Don’t need to send the math or anything just need the answer will give brainliest!!!

Answer:

Step-by-step explanation:

2 cos(A+45)cos (B-45)

=2[cos A cos 45-sin A sin 45][cos B cos 45+sin B sin 45]

=2[cos A ×1/√2-sin A ×1/√2][cos B×1/√2+sin B×1/√2]

=2[1/√2(cos A-sin A)][1/√2(cos B-sin B]

=2×1/√2×1/√2 (cos A-sin A)(cos B+sin B)

=cosA cos B+cos A sin B-sin A cos B-sin A sin B

=cos A cos B-sin A sin B-(sin A cos B-cos A sin B)

=cos (A+B)-sin (A-B)

i think there should be A in place of B.

then

=cos (A+A)-sin (A-A)

=cos 2A-sin 0

=cos 2A

as sin 0=0

Answer:

IDR 480,000

Step-by-step explanation:

Persentase diskon = Harga lama - Harga baru / Harga lama

Harga lama = Harga sebelum diskon = x

Harga Baru = IDR 336000

Persentase diskon = 30%

Karenanya:

30% = x - 336000 / x

30/100 = x - 336000 / x

0.3 = x - 336000 / x

Cross Multiply

0.3 × x = x - 336000

0.3x = x - 336000

x - 0.3x = 336000

0.7x = 336000

x = 336000 / 0.7

x = IDR 480,000

Answer:

r = dx - de

Step-by-step explanation:

x = e + r/d

x - e = r/d

d (x - e) = r

dx- de = r

r = dx - de

Answer:

-8.6363 the proper answer (estimated) is -8.66

Answer:

-7.37 is the answer for this.

Step-by-step explanation:

2x^2+6x=36

x^2+3x=12

x^2+3x-12=0

x=(-3+(57)^0.5)/2 or x=(-3-(57)^0.5)/2

Given the following quadratic expression:

Let's check if the given equation can be solved by factoring.

a.) Let's determine the original equation.

From the original equation, we observed that the constant 155/9 is not a perfect square. For the original quadratic equation to be factorable, we must apply the method of completing the square.

Therefore, we can say that the original quadratic equation can't be solved by factoring.

Answer:

D

Step-by-step explanation:

the graph has a negative correlation

Answer:   C

Step-by-step explanation:

hope this helped

To predict the cost of driving 1800 miles per month, substitute 1800 in the given function C(d) = 0.2d + 280C(1800) = 0.2 (1800) + 280= $640 per month. Therefore, the cost of driving 1800 miles per month is $640.

(b) Graph is shown below:(c)The slope of the graph represents the rate of change of the cost of driving a car per mile. The slope is given by 0.2, which means that for every mile Lynn drives, the cost increases by $0.2.The y-intercept of the graph represents the fixed cost (amount she pays even if she does not drive).

The y-intercept is given by 280, which means that even if Lynn does not drive the car, she has to pay $280 per month.The linear function gives a suitable model in this situation because the monthly cost increases as the number of miles driven increases.

This is shown by the positive slope of the graph. The fixed cost is also included in the function, which is represented by the y-intercept. Therefore, a linear function is a suitable model in this situation.

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Answer:

He started with 1.25

Step-by-step explanation:

Joe started with 1.25 if he spends 3 quarters of that which is equal to .75 hell have .50 left

1.25-.75=.50

Answer:

4 :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

The given error full solution is

5x+5(-2x-12)=130

5x+-10x-60=130

65x=130x=-2.

Correct answer is given as

5x+5(-2x-12)=130.

We solve this question using Bodmas rule. So first we remove the parenthesis.

5x+5(-2x-12)=130

5x+5(-2x)+5(-12)=130

5x-10x-60=130

-5x=130+60

-5x=190

dividing both side by by (-5). We, get

x=190/(-5)

x=-38

Hence, the correct answer is x=-5

Answer:

About 216 words per minute.

Step-by-step explanation:

Hence the required expression is Proved.

Given the expression is 2 1/4 ₋ 6/7 = 39/28

Consider L.H.S 2 1/4 ₋ 6/7

Convert improper fraction to proper fraction.

2 1/4 = 9/4

take LCM of the denominators.

The LCM is 28.

9×7/28 ₋ 6×4/28

63/28 ₋ 24/28

Now subtract.

63 ₋ 24/28

39/28

Hence proved.

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Your question is incomplete. Please find the missing content here.

Show that 2 1/4 ₋ 6/7 = 39/28

The relation xOy is not reflexive and not transitive, it is not an equivalence relation. There are no equivalence classes to describe.

To determine whether the relation xoy on the set of all integers, where xoy if x+y is odd, is an equivalence relation, we need to check if it satisfies the three properties of reflexivity, symmetry, and transitivity.

1. Reflexivity:

For any integer x, x+x=2x, which is even.

Therefore, x0x is false, and the relation is not reflexive.

2. Symmetry:

If xOy, then x+y is odd. But y+x is also odd since addition is commutative.

Therefore, yOx, and the relation is symmetric.

3. Transitivity:

If xOy and yOz, then x+y is odd and y+z is odd. Adding these equations together,

we get x+y+y+z=x+z+2y, which is even.

Therefore, x+z is even, and xOz is false. Thus, the relation is not transitive.

Since the relation xOy is not reflexive and not transitive, it is not an equivalence relation. There are no equivalence classes to describe.

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The relation xOy is not reflexive and not transitive, it is not an equivalence relation. There are no equivalence classes to describe.

To determine whether the relation xoy on the set of all integers, where xoy if x+y is odd, is an equivalence relation, we need to check if it satisfies the three properties of reflexivity, symmetry, and transitivity.

1. Reflexivity:

For any integer x, x+x=2x, which is even.

Therefore, x0x is false, and the relation is not reflexive.

2. Symmetry:

If xOy, then x+y is odd. But y+x is also odd since addition is commutative.

Therefore, yOx, and the relation is symmetric.

3. Transitivity:

If xOy and yOz, then x+y is odd and y+z is odd. Adding these equations together,

we get x+y+y+z=x+z+2y, which is even.

Therefore, x+z is even, and xOz is false. Thus, the relation is not transitive.

Since the relation xOy is not reflexive and not transitive, it is not an equivalence relation. There are no equivalence classes to describe.

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The given formula, aₙ = -3aₙ₋₁, where a₁ = -2, is a recursive formula. The first five terms of the sequence are -2, 6, -18, 54, and -162.

In a recursive formula, each term of the sequence is defined in terms of previous terms. In this case, the value of each term aₙ is determined by multiplying the previous term aₙ₋₁ by -3.

To find the first five terms of the sequence, we can use the recursive formula:

a₁ = -2

a₂ = -3a₁ = -3(-2) = 6

a₃ = -3a₂ = -3(6) = -18

a₄ = -3a₃ = -3(-18) = 54

a₅ = -3a₄ = -3(54) = -162

Therefore, the first five terms of the sequence are -2, 6, -18, 54, and -162.

The recursive formula allows us to generate subsequent terms of the sequence by applying the given rule to the previous term. It provides a relationship between terms in a sequential manner.

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Pairs of values that could be the number of grams of protein and fiber in the protein bar are:

10 grams of protein and 20 grams of fiber. That is, (10, 20)

and

15 grams of protein and 10 grams of fiber. That is, (15, 10)

From the question, we are to determine the pair of values that could be the number of grams of protein and fiber in the protein bar

From the given information,

The protein has 80 calories from p grams of protein and f grams of fiber

and

The equation that represents the relationship is

4p + 2f = 80

To determine the pair of values, we can determine the values of f for certain values of p

When p = 10

4p + 2f = 80

4(10) + 2f = 80

40 + 2f = 80

2f = 80 - 40

2f = 40

f = 40/2

f = 20

A pair of values is 10 grams of protein and 20 grams of fiber.

When p = 15

4p + 2f = 80

4(15) + 2f = 80

60 + 2f = 80

2f = 80 - 60

2f = 20

f = 20/2

f = 10

Thus,

Another pair of values is 15 grams of protein and 10 grams of fiber.

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Answer:

20.33%

Step-by-step explanation:

Answer:

D) 79.05%

Step-by-step explanation:

I JUST TOOK DA TEST

Answer:

B. 9

Step-by-step explanation:

m∠U = 2x°

m∠V = 4m∠U

        = 4(2x°)

        = 8x°

Complementary angles add up to 90°.

∠U + ∠V = 90°

2x° + 8x° = 90°

10x° = 90°

x = 90° ÷ 10°

  = 9

The transformation of f(x) to g(x) is g(x) = (x + 6)² + 4

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

Where, we have

f(x) = x²

The translation 6 units left and 4 units up means that

g(x) = f(x + 6) + 4

So, we have

g(x) = (x + 6)² + 4

This means that the transformation of f(x) to g(x) is g(x) = (x + 6)² + 4

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Answer:

It depends on what the question is.

Step-by-step explanation:

To transform a set of vectors into orthonormal vectors using the Gram-Schmidt process, normalize the first vector, compute the projections onto the previous orthonormal vectors, subtract the projections, and normalize the resulting vectors successively.

To apply the Gram-Schmidt process to transform the set of vectors (1, 2, 1), (1, -1, 0), (0, 1, 0) into orthonormal vectors, follow these steps:

Take the first vector, v1 = (1, 2, 1), and normalize it to obtain the first orthonormal vector, u1:

u1 = v1 / ||v1||, where ||v1|| represents the norm or magnitude of v1.

Compute the projection of the second vector, v2 = (1, -1, 0), onto the first orthonormal vector, u1:

proj(v2, u1) = (v2 · u1) * u1, where · represents the dot product.

Subtract the projection from v2 to obtain a new vector, v2' = v2 - proj(v2, u1).

Normalize v2' to obtain the second orthonormal vector, u2:

u2 = v2' / ||v2'||.

Repeat steps 2-4 for the third vector, v3 = (0, 1, 0), using u1 and u2 as the previous orthonormal vectors.

The resulting vectors u1, u2, and u3 will be the orthonormal vectors obtained through the Gram-Schmidt process.

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The other factor of f(x) is determined as 6x² - x - 15.

If you are given that x - 4 is a factor of f(x) = 6x³ - 25x² - 11x + 60, you can use polynomial long division or synthetic division to find the other factor(s) and the remainder.

Using synthetic division:

4 | 6  -25  -11  60

  |    24   -4 -28

  |----------------

  6   -1  -15  32

So, the quotient is 6x² - x - 15 and the remainder is 32. Therefore, we can write:

f(x) = (x - 4)(6x² - x - 15) + 32

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Answer:

2(-3±√120)

Step-by-step explanation:

quadratic formula

The equation that is quadratic form is 6(x + 2)²+ 8x + 2 + 1 = 0

A quadratic equation is an algebraic expression whose polynomial is in the order of two. The general formula for representing a quadratic equation takes the order of:

From the given options, the equation that takes a quadratic form is:

6(x + 2)²+ 8x + 2 + 1 = 0

solve the brackets

6(x² + 4x + 4) + 8x + 3 = 0

6x² + 24x + 24 + 8x + 3 = 0

6x² + 32x + 27 = 0

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Answer:

a

Step-by-step explanation:

Answer:

To find the perimeter of triangle ABC, we need to find the lengths of all three sides of the triangle. To do this, we can use the distance formula, which states that the distance between two points (x1, y1) and (x2, y2) is given by the square root of ((x2 - x1)^2 + (y2 - y1)^2).

Applying this formula, we can find the lengths of the sides of the triangle as follows:

AB = sqrt((7 - (-1))^2 + (-6 - (-6))^2) = sqrt(8^2 + 0^2) = sqrt(64) = 8

BC = sqrt((3 - 7)^2 + (-3 - (-6))^2) = sqrt(-4^2 + 3^2) = sqrt(16 + 9) = sqrt(25) = 5

AC = sqrt((-1 - 3)^2 + (-6 - (-3))^2) = sqrt(-4^2 + 3^2) = sqrt(16 + 9) = sqrt(25) = 5

Thus, the perimeter of triangle ABC is 8 + 5 + 5 = 18 units.

Answer:

A = 54 is the correct answer!

Step-by-step explanation:

I did this test too! Hope this helped!

Answer: The value of e^(-∞) (e to the power of negative infinity) is equal to zero.

To see why, recall that e is a positive constant approximately equal to 2.71828. As the exponent approaches negative infinity, e^(-∞) represents the limit of a number getting closer and closer to zero but never actually reaching zero.

We can use the limit definition to evaluate the limit of e^(-x) as x approaches infinity:

lim e^(-x) = 0

x→∞

To see this, note that as x becomes very large, the denominator e^x becomes very large, causing the fraction to approach zero. Since the limit of e^(-x) as x approaches infinity is zero, we can say that e^(-∞) is also equal to zero.

In summary, e^(-∞) = 0.

Step-by-step explanation:

Answer: 2x^2

Step-by-step explanation:

    (x+5)

 x (2x - 9)

-----------------

X times 2x = 2x^2