EXPLAINING ISSUES How did Rome’s status as a site of encounter change the lives of Roman citizen

Answer:

Anti-Particle

When the lengths of the two sides of a triangle are given, the possible lengths of the third side are given by the Triangle Inequality Theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

If the lengths of two sides of a triangle are a and b, the possible lengths of the third side c are given by the inequality:|a - b| < c < a + bThis inequality states that the length of the third side of the triangle must be greater than the difference between the lengths of the other two sides and less than the sum of their lengths.

To determine the possible lengths of the third side of a triangle, you can use the Triangle Inequality Theorem. The theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the remaining side. Let's call the given side lengths a and b, and the third side length x.
Here are the steps to find the possible lengths of the third side, x:

1. Add the lengths of the two given sides (a and b): a + b
2. Subtract the lengths of the two given sides: |a - b|
3. The possible lengths of the third side, x, should fall between these two values: |a - b| < x < a + b
So, the possible lengths of the third side of the triangle are between the sum and the absolute difference of the given side lengths.

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The speed of the artillery shell when it hits its target is 100 m/s.

Given:

Initial vertical displacement (y) = 200 m

Vertical displacement at 100 m in the air (y') = 100 m

Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)

Using the equation for vertical displacement in projectile motion:

y' = vy^2 / (2g),

where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).

100 m = vy^2 / (2 * 9.8 m/s^2),

vy^2 = 100 m * 2 * 9.8 m/s^2,

vy^2 = 1960 m^2/s^2,

vy = sqrt(1960) m/s,

vy ≈ 44.27 m/s.

Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.

Hence, the speed of the artillery shell when it hits its target is 100 m/s.

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Reference point

Explanation:

I am not sure

The angle that the net force makes with respect to the x- axis, is determined as 55.3⁰.

The angle that the net force makes with respect to the +x axis, is determined as follows;

F = qvBsinθ

Fy =  qv(By)sinθ

Fx =  qv(Bx)sinθ

The angle that the net force makes with respect to the +x axis;

tanθ = Fy/Fx

tanθ = qv(By)sinθ / qv(Bx)sinθ

tanθ = By/Bx

tanθ = 0.065/0.045

tanθ = 1.444

θ = tan⁻¹(1.444)

θ = 55.3⁰

Thus, the angle that the net force makes with respect to the x- axis, is determined as 55.3⁰.

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Answer:

acceleration

Explanation:

speed=v,

In speed vs time graph, slope = dv/dt = acceleration

Answer: Hello! I'm Jungkook. Here is your answer.....

A. conductivity

Explanation:

Hope this helps! Anneyong/Bye!

xoxoKookie

Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

Given the information on the graph, we can confirm that this profile represents the Ocean floor profile.

Therefore, we can confirm that the profile belongs to the ocean floor profile, firstly because of the information provided, as well as it being consistent with the irregularities in the depth of the ocean floor.

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Answer:

b Day-to-day condition of the atmosphere

Explanation:

Weather is short term, Climate is long term

Answer:

Average atmospheric condition.

Explanation:

Answer:

12.5 m/s

Explanation:

225 kilometres to meters = 225000 metres

5 hours to mins = 300 minutes

300 mins to seconds = 18000 seconds

Distance / Time = Speed (A form of the equation)

225000m (the distance) / 18000 (the time) = 12.5 m/s

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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Answer:

capacitive reactance equals inductive reactance

Answer:

the mass of the air in the classroom = 2322 kg

Explanation:

given:

A classroom is about 3 meters high, 20 meters wide and 30 meters long.

If the density of air is 1.29 kg/m3

find:

what is the mass of the air in the classroom?

density = mass / volume

where mass (m) = 1.29 kg/m³

volume = 3m x 20m x 30m = 1800 m³

plugin values into the formula

  1.29 kg/m³   =        mass    

                             1800 m³

mass =  1.29 kg/m³  ( 1800 m³ )

mass = 2322 kg

therefore,

the mass of the air in the classroom = 2322 kg

If A classroom is about 3 meters high, 20 meters wide and 30 meters long. If the density of air is 1.29 kg/m3, then the mass of the air in the classroom is 2322Kg.

Density is the ratio of mass to volume. it tells how much mass a body is having for its unit volume. for example egg yolk has 1027kg/m³ of density, means if we collect numbers of egg yolk and keep it in a container having volume 1 m³ then total amount of mass it is having will be 1027kg. Density is a scalar quantity. when we add egg yolk into the water, egg yolk has greater density than water( 997 kg/m³), because of higher density of egg yolk it contains higher mass in same volume as water. hence due to higher mass higher gravitational force is acting on the egg yolk therefore it goes down on the inside the water. water will float upon the egg yolk. same situation we have seen when we spread oil in the water. ( in that case water has higher density than oil. thats why oil floats on the water).

Given,

Height = 3 m

Width = 20 m

length= 30 m

Density of air = 1.29kg/m³

The  volume of the room = 3×20×30 m³

Volume V = 1800m³

By formula,

Density = Mass/Volume

1.29kg/m³ = Mass/1800m³

Mass of the air = 1.29×1800 = 2322 Kg

The mass of the air is classroom is 2322Kg.

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Answer:

The answer will be it has a mass of 40 kg.

Explanation:

Because Force = mass x acceleration or F = m a, we can say Force divided by mass or F/a = m or mass so 600 divided by 15 equals 40 kg.

The given velocity is 54km/hr, which, when converted to m/s using 1km = 1000m and 1 hour = 3600 seconds, equals 15m/s.

Now substitute the initial speed u = 15m/s values.

v = 0m/s as the final velocity

Time is 6 seconds.

In the a= -3 m/ s2 equation,

s= ut + 1/2at2 s= 15 6+ 1/2(-3)(6)2 s= 90-45 s = 45m

As a result, after using the brakes, the car will halt for up to 45 meters.

The inverse of acceleration is deceleration. The deceleration will be calculated by dividing the final velocity minus the initial velocity by the time required for the velocity drop.

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Answer:

D) 3.0

Explanation:

As we know that

\(The\ specific\ gravity\ of\ fluid = \frac{density\ of\ fluid}{density\ of\ water \ at\ 4\ C} = \frac{\rho_f}{1,000}\)

\(0.6 = \frac{\rho_f}{1000}\)

So,

\(\rho_f = 600\)

Now

T = True weight of object

= mg

\(= 25 \times 9.8\)

= 245 N

W = apparent weight = 200 N

\(\sigma\) = density of object

Now we use the formula

buoyancy force = True weight - W

\(\rho_f V g = 245 - 200\)

600 V (9.8) = 45

V = 0.007653

m = 25 kg

And as we know that

\(\sigma = \frac{m}{V}\)

\(= \frac{25}{0.007653}\)

= 3266.7

Now  

specific gravity is

\(= \frac{\sigma}{water\ density}\)

\(= \frac{3266.7}{1000}\)

= 3.2  

Hence, the correct option is d.

According to the information we can infer that the forces are PULLING forces, OPPOSITE FORCES, EQUAL, forces DO balance each other, the resultant force is ZERO, and there IS NO motion.

According to the information of the image, we can conclude that the forces shown above are PULLING forces because they involve pulling a rope on each side. Also, the forces shown above are OPPOSITE FORCES because they act in opposite directions, pulling the rope towards different sides.

On the other hand, the forces are EQUAL in magnitude because each side exerts a force of 1000 Newtons. Additionally, the forces DO balance each other because they have the same magnitude and act in opposite directions. The individuals on each side are exerting equal forces, resulting in a balanced system.

Finally, the resultant force is ZERO because the forces are equal in magnitude and act in opposite directions. The combined effect of the forces is no net force or resultant force and there IS NO motion because the forces are balanced, resulting in a net force of zero. In a balanced system, the objects will remain at rest or in a state of uniform motion.

Note: This question is incomplete. Here is the complete information:
Attached image

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Explanation:

Wapp=w+ma

Wapp=mg+ma

Wapp=6*10+6*10

Wapp=60+60

Wapp=120N

The ball's gravitational potential energy may be calculated in proportion to the velocity obtained by the ball as it rolls down the ramp.

The following is a model of the ball's GPE;

The height of the ball is related to the square of the velocity attained when rolling down the ramp.h ∝ v²

The gravitational potential energy, GPE, is given as follows;

GPE = m·g·Δh

Where;

m = The mass of the ball

g = The acceleration due to gravity

Δh = The change in elevation of the ball

The gravitational energy of the ball at the ramp's beginning (lowest) point, when h = 0, is 0

When a modest amount of energy is provided to the ball by moving it slowly, it advances up the ramp for a short distance before stopping.

When more energy is provided to the ball, it moves to a higher position on the ramp.

When energy is given to the ball, it is transformed into gravitational potential energy, and the height of the ball reflects the quantity of gravitational potential energy in the ball.

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The answer for the experiment is obtained by the principle of Newton's law of cooling. The initial temperature of the Room is taken as 32°C.

The ice cubes are mixed with room-temperature water, the ice starts to melt and the water becomes cold. This is because the ice and water have two different temperatures and when they are mixed there is an exchange of heat is taken place. When the ice cubes mixed with water the room temperature is decreases from 32°C. After stirring the mixture because of the heat released, the temperature increases.

When the ice-water mixture is stirred, the heat energy is evolved which melts the ice in the mixture, and therefore the temperature increases gradually. And stirring of water for every 5 minutes leads ice cubes to melt completely to form water and the level of water increases in the final stage. This was given by Newton's law of cooling.

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We are given that a car skids 34 meters before stopping with an acceleration of 8.2 meters per second squared. To determine the initial velocity we will use the following equation of motion:

Since the car stops completely the final velocity is zero, therefore, we have:

Now we replace the following values:

The acceleration has a negative sign because the car is decelerating. Replacing the values:

Now we solve the operations on the left side of the equation:

Now we multiply both sides by -1:

Now we take the square root to both sides:

Solving the operations:

Therefore, the initial velocity is 23.6 meters per second.

a) The tension in the rope is 123.9 N.

b) The moment of inertia of the wheel is 0.09 kg m².

c) The angular speed of the wheel 3.50 s after it begins rotating, starting from rest, is 58.5 rad/s.

(a) To determine the tension in the rope, we need to analyze the forces acting on the object. There are two forces: the force of gravity pulling the object down the incline and the tension force pulling the object up the incline.

The force of gravity can be broken down into two components: one parallel to the incline and one perpendicular to the incline.

The parallel component causes the object to accelerate down the incline, while the perpendicular component is balanced by the normal force of the incline.

The tension force is responsible for the object's acceleration down the incline, so we can set up the following equation:

T - mg sin(theta) = ma

where T is the tension force, m is the mass of the object, g is the acceleration due to gravity, theta is the angle of the incline, and a is the acceleration of the object down the incline.

Putting in the given values, we get:

T - (12.5 kg)(9.81 m/s²)(sin(37°)) = (12.5 kg)(2.00 m/s²)

Solving for T, we get:

T = 123.9 N

Therefore, the tension in the rope is 123.9 N.

(b) To determine the moment of inertia of the wheel, we can use the following equation:

I = (1/2)MR²

where I is the moment of inertia, M is the mass of the wheel, and R is the radius of the wheel.

Putting in the given values, we get:

I = (1/2)(12.5 kg)(0.12 m)²

 = 0.09 kg m²

Therefore, the moment of inertia of the wheel is 0.09 kg m².

(c) To determine the angular speed of the wheel after 3.50 s, we can use the following equation:

ω = ω₀ + αt

where ω is the final angular speed, ω₀ is the initial angular speed (which is zero in this case), α is the angular acceleration, and t is the time.

We can find the angular acceleration using the following equation:

α = a/R

where a is the acceleration of the object down the incline (which we already know) and R is the radius of the wheel.

Putting in the given values, we get:

α = 2.00 m/s² / 0.12 m

  = 16.7 rad/s²

Putting in the values for α and t, we get:

ω = 0 + (16.7 rad/s²)(3.50 s)

   = 58.5 rad/s

Therefore, the angular speed of the wheel 3.50 s after it begins rotating, starting from rest, is 58.5 rad/s.

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Explanation:

A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision. An inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision.

A sentence which best characterizes the design of the weigh-in study described in the video is: e) None of the above.

A scientific observation can be defined as an active acquisition of knowledge (information) through one of the sense organs, while using scientific tools and instruments to take measurement of a variable of interest while carrying out an experiment, research or study.

In Science, there are two main types of scientific observation and these include the following:

An experiment can be defined as a scientific investigation which typically involves the process of manipulating an independent variable (the cause), so as to determine or measure the dependent variable (the effect).

The sentences which best characterizes the design of the weigh-in study described in the video are:

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Complete Question:

Which of the following best characterizes the design of the weigh-in study described in the video?

a) Only the control group receives the IV, daily weigh-ins.

b) Both the control and experimental groups receive the IV, daily weigh-ins.

c) At the end of the experiment, the DV will only be collected for the experimental group.

d) Both a and c

e) None of the above

Answer:

The particles bump into each other, moving back and forth but after it passes they remain where they were initially

Explanation:

Some important formulas about sound wave

\(\\ \sf\longmapsto Frequency=\dfrac{1}{Time\: period}\)

\(\\ \sf\longmapsto\lambda=\dfrac{c}{v}\)

As a sound wave travels through a medium, the particles in the medium it travels bump into each other, moving back and forth but after it passes they remain where they were initially.

A sound wave can be defined as a mechanical wave that requires a medium for its propagation and it creates a disturbance in the medium. Also, the energy of a sound wave is transported in a perpendicular direction.

This ultimately implies that, a sound wave creates a disturbance when it travels through a medium.

Consequently, this disturbance causes the particles in the medium it travels through, to bump into each other, moving back and forth but after it passes they remain at the position and state where they were initially.

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For a longitudinal wave, the compression region, is the one represented by the densely packed particles with high pressure and the region with loosely packed particles is called rarefaction. Hence, the first part is C he dense region and the second one with some space between the dots is labeled as R.

Longitudinal waves are a type of mechanical waves passing through a medium. Unlike electromagnetic waves, they cannot be passed through vacuum.

In a longitudinal wave, the oscillation of particles is along the direction of wave propagation. The wave is composed of high pressure regions and low pressure regions called compressions and rarefactions respectively.

The regions where, particles are densely packed and shows the thick dote are labelled as compressions and the regions where, some space between particles are labeled as rarefactions.

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1) The starting temperature of the gas is 288 K

b) When the pressure is doubled, the temperature is 576 K

We know that we have to use the ideal gas equation so as to be able to obtain the temperature of the starting of the gas and we know that;

Pressure = 200 kPa or 1.97 atm

Volume =  3000 cm3  or 3 L

Temperature = ?

Number of moles = mass/molar mass = 7 g/28 g/mol = 0.25 moles

Then we have;

PV = nRT

T = PV/nR

T =  1.97 * 3/0.25 * 0.082

T = 5.91/0.0205

T = 288 K

If the pressure doubles and we have;

P1/T1 = P2/T2

P1T2 = P2T1

T2 = 2(1.97) * 288/1.97

T2 = 576 K

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