Help? cant seem to figure this out. Appreciate it!

The number of edges in the complete bipartite graph is 36

From the question, we have the following parameters that can be used in our computation:

K = (4, 9)

The above means that

The vertices in the sets of the bipartite graph are

Set 1 = 4

Set 2 = 9

The number of edges in the complete bipartite graph is then calculated as

Vertices = Set 1 * Set 2

So, we have

Vertices = 4 * 9

Evaluate

Vertices = 36

Hence, there are 36 edges in the bipartite graph

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the discount will be 200 x 25% = 50

he will pay 150 for the cordless drill finally

Answer:

-7q and 9q, 2 and 6

Step-by-step explanation:

they are like each other

Answer: Terms that have identical variable parts (same variable(s) and same exponent(s)). So in this case the like terms are -7q and 9q AND 2 and 6 are like terms *REMEMBER: constant (which are numbers with NO variables can also be like terms)

but to solve this:

first group the like terms so:

(-7q+9q) that gives us 2q

(2+6) that gives us 8

*In your FINAL answer ALWAYS put the number(s) with variables first so the final answer is 2q+8

Answer:

(y-5)(y+3)

Step-by-step explanation:

im assuming that the y2 meant y^2 :,33

Answer:

Step-by-step explanation:

The question is not exactly as clear as it could be. The square shape must have 4 sides. We must assume that the 4th side is a building, but it sure is big.

However working with what we have, 450 has to be cut into 3 parts. 450 / 3 = 150

So each side of fencing has to be 150

Area =s^2

s = 150

Area = 150^2

Area = 22500 square feet.

That's slightly bigger than 21780. What should be the size of the fence sides?

Take the square root of 21780 which is 147.6

That will be the size of each side of the 3 sides needed.

y₁ =  [1  -4  0  1] and y₂ = [5  1  -6  -1] is the orthogonal basis for w using Gram-Schmidt process.

Given,

The set;

x₁ = [1  -4  0  1]

x₂ = [7  -7  -6  1]

We have to produce the orthogonal basis for w using the Gram-Schmidt process;

Here,

y₁ = x₁ =  [1  -4  0  1]

Now,

Solve for y₂

y₂ = x₂ - [x₂y₁ / y₁y₁] y₁

That is,

y₂ = [7  -7  -6  1] - ( [7  -7  -6  1] [1  -4  0  1] / [1  -4  0  1] [1  -4  0  1] ) × [1  -4  0  1]

y₂ =  [7  -7  -6  1] - (7 + 28 - 0 + 1) / (1 + 16 + 0 + 1) × [1  -4  0  1]

y₂ = [7  -7  -6  1]  - 36/18 × [1  -4  0  1]

y₂ =  [7  -7  -6  1] - 2  × [1  -4  0  1]

y₂ =  [7  -7  -6  1] - [2  8  0  2]

y₂ = [5  1  -6  -1]

That is,

The orthogonal basis for w using Gram-Schmidt process is,

y₁ =  [1  -4  0  1] and y₂ = [5  1  -6  -1]

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Answer:

7.405882353 years

Step-by-step explanation:

Simple interest is

A = P(1+rt)

Where A is the amount in the account

P is the principle invested

r is the rate and

t is the time

6593.75 = 5000( 1+ .0425*t)

Divide each side by 5000

6593.75/5000 = ( 1+ .0425*t)

1.31475 = ( 1+ .0425*t)

Subtract 1 from each side

.31475 = .0425t

Divide each side by.0425

.31475/.0425 = .0425t/.0425

7.405882353 = t

7.405882353 years

Answer:

time =31.029 close to 31

Step-by-step explanation:

A=PRT ( A: amounted investment, p is the investment, R is the rate, T is the time)

rate=%4.25=0.0425

6593.75=5000*0.0425

t=6593.75/(5000*0.0425)

t=31 ( month or weeks the question did not mention the period of time)

Answer:

I cannot answer this question because it is not complete. Please use complete sentences and questions.

The teacher's goal in introducing students to a card game where they must find the missing addend could be to develop and enhance their algebraic reasoning skills.

By presenting the problem as a puzzle or game, the teacher aims to engage the students in a fun and interactive way while fostering their ability to think critically and solve mathematical problems. The game helps students practice identifying the missing addend and applying algebraic thinking to find the solution. Additionally, it promotes the development of problem-solving strategies, logical reasoning, and the ability to generalize mathematical patterns, which are foundational skills in algebraic reasoning.

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Answer:

16. 68

17. 97

18. 81

19. 96

20. 84.2

Step-by-step explanation:

A stem in a stem and leaf plot represents the tens place, and the leaf represents the ones place. The dat represented by the graph is the same exact as the numbers:

68, 75, 77, 79, 80, 82, 92, 96, 96, 97

Just by looking at the data, the minimum is 68 and the maximum is 97.

Next, to find the median, we can cross off the same amount of numbers from both sides until we are left with only two,:

68, 75, 77, 79,   80, 82,    92, 96, 96, 97

To find the median, we just find the mean of 80 and 82, which is 81.

The mode is the number that repeats the most, and that number is 96.

Lastly, to find the mean, we add up all the numbers and divide them by the amount of numbers:

(68 + 75 + 77 + 79 + 80 + 82 + 92 + 96 + 96 + 97) / 10

842 / 10

84.2 would be the mean.

The inverse function of f(x) = ∛(x-1) + 4 is f⁻¹(x) = (x - 4)³ + 1

Given the function in the question:

f(x) = ∛(x-1) + 4

To find the inverse of f(x), we need to switch the roles of x and y in the equation and then solve for y.

f(x) = ∛(x-1) + 4

Let y = f(x) = ∛(x-1) + 4.

y = ∛(x-1) + 4

Now, we can rewrite this equation in terms of x as follows:

x = ∛(y-1) + 4

Subtracting 4 from both sides, we get:

x - 4 = ∛(y-1)

Cubing both sides, we get:

(x - 4)³ = y - 1

Adding 1 to both sides, we get:

y = (x - 4)³ + 1

Replace y with f⁻¹(x)

f⁻¹(x) = (x - 4)³ + 1

Therefore, the inverse function is  f⁻¹(x) = (x - 4)³ + 1.

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The maximum distance Frank can travel would be 10 miles.

What is maximum distance?

For maximum distance that is maximum range of a projectile, the angle of projectile should be 45°.

From given question,

taxicabs charge for first mile = $1.00

for each additional mile = $0.30

The cost for the first mile is $1, and for each additional mile it's $0.30, so for 10 miles it would be $1 + 9 * $0.30 = $4.70. Since Frank has only $3.50, he can travel a maximum of 10 miles.

Therefore, The maximum distance Frank can travel would be 10 miles.

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The additional information required to prove  that ΔXYZ and ΔFEG are congruent is  ∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE. So option 1 and 5 are correct.

Here in the figure it is given that ∠F and ∠X are congruent. To prove the triangle is congruent we have to prove that either two sides including the angles are congruent or another angle and included side is congruent.

When ∠Z ≅ ∠G and XZ ≅ FG, two angles and included sides are congruent, so triangles are congruent.

∠Z ≅ ∠G and ∠Y ≅ ∠E , we can not apply ASA, since three angles are mentioned

XZ ≅ FG  and ZY ≅ GE , Two sides are given, ASA cannot be applied, we need two angles

XY ≅ EF and ZY ≅ FG, is not possible.

∠Z ≅ ∠G and XY ≅ FE, one corresponding side and two angles are equal, so ΔXYZ ≅ ΔFEG according to ASA.

So, the correct answer is option 1 and option 5.

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The complete question is as follows and image is given below

What additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS? Check all that apply.

∠Z ≅ ∠G and XZ ≅ FG

∠Z ≅ ∠G and ∠Y ≅ ∠E

XZ ≅ FG and ZY ≅ GE

XY ≅ EF and ZY ≅ FG

∠Z ≅ ∠G and XY ≅ FE

Answer:

1 and 5 are correct

Step-by-step explanation:

The correct answer of the operation is option B: 4x^2 - 9.

To perform the operation (2x-3)(2x+3), we can use the FOIL method, which stands for First, Outer, Inner, Last. Let's go through the steps:

First: Multiply the first terms of each binomial.

(2x)(2x) = 4x^2

Outer: Multiply the outer terms of each binomial.

(2x)(3) = 6x

Inner: Multiply the inner terms of each binomial.

(-3)(2x) = -6x

Last: Multiply the last terms of each binomial.

(-3)(3) = -9

A binomial is a two-term algebraic expression that contains variable, coefficient, exponents and constant, a binomial is an expression that has two unlike terms connected through an addition or subtraction operator in between.  

Now, let's combine the like terms:

4x^2 + 6x - 6x - 9

Notice that the terms 6x and -6x cancel each other out.

Simplifying further, we have:

4x^2 - 9

The correct answer is option B: 4x^2 - 9.

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The location of the values square root of 11, square root of 8, and twenty two ninths on the number line is illustrated below.

It should be noted that a number line simply means a straight line that serves as an abstraction for real numbers.

It should be noted that square root of 11 will be 3.316. The square root of 8 is 2.83 and twenty two ninths on the number line will be around 20.22.

This is important to know the place where each falls on the number line.

Note that an overview was given.

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a) The 90% confidence interval for the population mean is approximately 34.52 to 37.48.

b) The 95% confidence interval for the population mean is approximately 34.23 to 37.77.

c) The 99% confidence interval for the population mean is approximately 33.68 to 38.32.

a. 90% confidence interval:

A 90% confidence interval means that if we were to repeat this sampling procedure multiple times, approximately 90% of the intervals calculated would contain the true population mean. The standard error (SE) represents the standard deviation of the sample mean and is calculated by dividing the population standard deviation (σ) by the square root of the sample size (n).

Plugging in the values:

Confidence interval = 36 ± (1.645 * (7 / √60))

Confidence interval ≈ 36 ± (1.645 * 0.903)

Confidence interval ≈ 36 ± 1.487

Confidence interval ≈ 34.52 to 37.48

b. 95% confidence interval:

Similarly, to calculate a 95% confidence interval, we use a different critical value. For a 95% confidence level, the critical value is approximately 1.96. Applying the formula:

Confidence interval = 36 ± (1.96 * (7 / √60))

Confidence interval ≈ 36 ± (1.96 * 0.903)

Confidence interval ≈ 36 ± 1.771

Confidence interval ≈ 34.23 to 37.77

c. 99% confidence interval:

To calculate a 99% confidence interval, we use a higher critical value. For a 99% confidence level, the critical value is approximately 2.576. Applying the formula:

Confidence interval = 36 ± (2.576 * (7 / √60))

Confidence interval ≈ 36 ± (2.576 * 0.903)

Confidence interval ≈ 36 ± 2.326

Confidence interval ≈ 33.68 to 38.32

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Answer:

The choice A

Step-by-step explanation:

B+A=BA+BA+BA=3BA

Answer:

its negitave

Step-by-step explanation:

becuase negitave+negitave = negitave

Answer:

work is shown and pictured

From the coordinate points, we can see that the data point that differs significantly is (−4,−8)

An outlier in statistics is a data point that differs significantly from other observations in the given data

This may be due to variability in the measurement or it may indicate an experimental error.

From the coordinate points, we can see that the data point that differs significantly is (−4,−8). This gives the possible outlier of the given coordinate

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Answer:

It's would be -4,-8 Have a great day

Answer:

using solver, the optimal solution is 6,666P₁ or process 1 should work for 6,666 hours during the year.

Total production = 6,666 x 3 = 19,998 ounces of perfume.

Total revenue = 19,998 x $5 = $99,990

Total costs = (6,666 x $3 per labor hour) + (6,666 x 2 x $2 per unit of chemicals) = $46,662

Operating income = $53,328

Step-by-step explanation:

Variables:

P₁ = number of hours in process 1

P₂ = number of hours in process 2

P₁ yields 3 ounces of perfume

P₂ yields 5 ounces of perfume

both are sold at $5 per ounce

15P₁ + 25P₂

labor usage:

(1P₁ + 2P₂) x $3

3P₁ + 6P₂

chemicals usage:

(2P₁ + 3P₂) x $2

4P₁ + 6P₂

Profit = 15P₁ + 25P₂ - (3P₁ + 6P₂) - (4P₁ + 6P₂) = 8P₁ + 13P₂

so we need to maximize 8P₁ + 13P₂

the constraints are:

3P₁ + 6P₂ ≤ 20,000

4P₁ + 6P₂ ≤ 35,000

P₁, P₂ ≥ 0

using solver, the optimal solution is 6,666P₁ or process 1 should work for 6,666 hours during the year.

Total production = 6,666 x 3 = 19,998 ounces of perfume.

Total revenue = 19,998 x $5 = $99,990

Total costs = (6,666 x $3 per labor hour) + (6,666 x 2 x $2 per unit of chemicals) = $46,662

Operating income = $53,328

Answer 0.90

Step-by-step explanation: she makes 0.90 cents we know because if you multiply it by 5 you get the equation.

Therefore, the equivalent metric length of a 3-inch scar would be 7.62 centimeters.

Explanation: Metric length is a measurement system that uses the metric unit. The metric unit is more common than the customary unit system in the United States. To convert customary unit lengths to metric lengths, a conversion factor is used.3 inches is the measurement of the scar in customary units. To convert 3 inches to metric units, multiply it by the conversion factor. There are 2.54 centimeters in one inch, which is the conversion factor. To find the equivalent metric length of a 3-inch scar, multiply 3 by 2.54. Therefore, the equivalent metric length of a 3-inch scar would be 7.62 centimeters.  The equivalent metric length of a 3-inch scar would be 7.62 centimeters. Metric length is a measurement system that uses the metric unit. The metric unit is more common than the customary unit system in the United States. To convert customary unit lengths to metric lengths, a conversion factor is used. There are 2.54 centimeters in one inch, which is the conversion factor.

Therefore, the equivalent metric length of a 3-inch scar would be 7.62 centimeters.

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Answer:

Joanna will use 1 gallon of milk in each bowl.

Step-by-step explanation:

Divide 6 into 6 bowls to get 1

Number Line:

 -∞  ---------  x₁ ---------  x₂ ---------  +∞

To mark the points that represent the values of x satisfying |x-1|>2 on a number line, we follow these steps:

Find the boundary points:

The inequality |x-1|>2 can be rewritten as two separate inequalities:

x-1 > 2 and x-1 < -2

Solving the first inequality:

x-1 > 2

x > 2+1

x > 3

Solving the second inequality:

x-1 < -2

x < -2+1

x < -1

Therefore, the boundary points are x = 3 and x = -1.

Mark the boundary points on the number line:

Place a solid dot at x = 3 and x = -1.

Determine the intervals:

Divide the number line into intervals based on the boundary points.

We have three intervals: (-∞, -1), (-1, 3), and (3, +∞).

Choose a test point in each interval:

For the interval (-∞, -1), we can choose x = -2 as a test point.

For the interval (-1, 3), we can choose x = 0 as a test point.

For the interval (3, +∞), we can choose x = 4 as a test point.

Determine the solutions:

Plug in the test points into the original inequality |x-1|>2 to see if they satisfy the inequality.

For x = -2:

|(-2)-1| > 2

|-3| > 2

3 > 2 (True)

So, the interval (-∞, -1) is part of the solution.

For x = 0:

|0-1| > 2

|-1| > 2

1 > 2 (False)

So, the interval (-1, 3) is not part of the solution.

For x = 4:

|4-1| > 2

|3| > 2

3 > 2 (True)

So, the interval (3, +∞) is part of the solution.

Mark the solution intervals on the number line:

Place an open circle at the endpoints of the intervals (-∞, -1) and (3, +∞), and shade the intervals to indicate the solutions.

The number line representation of the points satisfying |x-1|>2 would be as follows:

                                        -∞  ----●----  x₁ ---------  x₂ ----●----  +∞

Here, x₁ represents -1 and x₂ represents 3. The shaded intervals (-∞, -1) and (3, +∞) represent the solutions to the inequality.

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Let θ be an angle in quadrant iii such that = cosθ − 45, the exact values of csc θ and tan θ are 5/3 and -3/4 respectively.

As an angle θ is in quadrant III, and cosθ = -4/5

To identify the exact value of cscθ and tanθ, we will first calculate the value of sinθ by using the Pythagorean identity

sin²θ + cos²θ = 1

⇒ sin²θ + (-4/5)² = 1

⇒ sin²θ = 1 - (-4/5)² = 1 - 16/25 = 9/25

⇒ sinθ = √(9/25) = 3/5

Now, we can calculate the value of cscθ as

cscθ = 1/sinθ = 1/(3/5) = 5/3

Next, we can estimate the value of tanθ by using the identity

tanθ = sinθ/cosθ= (3/5) / (-4/5) = -3/4

Therefore, the exact values of cscθ and tanθ are

cscθ = 5/3 and tanθ = -3/4.

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Step-by-step explanation:

what is the problem ?

the solution of such a system of 2 equations is the point, where they cross.

this point has the same coordinates for both equations, and that is called the solution.

and we can clearly see that point in the graph :

(-1, 1)

formally we can solve that way

y = 2x + 3

y = -x

therefore,

2x + 3 = -x

3x + 3 = 0

3x = -3

x = -1

y = -x = - -1 = 1

so, we get

(-1, 1) as solution.

Answer: (1, 4)

Step-by-step explanation:

When you reflect over y=x, (x, y) turns into (y, x).

So the coordinates of C' are (1, 4).

The equation of the tangent line to the curve \(y = \frac {(x^2 - 1)}{ (x^2 + x + 1)}\) at the point (1, 0) is y = (2/3)x - 2/3.

To find the equation of the tangent line to the curve at the point (1, 0), we need to find the slope of the tangent line and then use the point-slope form of a linear equation.
Let's differentiate \(y = \frac {(x^2 - 1)}{ (x^2 + x + 1)}\) using the quotient rule:

\(y' = [(2x)(x^2 + x + 1) - (x^2 - 1)(2x + 1)] / (x^2 + x + 1)^2\)
Substituting x = 1 into the derivative expression:

\(y'(1) = [(2(1))(1^2 + 1 + 1) - (1^2 - 1)(2(1) + 1)] / (1^2 + 1 + 1)^2\)

        \(= [2(3) - (0)(3)] / (3)^2\)

        = 6/9

        = 2/3

Using the point-slope form y - y₁ = m(x - x₁), where (x₁, y₁) = (1, 0) and m = 2/3 we get,  
y - 0 = (2/3)(x - 1)

y = (2/3)x - 2/3

The point-slope form of a linear equation is given by y - y₁ = m(x - x₁) where (x₁, y₁) is a point on the line, and m is the slope of the line.

Therefore, the equation of the tangent line to the curve y = (x^2 - 1) / (x^2 + x + 1) at the point (1, 0) is y = (2/3)x - 2/3.

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The complete question is:

Find an equation of the tangent line to the given curve at the specified point, \(y = \frac {(x^2 - 1)}{ (x^2 + x + 1)}\) at (1,0).

Answer:

x+8=Y

0,8

1,9

2,10

3,11

4,12

5,13

2x=Y

0,0

1,2

2,4

3,6

4,8

5,10

Step-by-step explanation:

The total amount of chlorine required per day would be 17,820 kg/day.

Therefore, the quantity of chlorine required to treat a flow of 3 MLD if the chlorine demand is 12mg/L and a chlorine residual of 2mg/L is desired is 30kg/day.

To treat a flow of 3 MLD, the quantity of chlorine required, given a chlorine demand of 12mg/L and a chlorine residual of 2mg/L is 30kg/day.Chlorination is a water treatment process that employs chlorine or chlorine-containing compounds to purify water. The most widely used disinfectant for drinking water, chlorine is relatively inexpensive and capable of killing most pathogens that might be present in the water.

How much chlorine is needed to treat water?

The amount of chlorine needed to treat water is determined by the amount of organic and inorganic matter, ammonia, nitrogen, and other substances present in the water that can react with the chlorine and the volume of water to be treated.

The quantity of chlorine that is required is usually measured in mg/L (milligrams per litre) or ppm (parts per million). For example, a chlorine demand of 12mg/L indicates that 12 milligrams of chlorine are required to disinfect 1 litre of water.

So, to calculate the quantity of chlorine needed to treat a flow of 3 MLD, we need to multiply the flow rate (3 MLD) by the chlorine demand (12mg/L) and then by the number of days in the year (365). This will give us the total amount of chlorine needed per year. Then, we divide this amount by 365 to get the amount of chlorine needed per day.Mathematically,Quantity of chlorine required

= Flow rate x Chlorine demand x 365 / 1000 kg/day

= 3 MLD x 12 mg/L x 365 / 1000 kg/day

= 13,140 kg/day

However, this only gives us the amount of chlorine needed to meet the chlorine demand. If we also want to achieve a chlorine residual of 2 mg/L, we need to add the amount of chlorine required to achieve this residual. The amount of chlorine required to achieve a residual can be determined by conducting a jar test or by using empirical data.For instance, let us say that based on empirical data, we need to add 4 mg/L of chlorine to achieve a residual of 2 mg/L. The total amount of chlorine required per day would be 17,820 kg/day.

Therefore, the quantity of chlorine required to treat a flow of 3 MLD if the chlorine demand is 12mg/L and a chlorine residual of 2mg/L is desired is 30kg/day.

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