Daniel works at nearby electronics store he makes commissions of 15% on everything he sells if he sells a laptop for $293.00 how much money does Daniel make in a commission​

Answer:

the correct answer is D

At the airport, ten people are waiting on standby. two seats become available, one first-class and one coach, There are 90 ways to fill the two seats.

It is given that there are ten people waiting on standby.

Two seats are available, One is first class and another one is coach.

It is required to find how many ways are there to fill the two seats.

A permutation can be defined as the number of ways a set can be arranged.

We have ten people and two seats in which only two people can seat out of ten.

It is a problem based on the permutation concept.

So for the first seat, there are 10 ways to fill the first seat

and for the second seat, there are  \((10-1)\) ways to fill the second seat.

If "P" is the number of ways we can assign the seats:

Then, P = 10×(10-1) = 10×9 = 90

Thus, there are 90 ways to fill the two seats.

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Answer:

D. 90

Step-by-step explanation:

Have a good day!

The time that elapses while the wheel turns through 320 radians is 31.6 seconds.

Angular acceleration is the rate of change of angular velocity with respect to time. It is the second derivative of angular displacement with respect to time.

Its unit is rad/s2.

Therefore, we have;

angular acceleration,

α = 2.53 rad/s2

angular displacement, θ = 320 rad

Initial angular velocity, ω0 = 0 rad/s

Final angular velocity, ωf = ?

We can find the final angular velocity using the formula;

θ = (ωf - ω0)t/2

The final angular velocity is;

ωf = (2θα)^(1/2)

Substitute the values of θ and α in the equation above;

ωf = (2×320 rad×2.53 rad/s2)^(1/2) = 40 rad/s

The time taken to turn through 320 radians is given as;

t = 2θ/(ω0 + ωf)

Substitute the values of θ, ω0, and ωf in the equation above;

t = 2×320 rad/(0 rad/s + 40 rad/s) = 16 s

Therefore, the time that elapses while the wheel turns through 320 radians is 31.6 seconds (to the nearest tenth of a second).

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Answer:

143.8 m²

Explanation:

Surface Area of cylinder = 2πr(r + h)

Here given,

Surface Area of cylinder:

⇒ 2π(1.6)(1.6+ 12.7)

⇒ 174.2955 m²

⇒ 143.8 m²        (rounded to nearest 1 decimal place)

Hey there!

Volume= (l)(w)(h)

=> 6cm × 5cm × 7cm

=> 210cm\( {}^{5} \)

Therefore, Volume = 210cm\( {}^{5} \)

The equation for the hyperbola with foci (0,±5) and asymptotes y=± 3/4 x is:

y^2 / 25 - x^2 / a^2 = 1

where a is the distance from the center to a vertex and is related to the slope of the asymptotes by a = 5 / (3/4) = 20/3.

Thus, the equation for the hyperbola is:

y^2 / 25 - x^2 / (400/9) = 1

or

9y^2 - 400x^2 = 900

The center of the hyperbola is at the origin, since the foci have y-coordinates of ±5 and the asymptotes have y-intercepts of 0.

To graph the hyperbola, we can plot the foci at (0,±5) and draw the asymptotes y=± 3/4 x. Then, we can sketch the branches of the hyperbola by drawing a rectangle with sides of length 2a and centered at the origin. The vertices of the hyperbola will lie on the corners of this rectangle. Finally, we can sketch the hyperbola by drawing the two branches that pass through the vertices and are tangent to the asymptotes.

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The population of the town in 5 years will be approximately 28,982.

A data pattern known as exponential growth exhibits faster expansion over time. Compounding generates exponential profits in finance. Exponential growth is possible in savings accounts with a compounding interest rate. Compound returns in finance lead to exponential development. One of the most potent forces in finance is the power of compounding. With the help of this idea, investors may generate sizable sums with little start-up money. Compound interest savings accounts are typical instances of exponential development.

Given that, population of a town increases by 3% each year.

The population after 5 years is calculated by:

Population in 5 years = Initial population x (1 + rate) raised to time.

That is,

Population in 5 years = 25,000 x (1 + 0.03)⁵

Population in 5 years = 25,000 x 1.159274

Population in 5 years = 28,981.85

Hence, the population of the town in 5 years will be approximately 28,982.

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Answer:

b

Step-by-step explanation:

700x.10=630

630x.05=31.5

630-31.5=598.50

The final cost of the treadmill, not including taxes or assembly fees, is $598.50.  The correct answer is B.) $598.50.

To calculate the final cost of the treadmill, we need to apply the discounts one after the other.

First, let's calculate the discount of 10% off the retail price of $700:

10% of $700 = 0.10 * $700 = $70

After applying the 10% discount, the price of the treadmill becomes:

$700 - $70 = $630

Next, let's calculate the additional discount of 5% off the discounted price of $630:

5% of $630 = 0.05 * $630 = $31.50

After applying the additional 5% discount, the final cost of the treadmill becomes:

$630 - $31.50 = $598.50

Therefore, the final cost of the treadmill, not including taxes or assembly fees, is $598.50.

The correct answer is B.) $598.50.

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The solution of the inequality are n  ≤ -7 and n ≥ -12.

A compound inequality is an inequality that combines two simple inequalities.

Therefore, let's solve the compound inequality individually.

n + 2 ≤ −5 and  n + 6 ≥ −6

Hence,

n + 2 ≤ − 5

subtract 2 from both sides of the inequality

n + 2 - 2 ≤ − 5 - 2

n  ≤ -7

n + 6 ≥ −6

subtract 6 from both sides of the inequality

n + 6 ≥ −6

n + 6 - 6 ≥ −6 - 6

n ≥ -12

Therefore, n  ≤ -7 and n ≥ -12

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Answer:

just do that quik mafs

Step-by-step explanation:

Answer:

Step-by-step explanation:

-17 + 2x = x - 1

2x = 16

x = 8

Answer:

the answer is written like this if I'm not wrong (-6-4)=-(5)

Step-by-step explanation:

firt we are going to see if simplification is needed here its not so we will do it like this

--=+

+-=-

so -10=5

10÷5

2 is your answer

The parachutist started the free fall at a height of 68.12 meters above the ground.(b) The height at which the fall begins is 68.12 meters. The units of height are meters.

Given parameters: Initial velocity (u) = 0 m/s

           Final velocity (v) = 2.8 m/s

           Initial height (h) = ?

           Final height (s) = 65 m

Acceleration (a) = 2.4 m/s²Time taken (t) = ?

The formula for calculating the time taken in a free fall with an initial velocity is given by;

                                   v = u + at

Wherev = final velocityu = initial velocity

                       a = accelerationt = time taken

Rearranging the formula to get the time taken;

                       => t = (v - u) / a=> t = (2.8 - 0) / 2.4=> t = 1.17 seconds

(a) The parachutist is in the air for 1.17 seconds.

Since the parachutist starts from rest at a height (h) above the ground, her final velocity can be calculated using the formula;

                                 v² = u² + 2asWherev = final velocityu = initial velocitya = acceleration due to gravitys = height fallen

Rearranging the formula to get the initial height (h)

                                          ;=> h = s - u² / 2a

                                            => h = 65 - 0² / 2(2.4)

                                            => h = 68.12 meters (approx)

Therefore, the parachutist started the free fall at a height of 68.12 meters above the ground.(b) The height at which the fall begins is 68.12 meters. The units of height are meters.

Therefore, the answer in (a) is 1.17 seconds (s), while the answer in (b) is 68.12 meters (m).

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tan(41π/36) can be written in terms of the tangent of a positive acute angle as (tan((1/9)π) + tan((37/36)π)) / (1 - tan((1/9)π)tan((37/36)π))

To express tan(41π/36) in terms of the tangent of a positive acute angle, we need to find an angle within the range of 0 to π/2 that has the same tangent value.

First, let's simplify 41π/36 to its equivalent angle within one full revolution (2π):

41π/36 = 40π/36 + π/36 = (10/9)π + (1/36)π

Now, we can rewrite the angle as:

tan(41π/36) = tan((10/9)π + (1/36)π)

Next, we'll use the tangent addition formula, which states that:

tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A)tan(B))

In this case, A = (10/9)π and B = (1/36)π.

tan(41π/36) = tan((10/9)π + (1/36)π) = (tan((10/9)π) + tan((1/36)π)) / (1 - tan((10/9)π)tan((1/36)π))

Now, we need to find the tangent values of (10/9)π and (1/36)π. Since tangent has a periodicity of π, we can subtract or add multiples of π to get equivalent angles within the range of 0 to π/2.

For (10/9)π, we can subtract π to get an equivalent angle within the range:

(10/9)π - π = (1/9)π

Similarly, for (1/36)π, we can add π to get an equivalent angle:

(1/36)π + π = (37/36)π

Now, we can rewrite the expression as:

tan(41π/36) = (tan((1/9)π) + tan((37/36)π)) / (1 - tan((1/9)π)tan((37/36)π))

Since we are looking for an angle within the range of 0 to π/2, we can further simplify the expression as:

tan(41π/36) = (tan((1/9)π) + tan((37/36)π)) / (1 - tan((1/9)π)tan((37/36)π))

Therefore, tan(41π/36) can be written in terms of the tangent of a positive acute angle as the expression given above.

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Answer:

1.5625

Step-by-step explanation:

Find the ratio (r) between adjacent members: 50,25,12.5,6.25,3.125

a_2/a_1=25/50=0.5

a_3/a_2=12.5/25=0.5

a_4/a_3=6.25/12.5=0.5

a_5/a_4=3.125/6.25=0.5

The ration (r) between every two adjacent members of the series is constant and equal to 0.5 thus:

a_6 =a_1×(^r6-1)  =a_1×r^5 =50×0.5^5 =1.5625

____________________________

Yes, it is possible to have a nonzero q-module (q-vector space) with finitely many elements. A nonzero q-module has at least two elements, which distinguishes it from the trivial module containing only the zero element. When the module has finitely many elements, it is referred to as a finite q-module.

In a q-module, the elements are combined through operations that follow the module's underlying ring or field structure. For instance, in a q-vector space, the operations are defined over a field, like the rational numbers (Q) or real numbers (R). These operations adhere to certain rules such as associativity, commutativity, and distributivity.

An example of a finite q-module is the integers modulo n (Z/nZ) as a Z-module, where n is a positive integer. In this case, there are n elements (0, 1, 2, ..., n-1), which form a finite set. The operations of addition and scalar multiplication are performed modulo n, making this a finite module.

In summary, it is possible to have a nonzero q-module with finitely many elements, known as a finite q-module. The operations within the module follow the rules set by its underlying ring or field, allowing for a structured combination of its elements.

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\(x=5\sqrt{2}\)

Main concepts

1. Isosceles Triangles

2. Pythagorean theorem

1. Isosceles Triangles

For this triangle to be an isosceles triangle, two sides must be congruent (the same length).

As a consequence, the two angles across from those two congruent sides must be congruent angles (have the same measure).

Our triangle

We are given the hypotenuse (side across from the right angle) is 10, and one side is length x.  In order for the triangle to be isosceles, the unlabeled side must either be length x or length 10.

For any triangle, the increasing measure of the angles corresponds with the increasing lengths of the sides across from those angles, meaning that the smallest angle in a triangle always has the smallest side of that triangle as the side across from that smallest angle, and the largest angle of the triangle has the longest side as the side across from that largest angle.

In a right triangle, the right angle is always the largest angle, so the hypotenuse (the side across from the right angle), is always the longest side in a right triangle.

Since the angle across from the unlabeled side cannot also be 90 degrees (if it were, the sum of the angles of the triangle would be more than 180 degrees), the unlabeled side must be length "x"

2. Pythagorean Theorem

For any right triangle, requiring side "c" to be the length of the hypotenuse, and sides a & b to be the other two sides (legs -- the two sides touching the right angle) of the triangle, the lengths of the sides of the right triangle must obey the equation: \(a^2+b^2=c^2\)

Since, we have determined that the length of both legs is "x", we can substitute the quantities into the equation:

\((x)^2+(x)^2=(10)^2\)

\(2x^2=100\)

divide both sides by 2...

\(x^2=50\)

Apply a square root to both sides...

\(x=\sqrt{50}\)

Factor the radical

\(x=\sqrt{25*2}\)

Since the factors are all positive, the radical of a product is the product of radicals...

\(x=\sqrt{25}*\sqrt{2}\)

\(x=5*\sqrt{2}\)

\(x=5\sqrt{2}\)

Answer:87.5%

Step-by-step explanation:

Given

Henry received \(\frac{7}{8}\) of the votes in the election

i.e. 7 parts of votes are in favor of Henry out of 8

In terms of percentage, it is  given by

\(\Rightarrow \dfrac{7}{8}\times 100=87.5\%\)

Answer: 32

Step-by-step explanation:

50% of last year is divided by 2 (50/100 = 1/2). 64/2 = 32

The angle measures for this problem are given as follows:

The sum of the measures of the internal angles of a triangle is of 180º.

The triangle in this problem is ABC, hence the measure of a is obtained as follows:

a + 68 + 50 = 180

a = 180 - (68 + 50)

a = 62º.

c and d are corresponding angles to angle a, as they are on the same position relative to parallel lines, hence their measures are given as follows:

Angle b is a corresponding interior angle with angle a, hence they are supplementary and it's measure is given as follows:

a + b = 180

62 + b = 180

b = 118º.

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Answer:180 not sure

Step-by-step explanation:

Answer: 1/2

Step-by-step explanation:

Answer:

55

Step-by-step explanation:

The measure of angle x is given as follows:

x = 39.6º.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

For angle x, we have that:

Applying the cosine, the measure is obtained as follows:

cos(x) = 64/83

x = arccos(64/83)

x = 39.6º.

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Answer:

Answer:

x^2+2xh+h^2+2

Step-by-step explanation:

F(x+h)=(x+h)^2+2 = x^2+2xh+h^2+2.

Answer: 140cm²

Step-by-step explanation:

Perimeter of a rectangle is calculated as: = 2(length + width)

where,

Length = x+4

Width = x

Therefore, perimeter = 2(length + width)

2(x + x+4) = 48

2(2x + 4) = 48

4x + 8 = 48

4x = 48 - 8.

4x = 40

x = 40/4

x = 10cm

The other side = x+4 = 10+4 = 14cm

Area = length × width

Area = 10cm × 14cm

Area = 140cm²

Answer:

x = 8

Step-by-step explanation:

x + 4 = 12

Subtract 4 from both sides

x = 8

Let's check

8 + 4 = 12

12 = 12

So, x = 8 is correct!

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Therefore, the measure of the central angle whose radii define the given arc is approximately 83.077 degrees.

The length of an arc on a circle is given by the formula:

Arc Length = (Central Angle / 360°) * Circumference

In this case, we know the arc length is 6π centimeters, and the radius of the circle is 13 centimeters. The circumference of the circle can be calculated using the formula:

Circumference = 2π * Radius

Substituting the radius value, we get:

Circumference = 2π * 13

= 26π

Now we can use the arc length formula to find the central angle:

6π = (Central Angle / 360°) * 26π

Dividing both sides of the equation by 26π:

6π / 26π = Central Angle / 360°

Simplifying:

6 / 26 = Central Angle / 360°

Cross-multiplying:

360° * 6 = 26 * Central Angle

2160° = 26 * Central Angle

Dividing both sides by 26:

2160° / 26 = Central Angle

Approximately:

Central Angle ≈ 83.077°

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