Determine the domain and range of (g ○ f)(x) if f of x is equal to 9 over the quantity x squared minus 9 end quantity and g(x) = x + 3.

A. D: {x ∈ ℝ} and R: (–∞, –3) ∪ (3, ∞)
B. D: {x ∈ ℝ| x ≠ –6, 0} and R: (–∞, –3) ∪ (3, ∞)
C. D: {x ∈ ℝ| x ≠ –3, 3} and R: (–∞, 2) ∪ (3, ∞)
D. D: {x ∈ ℝ| x ≠ –6, –3, 0, 3} and R: (–∞, –2) ∪ (2, ∞)

In both the Vendor Compliance at Geoffrey Ryans (A) and Operational Execution at Arrows Electronics cases, there are common problems and challenges. These include issues related to vendor management.

One of the key problems faced by both companies is vendor compliance. This refers to the ability of vendors to meet the requirements and standards set by the company. Both cases highlight instances where vendors fail to meet compliance standards, leading to disruptions in the supply chain and operational inefficiencies. This problem affects the overall performance and profitability of the companies.

Another challenge faced by both companies is operational execution. This encompasses various aspects of operations, including inventory management, order fulfillment, and delivery. In both cases, there are instances where operational execution falls short, leading to delays, errors, and customer dissatisfaction. This challenge requires the companies to streamline their processes, improve communication and coordination, and enhance overall operational efficiency.

Overall, the problems and challenges in both cases revolve around effective vendor management, supply chain optimization, and operational excellence. Addressing these issues is crucial for both companies to improve their performance, meet customer demands, and maintain a competitive edge in the market.

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Answer:
x = -2, y = 11
x = 0, y = 5

x = 5, y = -10

Step-by-step explanation:

function: h(x) = 5 - 3x

Replace x from the function with the given x- values.

Answer:

x = 3.05 and y = -0.615

Step-by-step explanation:

The given equations are :

3x-3y = 11 ...(1)

3x + 10y = 3 ...(2)

Subtract equation (2) from (1).

3x-3y-(3x + 10y) = 11-3

-3y-10y = 8

-13y = 8

y = -0.615

Put the value of y in equation (1).

3x-3(-0.615) = 11

3x = 11 -1.845

3x = 9.155

x = 3.05

Hence, the values of x and y are 3.05 and -0.615.

Step-by-step explanation:

perimeter = 2y + 2y + 3 + 3x + 2y + 3 + 2y + 4x + 5

= 8y + 7x + 11

Step-by-step explanation:

2y+3+2y+4x+5+3x

=2y+2y+3x+4x+3+5

=4y+7x+8

Answer:

x=1/4

Step-by-step explanation:

x=0.25

Answer:

∠R = 38°

Step-by-step explanation:

∠R = 1/2(arc PE - arc SQ)

∠R = 1/2(140 - 64) = 1/2(76) = 38°

Answer:

225

Step-by-step explanation:

(- 15)² = - 15 × - 15 = 225

The given system has a relationship between the output \( y(t) \) and its derivatives. It can be represented by the differential equation \(\frac{d^3 y}{dt^3} + 2\frac{d^2 y}{dt^2} + 1 = 0\).

The given differential equation represents a third-order linear homogeneous differential equation. It relates the output function \( y(t) \) with its derivatives with respect to time.

The equation states that the third derivative of \( y(t) \) with respect to time, denoted as \(\frac{d^3 y}{dt^3}\), plus two times the second derivative of \( y(t) \) with respect to time, denoted as \(2\frac{d^2 y}{dt^2}\), plus one, is equal to zero.

This equation describes the dynamics of the system and how the output \( y(t) \) changes over time. The coefficients 2 and 1 determine the relative influence of the second and first derivatives on the system's behavior.

Solving this differential equation involves finding the function \( y(t) \) that satisfies the equation. The solution will depend on the initial conditions or any additional constraints specified for the system.

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Answer: 3x+y=7  answer for that one is x=7/3-y/3

4x+2y=16 the answer for that is x=4-y/2

Step-by-step explanation:

Answer:

x is 76

Step-by-step explanation:

im pretty sure, i just sloved it

Answer:

76.

Step-by-step explanation:

Simplifying

-4(x + -26) = -200

Reorder the terms:

-4(-26 + x) = -200

(-26 * -4 + x * -4) = -200

(104 + -4x) = -200

Solving

104 + -4x = -200

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-104' to each side of the equation.

104 + -104 + -4x = -200 + -104

Combine like terms: 104 + -104 = 0

0 + -4x = -200 + -104

-4x = -200 + -104

Combine like terms: -200 + -104 = -304

-4x = -304

Divide each side by '-4'.

x = 76

Simplifying

x = 76

Answer:

3 hours 50 minutes

Step-by-step explanation:

since speed equals distance multiplied by the time taken, using the same formula time taken will be the distance divided by the speed. so 378kilometres divided by the 108 kmper hour you get the answer 3 hours 50 minutes

Answer:

The answer to this question is 12x.

Answer:

\(\huge\boxed{\sf 12x}\)

Step-by-step explanation:

\(\sf 5x+7x\\\\Take \ x \ as \ common\\\\x(5+7)\\\\x(12)\\\\= 12x\\\\\rule[225]{225}{2}\)

Hope this helped!

~AH1807

The school district's magnet school programs, of the 1882 qualified applicants, 52.44% were accepted, 16.41% were waitlisted, and 31.15% were turned away for lack of space.

The relative frequency for each decision made by the school district regarding their magnet school programs.
First, let's define relative frequency.

It is the fraction or proportion of the total data that belongs to a particular category or class. In this case, the categories are "accepted," "waitlisted," and "turned away."
To find the relative frequency for each decision, we need to divide the number of applicants in each category by the total number of qualified applicants, which is 1882.
So, the relative frequency for "accepted" is:
987/1882 = 0.524 or 52.4%
The relative frequency for "waitlisted" is:
309/1882 = 0.164 or 16.4%
And the relative frequency for "turned away" is:
586/1882 = 0.312 or 31.2%
To summarize the results, we can say that out of the 1882 qualified applicants for the school district's magnet school programs, 52.4% were accepted, 16.4% were waitlisted, and 31.2% were turned away due to lack of space.

This indicates that there is high demand for these programs and the school district needs to consider expanding their capacity to accommodate more students.

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Answer:

b = 4

Step-by-step explanation:

5b + 1 = 21

5b = 20

b = 4

Answer:

b= 4

Step-by-step explanation:

On order to get the answer of b first you need to 'undo' the equation.

1.First start by multiply both sides of the equation by 3. (you need to do this to cancel out the denominator of 3)

Now the equation should read 5b+1= 21.

2. Subtract 1 from each side of the equation. You need to get b and its coefficient alone on one side of the equation. The equation should now read 5b= 20

3. Divide both sides by 5. You now need to get b alone so you can figure out its value, you do this be getting rid of the coefficient.

4. You are left with b=4

5. Check your answer. 4x5=20   20+1= 21  21/3=7

Hope this helps <3

The value of dfbetween in the analysis of variances is 2. Thus option D is correct option.

According to the statement

we have given that the df total = 29 and df within = 27. And we have to find the value of the df between.

So, For this purpose, we know that the

Analysis of variance (ANOVA) is an analysis tool used in statistics that splits an observed aggregate variability found inside a data set into two parts.

So, Df between values are the values between the value of dftotal and dfwithin.

Here df total = 29 and df within = 27

So, df between = df total - df within

Substitute the values in it then

df between = df total - df within

df between = 29 - 27

df between = 2.

So, The value of dfbetween in the analysis of variances is 2. Thus option D is correct option.

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Answer:

6.25

Step-by-step explanation:

100-50=50

50 percent of 50 is 25

50-25=25

50 percent of 25 is 12.5

25-12.5=12.5

50 percent of 12.5 is 6.25

i did it 4 times so 6.25 is the answer

Given that \(\(T(n)\) = \(10n^2-3n\)\) if (\(\(n=1\)\)), you have to prove it by induction. So, we have proved it by induction that  \($$\(T(n)=10n^2-3n\)$$\)  if ( n= 1). The given statement is true for all positive integers n

Let's do it below: The base case (n=1) is given as follows: \(T(1)\) =\(10\cdot 1^2-3\cdot 1\\&\)=\(7\end{aligned}$$\). This implies that \(\(T(1)\)\) holds true for the base case.

Now, let's assume that \(\(T(k)=10k^2-3k\)\) holds true for some arbitrary \(\(k\geq 1\).\)

Thus, for n=k+1, T(k+1) = \(10(k+1)^2-3(k+1)\\&\) = \(10(k^2+2k+1)-3k-3\\&\)=\(10k^2+20k+7k+7\\&\) = \(10k^2-3k+20k+7k+7\\&\) = \(T(k)+23k+7\\&\) = \((10k^2-3k)+23k+7\\&\) =  \(10(k+1)^2-3(k+1)\).

Therefore, we have proved that the statement holds true for n=k+1 as well. Hence, we have proved it by induction that  \($$\(T(n)=10n^2-3n\)$$\)  if (n=1). Therefore, the given statement is true for all positive integers n.

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Answer:

615.44m²

Step-by-step explanation:

The base of the silo is a circle

Rea of the base of the silo = πr²

r is the radius of the silo

Given

radius r = 14m

Area of the base of the silo = π(14)²

Area of the base of the silo = 3.14(196)

Area of the base of the silo = 615.44

Hence the area of the base of the silo is 615.44m²

When we translate a graph adding X units it will have a horizontal shift to the left.

But if we subtract X units, it'll have a horizontal shift to the right

So in this case, x-3 means we are doing a horizontal shift to the right.

given that for all numbers of p and q,

q = 5/3p + 46

lets find p when q is 21

so lets substitute the value of q into the given equation

q = 5/3p + 46

21 = 5/3p + 46

lets collect like terms

21 - 46 = 5/3p

-25 = 5/3p

lets cross multiply

3 X -25 = 5p

-75 = 5p

5p = -75

divide both sides by 5

5p/5 = -75/5

p = -15

therefore for all values of p and q, q = 5/3p + 46,

the value of p is -15 when q is 21

To prove that 3x ≤ y, assume the opposite, that is, 3x > y, rearrange the inequality substitute x < 2y and simplify, contradict the given condition that x < 2y, therefore, concluding that 3x ≤ y.

Start by assuming the opposite, that is, 3x > y.

From the given inequality,\(7xy \leq 3x^2 + 2y^2,\), we can rearrange to get:
\(7xy - 3x^2 \leq 2y^2\)

We can substitute \(x < 2y\) into this inequality:
\(7(2y)x - 3(2y)^2 \leq 2y^2\)

Simplifying, we get:
\(y(14x - 12y) \leq 0\)

Since y is a real number, this means that either y ≤ 0 or 14x - 12y ≤ 0.

If y ≤ 0, then 3x ≤ y is trivially true.

If 14x - 12y ≤ 0, then we can rearrange to get:
3x ≤ (12/14)y
3x ≤ (6/7)y
3x < y (since we assumed 3x > y)

But this contradicts the given condition that x < 2y, so our assumption that 3x > y must be false.

Therefore, we can conclude that 3x ≤ y.

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Lou and Mira can rescind the contract to sell an MP3 player to Mira for $50 if both parties agree to the terms of rescission and sign a written agreement.

Rescission of a contract refers to an equitable remedy granted by the courts or given as a contractual right to one party to terminate a contract. This remedy returns the parties to their former positions before the contract's execution, which requires that both parties to a contract return whatever benefits they had received during the transaction.

In Lou and Mira's scenario, the rescission of their contract to sell an MP3 player to Mira for $50 can be possible if the parties reach an agreement to rescind the contract in writing. The following steps should be taken to rescind the contract:

1. The parties should agree to rescind the contract: For a rescission to be effective, both parties must consent to rescind the contract. This is possible if both parties agree to the terms of rescission and sign a written agreement. The agreement must state the date of rescission, the reason for the rescission, and the terms of the agreement.

2. Restitution: Restitution refers to the return of the subject matter of the contract. Since it is an MP3 player, Lou must return the MP3 player to Mira. In turn, Mira must also return the $50 to Lou. This will effectively end the contract, and the parties can go their separate ways.

3. Cancellation of any obligations: The parties must agree to cancel any obligation that arose from the contract. In this case, no obligations may arise from the rescission of the contract, so no further action is required.

4. Record keeping: It is crucial to keep a record of the rescission agreement. This record will serve as evidence of the rescission if any legal issues arise. It should include the date of rescission, the reasons for rescission, and the terms of the agreement. The parties must keep a copy of the document for their records.

In conclusion, Lou and Mira can rescind the contract to sell an MP3 player to Mira for $50 if both parties agree to the terms of rescission and sign a written agreement. The agreement must include the date of rescission, the reason for rescission, and the terms of the agreement.

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while the presence of only one spot on a TLC plate may suggest that the compound is pure, further analysis is needed to confirm the purity of the compound, such as melting point determination, NMR spectroscopy, or HPLC (high-performance liquid chromatography).

Using UV and seeing only one spot on a TLC (thin-layer chromatography) plate is not a definitive indicator of the purity of a product.

While it is true that a pure compound will only show one spot on a TLC plate, there are several reasons why a compound may still show only one spot even if it is not pure. For example:

The impurity may have a similar Rf (retention factor) value to the compound of interest and therefore co-migrate with it on the TLC plate, making it difficult to distinguish between the two.

The impurity may be present in such a small amount that it is not visible on the TLC plate.

The compound of interest may have multiple conformers or isomers that have the same Rf value and appear as a single spot.

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Answer:

3 times

Step-by-step explanation:

Answer:

\(y=\frac{4}{3}x+\frac{4}{3}\)

Step-by-step explanation:

Let \((x_1,y_1)\rightarrow(-4,-4)\) and \((x_2,y_2)\rightarow(2,4)\):

Determine slope

\(m=\frac{y_2-y_1}{x_2-x_1}\\ \\m=\frac{4-(-4)}{2-(-4)}\\ \\m=\frac{4+4}{2+4}\\ \\m=\frac{8}{6}\\ \\m=\frac{4}{3}\)

Use either coordinate point to find "b", the y-intercept

\(y=mx+b\\\\4=\frac{4}{3}(2)+b\\ \\4=\frac{8}{3}+b\\ \\\frac{4}{3}=b\)

Final Equation

\(y=\frac{4}{3}x+\frac{4}{3}\)

In the word problem, if mike has 40 coins consisting of dimes and quarters and if the dimes were quarters and the quarters dimes, he would have 90 cents more, he has 17 quarters.

A word problem refers to a mathematical exercise where significant information on the problem is given in ordinary language and not mathematical notation.  Let x be the number of dimes (10 cents) and y be the number of quarters (25 cents). Hence, the total number of coins is:

x + y = 40

The amount of the total coins would be 0.1x + 0.25y.

If the dimes were quarters and quarters were dimes, he would have 90 cents more than the amount he has now.

Hence,

0.25x + 0.10y = 0.1x + 0.25y + 0.9

Solving,

0.25x – 0.1x = 0.25y – 0.1y +0.9

0.15x = 0.15y + 0.9

As x + y = 40, x = 40 – y

Substituting,

0.15 (40 – y) = 0.15y + 0.9

6 - 0.15 y = 0.15y + 0.9

0.15y + 0.15y = 6 – 0.9

0.3y = 5.1

y = 5.1/0.3 = 17

Hence, the number of quarters are 17.

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Answer:  X=12.7

Step-by-step explanation:

Sorry if its wrong I am pretty rusty with these kind of questions

Given,x(t) = 7.4t² − 4.8t³m

We need to find the following.(b) Velocity (in m/s) and acceleration (in m/s²) at t = 2 s and indicate the direction with the sign of your answer.

(c) Find the time t > 0 (in s) when the position is at a maximum.

(d) Find the time t > 0 (in s) when the velocity is zero.

(e) Find the maximum position (in m) for time t > 0 and indicate the direction with the sign of your answer.

To calculate velocity, we need to differentiate position with respect to time.

That is,

v(t) = x′(t)

= 14.8t - 14.4t²m/s

We can calculate acceleration by differentiating velocity with respect to time.

That is,

a(t) = v′(t) = 14.8 - 28.8t m/s²

Now, we can substitute t = 2 s to find velocity and acceleration.

v(2.0 s) = 14.8(2.0) - 14.4(2.0)² = 4.4 m/s (The direction is positive because velocity is positive at t = 2 s) a(2.0 s) = 14.8 - 28.8(2.0) = -42.8 m/s²

(The direction is negative because acceleration is negative at t = 2 s)

Now, we can find the time when the position is at a maximum.

To find the maximum, we need to differentiate position with respect to time and equate it to zero.

dx/dt = 14.8t - 14.4t²

= 0.

Simplifying, we get 14.8t(1 - t) = 0.

Hence,t = 0, 1 s.To determine the time when velocity is zero, we set the expression for velocity to zero and solve for t.

v(t) = 0 = 14.8t - 14.4t² => 14.8t = 14.4t² => t(14.4t - 14.8) = 0.

Hence,t = 0, 1.028 s (rounded to three decimal places).

To find the maximum position, we substitute t = 1 s into the expression for position.

x(1.0 s) = 7.4(1.0)² − 4.8(1.0)³

= 2.6 m.

(The direction is positive because the particle is moving in the positive direction).

Therefore, the answers are,v(2.0 s) = 4.4 m/s (positive direction)a(2.0 s) = -42.8 m/s² (negative direction)t = 1 st = 0, 1.028 sx = 2.6 m (positive direction).

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Cost price is also known as CP. cost price is the original price of an item. The cost is the total outlay required to produce a product or carry out a service. Cost price is used in establishing profitability in the following ways: Selling price (excluding tax) less cost results in the profit in money terms.

A "selling price" is the price that the seller gives. something that he/she wants or is offering to sell. The item has not been sold. yet. A "sale price" could be the price that was actually paid by a buyer

1.

she earns if she babysits 3 children for 4 hours= $63.

solution :

Given :

Latoya earns $1.75 an hour for each child she babysits

Total Number of babysitting hours for 3 child= 3x12=36 hours

let,

Total amount earned by Latoya: S

S= 36x1.75

S= $63

she earns if she babysits 3 children for 4 hours= $63.

2.

James's total after the discount = $108.75

Given :

his total before the discount is $145.20

receives a 25% discount on his purchases

Solution :

Buy price = MRP X DISCOUNT /100

Let the Buying price is c

c = 145x25/100

c = 145/4

c= $ 36.25

= MRP - DISCOUNT

Let James's total after the discount =  p

p= 145-36.25

p= $108.75

3.

paid back after the third week= 19.5

Given :

Kegan borrows $78 from his sister.

Time = 4 week

each week Payment = 78/4=19.5

paid back after the third week= 19.5

4.

Ashley spends at the grocery= $8.34

Solution :

a loaf of bread = $1.09,

a pound of turkey = $4.59,

2 cans of soup =2x$0.79 each=$ 1.58

4 oranges = $0.27 x4= $1.08

Ashley spend at the grocery= 1.09 + $4.59, +$ 1.58+ $1.08 =$ 8.34

Ashley spends at the grocery= $8.34

5.

joe ticket is less Jackie's by 236-227=  $9

Solution :

Jackie buys a one-way ticket to Nevada=$118

a one-way ticket back home=$118

Total = $118x2 =$236

But

Joe buys a round-trip ticket to Nevada for $227

joe ticket is less Jackie's by 236-227=  $9

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