find the value of 2\5of rs75​

Response rates in online surveys can be problematic due to the inadequate number of individuals in organized panels of respondents. An organized panel of respondents is a group of individuals who are willing to participate in online surveys, but there are limited numbers of such individuals.

The low response rates may lead to bias results, lower precision, and increased variability, resulting in inaccurate findings. Researchers might also find it challenging to calculate the response rates when the data collection vendor is recruiting participants outside the official online data collection vendor.Response rates are usually determined by the number of surveys completed in relation to the total number of potential respondents in a sample. The greater the number of individuals who complete the survey, the greater the response rate. There might be a problem calculating response rates if data collection vendors identify and target participation from specific groups of individuals.

The use of radio buttons, pull-down menus for responses, and the use of visuals have no effect on calculating response rates. However, graphics and animation might affect survey response rates if they cause technical problems or distraction to the respondent while participating in the survey.

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Answer:1 5/7

Step-by-step explanation:

Answer:

12/7 or 1 5/7

Step-by-step explanation:

it's would be 1 5/7

a) The probability that the proportion of seriously delinquent loans has a rate above 8% is 0.9147 (rounded to 4 decimal places).

b) The probability that the proportion of seriously delinquent loans has a rate between 9.5% and 10.5% is 0.1186 (rounded to 4 decimal places).

a) We have given that the rate of seriously delinquent loans follow a normal distribution with a standard deviation of 0.80%.

Also, it is reported that the rate of seriously delinquent loans has an average of 9.1%. Let P be the proportion of seriously delinquent loans. We are to determine the probability that the proportion of seriously delinquent loans has a rate above 8%.

Now, we have to compute the Z-score associated with P = 8%.

The Z-score is given by:

Z = (P - µ) / σZ = (0.08 - 0.091) / 0.0080= -1.375

From the Z-table, we have

P(Z > -1.375) = 0.9147

b) We are to find the probability that the proportion of seriously delinquent loans has a rate between 9.5% and 10.5%.So, P(9.5% ≤ P ≤ 10.5%) = P(P ≤ 0.105) - P(P ≤ 0.095)

Now, we have to compute the Z-score associated with P = 10.5%.

The Z-score is given by:

Z = (P - µ) / σZ = (0.105 - 0.091) / 0.0080= 1.750 And, we have to compute the Z-score associated with P = 9.5%.The Z-score is given by:Z = (P - µ) / σZ = (0.095 - 0.091) / 0.0080= 0.500

So, from the Z-table, we have:

P(P ≤ 0.105) = 0.9599 and P(P ≤ 0.095) = 0.8413

Therefore, P(9.5% ≤ P ≤ 10.5%) = P(P ≤ 0.105) - P(P ≤ 0.095)= 0.9599 - 0.8413= 0.1186

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Answer:

250

Step-by-step explanation:

Answer:

33

Step-by-step explanation:

I believe that the question is asking this

4q+25 and not 4(q+25)

so 4(2)=8+25 is 33

So 4 times a number q means 4*q and when q is 2 you will get 8 and when you add that to 25 you get 33

The diagram can be drawn as,

The surface area of the base is

The lateral surface area can be determined as,

The total surface area can be determined as,

Thus, the total surface area is 20 sq km.

Answer:

If something is a function, every x-value, only has one (1) y-value. If the line x = 0 intersects the graph in two points, there are to values for y (instead of one). Therefore the graph is not a function of x.  This also means your answer is A. Hope this helps!!!

Answer:

A

Step-by-step explanation:

plz mark me brainliest

Answer:

110 degrees

Step-by-step explanation:

a triangle is made up of 180 degrees

first

25+45 = 70

180 - 70=110

110 degrees is the missing angle

The estimated value of the explanatory variable is not statistically significant at the 5%-level if a. the t-statistic is greater than 2.5.

The t-test is a hypothesis testing technique used to decide whether the estimated coefficient of a linear regression model is statistically significant or not. The t-value is used to measure the size of the difference between the estimated coefficient and the hypothesized value. When the t-value exceeds a critical value, such as 2.5, the estimated value of the explanatory variable is not significant at the 5%-level. It implies that the null hypothesis, which assumes that the explanatory variable's coefficient is zero, cannot be rejected.

The p-value is a measure of the probability of obtaining a more extreme value of the test statistic than the observed value if the null hypothesis is true. A small p-value implies that the null hypothesis should be rejected. When the p-value is less than 0.05, it means that the estimated value of the explanatory variable is significant at the 5%-level.

The confidence interval is a range of values that is expected to include the true value of the population parameter with a specified level of confidence. A 95% confidence interval means that the true value of the population parameter lies within the range 95% of the time. The 95% confidence interval does not contain zero implies that the estimated value of the explanatory variable is statistically significant at the 5%-level since it suggests that the population parameter is different from zero at the 5%-level. Conversely, if the 95% confidence interval contains zero, the estimated value of the explanatory variable is not statistically significant at the 5%-level since it means that the population parameter is not different from zero at the 5%-level. Therefore, it is essential to examine the t-statistic, p-value, and confidence interval while conducting hypothesis testing to make an informed decision.

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The coordinates of the relative maxima are (2, 13) and (-2, -13).

The coordinates of the relative minima are (0, -1).

The coordinates of the points of inflection are (-1, -10) and (1, 10).

There is no minimum. D. The coordinates of the points of inflection: A.

To determine the coordinates of the relative maxima, minima, and points of inflection, we need to analyze the behavior of the given function and its derivatives.

Let's start by finding the first and second derivatives of the function y = 3x^3 - 36x - 1.

Step-by-step explanation:

1. Find the first derivative (dy/dx) of the function:

  dy/dx = 9x^2 - 36

2. Set the first derivative equal to zero to find critical points:

  9x^2 - 36 = 0

  Solving for x, we get x = ±2

3. Determine the second derivative (d^2y/dx^2) of the function:

  d^2y/dx^2 = 18x

4. Evaluate the second derivative at the critical points to determine the concavity:

  d^2y/dx^2 evaluated at x = -2 is positive (+36)

  d^2y/dx^2 evaluated at x = 2 is positive (+36)

  Since the second derivative is positive at both critical points, we conclude that there are no points of inflection.

5. To find the relative maxima and minima, we can analyze the behavior of the first derivative and the concavity.

  At x = -2, the first derivative changes from negative to positive, indicating a relative minimum. The coordinates of the relative minimum are (-2, f(-2)).

  At x = 2, the first derivative changes from positive to negative, indicating a relative maximum. The coordinates of the relative maximum are (2, f(2)).

In summary, the coordinates of the relative maxima are (2, f(2)), there is no relative minimum, and there are no points of inflection.

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Answer:

(1664π)/7

Step-by-step explanation:

We first need to know the points of intersection of the two functions, y = x³ and y = 4x.

To do this, we equate both functions

x³ = 4x

x³– 4x = 0

x(x² – 4) = 0

x(x – 2)(x + 2) = 0

x = 0, x = 2 and x = –2

Since we are looking for the volume formed by rotating the region inside the FIRST QUADRANT, then the needed points of x are 0 and 2. These are our limits of integration.

The formula for the area of the solid is

\( \int\limits^2_0 {\pi (4x)^3} \, dx -\int\limits^2_0 {\pi (x^3)^3} \, dx \)

This gives:

\( \int\limits^2_0 {64\pi x^3} \, dx -\int\limits^2_0 {\pi x^6} \, dx \)

On integration, we have

16π(2⁴) – π(2^7)/7

=

256π – 128π/7

= (1792π – 128π)/7

= (1664π)/7

Because the point (-5, 3) in the pre-image and its corresponding position (5, 3) in the picture are both at the same distance from the y-axis. The pre-point image's (-3, 5) is mirrored to the image's point (3, 5).

The x-axis is the horizontal axis and the y-axis is the vertical axis in two-dimensional space. As seen in the image below, they are represented by two number lines that perpendicularly connect at (0, 0).

This is a reflection of the pre-image that was provided over the y-axis:

Segment

10 9 8 7 6 5 -5 -6 -7 -8 -9 -10

Because the point (-5, 3) in the pre-image and its corresponding position (5, 3) in the picture are both at the same distance from the y-axis, they are reflected to one another.

Similar to this, the pre-point image's (-3, 5) is reflected to the image's point (3, 5).

The x-coordinates of all other locations in the pre-image are negated in the image because they have corresponding points there that are equally spaced from the y-axis.

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Step-by-step explanation:

they are different because the first equation only ax is in absolute but in the second equation both ax and b are in absolute, so we could solve them differently.

The correct value of the product of a and b is 224

Taking the prime factorization of 161 reveals that it is equal to 23*7. Therefore, the only ways to represent 161 as a product of two positive integers are 161*1 and 23*7. Because neither 161 nor 1 is a two-digit number, the only two-digit factor of 161 is 23, we know that a and b are 23 and 7. Because 23 is a two-digit number, we know that a, with its two digits reversed, gives 23.

Therefore, a = 32 and b = 7. Multiplying our two correct values of a and b yields.

The correct product must have been

a*b =32*7

=224

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Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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Answer: its 40 because its a whole number

Step-by-step explanation:

The value of 12x given in the question above is 30

2x + 10 = 6x

Collect like terms

10 = 6x – 2x

10 = 4x

Divide both side by 4

x = 10 / 4

x = 2.5

Substitute the value of x into 12x

12x = 12 × 2.5

12x = 30

Thus, the value of 12x is 30

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If 2x + 10 = 6x, then 12x = 30.

To find the value of 12x, we need to solve the equation 2x + 10 = 6x to find the value of x.

So, 2x + 10 = 6x

Subtract 2x from both sides, we have

2x - 2x + 10 = 6x - 2x

0 + 10 = 4x

10 = 4x

4x = 10

Divide both sides by 4, we have

4x/4 = 10/4

x = 2.5

To find 12x, we substitute the value of x into 12x.

So 12x = 12 × 2.5

= 30

So, if 2x + 10 = 6x, then 12x = 30.

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The work done in pulling the rope up 20 ft is 101.43 ft-lbs.

To find the work done in pulling the rope up 20 ft, we need to first determine the initial potential energy of the rope before it is lifted up. We can do this using the formula:

Potential Energy = weight * height

where weight is the weight of the rope and height is the distance the rope is hanging from.

Given:

Length of the rope (L) = 70 ft

Weight of the rope (Wt) = 49 lbs

Height of the building (H) = 100 ft

Height to which the rope is lifted (h) = 20 ft

Using the Pythagorean theorem, we can find the distance (d) the rope is hanging from the building:

d^2 = H^2 + L^2

d^2 = 100^2 + 70^2

d^2 = 10000 + 4900

d^2 = 14900

d = \(\sqrt{14900}\)

d = 122.07 ft

Now we can find the initial potential energy of the rope:

Potential Energy = Wt * d

Potential Energy = 49 * 122.02

Potential Energy = 5981.43 ft-lbs

Next, we need to find the final potential energy of the rope after it is lifted up 20 ft. The height to which the rope is lifted is (H + h) = 100 + 20 = 120 ft. Using the same formula as before, we get:

Final Potential Energy = Wt * (H + h)

Final Potential Energy = 49 * 120

Final Potential Energy = 5880 ft-lbs

Finally, we can find the work done in lifting the rope up 20 ft:

Work Done = Initial Potential Energy - Final Potential Energy

Work Done = 5981.43 - 5880

Work Done = 101.43 ft-lbs

Therefore, the work done in pulling the rope up 20 ft is 101.43 ft-lbs.

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Using the normal distribution, the project completion time with a 75% certainty is of 42 weeks.

The z-score of a measure X of a normally distributed variable with mean \(\mu\) and standard deviation \(\sigma\) is given by:

\(Z = \frac{X - \mu}{\sigma}\)

For this problem, the parameters are given as follows:

\(\mu = 40, \sigma = \sqrt{9} = 3\)

The project completion time with a 75% certainty is the 75th percentile, which is X when Z = 0.675, hence:

\(Z = \frac{X - \mu}{\sigma}\)

0.675 = (X - 40)/3

X - 40 = 3 x 0.675

X = 42.

The project completion time with a 75% certainty is of 42 weeks.

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Using theories of Rhode island ,we got that when the British ship Gaspee ran a ground in Rhode island, the local population 1) burned it.

On June 9, Gaspee gave chase to the packet ship Hannah, but the Gaspee ran aground in shallow water on the northwestern side of  bay on what is now Gaspee Point. Her crew were unable to free her and the Dudingston decided to wait for the high tide, which would possibly set the vessel afloat. Before that could happen, however, the band of Providence men led by John Brown decided to act on a "opportunity offered of putting an end to the trouble and the vexation she daily caused."  They rowed out to the ship and boarded at the break of dawn on June 10.

Hence, when the british ship gaspee ran aground in rhode island, the local population 1) burned it.

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Answer:

the answer is a percent                                      

Answer:

A percent!

Step-by-step explanation:

50/100 is 50%

Answer:

yes, if AB ≅ DE

Step-by-step explanation:

Triangles are said to be congruent if they have the same sides and the same angles.

The following measures are used to determine if triangles are congruent:

1) Angle-side-angle: If two angles and a side of a triangle is equal to two angles and corresponding side of another triangle, then they are congruent.

2) Side-side-side: If all three sides of a triangle is equal to three sides of another triangle, then the two triangles are congruent.

3) Side angle side: If two sides and an included angle of a triangle is equal to the two sides and corresponding angle of another triangle, then they are congruent.

4) Hypotenuse - leg: If the hypotenuse and one leg of a triangle is equal to the hypotenuse and leg of another triangle then they are congruent.

From the triangles  DEF and ABC, already, they already have one equal triangle that is ∠F = ∠B and an equal side i.e DF = AC.

To satisfy congruence, two sides and an angle have to be equal, therefore if AB = DE then the two triangles would be congruent

Answer:

D). no, because the hypotenuses must have different lengths

Step-by-step explanation:

I just did the assignment on Edge and it's 100% correct.

Hope this helps!! Also heart and rate if you found this answer helpful!!  :)

The cost of the cylinder in terms of the single variable, r, alone is 2000π + πr⁴

The volume of a cylinder is given by πr²h. We know that the volume of the cylinder must be 1000π cubic feet, so we can set up the following equation:

πr²h = 1000π

h = 1000/r²

The cost of the cylinder is given by 2πr²h + πr² = 2πr²(1000/r²) + πr² = 2000π + πr⁴

The cost of the cylinder in terms of the single variable, r, alone is:

Cost of cylinder = 2000π + πr⁴

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After 5 hours, the northbound train is

(30 mph) (5 h) = 150 mi

north of the station, while the eastbound train is

(40 mph) (5 h) = 200 mi

east of the station.

The distance between the trains is the length of the hypotenuse in the right triangle formed by the trains' paths. By the Pythagorean theorem, this distance is

\(\sqrt{(150\,\mathrm{mi})^2 + (200\,\mathrm{mi})^2} = \sqrt{62,500\,\mathrm{mi}^2} = \boxed{250\,\rm mi}\)

Let \(n=0\). Then \(0^3 = 0\) but 0 > 0 is a false statement.

Answer:

43.2 inches  is  3.6ft

1.2 yards is 3.6ft

4x37

Step-by-step explanation:

only a few ways to get to 148

Answer:

7.14 well be your answer

Step-by-step explanation:

Slope of the line is - 3 and y-intercept is 6

Slope - intercept form of line is y = mx + b where m is slope of the line and b is intercept on y-axis

taking any two points from the table

A(-1 ,10) , B(0,7)

calculating slope by y₂-y₁/x₂-x₁

putting x₁ = -1 , x₂ = 10 and y₁ =0 , y₂=7

m = 7-10 / 0 + 1 = -3/1

m = -3

equation of line will be y = -3x + b

calculating intercept b by putting one point in equation of line

10 = -3(-1) + b

10 = 4 + b

b = 6

substituting value of b in the equation

y = -3x + 6 is our equation of line

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