Consider the acid-base reaction and classify each of the reactants and products as an acid or base according to the Brønsted theory. CF3COOH + H20 근 H30' + CF3COO- Acid Base Answer Bank CE,CoO CF,COOH 8 9 6

1) Beryllium. This element is in the second group and the second period. The atomic number is 4 which is the number of protons.

The mass number is the sum of neutrons and protons.

Assuming the element has no charge the number of electrons is equal to the number of protons.

Protons: 4.

Neutrons: the mass number - the atomic number = 9 - 4 = 5.

Electrons: 4.

Answer:

5.71cm^3

Explanation:

Volume = mass / density

V = 7.37 / 1.29

V = 5.71cm^3

Answer:

A minor-planet moon is an astronomical object that orbits a minor planet as its natural satellite.

Explanation:

An object in an orbit is called a satellite. A satellite can be natural, like Earth or the moon. Many planets have moons that orbit them. A satellite can also be man-made, like the International Space Station.

Answer:

1.66 M

Explanation:

Molarity = moles/L solution

We have the following data:

mass NaCl = m = 63 g

volume of solution = V = 0.65 L

Thus, we first convert the mass to moles with the molar mass of NaCl (MM):

MM(NaCl) = 23 g/mol Na + 35.4 g/mol Cl = 58.4 g/mol

moles NaCl = m/MM = 63 g/(58.4 g/mol)= 1.08 mol

Finally, we divide the moles into the volume of solution to calculate the molarity:

M = moles NaCl/V = 1.66 mol/L

It will take approximately 49,580 years for 80% of the plutonium-239 isotope to decay.

To determine the time required for 80% of the plutonium-239 isotope to decay, we can use the concept of half-life. The half-life of a radioactive isotope is the time it takes for half of the initial amount of the isotope to decay.

Given that the half-life of plutonium-239 is 24,360 years, we can calculate the number of half-lives required for 80% decay. Since each half-life reduces the amount of the isotope by half, we need to find how many times we need to divide 10 g (the initial amount) by 2 to reach 80% of the original amount.

Let's calculate:

Initial amount = 10 g

Amount after one half-life = 10 g / 2 = 5 g

Amount after two half-lives = 5 g / 2 = 2.5 g

Amount after three half-lives = 2.5 g / 2 = 1.25 g

Amount after four half-lives = 1.25 g / 2 = 0.625 g

We can see that after four half-lives, the amount remaining is less than 20% of the initial amount. Since each half-life is 24,360 years, the time required for four half-lives is approximately 97,440 years. Therefore, it will take approximately 49,580 years (97,440 years - 47,880 years) for 80% of the plutonium-239 isotope to decay.

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It can only occur in metals, having HCP or BCC crystal structures.

The statement that is not correct about twinning is: E.

In crystallography, twinning is the occurrence of two or more crystal structures with the same or nearly same atomic arrangements that are intergrown. Twinning is a phenomenon in which crystal lattices form "mirror image" intergrowths.Twinning can happen in any crystal structure, including face-centered cubic (FCC) and body-centered cubic (BCC) structures. As a result, statement E, which states that twinning can only occur in metals with HCP or BCC crystal structures, is incorrect. Statement A is correct because wide bands appear under a microscope, and these bands cannot be eliminated by polishing.

Statement B is also accurate because atoms in specific plans move more than one atomic spacing, which is known as shear. Statement C is true because when twinning occurs, crystallographic planes shift their orientation to produce a new crystal arrangement. Statement D is also correct because there is no shear stress threshold required to initiate atomic motion during twinning. Finally, statement F is incorrect because not all of the above statements are incorrect; rather, only one of them is wrong. Therefore, the correct option is E.

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The molecules which are bounded to hemoglobin when hemoglobin is in the r state are oxygen molecules.

Hemoglobin abbreviated as  Hb or Hgb, is the iron-containing oxygen-transport metalloprotein present in red blood cells (erythrocytes) of almost all vertebrates as well as the tissues of some invertebrates. Hemoglobin in blood carries oxygen from the respiratory organs (e.g. lungs or gills) to the rest of the body (i.e. tissues).

There it releases the oxygen to permit aerobic respiration to provide energy to power functions of an organism in the process called metabolism. A healthy individual human has 12 to 20 grams of hemoglobin in every 100 mL of blood.

In mammals, the chromoprotein makes up about 96% of the red blood cells' dry content (by weight), and around 35% of the total content (including water).

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Answer:

Something that's interdisciplinary covers more than one field of study. If you take an interdisciplinary science and literature class, you might read a science fiction novel and then explore the scientific ideas behind it. ... Interdisciplinary means between fields, but they don't have to be unrelated disciplines.

Explanation:

hope this helps:)

In the absence of a parallel collimator during SPECT imaging, the gamma rays emitted from the source would travel in multiple directions and result in blurred and scattered images.

A parallel collimator is used in order to localize the source of gamma emission during SPECT imaging. This is necessary because, in the absence of the collimator, the gamma photons emitted from different points in the source would reach the detector without any directionality, leading to blurred and indistinguishable images. The parallel collimator ensures that only gamma photons traveling parallel to the collimator's axis reach the detector, creating a clearer and more accurate representation of the gamma emission source.

The collimator is designed to only allow gamma rays that are traveling parallel to the collimator's axis to pass through, thus creating a focused beam and allowing for accurate localization of the source of gamma emission.

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A pair of water samples are taken from a well bored into a large underground salt deposit. These samples will likely have different properties compared to regular groundwater sources due to the presence of salt. The first sample, closer to the surface, may have a lower salt concentration as it is diluted by rainwater and runoff.  

The salt concentration can be measured using methods such as conductivity or salinity tests. Additionally, the pH level, temperature, and other chemical parameters can also be analyzed to understand the water quality. These samples provide valuable information about the water source and its suitability for various uses, such as drinking, agriculture, or industrial purposes.

In summary, the water samples taken from the well bored into a large underground salt deposit will likely have different salt concentrations based on their depth in the well and proximity to the salt deposit.

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Answer:

Bakelite is made from the reaction between formaldehyde and phenolic materials at high temperatures. Bakelite is used for wire insulation, break pads and other automotive parts, and other electronics components.

Answer:

Magnetic fields  and Electric fields

Explanation:

Answer:

6.273×10²³

Explanation:

hope this is useful friend

Answer:

6.023 × 10²³

Explanation:

Avogadro's number is used for calculating masses and moles and can applied to Stoichiometry. Avogadro's number is useful for atoms and molecules

Option C, a more saturated fat is the product(s) for the hydrogenation of corn oil.

Organic molecules are frequently reduced or saturated by the process of hydrogenation, which is a chemical reaction between hydrogen (H2) and another substance or element. The process of incorporating hydrogen molecules into the various carbon-carbon bonds is known as hydrogenation. Saturated fats emerge from this process. Double bonds change into single bonds throughout this Saturated fats, and the melting point steadily increases.

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The treatment step involves heating the crude oil in a furnace and then passing it through a distillation column.

During the treatment step in refining crude oil for energy use, the crude oil is processed to remove impurities and separate it into different components based on their boiling points. This step is also known as the refining or distillation process.

The treatment step involves heating the crude oil in a furnace and then passing it through a distillation column. The column has a series of trays or plates, each with a different temperature, which causes the different components of crude oil to vaporize and rise up the column.

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Answer:

Wavelength = 0.06024 m

Explanation:

Equation of energy of wavelength from Einstein's relativity equation is;

E = hc/λ

Where;

h is Planck's constant = 6.626 × 10⁻³⁴ J. s

c is speed of light = 3 × 10⁸

We are given E = 3.3 × 10^(-24) J

Making wavelength λ the subject, we have;

λ = hc/E

Thus;

(6.626 × 10⁻³⁴ × 3 × 10⁸)/(3.3 × 10^(-24)) = 6.024 × 10^(-2) = 0.06024 m

Wavelength = 0.06024 m

Answer:

3.8857037037g per cm3

Explanation:

52.357g/13.5 cm3 = 3.8857037037

Round if needed

Answer:

b is the answer my brudaa

Explanation:

The approximate normal boiling point of 2-chloroheptane can be determined using a vapor pressure nomograph. Given that the boiling point of 2-chloroheptane is 46 °C at 19 mmHg, we can use the nomograph to estimate the boiling point at normal atmospheric pressure.

1. The vapor pressure nomograph is a graphical representation that relates the boiling point and vapor pressure of a substance at different pressures. To estimate the normal boiling point, we need to determine the vapor pressure at standard atmospheric pressure (760 mmHg) using the given data.

2. On the vapor pressure nomograph, locate the point representing 19 mmHg on the y-axis and draw a horizontal line to intersect with the diagonal line representing the normal boiling point. From this intersection, draw a vertical line down to the x-axis to determine the temperature corresponding to 19 mmHg.

3. By estimating the intersection point, we find that the temperature is approximately 46 °C at 19 mmHg. Since the normal boiling point is defined as the boiling point at atmospheric pressure (760 mmHg), we can approximate the normal boiling point of 2-chloroheptane to be around 46 °C.

4. It's important to note that the accuracy of this approximation depends on the precision and reliability of the vapor pressure nomograph used.

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The energy difference between the [H<--->H]eclipsed and [CH3<--->CH3]gauche conformations is 0.2 KJ/mol.

The total energy difference between the two conformations can be calculated by adding the Letimes energy to the energy difference between [H<--->H]eclipsed and [H<--->CH3]eclipsed, and subtracting the energy difference between [CH3<--->CH3]gauche and [H<--->CH3]eclipsed.

Thus, the total energy difference is:

Letimes + [H<--->CH3]eclipsed - [CH3<--->CH3]gauche - [H<--->H]eclipsed

= 11 KJ/mol + 6 KJ/mol - 3.8 KJ/mol - 4 KJ/mol

= 9.2 KJ/mol

Therefore, the energy difference between the [H<--->H]eclipsed and [CH3<--->CH3]gauche conformations is 9.2 KJ/mol. However, the question asks for the energy difference between the [H<--->H]eclipsed and [CH3<--->CH3]gauche conformations only.

Therefore, we need to subtract the energy difference between [H<--->CH3]eclipsed and [CH3<--->CH3]gauche to get the answer:

[H<--->H]eclipsed - [CH3<--->CH3]gauche = 4 KJ/mol - 3.8 KJ/mol = 0.2 KJ/mol

Hence, the energy difference between the [H<--->H]eclipsed and [CH3<--->CH3]gauche conformations is 0.2 KJ/mol.

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Answer:

1. Chief executive officer = Nucleus.

2. Power house = Mitochondrion.

3. Maintenance team = Lysosomes.

4. Functional managers = Chromosomes.

5. Assembly line workers = Ribosomes.

6. Assembly line = Endoplasmic Reticulum.

7. Security and support = Cytoskeleton.

8. Drivers or messengers = Vesicles.

9. Packaging unit = Golgi apparatus.

10. Gate man/procurement unit = Cell membrane.

Explanation:

A cell can be defined as the structural, fundamental, biological and functional unit of life. Cells are found in all living organisms because they are the basic unit of life.

Generally, cells have the ability to independently replicate themselves. These cells can be compared to the kind of structures found in a business or factory, where you have different workers performing different functions.

In a cell, the "workers" that perform various functions or tasks for the survival of the living organism are referred to as organelles.

Factory worker = Cell organelle.

1. Chief executive officer = Nucleus.

The nucleus controls all the activities taking place in the cell and the synthesis of proteins.

2. Power house = Mitochondrion.

The mitochondria provides all the energy required in the cell by transforming energy forms.

3. Maintenance team = Lysosomes.

They are responsible for absorbing materials and breaking the materials taken in by the cells.

4. Functional managers = Chromosomes.

They give sets of instructions for the synthesis of products.

5. Assembly line workers = Ribosomes.

They are involved in the build up of proteins.

6. Assembly line = Endoplasmic Reticulum.

This is where the ribosomes perform their tasks.

7. Security and support = Cytoskeleton.

They help to maintain and support the shape of the cells.

8. Drivers or messengers = Vesicles.

They ensure proteins are properly transported to the right and exact location.

9. Packaging unit = Golgi apparatus.

Prepares the protein for export by chemically tagging them.

10. Gate man/procurement unit = Cell membrane.

It is the wall of the cell and typically controls what leaves and enters the cell.

Answer:

H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O).

Explanation:

The ratio of the concentrations in this solution of conjugate acid of Tris to the base form of Tris is 1:10.

Tris is a primary amine with a pKa of 8.3. At pH 7.3, Tris is mostly in its base form, with little of the Tris being protonated and thus forming the conjugate acid of Tris. As pH is less than pKa, the protonation of Tris is less favored than the deprotonation process.

The equilibrium expression is given below;

C₈H₁₁NO₃ + H₂O ⇌ C₈H₁₁NO₃  + H₃O+

In this equilibrium expression, C₈H₁₁NO₃  is Tris (which can act as either an acid or a base), and C₈H₁₁NO₃  is the conjugate acid of Tris.

Since Tris is a base, C₈H₁₁NO₃  is also the base form of Tris. The acidic form of Tris is C₈H₁₁NO₃ +. We can set up the equilibrium constant expression

(Ka) as;Ka = [C₈H₁₁NO₃ +][OH-] / [C₈H₁₁NO₃ ]

At pH 7.3, [OH-] = 10^-7.3. Thus;

Ka = [C₈H₁₁NO₃ +][10^-7.3] / [C₈H₁₁NO₃ ]

At equilibrium, [C₈H₁₁NO₃ ] will be equal to [OH-] since Tris is acting as a base and accepting H+.

Thus; Ka = [C₈H₁₁NO₃ +][10^-7.3] / [OH-]

We can then rearrange this equation to solve for the ratio of the concentrations in this solution of the conjugate acid of Tris to the base form of Tris.

C₈H₁₁NO₃ + + H₂O ⇌ C₈H₁₁NO₃  + H₃O+1 + 10^(pKa-pH) / 10^-pH

pKa -pH = log (1/10) = -1pKa - pH = -1pH = 7.3pKa = 8.3

Therefore;1 + 10^(8.3 - 7.3) / 10^-7.3 = 1 + 10¹ / 5.01187 × 10⁻⁸⁰ = 199147.54

Thus, the ratio of the concentrations in this solution of conjugate acid of Tris to the base form of Tris is 1:10.

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Answer: C: Texture change is not a clue that a chemical reaction is taking place.

Explanation: During a chemical reaction, the atoms in the reactants rearrange to form new products. This process can result in the formation of a solid, a change in color, or the formation of a new substance. However, the texture of the substances involved in the reaction may or may not change, and it is not a reliable indicator of a chemical reaction.

Therefore, the correct answer is C.

Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

Answer:

sulfur is found in group 16 period 3

Answer:

i belive the answer you are looking for is A.. hope this helps!

Explanation:

im not really 100% certain of this answer due to the fact i am a little rusty.