Cups are sold 6 to a package and plates are sold 8 to a package. If you want to have the same number of each item for a party, what is the least number of packages of each you need to buy? I need to find the greatest common factor or least common multiple
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Answer:

21

Step-by-step explanation:

Since the girls have the same age, let their age be x.
Then, their average is

\(\frac{x+x}{2} = \frac{2x}{2} = x\)

Let \(S_{i}\) denote the age of 'i' girls.
Then, \(S_{8} = S_{6} + x + x - eq(1)\)

Also, we have,

\(\frac{S_{8}}{8} =15 - eq(2)\)

\(\frac{S_{6}}{6} =13 - eq(3)\)

Then eq(2):

(from eq(1) and eq(3))

\(\frac{S_{6} + 2x}{8} =15\\\\\frac{13*6 + 2x}{8} = 15\\\\78+2x = 120\\\\2x = 120-78\\\\x = 21\)

The average of the other two girls with equal age​ is 21

Answer:

Round (n-value):   0.      1.       2.     3.    4.

# of Teams (aₙ): 1024, 512,  256,  128,  64

Step-by-step explanation:

aₙ = a₁ · r ⁿ⁻¹

Someone please correct me if I'm wrong.  I learned this very recently.

Answer:

a) rs 3000

b) rs 16800

a) rs 1600

b) rs 4000

main answer:  YES,the image formed is reflection from the origin is same

supporting answer :A reflection is referred to as a flip in geometry. A reflection is the shape's mirror image. The line of reflection is formed when an image reflects through a line. A figure is said to reflect another figure when every point in one figure is equidistant from every point in another figure. The reflected image should be the same shape and size as the original, but it should face in the opposite direction. Translation can also occur as a result of changes in position. The original image is referred to as the pre-image, and its reflection is referred to as the image. The pre-image and image are represented by ABC and A'B'C', respectively. The reflection transformation can be applied to the coordinate system (X and Y).

body of the answer: given the ponts p(1,2)

              p⁰=(-1,-2)

              p¹=(1,-2)

              p¹¹=(-1,-2)

here p⁰=p¹¹

final answer: therefore the image formed is reflection from the origin is SAME

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YES, the image formed is reflection from the origin is same.

A reflection is referred to as a flip in geometry. A reflection is the shape's mirror image. The line of reflection is formed when an image reflects through a line. A figure is said to reflect another figure when every point in one figure is equidistant from every point in another figure. The reflected image should be the same shape and size as the original, but it should face in the opposite direction. Translation can also occur as a result of changes in position. The original image is referred to as the pre-image, and its reflection is referred to as the image. The pre-image and image are represented by ABC and A'B'C', respectively. The reflection transformation can be applied to the coordinate system (X and Y).

Given the points p(1,2)

p⁰=(-1,-2)

p¹=(1,-2)

p¹¹=(-1,-2)

here p⁰=p¹¹

Therefore the image formed is reflection from the origin is SAME

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To solve this problem, we need to find the x-values where the curve intersects the x-axis, which occurs when y=0.
0=x²-2kx ,We can factor out an x: 0=x(x-2k) .So the x-intercepts are at x=0 and x=2k.

To find the value of k, we need to follow these steps:

Step 1: Find the points of intersection between the curve y = x^2 - 2kx and the x-axis.
To do this, set y = 0:
0 = x^2 - 2kx
x(x - 2k) = 0

This means that the curve intersects the x-axis at x = 0 and x = 2k.

Step 2: Determine the limits of integration.
Since we are looking for the region in the fourth quadrant, we will have limits 0 and 2k for our integration.

Step 3: Calculate the area using integration.
Area = ∫[0 to 2k] (x^2 - 2kx) dx

Step 4: Solve the integral.
Area = [1/3x^3 - kx^2] evaluated from 0 to 2k
Area = (1/3(2k)^3 - k(2k)^2) - (1/3(0)^3 - k(0)^2)
Area = (8k^3/3 - 4k^3)

Step 5: Set the area equal to 36 and solve for k.
36 = 8k^3/3 - 4k^3
36 = (8k^3 - 12k^3)/3
36 = -4k^3/3

Now, multiply both sides by 3 and divide by -4:
-108/-4 = k^3
27 = k^3

Take the cube root of both sides:
k = 3

The value of k is 3 (Option b).

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The total cost of repayment over 5 years is $23,300.

A loan repayment refers to the act of paying back money previously borrowed from a lender.

To get total cost of repayment, we must principal amount, the interest rate and the duration of the loan.

The formula to get total cost of repayment is given by \(Total Cost of Repayment = Principal + Interest\)

Interest = Principal * Interest Rate * Time

Given:

Principal amount is $20,000

Interest rate is 3.3%

Duration is 5 years.

Interest = $20,000 * 0.033 * 5

Interest = $3,300

Total Cost of Repayment = Principal + Interest

= $20,000 + $3,300

= $23,300.

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Answer:

A) 1/5

Step-by-step explanation:

Points on the graph: (10, 2) and (20, 4)

Slope:

m=(y2-y1)/(x2-x1)

m=(4-2)/(20-10)

m= 2/10

m = 1/5

Answer:

\(\Huge \boxed{\mathrm{No }}\)

\(\rule[225]{225}{2}\)

Step-by-step explanation:

Prime numbers have two factors, 1 and the number itself.

Factors of 123 are 1, 3, 41, 123.

123 has 4 factors, it is not a prime number.

\(\rule[225]{225}{2}\)

Answer:

No

Step-by-step explanation:

This is because it has factors other than 1. The factors of 123 are 1, 3, 41, and 123.

Answer:

9. y=6x+4

10. y=-1/3x-2

11. y= 2/3x

12. y=-3/2x+2

13. y=2/3x+4/3

14. y=1/2x-3

Step-by-step explanation:

For 9-10, the slope is always x, the y-intercept is the numbers at the end.

11-12: See how much it takes to move up, and then right. That'll be the fraction. Up 2, right 3.

13-14= Graphing cal. from Desmos.

The first five terms of the sequences are 2, 3, 5, 9, 17. and 1, 4, 7, 10, 13

Using the formula, an = 2an-1 - 1 where a1 = 2, we can find the first few terms of the sequence as follows:

a2 = 2a1 - 1 = 2(2) - 1 = 3

a3 = 2a2 - 1 = 2(3) - 1 = 5

a4 = 2a3 - 1 = 2(5) - 1 = 9

a5 = 2a4 - 1 = 2(9) - 1 = 17

Therefore, the first five terms of the sequence are: 2, 3, 5, 9, 17.

For the second sequence, the first five terms are

1, 4, 7, 10, 13

Because the common difference is 3

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Domain of function =  {-3 , -4}

Range of function =  {4 , -1 , -4}

The domain of a function is the set of values that we are allowed to plug into our function. This set is the x values in a function such as f(x). The range of a function is the set of values that the function assumes. This set is the values that the function shoots out after we plug an x value in.

Given,

points on graph of a function are

(-3 , 4) , (-3 , -1) , (-4 , -4)

Range is set of y-values,

Range = {4 , -1 , -4}

Domain is set of x - values

Domain = {-3 , -4}

Hence, Domain and range of function are {-3 , -4} and {4 , -1, -4} respectively.

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Answer:

128

Step-by-step explanation:

Add the two numbers then subtract from 360

Answer:

3 out of 4

Step-by-step explanation:

the denominator represent the whole number and numerator represent the amount

Answer: I THINK it’s A

Step-by-step explanation:

Answer:

C. 40%

Step-by-step explanation:

8 - black

12 - red

total: 20

8/20 = 40%

Answer:

0 is the answer on 16 x 64y

Answer:

1  x = 4      y= 2/3  = 1. 66667   see attached and join the lines to create shaded area.

Step-by-step explanation:

2x -3y = 3

16x (64y) = ?

we can multiply the 2x by 8 to find x = 16 and -3y = -24y and 3 = 24

as shown 2nd one.

16x + (64y) =  c

16x -24y = 24    =   64y - 24y = c

40y = c - 24

40y/24 = y

1.66667 = y

y = 1.6667 or  1  2/3

2x -3 (  1 2/3 ) = 3

2x - 5 = 3

2x = 8

x = 4

y = 1. 66657

Answer: Nueve

Step-by-step explanation: Si cuadras el número nueve obtendrás ochenta y uno. Agregue once a eso y obtendrá noventa y uno.

¿Brainliest por favor?

Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.

To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.

3 messages are classified as "Normal."

1 message is classified as "Spam."

We calculate the probabilities as follows:

P(Class = Normal) = 3/4 = 0.75

P(Class = Spam) = 1/4 = 0.25

Next, we analyze the occurrence of words in each class:

For the "Normal" class:

The word "Chinese" appears 5 times.

The word "Beijing" appears 1 time.

The word "Shanghai" appears 1 time.

The word "Macao" appears 1 time.

For the "Spam" class:

The word "Tokyo" appears 1 time.

The word "Japan" appears 1 time.

The word "Chinese" appears 1 time.

Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):

P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9

P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7

To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:

P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)

≈ (6/9) * (0/9) * (0/9) * 0.75

= 0

P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)

≈ (2/7) * (2/7) * (2/7) * 0.25

≈ 0.017

Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.

In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.

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Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.

To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.

3 messages are classified as "Normal."

1 message is classified as "Spam."

We calculate the probabilities as follows:

P(Class = Normal) = 3/4 = 0.75

P(Class = Spam) = 1/4 = 0.25

Next, we analyze the occurrence of words in each class:

For the "Normal" class:

The word "Chinese" appears 5 times.

The word "Beijing" appears 1 time.

The word "Shanghai" appears 1 time.

The word "Macao" appears 1 time.

For the "Spam" class:

The word "Tokyo" appears 1 time.

The word "Japan" appears 1 time.

The word "Chinese" appears 1 time.

Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):

P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9

P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7

To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:

P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)

≈ (6/9) * (0/9) * (0/9) * 0.75

= 0

P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)

≈ (2/7) * (2/7) * (2/7) * 0.25

≈ 0.017

Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.

In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.

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Answer:

16. 108°

17. 40°

18. 50°

19. 18°

20. 60°

Answer:

16. y=108 180-36-36=108

17. w=40. 180-23-117=40

18. x=50. 30+2x+x=180

19. y=18. 4y+y+90=180

20. w=60. w+w+10+50=180

Step-by-step explanation:

all of the angles in a triangle need to add up to 180

Using similar triangle theorem, to calculate the ratios of the length, the value of x is 14.4 units

The similar triangle theorem, also known as the AA (angle-angle) similarity theorem, states that if two triangles have two corresponding angles that are congruent, then the triangles are similar. That is, the corresponding sides of the triangles are in proportion, and the ratios of the corresponding sides are equal. In other words, if ΔABC ~ ΔDEF, then:

AB/DE = BC/EF = AC/DF

This theorem can be used to solve problems involving similar triangles, such as finding unknown side lengths or angles.

To find the value of x, we need to apply similar triangle theorem.

Taking the ratios of sides from the two triangles;

13.5 / 6.2 = x / 6.6

Cross multiply both sides and solve for x

x = (13.5 * 6.6) / 6.2

x = 14.4 units

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Answer:

14

Step-by-step explanation:

400 gallons of water are used everyday.

To determine the quantity or percentage of something in terms of 100, use the percentage formula. Per cent simply means one in a hundred. Using the percentage formula, a number between 0 and 1 can be expressed. A number that is expressed as a fraction of 100 is what it is. It is mostly used to compare and determine ratios and is represented by the symbol %.

Given:

Percentage of water used for cleaning= 16.8%

Gallons of water used for cleaning= 67.2

Let the number of gallons used everyday be represented by g. Then,

16.8 % of g = 67.2

16.8/100 × g = 67.2

0.168 × g = 67.2

g= 400 gallons

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Answer:

240

Step-by-step explanation:

Answer:

16 m^3

Step-by-step explanation:

Question:

"a regular square pyramid is 3m height and the perimeter of its base is 16m find the volume of the pyramid"

volume of pyramid = (1/3) * (area of base) * height

The perimeter of the base is 16 m, and the base is a square.

perimeter of square = 4 * side

4 * side = 16 m

side = 4 m

area of square = (side)^2

area of base = (4 m)^2 = 16 m^2

volume of pyramid = (1/3) * (area of base) * height

volume = (1/3) * (16 m^2) * 3 m

volume = 16 m^2

Answer:

2x=100 2*50=100 the answer correct 50

Step-by-step explanation:

You can use this app is call symbols and it's completely free.

Hope this helps

The p-value of the given hypothesis is; 0.9999

The formula for the z-score of proportions is;

z = (p^ - p)/√(p(1 - p)/n)

where;

p^ is sample proportion

p is population proportion

n is sample size

We are given;

p^ = 15% = 0.15

p = 20% = 0.2

n = 5000

Thus;

z = (0.15 - 0.2)/√(0.2(1 - 0.2)/5000)

z = -8.8388

From p-value from z-score calculator, we have;

P(Z < -8.8388) = 1 - 0.0001 = 0.9999

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