equ1.consider two springs a and b hanging from a pole. spring a extends 9.5 cm when 510 g is hung from it. spring b extends 0.95 mm when 5.1 kg is hung from it. a) determine the spring constant of each spring. b) explain which spring is stiffer.ation for kinetic energy

Answer:

Less strongly attracted.

Explanation:

Potassium and sodium are both alkali metals. That means that they have the ability to be able to gather more valence electrons. They will both gain a positive particle. The potassium electron is less attracted because of the fact that now the sodium has a positive chargem and the electron has a negative charge.

Answer:

B yes when displacement is negative

If the total energy at the top is 5 J, then the total energy at the bottom of the drop would also be 5 J. Since we are ignoring air resistance, we can apply the law of conservation of energy which states that energy cannot be created or destroyed but it can only be transformed from one form to another.

Assuming that the object starts from rest, the total energy at the top of the drop will be equal to the potential energy (PE) since there is no kinetic energy (KE) present in the object when it's at rest. Mathematically, we can represent this as:

Total energy at the top (E) = PE = mgh, Where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s²) and h is the height of the drop.

Now, as the object falls down, potential energy gets converted into kinetic energy. At the bottom of the drop, all the potential energy is converted into kinetic energy since the object has no height left to fall. Mathematically, we can represent this as:

Total energy at the bottom (E) = KE

= 1/2 mv², where v is the velocity of the object at the bottom of the drop. Since we are assuming that air resistance is ignored, we can use the law of conservation of energy to relate the total energy at the top to the total energy at the bottom.

Mathematically, we can represent this as: mgh = 1/2 mv²

Simplifying, we get: v² = 2ghv

= √(2gh)

Substituting the given values, we get: v = √(2 x 9.8 x h)

= √(19.6h)

Now, we can use the formula for KE to calculate the total energy at the bottom: Total energy at the bottom (E) = KE

= 1/2 mv²

= 1/2 m(19.6h)

= 9.8mh

Since h is the height of the drop, we can see that the total energy at the bottom is proportional to the height of the drop.

In other words, if the height of the drop is doubled, the total energy at the bottom will also be doubled. Therefore, if the total energy at the top is 5 J, then the total energy at the bottom of the drop would also be 5 J.

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Greater in size than that of the second star is the first star. If Chaya looks at the information for two stars. They are both the same hue, yet the first star is brighter overall than the second.

A star's absolute magnitude, M, is the magnitude it would have if it were situated 10 parsecs away from Earth. Astronomers might compare the true (intrinsic) brightness of various stars by taking into account stars at a given distance.

More powerful (or greater wattage) stars will glow brighter than less powerful ones (lower wattage). Nevertheless, that because a star appears brighter doesn't always imply it is. The brilliance of a star is also influenced by how close to us it is. An thing seems darker the further it is away.

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The photon's wavelength emitted during the transition from n = 2 to n = 3 is approximately 256 nm. The photon's wavelength emitted during the transition from n = 1 to n = 3 is about 160 nm. The width of the box is approximately 0.622 nm.

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

Let's assume the wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h² / (8× m × L²)) ×(9 - 4)

ΔE = (h²/ (8 × m × L²)) × 5

The energy difference is proportional to the frequency of the emitted photon:

ΔE = h × c / λ

where c is the speed of light.

We can equate the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

Plugging in the given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L² = 0.00047765 m²

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

Following the same steps,

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Simplifying and solving for λ:

λ = (m × L² × c) / h

Plugging in the given values:

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Therefore, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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The wavelength of the photon released during the change from n = 2 to n = 3 is roughly 256 nm. About 160 nm is the wavelength of the photon that is released when n = 1 changes to n = 3. The box has a width of about 0.622 nm.

Given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

The wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h²/ (8 × m × L²)) × 5

The frequency of the photon that was released directly correlates with the energy difference:

ΔE = h × c / λ

,c is the speed of light.

Evaluating the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Solving for λ:

λ = (m × L² × c) / h

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Thus, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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Answer:

See the explanation below.

Explanation:

By means of Hooke's second law, we can calculate the spring constant with the initial conditions of the problem.

\(F=k*x\)

where:

k = spring constant [N/m]

x = distance = 0.01 [m]

F = force or weight [N]

Weight can be calculated by means of the product of mass by gravitational acceleration.

m = mass = 500[g] = 0.5[kg]

\(W=F=m*g\\W = 0.5*9.81\\W= 4.905[N]\)

Now the spring constant can be calculated:

\(k=F/x\\k=4.905/0.01\\k = 490.5[N/m]\)

We must now use the same Hooke's law to determine the new spring force when stretching it 0.03 [m]

\(F_{new}=k*x\\F_{new}=490.5*0.03\\F_{new}=14.715[N]\)

Now we have to use Newton's second law to calculate acceleration. We must remember that Newton's Second Law tells us that the sum of forces is equal to the product of mass by acceleration.

\(F=m*a\)

where:

F = Fnew = 14.715[N]

m = mass = 500 [g] = 0.5 [kg]

a = acceleration [m/s²]

Now replacing:

\(14.715=0.5*a\\a=14.715/0.5\\a=29.43[m/s^{2} ]\)

Answer:

The kinetic energy of an object can be found if the object's mass and velocity are know because kinetic energy is energy possessed by a body due to its motion

Explanation:

Reference points change based on who is observing because they are subjective and depend on the frame of reference of the observer. A frame of reference is the set of coordinates and axes used to describe the position and motion of objects.

Different observers may have different perspectives, locations, or velocities relative to the observed object, leading to different reference points.

For example, consider two people observing a moving car. If one person is standing still on the sidewalk, their reference point would be the stationary position relative to the car. However, if another person is in a moving car alongside the observed car, their reference point would be the moving car itself.

Therefore, each observer's unique frame of reference affects their perception and measurement of position, velocity, and other physical quantities. Recognizing the relativity of reference points is crucial in understanding how different observers may have different interpretations of the same event or object's motion.

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A race car is moving at a constant speed around a track. The race car is changing its velocity as the direction of motion changes.

The primary indicator of an object's position and speed is its velocity. It is the distance that an object travels in one unit of time. The displacement of the item in one unit of time is the definition of velocity.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

As the race car is moving at a constant speed around a track, the magnitude of velocity remains same but during race it may changes its direction of motion, that is why, velocity of it, which depends on both magnitude and direction, may changes.

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Answer:

Energy cannot be created or destroyed

The total amount of energy remains the same even though it may change forms. The amount of energy before and after any energy transformations remain the same because energy cannot be created or destroyed.

Explanation:

The speed the spy satellite must have to maintain this orbit is approximately 3077 m/s.

What is Speed?

Speed is a measure of how fast an object is moving, defined as the distance traveled per unit of time. It is a scalar quantity, meaning it only has a magnitude (i.e., a numerical value) and no direction.

The speed required for an object to maintain a circular orbit around the Earth can be calculated using the formula v = √(GM/r), where G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the object. Plugging in the given values, we get v = √((6.67×\(10^{-11}\) \(Nm^{2}\)/\(kg^{2}\)) × (5.97×\(10^{24\) kg) / (2400 km + 6371 km)) = 3077 m/s.

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Answer:

?

Explanation:

To calculate the tensile strength (T), we need to use the formula:

T = Force/Area

In this case, we are given the peak compressive force as 2084 N. However, we need to convert this to tensile force since we want to calculate the tensile strength. Tensile force is equal in magnitude but opposite in direction to compressive force.

Therefore, T = 2084 N

Next, we need to calculate the cross-sectional area (A) of the material. Given that the diameter of the material is 1 inch, we can calculate the radius (R) as half of the diameter:

R = 1 inch / 2 = 0.5 inch

We need to convert the radius to meters since the SI unit of force is Newton (N) and the SI unit of area is square meters (m^2). Since 1 inch is equal to 0.0254 meters, we can convert the radius as follows:

R = 0.5 inch * 0.0254 meters/inch = 0.0127 meters

Now, we can calculate the cross-sectional area (A) of the material using the formula for the area of a circle:

A = π * R^2

A = 3.1416 * (0.0127 meters)^2

A ≈ 0.0005087 square meters

Finally, we can calculate the tensile strength (T) using the formula:

T = 2084 N / 0.0005087 square meters

T ≈ 4,093,981.8 N/m^2

Therefore, the tensile strength (T) is approximately 4,093,981.8 N/m^2.

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Answer:

You will have to do the last PE - the initial PE

Explanation:

The sound intensity level would increase by 20 decibels if 100 people shout instead of one. Hence option B is correct.

The sound intensity level (SIL) increases by 10*log(N), where N is the number of people shouting. With the help of this equation, we can determine the rise in SIL as follows: N₁ = 1 (one person shouting) and N₂ = 100 (100 people shouting) simultaneously,

ΔSIL = 10log(N₂/N₁)

ΔSIL = 10log(100/1)

ΔSIL = 10*2

ΔSIL = 20 dB

Therefore, the answer is B that says "The sound is 20 decibels higher".

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Answer:

is to meal

Explanation:

plz mark brainlest

Answer:

94 N-m

Explanation:

Joe is standing on the pedal of a bicycle. If his mass of 65 kg, the pedal makes an angle of 55º above the horizontal, and the pedal is 18 cm from the center of the chain ring. The amount of torque Joe exert is 94 N-m.

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is a torque.

Torque is defined as Γ = r×F = r.F.sin(θ). In other words, torque is the cross product of the force vector, where 'θ' is the angle between r and F, and the distance vector (the distance between the pivot point and the place where force is applied).

Given in question mass 65 Kg so force, F = mg = 637 N

Distance r = .18 m and  θ = 55 so sinθ = .82

Torque = rFsin(θ) putting the values, we get

Torque = 94 N-m.

The amount of torque Joe exert is 94 N-m.

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Kieran had a greater average speed than Jevon. Let us go into more detail in the explanation below. To compare the average speeds of Kieran and Jevon, we need to find out the speed of each person.

We can use the formula speed = distance/time. Kieran ran 8 laps in 18 minutes, which means he ran 8/18 = 0.44 laps per minute. To find out Kieran's speed, we need to multiply this by the length of one lap. If we assume that the length of one lap is 400 meters, then Kieran's speed is:0.44 laps per minute × 400 meters per lap = 176 meters per minute Jevon ran 6 laps of the track, but we don't know how long it took him.

Therefore, we can't calculate his speed directly. However, we can still compare his speed to Kieran's by using ratios. If we assume that Jevon ran the same length of track as Kieran, then we can write the following equation: Kieran's speed/Jevon's speed = Jevon's time/Kieran's time.

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The magnitude of the vector with components -14.0 units in the x-direction and 5 units in the y-direction can be calculated using the Pythagorean theorem.

The magnitude of a vector represents its length or size. In the xy plane, the magnitude of a vector with components in the x-direction (horizontal) and y-direction (vertical) can be found using the Pythagorean theorem. The theorem states that the square of the magnitude of a vector is equal to the sum of the squares of its components.

For the given vector with components -14.0 units in the x-direction and 5 units in the y-direction, we can calculate its magnitude as follows:

Magnitude = sqrt(\(14^{2} } +5^{2}\))

Magnitude = sqrt(196 + 25)

Magnitude = sqrt(221)

Magnitude ≈ 14.87 units

Therefore, the magnitude of the vector is approximately 14.87 units. This represents the length or size of the vector in the xy plane, taking into account its components in the x and y directions.

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Answer:

northen henisphere,southern hemisphere, Eastern hemisphere, Western hemisphere.

Answer:

Hydrosphere, Lithosphere, Atmosphere and Biosphere

"If the darts are thrown at the same speed then (B) Projectile that travels along trajectory B was projected earlier and (C) Second dart must be projected at angle, such that 0 + 0,8 = 90° is correct."

Initial speed of dart A = u'

Angle of dart A = θ'

Initial speed of dart B = u''

Angle of dart B = θ''

Both darts start out at the same speed,

Thus, u' = u'' = u

The darts are launched one at a time from the same location A, but not simultaneously. However, they cover the same horizontal distance and arrive at B simultaneously.

Since both darts' horizontal ranges are equal,

= [ u²sin(2θ') / g ] =  [ u²sin(2θ'') / g ]

= sin(2θ') = sin(2θ'')

Although θ' is not equal to θ", we can infer that θ" >θ' from the figure.

Since both are acute angles,

= sinθ'' > sinθ'

Multiplying both sides by 2u/g, we get,

= [ 2u X sinθ'' / g ] > [ 2u X sinθ' / g ]

so that the two darts' respective trajectories are as follows:

= T'' > T'.

Thus, statement B and C are correct options.

The given question is incomplete. The complete question is '(A) Projectile that travels along trajectory A was projected earlier (B) Projectile that travels along trajectory B was projected earlier. (C) Second dart must be projected at angle e, such that 0 + 0,8 = 90° (D) Second dart must be projected at angle , >, STA​.'

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Answer:

A *see picture*

B: 144N

Explanation:

Simply 317 - 173 = 144

So the answer is 144N!

I hope this is right :)

Answer:

T₂ = 305.17 K

Explanation:

Given that,

Heat, Q = 6000 J

Mass, m = 200 gram

Initial temperature, T₁ = 25° C

We need to find its final temperature. Let it is T₂.

We know that,

\(Q=mc\Delta T\)

Where

c is the specific heat of water, c = 4.18 J/g°C

So,

\(6000=200\times 4.18\times (T_2-298)\\\\\dfrac{6000}{200\times 4.18}=(T_2-298)\\\\7.17=(T_2-298)\\\\7.17+298=T_2\\\\T_2=305.17\ K\)

So, the final temperature is equal to 305.17  K.

Answer:

water has a low heat capacity

Explanation:

Ramsar has the highest level of natural radiation in the world.

Hot springs located in the Arkaroola Wilderness Sanctuary in Southern Australia are also credited with higher than normal radiation levels, due to spring water coming in contact with rocks rich in uranium and radon.