During the experiment it is determined that, as the cart rolls between two points on the track, the work done on the cart by the hanging masses and other forces present is 0.91 J. At the initial time of observation the cart moves with speed 0.61 m/s. Determine the speed at the second point of observation. The mass of the cart is 0.80 Kg.

Answers

Answer 1

Answer:

Explanation:

If the work done on the cart is NET work

Then the work will result in an increase in kinetic energy

KE₀ + W = KE₁

½mv₀² + W = ½mv₁²

½(0.80)(0.61²) + 0.91 = ½(0.80)v₁²

v₁ = 1.626991...

v₁ = 1.6 m/s

Answer 2

The speed of the cart at the second point of observation is equal to 1.62 m/s.

What is the work done?

Work can be demonstrated as the energy utilized when a force is exerted to make an object move through a particular displacement. Work done by this force is calculated from the product of the magnitude of the exerted force (F) and the distance (d) covered by the body

W= F.d

Where 'F' is the exerted force and 'd' is the displacement and W is work done.

Work and energy have a direct relationship with each other. Work done by an object can be expressed as a change in kinetic energy:

\(W =\frac{1}{2}mv_2^2- \frac{1}{2}mv_1^2\)

Where m is the mass of the object, v₂ is the final velocity (m/s), and v₁ is the initial velocity (m/s).

Given, the work done by the cart, W = 0.91 J

The mass of the cart, m = 0.80 Kg

The speed of the cart at the first point, v₁ = 0.61 m/s

\(0.91 =\frac{1}{2}\times 0.80 \times v_2^2- \frac{1}{2}0.80 \times (0.61)^2\)

0.40 v₂² = 1.06

v₂² = 2.65

v₂ = 1.62 m/s

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Related Questions

A string applies an upward (tension) force of 34 N to lift a bucket of mass 2.8 kg. What is
the acceleration of the bucket? (Answer in m/s²)

Answers

The acceleration of the bucket of mass 2.8 kg which is lifted upwards with a force of 34 N is 12.14 m / s²

According to Newton's second law of motion,

F = m a

F = Force

m = Mass

a = Acceleration

F = 34 N

m = 2.8 kg

a = F / m

a = 34 / 2.8

a = 12.14 m / s²

Acceleration is the rate of change of velocity of an object with respect to time. It is denoted as a.

Therefore, the acceleration of the bucket is 12.14 m / s²

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A chemist measures the flow of charged ions through a circuit. Which of these would increase the current? Select all that apply.

A chemist measures the flow of charged ions through a circuit. Which of these would increase the current?

Answers

2,3 and 5 should be right

Focal plane of a menisc lens

Answers

We will have that the general ray diagram of the meniscus lens is the following:

Focal plane of a menisc lens

what is indoor noise pollution​

Answers

Answer:

Domestic gadgets like the mixer-grinders, pressure cookers, desert coolers, air- conditioners, exhaust fans, vacuum cleaners, sewing and washing machines are all indoor sources of noise pollution.

Explanation:

What is the mass of gasoline consumed in kg (assume gasoline is made of octane, d=703 kg/m^3)?

Answers

Answer:

Explanation:

Is the equation above stoichiometrically balanced? (And what does stoichiometric mean?). This equation tells us that for each mole of octane (each 116 g!), 8 moles of carbon dioxide (

8

×

44

g

) will result. Now the question tells us that 1.8 gallons of gas have been consumed.

Consider a large truck carrying a heavy load, such as steel beams. A significant hazard for the driver is that the load may slide forward, crushing the cab, if the truck stops suddenly in an accident or even in braking. Assume, for example, that a 10000-kg load sits on the flatbed of a 20000-kg truck moving at 12.0 m/s. Assume that the load is not tied down to the truck, but has a coefficient of static friction of 0.500 with the flatbed of the truck.
(a) Calculate the minimum stopping distance for which the load will not slide forward relative to the truck.
(b) Is any piece of data unnecessary for the solution?

Answers

Answer:

\(14.68\ \text{m}\)

Masses of the truck and load

Explanation:

v = Final velocity = 0

u = Initial velocity = 12 m/s

\(\mu\) = Coefficient of friction = 0.5

a = Acceleration

g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)

s = Displacement

f = Friction

F = Force applied

The force balance of the system is given by

\(F=-f\\\Rightarrow ma=-\mu mg\\\Rightarrow a=-\mu g\)

From the kinematic equations we have

\(v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2(-\mu g)}\\\Rightarrow s=\dfrac{0-12^2}{2(-0.5\times 9.81)}\\\Rightarrow s=14.68\ \text{m}\)

The minimum stopping distance for which the load will not slide forward relative to the truck is \(14.68\ \text{m}\)

As it can be seen that the masses of the truck and load are not used in the above used formulae. So, they are unnecessary.

A student drops a rock from rest at a distance h above the ground such that the rock hits the ground at a time t0 . At what distance above the ground should the rock be dropped such that it hits the ground at a time 2t0 after it is released.?

Answers

The distance above the ground the rock should be raised in order to hits the ground double of initial time is 4h.

The given parameters;

initial velocity of the rock, u = 0height above the ground, = htime of motion of the rock from the height = t₀

The time of motion of the rock from the given height is calculated as;

\(h = ut + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt_0^2\\\\h = \frac{1}{2} gt_0^2\\\\t_0^2 = \frac{2h}{g} \\\\t_0 = \sqrt{\frac{2h}{g} }\)

When the time of motion is doubled to 2t₀, the height above the ground should be;

\(2(t_0) = 2(\sqrt{\frac{2h}{g} } )\\\\2(t_0) = \sqrt{\frac{4\times 2h}{g} }\)

Thus, the distance above the ground the rock should be raised in order to hits the ground double of initial time is 4h.

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What is a pendulum?

A.)A pendulum is a grandfather clock.

B.)A pendulum is a mass suspended on the bottom of a string.

C.)A pendulum is several weights tied together and arranged in a circle.

D.) A pendulum is the time it takes for a bob to swing back and forth one time.

Answers

B) A pendulum is a mass suspended on the bottom of a string.

A pendulum is a simple mechanical device that consists of a mass (known as the bob) suspended from a fixed point by a string, wire, or rod. When the bob is pulled to one side and released, it swings back and forth under the influence of gravity, forming a regular pattern of motion. The time it takes for the pendulum to complete one full swing (i.e., from one extreme position to the other and back again) is known as its period. The period of a pendulum is affected by the length of the string and the strength of gravity. The longer the string, the longer the period, and the stronger the gravity, the shorter the period.Pendulums have a wide range of practical applications, such as timekeeping, as seen in grandfather clocks. They are also used in scientific experiments to measure time intervals and gravitational acceleration.

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Calculate the first and second order angles for light of wavelength 400. nm and 700. nm of the grating contains 1.00 x 104 lines/cm.

Answers

Answer:

\(23.58^{\circ}\) and \(53.13^{\circ}\)

\(44.43^{\circ}\), second order does not exist

Explanation:

n = Number of lines grating = \(1\times10^4\ \text{Lines/cm}\)

\(\lambda\) = Wavelength

m = Order

Distance between slits is given by

\(d=\dfrac{1}{n}\\\Rightarrow d=\dfrac{1}{1\times 10^4}\\\Rightarrow d=10^{-6}\ \text{m}\)

\(\lambda=400\ \text{nm}\)

m = 1

We have the relation

\(d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}\\\Rightarrow \theta=\sin^{-1}\dfrac{1\times 400\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=23.58^{\circ}\)

m = 2

\(\theta=\sin^{-1}\dfrac{2\times 400\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=53.13^{\circ}\)

The first and second order angles for light of wavelength 400 nm are \(23.58^{\circ}\) and \(53.13^{\circ}\).

\(\lambda=700\ \text{nm}\)

m = 1

\(\theta=\sin^{-1}\dfrac{1\times 700\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=44.43^{\circ}\)

m = 2

\(\theta=\sin^{-1}\dfrac{2\times 700\times 10^{-9}}{10^{-6}}\)

Here \(\dfrac{2\times 700\times 10^{-9}}{10^{-6}}=1.4>1\) so there is no second order angle for this case.

The first order angle for light of wavelength 700 nm are \(44.43^{\circ}\).

Second order angle does not exist.

1. If airbags reduce the impact force from an accident why has there been questions over their safety?

2. Are airbags the safest option to prevent serious injury or death from a car accident?

Answers

Answer:Air bags can leave you in even more injury, From the impact they give

You could end up with a broken nose,arm

concussion

What is surface tension??​

Answers

Answer:

Surface tension is the tendency of liquid surfaces to shrink into the minimum surface area possible. Surface tension allows insects (e.g. water striders), usually denser than water, to float and slide on a water surface.

Explanation:

Answer:

It is the tension of the surface film of a liquid caused by the attraction of the particles in the surface layer by the bulk of the liquid, which tends to minimize surface area.

When the rate of the forward reaction equals the rate of the backward reaction, the system is said to be in

Answers

Answer:

equilibrium

Explanation:

bcoz forward reaction equals backward reaction

A machine has a velocity ratio of 5 and the efficiency is 80% what effort would be needed to lift a load of 200N​

Answers

Explanation:

To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:

Efficiency = (Output Work / Input Work) * 100

Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.

Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.

Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."

Using the velocity ratio, we have the following relationship:

dE / dL = 5

Now, we can calculate the input work (Wi) and the output work (Wo):

Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)

Output Work (Wo) = Load (L) * Distance moved by the load (dL)

Given that the efficiency is 80%, we can rewrite the formula for efficiency as:

0.80 = (Wo / Wi) * 100

Now, let's solve for the effort (E) using the given values:

Load (L) = 200N

Efficiency = 0.80

Velocity Ratio = 5

First, calculate the output work (Wo):

Wo = Load (L) * Distance moved by the load (dL)

Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):

dL = (1/5) * dE

Wo = L * (1/5) * dE

Wo = 200N * (1/5) * dE

Wo = 40N * dE

Next, calculate the input work (Wi):

Wi = Effort (E) * Distance moved by the effort (dE)

Wi = E * dE

Now, substitute the values into the efficiency formula:

0.80 = (Wo / Wi) * 100

0.80 = (40N * dE) / (E * dE) * 100

0.80 = 40 / E * 100

0.80 * E = 40

E = 40 / 0.80

E = 50N

Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.

Barney walks at a velocity of 1.7 meters/second on an inclined plane which has an angle of 18.5 with the ground what is the horizontal component of Barney’s velocity

Answers

Answer:

Explanation:

The horizontal velocity is 1.61.

Barney walks at a velocity of 1.7 meters/second on an inclined plane which has an angle of 18.5 with

What is the impulse that Earth exerts on it during the first 0.50m of its fall? The next 0.50 m ?

Answers

The impulse exerted by Earth on the apple during the first 0.50 m of its fall is 0.74 Ns, and during the next 0.50 m, it is 0.37 Ns.

Using the equation for impulse, which is impulse = force x time, we can calculate the impulse that Earth exerts on the apple during the first 0.50 m and the next 0.50 m of its fall.

First, we need to calculate the force of gravity acting on the apple, which is given by the equation F = mg, where m is the mass of the apple and g is the acceleration due to gravity (approximately 9.81 m/s^2).

The mass of the apple is 150 g, which is 0.15 kg. Therefore, the force of gravity acting on the apple is:

F = mg = (0.15 kg)(9.81 m/s^2) = 1.47 N

Now, we can calculate the impulse exerted by Earth on the apple during the first 0.50 m of its fall. Since the force of gravity is constant, we can use the equation impulse = force x distance, where distance is the distance over which the force is applied.

Impulse during first 0.50 m = force x distance = (1.47 N)(0.50 m) = 0.74 Ns

For the next 0.50 m of the apple's fall, we need to consider that the velocity of the apple is increasing, so the force of gravity is no longer constant. However, we can approximate the average force over this distance as half the force at the start of the fall, or 0.5(1.47 N) = 0.74 N.

Using the same equation impulse = force x distance, we can calculate the impulse exerted by Earth on the apple during the next 0.50 m of its fall:

Impulse during next 0.50 m = force x distance = (0.74 N)(0.50 m) = 0.37 Ns.

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Lightning flashes and you hear a thunderclap 4 seconds later. The velocity of sound is 340 m/s. How far away did the lightning strike?

Answers

Answer:

1,360 m

Explanation:

340 meters per second, and it was 4 seconds later.

340 * 4 is how to find teh distance where the lightning struck.

340 * 4 = 1,360 meters

Find the Magnitude of the resultant vector (the actual
path of the boat).
The picture is a little blurry, so here are the stats:
Velocity of the boat is 0.75 m/s
Velocity of the river is 1.2 m/s

Answers

The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.


To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.

Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.

To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:

Resultant magnitude = √(boat velocity^2 + river velocity^2)

Plugging in the given values, we have:

Resultant magnitude = √(0.75^2 + 1.2^2)

= √(0.5625 + 1.44)

= √2.0025

≈ 1.42 m/s

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Astronomers have recently observed stars orbiting at very high speeds around an unknown object near the center of our galaxy. For stars orbiting at distances of about 1014 m from the object, the orbital velocities are about 106 m/s. Assume the orbits are circular, and estimate the mass of the object, in units of the mass of the sun (MSun = 2x1030 kg). If the object was a tightly packed cluster of normal stars, it should be a very bright source of light. Since no visible light is detected coming from it, it is instead believed to be a supermassive black hole.

Answers

Answer:

The mass of the object is 745000 units of the sun

Explanation:

We know that the centripetal force with which the stars orbit the object is represented as

\(F_{c}\) = \(\frac{mv^{2} }{r}\)

and this centripetal force is also proportional to

\(F_{c}\) = \(\frac{kMm}{r^{2} }\)

where

m is the mass of the stars

M is the mass of the object

v is the velocity of the stars = 10^6 m/s

r is the distance between the stars and the object = 10^14 m

k is the gravitational constant = 6.67 × 10^-11 m^3 kg^-1 s^-2

We can equate the two centripetal force equations to give

\(\frac{mv^{2} }{r}\) = \(\frac{kMm}{r^{2} }\)

which reduces to

\(v^{2}\) = \(\frac{kM}{r}\)

and then finally

M = \(\frac{rv^{2} }{k}\)

substituting values, we have

M = \(\frac{10^{14}*(10^{6})^{2} }{6.67*10^{-11} }\) = 1.49 x 10^36 kg

If the mass of the sun is 2 x 10^30 kg

then, the mass of the the object in units of the mass of the sun is

==> (1.49 x 10^36)/(2 x 10^30) = 745000 units of sun

the critical angle of oil is 28.8 what is the refractive index

Answers

The light beam shown in the figure below makes an angle of ϕ=28.8∘ ϕ = 28.8 ∘ with the normal line NN' in the linseed oil. Determine the angles θ and θ′ . (The refractive index for linseed oil is 1.48.)

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Activity 1: UNITS OF MEASUREMENT

I. Identify the quantity described by the following units of measurement. Copy and write your answer on one whole sheet of paper.


1. meter per second = _________ 11. joule = ____________

2. meter = _________ 12. Kilogram = ____________

3. second = _________ 13. Cubic meter = _________

4. meter per second squared = ____ 14. Mole = ____________

5. square meter = _________ 15. Kilogram per cubic meter=

6. mass = _________ 16. Watt = ____________

7. newton = _________ 17. Ampere = ____________

8. kelvin = _________ 18. Hertz = ____________

9. volt = _________ 19. Coulomb = ____________

10. candela = __________ 20. Pascal = ____________

Answers

meter per second = speed or velocitymeter = length or distancesecond = timemeter per second squared = accelerationsquare meter = areamass = amount of matter in an objectnewton = forcekelvin = temperaturevolt = electric potential or voltagecandela = luminous intensityjoule = energy or workkilogram = masscubic meter = volumemole = amount of substancekilogram per cubic meter = densitywatt = power or rate of doing workampere = electric currenthertz = frequencycoulomb = electric chargepascal = pressure

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A sample of The halflife of the substance is 21 minutes the number of atoms remaining underway. radioactive Substances has 812X1020 atom Determine the number of atoms remaining

Answers

After 42 minutes, there are 203 x \(10^{20\) atoms remaining of the radioactive substance.

To determine the number of atoms remaining after a certain amount of time has passed, we can use the formula for radioactive decay:

N(t) = N0 * \((1/2)^{(t / T)\),

where:

N(t) = number of atoms remaining at time t,

N0 = initial number of atoms (812 x  \(10^{20\) atoms),

T = half-life of the substance (21 minutes), and

t = time that has passed.

Let's calculate the number of atoms remaining after a given time.

Suppose the time passed is t = 42 minutes (twice the half-life).

N(t) = 812 x  \(10^{20\) * \((1/2)^{(42 / 21)\)

N(t) = 812 x  \(10^{20\) * \((1/2)^2\)

N(t) = 812 x  \(10^{20\) * 1/4

N(t) = 203 x  \(10^{20\) atoms.

So, after 42 minutes, there are approximately 203 x \(10^{20\) atoms remaining of the radioactive substance.

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What is a black hole's escape velocity?

Answers

ANSWER

The simplest definition of a black hole is an object that is so dense that not even light can escape its surface. If we squished the Earth's mass into a sphere with a radius of 9 mm, the escape velocity would be the speed of light. Just a wee-bit smaller, and the escape velocity is greater than the speed of light.

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What is the field outside the capacitor plates in a parallel capacitor?​

Answers

Answer is zero

Plz mark me brainlist

Explanation:

Outside two infinite parallel plates with opposite charge the electric field is zero, and that can be proved with Gauss's law using any possible Gaussian surface imaginable

What is the period of an objects motion?

Answers

The time for an object to complete one full cycle. Can have a long period or short period.


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QUESTIONS An athlete, during his race in the 100 m sprint in the 2008 Beijing Olympics, exerted #force of 850 s on the race track using his show on the right foot at an angle of 50/' to the horizontal, 850 N 3.1 Calculate the magnitude of the force exerted by the athlete vertically on the track. 3.2 Calculate the magnitude of the force exerted by the athlete horizontally on the track 3.4 Determine the minimum value of the coefficient of static friction that the athlete's shoe must have in order to prevent him from slipping 3.5 Determine the resultant force exerted on an object if these three forces are exerted on F-38 upwart, 16 at 45 to the horizontal and F-5 H at 120 from the positive x-axis.​

Answers

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

There is a 247–m–high cliff at Half Dome in Yosemite National Park in California. Suppose a boulder breaks loose from the top of this cliff. What is the velocity of the boulder just before it strikes the ground?

Answers

Answer:

Vf = 69.61 m/s

Explanation:

We will use the third equation of motion to solve this problem:

\(2gh = V_{f}^2 - V_{i}^2\\\)

where,

g = acceleration due to gravity = 9.81 m/s²

h = height of cliff = 247 m

Vf = final velocity = ?

Vi = initial velocity = 0 m/s (boulder breaks loose from rest)

Therefore,

\((2)(9.81\ m/s^2)(247\ m) = V_{f}^2 - (0\ m/s)^2\\V_{f} = \sqrt{4846.14\ m^2/s^2}\\\)

Vf = 69.61 m/s

What magnification will be produced by a lens of power −4.10 D (such as might be used to correct myopia) if an object is held 22.5 cm away?

Answers

Answer:

The magnification = 0.52

Explanation:

Power, P = -4.10D

Object distance, u = 22.5 cm

Focal length, f = 100/power

f = 100/-4.10

f = -24.39 cm

Using the formula below, calculate the image distance (v)

\(\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\)

Substitute u = 22.5, f = -24.39, and solve for v

\(\begin{gathered} \frac{1}{-24.39}=\frac{1}{22.5}+\frac{1}{v} \\ \\ \frac{1}{v}=-\frac{1}{24.39}-\frac{1}{22.5} \\ \\ \frac{1}{v}=-0.041-0.044 \\ \\ \frac{1}{v}=-0.085 \\ \\ v=-\frac{1}{0.085} \\ \\ v=-11.8 \end{gathered}\)

The magnification, M = |v/u|

M = |-11.8/22.5|

M = |-0.52|

M = 0.52

The magnification = 0.52

can someone help with the vocabulary of the relative age of rocks

can someone help with the vocabulary of the relative age of rocks

Answers

I don’t think this is physics but I’ll help you out , ok well this is just basic vocab so your answers will be

5.b
6.h
7.g
8.e
9.c
10.d
11.a
12.f

4. Answer the following questions in terms of a wave's frequency, wavelength, amplitude, and
energy.
a. Describe the characteristics of a high pitch wave.
b. Describe the characteristics of a high-volume wave.

Answers

a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.

The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.

The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.

b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.

The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.

In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.

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Suppose particles A, B, and C in the figure (Figure 1) have identical masses and charges of the same magnitude. Rank the particles in order of decreasing speed. Rank particles from fastest to slowest. To rank items as equivalent, overlap them. The correct ranking cannot be determined.

Answers

The particles in order of decreasing speed, A, B and then C

Particle A will be moving the fastest, followed by Particle B, and then Particle C will be moving the slowest. This is because Particle A's trajectory is nearly perpendicular to the magnetic field and experiences the least magnetic force, while Particle C's trajectory is nearly parallel to the magnetic field and experiences the greatest magnetic force.

As all three particles have the same mass and charge, the force acting on them is proportional to their velocity, so Particle A will be moving the fastest and Particle C will be moving the slowest. Particle B will have an intermediate velocity between the two.

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--The complete question is, Suppose particles A, B, and C in the figure (Figure 1) have identical masses and charges of the same magnitude.

Rank the particles in order of decreasing speed.--

Suppose particles A, B, and C in the figure (Figure 1) have identical masses and charges of the same
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lexy is pursuing a graduate degree is psycholofy. As part of her program she must write a long detailed research paper based on the data she spent the last year gathering. What is the long research paper called 63.7+(-26) what is 63.7 plus negative 26 Which technique for sampling 20 tosses of a coin would most likely introduce a sampling error?Choosing the first 10 events for the samplePutting all the events into two groups of heads and tails and randomly selecting 5 events from each groupNumbering all the events and using a random number generator to select 10 eventsTaking every other event until 10 events are selected 1 2 3 4 5 6 7 8 9 10 Time Remaining 16:34:10 The president has six distinct roles. Which of the following roles does NOT belong to the President of the United States? A. head of state B. commander in chief C. leader of foreign policy D. chief justice of the Supreme Court What was the outcome of the 1980 presidential election?A. Ronald Reagan won both the electoral and popular votes, whilePresident Carter experienced losses in every region.B. President Carter won the electoral vote, but Ronald Reagan wonthe popular vote.C. President Carter won both the electoral and the popular vote, butRonald Reagan won two states.D. Ronald Reagan won both the electoral and popular votes, whilePresident Carter experienced losses in every region. Compromise is a form of bargaining. Next time you overhear a dispute, suggest ways that the two parties might reach an agreement. Question 1 of 50Which 2 statements regarding sources and targets are true?There is one source per transactionThere is only one target per transactionSources provide information about classesSource accounts are always Balance Sheet accounts do caveman like me use bathroom? Convert 78 angle to radians. (round to 3 decimal places)Suppose that a farmer has a mobile sprinkler that can be pulled by a tractor. He pulls it into his field and sets it rotate within an angle of 143 and a distance from the sprinkler head of 260 feet. What is area of the filed he is covering in water? (round your answer to the nearest foot) Compare the haldane effect and the bohr effect and explain how they allow for gas exchange in the blood. make sure to use the terms internal and external respiration, partial pressures, carbonic acid, bicarbonate, hemoglobin, and h+ ion in your comparison. Home Depot entered fiscal 2017 with a total capitalization of $21,904 million. In 2017, debt investors received interest income of $877 million. Net income to shareholders was $8,654 million. (Assume a tax rate of 21%.)Calculate the economic value added assuming its cost of capital is 10%. (Do not round intermediate calculations. Enter your answer in millions rounded to 2 decimal places.) Linda purchased a prepaid phone card for 30. Long distance calls cost 19 cents a minute using this card. Linda used her card only once to make a long distance call. If the remaining credit on her card is 23.73 , how many minutes did her call last? ILL GIVE BRAINLY THINGQuakers were tolerant of most. However, they opposed __________________ vehementlyGroup of answer choicesThe institution of Public EducationThe institution of SlaveryOrganized religionThe Natives Select the correct answer. Why does Bierce use a flashback in section 2 of "An Occurrence at Owl Creek Bridge" instead of proceeding with the events taking place? to introduce Peyton Farquhar to emphasize the folly of romanticism to depict the cunningness of the Federal soldiers to emphasize the naivety of the Confederacy to help the reader know what led to the events in section 1 A. 1, 2, 3 B. 3, 4, 5 C. 1, 2, 5 D. 2, 3, 5 E. 1, 4, 5 dr. rodriguez, a present-day psychiatrist in the us, most likely adheres to what model of mental illness and human behavior? group of answer choices supernatural analytic biopsychosocial cathartic Which XXX will search the input name in the GuestList.txt file? #include > userName: while (links. eof) inF5 >> listNome: XXX if(listName - userName) { Flag - 1 - > if(flag 1) cout A and B are complementary angles. If m_A= (2x + 10) and mZB = (3x + 15), then find the measure of ZB What is the name of the compound, c9 h18? a. 1,3 diethylcyclopentane b. 3,1 diethylcyclopentane c. 1,3 dimethylcyclopentane d. 3,1 dimethylcyclopentane Air quality monitoring a. is an important step toward making the air safe for all earth's organisms. b. is unnecessary when the air is free of pollutants from human activities. c. is not believed to be helpful in maintaining the health of human populations. d. does not produce data that are reliable enough to justify air quality controls. Which of these is a unit rate?18 students in a class18 students in 18 chairs18 students in 6 rows18 students in 2 reading groups