Answer:
\(M=1.9\times 10^{27}\ kg\)
Explanation:
Given that,
Orbital period, T = 42.5 hours = 153000 seconds
The average distance of Jupiter's mass, r = 422,000 km
We need to find Jupiter's mass. The formula for the orbital period is given by :
\(T^2=\dfrac{4\pi^2}{GM}r^3\\\\T^2GM=4\pi^2 r^3\\\\M=\dfrac{4\pi^2 r^3}{T^2 G}\\\\M=\dfrac{4\pi^2 \times (422000 \times 10^3)^3}{(153000 )^2 \times 6.67\times 10^{-11}}\\\\M=1.9\times 10^{27}\ kg\)
So, the mass of Jupiter is \(1.9\times 10^{27}\ kg\).
Based on orbital period formula, the mass of Jupiter is 1.9 × 10^27 kg.
What is the mass of Jupiter?The period, t = 42.5 hours = 153000 seconds
The mass of Jupiter is found using the formula for orbital period given below:
\( {t}^{2} = \frac{ 4{\pi}^{2} {r}^{3} }{gm} \)Making m subject of formula
\(m = \frac{4 {\pi}^{2} {r}^{3} }{g {t}^{2}} \)
substituting the values:
\(m = \frac{ 4{\pi}^{2} \times(4.22 \times {10}^{8}) ^{3} }{ {153000}^{2} \times 6.67 \times {10}^{ - 11} } \)
\(m = 1.9 \times {10}^{27} kg\)
Therefore, the mass of Jupiter is 1.9 × 10^27 kg.
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Marissa is thirty-four weeks pregnant and is experiencing contractions her doctor has classified as pre-term labor. How long does Marissa need to delay labor in order to have a full-term baby?
Answer:
42 more weeks or 6 more weeks
Explanation:
Pregnancy lasts for about 280 days or 40 weeks
hope it helps
There is no more time to wait she can have the baby now as it is healthy enough due to it being past the week 29 mark.
From 1981 to 2001, which change was most likely happening in the US economy?
What occurs most of the time is the transformation that was brought about in the economy of the United States by a rise in consumer spending that occurred between 1981 and 2001.
What exactly is the American economy?Despite the fact that the economy of the United States is now one of the most stable economies in the world, consumer expenditure went increased from 1981 to 2001, which contributed to this trend.
And in terms of economics, there will be a positive shift in the state of the economy whenever there is spending on the part of consumers.
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Answer: the answer is C
Explanation:
an increase in spending by consumers
edg2023
After 5.2 seconds of uniform acceleration from rest, a spacecraft reaches an
altitude of 5.7 x 102 m [up]. What is the final velocity of the spacecraft? What is the
acceleration of the spacecraft?
Answer:
Final Velocity: 109.615 m/s
Acceleration: 21.08 m/s²
Explanation:
Distance traveled is given by
Velocity v = Δx/Δt
where Δx is the distance covered and Δt the time to cover that distance
Here Δx = 5.7 x 10² m and t = 5.2 seconds
So v = 5.7 x 10²/5.2 = 109.615 m/s
Acceleration is Δv/Δt where Δv is the change in velocity from an initial velocity and Δt the time taken to reach that initial velocity
Here initial velocity is 0, so Δv= 109.615 - 0 = 109.615m/s
Time to reach this velocity = 5.2 s
So acceleration a = 109.615/5.2 = 21.08 m/s²
Hang two sheets of paper vertically from adjacent corners. The sheets should be parallel and close to each other with a small gap between them. Now gently blow down between the two sheets. What happens? a. The sheets move toward each other and the gap narrows. b. The sheets move away from each other and the gap widens c. Nothing happens. The gap between the two sheets remains constant.
Answer:
a. The sheets move toward each other and the gap narrows.
Explanation:
This exercise is related to fluid mechanics, when blowing between the two sheets, we can apply Bernoulli's equation, where the index 2 is the space between the two sheets
P₁ + ½ ρ g v₁² + ρ g y₁ = P₂ + ½ ρ g v₂² + ρ g y²
if the two leaves are at the same height
y₁ = y₂
whereby
P₁ + ½ ρ g v₁² = P₂ + ½ ρ v₂²
for the air velocity between the leaves let us use the continuity equation
A₁ v₁ = A₂ v₂
the area between the leaves is less than the external area, so the air speed must increase. If we use this in Bernoulli's equation, increasing the speed 2 (between the leaves) to maintain equality the pressure must decrease.
If the pressure decreases, the blades should move closer
When resisting the answers, the correct one is a
Sue and Jenny kick a soccer ball at exactly the same time. Sue's foot exerts a force of28.85 N East. Jenny's foot exerts a force of 15.53 N North. What is the direction ofthe resultant force on the ball?
The direction of the resultant force on the ball = 28.3°
Explanation:Sue's foot exerts a force of 28.85 N East
Jenny's foot exerts a force of 15.53 N North
This can be represented diagrammatically as:
The magnitude of the resultant force, R, is calculated using the Pythagora's theorem
\(\begin{gathered} R^2=28.85^2+15.53^2 \\ R=\sqrt[]{28.85^2+15.53^2} \\ R=32.76N \end{gathered}\)The resultant force on the ball is 32.76N
The direction of the resultant force is given as:
\(\begin{gathered} \theta\text{ =}\tan ^{-1}\text{ }\frac{15.53}{28.85} \\ \theta\text{ =}\tan ^{-1}\text{ }0.5383 \\ \theta=28.3^0 \end{gathered}\)The direction of the resultant force on the ball = 28.3°
How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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using an allowable shear stress of 50 mpa, determine the power that can be transmitted at 2000 rpm through a shaft with a 30-mm diameter.
The power that can be transmitted at 2000 rpm through a shaft with a 30-mm diameter is 55.5165kw.
Power=\(\frac{265.072*2*pi*2000}{60} = 55.5165kw\)
Resale rate upkeep (RPM) exists with a dealer specifying the minimal (or most) fee at which the product ought to be re-sold to clients. Context: From a competition policy viewpoint, specifying the minimal fee is of challenge.
Resale price upkeep Agreements (RPMs) are arrangements where resellers agree that they'll sell products or products at positive fees at or above charge ground (minimum RPM) or at or below a rate ceiling (most RPM). Early in the twentieth century RPM agreements were consistent with se illegal underneath federal antitrust regulation. Resale price protection (RPM) specifies the final fee that outlets fee purchasers. This roundtable targeted on using RPM for books, newspapers, and similar cultural merchandise. Resale price upkeep (RPM) exists with a dealer specifying the minimum (or maximum) rate at which the product must be re-sold to clients.
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A heavy storm leaves 1 cm of rain on a city 5 km wide and 8 km long on a 2 hour period. How many cm3 of water fell on the city?
Answer: wow that’s hard
Explanation:
a car travels at 50 m/s for first 20 seconds , 30 m/s for next 30 seconds and finally 20 m/s for next 10 seconds . find its average speed
The average speed traveled by car is \(35m/s\).
\(1^{st}\) case
Speed\(=50m/s\\\)Time \(=20s\)Distance \(=\) \(speed*time= 50*20=1000m\)
\(2^{nd}\) case
Speed\(=30m/s\)Time\(=30s\)Distance\(=30*30=900m\)
\(3^{rd}\) case
Speed\(=20m/s\)Time\(=10s\)Distance\(=20*10=200m\)
Now, The total distance\(=(1000+900+200)m=2100m\)
Total time\(=(20+30+10)s=60s\)
Average distance \(=\frac{total distance}{total time} = \frac{2100}{60}=35m/s\)
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https://brainly.com/question/21097620Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to the rest mass energy of an electron. What should be the accelerating potential that need to be applied on an electron so that it has a de Broglie wavelength equal to that of the proton calculated above?
mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.
What is the energy of an electron that has undergone a 100 kV potential difference?An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.
What is the relationship between kinetic energy and the de Broglie wavelength?De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.
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1) A cyclist moves a distance of 2000 meters during a time of 20 minutes. How fast is the cyclist?
2) A car moves for 20 minutes on a road with constant speed. If he traveled 60 kilometers, what is his speed?
Answer:
1) speed of a cyclist = 100 m/min.
2) speed of a car moving = 3 km/min.
Explanation:
1) speed of a cyclist = distance over time
= 2000 m / 20 min
= 100 m/min.
2) speed of car moving = distance over time
= 60 km / 20 min
= 3 km/min.
URGENT!!! sorry this is my first time using brainly! but here is my question: Two ropes are attached to a wagon, one horizontal to the west with a tension force of 30 N, and the other east and at an angle of 30° northward and a tension force of 40 N. Find the components of the net force on the cart. Show all your work. Thank you in advance!
The components of the net force on the cart is determined as 67.66 N.
Component of net force on the cart
The component of net force on the cart is determined by resolving the forces into x and y -components.
T1 = 30 N
T2 = 40 N
T1x = -30cos(0) = 30 N
T1y = 30sin(0) = 0
T2x = 40 x cos(30) = 34.64 N
T2y = 40 x sin(3) = 20 N
∑X = 30 N + 34.64 N = 64.64 N
∑Y = 0 + 20 N = 20 N
Resultant forceR = √(64.64² + 20²)
R = 67.66 N
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The first law of thermodynamics leads us to conclude that
A. disorder in the universe is increasing with the passage of time.
B. the total energy in the universe is decreasing with time.
C. it is theoretically impossible to convert work into heat with 100% efficiency
D. the total energy of the universe is constant.
E. the total energy in the universe is increasing with time.
Answer:
D
Explanation:
D - The total energy in the universe is constant
The first law of thermodynamics states that heat is also another form of energy, and that thermodynamic processes are as a result, subjected to the principle of conservation of energy. The principle of conservation of energy is another way of boldly saying that heat energy cannot be created and neither can heat energy be destroyed.
I hope that's clear enough
abigal drives her car with a constant speed of 32 miles per hour . how far can she travel in 1 hour?
Abigail drives her car with a constant speed of 32 miles per hour . How far can she travel in 1 hour?
Abigail is driving 32 miles an hour. This means she goes 32 miles in 1 hour.
a block of mass m is lsliding dow a righ incline surface that makes an angle o with respect tot he horizontal. if the coefficent of static frinction and mkinetic frinction then the accleration of
The acceleration of the block down the incline is given by,
\(- a = \dfrac{ mgsin\theta - \mu sN }{m}\text{ if }mgsin\theta > \mu sN\\\\a = \dfrac{ mgsin\theta - \mu kN }{m}\text{ if }mgsin\theta \le \mu sN\)
where N = mgcosθ.
Let N be the normal force acting on the block, and F be the force of friction acting on the block. The force acting down the incline is mgsinθ, where g is the acceleration due to gravity. The net force acting on the block down the incline is given by Fnet = mgsinθ - F. Therefore, the acceleration of the block down the incline is given by a = Fnet/m.
If the block is not yet sliding, we have F = \(\mu sN\). Therefore, the maximum value of the force of friction is \(\mu sN\). If the force of gravity down the incline is greater than the maximum force of static friction, the block will begin to slide, and we have F = \(\mu kN\).
Therefore, the acceleration of the block down the incline is given by:
\(- a = \dfrac{ mgsin\theta - \mu sN }{m}\text{ if }mgsin\theta > \mu sN\\\\a = \dfrac{ mgsin\theta - \mu kN }{m}\text{ if }mgsin\theta \le \mu sN\)
where N = mgcosθ.
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--The complete question is, What is the acceleration of a block of mass m sliding down a right inclined surface that makes an angle θ with respect to the horizontal, given the coefficients of static and kinetic friction?--
you made $100,000 this year. you have $0 in adjustments, $11,500 in deductions and $7,300 in exemptions. What is your taxable increase?
The tax rate you will pay is displayed in tax brackets for each category of taxable income.
Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.
Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.
As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.
Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.
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The following graph shows the force exerted on and the displacement of object being pulled
Find the work done to pull the object 7.0 m
The work done to pull the object 7.0 m is the total area under the graph from 0.0 m to 7.0 m, determined as 245 J.
Work done by the applied forceThe area under force versus displacement graph is work done.
The total work done by pulling the object 7 m, can be grouped into two areas;
First area, A1 = area of triangle from 0 m to 2.0 mSecond area, A2 = area of trapezium, from 2.0 m to 7.0 mA1 = ¹/₂ bh
A1 = ¹/₂ x (2) x (20)
A1 = 20 J
A2 = ¹/₂(large base + small base) x height
A2 = ¹/₂[(7 - 2) + (7-3)] x 50
A2 = ¹/₂(5 + 4) x 50
A2 = 225 J
Total work doneW = A1 + A2
W = 20 J + 225 J
W = 245 J
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A car with tires of radius 0.25 m come to a stop from 28.78 m/s (100 km/hr) in 50.0 m without any slipping of tires. Find: (a) the angular acceleration of the wheels; (b) number of revolutions made while coming to rest.
Answer:
The answer is below
Explanation:
a) Using the formula:
\(\omega^2=\omega_o^2+2\alpha \theta\\\\\omega=final\ angular\ velocity,\omega_o=initial\ anglular\ velocity,\alpha= angular\ acceleration,\\\theta=angular\ distance\\\\Given\ that:\\\\initial\ velocity(u)=28.78m/s,distance(s)=50\ m,radius(r)=0.25\ m,\\final/ velocity(v)=0(stop)\\\\\omega=v/r=\frac{28.78m/s}{0.25m} =115.12\ rad/s,\omega_o=0,\theta=s/r=\frac{50\ m}{0.25\ m}=200\ rad\\ \\\omega^2=\omega_o^2+2\alpha \theta\\\\115.12^2=0^2+2\alpha(200)\\\\2\alpha(200)=13252.6144\\\\\alpha=33.13\ rad/s^2\)
b)
\(\theta=200\ rad=200\ rad*\frac{1\ rev}{2\pi\ rad}=31.83\ rev\)
describe how moral relativism was influenced by einstein theories of relativity and subsequently the trend toward the idea there are no absolutes?
The special and general theories of relativity and Albert Einstein's audacious theory that light is a particle are his most famous works as a physicist and Nobel winner. The most well-known scientist of the 20th century is perhaps him.
In March 1879, he was born in Ulm, Württemberg. He had a great interest in nature and the capacity to comprehend challenging mathematical ideas even as a young man in Munich. He had an unremarkable high school experience, doing exceptionally well in arithmetic but completely failing the classics, which were then thought to be crucial for anybody planning to attend college. He detested school's dreary regimentation and uncreative atmosphere.
The second study established a lot of information regarding the nature of molecules and explained Brownian motion, which is the random jostling of molecules floating in a fluid. 16 years later, this study helped him win the physics Nobel Prize.
However, his third work, "On the Electrodynamics of Moving Bodies," was left out of the award's wording. The third article was the one that would have the biggest impact on contemporary physics. It included Einstein's Special Theory of Relativity, which greatly simplified how we think about how radiation, like light, interacts with matter. Speaking about one body moving and another being motionless has no real significance, according to Einstein. Only in connection to one other can bodies be conceived of as moving;
This specifically implies that, regardless of the frame of reference, electromagnetic radiation's (such as light's) speed remains constant. Even well-known scientists struggled to comprehend this theory because of Einstein's insightful and audacious viewpoint. But over time, when the predictions made by his theory were repeatedly verified, the Special Theory of Relativity finally transformed how scientists thought about matter, space, time, and everything that interacts with them.
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What is the type of friction force if the object appears just about to start motion? Why?
Answer and I will give you brainiliest
Answer:
static friction
Explanation:
As I mentioned before static is just the object is started to move if it kentic it is moving
A lightbulb manufacturer makes bulbs with different "color temperatures," meaning that the spectrum of light they emit is similar to a blackbody with that temperature. Assuming the emitting areas of the filaments in two bulbs with color temperatures of 2,000 K and 4,000 K are the same, which of the two is the brighter?
Answer:
The bulb with higher temperature(4000 K) will be brighter
Explanation:
From the question we are told that
The color temperature for first bulb is \(T_1 = 2000K\)
The color temperature for second bulb is \(T_2 = 4000K\)
Generally the emission power of black body radiation is mathematically represented as
\(E = \sigma T^4\)
Where \(\sigma\) is the Stefan-Boltzmann constant with a value \(\sigma = 5.67 * 10^{-8} W m^{-2} K^{-4.}\)
Now for \(T_1 = 2000K\)
\(E_1 = 5.67*10^{-8} * (2000)^4\)
\(E_1 = 907.2 \ W/m^2\)
At \(T_2 = 4000K\)
\(E_2 = 5.67*10^{-8} * 4000\)
\(E_2 = 14515.2 \ KW/m^2\)
Looking at the result we got we see that the emission power for the higher temperature bulb is higher, this means that its power to emit in the visible spectrum range would be higher
So the bulb with higher temperature will be brighter
Which of these statements is true of how a medium absorbs a wave’s energy?
A. The amount of energy absorbed by a medium only depends on a wave’s direction.
B. The amount of energy absorbed by a medium only depends on a wave’s frequency.
C. The amount of energy absorbed by a medium can depend on a wave’s properties.
D. The amount of energy absorbed by a medium only depends on how long a wave has been traveling.
Answer:
C. The amount of energy absorbed by a medium can depend on a wave's properties.
Explanation:
The statement that is true of how a medium absorbs a wave's energy is:
C. The amount of energy absorbed by a medium can depend on a wave's properties.
When a wave travels through a medium, the medium can absorb some of the wave's energy, which can cause the wave to weaken or decrease in amplitude. The amount of energy that is absorbed by the medium can depend on various factors, such as the properties of the medium, the frequency and wavelength of the wave, and the intensity of the wave. For example, certain materials may be more effective at absorbing certain wavelengths of light, while others may be more effective at absorbing sound waves of specific frequencies. Therefore, the amount of energy absorbed by a medium can depend on the properties of the wave as well as the medium it is traveling through.
Two positive point charges are 4.9cm apart. If the electric potential energy is 70.0 μJ, what is the magnitude of the force between the two charges?
Hi there!
Recall the following:
\(V \text{ (Electric Potential Energy) } = \frac{kq_1q_2}{r}\\\\F_E = \frac{kq_1q_2}{r^2}\)
k = Coulomb's Constant (Jm/C²)
q = Charge (C)
r = distance between charges (m)
To calculate the electric force between the two charges, we can simply divide by another 'r' (distance):
\(F_E = \frac{70}{0.049} = \boxed{1428.57 \mu J}\)
A material that provides resistance to the flow of electric current is called a(n):
circuit
conductor
insulator
resistor
Answer:
it's an insulator
Explanation:
Insulators provides resistance
Answer:
C. insulator
Explanation:
What is the angle of refraction for a beam of light moving from air (n =1.00) into a prism if the angle
of incidence is 70° and the prism's index of refraction is 1.73?
big sorry for this
imma follow you
a
Which of these is a chemical
change?
A. water boiling
B. salt disolving
C. paper burning
Answer:
Burning coal and boiling water are both chemical changes. Burning coal is a chemical change, and boiling water is a physical change. Burning coal is a physical change, and boiling water is a chemical change.
Explanation:
the mass of a density bottle is 18.00g when empty 44.00g when full of water, and 39.84g when full up of a second liquid. calculate the density of the liquid where density of water =1000kgm³
The density of the second liquid is 0.812 g/cm³
To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:
mass of liquid = mass of bottle + liquid - mass of empty bottle
mass of liquid = 39.84g + x - 18.00g
where x is the mass of the liquid.
We can now use the density formula, which is:
density = mass/volume
The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:
volume of liquid = volume of bottle filled with liquid - volume of empty bottle
We can now substitute this expression into the density formula to get:
density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)
We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:
volume of water = mass of water / density of water
volume of water = 44.00g / 1 g/cm³
volume of water = 44.00 cm³
Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:
volume of bottle filled with liquid = volume of water - volume of liquid
volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³
volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³
volume of bottle filled with liquid = 22.16 cm³
Finally, we can substitute these values into the density formula to get:
density of liquid = x / 22.16 cm³
Solving for x, we get:
x = density of liquid x 22.16 cm³
Substituting x back into the mass equation, we get:
mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g
Solving for the density of the liquid, we get:
density of liquid = (mass of liquid - 21.84g) / 22.16 cm³
Substituting the given values, we get:
density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³
In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.
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• A steel wire 4.7 m long stretches 0.11 cm when it is subjected to a tension of 360 N. What is the spring constant of the wire?
Answer:
Explanation:
length = 4.7 m
extension x = (0.11 /100) m + 4.7 m
= 4.7011 m
force = 360 N
spring constant k = ?
formula : F = kx
k = F/ x
k = 360 ÷ 4.7011
k= 76.578 Nm^-1
The spring constant of the wire of a steel wire 4.7 m long stretches 0.11 cm when it is subjected to a tension of 360 N is 76.57 N/m.
What is the spring constant?Simple, symmetrical motion i.e., SHM is a genuinely fascinating kind of agitation. It is continuously used in the objects' oscillatory motion. Most springs have SHM. The "spring constants" that are intrinsic to springs determine how stiff they are. A well-known law, Hooke's law, describes the SHM and provides a formula for the applied force using the spring constant.
Simple harmonic motions and Hooke's law are related to the definition of the spring constant. Therefore, we must first examine Hooke's rule before attempting to define the spring constant and comprehend how it operates.
Given:
The tension force, T = 360 N,
The length of the wire, L = 4.7 meters,
The elongation, l = 0.11 cm,
Calculate the spring constant by the following formula,
k = T / l
( l = x(0.11 /100) m + 4.7 m= 4.7011 m)
Here, k is the spring constant.
Substitute the values,
k = 360 / 4.7011
k = 76.57 N / m
Therefore, the spring constant of the wire of a steel wire 4.7 m long stretches 0.11 cm when it is subjected to a tension of 360 N is 76.57 N/m.
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An atom of an element can change into an atom of another element if it is:
A. extremely stable
B. radioactive and it's nucleus can trap or emit particles
C. an ion and it's atomic number is larger than it's mass number
D. an isotope and it has more electrons than neutrons
Answer:
B. radioactive and it's nucleus can trap or emit particles
Explanation:
Each element is unique because of the number of protons it possesses. All the atoms of one particular element will have same amount of protons. Thus, if I want to change an atom of an element into atom of another element, i must have a way to mess with the proton count and such. These are seen in radioactive process like fusion, fission, nuclear decay etc.
g the total mechanical energy of the satellite-Earth system when the satellite is in its current orbit is E. In order for the satellite to orbit Earth in a new stable circular orbit at an altitude of 12RE, the energy of the satellite-Earth system must be
Answer:
The correct answer is "\(\frac{4E}{3}\)".
Explanation:
According to the question,
Energy of satellite,
⇒ \(E_s=-\frac{GM_sM_E}{2r}\)
For the very 1st case:
\(r = R_E+R_E\)
\(=2R_E\)
or,
⇒ \(E=-\frac{GM_sM_E}{4R_E}\)...(1)
For the new case:
\(r = R_E+\frac{R_E}{2}\)
\(=\frac{3R_E}{2}\)
then,
⇒ \(E'=-\frac{GM_sM_E}{2 \frac{3R_E}{2} }\)
\(=-\frac{GM_sM_E}{3R_E}\)...(2)
From equation (1) and (2), we get
⇒ \(E'=\frac{1}{3}(4E)\)
\(=\frac{4E}{3}\)