The starting address of the array is 0x10010038 so option d is correct.
An array is a collection of elements of similar types, stored in contiguous memory locations. The index (subscript) is a zero-based number that starts at 0 and ends at (size-1).
Array declaration:
int Array A[100];
Array A is the starting address of the array, which is 0x10010000.
Size of an integer is 32 bits, which is 4 bytes. Therefore, the address of element 14 can be calculated as follows:
ArrayA [14] = Array A + (14 x 4 bytes) = 0x10010000 + (14 x 4 bytes) = 0x10010038. The address of element 14 in the given array declaration is 0x10010038. Therefore, option (d) 0x10010038 is the correct answer.
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The address of element 14 in an array in a program is 0x10010038. Here's how to solve it: Given array declaration: int ArrayA[100];Integer size = 32 bits
Starting address of array = 0x10010000To calculate the address of element 14:Since ArrayA is of integer type and occupies 4 bytes of memory, the address of the next element can be calculated as the current address + 4.
Next element address = Current element address + (size of each element)Address of element 14 = Starting address + (13*4)= 0x10010000 + 52= 0x10010034. Hence, the address of element 14 in the array is 0x10010038.
Option D: 0x10010038 is the correct answer.
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figure p4.10 shows an electric motor loaded by a belt drive. copy the drawing and show on both views the location
Motor and Belt
What is Motor?
Motor is an electrical device used to convert electrical energy into mechanical energy. It is composed of a stator, rotor, field magnet, commutator, and brushes. The stator consists of a number of electromagnets which are arranged in a circle and are connected to an electrical power source. The rotor is the part that rotates and consists of a number of windings connected to the commutator. The field magnet provides the magnetic field in which the rotor turns. The commutator is responsible for changing the direction of the current in the rotor and is connected to the brushes which supply the current to the rotor.
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Shear stress t produces a shear strain Yxy (be- tween lines in the x direction and lines in the y direction) of Yxy 1200 u (i.e., y = 0.0012 m). (a) Determine the horizon- tal displacement da of point A. (b) Determine the shear strain Yx'y between the lines in the x' direction and the y' direction, as shown on Fig. P2.7-12. y δ, τ A τ 120 mm T y' 150 mm
A) The horizontal displacement of point A is 0.144 mm. B) The shear strain Yx'y between the lines in the x' direction and the y' direction is 0.00096 m.
What is shear strain?Shear strain is a type of deformation caused by a force applied to an object. It occurs when two opposite parallel forces are applied in opposite directions, causing the object to elongate in one direction and compress in the other. Shear strain is different from tensile strain, which happens when a force is applied in one direction only.
(a) The horizontal displacement of point A due to the shear stress τ is given by the equation da = τYxy. Substituting the given values, we obtain da = τ(0.0012 m) = (120 N/mm2)(0.0012 m) = 0.144 mm.
(b) The shear strain Yx'y between the lines in the x' direction and the y' direction is given by the equation Yx'y = da/δ', where δ' is the distance between the lines in the x' direction. Substituting the given values, we obtain Yx'y = (0.144 mm)/(150 mm) = 0.00096 m.
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What signal propagation phenomena causes the diffusion, or the reflection in multiple different directions, of a signal?
In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.
Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.
Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.
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Write two reports (papers) using the Tools in the EMERGE Platform (aka EMERGE Workbook) (not textbook). - Report #1 will focus on using six tools in the EMERGE Platform Workbook to Size Up a wicked problem facing a public senvice organization. Ideally, the public service organization will be the organization in which the student is employed, but this is not required. Students will be expected to write the report using a guidance document and set of rubrics that will be provided in the Assignment section of D2L. - Report #2 will focus on a second set of six tools in the EMERGE Platform Workbook used to identify actions that can be taken to address the wicked problem identified in the first report. Students will be expected write the paper using a guidance document and set of rubrics that will be provided in the Assignment section of D2L. - Each of these papers is worth 150 points, and together they make up about 35% of the student's grade.
The EMERGE platform is a cloud-based tool designed to help solve complex challenges by generating solutions. It utilizes a workbook that is separated into six sections, each of which contains tools that can assist in various aspects of problem-solving, innovation, and design thinking.
Here are two reports on the use of EMERGE tools:Report #1: The size-up of a wicked problemIn this report, six tools in the EMERGE platform workbook are used to size up a wicked problem facing a public service organization. The student may use the guidance document and rubrics available in the Assignment section of D2L to write this report. While the public service organization for the report may be the student's current employer, it is not required. This paper is worth 150 points.Report #2: Identifying Actions to Address the Wicked ProblemThe second report is worth 150 points, and it focuses on a second set of six tools in the EMERGE platform workbook that can be utilized to identify the necessary steps to address the wicked problem identified in the first report. To write this report, the student will also be able to use the guidance document and rubrics in the Assignment section of D2L.
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determine the principal stresses. specify the orientation of the element. express your answers, separated by commas, to three significant figures.
Therefore, it is impossible to answer this question. Please provide complete information about the orientation of the element to determine the principal stresses.
The principal stresses are the maximum and minimum normal stresses that act on an element in a given direction. These stresses are also known as normal stresses because they act perpendicular to the plane's surface. In mechanics and structural engineering, principal stresses play a crucial role in calculating and designing the material's strength to handle the load.Because of the presence of a direct or shear stress in the element, the principal stresses arise. There are three principal stresses at every point in a three-dimensional solid; each is perpendicular to the other two. For each of the principal stresses, the direction of the stress is perpendicular to the stress plane, indicating that the stress vector and the normal vector are in the same direction.for more such question on orientation
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please i want to paraphrase this paragraph please helppppppppp don't skip!!!!!!
10. What refrigerant is no longer manufactured in the
United States?
Answer:
Freon Refrigerant
Explanation:
As of January 1, 2020 Freon Refrigerant can no longer be manufactured or imported to the United States. This is because R-22 (the principal component in Freon) has been banned in the states. Along with other greenhouse gasses, due to their contribution to damaging Earth’s ozone layer and global warming.
hope this helps:)
Answer:
Freon Refrigerant Is Now Banned in the US
As of January 1, 2020, a once very popular air conditioning refrigerant can no longer be made in or imported into the United States.
Please give me brainliest - you get 25% as well! I swear!
A European apparel manufacturer has production facilities in Italy and China to serve its European market, where annual demand is for 1.9 million units. Demand is expected to stay at the same level over the foreseeable future. Each facility has a capacity of 1 million units per year. With the current exchange rates, the production and distribution cost from Italy is 10 euro per unit, whereas the production and distribution cost from China is 7 euro. Over each of the next three years, the Chinese currency could rise relative to the euro by 15 percent with a probability of 0.5 or drop by 5 percent with a probability of 0.5. An option being considered is to shut down 0.5 million units of capacity in Italy and move it to China at a one-time cost of 2 million euros. Assume a discount factor of 10 percent over the three years. Do you recommend this option?
very big question aa having i can't answer it
The solid cylindrical bar shown is subjected to a bending force F = 55kN, an axial load P = 8 kN, and a torsional load T = 30 kN-mm. The bar is made of AISI 1060 CD steel (Sy = 280 MPa, Sut = 330 MPa). Find the factor of safety based on Maximum Distortion Energy Theory.
The factor of Safety by Maximum Distortion Energy Theory is given as: N = 6.04
What is Maximum Distortion Energy Theory?
According to this idea, failure by yielding happens when the distortion energy per unit volume in a condition of combined stress equals that associated with yielding in a basic tension test at any location in the body.
What is the calculation for the above value?
Note that we are given the following:
A solid Steel bar subjected to a bending force of F = 55kN
Torsional load T = 30 kN-mm; and
Yield Strength (sy) = 280Mpa
Sut = 330 Mpa
The formula for Normal Stress is given as:
\(\alpha _{x}\) = [UP/πd²] + [ (32* f * L)/πd³]
= [(4 * 8 * 10³)/π * (0.02)²] + [(32 * 55 *10³ * 0.1)/ π * (0.02)³]
= 25.46 + 7.003
\(\alpha _{x}\)= 32.5 Mpa
Tyz = (16T)/πd³
= (16 * 30)/ π * (0.02)³
= 19.098
Tyz = 19.098
Following from the above, sate of stress, we have:
α₁ = αₓ = 32.46 Mpa; and
α₂ = Tyz = 19.098 Mpa;
α₃ = -Tyz = -p19.098 Mpa;
Utilizing the formula given by the Maximum Distortion Energy Theory:
α₁² + α₂² + α₃² - (α₁α₂ + α₂α₃ + α₃α₁)
= Sy²/N²
→ 32.46² + 19.098² + 19.098² - ( 32.46* 19.098 - 19.098² -32.46 * 19.098)
= 280/N²
N = 6.04
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Find the normal and shear stresses at the following planes when σ1 = 100 MPa, and σ2 = 40 MPa. θ is an angle between the shear plane and σ2.
(a) At the plane of θ = 45°
(b) At the plane of θ = 60°
a)at the plane of θ = 45°, the normal stress (σn) is 70 MPa, and the shear stress (τ) is 60 MPa. b) at the plane of θ = 60°, the normal stress (σn) is 40 MPa, and the shear stress (τ) is -51.96 MPa.
To find the normal and shear stresses at specific planes, we can use the equations for stress transformations.
The stress transformation equations relate the normal and shear stresses on a plane to the principal stresses and the angle of the plane with respect to the principal stress axis.
Given:
σ1 = 100 MPa (principal stress)
σ2 = 40 MPa (principal stress)
θ = angle between the shear plane and σ2
(a) At the plane of θ = 45°:
For this plane, the angle between the plane and σ2 is 45°. Let's calculate the normal and shear stresses using the stress transformation equations.
Normal Stress (σn):
σn = (σ1 + σ2) / 2 + (σ1 - σ2) / 2 * cos(2θ)
Substituting the given values:
σn = (100 MPa + 40 MPa) / 2 + (100 MPa - 40 MPa) / 2 * cos(2 * 45°)
= 70 MPa + 30 MPa * cos(90°)
= 70 MPa
Shear Stress (τ):
τ = (σ1 - σ2) / 2 * sin(2θ)
Substituting the given values:
τ = (100 MPa - 40 MPa) / 2 * sin(2 * 45°)
= 60 MPa * sin(90°)
= 60 MPa
Therefore, at the plane of θ = 45°, the normal stress (σn) is 70 MPa, and the shear stress (τ) is 60 MPa.
(b) At the plane of θ = 60°:
For this plane, the angle between the plane and σ2 is 60°. Let's calculate the normal and shear stresses using the stress transformation equations.
Normal Stress (σn):
σn = (σ1 + σ2) / 2 + (σ1 - σ2) / 2 * cos(2θ)
Substituting the given values:
σn = (100 MPa + 40 MPa) / 2 + (100 MPa - 40 MPa) / 2 * cos(2 * 60°)
= 70 MPa + 30 MPa * cos(120°)
= 40 MPa
Shear Stress (τ):
τ = (σ1 - σ2) / 2 * sin(2θ)
Substituting the given values:
τ = (100 MPa - 40 MPa) / 2 * sin(2 * 60°)
= 60 MPa * sin(120°)
= -51.96 MPa (negative due to the choice of coordinate system)
Therefore, at the plane of θ = 60°, the normal stress (σn) is 40 MPa, and the shear stress (τ) is -51.96 MPa.
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Polarization: Unpolarized light passes through three ideal polarizing filters. The first filter is oriented with a horizontal transmission axis, the second one has its transmission axis at 30° from the horizontal, and the third filter has a vertical transmission axis. What percent of the light gets through this combination?
Answer:
the percentage of light that gets through this combination is 9.38
Explanation:
Given the data in the question;
Let us represent the incident unpolarized light with \(I_0\).
So, the amount of light intensity passing through the first polarizer will be;
\(I_1\) = \(I_0\) / 2 ------ let this be equation 1
An the amount of light intensity passing through the second polarizer will be;
\(I_2\) = \(I_1\)cos²θ
given that; the second one has its transmission axis at 30°
so, we substitute;
\(I_2\) = \(I_1\) × cos²( 30° )
\(I_2\) = \(I_1\) × 0.75
\(I_2\) = 0.75\(I_1\)
from equation; \(I_1\) = \(I_0\) / 2
\(I_2\) = 0.75( \(I_0\) / 2 )
\(I_2\) = 0.375\(I_0\) .
Now, the amount of light intensity passing through the third polarizer will be;
\(I_3\) = \(I_2\)cos² ( 90° - 30° )
\(I_3\) = \(I_2\) × cos²( 60° )
\(I_3\) = \(I_2\) × 0.25
we substitute
\(I_3\) = 0.375\(I_0\) × 0.25
\(I_3\) = 0.09375\(I_0\)
∴ \(I_3\)/\(I_0\) × 100 = 0.09375 × 100
⇒ 9.38%
Therefore, the percentage of light that gets through this combination is 9.38
A wind tunnel is used to study the flow around a car. The air is drawn at 60 mph into the tunnel. (a) Determine the pressure in the test section as determined by the manometer. (b) Determine the pre
Answer:
The answer is below
Explanation:
The complete question is attached.
a) Bernoulli equation is given as:
\(P+\frac{1}{2}\rho V^2+ \rho gz=constant\\\\\frac{P}{\rho g} +\frac{V^2}{2g} +z=constant\\\)
Where P = pressure, V = velocity, z = height, g = acceleration due to gravity and ρ = density.
\(\frac{P}{\rho g} +\frac{V^2}{2g} +z=constant\\\\\frac{P}{\gamma} +\frac{V^2}{2g} +z=constant\\\\\frac{P_1}{\gamma} +\frac{V_1^2}{2g} +z_1=\frac{P_2}{\gamma} +\frac{V_2^2}{2g} +z_2\\\\but \ z_1=z_2,P_1=0,V_1=0,V_2=60\ mph=88\ ft/s. Hence:\\\\\frac{P_2}{\gamma} =-\frac{V_2^2}{2g} \\\\P_2=\gamma*-\frac{V_2^2}{2g} =\rho g*-\frac{V_2^2}{2g} \\\\P_2=-\frac{V_2^2}{2}*\rho=-\frac{(88.8\ ft/s)^2}{2} * 0.00238\ slug/ft^3=-9.22\ lb/ft^2\\\\P_2+\gamma_{H_2O}h-\gamma_{oil}(1/12 \ ft)=0\\\\\)
\(\gamma_{oil}=0.9\gamma_{H_2O}=0.9*62.4\ lb/ft^3=56.2\ lb/ft^3\\\\Therefore:\\\\-9.22\ lb/ft^2+62.4\ lb/ft^3(h)-56.2\ lb/ft^3(1/12\ ft)=0\\\\h=0.223\ ft\)
b)
\(\frac{P}{\gamma} +\frac{V^2}{2g} +z=constant\\\\\frac{P_2}{\gamma} +\frac{V_2^2}{2g} +z_2=\frac{P_3}{\gamma} +\frac{V_3^2}{2g} +z_3\\\\but \ z_3=z_2,V_3=0,V_2=60\ mph=88\ ft/s. \\\\\frac{P_2}{\gamma}+\frac{V_2^2}{2g} = \frac{P_3}{\gamma}\\\\\frac{P_3-P_2}{\gamma}=\frac{V_2^2}{2g} \\\\P_3-P_2=\frac{V_2}{2g}*\gamma=\frac{V_2^2}{2g}*\rho g\\\\P_3-P_2=\frac{V_2}{2}*\rho=\frac{(88\ ft/s^2)^2}{2}*0.00238\ slg\ft^3\\\\P_3-P_2=9.22\ lb/ft^2\)
Calculate the rms value.
Answer:
(√6)/3 ≈ 0.8165
Explanation:
The RMS value is the square root of the mean of the square of the waveform over one period. It will be ...
\(\displaystyle\sqrt{\frac{1}{T}\left(\int_{\frac{T}{4}}^{\frac{3T}{4}}{1^2}\,dt+\int_{\frac{3t}{4}}^{\frac{5t}{4}}{(\frac{-4}{T}}(t-T))^2\,dt\right)}=\sqrt{\frac{1}{T}\left(\frac{T}{2}+\left.\frac{16}{T^2}\cdot\frac{1}{3}(t-T)^3\right|_{\frac{3t}{4}}^{\frac{5t}{4}}\right)}\\\\=\sqrt{\frac{1}{T}\left(\frac{T}{2}+\frac{T}{6}\right)}=\sqrt{\frac{2}{3}}=\boxed{\frac{\sqrt{6}}{3}\approx0.8165}\)
PLS HELPPP!!!!!!!!!!!!!!!
What is the sense of a vector that is 20° CW from the negative x-axis?
A. Up and right
B. Down and right
C. Up and left
D. Down and left
Answer:
C. Up and left
Explanation:
The negative x-axis is on the left side of a graph.
If you turn 20° clockwise, then it would still be in the second quadrant pointing up a little bit.
Just loook at the picture i linked below
Answer:
c
Explanation:
In the base of mechanical science knowledge, define work, energy and power
Answer:
Work is the amount of energy transfered by a force.
Energy is the amount of power an object gets from its position or motion.
Power is the combination of all forces and movements of a system that is the rate at which work can be done by a system.
d)What is the binary equivalent of the following decimal number
(floating point)? 14.0
e)What is the hexadecimal equivalent of the following bit
sequence? 0010 1110 1000 0001 1010 1111 1000
d) The binary equivalent of the decimal number 14.0 is 1110.0. e) The hexadecimal equivalent of the bit sequence 0010 1110 1000 0001 1010 1111 1000 is 2E81AF8.
d) To convert the decimal number 14.0 to binary, we can convert the integer part and the fractional part separately. The integer part, 14, is represented as 1110 in binary. The fractional part, 0, remains as 0 in binary. Combining the two parts, we get 1110.0 as the binary equivalent of 14.0.
e) The given bit sequence 0010 1110 1000 0001 1010 1111 1000 represents a binary number. To convert it to hexadecimal, we can group the binary digits into sets of four from right to left. The resulting groups are 0010, 1110, 1000, 0001, 1010, 1111, and 1000. Converting each group to hexadecimal, we get 2, E, 8, 1, A, F, and 8. Combining these hexadecimal digits, we obtain the result 2E81AF8.
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Does somebody know how to do this?
Only when all of the parts of an automobile are assembled does it become a functional vehicle. In this way, an automobile is best defined as a(n) niche system interaction component
An automobile is best described as a system in physics because it is made up of interacting, interrelated, or interdependent parts that function collectively to form an operational whole.
Explanation:In discussing the composition of automobiles, they can be best defined as a system. A system, in the physical sciences, is a group of interacting, interrelated, or interdependent parts that work together to form a complex whole. The parts of an automobile, such as the engine, transmission, wheels, etc., are all interdependent, working together to make the automobile function as a whole. This is similar to many natural and manufactured systems in our world, from biological ecosystems to complex human inventions.
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An automobile can be best defined as a complex niche system interaction component.
What is automobile?An automobile is most aptly characterized as a complex component within a specialized system of interactions. Each part, such as the engine, transmission, and wheels, plays a unique role within the larger system, and their assembly is crucial for the vehicle to function properly.
The term "niche system" highlights the specialized functions of each component, and "interaction component" emphasizes their interdependence in creating a functional vehicle, where individual parts work together harmoniously to achieve a common purpose.
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Complete Question:
Only when all of the parts of an automobile are assembled does it become a functional vehicle. In this way, an automobile is best defined as a(n) .................... niche system interaction component.
When choosing a respirator for your job, you must conduct a _____ test.
A) Fit B) Practice C) Breathing D) Weight?
Answer:
Fit test
Explanation:
it's on the automotive technology sight : )
A shaft of a circular cross section is supported by two housings at B and C. The shaft
is subjected to static loads: concentrated force N applied by gear D and an applied torque T. The yielding strength of the shaft is Sy, and the diameter of the shaft is d. For circular cross sections, | = nd*/64, J = md*/32. The length of the shaft is L. Transverse shear stress is ignored here.
1) Draw the bending moment diagram of the shaft. Specify the location of the weakest (most dangerous) cross section A on bending moment diagram.
2) Draw the weakest point(s) on cross section A.
3) Determine the von-Mises stress at the weakest point(s).
4) Determine the factor of safety n based on Distortion Energy Theory.
Answer:
1) The bending moment diagram of the shaft is shown in Figure 1. The weakest cross section A is located at the point where the bending moment is maximum.
2) The weakest point on cross section A is located at the point where the bending moment is maximum.
3) The von-Mises stress at the weakest point is given by:
σ = M/I
where M is the bending moment and I is the moment of inertia of the cross section.
4) The factor of safety n is given by:
n = Sy/σ
where Sy is the yield strength of the shaft and σ is the von-Mises stress at the weakest point.
Explanation:
Hope this helps!
Steam flows steadily through a turbine at a rate of 45,000 lbm/h, entering at 1000 psia and 9008F and leaving at 5 psia as saturated vapor. If the power generated by the turbine is 4 MW, determine the rate of heat loss from the steam.
Suppose that at UVA, 75% of all undergraduates are in the College, 11% are in Engineering. 7% are in Commerce, 3% aro in Nursing, and 4% are in Architecture. In each school, the percentage of females is as follows: 59% in the College, 23% in Engineering, 48% in Commerce, 90% in Nursing, and 34% in Architecture. If a randomly selected student is male, what is the probability that he's from the College? Probability =?
The probability that a randomly selected male student is from the College at UVA is 0.443.
To find the probability, we need to consider the proportion of male students in the College compared to the total number of male students in all the schools.
1. Calculate the proportion of male students in the College
Since the percentage of females in the College is 59%, the percentage of males would be 100% - 59% = 41%.
Therefore, 41% of the students in the College are male.
2. Calculate the proportion of male students in all the schools
We need to sum up the percentages of male students in each school and find the total proportion of males.
In the College: 41% (as calculated in step 1)In Engineering: 100% - 23% = 77%In Commerce: 100% - 48% = 52%In Nursing: 100% - 90% = 10%In Architecture: 100% - 34% = 66%To find the total proportion of male students, we multiply each proportion by the percentage of students in that particular school:
(0.75 * 0.41) + (0.11 * 0.77) + (0.07 * 0.52) + (0.03 * 0.10) + (0.04 * 0.66) = 0.443
Therefore, the probability that a randomly selected male student is from the College is 0.443.
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Which of the following workers are not likely to be paid during an election?
campaign press secretary
volunteer coordinator
poll worker
director of communications
Answer:
volunteer coordinator
Explanation:
because they are volunteering for that and in most of the cases they do not expect to be paid
Talc and graphite are two of the lowest minerals on the hardness scale. They are also described by terms like greasy or soapy. Both have a crystal structure characterized by sheet-structures at the atomic level, yet they don't behave like micas. What accounts for their unusual physical properties
Answer:
The reason for their unusual properties of the greasy feel and low hardness is that the chemical bonds between the sheets is so weak that very low stresses can allow slip between the sheets.
Explanation:
Talc is a monoclinic mineral with a sheet structure similar to the micas and also has perfect cleavage that follows planes between the weakly bonded sheets.
Now, these sheets are held together only by van der Waals bonds and this allows them to slip past each other easily. Thus, this unique characteristic is responsible for talc's extreme softness, its greasy, soapy feel, and its value as a high-temperature lubricant.
While for graphite, it's carbon atoms are linked in a hexagonal network which forms sheets that are one atom thick. It's sheets are poorly connected and easily cleave or slide over one another when subjected to a small amount of force. Thus, gives graphite its very low hardness, its perfect cleavage, and its slippery feel.
So, we can conclude that the reason for their unusual properties is that the chemical bonds between the sheets is so weak that very low stresses can allow slip between the sheets; hence, the greasy feel and low hardness.
the hydraulic lit in a car repair shop has an output diameter of 22.8 cm and is to lift cars up to 1620 kg. determine the fluid gage pressure in kpa that must be maintained
Answer:
To determine the fluid gage pressure that must be maintained in the hydraulic lift, you need to use the equation for force, which is:
Pressure = Force / Area
Where:
Pressure is in units of kPa (kilopascals)
Force is in units of N (newtons) and is equal to the weight of the car (1620 kg) multiplied by the acceleration due to gravity (9.81 m/s^2)
Area is in units of m^2 (square meters) and is equal to the output diameter of the lift (22.8 cm) converted to meters (0.228 m)
So the pressure that must be maintained is:
Pressure = (1620 kg * 9.81 m/s^2) / (0.228 m^2)
Pressure = (15,847.2 N) / (0.228 m^2)
Pressure = 69,844 kPa
So the fluid gage pressure that must be maintained is 69,844 kPa.
A technician is building a high-performance gaming pc. which two items should the technician focus on selecting parts for the machine?
The Answer is D. The technician should remove jewelry
Explanation: A technician has been given a PC that is not powering up. After brief troubleshooting, the technician comes to the conclusion the power supply needs to be replaced. Which of the following is the NEXT step in the process of performing the repair?
Identify the test in which a hole IS drilled in the exhaust pipe in front of the converter so that an emission analyzer tube can be inserted into the exhaust stream entering the converter:
Select one:
• A. EGR test
• B. Intrusive test
• C. Idling five-gas test
• D. Purge flow test
Answer:intrusive test
Explanation:
2) A heat turbine can generate a maximum power of 250.0 MegaWatts. How much work can the turbine do in 7.800 min
A heat turbine can generate a maximum power of 250.0 MegaWatts. The question demands the work done by the turbine in 7.800 min.
In order to calculate the work done by the turbine in 7.800 min, we need to calculate the energy produced by the turbine in that much time.Power (P) is the rate at which energy is being produced, which can be expressed in terms of energy (E) and time (t) as:Power = E/tWe can find the energy produced in 7.800 min by the heat turbine as:Power = 250.0 MegaWatts = 250.0 × 10⁶ WattsTime, t = 7.800 min = 7.800 × 60 s = 468 sEnergy produced (E) = P × t= 250.0 × 10⁶ × 468 J= 1.17 × 10¹¹ JWe now have the energy produced by the turbine in 7.800 min.
The energy produced by the turbine is the work done by the turbine. Hence, the work done by the heat turbine in 7.800 min is 1.17 × 10¹¹ Joules.Note: Since the unit of power is Watts and the unit of energy is Joules, we need to convert power from MegaWatts to Watts to find energy. The prefix "Mega" denotes 10⁶, so 1 MegaWatt = 10⁶ Watts.
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Think about how could you design, build, and test a light maze. What specific behavior of light will be essential to the success of your design It is due today
Answer:
Reflection
Explanation:
The specific behavior of light that will be essential to ensure the success of your design is "Reflection". This is because light maze makes use of a mirror and it's the light that is reflected that we see with our eyes. Also, the manner in which light is reflected off objects will affect the colors that are reflected as well.
If the load P on the beam causes the end C to be displaced 10mm downward, determine the normal strain in wires CE and BD.
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The normal strain in wire CE is equal to 10 mm 10 m = 0.001.
What is normal strain?Normal strain is a type of strain that occurs when an object is subjected to a stress where the stress is applied in a direction that is perpendicular to the surface of the object. This type of strain is also known as shear strain or transverse strain.
Normal strain is defined as the ratio of the change in length to the original length of the wire.
For wire CE, the original length L is equal to the length of the beam between points C and E, which is 10m. The change in length is equal to the downward displacement of end C, which is 10mm.
Therefore, the normal strain in wire CE is equal to $\frac{10 mm}{10 m} = 0.001$.
For wire BD, the original length L is equal to the length of the beam between points B and D, which is 10m. The change in length is equal to zero since point B is not displaced.
Therefore, the normal strain in wire BD is equal to 0.
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