do you think there were many scores below 35? explain. since a score of 35 is three standard deviations correct: your answer is correct. below the mean, that corresponds to a percentile of incorrect: your answer is incorrect. %. therefore, there were few correct: your answer is correct. scores below 35.

The box plot given by the number of students read 8 books is the centre quartile which is 5.

Three values called quartiles divide sorted data into four equal portions with the same amount of observations in each. One kind of quantile is a quantile.

Thus, for the stated question.

The box plot given by the number of students read 8 books is the centre quartile which is 5.

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Answer:

Lines f and g are parallel.

Angle 2 is congruent to angle 6.

Angle 2 and angle 5 are supplementary

Step-by-step explanation:

Answer:

explain pls

Step-by-step explanation:

Answer:

D n/2 = 9

Step-by-step explanation:

14 + (18) = 32 not 29

6(18)= 108 NOT 3

18 - 7 = 11 NOT 25

The only answer is D because 18 divided by 2 = 9

Answer:

A) x = -4

Step-by-step explanation:

\(3x-2\left(6-x\right)=7x+2\left(5+x\right)-6\\\\\mathrm{Expand\:}3x-2\left(6-x\right):\quad 5x-12\\\\\mathrm{Expand\:}7x+2\left(5+x\right)-6:\quad 9x+4\\5x-12=9x+4\\\\\mathrm{Add\:}12\mathrm{\:to\:both\:sides}\\5x-12+12=9x+4+12\\\\Simplify\\5x=9x+16\\\\\mathrm{Subtract\:}9x\mathrm{\:from\:both\:sides}\\5x-9x=9x+16-9x\\\\Simplify\\-4x=16\\\\\mathrm{Divide\:both\:sides\:by\:}-4\\\frac{-4x}{-4}=\frac{16}{-4}\\\\Simplify\\x=-4\)

Therefore, the probability that the team is comprised of 2 men and 2 women is approximately 0.4545, which is true.

To calculate the probability that the team is comprised of 2 men and 2 women, we need to determine the number of favorable outcomes (teams with 2 men and 2 women) and the total number of possible outcomes (all possible teams).

The number of ways to choose 2 men from 6 men is given by the combination formula: C(6, 2) = 6! / (2! * (6-2)!) = 15.

Similarly, the number of ways to choose 2 women from 6 women is also C(6, 2) = 15.

Therefore, the number of favorable outcomes is the product of the number of ways to choose 2 men and 2 women: 15 * 15 = 225.

Now, let's calculate the total number of possible outcomes. We need to choose 4 members from a total of 12 members, which is given by C(12, 4) = 12! / (4! * (12-4)!) = 495.

The probability that the team is comprised of 2 men and 2 women is the ratio of favorable outcomes to the total number of outcomes: 225/495 = 45/99 ≈ 0.4545 (rounded to four decimal places).

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Solution: B. 1/2

Analysis

We are transforming triangle ABC to DFE. If we see the graph, we can see the measures of each side of the triangle, decrease by half. According to that, it would be 1/2 of the original measure.

Answer:

n to the power of 6 (4n+3)

Step-by-step explanation:

Step-by-step explanation:

Since it remains only 1 sweet, we can subtract it from the total and get the amount of sweets distributed (=1024).

As all the sweets are distributed equally, we must divide the number of distributed sweets by all its dividers (excluding 1024 and 1, we'll see later why):

1) 512 => 2 partecipants

2) 256 => 4 partecipants

3) 128 => 8 partecipants

4) 64 => 16 partecipants

5) 32 => 32 partecipants

6) 16 => 64 partecipants

7) 8 => 128 partecipants

9) 4 => 256 partecipants

10) 2 => 512 partecipants

The number on the left represents the number of sweets given to the partecipants, and on the right we have the number of the partecipants. Note that all the numbers on the left are dividers of 1024.

Why excluding 1 and 1024? Because the problem tells us that there remains 1 sweet. If there was 1 sweet for every partecipant, the number of partecipants would be 1025, but that's not possible as there remains 1 sweet. If it was 1024, it wouldn't work as well because the sweets are 1025 and if 1 is not distributed it goes again against the problem that says all sweets are equally distributed.

Answer: ($9.40) or (d)

Step-by-step explanation:

Answer:5

Step-by-step explanation:

30 chapters in 6 hours. 30/6 =5

Answer:

The answer is 0.023<0.3

Answer:

1: 2, 2: 3

Step-by-step explanation:

1 is 2 because if you count the total students, (25), divide by 2 to get 12.5 and round down. we want to find the 12th number. For the second one, do the similar thing, but now we have 13. Add the 13th and 14th numbers and divide by 2 to get 3.

We can write\(:∫0¹(1-x^q)^1/pdx = ∫1⁰(1-v)^1/pv^(1/q - 1) dv.\)

To prove that \(∫0¹(1-x^p)^1/qdx=∫0¹(1-x^q)^1/pdx,\) we use the substitution u = x^p and u = x^q respectively.

Using the substitution method, we have the following:  Let\(u = x^p,\) then \(du/dx = px^(p-1)\)and \(dx = (1/p)u^(1/p - 1) du.\)

Hence we can write\(:∫0¹(1-x^p)^1/qdx = ∫0¹(1-u)^1/qu^(1/p - 1) duLet v = (1 - u), then dv/dx = -du and dx = -dv.\)

Therefore, we can write:\(∫0¹(1-u)^1/qu^(1/p - 1) du = ∫1⁰(1-v)^1/qv^(1/p - 1) dvS\)

Since p and q are both positive, 1/p and 1/q are positive, which implies that the integrals are convergent. Now let us apply the same technique to the other integral. I\(f v = x^q, then dv/dx = qx^(q-1) and dx = (1/q)v^(1/q - 1) dv.\)

Hence we can write:∫\(0¹(1-x^q)^1/pdx = ∫1⁰(1-v)^1/pv^(1/q - 1) dv.\)

Using the identity\((1 - u)^1/q = (1 - u^q)^(1/p),\)

we can write:\(∫0¹(1-x^p)^1/qdx = ∫0¹(1 - (x^p)^q)^(1/p)dx = ∫0¹(1 - x^q)^(1/p)dx∫0¹(1-x^q)^1/pdx = ∫0¹(1 - (x^q)^p)^(1/q)dx = ∫0¹(1 - x^p)^(1/q)dx.\)

Hence, we have shown that \(∫0¹(1-x^p)^1/qdx = ∫0¹(1 - x^q)^(1/p)dx.\)

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Answer:

1)The slope of the smaller triangle is smaller.

2)The slope of the larger triangle is larger than the slope of the smaller triangle.

3)Tre triangles are congruent

4)The slopes of the two triangles are the same.

5)Line A

Answer:

1(d), 2(not correct) 3,4,5 given below

Step-by-step explanation:

1. the slopes are same as we know

m=tan theta=y/x so the slope is same

2. it will be 10 m= tan theta=y/x

or, slope =70-40/7-4=10

3. let x and y are the sides of the triangles

so for 1 triangle it will be x=5 and y=2

"" "" another one its the multiple of 5 and 2 such as x=10 and y=4

4. the two triangle lie on the same line as slopes are equal

1st one , slope=72/12=6

2nd one slope=144/24=6

as slopes equal so they are collinear.

5. i am sorry i am not sure about it

i took all the three lines. as the slope of 5 and 7 no triangleare same(m=0.75) and smaller than others then on line A

then slope of 8 and 9 no triangle are same(m=1.5) so on the line B

then slope of 6 and 10 are same (m=3) so on the line C

i took the three lines for this...

THE ALL ANSWERS ARE BASED ON PRIMARY CONCEPT IF U FIND ANY MISTAKE PLEASE TELL ME LATER..THANK U

How much a statistic varies from one sample to another is known as the sampling variability of a statistic.

Testing variability arises due to the reality that exceptional samples of the same size can produce special values of a statistic, although the samples are described from the same populace. the quantum of slice variability depends on the scale of the sample, the variety of the populace, and the unique statistic being calculated.

The end of statistical conclusion is to apply the data attained from a sample to make consequences about the population, while counting for the slice variability of the statistic. ways similar as thesis checking out and tone belief intervals do not forget the sampling variability of a statistic to make redundant accurate consequences about the populace.

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To calculate the overall probability, we multiply the individual probabilities together:

(3/11) * (1/10) * (7/9) = 21/990 ≈ 0.0212

Therefore, the closest option is 0.02.

Answer:56

Step-by-step explanation:bc thats the answer

The point prevalence of brilliance at the end of Week 1 is 0.08 or 8%.

The point prevalence of brilliance at the end of Week 2 is 0.17 or 17%.

The point prevalence of brilliance at the end of Week 3 is 0.33 or 33%.

Using person-weeks as denominator, the incidence of brilliance over the course of the 10-week course is 0.017 or 1.7%

In epidemiology context, brilliance can be calculated through calculating point prevalence, cumulative incidence, and incidence rate. The provided data table can be used to determine the point prevalence, incidence, and incidence rate of brilliance among PHE 450 students. So, the calculations of point prevalence, cumulative incidence, and incidence rate based on the provided data are as follows:

The point prevalence of brilliance at the end of Week 1 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #8 was the only existing case of brilliance at the beginning of Week 1, so the point prevalence of brilliance at the end of Week 1 is; Point prevalence = 1 ÷ 12 = 0.08 or 8%.

The point prevalence of brilliance at the end of Week 2 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #3 and Student #8 were existing cases of brilliance at the beginning of Week 2, so the point prevalence of brilliance at the end of Week 2 is; Point prevalence = 2 ÷ 12 = 0.17 or 17%.

The point prevalence of brilliance at the end of Week 3 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #3, #4, #6, and #8 were existing cases of brilliance at the beginning of Week 3, so the point prevalence of brilliance at the end of Week 3 is; Point prevalence = 4 ÷ 12 = 0.33 or 33%.

The incidence of brilliance can be calculated by the following formula; Incidence = Total number of new cases ÷ Total person-weeks of observation

Student #5 and Student #7 developed brilliance during the 10-week course, so the incidence of brilliance over the course of the 10-week course is; Incidence = 2 ÷ 120 = 0.017 or 1.7%.

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The bearing of point A from point O is 256°.

In mathematics, a bearing is the angle in degrees measured clockwise from north. Bearings are usually given as a three-figure bearing. For example, 30° clockwise from north is usually written as 030°.

Given that, angle x= 076° and angle y = 111°.

Now, the bearing of point A from point O is

180°+ 076°

= 256°

Therefore, the bearing of point A from point O is 256°.

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Answer:

.57

Step-by-step explanation:

44 + 13 = 57 all you have to do is add the decimal behind it.

Answer:

Step-by-step explanation:

X=-6

Answer:

the correct answer will be

x=-6

Answer:

If 5x-2 = 3x+4, then x=3

Step-by-step explanation:

5x-2=3x+4

Add 2 to both sides, and you get 5x=3x+6. Subtract 3x from both sides, and you get 2x=6. Divide both sides by 2, and what's left is x=3. Hope this helps. :)

Answer: 120

Step-by-step explanation: divide 24 by 5 to get 4.8 so its 4.8 minutes for one question

25 x 4.8 = 120

Answer:

1

Step-by-step explanation:

On the Graph, When X is 4, Y is 1.

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The domain of f is the range of f-1, and the domain of f −1 is the range of f.

We can say that if we have a function f with domain X and range Y, then its inverse function f-1 will have domain Y and range X. This is because the roles of the input and output variables are reversed in the inverse function, so the domain and range of the original function become the range and domain of the inverse function, respectively.

It's important to note that not all functions have an inverse, and those that do may have restrictions on their domain and range to ensure the existence of a unique inverse.

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Answer:

D.

Step-by-step explanation:

Because the sign is facing the number 26 It means 26 is greater so 2x-4 has to be smaller (less then or equal to 26)

The component form of vector Vector A B minus vector C D is option D: LeftAngleBracket negative 6, 0, 5 RightAngleBracket.

To find the component form of vector AB minus vector CD, we first need to find the component form of each vector.

Vector AB has a change in x of 0, a change in y of -12, and a change in z of 1. So the component form of vector AB is <0, -12, 1>.

Similarly, vector CD has a change in x of 6, a change in y of -12, and a change in z of -4. So the component form of vector CD is <6, -12, -4>.

To find the difference between the two vectors, we subtract the corresponding components. So the component form of vector AB minus vector CD is
<0-6, -12-(-12), 1-(-4)>

which simplifies to
<-6, 0, 5>.

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