Given the image find the volume of this cone:
The volume of this cone =
\(\begin{gathered} V=\frac{\pi r^2h}{3} \\ where\pi\text{ = 3} \\ d=14 \\ r=\frac{d}{2}=\frac{14}{2}=7ft \\ h=4ft \end{gathered}\)radius = 7ft
height = 4ft
Volume of the cone =
\(\begin{gathered} V=\frac{3(7)^2(4)}{3} \\ V=49(4) \\ V=196ft^3 \end{gathered}\)
Therefore the volume of the cone = 196ft³
What is 30x2? Id love to know
Which of the following can \(\frac{sin^2x}{1+cosx}\) be simplified to? (2 points)
cos θ
1 + cos θ
1 − cos θ
sin θ + tan θ
The expression sin²x/(1+cosx) can be simplified to 1-cosθ
How to determine which of the expression sin²x/(1+cosx) can be simplified to?Trigonometry is a branch of mathematics dealing with the relationship between the ratios of the sides of a right-angled triangle with its angles.
Recall that sin²x = 1 - cos²x. Thus, we have:
sin²x/(1+cosx) = (1-cos²x) / (1+cosx)
= (1²-cos²x) / (1+cosx)
= (1+cosx)(1-cosx) / (1+cosx)
= 1-cosx
= 1-cosθ (If x = θ)
Note: Using difference of two squares, 1²-cos²x = (1+cosx)(1-cosx)
Therefore, the expression sin²x/(1+cosx) can be simplified to 1-cosθ
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how many times can 2 go into 67
fourth grade help
Answer:
Step-by-step explanation:
To answer this, divide 67 by 2, writing the answer as a mixed number:
67
---- = 33 1/2
2
thus, 2 can go into 67 33 times, keeping in mind that there's a remainder (1/2).
What is the solution for x in the equation?
1/2 - x + 3/2 = x - 4
The solution to the equation 1/2 - x + 3/2 = x - 4 is x = 3.
We have Equation 1/2 - x + 3/2 = x - 4
Now, solving the equation for x we get
/2 - x + 3/2 = x - 4
First, let's combine the like terms on both sides of the equation:
(1/2 + 3/2) - x = x - 4
4/2 - x = x - 4
2 - x = x - 4
Next, let's move the term with x to the left side by adding x to both sides:
2 - x + x = x - 4 + x
2 = 2x - 4
Then, let's move the constant term -4 to the right side by adding 4 to both sides:
2 + 4 = 2x - 4 + 4
6 = 2x
6/2 = 2x/2
3 = x
Therefore, the solution to the equation is x = 3.
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DO THE MATH: Skipper has a credit card account that charges 19% APR using 31
day billing periods. On the first day of the billing period, Skipper buys marine-grade
rope for $933 on the credit card. No other purchases are made. Skipper pays off the
purchase on day 31 at the end of the billing period. What is Skipper's finance
charge? Round your answer to the nearest penny.
Purchase
Day Description
1
Marine-grade rope
Payment
4
Amount
$933.00
Day Amount
31 $933.00
The table below will help you calculate the finance charge.
Skipper's finance charge at the end of the billing period is given as follows:
$14.77.
How to obtain the finance charge?The finance charge is obtained using simple interest, as there is a simple compounding per year for the debt, and the charge is the amount of interest accrued during the period of one month.
The amount of interest accrued after t years, using simple interest, is given as follows:
I(t) = Prt.
The parameters for the equation are given as follows:
P is the principal.r is the interest rate, as a decimal.t is the time, in years.Considering a period of one month = 1/12 of an year, the values of these parameters for this problem are given as follows:
P = 933, r = 0.19, t = 1/12.
Hence the finance charge for Skipper's purchase is calculated as follows:
I = 933 x 0.19 x 1/12 = $14.77.
(rounding to the nearest penny = nearest cent).
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write an algebraic equation for the followingn problem and then solve for it. Hilltop dormitory just purchased a new soft drink machine on sale for $480. The sale price was 75% of the original price. What was the original price of the soft drink machine?
Answer:
Step-by-step explanation:480 x o.75=360
and now you add this amount on payed
360 + 480=840 was original price
A man walks up 800m road AB which slopes at 10.2 to the horizon. He then walks 300m down road BC, which is at 6.3 to the horizon. The horizon is parallel to AD and BF perpendicular to AD. Find the length of CD
The length of CD is approximately 27.931 meters.
To find the length of CD, we can use the concept of similar triangles and trigonometric ratios.
Let's start by drawing a diagram to visualize the situation:
A----------B
/ /
/ /
/ /
D----------C
|
|
|
F
We are given that road AB slopes at 10.2 degrees to the horizon and road BC slopes at 6.3 degrees to the horizon. From the diagram, we can see that angle DAF is the same as the slope angle of road AB (10.2 degrees), and angle DCF is the same as the slope angle of road BC (6.3 degrees).
Now, we can set up the following trigonometric equations using the given information:
tan(10.2 degrees) = CD / AD (equation 1)
tan(6.3 degrees) = CD / BF (equation 2)
Since AD and BF are perpendicular, we can consider them as vertical heights. Let's calculate the lengths of AD and BF.
For road AB, we can use the definition of tangent:
tan(10.2 degrees) = height AB / length AB
Solving for the height AB, we have:
height AB = tan(10.2 degrees) * length AB
height AB = tan(10.2 degrees) * 800m
height AB ≈ 147.294m
Similarly, for road BC:
height BC = tan(6.3 degrees) * length BC
height BC = tan(6.3 degrees) * 300m
height BC ≈ 33.706m
Now, we can substitute these values into equations 1 and 2:
tan(10.2 degrees) = CD / 147.294m (equation 1)
tan(6.3 degrees) = CD / 33.706m (equation 2)
Solving equation 1 for CD:
CD = tan(10.2 degrees) * 147.294m
CD ≈ 27.931m
Therefore, the length of CD is approximately 27.931 meters.
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Mrs. Reynolds has $153. She buys a bicycle for $105.
Then, she finds $20 at the bottom of her purse.
How much money does she have now? Use the bar diagrams to help you.
Step 1:
Step 1: a bar diagram shows 105 and m, the money left after buying a bike. Together 105 and m are equal to 153.
Step 2:
Step 2: a bar diagram shows that 20 and m is equal to s, the money now.
Enter your answer in the box.
Mrs. Reynolds has $
now.
The total amounts of money which Mrs. Reynolds now has according to the descriptions in the task content is; $68.
How much does Mrs. Reynolds have now?It follows from the task content that;
Together 105 and m are equal to 153.20 and m is equal to s.On this note;
105 + m = 153m = 153 -105 = 48Hence, it follows that the amount of money, s she has now is;
s = 48 + 20 = $68Read more on addition and subtraction;
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Quadratic Equations:Solve the following quadratic equation using the quadratic formula: formula attached, picture -y^2 - 3 = -3y
We have the following equation:
\(-y^2-3=-3y\)by moving -3y to the left hand side, we have
\(-y^2+3y-3=0\)which is in the form
\(ay^2+by+c=0\)By comparing both equations, we can see that a=-1, b=3 and c=-3. By substituting these values in the quadratic formula, we get
\(y=\frac{-3\pm\sqrt[]{3^2-4(-1)(-3)}}{2(-1)}\)which gives
\(y=\frac{-3\pm\sqrt[]{9-12}}{-2}\)which leads to
\(y=\frac{-3\pm\sqrt[]{-3}}{-2}\)but
\(\begin{gathered} \sqrt[]{-3}=\sqrt{3}i \\ \text{where} \\ i=\sqrt[]{-1},\text{ the imaginary number} \end{gathered}\)Therefore, the solutions are:
\(\begin{gathered} y_1=\frac{-3+\sqrt[]{3i}}{-2} \\ \text{and} \\ y_2=\frac{-3-\sqrt[]{3}i}{-2} \end{gathered}\)This is Ratio math. In an office building, 66 offices are currently being rented. This represents 60% of the total units. How many offices are there in the building?There are ... offices in the building.
Let total number of units = x
As per the given data, 60% units constitutes 66 offices.
Hence,
\(0.6x=66\)Solving further for x we have,
\(\begin{gathered} x=\frac{66}{0.6} \\ =\frac{660}{6} \\ =110 \end{gathered}\)Thus, there are total number of 110 offices in a building.
Please help I’ll mark you as brainliest if correct!
Answer:
C
Step-by-step explanation:
Answer:
7/10 or 0.7
Step-by-step explanation:
first bag = 3/15
second bag 5/10
make them alike
first bag 3/30
second bag 15/30
add
18/30
simplify = 7/10
The number of exercises on Khan academy has increased rapidly since it began in 2006The relationship between the elapsed time, ttt, in years, since Khan academy began, and the total number of its exercises, E_{\text{year}}(t)E
year
(t)E, start subscript, start text, y, e, a, r, end text, end subscript, left parenthesis, t, right parenthesis, is modeled by the following function:
Eyear(t)=100⋅(1.7)t
Complete the following sentence about the monthly rate of change in the number of exercises.
Round your answer to two decimal places.
Every month, the number of exercises increases by a factor of
Answer:
1.05
Step-by-step explanation:
We start of with 100 * (1.7)^t
So the change in 100 is (1.7)^t(years). Well, that is in years, we need months. There are 12 months in a year, this is good to remember for several reasons ;). Since they ask for "Every month, the number of exercises increases by a factor of:", we must plug in 1/12 as t.
We can rewrite this as:
100 * (1.7)^1/12
Just plug the (1.7)^1/12 into a calculator, which is a cool device that can do boring math for you, and you should get 1.045... blah blah blah(a bunch of other useless numbers).
So now we have:
100*1.045
Well, the problem said "Round your answer to two decimal places."
So we need to round the 1.045.
5 is right in the middle, but if you know rounding, your probably know that the 5 goes up. So yay, your 1.045 is now 1.05.
So in the end, we get:
1.05
Ti⊂k∫∈s ω∅∅p :)
The number of exercises increases by a factor of approximately 14.17 each month.
To determine the monthly rate of change in the number of exercises, we need to find the factor by which the number of exercises increases each month.
The given function, Eyear(t) = 100 × \((1.7)^t\), represents the total number of exercises after t years. To convert this to a monthly rate, we need to divide the yearly rate by 12 (since there are 12 months in a year).
So, the monthly rate of change in the number of exercises is:
E_month(t) = Eyear(t)/12
Substituting the given function, we have:
Emonth(t) = 100 × \((1.7)^t\)/12
To find the factor by which the number of exercises increases each month, we can compare the value of E_month(t) at t = 1 to the value at t = 0:
E_month(1) = 100 × \((1.7)^t\)/12 = (100 × 1.7)/12 = 14.17
Therefore, the number of exercises increases by a factor of approximately 14.17 each month.
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What is the value of x
Answer:
28
Step-by-step explanation:
14x2=28
Therefore x=28
a. Consider the situation where you have three game chips, each labeled with one of the the numbers 3, 5, and 10 in a hat a. If you draw out 2 chips without replacement between each chip draw, list the entire sample space of po ssible results that can occur in the draw Use the three events are defined as follows, to answer parts b through n below:
Event A: the sum of the 2 drawn numbers is even.
Event B: the sum of the 2 drawn numbers is odd.
Event C: the sum of the 2 drawn numbers is a prime number
Now, using your answer to part a find the following probability values
b. P (A)=
c. P (B)=
d. P (C)=
e. P (A and C)-=
f. P(A or B)=
g. P (B andC)=
h. P(A or C)- =
i. P (C given B)=
j. P(C given A)=
k. P (not B)=
l. P (not C)=
Are events A and B mutually exclusive?Why or why not?
Are events B and C mutually exclusive? Why or why not?
Answer:
a) {3,5}{3,10}{5,10}
b) \(P(A)=\frac{1}{3}\)
c) \(P(B)=\frac{2}{3}\)
d) \(P(C)=\frac{1}{3}\)
e) \(P(A and C)=0\)
f) \(P(A or B)=1\)
g) \(P(B and C)=\frac{1}{3}\)
h) \(P(A or C)=\frac{2}{3}\)
i) \(P(C given B)=\frac{1}{2}\)
j) \(P(C given A)=0\)
k) \(P(not B)=\frac{1}{3}\)
l) \(P(not C)=\frac{2}{3}\)
Yes, events A and B are mutually exclusive. Because the results can either be even or odd, not both. No, events B and C are not mutually exclusive because the result can be both, odd and prime.
Step-by-step explanation:
a)
In order to solve part a of the problem, we need to find the possible outcomes, in this case, the possible outcomes are:
{3,5}{3,10} and {5,10}
We could think of the oppsite order, for example {5,3}{10,3}{10,5} but these are basically the same as the previous outcomes, so we will just take three outcomes in our sample space. We can think of it as drawing the two chips at the same time.
b)
Now the probability of the sum of the chips to be even. There is only one outcome where the sum of the chips is even, {3,5} since 3+5=8 the other outcomes will give us an odd number, so:
\(P=\frac{#desired}{#possible}\)
\(P(A)=\frac{1}{3}\)
c) For the probability of the sum of the chips to be odd, there are two outcomes where the sum of the chips is odd, {3,10} since 3+10=13 and {5,10} since 5+10=15 the other outcomes will give us an even number, so:
\(P(B)=\frac{2}{3}\)
d) The probability of the sum of the chips is prime. There is only one outcome where the sum of the chips is prime, {3,10} since 3+10=13 the other outcomes will give us non prime results, so:
\(P(C)=\frac{1}{3}\)
e) The probability of the sum of the chips to be even and prime. There are no results where we can get an even and prime number, since the only even and prime number there is is number 2 and no outcome will give us that number, so:
P(A and C)=0
f) The probability of the sum of the chips is even or odd. We can either get even or odd results, so no matter what outcome we get, we will get an odd or even result so:
\(P(A or B)=1\)
g) The probability of the sum of the chips is odd and prime. There is only one outcome where the sum of the chips is odd and prime, {3,10} since 3+10=13 the other outcomes will give us non prime results, so:
\(P(B and C)=\frac{1}{3}\)
h) The probability of the sum of the chips is even or prime. There are two outcomes where the sum of the chips is even or prime, {3,10} since 3+10=13 and {3,5} since 3+5=8 so:
\(P(A or C)=\frac{2}{3}\)
i) The probability of the sum of the chips is prime given that the sum of the chips is odd. There are two possible results where the sum of the chips is odd {3,10} and {5,10} and only one of those results is even, {3,10}, so
\(P(C given B)=\frac{1}{2}\)
j) The probability of the sum of the chips is prime given that the sum of the chips is even. There is only one possible even result: {3,5} but that result isn't prime, so
\(P(C given A)=0\)
k) The probability of the sum of the chips is not odd. There is only one outcome where the sum of the chips is not odd (even), {3,5} so:
\(P(not B)=\frac{1}{3}\)
l) The probability of the sum of the chips is not prime. There are two outcomes where the sum of the chips is not prime, {3,5} and {5,10} so:
\(P(not C)=\frac{2}{3}\)
Are events A and B mutually exclusive?
Yes, events A and B are mutually exclusive.
Why or why not?
Because the results can either be even or odd, not both.
Are events B and C mutually exclusive?
No, events B and C are not mutually exclusive.
Why or Why not?
Because the result can be both, odd and prime.
Abe digs a hole at a steady rate of (meaning negative) 1.2 feet every hour.
Consider ground level to be 0.
What value represents the elevation of the hole relative to ground level after digging for 2.5 hours?
Enter your answer in the box.
Simplify (1-√3) (1÷3+√3) leaving your answer in the form p+q√3
Answer:
\(1-\dfrac{2}{3}\sqrt{3}\)
Step-by-step explanation:
Maybe you want to simplify ...
\((1-\sqrt{3})\dfrac{1}{3+\sqrt{3}}\)
Multiply numerator and denominator by the 'conjugate' of the denominator:
\((1-\sqrt{3})\dfrac{1}{3+\sqrt{3}}\cdot\dfrac{3-\sqrt{3}}{3-\sqrt{3}}=\dfrac{(1-\sqrt{3})(3-\sqrt{3})}{9-3}=\dfrac{3-4\sqrt{3}+3}{6}\\\\\boxed{1-\dfrac{2}{3}\sqrt{3}}\)
Which number did
DennisMark and labor closest to five
Thank you for helping me
Answer:
4,8 is the answer
hope it helped
can you make me brianliest
What is the explicit formula for this sequence?
-5, -3,-1,1, 3, ...
A. an = (-5) + (n − 1)2
B. an = (-5) + (n - 1)(-2)
C. an = 5 + (n - 1)2
D. an = 2 + (n - 1)(-5)
Answer:
Step-by-step explanation:
A.-5+(n-1)*2 and n belong to 1 to ponitive infinity
∆RMQ ≅∆RMS by __________ congruence criterion
SAS
SSA
AAS
SSS
\( \huge \pink{ \underbrace { \overbrace { \ SAS}}}\)
Nancy wants to buy a sweater that is priced at $75. If the store is running a 60% off sale, what will be the
amount of the discount and the sale price of the sweater?
Answer:
$30.00
Step-by-step explanation:
The original price of the sweater is $75.00. The new sale price is the original price of 100% less 60% of the original price. That means the sales price is 40% of the original price.
You can do this 2 ways:
1. $75 x 60% or .60 = $45
$75-45 = $30
or
2. $75 x 40% or .40 = $30
a 8 1/2 foot board Is cut Into 2 1/2 foot lengths. how many sections will you have
Answer:
3 whole but 3.4 as a decimal
Step-by-step explanation:
Help math ASAP ASAP math
Answer:
y-7=-2/1 (x-1)
Step-by-step explanation:
Hope this helps!
A newspaper article is summarized: According to a new study, teachers may be more inclined to give higher grades to students, hoping to gain favor with the university administrators who grant tenure. The study examined the average grade and teaching evaluation in a large number of courses given in 1997 in order to investigate the effects of grade inflation on evaluations. " I am concerned with student evaluations because instruction has become a popularity contest for some teachers, " said Professor Smith, who recently completed the study. Results showed higher grades directly corresponded to a more positive evaluation. The last statement above means the study found that:_________.
a) Higher course grades are positively associated with teaching evaluation
b) Teaching evaluation is negatively associated with course grade
c) There was a perfect positive correlation between course grade and teaching evaluation
d) Each letter grade increase is associated with a 10% increase in positive evaluations for the professor.
A parabola can be drawn given a focus of
(-8,8) and a directrix of
x=−6. What can be said about the parabola
The parabοla is degenerate and it can be said that it is just a pοint.
What is parabοla ?A parabοla is a curve whοse equatiοn places a pοint οn it at a same distance frοm bοth a fixed pοint and a fixed line. The parabοla's fixed pοint is referred tο as the fοcus, and its fixed line is referred tο as the directrix.
The fixed pοint dοes nοt lie οn the fixed line, which is anοther crucial factοr tο remember. A parabοla is a lοcus οf any pοint that is equally distant frοm bοth the fοcus and directrix οf twο supplied pοints. The pοint where a parabοla makes its sharpest turn is knοwn as the vertex.
If a parabοlic functiοn has the shape οf a "," it has a maximum value; οtherwise, it has a minimum value.
If the fοcus οf a parabοla is given by (a,b) and the directrix is a hοrizοntal line given by y=c, then the equatiοn οf the parabοla is
\((y-b)^2=4a(x-a)-(b-c)^2.\)
In this case, the fοcus is (-8,8) and the directrix is x=-6, which is a vertical line.
Therefοre, the axis οf the parabοla is hοrizοntal, and the vertex is halfway between the fοcus and the directrix, which is (-1,8).
We can use the fοrmula abοve tο find the value οf a:
\((y-8)^2 = 4a(x+8)\)
Setting y=8 and x=-1 (the cοοrdinates οf the vertex),
we get:0 = 4a(-7)a=0
This means that the parabοla is actually a vertical line passing thrοugh the vertex (-1,8), with nο x-term.
Therefοre, the parabοla is degenerate and it can be said that it is just a pοint.
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The dot plot shows the prices (in dollars) of jeans. What are the most appropriate measures to describe the center and the variation? Find the measures you chose.
To describe the center of the data, we can use either the mean or the median.
To describe the variation of the data, we can use either the range or the interquartile range (IQR).
Looking at the dot plot, it seems that the data is somewhat skewed to the right, with a few high-priced outliers. In this case, the median and the IQR may be more appropriate measures of the center and variation, respectively, as they are less sensitive to outliers.
To find the median and IQR:
Arrange the data in order from smallest to largest.
Find the median, which is the middle value. If there are an even number of values, take the average of the two middle values.
Find the first quartile, which is the median of the lower half of the data.
Find the third quartile, which is the median of the upper half of the data.
Calculate the IQR as the difference between the third quartile and the first quartile.
Here are the steps applied to the dot plot:
We can see that the smallest value is about 20 and the largest value is about 120, giving a range of 100 dollars.
The median is approximately 60 dollars, as it is the middle value between the 11th and 12th data points when the data is arranged in order.
The first quartile is approximately 40 dollars, as it isthe median of the lower half of the data points, which are found below the median.
The third quartile is approximately 80 dollars, as it is the median of the upper half of the data points, which are found above the median.
The IQR can be calculated as the difference between the third quartile and the first quartile, which is approximately 40 dollars.
Therefore, the most appropriate measures to describe the center and the variation for this data set are the median and the interquartile range (IQR), respectively. The median is approximately 60 dollars, and the IQR is approximately 40 dollars.
please help it’s due tomorrow
[x + y = -4
[x - y = 2
Answer:
which one substitution or elimination
Step-by-step explanation:
Substitution: (-1,-3 )
Elimination: (-1,-3)
i hope this helps you :)
Please mark me brainlest
please solve these. i need help please.
worth 30 points.
Answer:
1- 27
2- 36
3- -200
this is the answer
4.2 x 10^8 is how many times the value of 2.1 x 10^2
A. 2 x 10^4
B. 2 x 10^6
C. 2.1 x 10^6
D. 2.1 x 10^4
4.2 x 10^8 is 2*10^6 times the value of 2.1 x 10^2 when division is performed.
How can the number of times can be calculated?The concept that will be used to solve the question is division operation.
We were given 4.2 x 10^8 which is greater than 2.1 x 10^2
The operation can be expressed as :
4.2 x 10^8 =( n *2.1 x 10^2)
where n = the number of times that 4.2 x 10^8 is greater than 2.1 x 10^2
Then make n the subject of the formular which is
n = 4.2 x 10^8/2.1 x 10^2
n = 2*10^6
Therefore, the values of 4.2 x 10^8 is greater than 2.1 x 10^2 in 2*10^6 times.
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The selling price p of an item is 1000 - 0.02x birr, where x is the number of items produced perday.If the cost of producing and selling x items is 40x+15000 birr perday.How many items should be produced and sold everyday in order to maximize the profit?
Which values of x are solutions of the inequality?
8 + 3x < 5x - 10
x=0
x=4
x= 9
x= 15
Answer:
\(x=15\)
Explanation:
Solving the inequality for x would give you \(x>9\), therefore, \(x=15\) would be the only option. While you might think \(x=9\) should also be a solution, it would only be one if \(x\geq 9\).
Hope this helps! :)