El Capitan is a rock formation in Yosemite National Park, located on the north side of Yosemite Valley, near its western end. El Capitan, a sheer granite cliff, is 910 m above the valley floor. The jumper is in free fall for 13.7 seconds.
Extreme-sports enthusiasts have been known to jump off the top of El Capitan, at which point she opens her parachute. How long is the jumper in free fall? We'll ignore air resistance.In free fall, acceleration is constant and equal to the acceleration due to gravity, g = 9.81 m/s2. The jumper's initial speed is 0 because she starts from rest. The final speed, vf, is determined using the following equation:v_f = sqrt(2gh)where g = 9.81 m/s2, and h = 910 m because this is the height of El Capitan above the valley floor. The final speed is:v_f = sqrt(2 * 9.81 * 910) = 134 m/sWe can now use the following equation to determine the time, t, it takes the jumper to fall:v_f = gtSolving this equation for t gives us:t = v_f/g = 134/9.81 = 13.7 seconds.
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A uniformly charged insulating sphere with radius r and charge +Q
lies at the center of a thin-walled hollow cylinder with radius R>r
and length L>2r. The cylinder is non-conducting and carries no net charge.
1:Determine the outward electric flux through the rounded "side" of the cylinder, excluding the circular end caps. (Hint: Choose a cylindrical coordinate system with the axis of the cylinder as its z -axis and the center of the charged sphere as its origin. Note that an area element on the cylinder has magnitude dA=2πRdz
2:Determine the electric flux upward through the circular cap at the top of the cylinder.
3:Determine the electric flux downward through the circular cap at the bottom of the cylinder.
4:Add the results from parts A - C to determine the outward electric flux through the closed cylinder.
5:What result is expected according to Gauss's law?
Note:Express your answers in terms of electric constant ϵ0
and some or all of the variables r, R , L , Q .
According to Gauss' equation, the total flux of an electric field in a confined surface is directly proportional to the charge enclosed.
State Gauss’s law.1)To determine the outward electric flux through the rounded "side" of the cylinder, we can use Gauss's law. We choose a cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The electric field due to the sphere is spherically symmetric, so the electric field lines are parallel to the cylinder's axis and perpendicular to its sides.
E = (1/4πϵ0) (Q/r^2)
where r is the distance from the origin (center of the sphere) to the point on the Gaussian surface.
The area element of the Gaussian surface is dA = 2πRdz, where dz is an element of length along the cylinder's axis. The electric flux through the top and bottom surfaces of the Gaussian surface is then given by:
Φ = ∫E⋅dA = E ∫dA = E(2πR)L
Substituting the expression for the electric field, we have:
Φ = (Q/2ϵ0r^2)(2πRL)
Therefore, the outward electric flux through the rounded "side" of the cylinder is:
Φ = (Q/ϵ0)(R/Lr^2)
2)To determine the electric flux upward through the circular cap at the top of the cylinder, we use a flat Gaussian surface with radius R and height r, centered at the top of the cylinder. The electric field due to the charged sphere is perpendicular to the Gaussian surface, so the electric flux through the top cap is simply the flux through the flat Gaussian surface. The electric field at any point on the Gaussian surface is given by Coulomb's law as:
E = (1/4πϵ0) (Q/R^2)
The area element of the Gaussian surface is dA = πR^2, so the electric flux through the top cap is given by:
Φ = ∫E⋅dA = E ∫dA = EπR^2
Substituting the expression for the electric field, we have:
Φ = (Q/ϵ0)(R/r^2)
3)To determine the electric flux downward through the circular cap at the bottom of the cylinder, we use a similar flat Gaussian surface with radius R and height r, centered at the bottom of the cylinder. The electric flux through the bottom cap is also given by:
Φ = (Q/ϵ0)(R/r^2)
4)Adding the results from parts 1-3, we have the total outward electric flux through the closed cylinder as:
Φ_total = Φ_side + Φ_top + Φ_bottom
= (Q/ϵ0)(R/Lr^2) + 2(Q/ϵ0)(R/r^2)
Simplifying this expression, we have:
Φ_total = (Q/ϵ0) [(2R/r^2) + (R/Lr^2)]
5)According to Gauss's law, the total outward electric flux through a closed surface is proportional to the total charge enclosed within that surface. In this case, the closed surface is the cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The charge enclosed within this surface is simply the charge of the sphere, which is +Q. Therefore, we expect the total outward electric flux through the closed cylinder to be:
Φ_total = Q/
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If one pound of force acts through a distance of two feet, one foot-pound of work is done.
True
False
It is false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.
What is work?Work is a measure of energy expended in moving an object. It is most commonly calculated by multiplying the force by distance.
It is said that no work is done if the object does not move.
According to this question, if one pound of force acts through a distance of two feet, a work of one pound-two feet is done.
It is therefore, false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.
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An object falling from a great height in Earth's atmosphere eventually reaches a speed called Terminal velocity. What cause a falling object to stop increasing in speed once it reaches terminal velocity? Really struggling, I need an answer--quick. Which letter is correct and why please?
A. Its mass and weight have become equal
B. It has no more potential energy
C. No forces are acting on it any longer
D. The forces acting on it are balanced
Answer:
A.
Explanation:
If its at a height the Gratitude of it falling down with only Gravity if Any other Forces are acting on it so as Friction But Sideways.
How much work is done by a person who
pushes a cant with a force of 200 newtons if
the cart moves 20 meters in the direction
of the fonce.
Potassium-40 has a half-life of approximately 1.25 billion years. Approximately how many years will pass before a sample of potassium-40 contains one-eighth the original amount of parent isotope?
Answer:
3.75 billion years
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 1.25 billion years
Number of half-lives (n) = 3
Time (t) =?
The time taken for the sample of potassium-40 to contains one-eighth the original amount of parent isotope can be obtained as:
n = t / t½
3 = t / 1.25
Cross multiply
t = 3 × 1.25
t = 3.75 billion years.
Therefore, it will take 3.75 billion years for the sample of potassium-40 to contains one-eighth the original amount of parent isotope
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In introductory physics, a typical cavendish balance for measuring the gravitational constant G use metal masses 2.39kg and 16g whose center are separated by 6.81cm calculate the gravitation force between these forces, treating each as a point mass located at the center of the sphere.
gravitational constant =6.67259 × 10⁻¹¹N·m²/kg²
Answer:
Explanation:
F = GMm/d²
F = 6.67259 x 10⁻¹¹(2.39)(0.016) / 0.0681²
F = 5.5019685...x 10⁻¹⁰ N
round as appropriate, probably no more than 3 significant figures.
Value of G seems low, but well within the 3 significant figures of the other numerals. I typically see G = 6.674 x 10⁻¹¹
As positively charged sodium ions enter the axon, _______ flow(s) out to repolarize part of the axon
a. potassium ions
b. a neural impulse
c. the action potential
d. glial cells
As positively charged sodium ions enter the axon, potassium ions flow out to repolarize part of the axon.
At the beginning of an action potential of cell membrane, the sodium ion gates open and sodium ions flows into the cell. This process is called depolarization. Due to rapid influx of sodium ion, the channel is eventually closed.
The potassium channels are then activated in a process called repolarization. This process occurs when the potassium channels open and allow potassium ions to flow out of the cell.
To maintain the cell membrane potential, cells are kept at low concentration of sodium ions and high concentration of potassium ions.
Thus, as positively charged sodium ions enter the axon, potassium ions flow out to repolarize part of the axon.
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a stone of mass 500g tied to a rope 50cm long is whirled at an angular velocity of 12rad calculatate the centripetal force?
As per the given data, the centripetal force acting on the stone is 18 N.
What is centripetal force?A force that causes a body to follow a curved path is known as a centripetal force.
The centripetal force always points in a direction that is opposite to the motion of the body and in the general direction of the instantaneous center of curvature of the route.
To calculate the centripetal force acting on the stone, we can use the following formula:
F = (m * \(v^2\)) / r
Where F is the centripetal force, m is the mass of the stone, v is the tangential velocity of the stone, and r is the radius of the circular path.
In this case, we are given the mass of the stone (m = 500g = 0.5kg), the radius of the circular path (r = 50cm = 0.5m), and the angular velocity of the stone (ω = 12 rad/s).
To find the tangential velocity of the stone, we can use the formula:
v = r * ω
Substituting the given values, we get:
v = 0.5m * 12 rad/s = 6 m/s
Now we can substitute the values for m, v, and r in the formula for centripetal force:
F = (m * \(v^2\)) / r = (0.5kg * \((6 m/s)^2\)) / 0.5m = 18 N
Therefore, the centripetal force acting on the stone is 18 N.
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If a block is sitting in a shelf 5 foot high and the same size block is sitting on the shelf above it at 6 feet high. Which has more potential energy? Explain your reasoning.
Answer:
Explanation:
Assuming that not only is the size of the two blocks the same but the MASS is also the same, then the higher block will have more potential energy.
Potential energy is equal to the amount of work required against gravity to position a mass
Work is a force times a distance. PE = W = Fd
As each block has the same mass, they each create the same force which would be their weight mg
PE = W = Fd = mgd
so potential energy is directly proportional to the height of each block
the lower block has potential energy PE = Fd = mg(5)
while the upper block has potential energy PE = mg(6)
above a reference frame origin, possibly the floor.
It is possible that the higher block has less potential energy then the lower block if only the size is considered. If the higher block is a one foot cube of ice at 57.2 lbs and the lower block is a one foot cube of copper at 559 lbs then the lower mass would have much more potential energy because of its much greater mass.
559(5) = 2795 ft•lb of potential energy
57.2(6) = 343.2 ft•lb of potential energy
On cold winter mornings, Ellen's mother will frequently put a space heater in the kitchen. The space heater has coils that use electrical energy to make heat. When the heater is turned on, the coils glow bright orange and heat the room. What types of energy are given off by the space heater?
Answer:
C
Explanation:
It seems right.
answer
Think of it this way. Osmosis occurs when water flows to a different side given its a membrane or not. This is because it flows to a less dense area to reach equilibrium between the two sides. Heat is very similar. It will try to spread to places where there is not as much heat. Keeping the laws of heat travels up, the heat from the coils will reach the ends. We call this "Thermal Equilibrium"
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Like magnetic fields, electric fields are invisible. How did the experiment allow you to gather evidence that electric fields exist?
Answer: while electric fields aren’t visible or tangible, they are mensurable.
Explanation: you might want to attach the experiment notes to your question***
Answer: 13 miles.
Explanation:
Inquiry is a process promoted by a Blank
Inquiry is a process prompted by curiosity, observation or question.
Explanation:Inquiry is driven by curiosity, wonder, interest and/or a need to answer a question. Being able to ask rich questions enables students to construct their knowledge and develop an understanding of concepts and experiences.
Find the magnitude and direction of the force on the particle a charged particle is moving in the xy horizontally plane it enters the region of space with a magetic field of magnitude oriented so that it makes an angle with respect to the:_____.
Answer:
The particle enters the region of space with a magetic field of magnitude oriented so that it makes an angle with respect to the direction of the uniform magnetic field.
Explanation:
Six identical cells with an EDS of 3 V connected in a battery. Resistors R₁ and R₂=16Ω are connected to the battery, the total resistance of the external circuit is R=6Ω and the current flowing in it is 1 A. Determine the resistance of the first resistor and the EDS and internal resistance of the battery.
- The resistance of the first resistor (R₁) is 12 Ω.
- The electromotive force (EMF) of the battery is 18 V.
- The internal resistance of the battery is 12 Ω.
To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.
Let's start by calculating the resistance of the first resistor (R₁):
1. Apply Ohm's law to find the voltage drop across the external circuit:
V = I * R
V = 1 A * 6 Ω
V = 6 V
2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:
V = E - Ir
6 V = E - (1 A * r) (where r is the internal resistance of the battery)
3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:
E = 6 cells * 3 V/cell
E = 18 V
4. Substitute the value of E in the equation from step 2:
6 V = 18 V - r
r = 12 Ω
Therefore, the resistance of the first resistor (R₁) is 12 Ω.
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Name:.
Date:
Homework: Writing an Argument About
Australia's Skin Cancer Rate
G
4
You now have enough evidence to explain why Australia's skin cancer rate is so high. Review your
argument from Chapter 2 and think about how you will convince the AHA that both Claim 2 and
Claim 3 are accurate. You will use your completed Reasoning Tool from Activity 3 to revise and add to
your argument.
Question: Why is the skin cancer rate in Australia so high?
A 20 g ball of clay traveling east at 2.5 m/s collides with a 25 g ball of clay traveling north at 2.0 m/s .
What is the speed of the resulting 45 g ball of clay?
What is the direction of the resulting ball of clay?
The final velocity of the two balls after collision is 1.7 m/s and the direction is 45⁰.
The given parameters;
mass of the first clay ball, m₁ = 20 g = 0.02 kg
initial velocity of the first clay ball, u₁ = 3 m/s
mass of the second clay ball, m₂ = 30 g = 0.03 kg
initial velocity of the second ball, u₂ = 2 m/s
The initial momentum of the fist ball is calculated as follows;
P₁ = m₁u₁
P₁ = (0.02)(3)
P₁ = 0.06 kg.m/s
The initial momentum of the second ball is calculated as follows
P₂ = m₂u₂
P₂ = (0.03)(2)
P₂ = 0.06 kg.m/s
The resultant initial momentum of the two balls is calculated as follows;
Apply the principle of conservation of momentum, to determine the final velocity of the two balls;
The direction of the two ball's velocity is calculated as follows;
Thus, the final velocity of the two balls after collision is 1.7 m/s and the direction is 45⁰To know more about speed direction visit:
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Velocity questions
1. Q: A car moved 80 km to the South. What is its displacement?
A: 20 km South
B: 50 km East
C: 80 km South
D: 160 km North
Two students run a race. Student A is 50 kg and runs at 5 m/s. Student B is 30 kg and runs at 2 m/s. Which
student has more Kinetic energy?
Answer:
Explanation:
KEA = ½(50)5² = 625 J
KEB = ½(30)2² = 60 J
Student A has more kinetic energy.
More than ten times more kinetic energy due to both larger mass and higher velocity.
Consider the chemical equation below:
S₂O²+1 13 + SO₂
a)The reaction is carried out in a basic solution. Express a balanced redox equation using the ion-electron method.
Answer:
emmm
I really think that the answer to the whole thing will be
S2 +O4+113
In a plane, add a 120 N force at 300 and a -100 N force at 900 using the parallelogram method. [111N 339]
See the attached figure.
The black arrows represent the two given vectors. The dashed black arrows are these same vectors, but translated so that the end of one vector is aligned with the start of another.
The red vector is their sum.
In case you also need to find the magnitude and direction of the sum, we have
A = (120 N) (cos(30°) i + sin(30°) j) = (60√3 i + 60 j) N
B = (-100 N) (cos(90°) i + sin(90°) j) = (-100 j) N
⇒ A + B = (60√3 i - 40 j) N
⇒ ||A + B|| = √((60√3)² + (-40)²) N = 20√31 N
and its direction relative to the positive horizontal axis (rightward) is θ such that
tan(θ) = (-40) / (60√3) = -2/(3√3)
⇒ θ = arctan(-2/(3√3)) ≈ -21.05°
Answer the following question according to formal grammatical rules.
Which of the following sentences corrects the pronoun errors in this sentence?
If a person wants to help their community, they should research opportunities.
A. If a person wants to help their community, you should research opportunities.
B. If you want to help your community, a person should research opportunities.
C. If people want to help their community, they should research opportunities.
D. If a person wants to help it, they should research opportunities.
If people want to help their community, they should research opportunities corrects the pronoun errors in this sentence.
What is a Pronoun?This is defined as a word which is used instead of a noun and examples include he, she etc.
In this scenario, the word 'people' agrees with the possessive adjective 'their' and the personal pronoun 'they', which is referred to the third-person plural hence the reason why option C is the most appropriate choice.
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Answer:
D
Explanation:
D
A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.
a. How much work does he do on the wall? ____________
b. How much energy is used?__________
c. How much power is exerted?____________
Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.
What is force?In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.
Here,
a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.
b. Since no work is done, no energy is used or transferred.
c. The power exerted by the man can be calculated using the formula:
Power = Work / Time
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Which of the following demonstrates proper maintenance of a sterile field?
A. Trevor is cold during a surgical procedure and covers his hands
with his cuffs.
B. Sally remains in the operating room at all times and avoids leaning
on tables.
C. Maureen leaves her hands at her side because she knows that
anything below the waist on her scrubs is sterile.
D. Fred drops a scalpel and continues to use it since it was still in the
exam area and therefore is sterile.
SUBMIT
Answer: B. Sally remains in the operating room at all times and avoids leaning
on tables.
Explanation: took the quiz.
The statement that demonstrates proper maintenance of a Sterile field is Sally remains in the operating room at all times and avoids leaning on tables.
What is a Sterile field?Sterile field refer to a section area that is set apart in order to place sterile surgical drapes on the patient's surgical site and also on the stand that will hold in place the sterile instruments and other items needed during surgery.
The purpose of the sterile field is to minimize the population of microbes.
Therefore, The statement that demonstrates proper maintenance of a Sterile field is Sally remains in the operating room at all times and avoids leaning on tables.
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A box is sliding along a frictionless surface and gets to a ramp. Disregarding friction, how fast should the box be going on the ground in order to slide up the ramp to a height of 2.5 meters, where it stops? (Use g = 9.8 m/s2.)
Answer:
7.0 m/s
Explanation: I just did it
1.A. Calculate the Normal Force on person A, of mass 84 kg while balancing person B, of mass 50 kg, on his head.B. What would the normal force be if someone handed person B a helium balloon capable of generating a lift force of 300 N?
Given data:
* The mass of person A is,
\(m_A=84\text{ kg}\)* The mass of person B is,
\(m_B=50\text{ kg}\)Solution:
The diagrammatic representation of the given case is,
The weight of person A is,
\(\begin{gathered} w_A=m_Ag_{} \\ w_A=84\times9.8 \\ w_A=823.2\text{ N} \end{gathered}\)The weight of person B is,
\(\begin{gathered} w_B=m_Bg \\ w_B=50\times9.8 \\ w_B=490N_{} \end{gathered}\)The normal force in the upward direction acting on person A due to the ground is equal to the weight of the person.
Thus, the net normal force acting on person A is,
\(\begin{gathered} F_{\text{net}}=N-w_A-w_B \\ F_{\text{net}}=823.2-823.2-490 \\ F_{\text{net}}=-490\text{ N} \end{gathered}\)Here, the negative sign indicates the direction of the net force is vertically downward.
Thus, the magnitude of normal force on person A is 490 N.
(B). If person B carries a helium balloon with an upward lift of 300 N, then the weight of person B is decreased to,
\(\begin{gathered} w_B=490-300 \\ w_B=190\text{ N} \end{gathered}\)Thus, the magnitude of normal force on person A is,
\(\begin{gathered} F_{\text{net}}=w_B \\ F_{\text{net}}=190\text{ N} \end{gathered}\)Hence, the normal force on person A, in this case, is 190 N.
If a car traveled 8 miles for 15 minutes, 3 miles for 11 minutes, and 2 miles for 4 minutes, what its average speed?
The average speed of the car is calculated as 0.43miles/min.
HOW TO CALCULATE AVERAGE SPEED:
The average speed of the car can be calculated by dividing the distance covered by the time taken. That is;Average speed (miles/mins) = distance covered (miles) ÷ time (mins)However, the total distance covered is summed as follows:8 miles + 3 miles + 2 miles = 13 milesThe total time taken is calculated as follows:15 mins + 11 mins + 4 mins = 30 minsAverage speed = 13 ÷ 30Average speed = 0.43miles/min.Therefore, the average speed of the car is calculated as 0.43miles/min.Learn more at: https://brainly.com/question/12322912?referrer=searchResults
What is the source of power in
this circuit?
A.A
B.B
С.С
Answer:
C and B
Explanation:
they both have vaults of energy
An astronaut is being tested in a centrifuge. The centrifuge has a radius of 11.0 m and, in starting, rotates according to θ = 0.260t2, where t is in seconds and θ is in radians. When t = 2.40 s, what are the magnitudes of the astronaut's (a) angular velocity, (b) linear velocity, (c) tangential acceleration, and (d) radial acceleration?
Answer:
a) 1.248 rad/s
b) 13.728 m/s
c) 0.52 rad/s^2
d) 17.132m/s^2
Explanation:
You have that the angles described by a astronaut is given by:
\(\theta=0.260t^2\)
(a) To find the angular velocity of the astronaut you use the derivative og the angle respect to time:
\(\omega=\frac{d\theta}{dt}=\frac{d}{dt}[0.260t^2]=0.52t\)
Then, you evaluate for t=2.40 s:
\(\omega=0.52(2.40)=1.248\frac{rad}{s}\)
(b) The linear velocity is calculated by using the following formula:
\(v=\omega r\)
r: radius if the trajectory of the astronaut = 11.0m
You replace r and w and obtain:
\(v=(1.248\frac{rad}{s})(11.0m)=13.728\frac{m}{s}\)
(c) The tangential acceleration is:
\(a_T=\alpha r\\\\\alpha=\frac{\omega^2}{2\theta}=\frac{(1.248rad/s)^2}{2(0.260(2.40s)^2)}=0.52\frac{rad}{s^2}\)
(d) The radial acceleration is:
\(a_r=\frac{v^2}{r}=\frac{(13.728m/s)^2}{11.0m}=17.132\frac{m}{s^2}\)
Calculate Time
d
12. A vehicle drives a distance of 26000 m at a speed of 65m/s, calculate the time taken for
this journey.
13. A train travels at a speed of 16 m/s and travel a distance of 3200 m, calculate the time it
takes the train to complete this journey.
urs 14. Calculate the time it takes to travel a distance of 672 km at a speed of 96 km/h.
15. A beetle travels at a speed of 0.09 m/s, it travels a distance of 1.08 m before it is caught
in a jar. Calculate the time taken for the beetle to run.
16. Carlisle is a distance of 35 miles away from Lockerbie. If I travelled at a constant speed
5147
deudate the time takon for this journey
12. The time taken for the journey is 400 s
13. The time taken for the train is 200 s
14. The time taken is 7 h
15. The time taken for the beetle is 12 s
16. The time taken for the journey is 0.0068 h
How do i determine the time taken?The time taken in each case as given by the question can be obtain as follow:
12. The time taken for the journey
Distance traveled = 26000 mSpeed = 65 m/s Time taken =?Time taken = Distance / Speed
Time taken = 26000 / 65
Time taken = 400 s
13. The time taken for the train
Distance traveled = 3200 mSpeed = 16 m/s Time taken =?Time taken = Distance / Speed
Time taken = 3200 / 16
Time taken = 200 s
14. The time taken to travel
Distance traveled = 672 kmSpeed = 96 Km/h Time taken =?Time taken = Distance / Speed
Time taken = 672 / 96
Time taken = 7 h
15. The time taken for the beetle
Distance traveled = 1.08 mSpeed = 0.09 m/s Time taken =?Time taken = Distance / Speed
Time taken = 1.08 / 0.09
Time taken = 12 s
16. The time taken for the journey
Distance traveled = 35 milesSpeed = 5147 mile per hourTime taken =?Time taken = Distance / Speed
Time taken = 35 / 5147
Time taken = 0.0068 h
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The water evaporated. How did that help ?
Answer:
hellooooo. hi hellooooo and programming laptops
Answer:
The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor. Evaporation is a very important part of the water cycle. The Heat from the sun, or solar energy, powers the evaporation process. ... Once the water evaporates, it also helps form clouds.
Explanation: