For his phone service, Tony pays a monthly fee of $17, and he pays an additional $0.07 per minute of use. The least he has been charged in a month is$114.58.What are the possible numbers of minutes he has used his phone in a month?Use m for the number of minutes, and solve your inequality for m.

The standard deviation of the sample, using the sample standard deviation (ox), is approximately 1.98.

Based on the provided calculator output, we have the following information for a sample:

x = 6.25 (mean)

Ex = 50 (sum of all data points)

Ex² = 344 (sum of the squares of all data points)

Sx = 2.121320344 (standard deviation)

ox = 1.984313483 (sample standard deviation)

n = 8 (sample size)

To calculate the mean, we divide the sum of all data points (Ex) by the sample size (n):

Mean = Ex / n = 50 / 8 = 6.25

Therefore, the mean of the sample is 6.25.

To calculate the standard deviation, we have two options: Sx or ox. Both represent measures of dispersion.

Sx is the population standard deviation, while ox is the sample standard deviation.

If we use the sample standard deviation (ox), then the standard deviation is:

Standard Deviation = ox = 1.984313483 (rounded to the nearest hundredth)

Therefore, the standard deviation of the sample, using the sample standard deviation (ox), is approximately 1.98.

It's important to note that the values provided are rounded to the nearest hundredth as specified in the instructions.

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Answer:

a

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

I might be wrong but i'm pretty sure it's right

Given the following formula, w=x-y/2 -z. The value of y is y = x - 2w + wz .

Usually, simplification involves proceeding with the pending operations in the expression.

Like, 5 + 2 is an expression whose simplified form can be obtained by doing the pending addition, which results in 7 as its simplified form.

Simplification usually involves making the expression simple and easy to use later.

Given the following formula,

w=x-y/2 -z

We need to solve for y.

\(w = \dfrac{x-y}{2 -z}\)

By cross multiplication

\(w\times (2 -z)= {x-y}\\\\2w - wz = x - y\)

subtract x both side

2w - wz -x = x - y -x

y = x - 2w + wz

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Answer: 4 pages

Step-by-step explanation:

To solve this problem, we need to use the formula:

Rate = Output/Time

Let's use "p" to represent the number of pages Ethan can type and "t" to represent the time he has before the meeting starts.

Rate = 2 pages/(1/8 hour) = 16 pages/hour

Since the meeting starts 3/4 hour later than the scheduled time, Ethan has t = 1 - 3/4 = 1/4 hour to type pages before the meeting starts.

Output = Rate * Timep = (16 pages/hour) * (1/4 hour) = 4 pages

Therefore, Ethan can type 4 pages before the meeting starts.

Answer: 4 pages

Answer:

\(a_5\) = 405

Step-by-step explanation:

Substitute value of a1 into equation to find a2.  Then found value of a2 to find a3 and so on.  Please refer to attached workings for full step-by-step.

Answer:

its a such a hard questions i think you should ask to you're teacher ?

Answer:

B

Step-by-step explanation:

both 1 and 2 .

both plane EBF and ACG can be coplaner.

thanks :)

Andre borrowed 350,000 from the bank and the bank will charge him 6% interest per month. To calculate the amount he has to pay for one month of interest, we can use the following formula:

Interest = Capital * Interest rate

In this case, the capital is 350,000 and the interest rate is 6%. So, we can plug in the values:

Interest = 350,000 * 0.06

Interest = 21,000

Therefore, Andre has to pay 21,000 for one month of interest.

The two values of y after factorizing the given quadratic equation are 0, -0.5

The given equation is quadratic as the order of the equation is 2. In a quadratic equation with a single variable, the variable will have two different values which satisfy the equation. These values of the variable can be real and different, real and equal, or imaginary.

So, there will be two values of y.

Consider the given equation,

10y^2 + 12y = 7y

10y^2 +12y - 7y = 0

10y^2 + 5y = 0

Since the coefficients of y and y^2 are both multiples of 5,

5*(2y^2 + y) = 0

2y^2 + y = 0

Taking y as a common factor,

y*(2y+1) = 0

Now, we get two cases,

y = 0 or 2y + 1 = 0 => y = -(1/2) = -0.5

Therefore, y = 0 or y = -0.5

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Answer:

52 min

Step-by-step explanation:

Answer:

Step-by-step explanation:

84

️️️️

Answer: The sum of 3 angles in a triangle always is 180º, the answer is B

Step-by-step explanation:

You see, the small triangle?

The sum of 3 angles is 180º, and we know 2 angles is 70º and 30º, so the left angle is equal to 180º-70º-30º=80º

Now, you look at the biggest triangle we have.

We have the top angle, is 80º that we found before, so a+b=180º-80º=100º

Answer:

B) 100

Step-by-step explanation:

The sum of the interior angles of a triangle add up to 180°.  The small triangle on the top has two known angles: 70 and 30.  If you add that together, you get 100, that means that the top angle must be 80 because 70 + 30 + 80 = 180.

Now look at the large triangle, the sum of the interior angles must add up to 180.  We know that the top angle of the triangle is 80.  We just figured that out.  Then a + b must be 100, because 80 + 100 = 180.

Helping in the name of Jesus.

\(\bold{\huge{\underline{\pink{ Solution }}}}\)

Yes, The rectangle 1 and rectangle 2 are similar .

Let's Understand the above theorem :-

The dimensions of rectangle 1 are x and y

Now,

Let assume the value of K be 5

Therefore,

The dimensions of rectangle 2 are

\(\sf{ 5x \:and \:5y }\)

Now, The ratios of dimensions of both the rectangle :-

\(\bold{\dfrac{ x }{y}}{\bold{ = }}{\bold{\dfrac{5x}{5y}}}\)

\(\bold{\blue{\dfrac{ x }{y}}}{\bold{\blue{ = }}}{\bold{\blue{\dfrac{x}{y}}}}\)

From above,

We can conclude that the ratios of both the rectangles are same

Hence , Both the rectangles are similar

Here,

We have to proof that, the

In the previous questions, we have assume the value of k = 5

According to the question,

Perimeter of rectangle 1

\(\sf{ = 2( length + Breath) }\)

\(\bold{\pink{= 2( x + y ) }}\)

Thus, The perimeter of rectangle 1

Perimeter of rectangle 2

\(\sf{ = 2( length + Breath) }\)

\(\sf{ = 2(5x + 5y) }\)

\(\sf{ = 2 × 5( x + y) }\)

\(\bold{\pink{= 10(x + y) }}\)

Thus, The perimeter of rectangle 2

According to the given condition :-

Subsitute the required values,

\(\sf{ 2(x + y) = 10(x + y)}\)

\(\bold{\pink{2x + 2y = 5(2x + 2y) }}\)

From Above,

We can conclude that the, Perimeter of rectangle 2 is 5 times of perimeter of rectangle 1 and we assume the value of k = 5.

Hence, The perimeter of rectangle 2 is k times of rectangle 1

Here,

We have to proof that ,

That is,

According to the question,

Area of rectangle 1

\(\sf{ = Length × Breath }\)

\(\sf{ = x × y }\)

\(\bold{\red{= xy }}\)

Area of rectangle 2

\(\sf{ = Length × Breath }\)

\(\sf{ = 5x × 5y }\)

\(\bold{\red{ = 25xy }}\)

According to the given condition :-

\(\sf{ xy = 25xy }\)

\(\bold{\red{xy = (5)²xy }}\)

From Above,

We can conclude that the, Area of rectangle 2 is (5)² times of area of rectangle 1 and we have assumed the value of k = 5

Hence, The Area of rectangle 2 is k times of rectangle 1 .

Answer:

there are 34 green marbles

there are 91 total marbles

Step-by-step explanation:

57 - 23 = 34

57 + 34 = 91

Answer:

pythagoren therom, law of sine, cosine, and tangent

Step-by-step explanation:

The negations of the given statements with the application of De Morgan's law and/or conditional law.

a) ∃x (¬P(x) ∨ ¬R(x))

De Morgan's law:

∃y ∀z(¬P(y) ∧ ¬Q(z))

b) ∃y ∀z(¬P(y) ∧ ¬Q(z))

The double negation:

∃y ¬∃z(P(y) ∨ Q(z))

c) ¬∃x (P(x) ∨ (∀z (¬R(z)) → (∀z ¬Q(z))))

The conditional law:

¬∃x (P(x) ∨ (∀z (¬R(z)) → (∀z ¬Q(z))))

Let's form the negation of the given statements and apply De Morgan's law and/or conditional law, when applicable:

a) ∀x (P(x) ∧ R(x))

The negation of this statement is:

∃x ¬(P(x) ∧ R(x))

Now let's apply De Morgan's law:

∃x (¬P(x) ∨ ¬R(x))

b) ∀y∃z(¬P(y) → Q(z))

The negation of this statement is:

∃y ¬∃z(¬P(y) → Q(z))

Using the conditional law, we can rewrite the negation as:

∃y ¬∃z(¬¬P(y) ∨ Q(z))

c) ∃x (P(x) ∨ (∀z (¬R(z) → ¬Q(z))))

The negation of this statement is:

¬∃x (P(x) ∨ (∀z (¬R(z) → ¬Q(z))))

Using the conditional law, we can rewrite the negation as:

¬∃x (P(x) ∨ (∀z (R(z) ∨ ¬Q(z))))

Applying De Morgan's law:

¬∃x (P(x) ∨ (∀z ¬(¬R(z) ∧ Q(z))))

Simplifying the double negation:

¬∃x (P(x) ∨ (∀z ¬(R(z) ∧ Q(z))))

Using De Morgan's law again:

¬∃x (P(x) ∨ (∀z (¬R(z) ∨ ¬Q(z))))

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Answer:

The answer to that question will be A

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

6x3=18

(hope this helps can i plz have brainlist :D hehe)

Answer:

18

Step-by-step explanation:

lol....................

Answer:

11.4

Step-by-step explanation:

a. If x is the number of copies Elsa sells and y represents her total pay, then, to determine her pay when she sells zero copies, let's replace "x" with zero in the provided equation and solve for y.

Therefore, Elsa receives a total pay of $1,700 only if she doesn't sell any copies of English is Fun.

b. On the other hand, if Elsa sells a copy of English is Fun, let's say 1 copy, we can replace "x" with "1" and see how much her total pay is.

Elsa receives a total pay of $1,790 if she can sell 1 copy of English is Fun.

Therefore, an additional $90 is given to Elsa whenever she sells a copy of English is fun. An increase of $90 is the change in Elsa's total pay for each copy of English is Fun she sells.

Answer:

1) c

2) c

3) c

4) c

Step-by-step explanation:

Answer:

Here is the solution

Step-by-step explanation:

9(p-4)=3(2p+6)

9p-36=6p+18

9p-6p-36=18

9p-6p=18+36

3p=54

p=54÷3

p=18

Answer:

  -3, 0, 5

Step-by-step explanation:

You want the zeros of P(x) = x³ − 2x² − 15x using the factored form.

We notice right away that x is a factor of every term. Factoring that out gives us a quadratic to factor:

  P(x) = x(x² -2x -15)

To factor this, we need two factors of -15 that have a sum of -2. The factors -5 and +3 have those properties. That means our factored form is ...

  P(x) = x(x +3)(x -5) . . . . factored form

This product will be zero when any of its factors is zero. Considering them one at a time, we find the zeros of P(x) to be ...

  x = 0

  x +3 = 0   ⇒   x = -3

  x -5 = 0   ⇒   x = 5

The zeros of P(x) are -3, 0, 5.

Answer:

1213/25

Step-by-step explanation: Convert to a mixed number by placing the numbers to the right of the decimal over 100. Reduce the fraction. Then, convert the mixed number to an improper fraction by multiplying the denominator by the whole number and adding the numerator to get the new numerator. Place this new numerator over the original denominator.

1213/25

Answer: 180 gallons needed

Step-by-step explanation:

Zykeith,

Assume x gallons of 50% antifreeze is needed

Final mixture is x + 60 gallons

Amount of antifreeze in mixture is 0.4*(x+60)

Amount of antifreeze added is .5x + .1*60 = .5x + 6

so .5x + 6 = .4(x + 60)

.5x -.4x = 24 -6

.1x = 18

x = 180

Let x be the number of gallons of the 50% antifreeze solution needed. We know that the resulting mixture will be 70 + x gallons. To get a 40% antifreeze mixture, we can set up the following equation:

\({\implies 0.5x + 0.1(70) = 0.4(70 + x)}\)

Simplifying the equation:

\(\qquad\implies 0.5x + 7 = 28 + 0.4x\)

\(\qquad\quad\implies 0.1x = 21\)

\(\qquad\qquad\implies \bold{x = 210}\)

\(\therefore\) We need 210 gallons of the 50% antifreeze solution to mix with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze.

\(\blue{\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}\)

The correct function to approximate the number of bees in the hive after x years is,

⇒ y (x) = 8928.57 (1.12)ˣ

Since, We have to given that;

Ellie is the agricultural manager of Apple a Day Orchards.

And, boost pollination, she puts a beehive with about 10,000 bees on the property.

Since, She expects the bee population to increase by 12% each year.

Hence, We can formulate;

the number of bees in the hive after x years is,

⇒ y (x) = 10,000 (1 + 0.12)ˣ⁻¹

⇒ y (x) = 10,000 (1.12)ˣ⁻¹

⇒ y (x) = 10,000 (1.12)ˣ / 1.12

⇒ y (x) = 8928.57 (1.12)ˣ

Thus, The correct function to approximate the number of bees in the hive after x years is,

⇒ y (x) = 8928.57 (1.12)ˣ

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The graph that shows the following system of equations and its solution is graph number C

A graph is the graphical representation of equations on a graph sheet

The given equations are

-4x-3y=4

4x-y=-4 Solving the equations

In equation 1

When x = 0

-3y = 4

y=-4/3                  (0, -4/3)

When y = 0

-4x = 4

x= -1            (-1, 0)

In equation 2 when x = 0

-y = -y = 4             (0, 4)

When y = 0

4x=-4 x=-1              (-1, 0)

When these coordinates are used to plot the graph, graph number is is obtained.

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The average is 40 and  the margin of error is 10.95.

What is margin of error?

The margin of error is a statistic expressing the amount of random sampling in the result of a survey.

Average (A) = sum of all the value/ given set.

A = (51+ 41 + 28)/3 = 40

margin of error = 100/square root of 120 = 10.95.

Therefore, the average is 40 and  the margin of error is 10.95.

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Answer:

Yes, the new equipment appear to be effective in reducing the variation of​ weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new​ equipment, and this sample has a standard deviation of 0.047.

Let \(\sigma\) = standard deviation of weights of new equipment.

SO, Null Hypothesis, \(H_0\) : \(\sigma \geq\) 0.065      {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, \(H_A\) : \(\sigma\) < 0.065      {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here One-sample chi-square test statistics;

                           T.S. =  \(\frac{(n-1)s^{2} }{\sigma^{2} }\)  ~ \(\chi^{2}__n_-_1\)

where, s = sample standard deviation = 0.047

           n = sample of quarters = 25

So, the test statistics  =  \(\frac{(25-1)\times 0.047^{2} }{0.065^{2} }\)  ~  \(\chi^{2}__2_4\)   

                                     =  12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.