Giving 50 points to answer problem pls help

Answer:

15x = 15x

or

0 = 0

Step-by-step explanation:

21(x + 1) - 6x = 15x + 21

21x + 21 -6x = 15x + 21

21x - 6x = 15x

15x = 15x

or

0 = 0

this equation is always true

Answer:

89

Step-by-step explanation:

Answer: 89 metres squared

Step-by-step explanation:

large area = 13 x 8 = 104

small area = 5 x 3 = 15

104 - 15 = 89

Answer:

7

Step-by-step explanation:

From the graph....you can see g(-2) = -3     ( see attached diagram below)  

then f(-3) =   7             ( because -3 is less than -2. ... so it = 7)

\(f(g(-2))=7.\)

When asking for \(f(g(-2))\) they are basically asking you to evaluate the function \(g(x)\) for -2, find a y value, and plug in that value as x in \(f(x).\)

Let's do it step-by-step:

1. Find the value of g(-2).

G(x) is given as a graph, therefore, you will have to see what value of axis y marks the graphic when you make x=-2. Check the attached image. As you may notice, the value that function g(x) generates for x= -2 is y= -3. Hence, g(-2)= -3.

2. Substitute the value into f(x).

F(x) is a piecewise function, so we'll need to determine the group the value fits into and calculate with the expession that corresponds for that value. Our value is -3, this value is less than -2, therefore, the function we'll have to use is \(f(x)=7\).

3. Determine the value of f(-3).

Since f(x)= 7 for our value (-3), the result is 7.

4. Express your answer.

\(f(g(-2))=7.\)

Answer:

y=1/2x-8

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-5-(-4))/(6-8)

m=(-5+4)/-2

m=-1/-2

m=1/2

y-y1=m(x-x1)

y-(-4)=1/2(x-8)

y+4=1/2(x-8)

y=1/2x-8/2-4

y=1/2x-4-4

y=1/2x-8

For function \(f(x) = \left \{ {\frac{x+1}{x^{2} -1} ,\ {x\neq 1} \atop {1,\ x=1}} \right.\) given in the problem, the limit \(\lim_{x \to 1} f(x)\) doesn't exists.

A relation between a set of inputs and a set of allowable outputs is called a function, and it has the characteristic that every input is associated to precisely one output. When every element in set A has one end and only one image in set B, then the mapping from set A to set B is a function. Let A & B be any two non-empty sets.

Now for given function,

Limit exists, if LHL=RHL=f(a)

I.  \(f(x) = \frac{1-x^{2} }{x-1}=\frac{(1-x)(1+x)}{x-1} = \frac{-(x-1)(x+1)}{(x-1)} = -(x+1)\)

applying limit,

\(\lim_{x \to 1} f(x)= -2\), LHL= RHL= f(1) = -2. Hence, limit exists

II. \(f(x) = \frac{x^{2} -x^{3} }{x^{2} -1}=\frac{-x^{2} (x -1)}{(x-1)(x+1)} = \frac{-(x^{2} )}{(x+1)}\)

applying limit,

\(\lim_{x \to 1} f(x)= \frac{-1}{2}\) , also LHL= RHL= f(1) = -1/2. Hence, limit exists

III. \(f(x) = \left \{ {\frac{x+1}{x^{2} -1} ,\ {x\neq 1} \atop {1,\ x=1}} \right.\)

\(for x\neq 1,\\f(x)=\frac{(x+1)}{x^{2} -1} = \frac{x+1}{(x-1)(x+1)} = \frac{1}{x-1}\)

RHL= \(\lim_{x \to 1+h} f(x) = \lim_{h \to 0} f(1+h) =\lim_{h \to 0} \frac{1}{1+h-1}\)

\(\lim_{h \to 0} \frac{1}{h} =\) Undefined.

LHL = \(\lim_{x \to 1-h} f(x) = \lim_{h \to 0} f(1-h) =\lim_{h \to 0} \frac{1}{1-h-1}\)

\(\lim_{h \to 0} \frac{1}{h} =\) Undefined

and \(f(1)=1\)

Hence,\(\lim_{x \to 1} f(x)\) doesn't exists

IV. \(f(x) = \left \{ {\frac{x^{2} -3x+2}{x -1} ,\ {x\neq 1} \atop {-1,\ x=1}} \right.\)

\(for x\neq 1,\\f(x)=\frac{(x^{2} -3x+2)}{x -1} = \frac{(x-1)(x-2)}{(x-1)} = {x-2}\)

RHL= \(\lim_{x \to 1+h} f(x) = \lim_{h \to 0} f(1+h) =\lim_{h \to 0} (1+h-2)= -1\)

LHL= \(\lim_{x \to 1-h} f(x) = \lim_{h \to 0} f(1-h) =\lim_{h \to 0} (1-h-2)= -1\)

and f(1) = -1

Hence,\(\lim_{x \to 1} f(x)\)  exists

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The size of the reflex angle above to the nearest degree is 277 degrees.

In Mathematics, a circle can be defined as a closed, two-dimensional curved geometric shape with no edges or corners. Additionally, a circle refers to the set of all points in a plane that are located at a fixed distance (radius) from a fixed point (central axis) with a measure of 360 degrees.

A reflex angle can be defined as a type of angle that is more than 180 degrees but less than 360 degrees.

Based on the information provided about this circle (protractor), we have:

83 + x = 360

x = 360 - 83

x = 277 degrees.

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a.) The value of pulses exported by US in billion would be=30 billion.

b.) The ratio of wheat export of UK to maize export of IND would be= 6:5

For question a.)

To calculate the pulses, the following steps should be taken as follows:

From the bar chart, the value of pulses in billions = 30 billions.

For question b.)

The ratio of wheat export at UK and maize export at IND would be calculated as follows:

The quantity of wheat export at UK = 24

The quantity of maize export at IND = 20

Therefore, the ratio of wheat to maize = 24:20= 6:5

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Answer:

The correct answer is 7 weeks 34 WPM

Step-by-step explanation:

The number of weeks and words typed will be D. 7weeks;34 WPM

Based on the information given, the formula to calculate my words per minutes = 13 + 3n

The formula to calculate my friend's words per minutes = 20 + 2n

Therefore, we'll equate both equations together and this will be:

13 + 3n = 20 + 2n

Collect like terms

3n - 2n = 20 - 13

n = 7.

Therefore, the WPM will be:

= 13 + 3n

= 13 + 3(7)

= 13 + 21

= 34

The number of weeks and words typed will be 7weeks;34 WPM

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According to the Empirical Rule, 99.7% of the measures fall within 3 standard deviations of the mean in the normal distribution.

The Empirical Rule states that, for a normally distributed random variable, the symmetric distribution of scores is presented as follows:

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Answer:

Rolling a six-sided die and flipping a coin: The sample space is 6 • 3or 18 equally likely outcomes

Step-by-step explanation:

mark me brainliest!!

Answer:

3.95833333333

Step-by-step explanation:

Step 1 : Given the function below

Step 2: Write the function for h(3), this is done by substituting 3 for x in the function h(x) above

Step 3: Write the corresponding value for the function g(9) and an inverse function of R⁻¹ (3) on the table.

Step 4: Substitute the g(9) and R⁻¹ (3) values in the h(3) equation and simplify

Hence, the value of h(3) is -11

The second option is the correct answer.

Option A is correct that is ASA postulate AC bisects ∠DAB and CA bisects ∠DCB then we proved ΔDAC≅ΔABC.

Given that,

We have to find the missing reasons in the two column.

Given

AC bisects ∠DAB and CA bisects ∠DCB

Prove

ΔDAC≅ΔABC

Statement                                                          Reasons

1. AC bisects ∠DAB                                           Given

2. ∠DAC≅∠BAC                                              definition of angle bisects

3.AC≅AC                                                         reflexive property
4.CA bisects ∠DCB                                           given

5. ∠DCA≅∠BCA                                              definition of angle bisects

6. ΔDAC≅ΔABC                                               ASA postulate

Therefore, Option A is correct that is ASA postulate AC bisects ∠DAB and CA bisects ∠DCB then we proved ΔDAC≅ΔABC.

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Answer:

Explanation:

First, let us subtract 7 from both sides of the equation; this gives

Finally, dividing both sides by -3 gives

Which is our answer!

Hence, the solution to the equation is x = 1.

Answer:

b = -3 a = - 1/2

Step-by-step explanation:

The value of t₄ in the arithmetic sequence is 103/8.To determine the value of t₄ in an arithmetic sequence, we need to use the given information that t₁ = 11 (the first term of the sequence) and S₉ = 243 (the sum of the first 9 terms of the sequence).

We know that the formula for the sum of an arithmetic sequence is Sₙ = (n/2)(2a + (n-1)d), where Sₙ is the sum, a is the first term, n is the number of terms, and d is the common difference.

From the given information, we have S₉ = 243, a = 11, and n = 9. Plugging these values into the sum formula, we can solve for d:

243 = (9/2)(2(11) + (9-1)d)

243 = 9(22 + 8d)

243 = 198 + 72d

45 = 72d

d = 45/72 = 5/8

Now that we have the common difference, we can find t₄ using the formula for the nth term of an arithmetic sequence:

tₙ = a + (n-1)d

t₄ = 11 + (4-1)(5/8)

t₄ = 11 + 3(5/8)

t₄ = 11 + 15/8

t₄ = 88/8 + 15/8

t₄ = 103/8

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Answer:

56,149 would be left over

Step-by-step explanation:

56,941-792=56,149

The representations of the inequality is  an open circle is at 1 and a bold line starts at 1 and is pointing to the right.

An inequality compares two values, showing if one is less than, greater than, or simply not equal to another value e.g. 5 < 6, x ≥ 2, etc.

Since our answer is x > 1.  An open circle will be at 1 and a bold line starts at 1 and is pointing to the right (>). Check the attached image.

Note: You only shade up if you have ≤ (less than or equal) or ≥ (greater than or equal).

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There are countless possibilities for shapes that are similar but not congruent to shape 1, as long as they maintain the same proportions and shape.

There are many shapes that are similar but not congruent to shape 1. Similar shapes have the same shape, but their sizes may be different. In contrast, congruent shapes have the same shape and size.

One example of a similar shape to shape 1 is a rectangle that is twice as long and half as wide. Another example could be a square that is three times larger in area than shape 1.

A parallelogram that has the same base as shape 1 but is three times as tall is also similar but not congruent.

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To solve for k, we first take the derivative of the differential equation to obtain:

ky'' - y' = 1

Then we substitute y = 0 and y' = 1 when x = 1, giving us:

k(1) - (1) = 1

k = 2

Therefore, the value of k that satisfies the given conditions is k = 2.

The two types of frequency distributions are Discrete Frequency Distribution and Grouped Frequency Distribution

The two types of frequency distributions are;

When the data consists of discrete, separate values, this sort of distribution is used. It displays the frequency or number of occurrences of each value.

The data is often expressed in a table with two columns: one for distinct values and another for the frequencies of those values.

This distribution is utilized when the data is continuous and has a wide range of values. It entails categorizing the data into intervals or classes and then calculating the frequency of values that fall within each interval.

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According to the information we can infer that the total yardage traveled from 0 to 120 seconds is 140 yards.

To calculate the total yardage traveled we have to consider the movement of the O'Connor Panthers. In this case we have to consider that the movement in the y axis.

In this case we can conclude that the total yardage traveled was 140 yards because:

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Answer:

$8.27

Hope this is right <3

Answer:

5

Step-by-step explanation:

Subtract 7-2=5.

The value of ∠1=60°, ∠2=120°, ∠3=75°, ∠4=45°, ∠5=60°, ∠6 = 75°

From the question, we have

∠1=∠DCE=60° (Vertically opposite angles)

∠1=∠5=60°(alternate interior angle)

∠6 = 180-105 = 75°(linear pair)

We know that,

∠1+∠4+∠6 = 180°  (sum of angles in triangle is equal to 180 degree)

⇒60°+75°+∠4=180°

⇒135°+∠4=180°

⇒∠4=45°

∠3=∠6=75°(alternate interior angle)

∠1+∠2=180°(linear pair)

⇒60°+∠2=180°

⇒∠2=180°-60°=120°

Triangles:

One of the fundamental shapes in geometry is the triangle. The smallest polygon is a triangle. It has three vertices and three edges.The three sides and three angles that make up a triangle are referred to as its elements. The two crucial properties of a triangle are the external angle property and the angle sum property. What does a triangle's angle sum attribute mean? How is the angle sum property proven? Here, it is discussed.

Angles on the inside and outside make up a triangle. The angle created between two adjacent sides of a triangle is referred to as the interior angle. The angle created between a triangle's side and its neighboring side is known as the outside angle.

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Step-by-step explanation:

Given the formula

a(n+1)=an−3

The first term a(1) = 31

For the second term

a(2)

We have

a( 1 + 1) = a(1) - 3

a(2) = 31 - 3

a(2) = 28

For the third term

a(3)

We have

a(2+1) = a(2) - 3

a(3) = 28 - 3

a(3) = 25

For the fourth term

a(4)

That's

a(3+1) = a(3) - 3

a(4) = 25 - 3

a(4) = 22

Hope this helps you

Answer:

49 * 7'4

Step-by-step explanation:

we know that

A vertical parabola of the form

y=a(x-h)^2+k has a vertical directrix (x=h)

and a horizontal parabola of the form

x=a(y-k)^2+h has a horizontal parabola (y=k)

therefore

In this problem

option 1 ----> horizontal directrix

option 2 -> horizontal directrix

option 3 ---> vertical directrix

option 4 -> vertical directrix

Answer:

x/2 = 1/2x

Step-by-step explanation:

# of paintbrushes/ 2 piles = 1/2 # of paintbrushes

Answer:

x/2

Step-by-step explanation:

Since Lucy is taking the paintbrushes, x, and splitting them into 2 equally sized groups we can assume that this IS 1/2 the size of the original group.

We can show this claim by simply doing this equation: x/2, since she is splitting them into 2 groups that are equally sized, we are just dividing x by two.