Each flyball of the centrifugal governor shown in Figure 2 has a mass of 0.5 kg and revolves at a constant speed v in the horizontal circle of 150-mm. radius shown. Neglecting the weights of links AB, BC, AD, and DE, and sleeve CE, and requiring that the links support only tensile forces, determine the range of the allowable values of v so that the magnitudes of the forces in the links do not exceed 75 N

Answer:

Where is the table?

Explanation:

Remove an electrical plug, ensure dry hands, and firmly pull it straight out from the socket.

To remove an electrical plug from its socket, your hands must be dry, and you should firmly grasp the plug and pull it straight out.

When removing an electrical plug from its socket, it is essential to ensure that your hands are dry to avoid the risk of electrical shock. Moisture or wetness on your hands can increase conductivity and make it easier for electricity to pass through your body. Additionally, it is important to firmly grasp the plug while pulling it straight out from the socket. This helps maintain control and prevents any accidental damage to the plug or socket.

It is advisable to avoid yanking or twisting the plug forcefully, as this can lead to bent or broken prongs and potential hazards. By following these precautions, you can safely remove electrical plugs from sockets and reduce the risk of electrical accidents.

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Answer:

The development of homosapiens

Explanation:

People adapted to the harsh weather by creating tools and used land bridges to spread to new regions

(1 Ans) Phone issues are quick for me to solve. I can probably have this fixed in 10 minutes.

(2 Ans)  Everything looked fine. but  i found one server we need to replace. Can we find a time to replace schedule replacement when it will affect the fewest people?

(3 Ans)  An app is any program that runs on your phone, like your email. A better app might be a good fix.

A computer that can provide services to other computers (clients) on its network is referred to as a server. Servers may be outfitted with particular software or hardware. Servers come in a variety of shapes and sizes, as well as capabilities.

Consider how you get around. Anything that can move a person or object from one place to another can be considered a form of transportation. One person can travel by bicycle, four people by car, fifty people by bus, and five hundred people by plane. All of them are transportation methods, but they each have a unique capacity. For servers, the same rules apply.

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Large motors with horsepower greater than 5 typically use higher voltage levels and require special protective measures for safe operation.

Large motors with horsepower greater than 5 are typically used in heavy industrial applications, such as mining, oil and gas, manufacturing, and transportation. These motors are designed to handle high power loads and operate in harsh environments, such as high temperatures, high humidity, and dusty or dirty conditions. They are often used to power large equipment, such as pumps, compressors, fans, conveyors, and cranes, that require high torque and high speed. Large motors can range in size from several hundred horsepower to several thousand horsepower and may be powered by electricity, diesel, or other fuels. For example, an electric motor with a rated output of 7.5 HP (horsepower) requires 208-230 volts for proper operation.

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Answer:

yes

Explanation:

blueprint of the construction is a prediction of project its is slightly auto cad

Answer:

All 3 principal stress

1. 56.301mpa

2. 28.07mpa

3. 0mpa

Maximum shear stress = 14.116mpa

Explanation:

di = 75 = 0.075

wall thickness = 0.1 = 0.0001

internal pressure pi = 150 kpa = 150 x 10³

torque t = 100 Nm

finding all values

∂1 = 150x10³x0.075/2x0,0001

= 0.5625 = 56.25mpa

∂2 = 150x10³x75/4x0.1

= 28.12mpa

T = 16x100/(πx75x10³)²

∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]

= 1/2[84.37±√791.2969+5.827396]

= 1/2[84.37±28.33]

∂1 = 1/2[84.37+28.33]

= 56.301mpa

∂2 = 1/2[84.37-28.33]

= 28.07mpa

This is a 2 d diagram donut is analyzed in 2 direction.

So ∂3 = 0mpa

∂max = 56.301-28.07/2

= 14.116mpa

Note that the nameplate or rating plate on an electric motor provides information that will assist a person in selecting, installing, and energizing the correct motor for the job.

The electric motor was not invented by a single individual, but rather its development involved the work of many scientists and inventors over time.

The earliest form of an electric motor was created in 1821 by Michael Faraday, who demonstrated the conversion of electrical energy into mechanical motion. Subsequent inventors such as Thomas Davenport, Nikola Tesla, and Galileo Ferraris made significant contributions to the development of the electric motor, paving the way for its modern-day applications in a wide range of industries.

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Answer:

  83.6%

Explanation:

On its current schedule, the plant can theoretically produce ...

  (30 pc/h/machine)(10 machine)(8 h/shift)(2 shift/day)(5 day/wk)(50 wk/yr)

  = (30)(10)(8)(2)(5)(50) pc/yr = 1,200,000 pc/yr

__

On the proposed schedule, this production becomes ...

  (30 pc/mach)(10 mach)(8 h/sh)(3 sh/da)(6 da/wk)(51 wk/yr)

  = (30)(10)(8)(3)(6)(51) pc/yr = 2,203,200 pc/yr

The increase in capacity is ...

  (2,203,200/1,200,000 -1) × 100% = 83.6% . . . capacity increase

_____

Additional comment

The number of parts per shift did not change. Only the number of shifts per year changed. It went up by a factor of (3/2)(6/5)(51/50) = 1.836. Hence the 83.6% increase in capacity.

We have to assume that maintenance and repair are done as effectvely as before in the reduced down time that each machine has.

6.25×10⁻¹⁸ electrons will flow through a copper wire.

Electrons can be defined as the sum of atomic particles that is the career of negative charge, they are responsible for the chemical property of an element, the electrons are present in the shell.

Use formula ( I = ne/t )

Here,

number of electron

electron =1.6 x 10¯¹9 C

We have a relation between charge and current as

Charge = Current×time i.e

Q = i×t.

Now we have current = 10 amp & time = 10sec from given data.

Therefore charge Q = 10×1 = 100 coulombs.

Again we have a relation between charge and no of electrons

I.e no of electrons= total charge / 1.6×10⁻¹⁹

So, no of electrons = ( 100C/1.6×10⁻¹⁸ )

= 6.25×10⁻¹⁸ electrons.

Therefore, 6.25×10⁻¹⁸ electrons will flow through a copper wire carrying 10 amps current for 10 sec

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The air conditioning system in a car can be modeled as a closed system, where the refrigerant circulates in a loop. The refrigerant used in most automobiles is called R-134a.

The refrigerant vapor (gas) is compressed from a low pressure (around 30 psig) to a high pressure, which can vary depending on factors such as the temperature and airflow across the condenser. This compression raises the temperature of the refrigerant vapor. The compressor pulley, which is rotated by mechanical energy from the engine, is used to compress the refrigerant. An electrically operated clutch connects and disconnects the pulley with the compressor shaft, allowing the compressor to be turned on and off as needed.

The high-pressure refrigerant vapor then passes through the condenser. In the condenser, heat is removed from the refrigerant, causing its temperature to drop. This causes the refrigerant to condense into a liquid while still at high pressure. An electrically or mechanically driven condenser fan moves air across the condenser to cool the refrigerant. The condensed liquid refrigerant then passes through an expansion valve, where it undergoes a pressure drop from high pressure (around 225 psig) to low pressure (around -30 psig). As the pressure drops, the temperature of the refrigerant is also reduced (to about 35°F). A temperature probe measures the temperature of the evaporator and provides a signal to control the size of the orifice in the expansion valve, which regulates the flow of refrigerant.

I hope this helps! Let me know if you have any further questions.

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The excludable interest is just $1,000 because Arthur's modified adjusted gross income exceeds the applicable dollar limit by $5,000.

Tax can be defined as the sum that is received by an individual or an organization on its profits or other income, and it is then received by the government.

Interest on education savings bonds is tax-free up to a maximum of $6,000 per bond.

$5,000 is the excess of the modified adjusted gross income.

Arthur should not exceed the phase-out limits in terms of adjusted gross income.

As a result, since Arthur's modified adjusted gross income is $5,000 more than the applicable dollar limit, the excludable interest is $1,000.

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2500 : 3

To solve this, let's build some relationships among the power, voltage, current and number of loops in an ideal transformer.

For an ideal transformer, the powers generated by the primary and secondary coils are the same. In other words, the input power and output power remain the same.

Input power = Output power

Where;

Input power = \(V_{p}\) x \(I_p\)

Output power = \(V_{s}\) x \(I_s\)

=> \(V_{p}\) x \(I_p\) = \(V_{s}\) x \(I_s\)

This can be re-written as:

\(\frac{V_p}{V_s}\) = \(\frac{I_s}{I_p}\)             ------------------(i)

Also, the transformer turns ratio (r) is the quotient of the number of turns/loops in the primary coil and the number of turns/loops in the secondary coil. i.e

r = \(\frac{N_p}{N_s}\)

This ratio is equal to the ratio given in equation (i) i.e

r = \(\frac{N_p}{N_s}\) = \(\frac{V_p}{V_s}\) = \(\frac{I_s}{I_p}\)

=> r = \(\frac{N_p}{N_s}\) = \(\frac{V_p}{V_s}\)

=> \(\frac{N_p}{N_s}\) = \(\frac{V_p}{V_s}\)

This can be re-written as

=> \(\frac{N_s}{N_p}\) = \(\frac{V_s}{V_p}\)       -----------(ii)

From the question,

\(V_{p}\) = 120V

\(V_{s}\) = 100kV = 100000V

Substitute these values into equation (ii) as follows;

\(\frac{N_s}{N_p}\) = \(\frac{100000}{120}\)

\(\frac{N_s}{N_p}\) =  \(\frac{10000}{12}\)

\(\frac{N_s}{N_p}\) =  \(\frac{2500}{3}\)

Therefore, the ratio of the number of loops in the secondary to the number of loops in the primary is 2500 : 3

The flowrate Q is estimated to be 10.83 m³/s, and the uncertainty is 0.64 m³/s (i.e., 5.89%).

To estimate the uncertainty in the flowrate for the measured values: Q = 128μL ΔPπD / 4.

Where ΔP = 12kN/m² ± 0.3kN/m²; D = 0.3m ± 0.01 m,

L = 150m ± 0.1m and μ = 0.001 kg/m-s (the dynamic viscosity of water).

The formula for the uncertainty of flowrate using the given parameters can be calculated as follows:

ΔQ/Q = ΔΔP/ΔP + ΔD/D + ΔL/L Since ΔP = 12kN/m² ± 0.3kN/m²,

The percentage uncertainty in ΔP is given as follows: (0.3kN/m²/12kN/m²) × 100% = 2.5%

Similarly, the percentage uncertainty for D and L can be computed as follows:

ΔD/D = (0.01m/0.3m) × 100% = 3.33%ΔL/L = (0.1m/150m) × 100% = 0.067%

The flowrate Q can be calculated as follows: Q = 128μL ΔPπD / 4Q = 128 x 0.001 x 150 x (12/4) x 3.1416 x (0.3) ⁴ = 10.83 m³/s

The uncertainty in Q can be calculated as follows:

ΔQ/Q = ΔΔP/ΔP + ΔD/D + ΔL/LΔQ/Q = 2.5% + 3.33% + 0.067%ΔQ/Q = 5.89%

Therefore, the flowrate uncertainty is ΔQ = (5.89/100) x 10.83 = 0.64 m³/s.

The volumetric flowrate formula in a horizontal pipe for laminar flow is Q = 128 μL ΔPπD / 4.

The flowrate uncertainty can be calculated using the formula, ΔQ/Q = ΔΔP/ΔP + ΔD/D + ΔL/L.

The values of ΔP, D, and L are ΔP = 12k N/m ² ± 0.3k N/m ², D = 0.3m ± 0.01 m, and L = 150m ± 0.1m,

Therefore, the flowrate Q is estimated to be 10.83 m³/s, and the uncertainty is 0.64 m³/s (i.e., 5.89%).

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Proteins, nucleic acids, carbohydrates, and lipids can all be broken down by a variety of enzymes found in lysosomes, which are organelles contained by a membrane and containing a membrane. Esophagus:

As part of a cellular "tug of war," the chromosomes of the cell align themselves in the centre during metaphase. Sister chromatids are the replicating chromosomes that are still connected at the centromere, which is the center of each chromosome. The pharynx (throat) and stomach are connected by a muscular tube called the esophagus. As food is pushed into the stomach, the esophagus tightens. Chromosome alignment promotes interchromosomal compaction during anaphase, as demonstrated by studies in Cell Biol. . This maintains mitotic integrity. Chromosome alignment creates a metaphase plate during mitosis at the spindle equator. 1

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Answer:

People have come up with all sorts of inventive ways of measuring length. The most intuitive are right at our fingertips. That is, they are based upon the human body: the foot, the hand, the fingers or the length of an arm or a stride.

In ancient Mesopotamia and Egypt, one of the first standard measures of length used was the cubit. In Egypt, the royal cubit, which was used to build the most important structures, was based on the length of the pharaoh’s arm from elbow to the end of the middle finger plus the span of his hand. Because of its great importance, the royal cubit was standardized using rods made from granite. These granite cubits were further subdivided into shorter lengths reminiscent of centimeters and millimeters.

piece of black rock with white Egyptian markings

Fragment of a Cubit Measuring Rod

Credit: Gift of Dr. and Mrs. Thomas H. Foulds, 1925

Later length measurements used by the Romans (who had taken them from the Greeks, who had taken them from the Babylonians and Egyptians) and passed on into Europe generally were based on the length of the human foot or walking and multiples and subdivisions of that. For example, the pace—one left step plus one right step—is approximately a meter or yard. (On the other hand, the yard did not derive from a pace but from, among other things, the length of King Henry I of England’s outstretched arm.) Mille passus in Latin, or 1,000 paces, is where the English word “mile” comes from.

And thus, the meter has and likely will remain so elegantly defined in these terms for the foreseeable future.

Explanation:

is this short enough

Answer:

The bending stress increases linearly away from the neutral axis until the maximum values at the extreme fibers at the top and bottom of the beam. The maximum bending stress is given by: where c is the centroidal distance of the cross section (the distance from the centroid to the extreme fiber).

Explanation:

Hi please mark me as the brainliest and please follow me I you want. Have a great day.

Answer: Problem Statement

Explanation:

When going about designing a new product or an improvement to an existing product, it is important to state the problem in a clear and concise way so that the designers know precisely what they are working towards.

This is where a Problem statement comes in. It states the problem in a concise manner and juxtaposes the current shortcomings of the current system against what the system should ideally be in such a way that even though the solution is clear, it is not so precise that it makes the designers narrow-minded.

When NAND gates are used, a minimal number of gates is used. In the circuit, NAND gates have a faster response than AND, OR gates. Therefore, the NAND version of the expression is better than the AND, OR, NOT version.

Given the Boolean expression is AB + A - B -We need to convert the given Boolean expression into an equivalent expression using only the Boolean operator NAND.(a) Conversion of the given expression AB + A - B - to an expression using NANDThe NAND is represented by a bar above the AND symbol. Using De Morgan's laws, AND and OR gates can be realized using the NAND gate.

NAND(x,y) = x⋅y + NAND(x,x) + NAND(y,y)

Using the above formula, we can convert the expression to its NAND form as follows:

AB + A - B -= NAND(NAND(A, NAND(A, B)), NAND(B, NAND(A, B)))

(b) Circuit realization of the NAND form of the given expression For the NAND form of the given Boolean expression AB + A - B -The circuit diagram realization for the NAND form of the expression is as shown below:

(c) Which is better, the AND, OR, NOT version or the NAND version? Or is there no better of the two? Explain your answer.The implementation of the circuit using the NAND gate is cheaper compared to the implementation using AND, OR, NOT gates.

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The last item in an HTML document must be the closing </html> tag. This tag is used to mark the end of the HTML document and it should always be included in the document to ensure proper rendering in web browsers.

The </html> tag is preceded by the closing </body> tag, which marks the end of the document's body section, and any other closing tags for elements that were opened earlier in the document.

Here's an example of a basic HTML document structure with the opening and closing <html> tags:

<!DOCTYPE html>

<html>

<head>

<title>My HTML Page</title>

<!-- meta tags, stylesheets, and other head content -->

</head>

<body>

<!-- page content, including text, images, and other HTML elements -->

</body>

</html>

Note that the opening <html> tag is at the beginning of the document, and the closing </html> tag is at the very end of the document.

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Both technicians are partially correct.

Tech A is correct that when disconnecting the battery, the negative terminal should be disconnected first. This is a standard safety precaution to prevent any accidental short circuits or sparks that could occur if the positive terminal were disconnected first. By disconnecting the negative terminal first, any accidental contact with metal tools or other conductive materials will not create a circuit.

Tech B is also partially correct that baking soda and water can remove lead oxide from battery terminals. Lead oxide can form on the terminals of a battery over time, reducing its performance and causing problems with starting and charging. Mixing baking soda with water to create a solution can help to neutralize the acidic lead oxide and make it easier to clean off the terminals. However, it's important to follow the appropriate safety precautions when handling batteries, including wearing gloves and eye protection and avoiding contact with any spilled battery acid or electrolyte solution.

In summary, both Tech A and Tech B are correct, but only in part. It's important to follow the appropriate safety guidelines and protocols when working with batteries to prevent injury or damage to the vehicle.

Answer:

  C)  4.65 mA

Explanation:

The series circuit will have a voltage drop of about 0.7 V across the silicon diode, so the voltage drop across the 2 kΩ resistor is 10 -0.7 = 9.3 V. The current through the resistor is given by Ohm's Law:

  I = V/R = 9.3 V/(2 kΩ)

  I = 4.65 mA

The family should accept a minimum of Kshs.42,250,000.00 to avoid incurring a loss.

To obtain the total cost, the expenses for the land, trees and upkeep are summed up and subsequently reduced by 6. 5% using a discount rate.

Hence, it can be seen that a forced acquisition appraisal primarily focuses on three key factors: the land's market value, the expenses involved in replacing the property, and the potential harm caused to the owner's belongings.

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Answer: hello some data related to your question is missing attached below is the missing data

answer:

T2 = 265°C

Explanation:

First step : calculate sum of vertical forces

∑ y = 0

Fmg - 2(0.5 Fst ) = 0

∴Fmg = ( 12 * 10^6 ) ( 2 * π/4 (0.01)^2 )

          = 1884.96 N

Also determine the Compatibility equation in order to determine the change in Temperature

ΔT = 250°C

therefore Temperature at which average normal stress becomes 12.0 MPa

ΔT = T2 - T1

250°C = T2 - 15°C

T2 = 250 + 15 = 265°C

attached below is the detailed solution

At amateur operating frequencies, the FTDX10 is designed for 50 Ohm resistive impedance.

Impedance is the sum of resistance and reactance. It was defined as anything that can obstructs the flow of electrons within the electrical circuit. As a result, it influences current generation in the electrical circuit. It could be found in all the possible circuit components and across all possible electrical circuits. Impedance is represented mathematically by the letter Z and has the unit ohm. It's a mix of resistance and reactance.

Z stands for impedance, which is an expression of the resistance to alternating and/or direct electric current that an electronic component, circuit, or system offers. Resistance and reactance are two independent scalar (one-dimensional) phenomena that make up the vector (two-dimensional) quantity known as impedance.

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