answer is D, x= 10;angle measure is 30°

The corresponding width of each class would be 5, option (a).

To determine the corresponding width of each class, we need to calculate the range of the given examination scores, which is the difference between the highest and lowest values.

The highest score in the given data is 99, and the lowest score is 11.

Range = Highest score - Lowest score

= 99 - 11

= 88

Since the range represents the total span of the scores, we can divide it by the number of classes to determine the width of each class. In this case, there are 20 students, so we have 20 classes.

Width of each class = Range / Number of classes

= 88 / 20

= 4.4

However, since we are dealing with discrete values (scores) and not continuous variables, we usually round up the width to the nearest whole number to ensure that all scores fall within a specific class interval.

Among the given choices, the closest whole number to 4.4 is 5.

Therefore, the corresponding width of each class would be 5, option (a).

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25% off means the new price of the item is 75% of the originl price ( 100% - 25% = 75%)

Multiply the original price by 75%:

20 x 0.75 = 15

The sale price is £15

S.P:25x/100

0.25x=20

x=20/0.25

x=80

Answer:

thats the equation for slope-intercept form

Step-by-step explanation:

m is the slope and b is where the line intercepts on the y axis

Answer:

linear equation

Step-by-step explanation:

happy to help ya :)

Answer:

a = 27

perimeter = 3a

= 3 * 27

= 81

Answer:

by using perimeter of rectangle 2(length +breath)

Answer:

Any quotient of polynomials a(x)/b(x) can be written as q(x)+r(x)/b(x), where the degree of r(x) is less than the degree of b(x). For example, (x²-3x+5)/(x-1) can be written as x-2+3/(x-1).

Non-normal distributions can take various forms, therefore, the correct answer is "All of the above."

A normal distribution, also known as a Gaussian distribution or bell curve, is characterized by a symmetrical shape with the majority of data points clustered around the mean, and the tails extending equally in both directions. However, real-world data often deviate from the normal distribution pattern.

Right-skewed distribution: This distribution is also known as positively skewed or right-tailed. It occurs when the tail of the distribution extends towards higher values, while the majority of the data is concentrated towards lower values.

Left-skewed distribution: Also referred to as negatively skewed or left-tailed, this distribution exhibits a tail extending towards lower values, while the bulk of the data is clustered towards higher values.

Leptokurtic distribution: Leptokurtic distributions have a higher peak and heavier tails compared to the normal distribution. They are characterized by a greater concentration of data points around the mean and a higher probability of extreme values.

Platykurtic distribution: Platykurtic distributions have a flatter shape and lighter tails compared to the normal distribution. They exhibit a lower peak and a lower probability of extreme values.

In summary, non-normal distributions encompass various shapes and characteristics, including right-skewed, left-skewed, leptokurtic, and platykurtic distributions. Therefore, all of the options provided are examples of non-normal distributions.

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The optimal values of x and y that minimize the objective-function x + y, subject to the given constraints, are x = 4 and y = 0.

We can find the corner points of the feasible region and evaluate the objective function at those points to determine the optimal solution.

Graph the constraints:

Start by graphing the inequalities:

x + y ≥ 7

5x + 2y ≥ 20

x ≥ 0

y ≥ 0

Plot the lines x + y = 7 and 5x + 2y = 20. To graph x + y = 7, plot two points that satisfy the equation, such as (0, 7) and (7, 0), and draw a line through them. To graph 5x + 2y = 20, plot two points such as (0, 10) and (4, 0), and draw a line through them.

Shade the region that satisfies the inequalities x ≥ 0 and y ≥ 0.

The feasible region will be the shaded region.

Identify the feasible region:

The feasible region is the shaded region where all the constraints are satisfied. In this case, the feasible region will be a polygon bounded by the lines x + y = 7, 5x + 2y = 20, x = 0, and y = 0.

Find the corner points:

Locate the intersection points of the lines and the axes within the feasible region. These are the corner points. In this case, we have the following corner points:

Intersection of x + y = 7 and x = 0: (0, 7)

Intersection of x + y = 7 and y = 0: (7, 0)

Intersection of 5x + 2y = 20 and x = 0: (0, 10)

Intersection of 5x + 2y = 20 and y = 0: (4, 0)

Evaluate the objective function:

Evaluate the objective function, which is x + y, at each corner point:

(0, 7): x + y = 0 + 7 = 7

(7, 0): x + y = 7 + 0 = 7

(0, 10): x + y = 0 + 10 = 10

(4, 0): x + y = 4 + 0 = 4

Determine the optimal solution:

The optimal solution is the corner point that minimizes the objective function (x + y). In this case, the optimal solution is (4, 0) because it has the smallest objective function value of 4.

Therefore, the optimal values of x and y that minimize the objective function x + y, subject to the given constraints, are x = 4 and y = 0.

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Answer:

Step-by-step explanation:

4+5(7)

4+ 35

39

I got this answer by simply plugging in the number that was given because it said a =7 I plugged in 7 instead of using a. The same goes to b it said that b=4 so then i plugged in 4 instead of using b.

By means of indefinite integrals, the solution to the differential equation is - 1 / (7 · y) = x⁴ / 4 - 85 / 21.

In this question we find the case of a differential equation that can be solved by separting each of the two variables and using indefinite integrals, that is, an equation of the form:

y' = f(y) · g(x)

If we know that f(y) = 7 · y², g(x) = x³ and y(2) = 3, then the solution to the differential equation is:

dy / dx = 7 · y² · x³

(1 / 7) ∫ dy / y² = ∫ x³ dx

- 1 / (7 · y) = x⁴ / 4 + C, where C is the integration constant.

C = - 1 / (7 · y) - x⁴ / 4

C = - 1 / (7 · 3) - 2⁴ / 4

C = - 1 / 21 - 4

C = - 85 / 21

Then, the solution to the differential equation is - 1 / (7 · y) = x⁴ / 4 - 85 / 21.

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Answer:

84

Step-by-step explanation:

Simplify the following:

6 (6 + 8)

6 + 8 = 14:

6×14

6×14 = 84:

Answer: 84

Answer:

Your correct answer is 84.

Step-by-step explanation:

6 (6+8) = (6)(14) = 84

Answer:

The answer is D.

Step-by-step explanation:

a) Plugging x = 18 gets numerator 0^2/18 = 0 that not continuous.

b) Plugging x = 18 the denomiator becomes a value/0 making it undefined.

c) Plugging x = 18 gets tan(2pi) = 0/1 which is 0

d) f(x) = 36 is should be a straight lines at y =36. I think. Best option is D.

Answer:

b) ∛7

Step-by-step explanation:

If p= 2q^3 - 1, what is the value of q when p is 13

Hence:

13 = 2q³ - 1

We add 1 to both sides

13 + 1 = 2q³ - 1 + 1

14 = 2q³

We divide both sides by 2

14/2 = 2q³/2

7 = q³

q³ = 7

We take the cube root of both sides

∛q³ = ∛7

q = ∛7

Option b is the correct option

Answer:

\(\textsf{1.} \quad 3x^2-4x+12\)

\(\textsf{2.} \quad 3x^2-8x+4\)

\(\textsf{3.} \quad 6x^3-8x+32\)

\(\textsf{4.} \quad \dfrac{3x^2-6x+8}{2x+4}\)

\(\textsf{5.} \quad 12x^2+36x+32\)

Step-by-step explanation:

Given functions:

\(\begin{cases}f(x)=3x^2-6x+8\\g(x)=2x+4\end{cases}\)

Function composition is an operation that takes two functions and produces a third function.

The composite function (f + g)(x) means to add function f(x) and g(x):

\(\begin{aligned}\implies (f+g)(x) & = f(x)+g(x)\\&=(3x^2-6x+8)+(2x+4)\\ &=3x^2-6x+2x+8+4\\ &=3x^2-4x+12\end{aligned}\)

The composite function (f - g)(x) means to subtract function g(x) from function f(x):

\(\begin{aligned}\implies (f-g)(x) & = f(x)-g(x)\\&=(3x^2-6x+8)-(2x+4)\\&=3x^2-6x+8-2x-4\\ &=3x^2-6x-2x+8-4\\ &=3x^2-8x+4\end{aligned}\)

The composite function f(x) · g(x) means to multiply functions f(x) and g(x):

\(\begin{aligned}\implies f(x)\cdot g(x) & =(3x^2-6x+8)(2x+4)\\ &=3x^2(2x+4)-6x(2x+4)+8(2x+4)\\&=6x^3+12x^2-12x^2-24x+16x+32\\&=6x^3-8x+32\end{aligned}\)

The composite function f(x)/g(x) means to divide function f(x) by function g(x):

\(\begin{aligned}\implies \dfrac{f(x)}{g(x)} & = \dfrac{3x^2-6x+8}{2x+4}\\\end{aligned}\)

The composite function f(g(x)) means to substitute the function g(x) in place of the x in function f(x):

\(\begin{aligned}\implies f(g(x))&=3(g(x))^2-6(g(x))+8\\&=3(2x+4)^2-6(2x+4)+8\\&=3(2x+4)(2x+4)-12x-24+8\\&=3(4x^2+16x+16)-12x-16\\&=12x^2+48x+48-12x-16\\&=12x^2+48x-12x+48-16\\&=12x^2+36x+32\end{aligned}\)

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The population mean is 8. Now, putting the values in the formula = (9+10+13+1+4+5)/(6-1) = 42/5. Therefore, the population variance is 4.9167.

Given,Population consists of the four members 5, 8, 9, 10.Total number of possible samples of size two which can be drawn without replacement from this population = 6.The possible samples are {5,8}, {5,9}, {5,10}, {8,9}, {8,10}, {9,10}.The sum of the values in each of the sample is as follows:{5,8} → 13{5,9} → 14{5,10} → 15{8,9} → 17{8,10} → 18{9,10} → 19Now, calculating the mean of all the possible samples of size two we get:Mean = (13+14+15+17+18+19)/6=96/6=16Therefore, the population mean is 16/2 = 8.2.

To find the population mean of a population, we use the formula;μ = ΣX/N Where,X is the value of each observation N is the total number of observations μ is the population mean .Given,Population consists of the four members 5, 8, 9, 10.Total number of observations = 4The sum of all observations = ΣX = 5+8+9+10 = 32Now, putting the values in the formula we get;μ = 32/4 = 8Therefore, the population mean is 8.To find the population variance of samples of size two, we use the  Where,N is the total number of possible samplesσ² is the population varianceS² is the sample variance of all possible samples of size two To calculate the sample variance of all possible samples of size two, we use the formula Where,X is the value of each sample  is the mean of the populationn is the size of the sampleGiven,Population consists of the four members 5, 8, 9, 10.Total number of possible samples of size two which can be drawn without replacement from this population = 6.The possible samples are {5,8}, {5,9}, {5,10}, {8,9}, {8,10}, {9,10}.First, we calculate the sample mean of all possible samples of size two using the formula Where,X is the value of each samplen is the size of the sample.

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We already know that Jackson biked k kilometers.

Maria biked 8 more kilometers than Jackson, which means that she biked

Peter biked 2 fewer kilometers than Jackson, which means that he biked

To get the total all of them biked, we add those expressions together.

Therefore by increasing  \(\alpha\) smoothing characteristics we can achieve minimum MSE which is good for forecasting in exponential smoothing.

Therefore the pattern of the data is a horizontal pattern in time series.

The given data can be summarized as follows:

Week Value

1 24

2 13

3 20

4 12

5 19

6 23

7 15

a) To calculate a two-week moving average, we first need to calculate the average of the first two weeks:

\(MA_{1}=\frac{24+13}{2}=18.5\)

Then we can calculate the moving average for the second week as follows:

\(MA_{2}=\frac{13+20}{2}=16.5\)

Similarly, we can calculate the moving averages for the rest of the weeks:

Week Value Two-Week Moving Average

1 24

2 13 18.5

3 20 16.5

4 12 16.0

5 19 15.5

6 23 21.0

7 15 19.0

The forecast for the fourth week is the moving average for the second week (16.5), and the forecast for the fifth week is the moving average for the third week (16.0), and so on. The forecast error is the difference between the forecast value and the actual value.

Week Value Two-Week Moving Average Forecast Forecast Error

1 24  

2 13 18.5  

3 20 16.5  

4 12 16.0 16.5 -4.5

5 19 15.5 16.0 3.0

6 23 21.0 15.5 7.5

7 15 19.0 21.0 -6.0

The mean squared error (MSE) is the average of the squared forecast errors:

MSE= \(\frac{(-4.5)^{2}+3^{2}+7.5^{2}+(-6)^{2}}{4}=33.375\)

The forecast for the eighth week is the moving average for the seventh week (19.0).

b) To calculate a three-week moving average, we first need to calculate the average of the first three weeks:

\(MA_{2}=\frac{24+13+20}{3}=19.0\)

Then we can calculate the moving average for the third week as follows:

\(MA_{3}=\frac{13+20+12}{3}=15.0\)

Similarly, we can calculate the moving averages for the rest of the weeks:

Week Value Three-Week Moving Average

1 24

2 13

3 20 19.0

4 12

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The equatiοn οf the line w will be equal tο y = (1/109)x + (325/109).

The definitiοn οf an equatiοn οf the line is a linear equatiοn with degree 1. X and Y are twο variables in the equatiοn fοr the line. The slοpe οf the line, which reflects the elevatiοn οf the line, is the third parameter.

The general fοrm οf the equatiοn οf the line:-

y = mx + c

m = slοpe

c = y-intercept

Given that Line, v has an equatiοn οf y=–109x–3. Perpendicular tο line v is line w, which passes thrοugh the pοint (2,3).

The slοpe οf the required line will be inverse and the οppοsite οf the given line,

m = 1/109

The intercept will be calculated as,

y = mx + b

3 = (1/109)2 + b

3 = 2/109 + b

327/109 = 2/109 + b

325/109 = b

The equatiοn οf the line is written as,

y = (1/109)x + (325/109)

Therefοre, the equatiοn οf the line w will be equal tο y = (1/109)x + (325/109).

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Answer:

12

Step-by-step explanation:

Answer:

If you are on delta math its 28.6

Step-by-step explanation:

The required proportion of side lengths is JK/LK= JM/LN.

The Side-Splitter Theorem states that if a line is parallel to one side of a triangle and intersects the other two sides, then it splits those sides proportionally. In the case of triangle J K L, with line segment M N drawn parallel to side J L and intersecting sides J K and L K, the proportion of the lengths of the sides that are split can be determined by the ratio of the corresponding segments on each side.

Let's call the length of side J K as x, the length of side J L as y, and the length of side L K as z. Let the length of segment J M be a and the length of segment L N be b.

According to the side-splitter theorem, the proportion of the length of side J K to side L K is equal to the proportion of the length of segment J M to segment L N. This means that:

x/z = a/b

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