g Initially, the motorcycle travels along a straight road with a speed of 35 m/s (this is almost 80 mph). The maximum deceleration of the motorcycle is -1.2 m/s2. If the biker is skilled and uses maximum deceleration, how long will it take them to come to a complete stop

Answer:

Δt = 1.1 s

Explanation:

Given information:

H= 50.0 m

g= 9.8 m/s²

   \(H = \frac{1}{2} * g* t^{2}\)

Solving for t, we get:

t₁= 3.2 s

We can find the final velocity for the object when it hits the ground, using the following expression:

\(v_{f}^{2} - v_{o}^{2} = 2*g*H\)

Solving for vf, we get:

vf = 33.9 m/s

Applying the definition of acceleration, being this acceleration the one due to gravity (g), we can write the following equation:

\(v_{f} = v_{o} + g*t\)

(Assuming the downward direction to be positive).

Solving for t, we get:

t₂ = 2.1 s

So the difference in time when both objects hit the ground, it's simply

Δt = t₂ - t₁ = 3.2 s - 2.1 s = 1.1 s

Answer:

we need the image to do so.

Explanation:

sorry

Explanation:

A concave lens is also known as a diverging lens because it is shaped round inwards at the centre and bulges outwards through the edges, making the light diverge. They are used to treat myopia as they make faraway objects look smaller than they are.

Answer:

less energy is needed to heat the house

the roof is a better insulator

The correct advantage of having a roof with a lower thermal conductivity is Less energy is needed to heat the house. The correct answer is option 1.

A roof with lower thermal conductivity acts as a better insulator, reducing heat transfer between the interior and exterior of the house. This means that during colder months, less heat escapes through the roof, requiring less energy to maintain a comfortable temperature indoors. Additionally, a roof with lower thermal conductivity will help regulate indoor temperatures more effectively, making it a better insulator against external weather conditions. It does not directly affect the likelihood of roof leaks or increase the rate of energy transfer by conduction. Option 1 is correct.

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--The complete Question is, What are the advantages of having a roof with a lower thermal conductivity?

Which of the following two is correct

1. Less energy is needed to heat the house

2. The roof is a better insulator

3. The roof is less likely to leak

4. The rate of energy transfer by conduction is greater

5. Weather will have a greater effect on the temperature of the house. --

The heat transfer in the winds, the earths oceans and the earths mantle are as a result of the rising and falling of heat, water and hot magma respectively.

This is referred to as a process of heat transfer which occurs in fluid substances such as gas and liquids and ensures uniform distribution of the heat content.

Heat transfer which is characterized by heat rising and the cool air falling results in the formation of wind while the rising and cooling of warm water results in the formation of the earth's ocean through the various types of precipitation which is experienced.

Convection currents arise from the convection process and ensures that energy is transferred from one place to another. This makes sure the heat transfer is achieved and uniformly distributed between the substances involved.

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The formula you mentioned is known as the dot product formula or the scalar product formula. It is used to find the angle between two vectors u and v.

Let's start by defining the vectors u and v. Suppose we have two vectors u and v in a two-dimensional space.

u = (u1, u2)

v = (v1, v2)

The dot product of these vectors is defined as:

u . v = |u| |v| cos(β)

where |u| and |v| are the magnitudes of the vectors u and v respectively, and β is the angle between the vectors u and v.

Now, let's derive this formula. The dot product of two vectors u and v is given by:

u . v = (u1 × v1) + (u2 × v2)

The magnitude of a vector is given by:

|u| = sqrt(u1² + u2²)

|v| = sqrt(v1² + v2²)

We can use the dot product and magnitude equations to obtain:

cos(β) = (u . v) / (|u| × |v|)

Multiplying both sides by |u| × |v| gives us:

|u| × |v| × cos(β) = u . v

Therefore, we have derived the dot product formula:

u . v = |u| × |v| × cos(β)

This formula can be used to find the angle between two vectors u and v in any two-dimensional or three-dimensional space.

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The complete question is-

Write the proof of the formula

u.v=|u||v|cosβ

Answer:

A

Explanation:

A vector quantity is when the unit has magnitude (#) and direction and velocity is speed in a given direction.

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

The correct answer is option A: 3.00 × 10^(-11) m.

Explanation:

To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:

wavelength = speed of light / frequency

Given:

Speed of light (c) = 3.00 × 10^8 m/s

Frequency (f) = 10^19 s^(-1)

Substituting the values into the equation:

wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))

To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:

wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s

To divide by a fraction, we multiply by its reciprocal:

wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)

Applying the properties of exponents, we can add the exponents when multiplying with the same base:

wavelength = 3.00 × 10^(-11) m

Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.

Answer:

33.8 minutes

Explanation:

speed = 400m/8.4min = 47.6 m/min

time = distance / speed = (1609 m) / (47.6 m/min) = 33.8 min

The reading on the scale is closest to 708N.

The weight of any object is the mass times the acceleration due to gravity on Earth or any other planet.

Weight W = mg

where g = 9.81 m/s²

Given is the mass of person, m = 60kg, and the acceleration downward of the elevator a =2 m/s² , then the weight will be

W = m(a+g)

W = 60x (2+9.81)

W=  60x11.8

W= 708 N

Thus, reading on the scale will be 708N

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Answer:  If the woodpecker drums upon a tree 5 times in one second, then the frequency is 5 Hz; each drum must endure for one-fifth a second, so the period is 0.2 s.

Answer:

B. contain hydrogen

C. clouds of gas and dust

E. needed to create a star

Explanation:

A star is a giant astronomical or celestial object that is comprised of a luminous sphere of plasma, binded together by its own gravitational force.

Some of the examples of stars are; Vega, Sun (closest to planet Earth), Antares, Betelgeus, Canopus, etc.

Stars are typically made up of two (2) main hot gas, Hydrogen (H) and Helium (He). The chronological order in which the formation of a star occur are;

1. Gravity pulls gas and dust together to form dense cores.

2. A protostar forms as mass increases.

3. Nuclear fusion begins under high pressure.

Scientists have been able to understand and discover that, gravity pulled materials (low-density cloud of interstellar gas and dust known as a nebula) together forming the planetary bodies in our solar system.

A dark nebula can be defined as an interstellar cloud that is so dense as a result of high concentration of gas and dust and as such it obscures the visible wavelengths of light from stars behind it, thus appearing completely opaque (dark patch) in front of a bright emission nebula or in regions having plenty stars.

The characteristics of a nebulae are;

I. It contain hydrogen.

II. Clouds of gas and dust

III. It is needed to create a star.

Answer:

a) F₂₁ = 0.02 N, attracting.

b) F₁₂ = 0.02 N, attracting.

Explanation:

a)

      \(F_{21} = k * \frac{q_{1} *q_{2}}{r_{12}^{2} } = 9e9 N.m2/C2 * \frac{(25e-9C)*(75e-9C)}{(0.03m)^{2}} = 0.02 N (1)\)

b)

Answer:

I think it would be A

Explanation:

Air, water, and warmth

Excuse my mistake if I get it wrong.

Answer:

I think it would be A

Explanation:

Air, water, and warmth

hopes this helps

Answer:

The moment of inertia of a slender uniform rod of length L about an axis at one end perpendicular to the rod is \(I = \frac{1}{3}\cdot m \cdot L^{2}\).

Explanation:

Let be an uniform rod of length L whose origin is located at one one end and axis is perpendicular to the rod, such that:

\(\lambda = \frac{dm}{dr}\)

Where:

\(\lambda\) - Linear density, measured in kilograms per meter.

\(m\) - Mass of the rod, measured in kilograms.

\(r\) - Distance of a point of the rod with respect to origin.

Mass differential can translated as:

\(dm = \lambda \cdot dr\)

The equation of the moment of inertia is represented by the integral below:

\(I = \int\limits^{L}_{0} {r^{2}} \, dm\)

\(I = \lambda \int\limits^{L}_{0} {r^{2}} \, dr\)

\(I = \lambda \cdot \left(\frac{1}{3}\cdot L^{3} \right)\)

\(I = \frac{1}{3}\cdot m \cdot L^{2}\) (as \(m = \lambda \cdot L\))

The moment of inertia of a slender uniform rod of length L about an axis at one end perpendicular to the rod is \(I = \frac{1}{3}\cdot m \cdot L^{2}\).

Answer:

The tensions in \(T_{BC}\) is approximately 4,934.2 lb and the tension in \(T_{BD}\) is approximately  6,035.7 lb

Explanation:

The given information are;

The angle formed by the two rope segments are;

The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°

The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°

Therefore, we have;

The tension in rope segment BC = \(T_{BC}\)

The tension in rope segment BD = \(T_{BD}\)

The tension in rope segment AB = \(T_{AB}\) = Pulling force of tugboat = 1200 lb

By resolution of forces acting along the line A_F gives;

\(T_{BC}\) × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = \(T_{AB}\) = 1200 lb

\(T_{BC}\) × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = 1200 lb............(1)

Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;

\(T_{BC}\) × sin(26.0°) + \(T_{BD}\) × sin(21.0°) = 0...........................(2)

Which gives;

\(T_{BC}\) × sin(26.0°) = - \(T_{BD}\) × sin(21.0°)

\(T_{BC}\) = - \(T_{BD}\) × sin(21.0°)/(sin(26.0°))  ≈ - \(T_{BD}\) × 0.8175

Substituting the value of, \(T_{BC}\), in equation (1), gives;

- \(T_{BD}\) × 0.8175 × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = 1200 lb

- \(T_{BD}\) × 0.7348  + \(T_{BD}\) ×0.9336 = 1200 lb

\(T_{BD}\) ×0.1988 = 1200 lb

\(T_{BD}\) ≈ 1200 lb/0.1988 = 6,035.6938 lb

\(T_{BD}\) ≈ 6,035.6938 lb

\(T_{BC}\) ≈ - \(T_{BD}\) × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb

\(T_{BC}\) ≈ -4934.1733 lb

From which we have;

The tensions in \(T_{BC}\) ≈ -4934.2 lb and  \(T_{BD}\) ≈ 6,035.7 lb.

Answer:

3.8 x 10^-11N

Explanation:

Given

M=72 kg

R=95 m

G=6.67x10^-11

Equation

Fg= 6.67x10^-11((72kg*72)/(95)^2)

Plug into calculator and get

3.8127756 x 10^-11

Across

2. opaque

4. hard

5. metal(s)

6. translucent

8. luster

Down

1. wood

3. transparent

7. soluble?

Happy to help, have a great day! :)

In the given assembly we have a stick with two masses "m" attached to its end. We are asked the following:

Part A. If the cube of "2m" moves a distance "y" to the floor then, by the principle of conservation of energy this means that the initial gravitational potential energy is converted into the final kinetic energy of the falling mass and the rotational kinetic energy of the assembly. This can be written as follows:

Where:

The gravitational potential energy is given by:

Where:

The mass of the falling object is "2m" therefore:

Substituting in the balance of energy:

Now, we can solve for the kinetic energy of the rotating object:

Therefore, the kinetic energy of the assembly is less than "2mgy".

Part B. We are asked to determine the angular speed o the assembly. To do that we will use the following formula for the rotational kinetic energy of the assembly:

Where:

The linear kinetic energy is given by:

Where:

Substituting the mass of the falling object:

Substituting in the balance of energy:

The rotational inertia is given by the following formula:

Substituting we get:

We can cancel out the mass "m":

We have that the linear velocity "v" of the falling object is related to the angular velocity of the assembly by the following equation:

Substituting we get:

Now, we add the square of the angular velocity and the radius to both sides:

Now, we take the square of the angular velocity as a common factor:

Now, we divide both sides by the factor of the square of the angular velocity:

Taking the square root to both sides we get:

And thus we got the expression to determine the angular velocity.

Part C. The impulse is given by:

Where:

If the system starts from rest then the initial angular velocity is zero and the formula reduces to:

Substituting the expressions:

And thus we get an expression to calculate the impulse.

Part D. If the mass of the swivel is "M", then the new balance of energy is:

Therefore, the rotational kinetic energy of the assembly would still be less than "2mgy" since the initial gravitational potential energy is converted into the kinetic energy of the falling object and the kinetic energy of the swivel.

Assuming that 200 Mev of energy is released per fission of u235 , the mass of that undergoes fission reactor of power 1MW will be approximately will be the correct option is a i.e. 10^-2g.

The mass of the material that undergoes fission in a reactor with a power of 1 MW, you need to know the number of fissions that occur per second in the fission reactor. The power of a reactor is the rate at which energy is released by the fission reactions taking place inside it. The energy released per fission of uranium-235 is 200 MeV.

The relationship between power, energy, and time is given by the equation:

Power = Energy / Time

Rearranging this equation to solve for the number of fissions per second gives:

Number of fissions/second = Power / (Energy/fission)

Putting the values from the problem gives:

Number of fissions/second = 1 MW / (200 MeV/fission) = 5 x 10^22 fissions/second

Since the mass of uranium-235 is approximately 235.04 g/mol, the mass of the material that undergoes fission in the reactor is approximately:

Mass = (Number of fissions/second) x (235.04 g/mol) / (6.022 x 10^23 fissions/mol) = 3.93 x 10^-2 g

So, the mass of the material that undergoes fission in the reactor is approximately 3.93 x 10^-2 g, which corresponds to the answer choice "a. 10^-2g".

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Answer:

unfournatletly

Explanation:

i have no clue sorry to waste ur time ill rather not say a answer that will be incorrect.

Answer:

Pluto

Explanation:

The graphs below show the height vs. time (teal), velocity vs. time (green), and acceleration vs. time (blue) for a shuttlecock. The statement  that is true is option A. The shuttlecock began 7 meters above the ground, and fell through a vacuum.

The amount of distance an object travels in a specific length of time is measured in terms of velocity. Here is a word equation that illustrates how time, velocity, and distance are related: Distance traveled divided by journey time is the definition of velocity.

A graph of velocity vs time demonstrates the evolution of velocity. The object's acceleration is equal to the slope, which is equal to rise over run. The change in velocity over time is known as acceleration. The distance between the start and end of a velocity versus time graph, or the displacement, determines the area under the graph.

Therefore, the item stood 7 meters tall at the beginning of time. Air resistance would slow the shuttlecock's acceleration if it fell through particularly dense air. There must not be any air resistance because the acceleration stays constant.

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Answer:

596.24

Explanation:

*See attached photo*

All adults complete all four stages of development by the age of 25. Option D.

For Piaget cognitive development was the gradual reorganization of mental processes as a result of biological maturation and environmental experience. Children make sense of the world around them and experience discrepancies between what they already know and what they discover around them.

Fundamentally Piaget believed that man could make sense of the world on his own. From a theological point of view, he was a psychological constructivist believing that learning is caused by a mixture of two processes for him assimilation and adaptation. Piaget supported the idea that children think differently than adults and his research identified several important milestones in children's intellectual development.

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The second ball should be dropped 2.19 seconds after the first ball is thrown so that it hits the ground at the same time as the first ball.

We can solve this problem using the kinematic equations of motion. Let's first find out how long it takes for the first ball to hit the ground.

Using the kinematic equation:

h = ut + 1/2 at^2

where;

Plugging in the values, we get:

-24 = 12t - 1/2 * 10 * t^2

Simplifying the equation:

5t^2 - 12t  - 24 = 0

Using the quadratic formula:

t = 3.7 seconds

Therefore, the first ball takes 3.6 seconds to hit the ground.

Now, let's find out at what time the second ball should be dropped so that it hits the ground at the same time as the first ball.

Since the second ball is dropped from rest, its initial velocity (u) is 0. Using the same equation:

h = ut + 1/2 at^2

Plugging in the values, we get:

24 = 0t - 1/2 * 10 * t^2

Simplifying the equation:

5t^2 = 24

t^2 = 4.8

t = √(4.8)

t = 2.19 seconds (approx)

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The higher density a material the: Slower the speed of light. Option C. slower the speed of light.

A material is considered high density material when it is endowed with more entity, or stuff gathered into a given space.

Higher-density materials is known to often have excess refractive indices. The greater the refractive index, the slower light travels through such material. In the same vain, lower-density materials normally have lesser refractive indices. Consequently, the lesser the refractive index, the faster light travels through the material.

Therefore, the correct answer is as given above.

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Answer:

20 40

Explanation:

A 10 kg box initially at rest accelerates uniformly to a speed of 20 m/s in 2 seconds, energy gained by the block 2000 J and Power developed by the box at the end of 10 seconds 5000 Watt

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

Work Done = Force * Displacement

As given in the problem A 10 kg box initially at rest accelerates uniformly to a speed of 20 m/s in 2 seconds

By using the first equation of motion

v = u + at

20 = 0 + 2a

a = 10 m/s²

By using the third equation of motion

v² - u² = 2as

20² - 0² = 2×10×s

s = 400/20

s = 20 m

Force = ma

          = 10 ×10

          = 100 N

work done = Force × displacement

                   = 100 ×20

                   = 2000 J

Velocity after 10 seconds

V= u + at

  = 0 + 10×10

  = 100 m/s

work done after 10 seconds

= 1/2mv²

= 0.5×10×10²

=50000 J

Power = work done  / time

           = 50000/10

           = 5000 Watt

Thus, energy gained by the block 2000 J and Power developed by the box at the end of 10 seconds 5000 Watt

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Answer:

a = ω^2 A      formula for max acceleration (ignoring sign)

V = ω A         formula for max velocity

V^2 = ω^2 A^2 = a A   from first equation

E = 1/2 M V^2 = 1/2 * 2.98 * 3.55 * .0805 = .426 J

(kg * m/sec^2 * m = kg m^2 / sec^2 = Joule