Find the distance between the two ponts rounding to the nearest tenth (if necessary)
(3,6) and (1,9)

Answer:

2y-7=5

Step-by-step explanation:

since the number represents y

the product of 2 and a number would be 2y

then since it says seven less than that you subtract 7 from 2y

this gives you 2y-7

finally, it says its equal to 5

so then all you have to put is 2y-7=5 as your answer since it only asks you to make the equation based off the sentence, not solve it.

Answer:

     81.2+79.9+80.22 ≈240

Step-by-step explanation:

The recurrence interval for the second largest flood on the Bow River in 1932 is approximately 1.0106 years. The probability of a flood with a discharge of 1,520 m3/s occurring next year is roughly 98.95%. When examining the 100-year trend of peak discharges, excluding major floods, there is likely a general pattern of fluctuations but with overall stability in typical peak discharge values.

Using the provided data on the highest discharge per year on the Bow River at Calgary, Canada, we can calculate the recurrence interval (R) for specific flood magnitudes and determine the probability of such floods occurring in the future. Additionally, we can examine the 100-year trend for floods on the Bow River, excluding major floods, to identify the general trend of peak discharges over time.

1) Calculating the Recurrence Interval for the Second Largest Flood (1,520 m3/s in 1932):

To calculate the recurrence interval (R) for the second largest flood, we need to determine the rank of that flood. Since there are 95 data points in total, the rank of the second largest flood would be 94 (as the largest flood, in 2013, is excluded). Applying the formula R = (n + 1) / r, we have:

R = (95 + 1) / 94 = 1.0106 years

Therefore, the recurrence interval for the second largest flood (1,520 m3/s in 1932) is approximately 1.0106 years.

2) Probability of a Flood of 1,520 m3/s Occurring Next Year:

The probability of a flood of 1,520 m3/s happening next year can be calculated by taking the reciprocal of the recurrence interval for that flood. Using the previously calculated recurrence interval of 1.0106 years, we can determine the probability:

Probability = 1 / R = 1 / 1.0106 = 0.9895 or 98.95%

Thus, the probability of a flood of 1,520 m3/s occurring next year is approximately 98.95%.

3) Examination of the 100-Year Trend for Floods on the Bow River:

To analyze the 100-year trend for floods on the Bow River while excluding major floods, we focus on the peak discharges over time. Without considering the labeled major floods, we can observe the general trend of peak discharges.

Unfortunately, without specific data on the peak discharges for each year, we cannot provide a detailed analysis of the 100-year trend. However, by excluding major floods, it is likely that the general trend of peak discharges over time would show fluctuations and variations but with a relatively stable pattern. This implies that while individual flood events may vary, there might be an underlying consistency in terms of typical peak discharges over the 100-year period.

In summary, the recurrence interval for the second largest flood on the Bow River in 1932 is approximately 1.0106 years. The probability of a flood with a discharge of 1,520 m3/s occurring next year is roughly 98.95%. When examining the 100-year trend of peak discharges, excluding major floods, there is likely a general pattern of fluctuations but with overall stability in typical peak discharge values.

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Answer:

48°

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

-9n+8

Step-by-step explanation:

Answer:

1/3

Step-by-step explanation:

constant proportionality = x/y

x1/y1 , x2/y2 , x3/y3 , ....

5/15 , 10/30 , 6/18 , 9/27 , 2/6

= 1/3 , 1/3 , 1/3 , 1/3 , 1/3

since in all the cases x/y = 1/3 ,

Therefore, the contant proportionality in the given table is 1/3

Hope it's helpful..

Answer:

Step by step explanation:                                                

.

The possible way of assigning the numbers that are fair:

(C) The numbers 1 and 2 represent Katia, 3 and 4 represent Tracy, and 5 and 6 represent Adan.

And (E) The numbers 1 and 6 represent Katia, 2 and 5 represent Tracy, and 3 and 4 represent Adan.

C and E are the correct options.

A combination is a selection of all or a portion of a group of items, regardless of the sequence in which the items are chosen.

Given:

Every week,

Katia’s parents randomly decide whether she, her sister Tracy, or her brother Adan takes out the trash.

Katia wants to use a fair number cube labeled 1 through 6 to simulate the results of the next 5 weeks.

The number of people = 3.

So, there are 6/3 = 2 distinct possible numbers.

From the given choices,

(C) The numbers 1 and 2 represent Katia, 3 and 4 represent Tracy, and 5 and 6 represent Adan.

And (E) The numbers 1 and 6 represent Katia, 2 and 5 represent Tracy, and 3 and 4 represent Adan.

Therefore, C and E are the correct statements.

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The complete question;

Every week, Katia’s parents randomly decide whether she, her sister Tracy, or her brother Adan takes out the trash. Katia wants to use a fair number cube labeled 1 through 6 to simulate the results of the next 5 weeks.

Select all the possible ways of assigning the numbers that are fair.

A)The number 1 represents Katia, 2 represents Tracy, and 3 represents Adan.

B) The odd numbers represent Katia, and the even numbers represent her other siblings.

C) The numbers 1 and 2 represent Katia, 3 and 4 represent Tracy, and 5 and 6 represent Adan.

D) The numbers 1 and 3 represent Katia, 2 and 5 represent Tracy, and 3 and 6 represent Adan.

E) The numbers 1 and 6 represent Katia, 2 and 5 represent Tracy, and 3 and 4 represent Adan.

Answer:

113.04 square inches

Step-by-step explanation:

(a)

Let X be the percentage of students who passed in both Nepali and English. Then the percentage of students who failed in at least one of the subjects would be:

Percentage of students who failed in Nepali = 30%

Percentage of students who failed in English = 27%

Percentage of students who failed in both subjects = 15%

Therefore, the percentage of students who failed in at least one of the subjects would be:

30% + 27% - 15% = 42%

This means that the percentage of students who passed in both subjects would be:

100% - 42% = 58%

Therefore, 58% of students passed in both Nepali and English.

    ____________

   /            \

  /              \

 /      NE        \

/                  \

/____________________\

       EN

NE: Nepali

EN: English

The left circle represents Nepali, the right circle represents English, and the overlap represents students who failed in both subjects. The percentage values can be added to each section of the Venn diagram to make it clearer.

Answer:

-3.75

Step-by-step explanation:

Answer and Step-by-step explanation:

The area of the tile is 9.

To find the area, we multiply the side by another side.

3 times 3 is equal to 9.

#teamtrees #PAW (Plant And Water)

Answer:

13/20 of a mile

Step-by-step explanation:

2/5 x 4 = 8/20

1/4 x 5 = 5/20

8/20 + 5/20 = 13/20

The missing term in the equation (x + 9)² = x² + 18x + is 81. The simplified form of the (x + 9 )² = x² + 18x + 81. The correct option is C.

Given

(x + 9)² =  x² + 18x +----

Required to find the missing term =?

It is given the form of ( a + b)² = a² + 2ab + b²

Putting the given values in the above form we get the value of the missing term from the equation

(x + 9 )² = x² + 2 × x ×9 + 9 × 9

              = x² + 18x + 81  

A quadratic equation is a second-order polynomial equation in one variable that goes like this: x ax2 + bx + c=0, where a 0. Given that it is a second-order polynomial equation, the algebraic fundamental theorem ensures that it has at least one solution. Real or complicated solutions are both possible.

Thus, we get the value of the missing term as 81.

Thus, the ideal selection is option C.

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Answer:

green because it sounds like garbage

Step-by-step explanation:

Answer:

the one u want to put em in?

Step-by-step explanation:

Answer:

hope you get ur answer ❤️☺️✨

The expression is simplified to give 2(9x + 2√3x - 5)

First, we need to know that surds are mathematical forms that can no longer be simplified to smaller forms

From the information given, we have that;

(2√3x - 2)(3√3x + 5)

expand the bracket, we get;

6√9x² + 5(2√3x) - 6√3x - 10

Find the square root factor

6(3x)  + 10√3x - 6√3x - 10

collect the like terms, we have;

18x + 4√3x - 10

Factorize the expression, we have;

2(9x + 2√3x - 5)

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Answer: 8a

Step-by-step explanation:

Step-by-step explanation:

I can only think of one way to simplify this and it is by taking out the greatest common factor: a². Or by multiplying the two values together so it's only one value.

a²(3*5)

a²(15)

Or...

(3a² * 5a²)

(15a⁴)

(this one is a⁴ because a variable with a power multiplied by a variable with a power only adds the powers together)

It also aids in the identification of key variables and trends, as well as the reduction of data to specific correlations or relationships.To summarize,A knowledge of statistics helps us make decisions based on empirical evidence.

A knowledge of statistics helps us make decisions based on empirical evidence.What is Statistics?Statistics can be described as the method of collecting, analyzing, interpreting, and presenting data. In order to make accurate decisions based on data, it is necessary to comprehend statistics. Data analysis is simplified with statistics, and data visualization is improved. It also aids in the identification of key variables and trends, as well as the reduction of data to specific correlations or relationships.To summarize,A knowledge of statistics helps us make decisions based on empirical evidence.

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False. The intercepted arc is actually twice the measure of the inscribed angle only if the inscribed angle is an angle at the center. If the inscribed angle is not at the center, the intercepted arc will have a different measure.

So, in general, the relationship between the measure of the intercepted arc and the inscribed angle it was created from depends on the location of the inscribed angle in the circle. This is a long answer, but it provides a detailed explanation of the relationship between the intercepted arc and the inscribed angle in different scenarios.

AN intercepted arc is twice the measure of the inscribed angle it was created from.
In a circle, when an inscribed angle is formed by two chords, it intercepts an arc on the circle. According to the Inscribed Angle Theorem, the measure of the inscribed angle is half the measure of the intercepted arc. Therefore, the intercepted arc is indeed twice the measure of the inscribed angle.

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Answer:

B: 2800 hydrogen atoms

C: 6760 hydrogen atoms

D: y=amount of oxygen atoms*2

Step-by-step explanation:

B: We know the formula for water is H2O. SO that means that there is 2 hydrogen atoms and 1 oxygen atom. So there is 2 times the amount of hydrogen atoms so we can do 1400*2=2800, So there is 2800 hydrogen atoms in the water.

C: Same thing as B. 3380*2=6760

D: y=amount of oxygen atoms*2. Because there is one oxygen atom and two hydrogen atoms so 1*2=2.

Answer:

\(\large\boxed{\tt x = 2}\)

Step-by-step explanation:

\(\textsf{We are asked to solve for x in the given equation.}\)

\(\textsf{We should know that x is cubed, meaning that it's multiplied by itself 3 times.}\)

\(\textsf{We should isolate x on the left side of the equation, then find x by cubic rooting}\)

\(\textsf{both sides of the equation.}\)

\(\large\underline{\textsf{How is this possible?}}\)

\(\textsf{To isolate variables, we use Properties of Equality to prove that expressions}\)

\(\textsf{are still equal once a constant has changed both sides of the equation. A Cubic}\)

\(\textsf{Root is exactly like a square root, but it's square rooting the term twice instead}\)

\(\textsf{of once.}\)

\(\large\underline{\textsf{For our problem;}}\)

\(\textsf{We should use the Subtraction Property of Equality to isolate x, then cubic root}\)

\(\textsf{both sides of the equation.}\)

\(\large\underline{\textsf{Solving;}}\)

\(\textsf{Subtract 1 from both sides of the equation keeping in mind the Subtraction}\)

\(\textsf{Property of Equality;}/tex]

\(\tt \not{1} - \not{1} - x^{3} = 9 - 1\)

\(\tt - x^{3} = 8\)

\(\textsf{Because x}^{3} \ \textsf{is negative, we should exponentiate both sides of the equation by}\)

\(\textsf{the reciprocal of 3, which is} \ \tt \frac{1}{3} .\)

\(\tt (- x^{3})^{\frac{1}{3}} = 8^{\frac{1}{3}}\)

\(\underline{\textsf{Evaluate;}}\)

\(\tt (- x^{3})^{\frac{1}{3}} \rightarrow -x^{3 \times \frac{1}{3} } \rightarrow \boxed{\tt -x}\)

\(\textsf{*Note;}\)

\(\boxed{\tt A^{\frac{1}{C}} = \sqrt[\tt C]{\tt A}}\)

\(\tt 8^{\frac{1}{3}} \rightarrow \sqrt[3]{8} \rightarrow 2^{1} \rightarrow \boxed{\tt 2}\)

\(\underline{\textsf{We should have;}}\)

\(\tt -x=2\)

\(\textsf{Use the Division Property of Equality to divide each side of the equation by -1;}\)

\(\large\boxed{\tt x = 2}\)

The journal enetry,

Debit cash is $67,000

Debit discount on payable is $670

Credit bonds payable is $66,330

(Recorded on bonds )

Debit Interest expense is $46,90

Debit discount on bonds payable is $46.9

credit cash is $4643.1..

Bonds payable

Bonds issued when the market price equals the standard rate are issued at face value. In other words, the cash received is face value.

Interest paid on the par Bond includes only the indicated. Interest rate calculated based on the number of annual payments.

We have given that

face amount, F = $67,000

Annually paid interest= $67,000

rate of bond, r = 7%

time bond, n = 10 year

market bond of interest= 7%

Coupon ammount = 7% of 67000 =$ 4690

we have to calculate bond issue and first interest payment .

bond price= C×[1 - (1 + r)⁻ⁿ] /r + F/(1+r)ⁿ

= 4690[ 1 - (8)¹⁰]/7 + 67000/(8)¹⁰

=669.99 + 0.000062 = 669.9901 ~ 670

Interest Expense = Principal * Rate * Time

=> Interest Expense = $67,000×7% ×1

= $46,90

discount or primum on bond payable

= interest expense - $66,330×7% × 1

= $46,90- $4643.1 = $46.9

date General

General journal debit credit

January, cash $67,000 $66,330

2024 Bonds

payable

Discount on

bond $670

payable

December

31, cash $4643.1

2024 interest

expense $46,90

Discount on

bond $46.9

payable

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Complete Question:.Pretzelmania, Inc., issues 7%, 10-year bonds with a face amount of $67,000 for $67,000 on January 1, 2024. The market interest rate for bonds of similarrisk and maturity is 7%. Interest is paid annually on December 31.Record the bond issue and first interest payment on December 31 . (If no entry is required for a transaction/event, select "No journal entry required" in thefirst account

The appropriate test to examine the relationship between the number of steps taken and HR in a group of 1000 athletes depends on the type of data and the research question.

If the number of steps and HR are both measured on a continuous scale and the research question is to examine the strength and direction of the relationship between the two variables, then the appropriate test would be Pearson's correlation coefficient.

If either the number of steps or HR is measured on a continuous scale and the other variable is measured on an ordinal scale, then the appropriate test would be Spearman's correlation coefficient.

However, if the research question is to predict HR based on the number of steps taken, and there are other variables that may influence the relationship, then multiple regression analysis would be the appropriate test.

Chi-Square test is used to examine the association between two categorical variables. It is not appropriate for examining the relationship between a continuous and categorical variable.

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Answer:

Number : 42

Step-by-step explanation:

This number will be a two - digit number, and hence we can say that it is yz. The ratio of the units digit to the tens digit is given by 1 / 2, so z / y = 1 / 2.

In addition the tens digit is 2 more than the units digit, so y = z + 2. We therefore have the following system of equations,

y = z + 2,

z / y = 1 / 2

Substituting the first equation into the second we receive z / z + 2 = 1 / 2. Using this we can solve for z.

z / z + 2 = 1 / 2 ( Cross - Multiply )

z + 2 = 2z, z = 2

And knowing z we can solve for y. y = z + 2 = 2 + 2 = 4. Therefore our number is 42.

The solution of the algebraic equation for the cost of downloading a song for members is x = $0.95

Given that:

1. Peggy pays an annual fee of $10.75. Last year she downloaded 105 songs

2. Non-members pay $0.35 more per song download than members

3. Daniel is not a member of the club and downloaded 85 songs last year

Let x represent the cost of downloading a song for members

Thus, the cost of a song for Peggy will be x

From statement 2: the cost of a song for Daniel will be x+0.35

The algebraic equation for the total amount for Peggy will be:

A = 105x + 10.75

The algebraic equation for the total amount for Daniel will be:

A = 85(x+0.35)

If Daniel and Peggy both paid the same total amount, we can say:

105x + 10.75 = 85(x+0.35)

105x + 10.75 = 85x + 29.75

105x - 85x = 29.75 - 10.75

20x = 19

x = 19/20

x = 0.95

Thus, the cost of a song for member is $0.95

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Answer:

First, Third, Fifth statements are true about the median of a data set. Step-by-step explanation: Median is the middle value . Median isn't affected much by one outlier because median is the middle value of an ordered sequences of value

The distance of the line is √17 and the midpoint of the line is ( 5/2 , 2).

Why do you use the word distance?

Distance is the total movement of an object without taking direction into account. Distance can be described as the amount of ground that an object has covered, regardless of its beginning or ending points.

points A (3,-1) B (2,5)

D = √(x₂ - x₁)² + (y₂ - y₁ )²

    = √(2 - 3)² + ( 5- ( -1))²

     = √(-1)² + (4)²

      = √1 + 16

        = √17

  midpoint =   x = 2 + 3/2

                          = 5/2

                   y = 5 - 1/2

                   y = 2

  (x,y) = ( 5/2 , 2)

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Eventually, the differential equation's general solution is:

y = y_h + y_p

y = c1e^(-2x) + c2e^(-x) - (1/6)e^(-x) + (2/3)

In the context of differential equations, the homogeneous solution of a differential equation is a solution that satisfies the equation when the right-hand side is equal to zero.

To find the particular solution of y'' + 3y' + 2y = 4e^x using the variation of parameters method, we first find the homogeneous solution of the differential equation by setting the right-hand side to zero:

y'' + 3y' + 2y = 0

The characteristic equation is r^2 + 3r + 2 = 0, which factors as (r + 2)(r + 1) = 0. Therefore, the solutions are y_h = c1e^(-2x) + c2e^(-x), where c1 and c2 are constants.

Next, we find the Wronskian of the homogeneous solution:

W(y1, y2) = |e^(-2x) e^(-x) | = e^(-3x)

To find the particular solution, we assume that it has the form y_p = u1(x)e^(-2x) + u2(x)e^(-x), where u1(x) and u2(x) are unknown functions to be determined.

We then find y_p' and y_p'':

\(y_p' = u1'(x)e^(-2x) + u2'(x)e^(-x) - 2u1(x)e^(-2x) - u2(x)e^(-x)y_p'' = u1''(x)e^(-2x) + u2''(x)e^(-x) - 4u1'(x)e^(-2x) - 2u2'(x)e^(-x) + 4u1(x)e^(-2x) + u2(x)e^(-x)u1''(x)e^(-2x) + u2''(x)e^(-x) + u1'(x)e^(-2x) + u2'(x)e^(-x) - 4u1'(x)e^(-2x) - 2u2'(x)e^(-x) + 4u1(x)e^(-2x) + u2(x)e^(-x) = 4e^x\)

Simplifying and grouping terms, we get:

\(u1''(x)e^(-2x) - 3u1'(x)e^(-2x) + u2''(x)e^(-x) - u2'(x)e^(-x) = 4e^x\)

To solve for u1(x) and u2(x), we use the method of undetermined coefficients and assume that they are both linear combinations of the exponential function and its derivative:

u1(x) = A(x)e^x

u2(x) = B(x)e^(2x)

Substituting these expressions into the previous equation and solving for A(x) and B(x), we get:

A(x) = -e^x/6

B(x) = 2e^x/3

Therefore, the particular solution is:

\(y_p = (-e^x/6)e^(-2x) + (2e^x/3)e^(-x)y_p = (-1/6)e^(-x) + (2/3)\)

Eventually, the differential equation's general solution is:

y = y_h + y_p

y = c1e^(-2x) + c2e^(-x) - (1/6)e^(-x) + (2/3)

Therefore, the particular solution of the given differential equation y′′+3y′+2y=4ex is

\(y(x)=c_1e^{-x} + c_2e^{-2x} - 4 + 2e^{x}.\)

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Answer:

c = 6√2

Step-by-step explanation:

The following data were obtained from the question:

Angle θ = 30°

Opposite = 3√2

Hypothenus = c

The value of 'c' can be obtained by using the sine ratio as shown below:

Sine θ = Opposite /Hypothenus

Sine 30° = 3√2/c

Cross multiply

c × sine 30° = 3√2

Divide both side by sine 30°

c = 3√2 / sine 30°

But: sine 30° = 1/2

c = 3√2 / sine 30°

c = 3√2 ÷ 1/2

c = 3√2 × 2

c = 6√2 yard

Therefore, the value of 'c' is 6√2 yard.

a. The probability that dies 1 beat die 2 is 4/6 or 2/3.

b. The probability that dies 2 beats die 3 is 5/6.

c. The probability that dies 3 beats die 1 is 1/6.

d. Die 2 is the best die.

a. To find the probability that dies 1 beat die 2, we count the favorable outcomes where the roll of die 1 is greater than the roll of die 2. Die 1 has 4 numbers greater than any number on die 2 (6, 7, 8, and 9), out of a total of 6 possible outcomes. Therefore, the probability is 4/6 or 2/3.

b. Similarly, to find the probability that dies 2 beats die 3, we count the favorable outcomes where the roll of die 2 is greater than the roll of die 3. Die 2 has 5 numbers greater than any number on die 3 (3, 4, 15, 16, and 17), out of a total of 6 possible outcomes. Therefore, the probability is 5/6.

c. To find the probability that dies 3 beats die 1, we count the favorable outcomes where the roll of die 3 is greater than the roll of die 1. Die 3 has only 1 number greater than any number on die 1 (14), out of a total of 6 possible outcomes. Therefore, the probability is 1/6.

d. To determine the best die, we compare the probabilities of winning for each die against the other two dice. Comparing the probabilities:

Die 1 has a probability of 2/3 of beating die 2 and a probability of 1/6 of beating die 3.

Die 2 has a probability of 5/6 of beating Die 3 and a probability of 2/3 of being beaten by Die 1.

Die 3 has a probability of 1/6 of beating die 1 and a probability of 5/6 of being beaten by die 2.

Based on these probabilities, die 2 has the highest chance of winning, making it the best die in this game.

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