energy is required to move an 843 kg mass from the earth’s surface to an altitude 2.78 times the earth’s radius re. what amount of energy is required to ac- complish this move? the acceleration of grav- ity near the earth is9.8 m/s2 , the

Answer: below

Explanation: Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume

Answer:

Density is defined as the amount of matter contained in unit volume of body

Answer:

Hi

Explanation:

A H20

(a) Moment of the wedge shift is 21168 kg-m. (b) The moment of the centre of buoyancy shift is 36.7 kN-m. (c) The value of the righting moment or upsetting moment is 42.2 kN-m.

a. The moment of the wedge shift in kg-m can be calculated by multiplying the weight of water displaced by the area of the triangle formed by the triangle's centroid and the point at which the triangle intercepts the waterline.

The moment of the wedge shift is given by;

Moment of the wedge shift = weight of water displaced x distance from the centroid of the triangle to point of interception of the waterline

= (0.5 × AB × AC × BC) ρ g d= (0.5 × 4.5 × 2.4 × AB) ρ g d= 5.4 AB ρ g

where AB is the distance between the centerline of the barge and the point of interception of the waterline.ρ is the density of water = 1000 kg/m3.g is the acceleration due to gravity = \(9.81 m/s^2\).

Substituting \(AB = 0.4 m,\rho = 1000 kg/m^3,g = 9.81 m/s^2\) in the above equation:

Moment of the wedge shift = 21168 kg-m.

b. Moment of the centre of buoyancy shift is given by the formula,

Moment of the centre of buoyancy shift = GM x displacement

Where, Gm = the distance between the centre of gravity and the metacentre. Displacement = the weight of water displaced by the barge.

The distance Gm can be calculated using the formula:

Gm = I/V

where I is the second moment of area of the waterplane about its longitudinal axis and V is the volume of displacement.  

The second moment of area:

I = b x d3/12

where b is the breadth of the waterplane and d is the depth of the waterplane below the waterline.

The volume of displacement =\((12 * 4.5 * 2.4) m^3= 129.6 m^3\)

The distance Gm can be calculated as follows:

Gm = I/V= [4.5 × (2.4)3]/12 ÷ [12 × 4.5 × 2.4]= 0.28 m

The displacement of the barge is given by;

Displacement =\(12 * 4.5 * 2.4 * 1000 kg/m^3= 129.6 kN\)

Thus, the moment of the centre of buoyancy shift = GM x displacement

= (0.28 m × 129.6 kN) = 36.7 kN-m

c. Value of the righting moment or upsetting moment can be calculated using the formula;

Upsetting moment = W × GM

where W is the weight of the barge. The weight of the barge can be calculated using the formula:

Weight of barge = Displacement + weight of the wedge

= 129.6 + 21.12= 150.72 kN

The distance between the centre of gravity and the metacentre (Gm) has already been calculated as 0.28 m.

Therefore, the Upsetting moment = W × GM= 150.72 × 0.28= 42.2 kN-m

Therefore, the value of the righting moment or upsetting moment is 42.2 kN-m.

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ANSWER

False.

EXPLANATION

In radioactive decay (or nuclei decay), an unstable nucleus emits radiation into a nucleus that is table and has less energy and a lower mass.

Therefore, nuclei decay from a less stable form to a more stable form.

The answer is false.

The maximum velocity of the object is 0.0272 m/s, and the kinetic energy it has at that point is 3.76 × 10⁻⁶ J.

The maximum velocity of the object and the amount of kinetic energy it has at that point can be found using the given values. Here's the step-by-step solution: Given data: Mass of the object, m = 0.0100 kg Force constant of the spring, k = 1.3 N/m Displacement of the object, d = 3.00 cm = 0.0300 m We know that the maximum velocity of the object can be determined using the following formula: v = ±√(2K/m)where, K = Potential Energy and m = mass of the object. The potential energy of the system can be obtained using Hooke's law.

According to Hooke's law, F = -k x Where, F = restoring force k = force constant x = displacement of the object from the equilibrium position. By using the above formula, we can find the force acting on the object. F = k x'. Force acting on the object, F = 1.3 N/m × 0.0300 m = 0.039 N. The restoring force is acting in the opposite direction of the displacement of the object. So, the force acting on the object is negative, i.e., F = -0.039 N. Now, we can calculate the potential energy of the system. K = (1/2)kx²K = (1/2) × 1.3 N/m × (0.0300 m)²K = 5.85 × 10⁻⁵ J By using the above value of potential energy and mass of the object, we can calculate the maximum velocity of the object. v = ±√(2K/m)v = ±√[(2 × 5.85 × 10⁻⁵ J) / 0.0100 kg]v = ±0.0272 m/s.

The maximum velocity of the object is 0.0272 m/s (rounded off to four significant figures).Now, we can calculate the amount of kinetic energy the object has at that point by using the following formula. Kinetic energy, K = (1/2)mv²where m = 0.0100 kg and v = 0.0272 m/s K = (1/2) × 0.0100 kg × (0.0272 m/s)²K = 3.76 × 10⁻⁶ J. The amount of kinetic energy the object has at its maximum velocity is 3.76 × 10⁻⁶ J (rounded off to three significant figures).So, the maximum velocity of the object is 0.0272 m/s, and the kinetic energy it has at that point is 3.76 × 10⁻⁶ J.

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If a ball is tossed horizontal at a speed of 7.9 m/s, it will travel 4.8 meters (horizontally).

Teenagers, young adults, and others take various stimulant medications collectively referred to as "speed" to feel more focused and alert, as well as occasionally to get high. Additionally, some people take various forms or speed to suppress their appetite.

Relativistic speed is the rate at which relativity effects matter for the desired level of measurement precision of the phenomenon being examined. Relativistic effects are the differences between values calculated using models that take relativity into account and those that do not.

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The component of the airplane's velocity toward or away from the satellite is approximately 39.81 m/s.

When an airplane communicates with a satellite using a frequency of 1.585×10^9 Hz, the signal received by the satellite is shifted higher by 210 Hz. To find the component of the airplane's velocity toward or away from the satellite, we can use the Doppler effect formula:

Δf/f = v/c

Where Δf is the frequency shift (210 Hz), f is the original frequency (1.585×10^9 Hz), v is the component of the airplane's velocity toward or away from the satellite, and c is the speed of light (3.00×10^8 m/s).

Step 1: Plug the values into the formula:

210 Hz / (1.585×10^9 Hz) = v / (3.00×10^8 m/s)

Step 2: Solve for v:

v = (210 Hz / (1.585×10^9 Hz)) * (3.00×10^8 m/s)

Step 3: Calculate the value of v:

v ≈ 39.81 m/s

The component of the airplane's velocity toward or away from the satellite is approximately 39.81 m/s.

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Spherical star clusters that are distributed around the central core of the galaxy are called globular clusters.

Globular clusters.

Globular clusters are compact and spherical collections of stars that orbit around the center of a galaxy. They are typically found in the outer regions of galaxies and are composed of hundreds of thousands of stars that are tightly bound together by gravity.

Therefore, the term for spherical star clusters that are distributed around the central core of the galaxy is globular clusters.

Globular clusters are dense groups of stars that orbit the core of a galaxy, forming a spherical distribution. They contain a large number of stars, often ranging from tens of thousands to millions, held together by gravitational forces. These clusters are primarily composed of older, low-mass stars.

the term you are looking for to describe spherical star clusters distributed around a galaxy's central core is "globular clusters."

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To test the circuit breaker's tripping behavior, you can perform an overload test.

The following are the procedures for testing the circuit breaker:

Inspection:

Examine the circuit breaker for any visual harm or defects.

Ensure that all screws and terminals are secure and free of debris.

Continuity:

Use a multimeter to check the circuit breaker's continuity.

Ensure that there is continuity between the input and output wires of the circuit breaker and that the multimeter's resistance reading is zero when the breaker is closed.

Load:

Examine the circuit breaker's load-carrying capacity.

To do so, use a power source that is within the circuit breaker's current range and attach the circuit breaker to it.

As a result, the power source's current would flow through the circuit breaker.

Observe the tripping behavior:

After the power source has been connected, increase the current gradually to see if the circuit breaker trips at the appropriate value.

To do this, use a variable resistor or a load bank device to regulate the current flowing through the circuit breaker.

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Answer:

Amontons's law. If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas

The explanation of how the natural world works based on experimentation is ;A theory ( D )

A theory is proportionally related to an experiment because a theory is an informed /phenomenon based on facts approved or disproved by an experiment.

Therefore an explanation of how the natural world works should be factual based on experimentation. and not an opinion, while a law in science is developed based on ideal conditions and not natural world conditions.

Hence we can conclude that The explanation of how the natural world works based on experimentation is A theory.

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The volume of the triangular shape is 10.35 km³.

In geometry, volume is the amount of space enclosed by a three-dimensional object. It is measured in cubic units, such as cubic meters or cubic centimeters. The volume of a regular object can be calculated using a formula, while the volume of an irregular object can be calculated by dividing it into smaller regular objects and adding up their volumes.

For example, the volume of a cube with a side length of 1 meter is 1 cubic meter. The volume of a sphere with a radius of 1 meter is 4/3π cubic meters. The volume of a cylinder with a radius of 1 meter and height of 2 meters is 2π cubic meters.

The formula gives the volume of a triangular shape:

V = 1/2 * b * h * t

where:

b is the base of the triangle

h is the height of the triangle

t is the thickness of the triangle

In this case, we have:

b = 7 km

h = 1.9 km

t = 3 km

So now, the volume of the triangular shape is:

V = 1/2 * 7 km * 1.9 km * 3 km = 10.35 km³

Therefore, the volume of the triangular shale is 10.35 km³.

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Answer:

B. 14.4 N

Rotational speed (Angular Velocity) = 2

The Radius of the circle = 1.2 m

Velocity = Angular velocity × radius = 2×1.2 = 2.4 m/s

Centripetal force= mv²/r = 3 × 2.4×2.4/1.2 = 3 × 2.4 × 2

= 14.4 N

Considering the coordinates of the radars as well as the direction of the object in order to determine the object's position in terms of distance and angle. Sincе thе radars arе situatеd at (0,0) and thе sеcond radar is on thе еast sidе of thе first onе, wе can assumе that thе first radar is locatеd on thе x-pivot and thе sеcond radar is locatеd on thе positivе y-hub.

Lеt's say thе objеct is dеtеctеd at coordinatеs (x, y). The objесt's y-coordinativity will be negative and its x-coordinativity positive as it approaches the southern direction in the first quadrant.

We can use the distancе formula to determine the object's diameter from its origin (0, 0):

Distancée = (x + y) 2 The angle can be calculated with trigonometry. The angle can be summarized as:

= arctan(y/x) ii) We must consider the circles of overlap for each radar in order to calculate the overlap from the radar signal intersection in the first quadrant.

Due to the fact that both radars have distinctive overlap and divide the covered area into circles, the overlapped area will be the intersection of these circles.

Thе ovеrlapping arеa can bе calculatеd by finding thе arеa of thе intеrsеction of two circlеs. The formula for the area of the intersection of two circles can be complex and depends on the specific radii and dimensions that exist between the circles' centers.

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When Justine is ice-skating, her final velocity if she accelerates at a rate of 2.0 m/s² for 3. 5 seconds is 7 m/s and it would take Jesse 5.4 seconds to stop the bicycle moving at an initial velocity of 13.5 m/s by accelerating at -2.50 m/s².

To find Justine's final velocity, we can use the equation:

v = u + at

where v is the final velocity, u is the initial velocity (which is assumed to be 0 in this case), a is the acceleration, and t is the time. So

v = 0 + (2.0 m/s²) × (3.5 s) = 7.0 m/s

To find the time it would take for Jesse to bring his bicycle to a stop, we can use the equation:

v = u + at

where v is the final velocity (which is assumed to be 0 m/s in this case as bicycle is brought to a stop), u is the initial velocity, a is the acceleration, and t is the time.

Given that a = -2.5 m/s² (negative sign indicates deceleration) and u = 13.5 m/s.

so t = (v - u) / a = (0 - 13.5 m/s) / -2.5 m/s² = 5.4 seconds

It would take Jesse 5.4 seconds to bring his bicycle to a complete stop.

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To determine the absolute maximum shear stress in a beam with given loads P1 and P2, we need to consider several factors, such as the beam's cross-sectional area and the distribution of the loads. These are not given In this case, so we cant find exact absolute maximum shear stress developed

First, identify the critical points where the maximum shear stress is likely to occur, which are usually at the supports and points of load application. Next, find the internal shear force (V) at each of these critical points. This can be done using equilibrium equations or shear force diagrams.

Once you have the internal shear force values, the absolute maximum shear stress can be calculated using the following formula: τ_max = VQ/Ib

Where τ_max is the maximum shear stress, V is the internal shear force, Q is the first moment of area about the neutral axis, I is the moment of inertia of the beam's cross-section, and b is the width of the beam's cross-section at the location of interest.

Calculate the maximum shear stress at each critical point and compare the values. The highest value among them will be the absolute maximum shear stress developed in the beam.

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Answer:C

Explanation:

Answer:

v = 1.98 mph

Explanation:

Given that,

Speed to travel one mile is 100 mph

Speed to travel another mile is 1 mph

The formula used to find your average speed is given by :

\(v=\dfrac{2v_1v_2}{v_1+v_2}\)

Putting the values, we get :

\(v=\dfrac{2\times 100\times 1}{100+1}\)

v = 1.98 mph

So, yours average speed is 1.98 mph.

Answer:

Explanation:

Waves and Diffraction: Lab ReportTitle:Lab: Waves and DiffractionPurpose:When a wave encounters a small obstacle or the edge of a barrier, the phenomenon known asdiffraction will occur. The wave theory of light can help explain diffraction, although observingdiffraction of light directly is difficult due to the very short wavelengths of light. In this lab, you willuse a “ripple tank” simulation, which provides a convenient way to study wave diffraction on alarger scale, since the principles of wave diffraction apply to physical waves (such as soundwaves and waves in liquid) as well as electromagnetic waveswaves

Answer:

Is a

Explanation:

Answer:

As the plane moves toward the listener, the apparent frequency of the plane would be \(4250\; {\rm Hz}\) (\(2250\; {\rm Hz}\) higher than the frequency at the source.)

As the plane moves away from the listener, the apparent frequency of the plane would be approximately \(1308\; {\rm Hz}\) (approximately \(692\; {\rm Hz}\) lower than the frequency at the source.)

Assumption: the speed of sound in the air is \(340\; {\rm m\cdot s^{-1}}\).

Explanation:

Crests of this sound wave travel toward the listener at a constant \(v = 340\; {\rm m\cdot s^{-1}}\). Since there is a pause of \(t = 1 / f = (1/2000)\; {\rm s}\) between every two consecutive crests of this sound wave, the distance between each pair of consecutive crests would be:

\(\begin{aligned}\lambda &= \frac{v}{f} \\ &= \frac{340\; {\rm m \cdot s^{-1}}}{2000\; {\rm s^{-1}}} \\ &= 0.17\; {\rm m} \end{aligned}\).

Hence, if the aircraft wasn't moving, the first crest would have a head start of \(\lambda = 0.17\; {\rm m}\) relative to the second one. This head start would ensure that the first crest arrive \(t = \lambda / v = 0.17\; {\rm m} / (340\; {\rm m \cdot s^{-1}}) = (1/2000)\; {\rm s}\) earlier than the second crest.  

However, at a speed of \(v_{\text{s}} = 180\; {\rm m\cdot s^{-1}}\), the aircraft would have travelled an additional \(v_\text{s}\, t = 180\; {\rm m\cdot s^{-1}} \times (1/2000)\; {\rm s} = 0.09\; {\rm m}\) within that \(t = (1 / 2000)\; {\rm s}\).

In other words, if the aircraft was moving towards the listener, the period of the sound would appear to the listener to be approximately \(0.000235\; {\rm s}\). in contrast, if the aircraft was moving away from the listener, the period of the sound would appear to the listener as approximately \(0.000765\; {\rm s}\).

Therefore:

Answer: D. thousands to millions of years

Explanation: Stages within a rock's cycle cannot happen quickly. The formation and deterioration can take thousands to millions of years to occur.

I hope this helps!

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The velocity of the rocket, at the instant, the fuel is exhausted is 2103 m/s

Given that,

m = \(m_{0}\) - k t                               ⇒ ( 1 )

m dv / dt = ck - mg                   ⇒ ( 2 )

dv / dt = ( ck / m ) - g

dv = ( ck / ( \(m_{0}\) - k t ) - g ) dt

∫ dv = c ∫( k / ( \(m_{0}\) - k t ) dt - ∫ g dt

v = -c ln ( \(m_{0}\) - k t ) - gt + \(C_{1}\)       ⇒ ( 3 )

\(C_{1}\) = Constant of integration

At t = 0, v = 0 i.e. v ( 0 ) = 0

Substitute v ( 0 ) = 0 in ( 3 )

0 = -c ln ( \(m_{0}\) - 0k ) - 0 g + \(C_{1}\)    

\(C_{1}\) = c ln ( \(m_{0}\) )

Substitute \(C_{1}\) in ( 3 )

v = -c ln ( \(m_{0}\) - k t ) - gt + c ln ( \(m_{0}\) )

v = c ln ( \(m_{0}\) /  \(m_{0}\) - kt ) - gt     ⇒ ( 4 )

After the fuel is fully consumed after 140 s, the mass of rocket is 25% of initial mass.

m ( 140 ) = 0.25 \(m_{0}\)

From ( 1 )

m ( t ) = \(m_{0}\) - k t    

m ( 140 ) = \(m_{0}\) - 140k

0.25 \(m_{0}\) = \(m_{0}\) - 140k

From ( 4 )

v ( 140 ) = 2500 ln ( \(m_{0}\) /  \(m_{0}\) - 140k ) - 9.8 ( 140 )

v ( 140 ) = 2500 ln ( \(m_{0}\) / 0.25 \(m_{0}\) ) - 1372

v ( 140 ) = 2500 ln ( 4 ) - 1372

v ( 140 ) = ( 2500 * 1.39 ) - 1372

v ( 140 ) = 2103 m / s

Velocity at a given instant is the displacement at that given instant.

The given question is incomplete. The complete question is:

A rocket, fired upward from rest at time t=0, has an initial mass of \(m_{0}\)(including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m = \(m_{0}\) - k t. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity v of the rocket will satisfy the equation m  dv / dt  = c k - m g where g is the acceleration due to gravity. Suppose that the fuel accounts for 75% of the initial mass of the rocket and that all of the fuel is consumed in 140 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g=9.8 m/s and c=2500 m/s.]

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a) Using Kepler's third law, the orbital period of planet B located at 1.0 AU from the sun can be calculated. b) Given an orbital period of 4 years for planet C, we can determine its average distance from the sun.

Kepler's third law states that the square of the orbital period (P) of a planet is proportional to the cube of its average distance (a) from the sun. Mathematically, it can be expressed as:

\(\[P^2 = a^3\]\)

Given that planet B is located at an average distance of 1.0 AU from the sun, we can substitute this value into the equation to solve for P:

\(\[P^2 = (1.0 \, \text{AU})^3\]\)

Taking the square root of both sides, we find:

\(\[P = \sqrt{(1.0 \, \text{AU})^3}\]\)

Evaluating the expression, we get:

\(\[P \approx 1.0 \, \text{year}\]\)

Therefore, the orbital period of planet B is approximately 1.0 year.

Similarly, using Kepler's third law, we can solve for the average distance (a) of planet C from the sun. We have the equation:

\(\[P^2 = a^3\]\)

Given an orbital period (P) of 4 years, we can substitute this value into the equation to solve for a:

\(\[(4 \, \text{years})^2 = a^3\]\)

Simplifying, we get:

\(\[16 \, \text{years}^2 = a^3\]\)

Taking the cube root of both sides, we find:

\(\[a = \sqrt[3]{16 \, \text{years}^2}\]\)

Evaluating the expression, we get:

\(\[a \approx 2.52 \, \text{AU}\]\)

Therefore, if planet C has an orbital period of 4 years, its average distance from the sun is approximately 2.52 AU.

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Answer:

5.1 meters

Explanation:

Terra tosses a 0.20kg volleyball up at at a speed of 10 m/s

The height can be calculated as follows

= v^2/2g

= 10^2/2×9.8

= 100/19.6

= 5.1 meters

Hence the height is 5.1 meters

Answer:

Kinetic energy is the energy that an object has because of its motion. The molecules in a substance have a range of kinetic energies because they don't all move at the same speed. As a subtance absorbs heat the particles move faster so the average kinetic energy and therefore the temperature increases.

The valid combinations are:

Total resistance for a circuit in series is R_T = R1 + R2 + R3 + ...

Question 1

To determine the valid combinations of resistors for a circuit with a total resistance of 21, find combinations where the sum of the individual resistances equals 21. Analyze each option:

5, 12, and 4:

Total resistance = 5 + 12 + 4 = 21 (Valid combination)

7, 7, and 7:

Total resistance = 7 + 7 + 7 = 21 (Valid combination)

3, 3, and 3:

Total resistance = 3 + 3 + 3 = 9 (Invalid combination)

5, 5, and 5:

Total resistance = 5 + 5 + 5 = 15 (Invalid combination)

Therefore, the valid combinations are:

5, 12, and 4

7, 7, and 7

Question 2:

Regarding the second question, the equation that calculates the total resistance for a circuit in series is:

R_T = R1 + R2 + R3 + ...

So, the correct option is:

R_T = R1 + R2 + R3 + ...

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