damping is negligible for a 0.150kg object hanging from a light, 6.30n/m spring. a sinusoidal force with an amplitude of 1.70n drives the system. at what frequency will the force make the object vibrate with an amplitude of 0.440m ?\

Answer:4 and 5

Explanation:it you add 1+3 and 2+3 it is 4 and 5

Answer: 20 minutes

Explanation:

Given the following :

Average speed of train = 120km/hr

Distance = 40km.

The time take by the train moving at an average speed of 120km/hr to cover a distance of 40km due is ;

Recall:

Speed = distance / time

Therefore,

Time taken = distance covered / speed

Time taken = 40km / 120km/hr

Time taken = 1/ 3 hr

Therefore, 1/3 rd of an hour equals

1/3 × 60 = 20 minutes.

Time taken) 20 minutes

Time taken by tain to cover distance is 20 minutes as:

Distance= 40 km

Speed= 120 km/h

Time= distance/speed

= 40/120

= 1/3 hour

= 20 min

or  =0.33 hrs

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Answer:

→They are the followings :

This are some points that teacher should have mentally.

The line or boundary that forms when two air masses with different temperatures or humidity levels meet is called a front.

A front is a boundary or transition zone that separates two air masses with different characteristics such as temperature, humidity, and density. When two different air masses meet, they do not mix readily due to their different properties, and a front is formed at their boundary. Fronts can be classified into four types: cold fronts, warm fronts, stationary fronts, and occluded fronts, based on the direction of movement and the characteristics of the air masses involved. Fronts are important in weather forecasting as they can cause significant changes in the weather conditions, such as the development of thunderstorms, rain, or snow.

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According to Newton's second law of motion, acceleration is directly proportional to the net force applied to an object and inversely proportional to its mass. Therefore, in order to have the smallest acceleration, we would need to have the smallest net force applied to the object and/or the largest mass.

So, the set of conditions that would result in the smallest acceleration are:

Smallest net force: If the net force applied to an object is small, it will result in a smaller acceleration. For example, if a car is moving at a constant speed on a level road, the net force on the car is zero, and the acceleration is also zero.

Largest mass: If the object has a large mass, it will require a larger force to produce the same acceleration.

Answer:

O2 has two more electrons compared to N2, with extra 2 electrons in the higher energy anti-bonding orbitals known as Diradical. These electrons have higher energy and are unpaired; therefore, O2 is more reactive

Explanation:

Answer:

O B. Oxygen needs to gain only 2 electrons to have a full octet, while nitrogen needs to gain 3.

Explanation:

The magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.

The magnitude of the force required to stop the weight in 0.333 seconds is calculated by applying Newton's second law of motion as shown below;

F = ma

F = m(v/t)

F = (mv)/t

F = (5 x 4.5)/0.333

F = 67.6 N

Thus, the magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.

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It is TRUE that loose and granular particles assume a stable slope known as the angle of repose.

The angle of repose refers to the maximum angle at which a pile of unconsolidated granular material can remain stable without collapsing or sliding. It is the result of the balance between gravitational forces pulling the particles downward and the frictional forces between the particles. The angle of repose varies depending on factors such as the size, shape, and cohesion of the particles. For example, fine sand typically has a lower angle of repose compared to larger, more angular particles like gravel. Understanding the angle of repose is important in various fields such as engineering, geology, and materials handling to assess the stability and flow characteristics of granular materials.

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Answer: The advantage is it doesn't tip over as quickly therefore the rider is less likely to get hurt. The disadvantage is the rider won't be able to learn how to balance because they didn't use the bicycle and the tricycle already balanced for you.

Explanation:

Hope this helps comment if you need more help!

The change in the kinetic energy of the monster truck during the time is 507500 J and the right option is B). 507500

Kinetic energy is the energy of a body due to its motion.

To calculate the increase in the kinetic energy of the monster truck, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The increase in the kinetic energy of the monster truck during the time is 507500 J and the right option is B). 507500.
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The net force acting on the crate is determined as 176 N to the left.

The net force acting on the crate is calculated as follows;

∑F = F1 + F2 + F3 + F4

F(net) = -440y + 176x + 440y - 352x

F(net) = -176 x

The resultant force is pointing in negative x direction.

Thus, the net force acting on the crate is determined as 176 N to the left.

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The branches that sometimes occur along the length of an axon are called axon collaterals.

Axon collaterals are the branches that occasionally emerge from the main axon shaft. They can extend at various points along the axon's length and allow for communication between different neurons or neuronal circuits. Axons are long, slender projections of nerve cells responsible for transmitting electrical impulses, known as action potentials, away from the cell body. These axonal branches or collaterals can diverge and form connections with other neurons, enabling the transmission of signals to multiple targets simultaneously.

Axon collaterals play a vital role in neuronal communication and the integration of information within the nervous system. They provide a mechanism for branching connectivity, allowing a single axon to relay signals to multiple target cells. This branching architecture enables the coordination and synchronization of neural activity across different regions of the brain and facilitates complex information processing. Axon collaterals contribute to the extensive network of interconnected neurons, forming the basis for neural circuits and enabling the transmission of information throughout the nervous system.

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Answer:

When a switch is closed, electrons move through a circuit from the negative side of a battery to the positive side

Explanation:

Note that current is marked to flow from positive to negative on circuit diagrams, but that's for historical reasons only. Benjamin Franklin did a fabulous job of understanding what was going on, but no one yet knew about protons & electrons, so he assumed current was flowing from positive to negative.

However, what really happens is electrons flow from negative (where they repel each other) to positive (where they are attracted).

As electrons flow through a circuit, they need 'something to do'. In many cases, that something is to light a bulb or heat an element, such as an element on a stove. So, the energy of an electron can be converted to heat or light.

I hope I'm understanding your question correctly

Answer & Explanation:

In science, rationality and creativity work together. Creativity allows us to view and solve problems with innovation and openness. Scientific theories often came from sparks of creative thinking and bold yet logical processes.

Cell potential (Ecell) for the \(Sn^4^+ (1.5m) + Zn\) gives \(Sn^2^+ (0.5m) + Zn^2^+ (2m) Ecell = 0.80v\) is  0.80554 V. If the concentration of \(Sn^4^+\) increases, the cell potential Ecell will increase.

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Sure, here is a table that shows conversions from mph to ft/s:

mph    |    ft/s
-----------------
0      |     0  
5      |   7.33  
10     |  14.67  
15     |  22    
20     |  29.33  
25     |  36.67  
30     |  44    
35     |  51.33  
40     |  58.67  
45     |  66    
50     |  73.33  
55     |  80.67  
60     |  88    
65     |  95.33  

As you can see, the mph column starts at 0 and increments by 5 mph until it reaches 65 mph, which is the last line in the table. The ft/s column shows the corresponding speed in feet per second, based on the conversion factor of 1 mi = 5,280 ft.

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Answer:

0.0299 N

Explanation:

Applying,

F = Gmm'/r²................... Equation 1

Where F = gravitational force between the boulders, m = mass of the first boulder, m' = mass of the second boulder, r = distance between the boulders, G = Universal constant.

From the question,

Given: m = 7.5×10⁶ kg, m' = 9.2×10⁵ kg, r = 124 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 1

F = (6.67×10⁻¹¹× 7.5×10⁶ × 9.2×10⁵ )/124²

F = (460.23)/15376

F = 0.0299 N

Answer:

0.3 N

Explanation:

Plug in all your variables:

6.67 ⋅ 10^-11 (7.5 ⋅ 10^6) (9.2 ⋅ 10^5)

                    --------------------------------

                                 (124)^2

Once you plugin, You start to multiple solving to solve your problem:

460.23

----------      = 0.02993171 N

15376

Now Simplify:

Answer = 0.03 N

a)

We use the formula :

m1v1i + m2v2i = m1v1f + m2v2f

Substituting the values in:

4.0kg*8.0m/s + 4.0kg*0m/s = 4.0kg*0m/s +4.0kg*v2f

Calculating this we get:

32.0kg*m/s + 0kg*m/s = 0kg*m/s + 4.0kg*v2f

Rearrange for v2f:

v2f = \(\frac{32.0kg*m/s}{4.0kg}\)

This gives us 8.0 m/s as the final velocity of the second ball.

b)

Since the collision is assumed to be elastic it means that the kinetic energy must be equal before and after the collision.

This means we use the formula:

Ek = \(\frac{1}{2} *m*v^{2}\)+ \(\frac{1}{2} *m*v^{2}\) = \(\frac{1}{2} *m*v^{2}\) +  \(\frac{1}{2}*m*v^{2}\)

Substituting in values:

Ek = 0.5*4.0kg*(8.0m/s)^2 + 0.5*4.0kg*(0m/s)^2 = 0.5*4.0kg*(0m/s)^2 + 0.5*4.0kg*(8.0m/s)^2

This simplifies to:

Ek= 128J + 0J = 0J + 128J

This shows us that the kinetic energy is equal on each side therefore the collision is Elastic and no energy has been lost.

The final velocity of the second ball after collision is 8 m/s.

The total kinetic energy of the balls before and after collision is the same.

The given parameters;

Apply the principle of conservation of linear momentum to determine the final velocity of the second ball.

\(m_1u_1 + m_2u_2 = m_1v_1 + m_2 v_2\\\\4(8) + 4(0) = 4(0) + 4(v_2)\\\\32 = 4v_2\\\\v_2 = 8 \ m/s\)

The final velocity of the second ball after collision is 8 m/s.

The total kinetic energy of the balls before collision is calculated as follows;

\(K.E_i = \frac{1}{2} \times 4 \times 8^2 \ + \ \frac{1}{2} \times 4 \times 0^2\\\\K.E_i = 128 \ J\)

The total kinetic energy of the balls after collision is calculated as follows;

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The center of mass of a thin plate with constant density δ covering a given region can be found by integrating the product of the density function and the position coordinates over the region and then dividing by the total mass. The region is bounded by the given curves or lines, and the density function is given as a constant or a function of x and/or y.

To find the center of mass, we need to calculate the following integrals:

Integrate δ * x over the region and then divide by the total mass.

Integrate δ * y over the region and then divide by the total mass.

The result of these integrals will give us the x-coordinate and y-coordinate of the center of mass, respectively. The density of the thin plate is given as a constant δ or a function of x and/or y. The center of mass will be located at the point (x, y) that satisfies the above integrals. The exact coordinates of the center of mass can be determined by solving the integrals and rounding to the nearest hundredth.

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Determine the gravitational pull of the Earth on a spaceship. If its mass is 1850 kg, it is 2.00 Earth radii above the surface of the planet. A spacecraft experiences gravity at a force equal to its weight.

The spacecraft is three times as far from the Earth's centre since it is 2.00 Earth radii above the planet's surface. The spacecraft is three times as far from the Earth's centre since it is 2.00 Earth radii above the planet's surface. The height of the spacecraft is 2.00 earth radii. Consequently, the gravitational force equation is given by, The spacecraft is three times as far from the Earth's centre since it is 2.00 Earth radii above the planet's surface. There are spacecraft at a height of.

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The speed of light is approximately 1.86x10^5 miles per second. the approximate distance from the Sun to Saturn is 8.928x10^8 miles or 9.6 AU.

Given that it takes light from the Sun about 4.8x10^3 seconds to reach Saturn, we can calculate the distance from the Sun to Saturn.

To find the distance, we can use the formula:

Distance = Speed x Time

Plugging in the values we have:

Distance = \(1.86\times 10^5 miles/second \times 4.8x10^3 seconds\)
Multiplying the values, we get:

Distance = \(8.928 \times 10^8 miles\)

Therefore, the approximate distance from the Sun to Saturn is 8.928x10^8 miles.

To put this answer in perspective, it is important to note that the distance between celestial bodies is often measured in astronomical units (AU), where 1 AU is equal to the average distance between the Earth and the Sun, approximately 93 million miles. In this case, the distance from the Sun to Saturn would be approximately 9.6 AU.

In conclusion, the approximate distance from the Sun to Saturn is 8.928x10^8 miles or 9.6 AU.

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Answer:

Hello stranger I don't know

Explanation:

._____.

Answer:

hi stranger lol

Explanation:

To determine the strength of the dipole created by the redistributed charge on the conducting spherical shell, we can consider the concept of electric dipole moment.

The electric dipole moment (p) is defined as the product of the magnitude of either charge (q) in the dipole and the separation distance (d) between them:

p = q * d

In this case, the dipole moment arises from the redistribution of charge on the conducting spherical shell. The magnitude of the charge on the shell will depend on the electric field (E) it experiences.

Now, let's analyze the scenario step by step:

1. The electric field (E) is uniform and acts on the conducting spherical shell of radius (r).

2. Due to the presence of the electric field, charges on the shell will redistribute themselves until equilibrium is reached.

3. The redistribution of charges will result in a dipole-like configuration, where positive charge accumulates on one side and negative charge on the other side.

4. To calculate the strength of the dipole moment (p), we need to determine the magnitude of the charge (q) and the separation distance (d) between them.

5. In the case of a conducting shell, the electric field inside the shell is zero, and the charges redistribute themselves to the outer surface of the shell. This means that the separation distance (d) between the positive and negative charges is equal to the diameter of the shell (2r).

6. The magnitude of the charge (q) on each side of the dipole can be determined by considering the net charge on the shell, which is zero. Therefore, the charges on each side of the dipole are equal in magnitude.

Now, we can express the dipole moment (p) as:

p = q * d = q * 2r

To find the value of q, we need to consider the electric field (E) acting on the shell. The electric field due to an idealized dipole at the center of the shell is given by:

E = (kp * cosθ) / r^2

where kp is the electric dipole moment of the idealized dipole and θ is the angle between the direction of the electric field and the axis of the dipole.

Since the electric field (E) acting on the shell is the same as the field due to the idealized dipole, we can equate these two expressions:

E = (kp * cosθ) / r^2 = (kq * 2r * cosθ) / r^2

From this equation, we can deduce that kp = 2krq.

Therefore, the strength of the dipole moment (p) is given by:

p = q * 2r = (kp * r) / (2k)

Substituting kp = 2krq, we get:

p = (2krq * r) / (2k) = rq

Hence, the strength of the dipole moment is given by p = rq, where r is the radius of the conducting spherical shell and q is the magnitude of the charge on each side of the dipole.

Note: The negative sign indicating the direction of the dipole is not considered here since we are only interested in the magnitude of the dipole moment.

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The trailer's mass is 0.10 kg.

The period of a mass-spring system is directly related to the square root of the mass but inversely related to the square root of the spring constant.

Thus, the period T is expressed as;

T = 2π × √ m ÷ k

The period (T) is reciprocally related to the frequency (f)

Expressed in an equation as;

T = 1 ÷ f

Therefore, T = 2π × √ m ÷ k = 1 ÷ f

Making the mass 'm' the subject of the formula, the above equation becomes;

m = k ÷ 2π^2 × f^2

Where

m represents the mass

k represents the spring constant

f is the frequency

π = 3. 14 (constant)

Replacing the values, the mass equation becomes;

Mass, m = 1. 0 × 10^ 0 ÷ 2× 3.14 × 3.14 × 0.71 × 0. 71

= 1.0 × 1 ÷ 9. 94

= 0. 10 kg

Therefore, the mass of the trailer is 0. 10kg.

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Hey there!

Answer:

9.4 million kilometers (km) converted to light years would be 9.93580784e-7 I believe.

Hope this helps!

Three uncertain digits are present when a quantity is expressed in significant figures.

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The coefficient of static friction between the mass and the plane is 0.52.

Then coefficient of static friction is the value that must be overcomed when two surfaces are in contact. This value depends on the nature of the surfaces in contact.

In the given question, since the two surfaces are rough, frictional force will act in opposite direction of the motion.

Given that;

F = μR

where F is the force applied to the mass and R is its reaction.

F = 250 N

R = mgCos θ

  = 50 x 10 Cos 15

  = 483 N

So that;

μ = F/R

  = 250/483

μ = 0.52

The coefficient of static friction between the mass and the plane is 0.52.

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The acceleration that the same net force would give to an 18-kg tool is 13.3 m/s² (meters per second squared).

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.

Mathematically, this can be expressed as F = ma, where F is the net force, m is the mass, and a is the acceleration.

In the given scenario, the net force is accelerating a 4.8-kg tool at 40 m/s². To find the acceleration for an 18-kg tool, we can rearrange the equation to solve for a:

a = F/m

Substituting the values, we have:

a = (F)/(18 kg) = (40 m/s²)/(18 kg) = 2.22 m/s²

Therefore, the net force would give an acceleration of 2.22 m/s² to an 18-kg tool.

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Answer:

→ Mass is the lightness or heaviness of a body that is free from any force field.

→ Mass is the volume of a body multiplied by its density.

\(.\)

Answer:

9.55

Explanation:

i took the test