F(x)=4x^2+4x-15 Write the function D in intercept form. Use this form to list the zeros of the function.

Answer:

128 <33

Step-by-step explanation:

6 ÷ 3 + 32 • 4 - 2 = 128

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Answer:

Only the second equation is an identity

Step-by-step explanation:

1)

\(1+\dfrac{\cos^2\theta}{\cot^2\theta(1-\sin^2\theta)}= \\\\\\1+\dfrac{\cos^2\theta}{\cot^2\theta(\cos^2\theta)}= \\\\\\1+\dfrac{1}{\cot^2 \theta}= \\\\\\1+\tan^2\theta=\sec^2\theta\neq 2\sec^2 \theta\)

This one is not an identity.

2)

\(19\cos \theta\left( \dfrac{1}{\cos \theta}-\dfrac{\tan \theta}{\csc \theta} \right)= \\\\\\19\cos \theta \left( \dfrac{1}{\cos \theta}-\dfrac{\sin^2 \theta}{\cos \theta} \right)= \\\\\\19\cos \theta \left( \dfrac{1-\sin^2 \theta}{\cos \theta}\right)= \\\\\\19\cos \theta \left( \dfrac{\cos^2 \theta}{\cos \theta}\right)= \\\\\\19\cos \theta (\cos \theta)= \\\\\\19\cos^2 \theta = 19\cos^2 \theta\)

This one is an identity. Therefore, only the second equation is an identity. Hope this helps!

Answer:

the person above me is right :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

X=59/95

Answer:

Step-by-step explanation:

slope=(6-2)/(1-4)=4/-3=-4/3

eq. of line is y-2=-4/3(x-4)

Answer: It would be 0.05%

Step-by-step explanation: To transform a number to a percentage of 100, simply divide said number by 100.

The probability of a Type II error is represented by beta. Thus, the correct answer is option B.

Beta represents the probability of failing to reject the null hypothesis when it is false.

On the other hand, Type I error (alpha) represents the probability of rejecting the null hypothesis when it is true. A Type II error occurs when a false null hypothesis is not rejected. Hence, beta is the probability of making a Type II error.

The null hypothesis is rejected when the p-value is less than or equal to the level of significance, not exceeds it.

The p-value is the probability of obtaining a result as extreme as or more extreme than the observed result when the null hypothesis is true. If the p-value is less than the level of significance, the null hypothesis is rejected, and vice versa.

Hence, the statement "The null hypothesis is rejected when the p-value exceeds the level of significance" is false.

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Answer:

The mean will be 22.436363636364.. or 22.4 (rounded to the nearest tenth)

you add them then divide by 22 since it has 22 terms, to find the mean

Answer:

use a calculator and add all values and divide by 22

u et final value as ( as per me not sure..maybe mistake) is

493.6/22 and ans Is 22.4363636364

Answer:

It's quite easy

Step-by-step explanation:

people less than 30 years = frequency of people 0 to 15 + 15 to 30 = 8+15 =23

Therefore there are 23 people less than 30 years old.

pls mark me as brainliest pls.

Answer: 2,306,973.7 rounded... 2,306,974

900,000(1+.04)^24

Answer:

They use collected data to recognize trends, predict outcomes, and plan for the future.

Step-by-step explanation:

The rate of change of the function that has a graph that passes

through the points (-1, 3) and (-2,-4) is slope and is equal to 7.

We have given two points  (-1, 3) and (-2,-4) .

Rate of change of graph is given by slope

Using slope formula , we get

      m = -4 - 3 / -2 - (-1)

      m = -7 / -2 + 1

      m = -7 / -1

       m = 7

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Answer:

18

Step-by-step explanation:

18

Answer:

\(\begin{array}{ccc}cause&accidents&frequency\\pilot\ error&581&0.253\\human\ error&56&0.024\\weather&579&0.252\\mechanical&555&0.242\\sabotage&526&0.229\end{array}\)

Pilot error, better training of pilots may reduce accidents.

Step-by-step explanation:

The total number of crashes is:

\(n = 581+56+579+555+526\\n=2297\ crashes\)

The relative frequency is given by the number of accidents caused by each factor divided by the total number of accidents. The relative frequency distribution is:

\(\begin{array}{ccc}cause&accidents&frequency\\pilot\ error&581&0.253\\human\ error&56&0.024\\weather&579&0.252\\mechanical&555&0.242\\sabotage&526&0.229\end{array}\)

The most serious threat to aviation​ safety is pilot error, a better training of current and future pilots could be a solution to reduce accidents.

Answer:

4b\(\sqrt{5}\)

Step-by-step explanation:

Factor 80\(b^{2}\).

80\(b^{2}\) = 4 * 4 * 5 * b * b

Since there are two 4s and bs, they can be taken out of the square. (Because if you put a square root over 4 squared or b squared, you would get 4 or b.)

Now you are left with 4b\(\sqrt{5}\).

Answer:

A

Step-by-step explanation:

The picture is how you solve it

Answer:

V =904.7786842 m^3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

The diameter is 12 so the radius is  d/2 = 12/2 = 6

V = 4/3 pi 6^3

V = 288 pi

Let pi = 3.14

V =904.32

If we use the pi button

V =904.7786842

Answer:

its G(2)

Step-by-step explanation:

Gg

\(m\angle E=\sin \dfrac{\sqrt{10}}{2\sqrt5}=\sin \dfrac{\sqrt2}{2}=45^{\circ}\)

Answer:what

Step-by-step explanation:what does this mean

Answer:

h = 11

Step-by-step explanation:

Sum of the angles in a Triangle = 180°, So;

\(83 + 39 + (6h - 8) = 180 \\ 122 - 8 + 6h = 180 \\ 114 + 6h = 180 \\ 6h = 180 - 114 \\ 6h = 66 \\ h = 66 \div 6 \\ h = 11\)

Answer:

see below

Step-by-step explanation:

\( \huge14 {x}^{ 5 } = 2 {x}^{3} . \boxed{7 {x}^{2} }\)

The answer of 1. The probability density function (PDF) of \(W = X^2\) when X has an exponential (1) PDF and 2. The X and Y are dependent random variables.

The PDF of \(W = X^2\), where X has an exponential (1) distribution, is given by \(\lambda e^{(-\lambda \sqrt w)} * 1/(2w^{(1/2)})\). X and Y are dependent random variables based on their joint PDF.

1. If X has an exponential (1) probability density function (PDF), we can find the PDF of \(W = X^2\) using the method of transformations.

Let's denote the PDF of X as fX(x). Since X has an exponential (1) distribution, its PDF is given by:

\(fX(x) = \lambda e^{(-\lambda x)}\)

where λ = 1 in this case.

To find the PDF of \(W = X^2\), we need to apply the transformation method. Let \(Y = g(X) = X^2\). The inverse transformation is given by X = h(Y) = √Y.

To find the PDF of W, we can use the formula:

fW(w) = fX(h(w)) * |dh(w)/dw|

Substituting the values:

fW(w) = fX(√w) * |d√w/dw|

Taking the derivative:

d√w/dw = 1/(2√w) = \(1/(2w^{(1/2)})\)

Substituting back into the equation:

\(fW(w) = fX(\sqrt w) * 1/(2w^{(1/2)})\)

Since fX(x) = \(\lambda e^{(-\lambda x)}\), we have:

fW(w) = \(\lambda e^{(-\lambda x)}\)  \(* 1/(2w^{(1/2))}\)

This is the probability density function (PDF) of \(W = X^2\) when X has an exponential (1) PDF.

2. To find the constant c for the joint probability density function (PDF) fx,y(x, y) = \(ce^{(-(x^2/8) - (4y^2/18))\), we need to satisfy the condition that the PDF integrates to 1 over the entire domain.

The condition for a PDF to integrate to 1 is:

∫∫ f(x, y) dx dy = 1

In this case, we have:

∫∫ \(ce^{(-(x^2/8) - (4y^2/18)) }dx dy = 1\)

To find the constant c, we need to evaluate this integral. However, the limits of integration are not provided, so we cannot determine the exact value of c without the specific limits.

Regarding the independence of X and Y, we can determine it by checking if the joint PDF fx,y(x, y) can be factored into the product of individual PDFs for X and Y.

If fx,y(x, y) = fx(x) * fy(y), then X and Y are independent random variables.

However, based on the given joint PDF fx,y(x, y) = \(ce^{(-(x^2/8) - (4y^2/18))\), we can see that it cannot be factored into separate functions of X and Y. Therefore, X and Y are dependent random variables.

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the base of the triangular window is 24 feet and the height is 10 feet.

Let's denote the height of the triangular window as h feet. According to the given information, the area of the window is 120 square feet.

The formula to calculate the area of a triangle is:

Area = (1/2) × base × height

In this case, we can write the equation as:

120 = (1/2) × base × h

Now, we are also given that the base of the window is 4 feet more than twice the height. So we can express the base as:

base = 2h + 4

Substituting this expression for the base into the area equation, we have:

120 = (1/2) × (2h + 4) × h

Now we can solve this equation for the height.

Multiplying both sides of the equation by 2 to remove the fraction:

240 = (2h + 4) × h

Expanding the right-hand side:

240 = 2h² + 4h

Rearranging the equation and setting it equal to zero:

2h² + 4h - 240 = 0

Now we can solve this quadratic equation. Factoring out a 2:

2(h² + 2h - 120) = 0

Factoring the quadratic expression inside the parentheses:

2(h + 12)(h - 10) = 0

Setting each factor equal to zero:

h + 12 = 0   or   h - 10 = 0

Solving these equations, we get:

h = -12   or   h = 10

Since height cannot be negative in this context, we discard the negative value. Therefore, the height of the triangular window is h = 10 feet.

Substituting the height value back into the expression for the base:

base = 2h + 4

    = 2(10) + 4

    = 20 + 4

    = 24

Therefore, the base of the triangular window is 24 feet and the height is 10 feet.

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Inverse distance weighting is a useful tool for estimating values at unsampled locations in geostatistics. Another advantage of inverse distance weighting is that it allows for the incorporation of multiple variables into the estimation process.

Inverse distance weighting is a method used in geostatistics to estimate values at unsampled locations based on values at surrounding sample locations. It works by assigning weights to the sample points based on their proximity to the unsampled point. The closer a sample point is to the unsampled point, the higher its weight. The weights are then used to calculate a weighted average of the sample values, which is used as the estimate for the unsampled location.
The benefit of inverse distance weighting over a simple average is that it takes into account the spatial variability of the data. A simple average treats all sample points equally, regardless of their distance from the unsampled point. This can lead to inaccurate estimates if there is a high degree of spatial variability in the data. In contrast, inverse distance weighting gives more weight to sample points that are closer to the unsampled point, which is likely to provide a more accurate estimate.
Another advantage of inverse distance weighting is that it allows for the incorporation of multiple variables into the estimation process. For example, if there are two variables of interest (e.g., temperature and precipitation), inverse distance weighting can be used to estimate values for both variables simultaneously. This is not possible with a simple average.
Overall, inverse distance weighting is a useful tool for estimating values at unsampled locations in geostatistics. Its ability to account for spatial variability and incorporate multiple variables makes it a powerful technique for analyzing spatial data.

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We have proved that there exist constants A and B such that ∣f(x)∣≤A+B∣x∣ for all x∈R, when f is uniformly continuous on R.

to prove that there are constants A and B such that ∣f(x)∣≤A+B∣x∣ for all x∈R, where f is a uniformly continuous real-valued function on R, we can use the definition of uniform continuity.

Since f is uniformly continuous on R, for any ε>0, there exists a δ>0 such that |f(x) - f(y)| < ε for all x, y in R, whenever |x - y| < δ.

Let's choose ε = 1. Then, there exists a δ>0 such that |f(x) - f(y)| < 1 for all x, y in R, whenever |x - y| < δ.

Now, let's choose x = 0. Since |x - y| < δ, we have |y| < δ.

Using the triangle inequality, we have |f(y)| ≤ |f(0)| + |f(y) - f(0)|.

Since |f(x) - f(y)| < 1 for all x, y in R, whenever |x - y| < δ, we can say |f(y) - f(0)| < 1.

Therefore, we have |f(y)| ≤ |f(0)| + 1.

Let A = |f(0)| and B = 1, we have |f(y)| ≤ A + B|y| for all y in R.

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Answer: 77m

Step-by-step explanation:

The equation for the perimeter of a rectangle is: p = 2(length) + 2(width). We are given both perimeter and the length, so we can plug in these values to solve for what is missing.

332m = 2(89) + 2(width)

332m = 178 + 2(width)

154 = 2(width)

width = 77

Just combine like terms and get the variable (width) by itself on one side of the equation to solve. Hope this helps!

Answer:

width = 77 m

Step-by-step explanation:

Perimeter = sum of all sides

As a rectangle has 2 lengths and 2 widths making a total of four sides;

P = 2 ( l + w)

332 = 2 ( 89 + w)

332/2 = 89 + w

166 = 89 + w

166 - 89 = w

77 = w

Therefore, the width of the pool is 77 m

Answer:

R41, R103

Step-by-step explanation:

A ratio has two or more numbers that symbolize relation to each other. Ratios are used to compare numbers, and you can compare them using division.

If the ratio is 5: 7, we can use these equations to solve for the amount each will get:

Therefore, Hashim will get R41, and Hannah will get R103.

The equation for the given phrase is 1/2(x)+2y=14.

Given that, Diego then says if we take half of the first number and double the second the sum is 14.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the first number be x and the second number be y.

Now, half of the first number and double the second the sum is 14

So, 1/2(x)+2y=14

Hence, the equation for the given phrase is 1/2(x)+2y=14.

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Answer:

8

Step-by-step explanation:

the degree is the highest sum of expinonts

in this case 6+2=8

all whole number have an exponent of zero

Hope this helps please mark brainiest

Answer:

\(\displaystyle 4536,4597918...\:cm.^2 = A\)

Step-by-step explanation:

Split the diametre in half before proceeding:

\(\displaystyle \pi{r}^2 = A \\ \\ 38^2\pi = A \hookrightarrow 1444\pi = A \\ \\ \boxed{4536,4597918... = A}\)

I am joyous to assist you at any time.

A rock that has been significantly reshaped on multiple surfaces by windborne particles and sometimes has a sharp edge is a(n)  ventifact:

A rock refers to the solid portion of the earth crust which contains minerals. There are three types of rocks; The sedimentary rock: They are formed from dead plants, dead animals, sand etc.

The metamorphic rock: They are formed from previously existing rocks. The igneous rock: They are formed from the solidification of the molten magma.

Hence, ventifact are rock  that has been significantly reshaped on multiple surfaces by windborne particles and sometimes has a sharp edge.

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