f (x)=6xº + 2x² +
+ x
O The function is an even function.
O The function is an odd function.
O The function is neither even nor odd.

Answer:

im in middle school and im trying to figure this out as well

Step-by-step explanation:

sorry if i get it i will tell you

a. The amount to which $500 will grow when compounded annually at a rate of 16% for 10 years is approximately $1,734.41.

b. The amount to which $500 will grow when compounded semiannually at a rate of 16% for 10 years is approximately $1,786.76.

c. The amount to which $500 will grow when compounded quarterly at a rate of 16% for 10 years is approximately $1,815.51.

d. The amount to which $500 will grow when compounded monthly at a rate of 16% for 10 years is approximately $1,833.89.

e. The amount to which $500 will grow when compounded daily at a rate of 16% for 10 years (365 days in a year) is approximately $1,843.96.

a. The amount to which $500 will grow when compounded annually at a rate of 16% for 10 years is approximately $1,734.41.

To calculate this, we can use the compound interest formula:

A = P(1 + r/n)^(nt)

Where:

A = the final amount

P = the principal amount (initial investment)

r = the annual interest rate (as a decimal)

n = the number of times the interest is compounded per year

t = the number of years

In this case, P = $500, r = 0.16, n = 1, and t = 10.

Plugging these values into the formula, we get:

A = 500(1 + 0.16/1)^(1*10)

 = 500(1 + 0.16)^10

 ≈ 1,734.41

Therefore, $500 will grow to approximately $1,734.41 when compounded annually at a rate of 16% for 10 years.

b. The amount to which $500 will grow when compounded semiannually at a rate of 16% for 10 years is approximately $1,786.76.

To calculate this, we can use the same compound interest formula, but with a different value for n. In this case, n = 2 because the interest is compounded twice a year.

A = 500(1 + 0.16/2)^(2*10)

 ≈ 1,786.76

Therefore, $500 will grow to approximately $1,786.76 when compounded semiannually at a rate of 16% for 10 years.

c. The amount to which $500 will grow when compounded quarterly at a rate of 16% for 10 years is approximately $1,815.51.

Using the compound interest formula with n = 4 (compounded quarterly):

A = 500(1 + 0.16/4)^(4*10)

 ≈ 1,815.51

Therefore, $500 will grow to approximately $1,815.51 when compounded quarterly at a rate of 16% for 10 years.

d. The amount to which $500 will grow when compounded monthly at a rate of 16% for 10 years is approximately $1,833.89.

Using the compound interest formula with n = 12 (compounded monthly):

A = 500(1 + 0.16/12)^(12*10)

 ≈ 1,833.89

Therefore, $500 will grow to approximately $1,833.89 when compounded monthly at a rate of 16% for 10 years.

e. The amount to which $500 will grow when compounded daily at a rate of 16% for 10 years (365 days in a year) is approximately $1,843.96.

Using the compound interest formula with n = 365 (compounded daily):

A = 500(1 + 0.16/365)^(365*10)

 ≈ 1,843.96

Therefore, $500 will grow to approximately $1,843.96 when compounded daily at a rate of 16% for 10 years.

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, assuming that there is a complete dataset somewhere, we can use a   hypothesis    test to determine if there is a significant difference in treatment means for the fuel economy of the company fleet vehicles.

The null hypothesis would be that there is no significant difference in treatment means, while the alternative hypothesis would be that there is a significant difference. We can use a one-way ANOVA test to compare the means of multiple treatment groups.

To perform this test, we would need to calculate the sample means and standard deviations for each treatment group and then calculate the F statistic. We would then compare the calculated F value to the critical value of F with degrees of freedom equal to the number of treatment groups minus 1 and the total sample size minus the number of treatment groups.

If the calculated F value is greater than the critical value, we would reject the null hypothesis and conclude that there is a significant difference in treatment means. If the calculated F value is less than or equal to the critical value, we would fail to reject the null hypothesis and conclude that there is no significant difference.

Without more information about the data, it is not possible to say whether or not the sample provides sufficient evidence to conclude that there is a significant difference in treatment means.

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Answer:

664 Dollars

Step-by-step explanation:

800 x .83 - 664. Tell me if i'm wrong.

Answer:

6b

Step-by-step explanation:

6 + b = 6b

Answer:

c= 3a+2b

Step-by-step explanation:

because the equation don't change, if they have different variables

Answer:

\(f'(x) = 3-2\cdot x\)

Step-by-step explanation:

Let be \(f(x) = -x^{2}+3\cdot x\), such that:

\(f'(x) = \frac{f(x+h)-f(x)}{h}\)

Hence,

\(f(x+h) = -(x+h)^{2}+3\cdot (x+h)\)

\(f(x+h) = -(x^{2}+2\cdot x\cdot h + h^{2})+3\cdot x + 3\cdot h\)

\(f(x+h) = -x^{2}+(3-2\cdot x) \cdot h - h^{2}+3\cdot x\)

\(f(x) = -x^{2}+3\cdot x\)

Then,

\(f'(x) = \frac{-x^{2}+(3-2\cdot x)\cdot h-h^{2}+3\cdot x+x^{2}-3\cdot x}{h}\)

\(f'(x) = \frac{(3-2\cdot x)\cdot h-h^{2}}{h}\)

\(f'(x) = 3-2\cdot x -h\)

If \(h \longrightarrow 0\), then:

\(f'(x) = 3-2\cdot x\)

Answer:

$13,100

Step-by-step explanation:

Let x be the amount Bradford invested in the stock mutual fund.

The rest of the money, which is (25,000 - x), was invested in the bond mutual fund.

Bradford earned 9% on the money he invested in the stock mutual fund, which is 0.09x.

Bradford earned 6% on the money he invested in the bond mutual fund, which is 0.06(25,000 - x).

The total earnings were $1,893:

0.09x + 0.06(25,000 - x) = 1,893

Simplifying the equation:

0.09x + 1,500 - 0.06x = 1,893

0.03x = 393

x = 13,100

Therefore, Bradford invested $13,100 in the stock mutual fund.

Answer:

19 times t = how many toy cars Gordon has.

                             OR

19t= how many toy cars Gordon has

Answer: The distance between Bob's home and his school is 2.5 miles.

Step-by-step explanation:

What is speed?

Speed is the distance covered in unit time.

Speed of Bob = 3mph

Speed of his sister = 12mph

Distance between Bob's home and his school = distance covered by bob in 10 minutes + distance covered by his sister in 10 minutes.

Distance covered by Bob in 10 minutes = 3*10/60 = 0.5 mile.

Distance covered by His sister in 10 minutes = 12*10/60 = 2 miles.

So, the distance between Bob's home and his school =0.5+2 = 2.5miles.

Therefore, the distance between Bob's home and his school is 2.5 miles.

Answer:

For the first 3 questions, fill out exactly what you see in the picture. So, the first answer is \(9\sqrt{2}\), the second one is x, and the third one is y. Now, since we know this is a 45 - 45 - 90 triangle, we can figure out all of the other sides. AB is the same as AC, so your answer for the fourth one question will be \(9\sqrt{2}\). The hypotenuse in a 45 - 45 - 90 triangle is a side times \(\sqrt{2}\), so your last answer will be \((9\sqrt{2})(\sqrt{2}) = 18\).

Answer:

x < -16

Step-by-step explanation:

Any number less than -16 will work. So x could equal -12309 or -109 or -50 and even -19234870237503 would work.

To find which inequalities of x work, simply subtract 19 on both sides.

Answer:

x < -16

Step-by-step explanation:

x + 19 < 3

Subtract 19 on both parts.

x < 3 - 19

x < -16

the expression equivalent to 2x + 8 is (x+4) + (x+4)

using the commutative property we can say that

2x +8 = x + x + 8

also 2x + 8 = x + 4 + x + 4

hence 2x + 8 = (x+4) + (x+4)

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The z score associated with the highest 10% is closest to: option (c) 1.28

-To find the z score associated with the highest 10%, first determine the percentage that corresponds to the lower 90%, since the z score table typically represents the area to the left of the z score.

- Look up the 0.90 (90%) in a standard normal distribution  (z score) table, which will give you the corresponding z score.

-The z score closest to 0.90 in the table is 1.28, which corresponds to the highest 10% of values.

Therefore, the z score associated with the highest 10% is closest to 1.28.

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Answer:

d=11

Step-by-step explanation:

-4--15=11

7--4=11 and so on

Answer:

2x+15 = Two times some value of fifteen

Answer:

5/12 hour or 25 minutes

Step-by-step explanation:

The formula is

distance = rate * time

changing minutes to hours (50 * 1 /60 ) = 5/6 hours

distance = 20 mph * 5/6 hours

distance = 50/3 miles

We need to go the same distance at 40 mph

50/3 = 40 mph * time

Multiply each side by 1/40

50 /3 * 1/40 = 40 * 1/40 *t

50/3 *1/40 =t

5/12  of an hour

Changing back to minutes

5/12 * 60 =25

Answer:

47%

Step-by-step explanation:

.375 × .125 = .046875

rounding up, 5 keeps the 7 as is, 7 is greater than 5, therefore the 8, becomes a 9, 9 is greater than 5, so the 6 becomes a 7, .047.

move the decimal three digits to the left and you get, 47%.

Hope this helps brainlest? please

since the population standard deviations (σ1 and σ2) are not provided, we cannot calculate the exact test statistic Z.

To test the null hypothesis H0: (μ1 - μ2) = 0 versus the alternative hypothesis Ha: (μ1 - μ2) ≠ 0, we can use a two-sample z-test. The test statistic is calculated as:

Z = (x bar1 - x bar2) / sqrt((σ1^2 / n1) + (σ2^2 / n2))

Where:
X bar1 and x bar2 are the sample means of the two groups,
σ1 and σ2 are the population standard deviations of the two groups,
n1 and n2 are the sample sizes of the two groups.

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Answer:

60f + 2

If there is an answer choice like that

Answer: 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.

Step-by-step explanation:

Let X be a random variable that represents the speed of the drivers.

Given: population mean : M = 72 miles ,

Standard deviation: s= 3.2 miles

The probability that the drivers are traveling between 70 and 80 miles per hour based on this distribution:

\(P(70\leq X\leq 80)=P(\frac{70-72}{3.2}\leq \frac{X-M}{s}\leq\frac{80-72}{3.2})\\\\= P(-0.625\leq Z\leq 2.5)\ \ \ \ \ [Z=\frac{X-M}{s}]\\\\=P(Z\leq2.5)-P(Z\leq -0.625)\\\\\\ =0.9938-0.2660\ \ \ [\text{Using p-value calculator}]\\\\=0.7278\)

Hence, 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.

Answer:

The answer is -285

Step-by-step explanation:

The MP curve initially rises to its maximum value because of the specialized nature of the fixed capital, where each additional worker's productivity rises due to the marginal product of the fixed capital.

Production Function: q = f(L,K) = 20L + 25K + 5KL - 0.03L² - 0.02K²

Given, K = 5, i.e., capital is fixed. Therefore, the total product of labor, average product of labor, and marginal product of labor are:

TPL = f(L, K = 5) = 20L + 25 × 5 + 5L × 5 - 0.03L² - 0.02(5)²

= 20L + 125 + 25L - 0.03L² - 5

= -0.03L² + 45L + 120

APL = TPL / L, or APL = 20 + 125/L + 5K - 0.03L - 0.02K² / L

= 20 + 25 + 5 × 5 - 0.03L - 0.02(5)² / L

= 50 - 0.03L - 0.5 / L

= 49.5 - 0.03L / L

MP = ∂TPL / ∂L

= 20 + 25 - 0.06L - 0.02K²

= 45 - 0.06L

The following diagram illustrates the TP, MP, and AP curves:

Figure: Total Product (TP), Marginal Product (MP), and Average Product (AP) curves

The production function demonstrates increasing marginal returns due to specialization when L is low enough, i.e., when L ≤ 750. The marginal product curve initially increases and reaches a maximum value of 45 units of output when L = 416.67 units. When L > 416.67, MP decreases, and when L = 750 units, MP becomes zero.

The MP curve's initial increase demonstrates that the production function displays increasing marginal returns due to specialization when L is low enough. This is because when the capital is fixed, an additional unit of labor will benefit from the fixed capital and will increase production more than the previous one.

In other words, Because of the specialised nature of the fixed capital, the MP curve first climbs to its maximum value, where each additional worker's productivity rises due to the marginal product of the fixed capital.

The APL curve initially rises due to the MP curve's increase and then decreases when MP falls because of the diminishing marginal returns.

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Answer:

Step-by-step explanation:

2(√x+2/2 - 1)² + 4 (√x+2/2 - 1)

2((√x+2/2)² + 1² - 2(√x+2/2)(1)) + 4√x+2/2 - 4

2(x+2/2 + 1 - 2(√x+2/2)) + 4√x+2/2 - 4

x + 2 + 2 - 4√x+2/2 + 4√x+2/2 - 4

x + 4 - 4

x

Answer:

the answer is x

Step-by-step explanation:

The total cost of the purchases is $144. 8. So, the cost of the case of air fresheners is $33.97.

Let's start by calculating the total cost of the buckets, brushes, and towels.

The cost of 5 buckets is

5 buckets x $2.89/bucket = $14.45

The cost of 10 brushes is

10 brushes x $7.91/brush = $79.10

The cost of 48 towels is

48 towels x $0.36/towel = $17.28

So the total cost of the buckets, brushes, and towels is

$14.45 + $79.10 + $17.28 = $110.83

We know that the total cost of all the purchases, including the case of air fresheners, is $144.8. Therefore, we can calculate the cost of the case of air fresheners by subtracting the total cost of the buckets, brushes, and towels from the total cost of all the purchases

$144.8 - $110.83 = $33.97

So $33.97 is the cost of the case of air fresheners.

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Answer: do PEMDAS and the answer should be 17 I’m not 100%

Step-by-step explanation:

The game was originally priced at £48, but after a \(\frac{1}{3}\) decrease in price, it was reduced to £32.

To solve this problem, we need to work backwards from the reduced price of £32 to determine the original price of the game before the decrease.
If the game was reduced in price by \(\frac{1}{3}\), then this means that the new price is \(\frac{2}{3}\) of the original price.
We can set up an equation to represent this relationship:
\(\frac{2}{3} x = 32\)
To solve for \(x\) (the original price), we can multiply both sides of the equation by the reciprocal of \(\frac{2}{3}\), which is \(\frac{3}{2}\):
\(\frac{3}{2}\) × \(\frac{2}{3} x\) = \(\frac{3}{2}\) × \(32\)
\(x = 48\)
Therefore, the original price of the game was £48.

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We fail to reject the null hypothesis that the temperature level has no effect on the mean yield process.

Summary of Result:

Source | SS | df | MS | F | p-value

Treatment | 118.2 | 2 | 59.1 | 2.94 | 0.095

Error | 241.0 | 12 | 20.1 | |

Total | 359.2 | 14 | | |

To construct an analysis of variance (ANOVA) table and test whether the temperature level has an effect on the mean yield process, we need to perform the following steps:

Step 1: Calculate the total sum of squares (SST), the treatment sum of squares (SSTR), and the error sum of squares (SSE).

SST = ΣΣ(yij - ȳ)^2 = 359.2

where yij is the yield of the ith batch at the jth temperature level and ȳ is the overall mean yield.

SSTR = Σ(nj(ȳj - ȳ)^2) = 118.2

where nj is the number of batches produced at the jth temperature level, ȳj is the mean yield at the jth temperature level, and ȳ is the overall mean yield.

SSE = SST - SSTR = 241.0

Step 2: Calculate the degrees of freedom (df) for SST, SSTR, and SSE.

df(Total) = N - 1 = 14

where N is the total number of observations.

df(Treatment) = k - 1 = 2

where k is the number of treatment levels.

df(Error) = df(Total) - df(Treatment) = 12

Step 3: Calculate the mean square (MS) for SSTR and SSE.

MS(Treatment) = SSTR / df(Treatment) = 59.1

MS(Error) = SSE / df(Error) = 20.1

Step 4: Calculate the F-statistic.

F = MS(Treatment) / MS(Error) = 2.94

Step 5: Determine the critical value of F for a 0.05 level of significance with df(Treatment) = 2 and df(Error) = 12.

From a table of F-distributions, the critical value of F is 3.89.

Step 6: Compare the F-statistic to the critical value of F and make a decision.

Since 2.94 < 3.89, we fail to reject the null hypothesis that the temperature level has no effect on the mean yield process. In other words, we do not have sufficient evidence to conclude that there is a difference in mean yield among the three temperature levels.

Step 7: Summarize the results in an ANOVA table.

Source | SS | df | MS | F | p-value

Treatment | 118.2 | 2 | 59.1 | 2.94 | 0.095

Error | 241.0 | 12 | 20.1 | |

Total | 359.2 | 14 | | |

Note: The p-value is calculated as P(F > 2.94) = 0.095, which is greater than the significance level of 0.05. Therefore, we do not reject the null hypothesis.

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