Answer:
StartFraction 15 x cubed + 25 x squared + 5 x + 2 Over (5 x squared + 1) squared EndFraction, can be written in mathematical form as
Let y = \(\frac{15 x^3 + 25x^2 +5x+2}{({5x^2+1})^2}\)
on expanding \({({5x^2+1})^2 = 25x^4 +1 + 10x^2\)
⇒ y = \(\frac{15 x^3 + 25x^2 +5x+2}{25x^4 +1 + 10x^2}\)
there correct form of partial fraction is \(\frac{15 x^3 + 25x^2 +5x+2}{25x^4 +1 + 10x^2}\)
Answer:
Option-B
Step-by-step explanation:
edge
find the product:42(100,000)
Answer:
4200000
Step-by-step explanation:
Answer:
4,200,000
Step-by-step explanation:
All real numbers that are greater than or equal to -4 and less than 2.
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The set of all first degree polynomial functions ax+b, a not equal to zero, whose graphs pass through the origin with the standard operations is not a vector space. State all of the axioms that fail and give a counterexample for each.
The closure under scalar multiplication axiom fails.
For example, let f(x) = x be a member of the set. Then, 2f(x) = 2x should also be a member of the set. However, 2f(x) does not pass through the origin since f(x) passes through the origin at (0,0) but 2f(x) passes through the origin at (0,1).
The closure under addition axiom fails. For example, let f(x) = x and g(x) = -x be members of the set. Then, f(x) + g(x) = x - x = 0 should also be a member of the set. However, this function does not pass through the origin since it is constantly 0 and does not have any x-intercepts.
The additive inverse axiom fails. For example, let f(x) = x be a member of the set. Then, -f(x) = -x should also be a member of the set. However, -f(x) does not pass through the origin since f(x) passes through the origin at (0,0) but -f(x) passes through the origin at (0,-1).
The set of all first degree polynomial functions with standard operations is not a vector space because it does not satisfy the closure under scalar multiplication, closure under addition, and additive inverse axioms.
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Does an X or y-axis scale have to always start at zero?.
No, X or y-axis scale does not have to always start at zero. In a line chart, it's OK to start the axis at a number other than zero
Define axis.A line that is used to take or mark measurements is known as an axis in mathematics. Two crucial axes of the coordinate plane are the x and y axes. A horizontal number line is the x-axis, while a vertical number line is the y-axis. The coordinate plane is created by the perpendicular intersection of these two axes.
Given,
No, X or y-axis scale does not have to always start at zero.
A line chart encodes data using location (x, y coordinates), whereas a bar chart represents data using length. In a line chart, it's OK to start the axis at a number other than zero despite many claims that they are always misleading since this minute difference influences how a reader utilizes the chart.
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There are four students named A,B,C, and D. All four of them are loss averse over money, with the same value function for money: v(x dollars )={√x x ≥ 0
{-2√-x x < 0
All three of them are also loss averse over mugs, with the same value function for mugs:
v(y mugs)={3y y ≥ 0
{4y y < 0
Total utility is the sum of the gain/loss utility for mugs and the gain/loss utility for money. The reference point is the status quo, that is, a person's initial endowment. Student A owns a mug and is willing to sell it for a price of a dollars or more. Student B does not own a mug and is willing to pay up to b dollars for buying it. Student C does not own a mug and is indifferent between getting a mug and getting c dollars. Student D is indifferent between losing a mug and losing d dollars.
1. Solve for a,b,c, and d.
2. Instead, suppose A, B, C, and D are only loss averse over mugs, but not over money. That is, their value function for money is instead:
v(x dollars)={√x x ≥ 0
{-√-x x < 0
and their value function for mugs remains:
v(y mugs)={3y y ≥ 0
{4y y < 0
Solve for a,b,c, and d.
3. Instead, suppose A,B,C, and D are not loss averse:
v(x dollars)={√x x ≥ 0
{-√-x x < 0
and v(y mugs)=3y
Solve for a,b,c, and d.
4. Suppose A, B, C, and D are not loss averse (as in the previous question), but their value for a mug varies with ownership. Specifically, the value of the mug is 3 for someone who does not currently own the mug, and 4 for someone who currently owns a mug. Solve for a,b,c, and d.
As per the question, All four students A, B, C, and D are loss-averse over money and have the same value function as below:v(x dollars)={√x x ≥ 0 {-2√-x x < 0They are also loss averse over mugs and have the same value function.
v(y mugs)={3y y ≥ 0
{4y y < 0
Now, we have to find the values of a, b, c and d as below:
- Student A owns a mug and is willing to sell it for a price of a dollars or more. i.e v(a) = v(0) + v(a-A), where A is the initial endowment of A. According to the given function, v(0) = 0, v(a-A) = 3, and v(A) = 4.
So, a ≥ A+3/2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. i.e v(B-b) = v(B) - v(0), where B is the initial endowment of B. According to the given function, v(0) = 0, v(B-b) = -4, and v(B) = -3.
So, b ≤ B+1/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. i.e v(c) = v(0) + v(c), where C is the initial endowment of C. According to the given function, v(0) = 0, v(c) = 3.
So, c = C/2
- Student D is indifferent between losing a mug and losing d dollars. i.e v(D-d) = v(D) - v(0), where D is the initial endowment of D. According to the given function, v(0) = 0, v(D-d) = -3.
So, d = D/2
2) In this case, value function for money changes to:v(x dollars)={√x x ≥ 0
{-√-x x < 0
However, the value function for mugs remains the same:v(y mugs)={3y y ≥ 0
{4y y < 0
Therefore, values for a, b, c, and d will remain the same as calculated in part (1).
3) In this case, students are not loss-averse. Value function for money:v(x dollars)={√x x ≥ 0
{-√-x x < 0
Value function for mugs:v(y mugs)={3y y ≥ 0
The reference point is the status quo, i.e initial endowment. So,
- Student A owns a mug and is willing to sell it for a price of a dollars or more. The value of mug for A is 3 initially and he would sell it for 3 or more.
So, a ≥ A+3/2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. The value of mug for B is 3 initially and he would buy it for 3 or less.
So, b ≤ B+3/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. The value of the mug for C is 3 initially.
So, c = 3
- Student D is indifferent between losing a mug and losing d dollars. The value of the mug for D is 3 initially.
So, d = 3
4) In this case, value function for money:v(x dollars)={√x x ≥ 0
{-√-x x < 0
Value function for mugs: Mug will have a value of 4 for someone who owns it and 3 for someone who does not own it.
The reference point is the status quo, i.e initial endowment. So,
- Student A owns a mug and is willing to sell it for a price of a dollars or more. The value of mug for A is 4 initially and he would sell it for 4 or more.
So, a ≥ A+2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. The value of mug for B is 3 initially and he would buy it for 3 or less.
So, b ≤ B+3/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. The value of the mug for C is 3 initially and he would like to buy it for 3.
So, c = 3
- Student D is indifferent between losing a mug and losing d dollars. The value of the mug for D is 3 initially.
So, d = 3.
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assume that y varies inversely with x. if y = 8 when x = 1.55, find x when y = -0.62
Answer:
y varies inversely with x is written as
y = k /x
where k is the constant of variation
y = 8 x = 1.55
8 = k / 1.55
Multiply through by 1.55
k = 12.4
The formula is
y = 12.4 / x
when y = - 0.62
- 0.62 = 12.4/x
- 0.62x = 12.4
Divide both sides by - 0.62
x = 12.4/-0.62
x = - 20
When y = - 0.62 x = - 20
Hope this helps
find the conditional probability of the indicated event when two fair dice (one red and one green) are rolled. hint [see example 1.] the sum is 4, given that the green one is either 3 or 2.
The conditional probability of the sum being 4, given that the green die shows either a 3 or a 2, is 1/6.
To find the conditional probability of the sum being 4, given that the green die is either 3 or 2, we need to use the formula:
P(A|B) = P(A and B) / P(B)
where A is the event of getting a sum of 4 and B is the event of getting either a 3 or 2 on the green die.
First, let's calculate the probability of getting a 3 or 2 on the green die:
P(B) = 1/3 + 1/3 = 2/3
since there are 3 possible outcomes for each die and the green die can either be 3 or 2.
Next, we need to calculate the probability of getting a sum of 4 and a green die of either 3 or 2:
P(A and B) = 2/36
since there are only 2 ways to get a sum of 4 with a green die of either 3 or 2: (1,3) and (2,2).
Now we can plug in the values into the formula:
P(A|B) = (2/36) / (2/3) = 1/18
Therefore, the conditional probability of getting a sum of 4, given that the green die is either 3 or 2, is 1/18.
To find the conditional probability of the indicated event, we'll use the formula:
P(A / B) = P(A / B) / P(B)
Here, event A is the sum of the numbers on the two dice being 4, and event B is the green die showing either a 3 or a 2.
First, let's find P(B). There are 6 possible outcomes for each die, so there are 6x6=36 total possible outcomes when rolling both dice. There are 2 favorable outcomes for event B: the green die showing a 3 or a 2. Therefore, P(B) = 2/6 = 1/3.
Now, let's find P(A / B). This is the probability of both events A and B happening at the same time. For the sum to be 4 and the green die to show a 2, the red die must show a 2. For the sum to be 4 and the green die to show a 3, the red die must show a 1. There are 2 favorable outcomes for P(A /B) out of the 36 possible outcomes. Therefore, P(A ∩ B) = 2/36 = 1/18.
Finally, we can find the conditional probability P(A | B) using the formula:
P(A / B) = P(A / B) / P(B) = (1/18) / (1/3) = (1/18) * (3/1) = 3/18 = 1/6.
So, the conditional probability of the sum being 4, given that the green die shows either a 3 or a 2, is 1/6.
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Given the following sections: 1 Hour, 33 Minutes, 19 Seconds Station 2+020 Station 2+080 Base for cut =12 m, Sideslope for cut = 1.5:1 Base for fill =12 m, Sideslope for fill = 2:1 Required: 1. What is the stationing of the end of excavation? 2. Find the volume of fill by end area method. 3. Compute the volume of excavation by end area.
The stationing of the end of the excavation is Station 2+080.
The volume of fill by end area method is 1440 cubic meters.
The volume of excavation by end area is 1080 cubic meters.
We have,
The stationing of the end of excavation can be determined by adding the given sections to the starting station.
Assuming the starting station is Station 2+020, the end of excavation would be at Station 2+080 (given as Station 2+020 + 60 meters).
To find the volume of fill by end area method, we need to calculate the area of the end section and multiply it by the distance between the start and end stations.
Given that the base for fill is 12 meters and the sideslope for fill is 2:1, the area of the end section can be calculated as follows:
Area of end section = (Base for fill) * (Sideslope for fill)
Area of end section = 12 * (2/1) = 24 square meters
Now, multiply the area of the end section by the distance between the start and end stations (60 meters) to find the volume of fill:
Volume of fill = Area of end section * Distance
Volume of fill = 24 * 60 = 1440 cubic meters
Therefore, the volume of fill by end area method is 1440 cubic meters.
Similarly, to compute the volume of excavation by end area, we calculate the area of the end section (base for cut * sideslope for cut) and multiply it by the distance between the start and end stations. Given that the base for cut is 12 meters and the sideslope for cut is 1.5:1, the area of the end section can be calculated as follows:
Area of end section = (Base for cut) * (Sideslope for cut)
Area of end section = 12 * (1.5/1) = 18 square meters
Multiply the area of the end section by the distance between the start and end stations (60 meters) to find the volume of excavation:
Volume of excavation = Area of end section * Distance
Volume of excavation = 18 * 60 = 1080 cubic meters
Therefore, the volume of excavation by end area is 1080 cubic meters.
Thus,
The stationing of the end of the excavation is Station 2+080.
The volume of fill by end area method is 1440 cubic meters.
The volume of excavation by end area is 1080 cubic meters.
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What is the solution to this equation?
7x + 3 = 10x - 5.4
Answer:
\(x=2.8\)
Step-by-step explanation:
\(7x+3=10x-5.4\)
Subtract 3 from both sides:
\(7x+3-3=10x-5.4-3\)
\(7x=10x-8.4\)
Subtract 10x from both sides:
\(7x-10x=10x-8.4-10x\)
\(-3x=-8.4\)
Divide both sides by -3:
\(\frac{-3x}{-3}=\frac{-8.4}{-3}\)
\(x=2.8\)
Match the Definition with the Property.
Question 3 options:
Commutative Property
Symmetric Property
Transitive Property
Reflexive Property
Associative Property
1.
The order in which you add or multiply numbers does not affect the result.
2.
The way you group numbers when adding or multiplying does not affect the result.
3.
Any real number is equal to itself:
a = a
4.
Let's you switch the expressions on either side of an equation:
If a = b, then b = a
5.
If one real number is equal to a second real number, and the second real number is equal to a third real number, then the first real number must equal the third:
If a = b and b = c, then a = c
Answer:
Commutative Property
The way you group numbers when adding or multiplying does not affect the result.
Reflexive Property
he order in which you add or multiply numbers does not affect the result.
Step-by-step explanation:
Example 4 A closed box has a fixed surface area A and a square base with side x. (a) Find a formula for the volume, V. of the box as a function of x. What is the domain of V? (b) Graph V as a function of x. (c) Find the maximum value of V.
use the work in example 4 in this section of the textbook to find a formula for the volume of a box having surface area 10.
The volume of the box with surface area 10 is given by the formula V = 2.5x^2 - 0.25x^4, where x is the length of a side of the square base.
To find a formula for the volume of the box with surface area A and square base with side x, we first need to find the height of the box. Since the box has a square base, the area of the base is x^2. The remaining surface area is the sum of the areas of the four sides, each of which is a rectangle with base x and height h. Therefore, the surface area A is given by:
A = x^2 + 4xh
Solving for h, we get:
h = (A - x^2) / 4x
The volume V of the box is given by:
V = x^2 * h
Substituting the expression for h, we get:
V = x^2 * (A - x^2) / 4x
Simplifying, we get:
V = (Ax^2 - x^4) / 4
The domain of V is all non-negative real numbers, since both x^2 and A are non-negative.
To graph V as a function of x, we can use a graphing calculator or plot points using a table of values. The graph will be a parabola opening downwards, with x-intercepts at 0 and sqrt(A) and a maximum at x = sqrt(A) / sqrt(2).
To find the maximum value of V, we can take the derivative of V with respect to x and set it equal to 0:
dV/dx = (2Ax - 4x^3) / 4
Setting this equal to 0 and solving for x, we get:
x = sqrt(A) / sqrt(2)
Plugging this value of x into the formula for V, we get:
V = A^1.5 / (4sqrt(2))
Therefore, the maximum value of V is A^1.5 / (4sqrt(2)).
To find the formula for the volume of a box having surface area 10, we simply replace A with 10 in the formula we derived earlier:
V = (10x^2 - x^4) / 4
Simplifying, we get:
V = 2.5x^2 - 0.25x^4
Therefore, the volume of the box with surface area 10 is given by the formula V = 2.5x^2 - 0.25x^4, where x is the length of a side of the square base. The domain of V is all non-negative real numbers.
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Given: ∆MNP, PM = 8 m∠P = 90°, m∠N = 58° Find: Perimeter of ∆MNP
(Not 22.4 or 22.43)
Please answer ASAP, brainly awarded.
Answer:
Step-by-step explanation:
Triangle MNP is a right triangle with the following values:
m∠P = 90°m∠N = 58°PM = 8Interior angles of a triangle sum to 180°. Therefore:
m∠M + m∠N + m∠P = 180°
m∠M + 58° + 90° = 180°
m∠M + 148° = 180°
m∠M = 32°
To find the measures of sides MN and NP, use the Law of Sines:
\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)
Substitute the values into the formula:
\(\dfrac{MN}{\sin P}=\dfrac{NP}{\sin M}=\dfrac{PM}{\sin N}\)
\(\dfrac{MN}{\sin 90^{\circ}}=\dfrac{NP}{\sin 32^{\circ}}=\dfrac{8}{\sin 58^{\circ}}\)
Therefore:
\(MN=\dfrac{8\sin 90^{\circ}}{\sin 58^{\circ}}=9.43342722...\)
\(NP=\dfrac{8\sin 32^{\circ}}{\sin 58^{\circ}}=4.99895481...\)
To find the perimeter of triangle MNP, sum the lengths of the sides.
\(\begin{aligned}\textsf{Perimeter}&=MN+NP+PM\\&=9.43342722...+4.99895481...+8\\&=22.4323820...\\&=22.43\; \sf units\; (2\;d.p.)\end{aligned}\)
HBI inc. seeks to schedule manual labor for 18 new homes being constructed. Historical data leads HBI to apply a 92 % learning curve rate to the manual labor portions of the project. If the first home requires 3,500 manual labor hours to build, estimate the time required to build:
a. the 5th house
b. the 10th house
c. all 18 houses
d. What would the manual labor estimate be for all 18 of the HBI houses in the problem above if the learning curve rate is 1) 70% 2) 75% 3) 80%
Please use a excel spreadsheet and explain how you got your answers in the excel spreadsheet with what to do and how to do it.
Using a 92% learning curve rate, the estimated manual labor hours required to build the 5th house would be 1,034 hours, the 10th house would be 692 hours, and all 18 houses combined would require 3,046 hours. Additionally, if the learning curve rates are 70%, 75%, and 80%, the estimated manual labor hours for all 18 houses would be 5,177, 4,308, and 3,636 hours, respectively.
The learning curve formula is given by \(Y = a * X^b\), where Y represents the cumulative average time per unit, X represents the cumulative number of units produced, a is the time required to produce the first unit, and b is the learning curve exponent.
In this case, the learning curve rate is 92%, which means the learning curve exponent (b) is calculated as log(0.92) / log(2) ≈ -0.0833.
a. To estimate the time required to build the 5th house, we can use the learning curve formula:
\(Y = a * X^b\)
\(Y(5) = 3500 * 5 ^ (-0.0833)\)
Y(5) ≈ 1034 hours
b. Similarly, the time required to build the 10th house can be estimated:
\(Y(10) = 3500 * 10^(-0.0833)\)
Y(10) ≈ 692 hours
c. The cumulative time required to build all 18 houses can be estimated by summing the individual estimates for each house:
\(Y(18) = 3500 * 18^(-0.0833)\)
Y(18) ≈ 3046 hours
d. To calculate the manual labor estimates for all 18 houses using different learning curve rates, we can apply the respective learning curve exponents to the formula. The results are as follows:
- For a 70% learning curve rate: Y(18) ≈ 5177 hours
- For a 75% learning curve rate: Y(18) ≈ 4308 hours
- For an 80% learning curve rate: Y(18) ≈ 3636 hours
In conclusion, using the given learning curve rate of 92%, the estimated time required to build the 5th house is 1034 hours, the 10th house is 692 hours, and all 18 houses combined would require 3046 hours. Additionally, different learning curve rates yield different manual labor estimates for all 18 houses.
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find f ( a ) , f ( a h ) , and the difference quotient for the function given below, where h ≠ 0 . f ( x ) = 8 x − 9
The difference quotient for the function is 8.
The function is given by:
f ( x ) = 8 x − 9, where h ≠ 0
To find f(a), substitute a for x in the function. So we have:
f ( a ) = 8 a − 9
To find f(a + h), substitute a + h for x in the function. So we have:
f ( a + h ) = 8 ( a + h ) − 9
The difference quotient can be found using the formula:
(f(a + h) - f(a))/h
Substituting the values found above, we have:
(8 ( a + h ) − 9 - (8 a − 9))/h
Expanding the brackets and simplifying, we have:
((8a + 8h) - 9 - 8a + 9)/h
= 8h/h
= 8
Therefore, the difference quotient for the function is 8.
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17. The volleyball club is raising money for a
new net and equipment. They need $842.36 to
purchase the swing set and have received a
$300.00 donation. The remaining amount will
be equally divided among 4 different
fundraisers throughout the summer. How
much money will each fundraiser need to raise
in order to purchase the new net and
equipment?
$2,169.44
$542.36
0 $135.59
O $210.59
The money will each fundraiser need to raise in order to purchase the new net and equipment is $135.59. Therefore, option C is the correct answer.
Given that, the volleyball club need $842.36 to purchase the swing set and have received a $300.00 donation.
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
Let the money will each fundraiser need to raise in order to purchase the new net and equipment be x.
Now, the remaining amount = 842.36 - 300.00
= $542.36
The remaining amount will be equally divided among 4 different fundraisers = x = 542.36/4
=135.59
The money will each fundraiser need to raise in order to purchase the new net and equipment is $135.59. Therefore, option C is the correct answer.
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i’m losing my mind over this question :,) help asap would be amazing
find the length of c.
- 12sqrt3
- 16sqrt3
- 12sqrt6
- 16sqrt6
Answer:
I think it's either C or A
in a survey of 1004 individuals, 442 felt that keeping a pet is too much work. find a 95%confidence interval for the true proportion
Answer:
(0.407,0.471)
Step-by-step explanation:
To find the 95% confidence interval for the true proportion, we can use the following formula:
CI = p ± zsqrt((p(1-p))/n)
where:
p = sample proportion = 442/1004 = 0.4392
n = sample size = 1004
z = z-score corresponding to the desired confidence level (95% = 1.96)
Substituting the values, we get:
CI = 0.4392 ± 1.96sqrt((0.4392(1-0.4392))/1004)
CI = 0.4392 ± 0.032
Therefore, the 95% confidence interval for the true proportion of people who feel that keeping a pet is too much work is (0.407, 0.471).
What is the stem-and-leaf plot for 29,22,21,6,13,6,17,29,26,9,16,10,25,3,2,23,13,10,7,16,29,30,4,11,7,28,27,22,10
Answer:
I think thats it but im not for sure.
dave is 15 years old and his uncle rob is three times as old. when dave will be 32 years old, his uncle rob will be
By considering ages and equations we have,
Uncle Rob will be 62 years old when Dave is 32.
Dave is listed as being 15 years old, while his uncle Rob is listed as being three times Dave's age. Rob's age as of right now may be calculated using the formula below:
Age of Rob is Dave times three.
Using Dave's age as a plug-in, we obtain following equations,
Rob's age is equal to 15 + 3 = 45.
Rob is currently 45 years old, according to this.
We need to know how many years it will be before Dave turns 32 in order to calculate Rob's age at that time. By deducting Dave's present age from his anticipated age, we may determine this:
Years from now = Dave's age in the future minus Dave's age currently
By entering the specified values, we obtain:
The number of years from now is equal to 32 - 15 = 17 years.
Dave will turn 32 in 17 years, according to this.
We may multiply Rob's current age by the number of years from now to determine his age at that point:
When Dave reaches the age of 32, Rob will be that age plus the number of years.
When we enter the calculated values, we obtain:
When Dave is 32 years old, Rob will be 45 + 17 years old, or 62 years old.
So, Dave uncle rob 's age will be 62 years old.
As a result, when Dave's age is 32, his uncle Rob's age will be 62.
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before the electronic calculator became widely available, logarithms were used to carry out complicated calculations. true false
True, Logarithms were used extensively for complicated calculations before the electronic calculator became widely available. A logarithm is a mathematical function that helps simplify complex arithmetic operations by converting multiplication and division into addition and subtraction, respectively.
By using logarithms, complex calculations could be broken down into simpler steps and performed more easily. Logarithms were particularly useful in fields such as astronomy, physics, and engineering, where large numbers and complicated formulas were common. However, with the advent of electronic calculators, the use of logarithms for everyday calculations declined. Today, logarithms are still used in certain fields and for specific applications, but they are no longer the primary tool for carrying out complicated calculations.
Before the electronic calculator became widely available, logarithms were used to carry out complicated calculations. Logarithms simplified complex calculations by turning multiplication and division operations into addition and subtraction.
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9x-7i>3(3x-7u)I need the answer please
Step-by-step explanation:
9x-7i<3(3x-7u)=
9x-7i<9x-21u=
-7i<-21u=
i<3u
Use the law of cosines to find each missing side. Round to the nearest tenth
The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known. The value of x is 117.8°. thus, the correct option is A.
What is the Law of Cosine?The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. It is given by the formula,
\(Cos(\theta) = \dfrac{a^2+b^2-c^2}{2ab}\)
where
c is the third side of the triangle
a and b are the other two sides of the triangle,
and θ is the angle opposite to the third side, therefore, opposite to side c.
As per the law of cosine, the measure of angle x can be written as,
\(Cos(x) = \dfrac{12^2+5^2-15^2}{2(5)(12)}\\\\Cos(x) = \dfrac{-56}{120}\\\\x = 117.8^o\)
Hence, the value of x is 117.8°. thus, the correct option is A.
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The cost of fuel per litre is calculated using the following formula. (1 + 100) X + X 160 C = cost of oil per barrel. F = rate of fuel duty tax in %. P = percentage profit the petrol station wants to make. Fuel duty is 50%, and oil costs £128 per barrel. A petrol station wants to make 100% profit. Work out the cost of fuel per litre at this petrol station.
If a petrol station wants to make 100% profit. the cost of fuel per litre at this petrol station is 1.4 pence.
How to find the cost?Given, the formula to calculate the cost of fuel per litre:
(1 + 100) X + X 160 C = cost of oil per barrel.
Where :
X = cost of oil per litre
C= rate of fuel duty tax in %.
We know that fuel duty is 50% and oil costs £128 per barrel, so we can substitute these values into the equation:
(1 + 100) X + X 160 * 0.5 = 128
Expanding the equation:
100 X + 80 X = 128
180 X = 128
Dividing both sides by 180:
X = 128/180 = 7/10 = 0.7
So, the cost of oil per litre is 0.7 pence.
The petrol station wants to make 100% profit, so we add the profit to the cost of oil per litre:
0.7 + 0.7 * (100/100) = 1.4 pence
Therefore, the cost of fuel per litre at this petrol station is 1.4 pence.
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please help me with this its math!!
when entering units, capitalization is important. for example, m is the symbol for meter and m is the symbol for molarity. if the length of one side of a square is 12.0 m , what is the perimeter of the square?
The perimeter of the square is 40 meters.
The complete length that a square's edge in a plane covers is known as its perimeter. The route that encircles a form is called the perimeter.
By summing all the sides of a closed geometrical object (two-dimensional), the perimeter is determined. Since a square is a polygon with four equal sides, its perimeter will be equal to the sum of those sides.
Since all the sides of a square are equal, therefore, the perimeter of the square will be 4 times its side, i.e. 4 × Side. It is measured in units, such as m, cm, in, ft, etc.
Because a square has four sides of equal length, the perimeter is 12 m+12 m+12 m+12 m=48.0m
Thus, The perimeter of the square is 40 meters.
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Javier drinks 8 cups of water in one day.What is the unit rate of cups of water to days?
The unit rate here is also 8 cups of water per day.
We need to remember that in the unit rate we have as the denominator one unit of any quantity.
In this case, we have a day as the denominator one day, since:
\(\frac{8cupofwater}{1\text{day}}\)In summary, therefore, the unit rate, in this case, is 8 cups of water per day:
The probability that an individual is left-handed is 0.15. In a class of 93 students, what is the
probability of finding five left-handers?
A) 0.002 B) 0.000 C) 0.054 D) 0.15
The answer is (C) 0.054.
Regularly a binomial probability issue, where we are captivated by the probability of getting five left-handers in a course of 93 understudies, given that the probability of an individual being left-handed is 0.15.
The condition for the binomial probability spread is:
P(X = k) = (n select k) * \(p^k * (1 - p)^(n - k)\)
where:
P(X = k) is the likelihood of getting k triumphs (in our case, k left-handers)
n is the general number of trials (in our case, the degree of the lesson, 93)
p is the probability of triumph on each trial (in our case, the probability of an individual being left-handed, 0.15)
(n select k) is the binomial coefficient, which speaks to the number of ways of choosing k objects from a set of n objects.
Utilizing this condition, able to calculate the probability of finding five left-handers in a lesson of 93 understudies:
P(X = 5) = (93 select 5) * \(0.15^5 * (1 - 0.15)^(93 - 5)\)
P(X = 5) = 0.054
Consequently, the answer is (C) 0.054.
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6) Calculate the volume and surface area of the cuboid below:
Volume =
Surface area =
Answer:
what's that bottom number???
Answer:
Answer: 54
Step-by-step explanation:
3x2=6 6x9=54
Step 1:
3x2=6
Step 2:
get the 6 from last step and multiply it by 9
6x9=54 √
Arturo was comparing the price of apple juice at two stores. The equation y=0.29x represents what Arturo would pay in dollars and cents, y, for x bottles of apple juice at store A. Arturo can buy 13 bottles of apple juice at Store B for a total cost of $8.84. How much more is a bottle of apple juice at Store B than at Store A?
Answer:
$0.39
Step-by-step explanation:
First find the unit rate for store B ( $8.84/13)
At store B Artuto spends $0.68 for one bottle of apple juice
At store A they spent $0.29
0.68-0.29= 0.39
Just need answer x=
Answer:
\(at \: y = 20 \\ x = 20\)