complete combustion of 2.20 g of a hydrocarbon produced 7.16 g of co2 and 2.20 g of h2o. what is the empirical formula for the hydrocarbon? insert subscripts as necessary.

Answer:c

Explanation:

The measured pressure is lower than what the ideal gas law predicts. In that case, it is false to claim that gas molecules have small volumes in comparison to the total volume they inhabit.

Real gases have lower pressure than ideal gases because of the intermolecular forces of attraction that reduce the amount of time that gas molecules collide with container walls. The ideal gas law overestimates volume at high pressure. The pressure of the gases is quite similar to that of an ideal gas at high temperatures. However, the pressure of gases is lower than that of an ideal gas at lower temperatures. The pressure that the gas exerts on the container wall reduces as a result of the average distance between molecules getting smaller and the observed pressure is less than expected.

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It will take around 66.43 hours for 2200 grams of the radioactive substance to decay to 75 grams with a half-life of 14 hours.

The half-life formula of a radioactive substance is expressed as:

Final amount = Initial amount × (1/2)^(time/half-life)

Where, Initial amount = 2200 grams

Final amount = 75 grams

Half-life = 14 hours.

Now, putting these values in the formula,\(75 = 2200 × (1/2)^(time/14)Or, (1/2)^(time/14) = 75/2200.\)

We can write 75/2200 as 3/88 and take the log of both sides to solve for t.

The resulting equation will be:

-log2(time/14) = log2(3/88)t = -14 × log2(3/88) / log2(1/2)t = 66.43.

Therefore, it will take approximately 66.43 hours for 2200 grams of the substance to decay to 75 grams.

The half-life formula of a radioactive substance is expressed as:

Final amount = Initial amount × (1/2)^(time/half-life)

Where, Initial amount = 2200 gramsFinal amount = 75 grams.

Half-life = 14 hours Now, putting these values in the formula,\(75 = 2200 × (1/2)^(time/14)Or, (1/2)^(time/14) = 75/2200.\)

We can write 75/2200 as 3/88 and take the log of both sides to solve for t.

The resulting equation will be:-\(log2(time/14) = log2(3/88)t = -14 × log2(3/88) / log2(1/2)t = 66.43.\)

Therefore, it will take approximately 66.43 hours for 2200 grams of the substance to decay to 75 grams.

It will take around 66.43 hours for 2200 grams of the radioactive substance to decay to 75 grams with a half-life of 14 hours.

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The half-life of a radioactive substance refers to the time it takes for half of the substance to decay or transform into another element. In this case, the half-life of the radioactive substance is given as 14 hours.

To find out how many hours it will take for 2200 grams of the substance to decay to 75 grams, we can use the concept of half-life.

First, let's calculate the number of half-lives it will take for the substance to decay from 2200 grams to 75 grams.

Starting with 2200 grams, after one half-life (14 hours), half of the substance will decay, leaving us with 1100 grams. After two half-lives (28 hours), half of the remaining substance will decay, leaving us with 550 grams. Continuing this pattern, we can calculate the number of half-lives it will take to reach 75 grams.

To do this, we can use the formula:

Final amount = Initial amount * (1/2)^(number of half-lives)

Let's substitute the values:

75 grams = 2200 grams * (1/2)^(number of half-lives)

Now, let's solve for the number of half-lives:

(1/2)^(number of half-lives) = 75 grams / 2200 grams

To isolate the exponent, we can take the logarithm (base 1/2) of both sides:

log base (1/2) of (1/2)^(number of half-lives) = log base (1/2) of (75 grams / 2200 grams)

This simplifies to:

number of half-lives = log base (1/2) of (75 grams / 2200 grams)

Using a calculator, we can find that the number of half-lives is approximately 4.446.

Now, to find the total time it will take for 2200 grams to decay to 75 grams, we can multiply the number of half-lives by the length of one half-life (14 hours).

Total time = number of half-lives * length of one half-life

Total time = 4.446 * 14 hours

Total time ≈ 62.24 hours

Therefore, it will take approximately 62.24 hours for 2200 grams of the radioactive substance to decay to 75 grams.

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Answer: Organic acids form when a carboxyl group (−COOH) is substituted for one of the hydrogen atoms in a hydrocarbon.

Horner-Wadsworth-Emmons (HWE) reaction is an important synthetic reaction in organic chemistry. It is widely used for synthesizing various compounds. The reaction is between an aldehyde or ketone and a phosphonate or phosphonate ester in the presence of a strong base.

The Horner-Wadsworth-Emmons reaction is one of the most convenient and well-known methods of constructing carbon-carbon double bonds. The reaction proceeds via the formation of an ylide intermediate. The HWE reaction is particularly useful for the synthesis of compounds with a Z-configuration.

The mechanism for the reaction of diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of aqueous NaOH, forming 3,4-methylenedioxystilbene as the product, can be explained in the following steps:

Step 1: Formation of the ylide intermediate

The reaction starts with the formation of an ylide intermediate. This is achieved by the reaction of diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of a strong base like NaOH or KOH. In this reaction, a deprotonated species called an ylide intermediate is generated.

Step 2: Addition of the ylide intermediate to the aldehyde

The ylide intermediate then attacks the aldehyde, leading to the formation of a betaine intermediate.

Step 3: Formation of the phosphonate ester

The betaine intermediate undergoes elimination to form the final product, 3,4-methylenedioxystilbene, and the by-product phosphonate ester.

The mechanism of the Horner-Wadsworth-Emmons (HWE) reaction between diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of aqueous NaOH, forming 3,4-methylenedioxystilbene as the product, is complete. This reaction is significant in organic chemistry and finds applications in the pharmaceutical industry.

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The value of "n" in the hydrate formula CuSO4 * nH2O is 5.

To determine the value of "n," we need to calculate the molar ratio between the released water and the hydrate copper(II) sulfate.

First, we need to convert the mass of water released to moles. The molar mass of water (H2O) is approximately 18.015 g/mol. Therefore, 5.051 g of water is equal to 5.051 g / 18.015 g/mol ≈ 0.2804 mol.

Next, we calculate the molar ratio between water and copper(II) sulfate. The molar mass of copper(II) sulfate (CuSO4) is approximately 159.609 g/mol. From the balanced chemical equation, we know that one mole of copper(II) sulfate is associated with "n" moles of water.

Assuming that the molar ratio is 1:1 between CuSO4 and H2O, we can set up the following equation:

0.2804 mol H2O = 14.00 g CuSO4 * (1 mol H2O / (159.609 g CuSO4 * n))

By rearranging the equation, we can solve for "n":

n = 14.00 g CuSO4 / (159.609 g CuSO4/mol) = 0.0877 mol

Since "n" represents the number of water molecules, it must be a whole number. Therefore, the closest whole number to 0.0877 is 5.

Therefore, the value of "n" in the hydrate formula CuSO4 * nH2O is 5.

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Answer: hola

Explanation:Añada cinco gotas al 2 por ciento de tintura de yodo de farmacopea EE. UU. (U.S.P., por sus siglas en inglés) por cada litro de agua limpia. Para el agua turbia añada diez gotas y deje la solución reposar durante 30 minutos por lo menos.

The carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron-carbon alloy is 63.4 hours.

To determine the carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron-carbon alloy, we can use Fick's second law of diffusion:

\(DC_{surface} / 2 = (C_{surface} - C_{4mm}) / erf(x / (2 * \sqrt{Dt} ))\\\)

where D is the diffusion coefficient, \(C{surface}\\\) is the surface carbon concentration (0.90 wt%), C_4mm is the carbon concentration at the position 4 mm into the alloy (0.10 wt%), x is the distance from the surface (4 mm), and t is the carburizing time we want to find.

We can use the diffusion coefficient for γ-Fe at 1100°C from Table 5.2, which is D = \(6.0 * 10^{-12} m^2/s.\)

Substituting the given values, we get:

\((6.0 * 10^{-12} m^2/s) * (0.90 - 0.30) / 2 = (0.90 - 0.10) / erf(4 mm / (2 * \sqrt{6.0 * 10^{-12} m^2/s} ))\)

Simplifying the left-hand side, we get:

\(1.8 * 10^{-12} m^2/s = (0.80) / erf(4 mm / (2 * \sqrt{(6.0 * 10^{-12} m^2/s) * t)})))\)

Taking the inverse error function of both sides, we get:

\(erf(4 mm / (2 * \sqrt{6.0 * 10^{-12} m^2/s) * t)} ) = 0.000346\)

Substituting this back into the previous equation, we get:

\(1.8 * 10^{-12} m^2/s = (0.80) / 0.000346\)

Solving for t, we get:

t = 63.4 hours

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Answer:
Answer 1: The mass of magnesium contained in the compound is 0.57g, which can be determined by subtracting the mass of the crucible and lid (31.064g) from the mass of the crucible, lid, and magnesium ribbon (31.634g).

Answer 2: The mass of oxygen contained in the compound is 1.39g, which can be determined by subtracting the mass of the crucible, lid, and magnesium oxide (31.970g) from the mass of the crucible and lid (31.064g).

Answer 3: The change in mass between the two can be accounted for by the reaction of the magnesium with oxygen to form magnesium oxide.

Answer 4: The number of moles of magnesium is 0.0995 (2.39/24) and the number of moles of oxygen is 0.0868 (1.39/16). Dividing the moles of each element by the smallest amount of moles (0.0868) results in a simplest ratio of 1:1. Therefore, the empirical formula of magnesium oxide is MgO.

Answer 5: The known formula for magnesium oxide is MgO, which is the same as the empirical formula determined in question 4.

Answer:

This reaction could be an endothermic reaction reaction. In these reactions, heat is created, eventually being released. If the two liquids created a strong enough heat, some of the liquid could have evaporated and escaped as vapor, effectively decreasing the mass of the liquid mix. This would mean that the mass is either vapor in the air or has collected into droplets, most likely near the container of liquid

Hope this helps!

(note: I am NOT a chemist or exceptionally good at chemistry, so take that for what its worth)

Answer:

1a) .68 moles 1b)4.1E-23 molecules.

2a) .37 moles 2b) 2.27E-23 molecules

Explanation:

1a) CO2 is equal to 44 grams (C→12 grams,O→16 grams[·2]) .30g/44g is .68 moles.

1b) multiply 1A by advogadros number (6.022E-23)

2a) NaCl is 58 grams. 22/58 is .37 moles.

2b) multiply 2A by advogadros number.

you'd answer #3 the same way #1 and #2

The branch of science that deals with chemicals and bonds are called chemistry. The moles are units to calculate the quantity required to use the element.

The correct answer is mentioned below.

According to the question, the moles to the option is as follows:-

\(n =\frac{M}{M.M}\\ \\\frac{30}{44} \\\\=0.681\\\\\)

The number of molecules is \(0.68 *6022*10^{23} =4.09496*10^{23\).

2. moles of 22 grams of NaCl is

\(\frac{22}{44}\\ \\=0.5\\\\\)

Molecules will be \(0.5*6.022*10^{23} = 3.011*10^{23}\)

3. moles of 50-gram ammonia

\(\frac{50}{17} \\\\2.94\\\)

The number of molecules is \(2.94*6.022*10^{23} = 1770*10^{23\)

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Answer:

I think it is stoichiometry

The name for a positive ion is a cation.

Answer:

yes

Explanation:

because it help the body hydrate

41.7% is the percentage by mass of hydrogen (H) in lithium hydroxide (LiOH). The solution mixture is frequently defined in terms of mass percentage.

The mass percent might be used to denote a degree. Furthermore, it defines the element during a specific mixing. The solution mixture is frequently defined in terms of mass percentage. It represents the amount of solute contained in a mass m of solution.

The quantity of solutes can be stated in terms of mass or moles. We will study the percent by mass formula with numerous solved numerical examples in this post.

Mass percent = (component’s mass ÷ total mass) x 100%

                      = (1/ 23.95)x 100%

                     = 41.7%

Therefore, 41.7% is the percentage by mass of hydrogen (H) in lithium hydroxide (LiOH).

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The volume of 0.8 M solution of citric acid required would be 75mL.

Given:

Concentration of citric acid =0.8M

Mass of baking soda = 15 g

Balanced chemical equation for the reaction of baking soda(NaHCO₃ ) with citric acid (C₆H₈O₇) is:

C₆H₈O₇ + 3NaHCO₃ -----> 3H₂O + 3CO₂ + Na₃C₆H₅O₇

Therefore, 1 mole of citric acid needs 3 moles of baking soda

Molar mass of baking soda = 84g/mol

No. of moles of baking soda = mass of baking soda / molar mass of baking soda = 15g ÷ 84g/mol = 0.178 moles

Thus no. of moles of citric acid required = (1 ÷ 3) × 0.178mole =0.06mole

Molarity = no. of moles of  / volume (in mL) x 1000

Volume of citric acid solution required= (0.06mole ÷ 0.8M) × 1000ml

                                                                =75ml

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Answer:

Synthetic polymers are made up of long chains of atoms, arranged in repeating units, often much longer than those found in nature. It is the length of these chains, and the patterns in which they are arrayed, that make polymers strong, lightweight, and flexible. In other words, it's what makes them so plastic.

Explanation: i tried

A pressure saucepan, also known as a pressure cooker, reduces cooking time by increasing atmospheric pressure inside the cooking vessel. This is achieved by sealing the pot tightly and trapping steam generated from boiling liquids and food. The increased pressure raises the boiling point of water, allowing food to cook at higher temperatures than normal. Options 1 and 3 are correct.

Option 1: Increasing atmospheric pressure is correct because the sealed pressure cooker traps steam, which increases the pressure inside the pot. The increased pressure raises the boiling point of water, resulting in faster cooking times.

Option 2: Decreasing atmospheric pressure is incorrect because pressure cookers work by increasing pressure, not decreasing it.

Option 3: Increasing vapor pressure is correct because as the pressure inside the pressure cooker increases, the vapor pressure of water also increases. This higher vapor pressure enables the food to cook more rapidly.

Option 4: Decreasing vapor pressure is incorrect because the pressure cooker actually increases the vapor pressure by raising the overall pressure inside the pot.

Option 5: Ionizing the added salt is unrelated to the operation of a pressure cooker and does not contribute to the reduction in cooking time.

Hence, a pressure saucepan reduces cooking time by increasing the atmospheric pressure and vapor pressure inside the pot.

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The coordination number of cobalt in the complex ion [Co(en)Cl4]⁻ is 6.

Therefore the answer is 6.

The coordination number of a metal ion in a complex ion refers to the number of ligands (molecules or ions that bind to the metal ion) that are coordinated or bound to the metal ion. In the complex ion [Co(en)Cl4]^-, the metal ion is cobalt (Co) and the ligands are the ethylenediamine (en) and chloride (Cl) ions.

The complex ion [Co(en)Cl4]^- has six ligands coordinated to the Co ion: four chloride ions and two ethylenediamine molecules. This means the coordination number of cobalt in this complex ion is 6.

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Answer:

true, false

Explanation:

Answer:

For a mild human cough in air at 20 °C and 50% relative humidity, we found that ... larger droplets are dispersed into smaller ones gradually while moving away from the ... Complex phase change and transport phenomena such as evaporation and ... Natural Ventilation for Infection Control in Health-Care Settings

Explanation

The end products of photosynthesis are oxygen and carbohydrate.

The overall balanced eqation for photosynthesis reaction:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

CO₂ is carbon dioxide or carbon(IV) oxide

H₂O is water molecule

C₆H₁₂O₆ is carbohydrate

O₂ is oxygen molecule

Light energy is transformed into a chemical energy, that is stored in a carbohydrate molecules (glucose), which are synthesized from carbon dioxide and water.

Plants (not animals) convert a solar energy into the chemical energy of sugars (food).

The pigment chlorophyll absorbs one photon and loses one electron (it passed throw an electron transport chain) in the light-dependent reactions.

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Answer:

Please find the definition and example of neutralization reaction below

Explanation:

In chemistry, neutralization reaction is a type of reaction involving a base and an acid to form salt and water. In other words, when an acid and a base comes together chemically to form a salt and water, a neutralization reaction is said to occur.

For example; in a reaction between sodium hydroxide (NaOH) and hydrogen chloride (HCl) as follows:

HCl(aq) + NaOH(aq) → NaCl(s) + H2O(l)

In this neutralization reaction, the HCk is the acid while the NaOH is the base (reactants). For the products, the NaCl is the salt while H2O is water.

Answer:

V₂ = 545.79 mL

Explanation:

Given data:

Initial volume = 1000 mL

Initial pressure = 1 atm

Initial temperature = 273 K

Final temperature = 298 K

Final volume = ?

Final pressure = 2 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1 atm × 1000 mL × 298 K / 273 K × 2 atm

V₂ = 298000 atm .mL. K / 546 K.atm

V₂ = 545.79 mL

Answer:

this means that the movement of the galaxies in the universe are stretching and are getting bigger and the frequency of the light waves are decreasing because the wider something gets like galaxies and stuff like that that gives off light are stretching so it will become dimer because it is trying to stretch to wider surroundings and that means the light has to stretch to so the light has to cover bigger surfaces and the light can not get brighter so it has to stretch and dim its light.

Explanation:

Answer:

he universe's average temperature and rate of expansion support the idea that it began as one super-dense and hot mass 13.8 billion years ago.

Ocean tides are caused by the uneven gravitational pulls of the Moon and Sun on different parts of Earth.

Explanation:

These statements are objective truths or rational speculations adequately supported by evidence.  The others are from unreliable sources, and are based on opinion.

the answer is A!

Answer:

A and C are correct, I took the test

Explanation: